Post-Lab Problem 2 (5 points). 20 L of HCl(g) with density of 0.7292 were dissolved
in 2.0 L of water. Then 20 mL of that solution were titrated to the end point by 10 mL of
NaOH(aq). What was the molar concentration of NaOH? Assume that HCl(9) does not change
the volume of water when dissolved in it. Enter your answers in the boxes provided with correct units and
sig. figs.:
Answer:
The molar concentration
of sodium hydroxide is ): СNaOH =

Answer:

im pretty sure thats physical

Explanation:

Normality of a solution of sulfuric acid (H2SO4) that containing 86 g

per liter of solution is 1N

The gram equivalent weight of a solute per liter of solution is what is known as a solution's normalcy. The comparable concentration is another name for it. The units of concentration are denoted by the symbols N, eq/L, or meq/L (= 0.001 N). A hydrochloric acid solution's concentration, for instance, could be stated as 0.1 N HCl. The reactive capacity of a specific chemical species is measured by gram equivalent weight or equivalent (ion, molecule, etc.). Utilizing the chemical species' molecular weight and valence, the equivalent value is calculated. The only concentration unit that is reaction-dependent is normality.

g equivalent mass of H2SO4 = 86g

Volume of solution in liter = 1 l

number of g equivalent of H2SO4 = 86/86 = 1

Normality = number of g equivalent/ volume of solution in liter

N = 1 / 1

Normality = 1 N

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The number of chlorine moles present in the vessel are 37.67 mol.

What are moles?

Moles are the number of substances present in a system which consists of entities like ions, atoms, or molecules as much as atoms in the weight of pure carbon which is 12 grams. It is the SI unit of amount of substance.

One mole of a substance is equal to the Avogadro Number which is equal to 6.022×10²³.

According to Ideal gas law,

PV=nRT where,

P= Pressure

V= Volume

n= number of moles

R= Ideal gas constant

T= temperature (in Kelvin)

n= PV/RT

⇒33.3×36.5/0.0821×393

⇒1215.45/32.2653

⇒37.670

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W = Pexternal(ΔV),W = (1 atm) 8.93  L - 1 L)(101.3 J/1 L·atm)= 803.309J. W. Work, pressure, and volume are directly correlated using a formula. W = Pexextr(V) Consequently, the environmental work is 803.309J. W

Market share comes in two flavors: value and volume. The business's overall shares of its total accumulated sector sales serve to define a value market share. On the other hand, a volume market share refers to the precise number of units that an entity markets relative to the total number of units that are sold in the market.

W = quantity of work completed =?

1.00 atm of pressure is P.

1.00 L is the initial volume.

= 8.93 L ultimate volume

W = Pexternal(ΔV),W = (1 atm) 8.93  L - 1 L)(101.3 J/1 L·atm)= 803.309J. W.

How much room an object occupies is determined by its volume. It is calculated using the quantity of unit cubes required to completely fill the solid. We have 30 unit cubes in the solid after counting the unit cubes, hence the volume is 2 units. 3 units 1 unit equals 30 cubic units

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For reflex action the motor neuron that generates the reflex action and pass to the sensory neuron. Interneuron helps to sensory neuron to communicate with motor neurons. Thus in this picture, the motor neuron be the interneuron and interneuron be the motor neuron. Thus option A and D are correct.neuron should be the interneuron.

Reflex action is generated by our body by the sudden action to for sense of touch or other stimulants. For example, if touch a very hot body, we will take our hand within second and this is resulted by the action of neuron and is called the reflex action.

The movement of hands and legs are controlled by the motor neurons. If we touch any stimulant sensory neurons pass signals to the motor neuron and a signal containing the information of action is returned to the sensory neurons of our hand.

Here, the communication between sensory neuron and motor neuron is facilitated by interneurons. Thus, in this picture the motor neuron be the interneuron and interneuron be the motor neuron. Thus option A and D are correct.

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The volume of the given ball is 21 L.

Pressure = 1.0 atm      

no. of moles = 0.85 mol

Temperature = 25°C = (25+273) K = 298 K.

we will use the ideal gas equation,

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Let's substitute the values into the above formula,

1.0 x V = 0.85 x 0.0821 x 298

V =  20.7 [tex]\approx[/tex] 21 L.

Thus, the volume of the ball is 21 L.

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The IUPAC nomenclature of compound 1 is 5-bromo-2-methylchloridepent-2-ene and the name for structure 2 is 5-iodo-hex-2-ene

IUPAC nomenclature is the method of naming the organic chemical compounds by following certain rules and criteria given by IUPAC.

This nomenclature is based on naming a molecules longest chain of carbons connected by single bonds, whether in a continuous or in ring form. Everything else like multiple bonds or atoms are other than carbon and hydrogen are indicated by prefixes or suffixes according to a specific set of priorities.

In structure 1 we can see that we are number so that the double bond that is present gets the least priority and then the naming is done in the alphabetic order. so the name is 5-bromo-2-methylchloridepent-2-ene

In structure 2 the same thing is followed and the name of the structure is

5-iodo-hex-2-ene

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10x - 74 = 92  --->  (Add 74 to both sides. This gets rid of the 74)

     + 74   +74

10x = 166   --->  (Simplify. The 74 you added to the 92 becomes 166)

10x/10 = 166/10    ---> (Divide both sides by 10. This gets the x by itself)

v(Simplify)v

x = 83/5    OR    x = 16.6

The following are some things you do to help you learn and remember new words and they mean:-

Reading is one of the only methods to teach vocabulary and normal learning is the approach that gives college students the possibility to exercise and grasp the stages of crucial reading that result in studying success and progressed word utilization.

One of the maximum impactful mastering techniques is allotted practice spacing out your analyzing over several brief intervals of time over several days and weeks. The only exercise is to work a quick time on every elegance every day.

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A synthesis showing the necessary reagents and intermediate molecules for carbon sources, use alkyl halides with 4 or fewer carbons is zinc and copper pair in alcohol to reduced alkyl halide.

The Zn/Cu pair in alcohol is used to reduce alkyl halides. In alcohol, the Zn/Cu pair substitutes hydrogen for the halide of an alkyl halide to generate hydrocarbons. The Zn/Cu combination produces methane in alcohol by taking the iodine out of methyl halide and adding hydrogen.

Thus, a synthesis showing the necessary reagents and intermediate molecules for carbon sources, use alkyl halides with 4 or fewer carbons is zinc and copper pair in alcohol to reduced alkyl halide. Alkyl iodide is more reactive.

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Answer:

A

Explanation: