Answer:
(x, y) = (-3, -6)
Step-by-step explanation:
The (x, y) distance from R to T is ...
(Δx, Δy) = T - R = (3, -3) -(-5, -7) = (3 -(-5), -3 -(-7)) = (8, 4)
Then 1/4 of the distance is ...
(Δx, Δy)/4 = (8, 4)/4 = (2, 1)
This is added to the R coordinates to find the desired point:
point = R +(2, 1) = (-5, -7) +(2, 1) = (-5+2, -7+1) = (-3, -6)
The coordinates are ...
x-coordinate: -3
y-coordinate: -6
1. You have a home business selling designer necklaces. You have done
some market research, which shows that at a price of $40 you can sell
500 per week, and at a price of $60 you can sell 400 per week. Assuming
that the relationship between price and quantity sold is linear, find the
price that maximizes revenue. You must use methods that we developed
and practiced in the course. You will be graded not only on your answer
but on the clarity of your presentation.
Answer:
The price that maximizes the profits from the sale of the product is $60.
Step-by-step explanation:
Since selling necklaces at $ 40 allows a total amount of 500 sales per week, while a price of $ 60 allows 400 sales at the same time, the following calculations must be made to determine the price that maximizes sales performance:
40 x 500 = $ 20,000
60 x 400 = $ 24,000
50 x 450 = $ 22,500
55 x 425 = $ 23,375
58 x 410 = $ 23,780
59 x 405 = $ 23,895
As can be seen from the calculations developed, the price that maximizes the profits from the sale of the product is $60.
Bytecoin is a new cryptocurrency that is currently valued at $243 per coin. You want to make an investment and purchase 1 Bytecoin and cash out when its value reaches $1,000. Over the last 12 months, you ve seen the value of the Bytecoin grow exponentially at a rate of 15% per month! You want all of your friends and family to invest with you, but you need to make predictions about how long it will take for your $243 investment to earn $1,000. Write an exponential equation in the form y = a * b ^ x and explain what a and b represent
Answer:
Step-by-step explanation:
The growth rate of the coin is exponential. We would apply the formula for exponential growth which is expressed as
y = ab^x
y = b(1 + r)^ t
Where
y represents the value of the coin after x months.
x represents the number of months.
a represents the initial value of the coin.
b represents rate of growth.
From the information given,
a = 243
b = 1 + 15/100 = 1 + 0.15 = 1.15
Therefore, the exponential expression to determine the number of months, x it will take for the coin to attain a certain value, y is expressed as
y = 243(1.15)^x
If y = 1000, it means that
1000 = 243(1.15)^x
1000/243 = 1.15^x
4.115 = 1.15^x
Taking log of both sides, it becomes
log 4.115 = xlog1.15
0.614 = 0.061x
x = 0.614/0.061
x = 10 months
It will take 10 months
Find an Equation of a line with the given slope that passes through the point. Write the equation in the form Ax + By=C
M=3/2, (7,-2) -problem
Bridge math sails
Module 4B2
Answer:
c = 24 can i get brainliest
Step-by-step explanation:
Does anyone know this?
How can sums and differences of cubes be identified for factoring?
Answer:
Step-by-step explanation:
The sum of two perfect cubes breaks down into two factors, the first is the sum of their cube roots, and the second is made up of the square of the first root minus the product of both roots plus the square of the second root.
The difference of two perfect cubes is decomposed into two factors, the first is the difference of their cube roots, and the second is made up of the square of the first root plus the product of both roots plus the square of the second root.
Which expression is equivalent to (2g^3+4)^2
[tex]answer \\ 4g ^{6} + 16 \\ solution \\ ( {2g}^{3} + 4)^{2} \\ = 2 \times 2 \: g ^{3 \times 2} + 4 \times 4 \\ = 4 {g}^{6} + 16 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment[/tex]
Answer:
4g^6+16 IS equivalent to (2g^3+4)^2
The probability that a member of a certain class of homeowners with liability and property coverage will file a liability claim is 0.04, and the probability that a member of this class will file a property claim is 0.10. The probability that a member of this class will file a liability claim but not a property claim is 0.01. Calculate the probability that a randomly selected member of this class of homeowners will not file a claim of either type.
Answer:
The probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.
