Pls he’ll I’ll brainlest and add extra points

well, first off let's check which term has the highest degree, hmmm in this case it has to be the x³, so that's the leading term and its coefficient is 9.

STEP

1

:

           5

Simplify   —

           4

Equation at the end of step

1

:

  1          5

 (— +  a) -  —  = 0

  3          4

STEP

2

:

           1

Simplify   —

           3

Equation at the end of step

2

:

  1          5

 (— +  a) -  —  = 0

  3          4

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1   Adding a whole to a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        a     a • 3

   a =  —  =  —————

        1       3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1 + a • 3     3a + 1

—————————  =  ——————

    3           3  

Equation at the end of step

3

:

 (3a + 1)    5

 ———————— -  —  = 0

    3        4

STEP

4

:

Calculating the Least Common Multiple :

4.1    Find the Least Common Multiple

     The left denominator is :       3

     The right denominator is :       4

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

3 1 0 1

2 0 2 2

Product of all

Prime Factors  3 4 12

     Least Common Multiple:

     12

Calculating Multipliers :

4.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions :

4.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (3a+1) • 4

  ——————————————————  =   ——————————

        L.C.M                 12    

  R. Mult. • R. Num.      5 • 3

  ——————————————————  =   —————

        L.C.M              12  

Adding fractions that have a common denominator :

4.4       Adding up the two equivalent fractions

(3a+1) • 4 - (5 • 3)     12a - 11

————————————————————  =  ————————

         12                 12  

Equation at the end of step

4

:

 12a - 11

 ————————  = 0

    12  

STEP

5

:

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 12a-11

 —————— • 12 = 0 • 12

   12  

Now, on the left hand side, the  12  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  12a-11  = 0

Solving a Single Variable Equation:

5.2      Solve  :    12a-11 = 0

Add  11  to both sides of the equation :

                     12a = 11

Divide both sides of the equation by 12:

                    a = 11/12 = 0.917

a = 11/12 = 0.917

Answer:

11/12

Step-by-step explanation:

You want to subtract 5/4 minus 1/3 but you cant so you have to find the greatest denominator first which would be 12 because 3x4=12.

Since you multiplied 4x 3 to get 12 then you will multiply the 5 by 3 and the 1 by 4 to get this -> 5/4= 15/12     1/3= 4/12

Then subtract 15/12- 4/12= 11/12

a=11/12

Answer:

After 10 weeks: 40 inches

Step-by-step explanation:

Equation

15 + 2.5w = h

15 = beginning height

2.5 = rate per week

w = weeks passed

h = total height

Two or more expressions with an Equal sign is called as Equation.15+2.5W tall l would the sunflower be after w weeks and 40 inches tall after 10 weeks.

Two or more expressions with an Equal sign is called as Equation.

Given that, At the beginning of spring, Caroline planted a small sunflower in her backyard

The initial height of the sunflower was  15 inches tall.

The sunflower then began to grow at a rate of 2.5 inches per week.

We need to find the height of the tree after 10 weeks.

15+2.5(10)

15+25

40 inches tall after 10 weeks.

the sunflower height after w weeks

15+2.5W

Hence 15+2.5W tall l would the sunflower be after w weeks and 40 inches tall after 10 weeks.

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Answer:

The answer is 60 and 80

Step-by-step explanation:

Answer:

1234567891011121314151617181920

Answer:

the first one is true

Step-by-step explanation:

√36>5 = 6>5

7<√10 = 7<3.162

√9>√25 = 3>5

Therefore, the first one is correct

Answer:

x=4y

Step-by-step explanation:

Solving for x means you need to get it in the form x=?.

1. let's isolate the variable.

-2x-7y=y-4x

Add 4x to both sides to isolate:

2x-7y=y

Add 7y to both sides to isolate the x term:

2x=8y

Now we divide both sides by 2 (as we are solving for x):

x=4y

Hope this helps!

Answer:

[tex]5x^2 - 4[/tex]

Step-by-step explanation:

For shifted down a function you have to follow the next structured:

[tex]f(x) - c[/tex]

In our case is:

[tex]x^2 - 4[/tex]

Now for compressed or shrink a graph you have to multiply by a factor in the input something like this:

[tex]f(cx)[/tex]

In our case is:

[tex]5x^2[/tex]

Maybe you can think, why 5 and not [tex]\frac{1}{5}[/tex] instead?. Well, when you multiply by [tex]\frac{1}{5}[/tex] this dilate or stretch the graft because the output of each value is smaller, example:

[tex]f(x) = x^2\\g(x) = \frac{1}{5} x^2[/tex]

Then evaluate for a number, for example 5:

[tex]f(5) = 25\\g(5) = 5[/tex]

the output of [tex]g(x)[/tex] is 5 steps a far from the answer of [tex]f(x)[/tex] this in a graph is illustrate as a stretching.

