Polygon ABCDE is the first in a pattern for a high school art project. The polygon is transformed so that the image of A' is at (−2, 2) and the image of D' is at (−3, 0). Which transformation can be used to show that ABCDE and its image are congruent?

Answer:

width is 30, and the length 69.

Step-by-step explanation:

In order to do this, we need to do ALGOOBRAA

lets say x is equal to the width of the room

then, that means the length is (9+2x) Sooooo,

198=2x+2(9+2x)

Using the distributive property, we know that

2(9+2x)=18+4x

If you dont know what that is, then go search it up :/

so,

198=2x+18+4x

198=6x+18

180=6x

30=x

BAM

Now, we know that the width is 30, bro.

That means the length is 60+9, Which is 69.

Therefore, the width is 30, and the length 69.

Sry if im wrong btw.

The width of rectangle is 30, and the length is 69.

A rectangle is a quadrilateral. The opposite sides of a rectangle are equal and parallel to each other. The interior angle of a rectangle at each vertex is 90°. The sum of all interior angles is 360°. The diagonals bisect each other.

Here, lets say x is equal to the width of the room

then, that means the length is (9+2x) So,

              198 = 2x+2(9+2x)

Using the distributive property, we know that

                 2(9+2x)=18+4x

If you don't know what that is, then go search it up :/

so,

               198 = 2x+18+4x

                198=6x+18

                 180=6x

                  30=x

Now, we know that the width is 30,

That means the length is 60+9, Which is 69.

Thus, the width of rectangle is 30, and the length is 69.

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The value of [tex]38 \frac{22}{75} + 3\frac{11}{15}[/tex] is [tex]42\frac{2}{75}[/tex]

The summation expression is given as:

[tex]38 \frac{22}{75} + 3\frac{11}{15}[/tex]

Rewrite as:

[tex]38 + 3 + \frac{22}{75} + \frac{11}{15}[/tex]

Evaluate the sum and take LCM

[tex]41 + \frac{22 + 5 * 11}{75}[/tex]

Evaluate the sum

[tex]41 + \frac{77}{75}[/tex]

Express as mixed number

[tex]41 + 1\frac{2}{75}[/tex]

Add

[tex]42\frac{2}{75}[/tex]

Hence, the value of [tex]38 \frac{22}{75} + 3\frac{11}{15}[/tex] is [tex]42\frac{2}{75}[/tex]

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Answer:

see the attachment photo!

The correct representations of this solution is {n | n > 3} an open circle appears at positive 3.

Inequalities are expressions not separated by an equal sign. Given the inequality

6 + 2n > 12

Subtract 6 from both sides

2n > 12 - 6

2n >6

Divide both sides by 2

2n/2 >6/2

n >3

Hence the correct representations of this solution is {n | n > 3} an open circle appears at positive 3.

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The value of x in the segment is 3

Using the secant and segment theorem, we have:

x * (x + 21) = (x + 1) * (x + 1 + 14)

Evaluate the sum

x * (x + 21) = (x + 1) * (x + 15)

Expand

x^2 + 21x = x^2 + 15x + x + 15

Subtract x^2 from both sides

21x = 15x + x + 15

Evaluate the like terms

5x = 15

Divide both sides by 5

x = 3

Hence, the value of x is 3

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The distance of the first truck from the fire is 0.578 mile and the distance of the second truck from fire is 0.722 mile.

Using sine rule, we find the length of AB and BC as shown in the image.

a/sin A = b/sin B = c/sin C

Angle C = 180 - (58 + 52) = 70⁰

1.3/(sin 70) = b/(sin 52)

b = (1.3sin 52) / (sin 70)

b = 1.09 mile

c = (1.3sin 58) / (sin 70)

c = 1.1732 miles

Bisect angle C, and use sine rule again to find the lengths of bisected line AB.

