Jasmine the Great Dane has a head 30 cm long. Her tall is equal to the size of her head plus one-half the size of her body. Her body is the size of her head phluss the tal. How long is Jasmine?
Answer:
240 cm
Step-by-step explanation:
Let x = tail y = body
x = 30 + 1/2y
y = 30 + x
Let's plug in the x equation at the bottom
y = 30 + 30 + 1/2y
y = 60 + 1/2y
Bring the like terms to one side
y = 60 + 1/2y
-1/2y -1/2y
1/2y = 60
Multiply both sides by 2 to get the length of the body
1/2y x 2 = 60 x 2
y = 120
Now we can plug in the new y into another equation, let's use the top one
x = 30 + 1/2(120)
x = 30 + 60
x = 90 = length of the tail
Add em all up
120 + 90 + 30 = 240
Write a quadratic equation with integer coefficients having the given numbers as solutions.
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Answer:
x² -22 = 0
Step-by-step explanation:
The roots are opposites, so the equation is pretty simple.
x = ±√22
x² = 22 . . . . . square both sides
x² -22 = 0 . . . . your quadratic equation in standard form
what expression is equivalent to (-7²-x-5)-(3x²+x)
Answer:
-3x² - 2x - 54
Step-by-step explanation:
(-7²-x-5)-(3x²+x)
-7² - x - 5 - 3x² - x
-49 - x - 5 - 3x² - x
-3x² - x - x - 49 - 5
-3x² - 2x - 54
an international company has 27,100 employees in one country. if this represents 18.4% of the company's employees, how many employees does it have in total? round to nearest whole number
Solve 3 - 5(a - 4) any one who can answer in the next 3 mins plz answer
Answer:
[tex]3-5\left(a-4\right)[/tex]
[tex]-5(a-4)=-5a+20[/tex]
[tex]=3-5a+20[/tex]
[tex]=-5a+23[/tex]
OAmalOHopeO
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\text{3 - 5(a - 4)}\\\\\huge\text{\underline{\underline{DISTRUBUTE -5 within the parentheses}}}\\\\\large\text{3 - 5(a) - 5(-4)}\\\large\text{= 3 - 5a + 20}\\\\\huge\text{\underline{\underline{COMBINE the LIKE TERMS}}}\\\large\text{-5a + (3 + 20)}\\\large\text{= \bf -5a + 23}\\\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \bf -5a + 23}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!} \\\\\\\frak{Amphitrite1040:)}[/tex]
Help me this question
Answer:
(a) 218.6 N
(b) 97.14 N
Step-by-step explanation:
When the system is in equilibrium, the net torque on the system is zero.
AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m
Let the centre of gravity of plank is at G.
AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m
(a) Let the reaction at C is R and at D is R'.
R + R' = 29 x 9.8 = 284.2 N ... (1)
Take the torque about C.
29 x 9.8 x CG = R' x GD
29 x 9.8 x 1 = R' x 1.3
R' = 218.6 N
(b) Take the torque about D.
6 x 9.8 x AD = R x CD
6 x 9.8 x (1.5 + 2.3) = R x 2.3
R = 97.14 N
Which equation represents a slope of −4 and y-intercept of (0,2)?
y = −4x + 2
y = −2x
y = −2x − 4
y = 4x + 2
Answer:
y=-4x+2
Step-by-step explanation:
Hi there!
We want to find out which equation represents a line with a slope of -4 and a y intercept of (0,2)
The most common way to write the equation of the line is in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
We have everything we need to plug into the equation, let's just label the values to avoid confusion
m=-4
b=2 (when you substitute the y intercept as b, b is the value of y in the point)
Now substitute into the equation
y=-4x+2
Hope this helps!
What is the height of spanning tree obtained from Wn by the breadth-first search, starting at the central vertex of Wn?
Answer:
The height of the spanning tree is one by the breadth-first search at the central vertex of Wn.
Step-by-step explanation:
The graph is connected and has a spanning tree where the tree can build using a depth-first search of the graph. Start with chosen vertex, the graph as the root, and root add vertices and edges such as each new edge is incident with vertex and vertices are not in path. If all vertices are included, it will do otherwise, move back to the next level vertex and start passing. It is for depth-first search. For breadth-first search, start with chosen vertex add all edges incident to a vertex. The new vertex is added and becomes the vertices at level 1 in the spanning tree, and each vertex at level 1 adds each edge incident to vertex and other vertex connected to the edge of the tree as long as it does not produce.