So the opposite happen when you multiply by a integer number, the graph is compressed because the output take the "faster steps".

So combine the two transformation and get [tex]5x^2 - 4[/tex]

Answer:

you draw a T. form and then you can start to in debit and credit

Answer:

4.30 naira

Step-by-step explanation:

Splitting in half, we have that they both get 3.60 naira each. Adding 70 kobo to 3.60 naira, we have 4.30 naira. Since we need Tayo's share to be 70 kobo more than Bisi's, we give Tayo the bigger share and the left cash to Bisi (2.90 naira).

Tayo will get 3.95 more than the naira of the given shares.

In mathematics, an expression is a combination of numbers, variables, and operators (such as addition, subtraction, multiplication, and division) that can be evaluated to obtain a value.

Let's call the amount that Visit gets "x".

According to the problem, Tayo gets 70 kobos (0.70 nairas) more than Visit. So, Tayo gets:

x + 0.70

The total amount of money shared between them is 7.20 naira. So, we can set up an equation:

x + (x + 0.70) = 7.20

Simplifying this equation, we get:

2x + 0.70 = 7.20

Subtracting 0.70 from both sides, we get:

2x = 6.50

Dividing both sides by 2, we get:

x = 3.25

To find out how much Tayo gets, we can use the equation we came up with earlier:

x + 0.70

Substituting x = 3.25, we get:

3.25 + 0.70 = 3.95

Therefore, Tayo will get 3.95 more than the naira.

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Answer:

17.791361

Step-by-step explanation:

Hope this helps!

Can I get Braineist Pls?

Answer:

17.791361

You can cross multiply. I am almost sure this is the method. Put the first number over each other. Then multiply the numbers across. Hope this is helpful!

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Use the half angle formulas

sin(θ/2) = ±√((1 - cosθ)/2)

sin(θ/2) = ±√((1 - (3/5))/2)

sin(θ/2) = ±√((2/5)/2)

sin(θ/2) = ±√(1/5)

knowing θ is in the 4th quadrant, θ/2 will be in the second quadrant where sines are positive.

sin(θ/2) = +√(1/5) = √0.2

we know he filled 2/3 of the bucket in 15mins, how long for the "whole", namely 3/3 = whole, bearing in mind that 3/3 = 1, just the same as 7/7 = 1 or 1,000/1,000 = 1, so one whole is always 1 fraction wise.

[tex]\begin{array}{ccll} fraction&mins\\ \cline{1-2} \frac{2}{3}&15\\[1em] \underset{whole}{1}&x \end{array}\implies \cfrac{~~ \frac{2}{3}~~}{1}=\cfrac{15}{x}\implies \cfrac{2}{3}x=15\implies \cfrac{2x}{3}=15 \\\\\\ 2x=45\implies x=\cfrac{45}{2}\implies x=22\frac{1}{2}\qquad \textit{22 minutes and 30 seconds}[/tex]

Answer:

True

Step-by-step explanation:

For instance, twins are born on the same day but imagine ten people instead of two being born on the same day.

Answer:

  $12

Step-by-step explanation:

Jane's commission is the product of sales and her rate.

  commission = (20)($4.00)(0.15) = $12.00

Jane's commission is $12.00 if she sells 20 boxes of pencils.

aight slide it here big boy

Answer: the difference if that 5.4 is not a negative number they are relatied because it takes them both 5.4 ,3 moves to get to 0

Step-by-step explanation:

Answer:

They bought 20 plants

Step-by-step explanation:

If you minus the total 750- 250 of potting supplies it leaves you with 500.

Divide 500/ 25 = 20

Answer:

20 plants

Step-by-step explanation:

500 divided by 25 = 20

have a nice day

Answer:

Maybe

Step-by-step explanation:

maybe

Answer:

yes because it can be written as a fraction 225/1000

Answer:

81 people

Step-by-step explanation:

Each digit can be one of {1, 3, 5, 7, 9}, so there are 5 choices for each. Then there are 5•5•5 = 5³ = 125 integers containing only odd digits, which means they make of 125/900 ≈ 14% of them.

Answer:

D

Step-by-step explanation:

You add the "columns."  The equations are arranged so that like terms are stacked vertically.  3x and 7x are like terms; when you add them, you get 10x.

-y and y are like terms; when you add them, you get 0 (that doesn't appear in the sum).