1.09/(sin 90) = x/[sin (90 - 58)]

1.09/(sin 90) = x/(sin 32)

x = (1.09 sin 32)/(sin 90)

x = 0.578 mile

Truck B's position from the fire = 1.3 miles - 0.578 mile = 0.722 mile

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Answer: [tex]\frac{1}{7^{2}}[/tex]

Step-by-step explanation:

Using the exponent rule [tex]a^{b} \cdot a^{c}=a^{b+c}[/tex], we get that

[tex]7^{3} \cdot 7^{-5}=7^{-2}[/tex]

Then, using the exponent rule [tex]a^{-b}=\frac{1}{a^b}[/tex], we get that

[tex]7^{-2}=\boxed{\frac{1}{7^{2}}}[/tex]

Therefore, the equation of the hyperbola with a given origin has vertices at (0, ±9) and foci at  (0, ±10) is [tex]\frac{x^{2} }{81}-\frac{y^{2} }{19} =1[/tex].

Given, that a hyperbola centred at the origin has vertices at (0, ±9)  and foci at  (0, ±10).

In mathematics, a hyperbola is a type of smooth curve lying in a plane, defined by its geometric properties or by equations for which it is the solution set. A hyperbola has two pieces, called connected components or branches, that are mirror images of each other and resemble two infinite bows.

The formula for a hyperbola centred at the origin is [tex]\frac{(x-h)^{2} }{a^{2} } -\frac{(y-k)^{2} }{b^{2} } =1[/tex]

Where (h, k) is the center = (0, 0)

Distance from centre to vertices a = 9 ⇒ a² = 81

Distance from centre to vertices which is given from the foci c = 10

⇒ c² = 100

Using the Pythagorean formula, c²= a²+ b²

Substituting the values 100 = 81 + b²

So we get, b²= 100 - 81 = 19

Substituting the values in the standard form [tex]\frac{x^{2} }{81}-\frac{y^{2} }{19} =1[/tex].

Therefore, the equation of the hyperbola with a given origin has vertices at (0, ±9) and foci at  (0, ±10) is [tex]\frac{x^{2} }{81}-\frac{y^{2} }{19} =1[/tex].

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Answer:

540,000 cubic centimeters

Step-by-step explanation:

1 meter and 20 centimeters is equal to 120 centimeters.

[tex]120 \times 90 \times 50 = 540000[/tex]

The equation of line is y = 3x + 3 that passes throgh the provided points option (C) y = 3x + 3 is correct.

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

The options are missing.

The options are:

A) y = 3x - 3

B) y = -3x + 3

C) y = 3x + 3

D) y = -3x - 3

From the points [tex]\left(-2,3\right)[/tex] and [tex]\left(-1,0\right)[/tex]:

[tex]\rm y\ =\ \dfrac{3}{-1+2}\left(x+1\right)[/tex]

y = 3(x + 1)

y = 3x + 3

Thus, the equation of line is y = 3x + 3 that passes throgh the provided points option (C) y = 3x + 3 is correct.

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Step-by-step explanation:

2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2)

2x+4+5x+25=4x-32+2x-4

7x+29=6x-36

7x-6X=-36-29

X=-65

Answer:

x = -65

Step-by-step explanation:

2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2) ​

Distribute:

2(x + 2): 2x + 4

5(x + 5): 5x + 25

=

4(x - 8): 4x - 32

2(x - 2): 2x - 4

Combine like terms:

(2x + 4) + (5x + 25) = (4x - 32) + (2x - 4)

5x + 2x: 7x              =  4x + 2x: 6x

4 + 25 = 29             =  -32 - 4: -36

7x + 29 = 6x - 36

Now we want to separate like terms,

subtract 29 from both sides

subtract 6x from both sides

7x + 29 - 29 - 6x = 6x - 29 - 6x- 36

7x - 6x = - 29 - 36

x = -65

the correct options are:

Here we have the function:

[tex]F(x) = -\sqrt[3]{x}[/tex]

First, this is a cubic root, so its domain is the set of all real numbers (same for the range). And we know that the cubic root is an increasing function, so if we put a negative sign before it, we will have a decreasing function.

Then the correct options are:

The fourth option is incomplete, so we can't conclude if it is true or not, it would be true if it said:

"The function is a reflection over the x-axis of y = ∛x"

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Answer:

b, c, d

Step-by-step explanation:

Answer:

The range of the function f(x) :  is y > 0.

The correct option is (A)

Step-by-step explanation:

The definition of range is the set of all possible values that the function will give when we give in the domain as input.