Let f(x)= [x/3] (where f(x) is the ceiling function). We learned that the floor and the ceiling functions are NOT invertible, but we also learned about the set of preimages of any value in the Range, the set of images. Keeping that in mind, give your answer in interval notation if necessary.
a. Find f-1({5})
b. Find f-1({-2})
c. Find f-1({x | 5 = x = 9 })
d. Find f-1({x | -6 = x = -2})
(a) We have ⌊x⌋ = 5 if 5 ≤ x < 6, and similarly ⌊x/3⌋ = 5 if
5 ≤ x/3 < 6 ==> 15 ≤ x < 18
(b) ⌊x⌋ = -2 if -2 ≤ x < -1, so ⌊x/3⌋ = -2 if
-2 ≤ x/3 < -1 ==> -6 ≤ x < -3
In general, ⌊x⌋ = n if n ≤ x < n + 1, where n is any integer.
I do not understand what is being asked in (c) and (d), so you'll have to clarify...
Help please ……………….zzzz
1) I think 15 choose (d)
2) The choose (C) -4fg+4g
3) The choose (d) 3xy/2
4) The choose (a) ab/6
5) The choose (C) 2p+4q-6
6)
[tex]\pi {r}^{2} h = 3.14 \times {3}^{2} \times 1.5 = 42.39 {m}^{3} = 42.390 {m}^{3} [/tex]
Point 6 I think there is an error because the unit m must be m³ because it is r² (m²) and h(m) becomes m³.
I hope I helped you^_^
Help me please thanks guys
Answer:
B, D, F
Step-by-step explanation:
In a rational exponent, the numerator is an exponent, and the denominator becomes the index of the root.
[tex]a^{\frac{m}{n}} = \sqrt[n] {a^m}[/tex]
Answer: B, D, F
Please help me with this on the picture
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Answer:
(-5, 4)
Step-by-step explanation:
The inside corner moves from (2, -2) to (-3, 2). That is 5 is subtracted from the x-coordinate, and 4 is added to the y-coordinate. (x, y) ⇒ (x -5, y +4)
The translation vector can be written horizontally as (-5, 4), or vertically as ...
[tex]\displaystyle\binom{-5}{4}[/tex]
Four spinners are spun. Spinner 1 has outcomes Spinner 2 has outcomes Spinner 3 has outcomes Spinner 4 has outcomes The outcomes for each spinner are equally likely. is the sum of the numbers that come up on the spinners. What is the expected value of
Complete Question
Four spinners are spun. Spinner 1 has outcomes {1,2,3,4,5,6,7,8} Spinner 2 has outcomes {1,2,3,4,5,6} Spinner 3 has outcomes {1,2,3,4,5,6} Spinner 4 has outcomes {1,2,3,4,5} The outcomes for each spinner are equally likely. S is the sum of the numbers that come up on the spinners. What is the expected value of S?
Answer:
[tex]E(s)=14.5[/tex]
Step-by-step explanation:
From the question we are told that:
Spinner 1 ={1,2,3,4,5,6,7,8}
Spinner 2= {1,2,3,4,5,6}
Spinner 3 = {1,2,3,4,5,6}
Spinner 4 {1,2,3,4,5}
Generally the equation for expected outcome is mathematically given by
[tex]E(s)=\sum P(x).x[/tex]
Where
[tex]x=\frac{n(n+1)}{2}[/tex]
For Spinner 1
[tex]E(s_1)=\sum \frac{1}{8}*\frac{8(8+1)}{2}[/tex]
[tex]E(s_1)=4.5[/tex]
For Spinner 2
[tex]E(s_2)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]
[tex]E(s_2)=3.5[/tex]
For Spinner 3
[tex]E(s_2)=E(s_3)[/tex]
For Spinner 3
[tex]E(s_4)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]
[tex]E(s_4)=3[/tex]
Therefore The Expected Value
[tex]E(s)=\sum E(s 1..4)[/tex]
[tex]E(s)=4.5+2(3.5)+3[/tex]
[tex]E(s)=14.5[/tex]
[tex]\sqrt{25}[/tex]
Answer:
5
Step-by-step explanation:
Calculate the square root of 25 and get 5.