-5 and 15 are like terms; add them to get 10.

The sum of the two equations is the equation 10x = 10.

Answer:

A. exponential growth or decay function is a function that grows or shrinks at a constant percent growth rate. The equation can be written in the form f(x) = a(1 + r)x or f(x) = abx where b = 1 + r. ... r is the percent growth or decay rate, written as a decimal, b is the growth factor or growth multiplier.

Answer:

B. y = 3x^2 + 3x - 3

Step-by-step explanation:

Find the function rule.

y = 3 x ^2 + 3 x − 3

\table[[x,y],[-1,-3],[0,-3],[3,33]]

The quadratic function to model the values in the table is,

⇒ y = 3x² + 3x - 3

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The values of x and y in the table are,

⇒ x = - 1, 0, 3

⇒ y = - 3, - 3, 33

Now, We know that;

The standard form of the quadratic equation is,

⇒ y = ax² + bx + c

Put x = - 1, y = - 3;

⇒ - 3 = a (- 1)² + b (- 1) + c

⇒ - 3 = a - b + c  .. (i)

Put x = 0, y = - 3;

⇒ - 3 = a (0)² + b (0) + c

⇒ - 3 = c

Put x = 3, y = 33;

⇒ 33 = a (3)² + b (3) + c

⇒ 33 = 9a + 3b - 3

⇒ 36 = 9a + 3b

⇒ 36/3 = 3a + b

⇒ 3a + b = 12  .. (ii)

From (i);

⇒ - 3 = a - b + c

⇒ - 3 = a - b - 3

⇒ a - b = 0 .. (iii)

Solve for (i) and (iii), we get;

⇒ a = 3, b = 3

Hence, The quadratic function to model the values in the table is,

⇒ y = ax² + bx + c

⇒ y = 3x² + 3x - 3

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Answer:

-65/36

Step-by-step explanation:

The domain are the possible input while the range are the possible output

of a function.

Reasons:

The given functions can be expressed by the equation; (-x + 1)·(x + 1) = -x² + 1

Therefore, we have;

(a) y = f(x) + 1 = -x² + 1 + 1 = -x² + 2

The x-intercept of the above function are, x = √2, and x = -√2

Which gives;

The domain = [-√2, √2]

The range = [0, 2]

(b) y = 3·f(x) = 3 × (-x² + 1) = -3·x² + 3

At the x–intercepts, we have;

-3·x² + 3 = 0

x = ±1

The domain = [-1, 1]

The maximum value of y is given at x = 0, therefore;

= -3 × 0² + 3 = 3

The range = [0, 1]

(c) y = -f(x) = -(-x² + 1) = x² - 1

At the x–intercepts, x² - 1 = 0

x = ± 1

The domain = [-1, 1]

The minimum value of y is given at x = 0, which is y = -1

The range = [0, -1]

(d) y = f(x - 1) = -(x - 1)² + 1 = -x² + 2·x

At the x–intercepts, we have;  -x² + 2·x = 0, which gives;

(-x + 2)·x = 0

Which gives, x = 0, or x = 2

The domain = [0, 2]

The maximum value of y is given when x = -b/(2·a) = -2/(2×(-1)) = 1

y = f(1) =  -1² + 2×1 = 1

Therefore;

The range = [0, 1]

(e) y = f(x + 2) + 1 = (-(x + 2)² + 1) + 1 = -x² - 4·x - 2

At the x–intercepts, we have;  -x² - 4·x - 2 = 0, which gives;

x = -(2 + √2) or x = x = √2 - 2

The domain = [-(2 + √2), (√2 - 2)]

The maximum value of y is given when x = -4/(2)) = -2

Which gives;

-(-2)² - 4·(-2) - 2 = 2

The range = [0, 2]

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[tex]\begin{cases} x = -4\implies &x+4=0\\ x=-5\implies &x+5=0\\ x = 0\implies &x=0\\ x=\frac{1}{3}\implies &x -\frac{1}{3}=0\\ &3\left( x -\frac{1}{3} \right)=3(0)\\ &3x-1=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x+4)(x+5)(x)(3x-1)=\stackrel{\textit{original equation}}{0} \\\\\\ (x^2+9x+20)(x)(3x-1)=y\implies (x^3+9x^2+20x)(3x-1)=y \\\\\\ (3x^4+27x^3+60x^2)+(-x^3-9x^2-20x)=y[/tex]

[tex]3x^4+27x^3+60x^2-x^3-9x^2-20x=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 3x^4+26x^3+51x^2-20x=y~\hfill[/tex]