Given function is :

If we draw the graph for this, then we can see that the horizontal asymptote is 0.

So,  the range is real numbers higher than 0.

Hence, the range should be y > 0.

Step-by-step explanation:

I'm going to assume you mean

[tex]log(5^{125})[/tex] which can be rewritten as [tex]125 log(5)[/tex] since if you start with [tex]log(a) = x = > 10^x=a\\(10^x)^c=a^c\\c *log(a^c)[/tex]since when you do (10^x)^c you're just multiplying the exponent which is represented by the x but is equal to the log you just multiply the log which is why you can bring it in front.

You can then approximate the value of log(5) using a calculator and multiply by 125 to get around 87.371

The option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7], and the range is R: [–5, 1]

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have an ellipse equation:

[tex]\rm x^{2}+4y^{2}-2x+16y-19=0[/tex]

We can write the above equation as:

[tex]\rm \dfrac{\left(x-1\right)^{2}}{36}+\dfrac{\left(y+2\right)^{2}}{9}=1[/tex]

The domain will be:

D: [–5, 7]

The range will be:

R: [–5, 1]

Thus, the option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7] and the range is R: [–5, 1]

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Answer:

Option C.  [tex]g(x)=(\frac{1}{3}x)^2[/tex]

Step-by-step explanation:

Given a function to start with, extra operations that are done outside of the given function, cause vertical transformations, whereas operations that are done inside of the function cause horizontal transformations.

Transformations on the outside

Ex. [tex]g(x)=(x^2)-3[/tex]  is subtracting 3 outside, so its transformation is vertical.

Transformations on the inside

Ex. [tex]g(x)=(x-7)^2[/tex] is subtracting 7 inside, so its transformation is horizontal.

For any function, stretches or compressions occur by multiplying by positive numbers larger or smaller than 1.

Multiplying by numbers larger than one, quantities get larger, and multiplying by a positive number less than one, quantities get smaller.

For example, [tex]\$10*2 = \$20[/tex], but [tex]\$10*\frac{1}{2} = \$5[/tex]

For transformations, this intuition needs a small modification:

Multiplying on the outside

When multiplying outside of the function, things outside happen normally, and since it is happening outside, it is in a vertical direction.

Ex. Multiplying outside by 3, things get larger (stretch) vertically to 3 times as much as (300% of) normal (away from a height of zero).

Multiplying outside by [tex]\frac{1}{2}[/tex] , things get smaller (compress) vertically down to [tex]\frac{1}{2}[/tex] as much as (50% of) normal (toward a height of zero).

"g" is lower than "f", so it may have been compressed vertically (see alternative solution at end).

Looking at the only options with multiplication outside (A & B), option B multiplies by 3 (greater than 1), so it would stretch "f" even taller.

Option A, does compress "f" vertically (by 1/3), but doesn't compress it enough to arrive at the point (3,1) defined on function "g". Note ordered pair (3,1) on "g", meaning when you input "3", you get out "1".  

Putting 3 into the "f" function, f(3)=9.  Since one-third (the transformation in Option A) of 9 is 3, not 1, Option A doesn't compress "f" enough.

Multiplying on the inside

When multiplying inside, transformations happen horizontally, and inside things happen "backwards".

So, if multiplying inside by 4, (...normally things get bigger...) things actually get smaller (compressed) horizontally, reduced to 1/4 (the reciprocal of 4) the size (toward a horizontal distance of zero).

If multiplying by a number less than one (but positive), like [tex]\frac{1}{3}[/tex] , (...things normally get smaller...) things will actually get larger (stretch) in the horizontal direction out to triple (the reciprocal of [tex]\frac{1}{3}[/tex]) as much as normal.

Looking options C & D (where multiplication happens inside), both have multiplication by a positive number less than one (... normally would make things smaller...), which will stretch "f" out horizontally.

Looking at the red point (3,1), the blue function does have a height-matched point at (1,1).

Measuring horizontal distances, (3,1) is 3-units from the y-axis, whereas (1,1) is only 1-unit away.  Thus, the "g" is 3 times as far as "f", meaning a horizontal stretch outward by 3.

Answer C multiplies inside by [tex]\frac{1}{3}[/tex], so it actually makes things 3 times bigger horizontally.