Question 6 of 11 Step 1 of 6 No Time Limit The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, û = bo + bjx, for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.
Price in Dollars 23 34 44 46 50
Number of Bids 1 2 4 9 10
Step 1 of 6: Find the estimated slope. Round your answer to three decimal places.
The estimated slope is approximately 2.344
The given table is presented as follows;
[tex]\begin{array}{ccc}Number \ of Bids &&Price \ in \ Dollars\\1&&23\\2&&34\\4&&44\\9&&46\\10&&50\end{array}[/tex]
The regression line formula to be considered = [tex]\bar u = b_0 + b\cdot \bar x[/tex]
The required parameter is;
The estimated slope
The method to find the estimate slope;
The least squares regression formula (method) is presented as follows;
[tex]\bar u = b_0 + b\cdot \bar x[/tex]
Where;
b₀ = The y-intercept
[tex]\mathbf{ b = \dfrac{\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right) }{\sum \left(x_i - \bar x\right )^2 } = The \ estimated \ slope}[/tex]
From MS Excel, we have;
[tex]\bar x[/tex] = 5.2, [tex]\bar u[/tex] = 39.4
[tex]\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right)[/tex] = 156.6
[tex]{\sum \left(x_i - \bar x\right )^2 }[/tex] = 66.8
Therefore;
The estimated slope, b = 156.6/66.8 ≈ 2.344 (by rounding the answer to three decimal places)
Learn more about regression line here;
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According to government data, the probability than an adult never had the flu is 19%. You randomly select 70 adults and ask if he or she ever had the flu. Decide whether you can use the normal distribution to approximate the binomial distribution, If so, find the mean and standard deviation, If not, explain why. Round to the nearest hundredth when necessary.
Answer:
Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.
The mean is 13.3 and the standard deviation is 3.28.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].
The probability than an adult never had the flu is 19%.
This means that [tex]p = 0.19[/tex]
You randomly select 70 adults and ask if he or she ever had the flu.
This means that [tex]n = 70[/tex]
Decide whether you can use the normal distribution to approximate the binomial distribution
[tex]np = 70*0.19 = 13.3 \geq 10[/tex]
[tex]n(1-p) = 70*0.81 = 56.7 \geq 10[/tex]
Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.
Mean:
[tex]\mu = E(X) = np = 70*0.19 = 13.3[/tex]
Standard deviation:
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.19*0.81} = 3.28[/tex]
The mean is 13.3 and the standard deviation is 3.28.
CAN SOMEONE PLEASE HELL ME WITH THIS PROBLEM? THANK YOU!!!
Answer:
71
Step-by-step explanation:
The reference angle is always the smallest angle with the x-axis.
The nearest x axis is at 0 or another name for 0 is 360
360 -289 = 71
The reference angle is 71
In an experiment, you choose to have two randomly assigned groups. In one, you take measurements both pretest and posttest; with the second, a posttest-only measure. This describes which task of conducting an experiment
Answer:
The answer is "Specific treatment levels".
Step-by-step explanation:
When we experimenting with 'level' which is related to the quantity or magnitude of treatment. For this part of an experiment or study, a group or individual is exposed to a specified set of circumstances. For example: If four categories are exposed to different doses of a given drug, then each dose reflects a level of a treatment factor in the model.
Find the measure of x. X=8, x=7, x=9, x=11
Answer:
[tex]\frac{135}{15} =\frac{15(x+2)}{15}[/tex]
[tex]9=x+2[/tex]
[tex]x=7[/tex]
OAmalOHopeO
The average mileage per gallon for cars built since 1940 approximates to the following curve 0.0075*t^2-.2672*t+14.8 where t is year -1940.
Answer the following questions:
What is the expected MPG in 2025?
How about 2050?
Is this a valid function?
Is there a top end to MPG?
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Answer:
46.3 in 202576.2 in 2050Step-by-step explanation:
The attached shows the predicted mileage for cars built in 2025 to be 46.3 mpg, 76.2 mpg for cars built in 2050.
__
No doubt, the function is valid over the time period used to derive it. It may or may not be valid for predicting MPG beyond that period.
Virtually any function that predicts future increases without bound will turn out to be unreliable at some point. In this universe, there are always limits to growth.