Step-by-step explanation:
Denote the events as follows:
X = liability claim will be filled
Y = property claim will be filled
The information provided is:
P (X) = 0.04
P (Y) = 0.10
P (X ∩ Y') = 0.01
The probability that a randomly selected member of the class of homeowners will not file a claim of either type will be given by:
[tex]P[(X\cup Y)']=1-P(X\cup Y)=1-[P(X)+P(Y)-P(X\cap Y)][/tex]
According to the law of total probability:
[tex]P(B)=P(B\cap A)+P(B\cap A')[/tex]
Use the law of total probability to determine the value of P (X ∩ Y) as follows:
[tex]P(X)=P(X\cap Y)+P(X\cap Y')\\\\P(X\cap Y)=P(X)-P(X\cap Y')\\\\=0.04-0.01\\\\=0.03[/tex]
The value of P (X ∩ Y) is 0.03.
Compute the value of P (X ∪ Y) as follows:
[tex]P[(X\cup Y)']=1-P(X\cup Y)[/tex]
[tex]=1-[P(X)+P(Y)-P(X\cap Y)]\\\\=1-[0.04+0.10-0.03]\\\\=1-0.11\\\\=0.89[/tex]
Thus, the probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.
Bob has 54 more five-dollar bills than ten-dollar bills. The number of five-dollar bills he has
is 7 times that of ten-dollar bills. How many dollars does Bob have in all?
Answer:5000 sum
Step-by-step explanation:
Can someone please help me with this question the first one
A candidate scored 32 marks out of 80,
find his percentage score.
A. 20% B.32% 0.40% D. 48% E80%
Answer:
40%
Step-by-step explanation:
you need to divide 80 by 8 to get 10 and then divide 32 by 8 aswell. this gives you 4/10 which is equivalent to 40/100 or 40%
Candidate percent scored is, 40%.
What is mean by Percentage?A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.
Given that;
A candidate scored 32 marks out of 80.
Now, Total marks = 80
And, A candidate score = 32
Hence, The percent score is,
⇒ 32 / 80 × 100
⇒ 3200 / 80
⇒ 40%
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Consider the following geometric series.
[infinity]∑n=1 (−8)n−19n
a) Find the common ratio.
b) Determine whether the geometric series is convergent or divergent.
c) If it is convergent, find its sum. (If the quantity diverges, answer diverges.)
Answer:
a) -8/9
b) The series is a convergent series
c) 1/17
Step-by-step explanation:
The series a+ar+ar²+ar³⋯ =∑ar^(n−1) is called a geometric series, and r is called the common ratio.
If −1<r<1, the geometric series is convergent and its sum is expressed as ∑ar^(n−1) = a/1-r
a is the first tern of the series.
a) Rewriting the series ∑(-8)^(n−1)/9^n given in the form ∑ar^(n−1) we have;
∑(-8)^(n−1)/9^n
= ∑(-8)^(n−1)/9•(9)^n-1
= ∑1/9 • (-8/9)^(n−1)
From the series gotten, it can be seen in comparison that a = 1/9 and r = -8/9
The common ratio r = -8/9
b) Remember that for the series to be convergent, -1<r<1 i.e r must be less than 1 and since our common ratio which is -8/9 is less than 1, this implies that the series is convergent.
c) Since the sun of the series tends to infinity, we will use the formula for finding the sum to infinity of a geometric series.
S∞ = a/1-r
Given a = 1/9 and r = -8/9
S∞ = (1/9)/1-(-8/9)
S∞ = (1/9)/1+8/9
S∞ = (1/9)/17/9
S∞ = 1/9×9/17
S∞ = 1/17
The sum of the geometric series is 1/17
Find the value of the logarithm.
log 110
Round your answer to the nearest thousandth.
Answer:
Log 110 = 2.041
Step-by-step explanation:
Log 110 can be simplified and reduced to
Log 110 = log (10*11)
Log 110 = log10 + log11
But log10 = 1
Log 11= unknown = x
10^x= 11
X= 1.0413926
Log 110 = 1+1.0413926
Log110 = 2.0413926
Log 110 = 2.041
What is the product?
(45+2)(5s2+ 10s+3)
Answer:
your answer is 127596 because you would take (45+2) first then you would take (55^2+10s+3) then you multiply them
Step-by-step explanation:
Examine the details of the chi‑square test and conclude in context. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence in the study among those drinking cranberry juice daily. The conditions for inference are not met. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence among those abstaining from both drinks. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence among those drinking Lactobacillus drink. There is good evidence (cite P-value) that, in the population of women just treated for a UTI, women drinking cranberry juice daily have fewer UTI recurrences, on average. Question Source: Baldi 4e - The Practice Of Statistics
Answer:
Step-by-step explanation:
We will examine and outline the details of this chi-square test and then conclude in context.
(A) A population of women have just been treated for a urinary tract infection.
(B) Since the chi-square test is done for categorical variables, we will pick out the variable involved here.
That variable is: "UTI Recurrence"
Hence, we are looking at the recurrence of a urinary tract infection, among samples of the population of women who have recently been treated of it.