The correct answer is option C.

To verify, from (3,1), put 3 into the option C g(x) --  it gives "1" as an output.

[tex]g(x)=(\frac{1}{3}x)^2\\g(3)=(\frac{1}{3}(3))^2\\g(3)=(1)^2\\g(3)=1\\[/tex]

This function could have been compressed vertically to obtain the red graph.

Note that f(3)=9.

The point (3,1), on the red function, is only at a height of 1 ... 1/9th the height of the blue function.  We could compress the "f" vertically by 1/9th to transform the blue function into the red function.

Vertical transformations come from operations outside, and outside things behave "normally", so to vertically compress by 1/9th, just multiply on the outside by 1/9th.

Thus, an alternative answer to transform f(x) to g(x) is [tex]g(x)=\frac{1}{9}(x^2)[/tex]

Two last things:

Simplifying this function we just obtained we get [tex]g(x)=\frac{1}{9}x^2[/tex]

Returning to the function that we chose for our answer in option C, [tex]g(x)=(\frac{1}{3}x)^2[/tex]

[tex]g(x)=(\frac{1}{3}x)(\frac{1}{3}x)[/tex]

[tex]g(x)=\frac{1}{9}x^2[/tex]

Note that the transformation answer for this problem (Option C) and our alternative solution both simplify and match perfectly, so they both represent the same end result.

0.21094 is the probability that the surgery is successful on exactly 3 patients.

It is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true.

According to the given question,

Let Y = The number of patients who respond yes: [tex]Y - Bin (n,p)[/tex]

Given , [tex]n = 4 , p = 0.75 , q = 1 - p = 0.25[/tex]

[tex]P (Y = 3) = \left(\begin{array}{ccc}4\\3\\\end{array}\right) (0.75)^{2}(0.25)^{4-3} \\ = 0.21094\\\\[/tex]

The probability that the surgery is successful on exactly 3 patients is 0.21094

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Answer:

3(4)² - 2(4) + 1 = 48 - 8 +1 = 41

x = 4

[tex] {3x}^{2} - 2x + 1 \\ \\ 3 \times {4}^{2} - 2 \times 4 + 1 \\ \\ 3 \times 16 -8 + 1 \\ \\ 48 - 8 + 1 \\ \\ 41.[/tex]

Answer: 3/4

Step-by-step explanation:

The options are not mentioned , but the correct graph is plotted and attached with the answer.

A function is a mathematical statement that relates a dependent variable with an independent variable .

It is given to find among the options which is the correct graph for

y = log₃ (x-1)

The options are not mentioned , but the correct graph is plotted and attached with the answer.

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Answer:

  f(x) = 2(x -3)² +5   or   f(x) = 2x² -12x +23

Step-by-step explanation:

The equation of a quadratic is easily written in vertex form when the coordinates of the vertex are given. Here, the point one horizontal unit from the vertex is 2 vertical units higher, indicating the vertical scale factor is +2.

__

The vertex form equation for a parabola is ...

  f(x) = a(x -h)² +k . . . . . . vertex (h, k); vertical scale factor 'a'

For vertex (h, k) = (3, 5) and vertical scale factor a=2, the vertex form equation of the parabola is ...

  f(x) = 2(x -3)² +5 . . . . . vertex form equation

Expanded to standard form, this is ...

  f(x) = 2(x² -6x +9) +5

  f(x) = 2x² -12x +23 . . . . . standard form equation

I consider the original fraction: x/y.

If the numerator "x" increases by 20%, it can be interpreted in this way:

"x" represents 100% (the unit) and when increasing by 20% we have that the value of "x" becomes 120%

120% of "x" is [tex]\bf{\frac{120*x}{100}=1,2x }[/tex]

This is what we have left in the numerator.

By the same reasoning, in the denominator "y" remains:

100% - 40% = 60% of "and"

60% of "y" is...[tex]\bf{\frac{60*y}{100}=0.6 y }[/tex]

The new fraction is: 1,2x / 1,6y.

...simplifying by dividing top and bottom by 0.6,... 2x / y

To find out the percentage by which the original fraction has changed, we first find the relationship or ratio between the original fraction and the new fraction with the fraction quotient:

[tex]\bf{\dfrac{\frac{2x}{y} }{\frac{x}{y} }=\frac{2xy}{xy}=2 }[/tex]

... that is to say that the new fraction has doubled in relation to the original.