Please help me to find this answer
Answer:
Look in Step by Step Explanation
Step-by-step explanation:
3)SOHCAHTOA
tan=opposite/adjacent
tan(20)=x/83
83tan(20)=x
x=30.209
2) SOHCAHTOA
Tangent=opposite/adjacent
Tan(62)=x/8
8tan(62)=x
x=15.04
3)SOHCAHTOA
Sin=opposite/hypotonouse
sin(25)=30/x
x=30/sin(25)
x=70.986
Let f(x) = e ^3x/5x − 2. Find f'(0).
Answer:
Step-by-step explanation:
Our friend asking what the actual function is has a point. I completed this under the assumption that what we have is:
[tex]f(x)=\frac{e^{3x}}{5x-2}[/tex] and used the quotient rule to find the derivative, as follows:
[tex]f'(x)=\frac{e^{3x}(5)-[(5x-2)(3e^{3x})]}{(5x-2)^2}[/tex] and simplifying a bit:
[tex]f'(x)=\frac{5e^{3x}-[15xe^{3x}-6e^{3x}]}{(5x-2)^2}[/tex]and a bit more to:
[tex]f'(x)=\frac{5e^{3x}-15xe^{3x}+6e^{3x}}{(5x-2)^2}[/tex] and combining like terms:
[tex]f'(x)=\frac{11e^{3x}-15xe^{3x}}{(5x-2)^2}[/tex] and factor out the GFC in the numerator to get:
[tex]f'(x)=\frac{e^{3x}(11-15x)}{(5x-2)^2}[/tex] That's the derivative simplified. If we want f'(0), we sub in 0's for the x's in there and get the value of the derivative at x = 0:
[tex]f'(0)=\frac{e^0(11-15(0))}{(5(0)-2)^2}[/tex] which simplifies to
[tex]f'(0)=\frac{11}{4}[/tex] which translates to
The slope of the function is 11/4 at the point (0, -1/2)
If sin(x) = 1 and cos(x) = 0, what is cot(x)?
0
1
undefined
Answer:
It's 0
Edge said it's 0
The value of the ratio of the cos(x) and the sin(x) is 0.
Trigonometric ratios are mathematical functions that relate the angles of a right triangle to the ratios of the lengths of its sides. These ratios are fundamental in trigonometry and have applications in various fields, such as physics, engineering, and navigation.
Trigonometry is a branch of mathematics that deals with the relationships and properties of angles and triangles. It explores the ratios between the sides of a triangle and the angles within that triangle. The word "trigonometry" is derived from two Greek words: "trigonal," meaning "triangle," and "metron," meaning "measure."
The value of the sin(x) is 1. The value of cos(x) is 0.
The formula for the cot(x) is written below:
cot(x) = cos(x) / sin(x)
cot(x) = 0 / 1
cot(x) = 0
To know more about trigonometry follow
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PLEASE HELPP ASAP!!
5.(06.02 MC)
Line BC contains points B (4, -5) and C (3, 2). Line DE contains points D (2,0) and E (9, 1). Lines BC and DE are (1 point)
parallel
perpendicular
neither
Answer:
Answer: Option A.
Step-by-step explanation:
Hey there!
Given; The Line BC contains points B (4, -5) and C (3, 2).
And the Line DE contains points D (2,0) and E (9, 1)
Note: Use double point formula for finding the equation and then find slopes of both then put the condition for perpendicular lines and parallel lines.
From line BC;
The points are B (4, -5) and C (3, 2).
Using double point formula;
[tex](y - y1) = \frac{y2 - y1}{x2 - x1}(x - x1) [/tex]
Keep all the value;
[tex](y + 5) = \frac{2 + 5}{3 - 4} (x - 4)[/tex]
Simplify it;
[tex]y + 5 = - 7x + 28[/tex]
Therefore, the equation is y = -7x+23........(I)And slope(m1) is -7 {comparing the equation (I) with y=Mx+c}
Again;
The points D (2,0) and E (9, 1)
Using double point formula;
[tex](y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)[/tex]
Keep all values;
[tex](y - 0) = \frac{9 - 2}{1 - 2} (x - 2)[/tex]
[tex]y = - 7x + 14[/tex]
Therefore, the equation is y = -7x+14......(ii)And the slope (m2) is -7. {comparing the equation (ii) with y= mx+c}
Check:
For parallel lines:
m1= m2
-7 = -7 (true)
Therefore, the lines are parallel.