(C) There are three samples from this population and they are distinguished thus:
SAMPLE 1: Those drinking cranberry juice daily
SAMPLE 2: Those taking lactobacillus drink
SAMPLE 3: Those abstaining from both drinks (the placebo sample)
(D) The result of the test gave good evidence that SAMPLE 1 has the lowest value of the categorical variable involved; as compared to the values from SAMPLE 2 and SAMPLE 3.
In other words, on the average (average here is equal to mode or frequency of occurrence of the variable), the lowest number of UTI recurrences stems from Sample 1, as compared to the numbers of UTI recurrences in the other two samples
are supplementary angles, then
A) Both should be acute B) Both should be obtuse C) one acute other right D) None of these
Answer:
D
Step-by-step explanation:
Answer:
D) None of these
Step-by-step explanation:
Supplementary pairs must equal to 180 degrees. They can either be made up of two right angles, or one acute and one obtuse angle.
Find the x-intercept(s) and the coordinates of the vertex for the parabola.
Answer:
see explanation
Step-by-step explanation:
Given
y = x² - 2x - 8
To find the x- intercepts let y = 0 , that is
x² - 2x - 8 = 0 ← in standard form
(x - 4)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x + 2 = 0 ⇒ x = - 2
x- intercepts : x = - 2, x = 4
The x- coordinate of the vertex is mid way between the x- intercepts, that is
[tex]x_{vertex}[/tex] = [tex]\frac{-2+4}{2}[/tex] = [tex]\frac{2}{2}[/tex] = 1
Substitute x = 1 into the equation for corresponding y- coordinate
y = 1² - 2(1) - 8 = 1 - 2 - 8 = - 9
vertex = (1, - 9 )
A typical classroom is a rectangle with dimensions of 20 feet wide by 25 feet long, and the area needed for each person in the room is approximately 28 square feet, what fraction of the total area in a classroom is needed for each person? What is the largest number of people that would fit in an average sized classroom while practicing good social distancing?
Answer:
A fraction of 0.056 of the classroom is needed for each student.
A typical classroom can acomodate up to 17 persons while practicing good social distancing.
Step-by-step explanation:
We have a classroom that is a recatngle with dimensions of 20 feet wide by 25 feet long.
The total area of the classroom is:
[tex]A=w\cdot l=20\cdot25=500[/tex]
As the area of the classromm is 500 square feet and we need 28 square feet for each student, the fraction that is needed for each student is:
[tex]f=\dfrac{A_{\text{student}}}{A_{\text{classroom}}}=\dfrac{28}{500}=0.056[/tex]
A fraction of 0.056 of the classroom is needed for each student.
The largest number of students that would fit in an average sized classroom while practicing good social distancing can be calculated dividing the area of the classroom by the area needed for each student. This is equal to the inverse of the fraction calculated previously:
[tex]n=\dfrac{1}{f}=\dfrac{1}{0.056}\approx17.86[/tex]
A typical classroom can acomodate up to 17 persons while practicing good social distancing.
What is the value of y at the point where the graph of an equation crosses the x-axis?
Answer:
0
Step-by-step explanation:
The x-axis corresponds to the line y = 0. All points on the x-axis have a y-value of zero.
In a group of 50 patrons, 14 patrons like lattes and espressos, 11 patrons like
espressos and cappuccinos, 7 patrons like lattes and cappuccinos, and 3
patrons like all 3 coffee drinks. Altogether, 22 patrons like lattes, 30 patrons
like espressos, and 23 patrons like cappuccinos. How many patrons don't like
any of these coffee drinks?
Answer:the answer would be 4. Hope this helps.
Step-by-step explanation:
Using the formula of union of three events, the number of patrons who didn't like any of given coffee drinks = 4.
What is union of three events?Union of three events : P(A ∪ B ∪ C) = P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C).
n (latte ∩ espressos) = 14
n (espressos ∩ cappuccinos) = 11
n (lattes ∩ cappuccinos) = 7
n (latte ∩ espressos ∩ cappuccinos) = 3
n (lattes) = 22
n (espressos) = 30
n (cappuccinos) = 23
n(latte ∪ espressos ∪ cappuccinos) =
= n (lattes) + n (espressos) + n (cappuccinos) - n (latte ∩ espressos) - n (espressos ∩ cappuccinos) - n (lattes ∩ cappuccinos) + n (latte ∩ espressos ∩ cappuccinos)
= 22 + 30 + 23 - 14 - 11 - 7 + 3
= 46
n (universe) = 50
Number of patrons who didn't like any of these drinks =
= n (universe) - n (latte ∪ espressos ∪ cappuccinos) = 50 - 46 = 4
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A researcher conducts two studies. Study 1 uses a one-way between-subjects ANOVA. and Study 2 uses a within-subjects ANOVA. If the number of groups and participants per group are the same in each study, then in which study was the total number of participants larger? Explain.
Answer:
One way between subjects ANOVA
Step-by-step explanation:
In the between groups ANOVA, different people tests each conditions corresponding to the variables in the study while for the within groups ANOVA, the same person tests for all conditions corresponding to the variables. This way the total number of participants will be larger in the between subjects ANOVA group.
What is the sum of 1/6 and 1/7
1/6 + 1/7 = 13/42
aka: 7/42 + 6/42
Answer:
13/42
Step-by-step explanation:
1/6 + 1/7
We need a common denominator of 42
1/6 *7/7 + 1/7 *6/6
7/42 + 6/42
13/42
intext:"A shipment of 50 inexpensive digital watches, including 6 that are defective, is sent to a department store. The receiving department selects 10 at random for testing and rejects the whole shipment if 1 or more in the sample are found defective. What is the probability that the shipment will be rejected?"
Answer:
0.7125
Step-by-step explanation:
The binomial distribution with parameters n and p is the discrete probability distribution of the number of successes (with probability p) in a sequence of n independent events.
The probability of getting exactly x successes in n independent Bernoulli trials = [tex]n_{C_{x}}(p)^x(1-p)^{n-x}[/tex]
Total number of watches in the shipment = 50
Number of defective watches = 6
Number of selected watches = 10
Let X denotes the number of defective digital watches such that the random variable X follows a binomial distribution with parameters n and p.
So,
Probability of defective watches = [tex]\frac{X}{n}=\frac{6}{50}=0.12[/tex]
Take n = 10 and p = 0.12
Probability that the shipment will be rejected = [tex]P(X\geq 1)=1-P(X=0)[/tex]
[tex]=1-n_{C_{x}}(p)^x(1-p)^{n-x}\\=1-10_{C_{0}}(0.12)^0(1-0.12)^{10-0}[/tex]
Use [tex]n_{C_{x}}=\frac{n!}{x!(n-x)!}[/tex]
So,
Probability that the shipment will be rejected = [tex]=1-\left ( \frac{10!}{0!(10-0)!} \right )(0.88)^{10}[/tex]
[tex]=1-(0.88)^{10}\\=1-0.2785\\=0.7125[/tex]
These items are taken from the financial statements of Sean McCann, CPA for 2019. Sean McCann, capital 1/1/19 $106,000 Sean McCann, Drawing 10,000 Equipment 130,000 Accumulated depreciation (equip) 32,000 Accounts payable 10,600 Cash 33,800 Supplies 7,000 Salaries payable 6,000 Fees earned 136,000 Salaries expense 66,000 Rent expense 14,200 Supplies expense 1,600 Depreciation expense 4,000 Utilities expense 2,400 Accounts receivable 28,000 Mortgage payable (due 12/31/35) 6,400 Instructions: 1. Prepare the journal entries to close your temporary accounts. (Hint: The temporary accounts are revenues, expenses and the drawing account) Date Description Debit Credit 2. Prepare an income statement and a statement of owner’s equity for the year ended December 31, 2019 and a classified balance sheet as of December 31, 2019. Sean McCann, CPA Income Statement For year ended 12/30/19 Sean McCann, CPA Statement of Owner’s Equity For Period Ended 12/31/19 Sean McCann, CPA Balance Sheet For Period Ended 12/30/19
Answer:
1. Prepare the journal entries to close your temporary accounts.
the journal entries required to close the temporary accounts are:
December 31, 2019, closing of temporary revenue accounts
Dr Fees earned 136,000
Cr Income summary 136,000
December 31, 2019, closing of temporary expense accounts
Dr Income summary 88,200
Cr Salaries expense 66,000
Cr Rent expense 14,200
Cr Supplies expense 1,600
Cr Depreciation expense 4,000
Cr Utilities expense 2,400
December 31, 2019, closing of temporary income summary account
Dr Income summary 88,200
Cr Retained earnings 88,200
December 31, 2019, closing of drawings account
Dr Retained earnings 10,000
Cr Sean McCann, Drawing 10,000
2. Prepare an income statement and a statement of owner’s equity for the year ended December 31, 2019 and a classified balance sheet as of December 31, 2019.