Therefore, the percentage of variation per increase is 100%.

Answer:

The commutative property of addition says that changing the order of addends does not change the sum.

(a+b)+c = a+ (b+c)

( -8 + -7) + 6 = -8 + ( -7 + 6)

-15 + 6          =   -8 + -1

-9                  =  -9

Answer:

Hence, proved (a+b) + c = a + (b+c)."

Step-by-step explanation:

first take left hand side and insert the values of a, b, and c and similarly than take right hand side.

L.H.S

(a+b)+c

(-8+(-7))+6

(-8-7)+6

-15+6

-9

R.H.S

a+(b+c)

-8+(-7+6)

-8+(-1)

-8-1

-9

hence, proved (a+b) + c = a + (b+c)."

Answer:

70%

$571.41

Step-by-step explanation:

100% means 1, or a whole thing.

Since the discount is 30% of the original price, and the original price is 100% of the original price, then

100% - 30% = 70%

With a 30% discount, you actually pay 70% of the original price.

$399.99 is 70% of the original price.

399.99 / 70% = x / 100%

70x = 100 × 399.99

x = 571.41

The original price was $571.41.

Answer:

All the possible zeroes of the polynomial: f(x) = [tex]3x^{6} + 4x^{3} - 2x^{2} +4[/tex] are  ±1 , ±2 ,  ±4 ,  ±[tex]\frac{1}{3}[/tex] , ±[tex]\frac{2}{3}[/tex]  , ±[tex]\frac{4}{3}[/tex] by using rational zeroes theorem.

Step-by-step explanation:

Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.

The polynomial f(x) = [tex]3x^{6} + 4x^{3} - 2x^{2} +4[/tex]

Find all factors (p) of the constant term.

Here we are looking for the factors of 4, which are:

±1 , ±2 and ±4

Now find all factors (q) of the coefficient of the leading term

we are looking for the factors of 3, which are:

±1 and ±3

List all possible combinations of ± [tex]\frac{p}{q}[/tex]  as the possible zeros of the polynomial.

Thus, we have ±1 , ±2 ,  ±4 ,  ±[tex]\frac{1}{3}[/tex] , ±[tex]\frac{2}{3}[/tex]  , ±[tex]\frac{4}{3}[/tex] as the possible zeros of the polynomial

Simplify the list to remove and repeated elements.

All the possible zeroes of the polynomial: f(x) = [tex]3x^{6} + 4x^{3} - 2x^{2} +4[/tex] are  ±1 , ±2 ,  ±4 ,  ±[tex]\frac{1}{3}[/tex] , ±[tex]\frac{2}{3}[/tex]  , ±[tex]\frac{4}{3}[/tex]

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The interest rate will be equal to 24% in 2 years.

Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-

Given that:-

The interest rate will be calculated by using the following formula:-

[tex]A = P[1+\dfrac{r}{n}]^{nt}[/tex]

[tex]50=32[1+\dfrac{r}{1}]^{2}[/tex]

[tex]\dfrac{50}{32}=(1+r)^2[/tex]

1.56 = ( 1 + r )²

√1.56 = ( 1 + r )

r = 1.24 - 1

r = 0.24

r = 24%

Therefore  interest rate will be equal to 24% in 2 years.

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The product of (√3x + √5)(√15x+2√30) assuming x ≥ 0 is 3√5x² + 6√10x + 5√3x + 10√6

It follows from the task content that the expression given whose product is to be evaluated is;

(√3x + √5)(√15x+2√30)

Hence, by multiplying the terms with each other accordingly; we have;

= (√45x² + 2√90x + √75x + 2√150)

= 3√5x² + 2√90x + √75x + 2√150

= 3√5x² + 2×3√10x + √75x + 2√150

= 3√5x² + 2×3√10x + 5√3x + 2√150

= 3√5x² + 2×3√10x + 5√3x + 10√6

= 3√5x² + 6√10x + 5√3x + 10√6

Ultimately, the product of the expression is; 3√5x² + 6√10x + 5√3x + 10√6

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