Hope it helps!
Yooooo HELPPP
with this question plz
Answer:
Step-by-step explanation:
(x-2)(x+4)=x^2+4x-2x-8=0=> x =2, x=0
Answer:
A
Step-by-step explanation:
Solve the initial-value problem using the method of undetermined coefficients.
y'' − y' = xe^x, y(0) = 6, y'(0) = 5
First check the characteristic solution. The characteristic equation to this DE is
r ² - r = r (r - 1) = 0
with roots r = 0 and r = 1, so the characteristic solution is
y (char.) = C₁ exp(0x) + C₂ exp(1x)
y (char.) = C₁ + C₂ exp(x)
For the particular solution, we try the ansatz
y (part.) = (ax + b) exp(x)
but exp(x) is already accounted for in the second term of y (char.), so we multiply each term here by x :
y (part.) = (ax ² + bx) exp(x)
Differentiate this twice and substitute the derivatives into the DE.
y' (part.) = (2ax + b) exp(x) + (ax ² + bx) exp(x)
… = (ax ² + (2a + b)x + b) exp(x)
y'' (part.) = (2ax + 2a + b) exp(x) + (ax ² + (2a + b)x + b) exp(x)
… = (ax ² + (4a + b)x + 2a + 2b) exp(x)
(ax ² + (4a + b)x + 2a + 2b) exp(x) - (ax ² + (2a + b)x + b) exp(x)
= x exp(x)
The factor of exp(x) on both sides is never zero, so we can cancel them:
(ax ² + (4a + b)x + 2a + 2b) - (ax ² + (2a + b)x + b) = x
Collect all the terms on the left side to reduce it to
2ax + 2a + b = x
Matching coefficients gives the system
2a = 1
2a + b = 0
and solving this yields
a = 1/2, b = -1
Then the general solution to this DE is
y(x) = C₁ + C₂ exp(x) + (1/2 x ² - x) exp(x)
For the given initial conditions, we have
y (0) = C₁ + C₂ = 6
y' (0) = C₂ - 1 = 5
and solving for the constants here gives
C₁ = 0, C₂ = 6
so that the particular solution to the IVP is
y(x) = 6 exp(x) + (1/2 x ² - x) exp(x)
Which of the answer choices has matrix multiplication defined?
Answer:
AB
Step-by-step explanation:
For the multiplication of two matrices to be defined then the number of columns of the first matrix must be equal to the number of rows of the second matrix. For example, 2*3 and 3*2 matrices can be multiplied since the number of columns of the first matrix must be equal to the number of rows of the second matrix.
Matrix A = 2*2
Matrix B = 2*3
Matrix C = 3*3
Matrix D = 1 * 3
From the matrices given, we can see that the matrices that can be multiplied together are AB and BC since the number of columns of the first matrix must be equal to the number of rows of the second matrix. Hence the correct option is AB
The access code for a vault consists of four digits. The first digit
must be even and the last digit cannot be a zero. How many possible
codes are there?
Answer:
5 * 10 * 10 * 9 = 4500
Step-by-step explanation:
I need you guy’s help answer thanks so much
Dưới đây là bảng CĐKT gần đây nhất của VNA:
ĐVT: tỷ đồng
TÀI SẢN
NGUỒN VỐN
Tài sản lưu động
Tài sản cố định
Tổng tài sản
11.30
21.35
32.65
Nợ ngắn hạn (NH)
Nợ dài hạn
Vốn cổ phần ưu đãi
Vốn cổ phần thường
Tổng nguồn vốn
10.69
9.46
2.50
10.00
32.65
Biết: Nợ NH không chịu bất kỳ khoản phí nào, chi phí trung bình nợ NH sau thuế là 5.5%;
Chi phí nợ dài hạn trước thuế là 11.5%;
Tỷ suất sinh lời cần thiết trên vốn cổ phần ưu đãi là 13.5%; hệ số beta = 1,25
Tỷ suất lợi nhuận cho rủi ro thị trường là 8%; tỷ lệ lãi suất trái phiếu cũng 8%
Thuế TNDN là 32%.
Yêu cầu:
Tính chi phí vốn của mỗi nguồn nợ ngắn hạn, nợ dài hạn, vốn cổ phần ưu đãi, vốn cổ phần phổ thông?
Tính chi phí bình quân gia quyền vốn WACC của VNA?