Sean McCann, CPA
Income Statement
For the Year Ended December 31, 2019
Fees earned $136,000
Salaries expense ($66,000)
Rent expense ($14,200)
Supplies expense ($1,600)
Depreciation expense ($4,000)
Utilities expense ($2,400)
Net income $47,800
retained earnings = net income - drawings = $47,800 - $10,000 = $37,800
Sean McCann, CPA
Balance Sheet
For the Year Ended December 31, 2019
Assets
Current assets:
Cash $33,800
Accounts receivable $28,000
Supplies $7,000
Total current assets $68,800
Non-current assets:
Equipment $130,000
Accumulated dep. (equip)-$32,000
Total non-current assets $98,000
Total assets $166,800
Liabilities and equity
Current liabilities:
Accounts payable $10,600
Salaries payable $6,000
Total current liabilities $16,600
Long term liabilities:
Mortgage payable $6,400
Total long term liabilities: $6,400
Equity
Sean McCann, capital $106,000
Retained earnings $37,800
Total equity $143,800
Total liabilities and equity $166,800
Sean McCann, CPA
Statement of Owner’s Equity
For the Year Ended December 31, 2019
Sean McCann, capital 1/1/19 $106,000
Net income $47,800
Subtotal $153,800
Drawings during the year -$10,000
Sean McCann, capital 1/1/19 $143,800
The function g is defined by g(x) = 1/2x - 1. What is
the value of g(6) ?
Answer:
2
Step-by-step explanation:
g(x) = 1/2x - 1
g(6= 1/2*6-1= 3-1= 2
Solve for x. 6−x3=3 x=9 x=−9 x=27 x=−27
52 is what percent of 93?
Answer:
55.9139785%
Step-by-step explanation:
Is means equals and of means multiply
52 = P * 93
Divide each side by 93
52/ 93 = P
.559139785
Change to percent form
55.9139785%
what is the radius diameter of the following circle?
Answer:
radius=7
diameter =2×radius
d=2×7
diameter=14
Answer:
Hello!
The answer is-
Radius: 7
Diameter: 14
Step-by-step explanation:
Diameter:
2*(radius)
d=2(7)
Diameter is 14
theo started to solve the quadratic equation (x+2)2 - 9 = -5
Answer:2x−5=−5
Add 5
to both sides of the equation.
2x=−5+5
Add −5
and 5
.
2x=0
Divide each term by 2
and simplify.
Divide each term in 2x=0
by 2
.
2x2=02
Cancel the common factor of 2
.
Cancel the common factor.
2
x2=02
Step-by-step explanation:
Apply the distributive property.
x⋅2+2⋅2−9=−5
Move 2
to the left of x
.
2⋅x+2⋅2−9=−5
Multiply 2
by 2
.
2x+4−9=−5
Subtract 9
from 4
.
Please answer this correctly
Answer:
Area of the figure = 169.5 yards²
Step-by-step explanation:
Area of Rectangle = Length × Width
Area of triangle = 1/2(base × height)
We'll divide the whole figure into parts so that we can find the area more easily!
Rectangle 1 (uppermost):
10 × 4 = 40 yards²
Square 1 (right below the rectangle 1):
7 × 7 = 49 yards²
Rectangle 2 (with square 1):
7 × 3 = 21 yards²
Triangle 1 (Below rectangle 2):
1/2(17 × 7) = 119/2 = 59.5 yards²
Now adding up all to get the area of the whole figure:
Area of the figure = 40 + 49 + 21 + 59.5
Area of the figure = 169.5 yards²
Given: AB || DE , AD bisects BE.
Prove: ABC = DEC using the ASA postulate.
Answer:
As per ASA postulate, the two triangles are congruent.
Step-by-step explanation:
We are given two triangles:
[tex]\triangle ABC[/tex] and [tex]\triangle DEC[/tex].
AD bisects BE.
AB || DE.
Let us have a look at two properties.
1. When two lines are parallel and a line intersects both of them, then alternate angles are equal.
i.e. AB || ED and [tex]\angle B[/tex] and [tex]\angle E[/tex] are alternate angles [tex]\Rightarrow[/tex] [tex]\angle B = \angle E[/tex].
2. When two lines are cutting each other, angles formed at the crossing of two, are known as Vertically opposite angles and they are are equal.
[tex]\Rightarrow \angle ACB = \angle DCE[/tex]
Also, it is given that AD bisects BE.
i.e. EC = CB
1. [tex]\angle B = \angle E[/tex]
2. EC = CB
3. [tex]\angle ACB = \angle DCE[/tex]
So, we can in see that in [tex]\triangle ABC[/tex] and [tex]\triangle DEC[/tex], two angles are equal and side between them is also equal to each other.
Hence, proved that [tex]\triangle ABC[/tex] [tex]\cong[/tex] [tex]\triangle DEC[/tex].
