(a) The amount of argon gas in the cylinder is approximately [tex]\rm \(4.09 \times 10^{-5}\)[/tex] moles.
(b) The change in temperature of the gas is approximately 976.7°C.
Part (a):
Given data:
Inner diameter of the cylinder (d) = 11.43 cm = 0.1143 m
Height of the cylinder ([tex]h_{max[/tex]) = 15.56 cm = 0.1556 m
Height of the disc above the bottom of the cylinder ([tex]h_0[/tex]) = 41.9% of h_max = 0.419 * 0.1556 m
Combined mass of the disc and weights (m) = 19.07 kg
Temperature of the gas (T) = 22.1°C = 22.1 + 273.15 = 295.25 K
We need to find the amount of argon gas in moles in the cylinder.
Step 1: Calculate the volume of the gas in the cylinder.
[tex]\[ V_{\text{gas}} = \pi \left(\frac{d}{2}\right)^2 \times h_0 \]\\\\\ V_{\text{gas}} = \pi \left(\frac{0.1143}{2}\right)^2 \times 0.419 \times 0.1556 \]\\\\\ V_{\text{gas}} \approx 0.00121 \, \text{m}^3 \][/tex]
Step 2: Calculate the number of moles of argon gas using the ideal gas law.
[tex]\[ PV = nRT \][/tex]
Where P is the pressure of the gas (we assume it is constant), V is the volume of the gas, n is the number of moles, R is the universal gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin.
[tex]\[ n = \frac{PV}{RT} \]\\\\\ n = \frac{1 \times 0.00121}{8.314 \times 295.25} \]\\\\\ n \approx 4.09 \times 10^{-5} \, \text{moles} \][/tex]
Part (b):
Given data:
Additional mass placed on the disc ([tex]m_{extra[/tex]) = 5.56 kg
New height of the disc above the bottom of the cylinder (h_new) = 87.8% of h_max = 0.878 * 0.1556 m
We need to find the change in the temperature of the gas.
Step 1: Calculate the new volume of the gas in the cylinder.
[tex]\[ V_{\text{gas\_new}} = \pi \left(\frac{d}{2}\right)^2 \times h_{\text{new}} \]\\\\\ V_{\text{gas\_new}} = \pi \left(\frac{0.1143}{2}\right)^2 \times 0.878 \times 0.1556 \]\\\\\ V_{\text{gas\_new}} \approx 0.00178 \, \text{m}^3 \][/tex]
Step 2: Use the ideal gas law again to find the new temperature of the gas.
[tex]\[ n_{\text{new}} = \frac{P \times V_{\text{gas\_new}}}{RT_{\text{new}}} \]\\\\\\ T_{\text{new}} = \frac{P \times V_{\text{gas\_new}}}{n_{\text{new}} \times R} \]\\\\\ T_{\text{new}} = \frac{1 \times 0.00178}{4.09 \times 10^{-5} \times 8.314} \]\\\\\ T_{\text{new}} \approx 1271.95 \, \text{K} \][/tex]
Change in temperature:
[tex]\[ \Delta T = T_{\text{new}} - T \]\\\\\ \Delta T = 1271.95 - 295.25 \]\\\\\ \Delta T \approx 976.7 \, \text{K} \][/tex]
Result:
(a) The amount of argon gas in the cylinder is approximately [tex]\rm \(4.09 \times 10^{-5}\)[/tex] moles.
(b) The change in temperature of the gas is approximately 976.7°C.
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a small block with mass 0.390 kg is attached to a string passing through a hole in a frictionless, horizontal surface (figure 1). the block is originally revolving in a circle with a radius of 0.800 m about the hole with a tangential speed of 4.00 m/s. the string is then pulled slowly from below, shortening the radius of the circle in which the block revolves. the breaking strength of the string is 30.0 n.
The radius of the circle when stringe break is 6.93×10^-2.
What is radius?The radius is the distance from the centre of a circle.
When finding the radius of the string at the point it breaks, the tangential
velocity is assumed to be constant.
The radius when the string breaks is 6.9.3×10^-3m
Reasons:
The mass of the small block, m = 0.130 kg
Initial radius of the circle of rotation = 0.800 m
Tangential velocity, v = 4.00 m/s
The radius of the path of rotation is reduced as the string is pulled
Breaking strength of the string = 30.0 N
Required:
The radius of the circle when the string brakes
Solution:
centripetal force =m.v^2/r
Where;
r = The radius of the circle of rotation
When the string brakes, w have;
Centripetal force = Breaking strength of the string = 30.0 N
Which gives;
r=m.v^2/centrigual force =6.93×10^-2
The radius of the circle when, the string breaks r = =6.93×10^-2.
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a workstation is connected to a switch on the gi 0/2 interface using a straight-through cable. the ethernet interface in the workstation has been manually configured to use a 100 mbps link speed in full-duplex mode. which of the following are true in this scenario? (select three.)
The following are true in this scenario:
1. If the link speed is 10 Mbps or 100 Mbps, half- duplex is used.
2. If the link speed is 1000 Mbps or faster, full-duplex is used.
3. The switch attempts to sense the link speed. If it can't, the lowest link speed supported on the interface is selected.
Interfaces can work in the following two duplex modes. They are half duplex mode and full duplex mode.
Half- duplex mode: An interface in this mode can send data only when it is not received data and conversely, it can receive data only when it is not sending data. There is a limit on transmission distance in this mode.
Full-duplex mode: An interface in this mode can send and receive data simultaneously. The maximum throughput in full-duplex mode is theoretically double than in half duplex mode. There is no limit on transmission distance in this mode.
You can configure the rate and duplex mode of an Ethernet interface working in either auto-negotiation or non-auto negotiation mode.
