Pls help I’m failing I’ll brainlest and add extra points ASAP help with both

Answer: 101

Step-by-step explanation:

.

Sh363gdbzej3yve truly urban urge Heydyeh hdye

Answer:

option a 5......

...

I hope it's correct

Answer:

[tex]\frac{3}{4} =\frac{1}{4} (3)[/tex]

Step-by-step explanation:

like that?

Answer:

3/4

Step-by-step explanation:

Step 1:  Write an expression

A fourth is 1/4

3 fourths means 3 one forths

1/4 + 1/4 + 1/4

3/4

Answer: 3/4

Answer:

Step-by-step explanation:

6×1 = 6

7×10 = 70

14×100 = 1400

6+70+1400 = 1476

Answer:

1,476

Step-by-step explanation:

I hope this helps you out! (please give me brainliest)

Solve all of the equations below and add all of the solutions to those equations to get your answer.

10x4x2=

8x4x2=

10x8=

(10x8)-(7x6)=

7x2x2=

6x2x2=

7x6=

Answer:

140-5x

Step-by-step explanation:

x would be the number of minutes

for eg, after 1 min, the temperature of the steak would be 140-5(1) = 135

not sure how to explain this, but its basically the start temperature - change

Answer:

0.1151 = 11.51% probability of completing the project over 20 days.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Expected completion time of the project = 22 days.

Variance of project completion time = 2.77

This means that [tex]\mu = 22, \sigma = \sqrt{2.77}[/tex]

What is the probability of completing the project over 20 days?

This is the p-value of Z when X = 20, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{20 - 22}{\sqrt{2.77}}[/tex]

[tex]Z = -1.2[/tex]

[tex]Z = -1.2[/tex] has a p-value of 0.1151.

0.1151 = 11.51% probability of completing the project over 20 days.

Answer:

12 x^5y^12

Step-by-step explanation:

3x^2y^5 * 4x^3y^7

Multiply the constants

3*4 = 12

Multiply the x terms

x^2 * x^3

We know a^b* a^c = a^(b+c)

x^(2+3) = x^5

Multiply the y terms

y^6 * y^7 = y&(5+7) = y^12

Put them back together

12 x^5y^12

Answer:

y = -3x/2 + 5/2

Step-by-step explanation:

Well, basically what you do is modify it so that y is on one side.

3x+2y = 5

2y = 5-3x

y = (5-3x)/2

y = 5/2 -3x/2

So, the answer is the second option.

Answer:

B

Step-by-step explanation:

3x + 2y = 5

Our goal is this form:

y = mx + b

- move 3x to right anc change its sign

2y = -3x + 5

- divide each member by 2

y = -3/2 x + 5/2

9514 1404 393

Answer:

  B) (4,–1)

Step-by-step explanation:

A graph can help you figure this out. The point (4, -1) is in the doubly-shaded area, so is a solution to this system.

==========================================================

Explanation:

Choice A can be ruled out because

[tex]y \le x+1\\\\5 \le 0+1\\\\5 \le 1\\\\[/tex]

which is false.

Choices C and D are similar, so they can be ruled out as well.

---------------------

Choice B is the answer because it makes both inequalities true.

If we plug the coordinates of (4,-1) into the first inequality, we get

[tex]y > -x\\\\-1 > -4[/tex]

which is a true statement because -1 is to the right of -4 on the number line.

Now try the other inequality

[tex]y \le x+1\\\\-1 \le 4+1\\\\-1 \le 5\\\\[/tex]

that's true also. So again, (4,-1) makes both inequalities true, and that's why choice B is the answer.

Answer:

1217

Step-by-step explanation:

Given

[tex]Subjects = 2353[/tex]

[tex]Improvement = 1136[/tex]

Required

The number that didn't improve --- missing from the question.

Let the unimproved be represented as x.

So, we have:

[tex]x + Improvement = Subjects[/tex]

Substitute known values

[tex]x + 1136 = 2353[/tex]

Solve for x

[tex]x =- 1136 + 2353[/tex]

[tex]x =1217[/tex]

Answer:

14

Step-by-step explanation:

The angles created by the diagonals of a rhombus add up to 360 meaning each one is 90 degrees

5x+20 = 90

subtract 20 from both sides

5x = 70

divide by 5 on both sides

x=14

volume= a^2 * h

area= a^2+4ah

take the second equation, solve for h

4ah=1100-a^2

h=1100/4a -1/4 a now put that expression in volume equation for h.

YOu now have a volume expression as function of a.

take the derivative, set to zero, solve for a. Then put that value back into the volume equation, solve for Volume.

Cited from jiskha

Work Shown:

30 min = 30/60 = 0.5 hours

distance = rate*time

rate = distance/time

rate = (2450 miles)/(0.5 hours)

rate = (2450/0.5) mph

rate = 4900 mph

For the sake of comparison, a typical commercial passenger jet can reach max speeds of about 600 mph.

Answer:

$6.60

Step-by-step explanation:

12% = 0.12

12% of $55 = 0.12 x 55

=6.6

So, $6.60

Answer:

total = 2.8 + 3x

x is the price of the candy bars

Answer:

Prove that all sides are congruent and that the slopes of consecutive sides are opposite reciprocals. Step-by-step explanation: In order to two segmets to be perpendicular, the slope of both lines must be opposite and reciprocals, having a 90° interception and forming a square.

Answer:

-3/2 ±1/2 sqrt(5) = x

Step-by-step explanation:

f(x) = 2x^2 + 6x + 2

Set the function equal to 0

0 = 2x^2 + 6x + 2

Factor out 2

0 = 2(x^2 + 3x + 1)

Divide by 2

0 = (x^2 + 3x + 1)

Subtract 1 from each side

-1 = x^2 +3x

Complete the square by dividing the x coefficient by 2 and then squaring

(3/2)^2 = 9/4

-1 +9/4 = x^2 +3x+9/4

-4/4+9/4 = (x+3/2) ^2

5/4 = (x+3/2) ^2

Taking the square root of each side

± sqrt(5/4) = sqrt( (x+3/2) ^2)

±1/2 sqrt(5) =  (x+3/2)

Subtract 3/2 from each side

-3/2 ±1/2 sqrt(5) = x

Answer:

3

Step-by-step explanation:

The dilation factor is 3

The rocket will be at the height of 450metres at 13.16secs and 6.84secs

Given the expression modeled by the height S(t)=-5t^2+100t where

t is the time taken by the rocket to take off

s is the height traveled by rocket

In order to find the height of the rocket 7 seconds after it takes off, we will substitute t = 7 into the equation

S(7) = -5(7)²+100(7)

S(7) = -5(49)+700

S(7) = -245+700

S(7) = 455metres

Hence the height of the rocket 7 seconds after it takes off is 455metres

Given that S = 450m, we can also get the time taken by the rocket at this height.

Recall that S(t)= -5t²+100t

450 = -5t²+100t

Rearrange

-5t²+100t - 450 = 0

5t²-100t + 450 = 0

Divide through by 5

t²-20t + 90 = 0

On factorizing above equation;

t= 10+√10 or t=10−√10

t = 10+3.1623 or 10 - 3.1623

t = 13.16 and 6.84secs

Hence the rocket will be at the height of 450metres at 13.16secs and 6.84secs

Learn more here: https://brainly.com/question/1063981

Area of shaded region = 1/2(πr²)

= 1/2(22/7×3×3)

= 99/7

= 99/7×2

= 198/7 cm^2

Thats the total area of the shaded region

Must click thanks and mark brainliest

Answer:

1/2

Step-by-step explanation:

2/5 + 1/10

Get a common denominator of 10

2/5 * 2/2 + 1/10

4/10 + 1/10

5/10

simplify

Divide the top and bottom by 5

1/2

Answer:

[tex] \frac{1}{2} [/tex]

Step-by-step explanation:

[tex] \frac{2}{5} + \frac{1}{10} \\ \frac{2 \times 2}{5 \times 2} + \frac{1}{10} \\ \frac{4}{10} + \frac{1}{10} \\ \frac{5}{10} \\ \frac{5 \div 5}{10 \div 5} \\ = \frac{1}{2} [/tex]

Answer:

8000 and 12000 respectively

Step-by-step explanation:

Let the amount invested in first account be x and y be the amount invested in the second account.

ATQ, x+y=20000 and 1280=(7/100)*x+(6/100)*y

x=8000 and y=12000.

The n-th row in Pascal's triangle tells you the coefficients of terms in the expansion of (a + b)ⁿ. Starting with n = 0,

1

1 … 1

1 … 2 … 1

1 … 3 … 3 … 1

1 … 4 … 6 … 4 … 1

1 … 5 … 10 … 10 … 5 … 1

In more concrete terms, this translates to

(x - 5y)⁵ = 1 x ⁵ (-5y)⁰ + 5 x ⁴ (-5y)¹ + 10 x ³ (-5y)² + 10 x ² (-5y)³ + 5 x ¹ (-5y)⁴ + 1 x ⁰ (-5y)⁵

Simplify:

(x - 5y)⁵ = x ⁵ - 25x ⁴y + 250x ³y ² - 1250x ²y ³ + 3125xy ⁴ - 3125y ⁵

$5531.49

(9×9)×$68.29

Answer:

45x=-44

x=-44/45

Step-by-step explanation:

is this a free question?

Answer:

D.√85

Step-by-step explanation:

We can find the distance between two points using the distance between two points formula

Distance between two points formula:

d = √(x2 - x1)² + (y2 - y1)²

Where the x and y values are derived from the given points

We are given the two points (-2,7) and (7,9)

Using these points let's define the variables ( variables are x1, x2, y1, and y2)

Remember points are written as follows (x,y)

The x value of the first point is -2 so x1 = -2

The x value of the second point is 7 so x2 = 7

The y value of the first point is 7 so y1 = 7

The y value of the second point is 9 so y2 = 9

Now that we have defined each variable let's find the distance between the two points

We can do this by substituting the values into the formula

Formula: d = √(x2 - x1)² + (y2 - y1)²

Variables: x1 = -2, x2 = 7, y1 = 7, y2 = 9

Substitute values in formula

d = √(7 - (-2))² + (9 - 7)²

Evaluation:

The two negative signs cancel out on 7-(-2) and it changes to +7

d = √ (7+2)² + (9-7)²

Add 7+2 and subtract 9 and 7

d = √ (9)² + (2)²

Simplify exponents 9² = 81 and 2² = 4

We then have d = √ 81 + 4

Finally we add 81 and 4

We get that the distance between the two points is √85

Answer:

d. The relationship between a and b cannot be determined.

Step-by-step explanation:

Given

[tex]a < 0[/tex]

[tex]b > 0[/tex]

Required

Which is true

To do this, we test each of the options using assumed values

[tex]a + b > 0[/tex]

Let:

[tex]a = -5[/tex]       [tex]b= 1[/tex]

So:

[tex]-5 + 1 > 0[/tex]

[tex]-4 > 0[/tex] --- false

[tex]a + b < 0[/tex]

Let:

[tex]a = -5[/tex]       [tex]b= 7[/tex]

So:

[tex]-5 + 7 < 0[/tex]

[tex]2 < 0[/tex] --- false

[tex]a + b = 0[/tex]

Let:

[tex]a = -5[/tex]       [tex]b= 7[/tex]

So:

[tex]-5 + 7 = 0[/tex]

[tex]2 = 0[/tex] --- false

Hence, the relationship is not specific and cannot be determined