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the longer the pendulum is, the longer it takes to swing. therefore, when the pendulum of a clock is lengthened, the clock slows down.
Deductive
The conclusion follows necessarily from the premise. (The lengthening of the pendulum of a clock makes the mechanism that moves the hands of the clock slow down)
Argument, premises and conclusion
The statements that make up an argument are divided into one or more premises and exactly one conclusion. The premises are the statements that set forth the reasons or evidence, and the conclusion is the statement that the evidence is claimed to support or imply. That is, the conclusion is the statement that is claimed to follow from the premise.
Inductive and deductive argument
A deductive argument is an argument incorporating the claim that it is impossible for the conclusion to be false given that the premises are true.An inductive argument is an argument incorporating the claim that it is improbable that the conclusion be false given that the premises are true.To decide whether an argument is inductive or deductive look for
1. the occurrence of special indicator words
2. the actual strength of the inferential link between premises and conclusion, and
3. the form or style of argumentation.
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which of the following is not a vector? the diameter of earth the force that represents your weight the unbalanced force from two people pushing a cart in opposite directions your displacement from walking five blocks to the north the velocity of a baseball in flight
The earth's diameter is not a vector.
Weight: Is it a vector quantity?A body's weight is a measurement of the gravitational force acting on it. Given that a force has both magnitude and direction, and since we refer to such a quantity as a vector quantity, we can infer that weight is also a vector quantity.
Which of the following is not a vector object?Response and Justification: All other quantities, with the exception of mass, have both a magnitude and a direction. Mass, however, only has a magnitude. Therefore, mass is not an illustration of a vector quantity but rather a scalar number.
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if two resistors (10 ohm and 20 ohm) are connected in series, the total resistance will be less than lease one (10 ohm).
The equivalent resistance of the circuit is 30 ohms. The circuit currently has a current of 0.2 A. The potential difference across a 10 ohm resistor measures at 2 V.
Two resistors with resistances of 10 and 20 ohms are linked together in series. As a result, the equivalent resistance of the circuit is equal to the sum of the resistance of the two resistors, which is 10 ohms plus 20 ohms, or 30 ohms.
Currently, based on assertion 2;
The circuit's equivalent resistance is equal to the voltage supply across the circuit times the circuit's current, which equals the circuit's current = V/R = (6 v)/(30 ohms) = 1/5 A = 2 V.
Currently, based on assertion 2;
V/R = (voltage supplied across the circuit)/(equivalent resistance of the circuit) = (6 v)/(30 ohms) = 1/5 A = 0.2 A is the formula for the current flowing through the circuit.
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The complete question is -
If two resistors 10 ohm and 20 ohm are connected in series to a 6V battery. Calculate the current flowing through the circuit and the potential difference across 10 ohm resistor.
this is the distance from the peak to a peak of a successive wave.; this the bottom, or lowest point, of a wave.; this is the material in which a mechanical wave travels; this is the constructive or destructive overlap of waves.; a rhythmic disturbance that carries energy through matter or space.; the point where a sound or other wave originates.; the complete range of light waves organized by wavelength/frequency.; this is the peak, or highest point, of a wave.
The peak to peak distance of successive wave is the wavelength, trough is the bottom of the wave, the wave travels in a medium, the constructive or destructive overlap of the Waves is interference, disturbance in space is called wave, the point where the wave originate is called source, the complete range of the light wave is called electromagnetic spectrum and the peak of the wave is called crest.
A wave carries a lot of information about itself.
The peak to peak distance between the two successive wave is called the wavelength of the wave.
The material in which the mechanical wave travels is called medium.
The interference of two waves can be constructive or destructive overlap of the waves.
A wave is basically a rhythmic disturbance that carries energy through matter or space where a sound or other waves originate is called a source while the complete range of light wave which when organised in a complete manner on the basis of wavelength and the frequency is said to be a electromagnetic spectrum the peak what the highest point of a wave is called the crest of the wave.
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if you wanted to observe the center of our galaxy, you would need to point a telescope in the direction of the constellation. Aquarius Sagitarius
You would be required to focus a telescope towards the general direction of a constellation "Sagittarius." in order to see the galactic center.
Explain the function of telescope?Astronomers use a telescope to observe distant things.
Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from of the night sky. The original telescopes employed lenses, which are simply curved pieces of clear glass, to focus light.The two most crucial tasks of a telescope are-
(1) gathering the weak light coming from such an astronomical source and (2) concentrating all of the light into a single point or image.The majority of astronomical objects of interest are quite dim; more the light we can gather, the better we can examine such objects.
As the galactic center is located in the direction of the Sagittarius constellation. That is why the name of the main item (Sagittarius A*) contains the word "Sagittarius".
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The complete question -
if you wanted to observe the center of our galaxy, you would need to point a telescope in the direction of the constellation.
The correct option is-
Aquarius Sagitariuslight with a wavelength of 360 nm shines on a metal surface, which emits electrons. the stopping potential is measured to be 1.15 v.What is the maximum speed of emitted electrons?
Calculate the work function?
Identify the metal.
Maximum speed of emitted electrons is [tex]5.51 * 10^{-19} m/s[/tex] and work function is [tex]1.84 * 10^{-19}[/tex]eV.
We know that maximum speed of emitted electrons is given by: [tex]\frac{hc}{\alpha }[/tex]
where, h = planck's constant = [tex]6.62* 10^{-34}[/tex]
c = speed of light = [tex]3 * 10^{8} m/s[/tex]
[tex]\alpha[/tex] = wavelength = 360 nm = [tex]3.6 * 10^{-9} m[/tex]
Putting these values in above equation we get E = [tex]5.51 * 10^{-19} m/s[/tex] .
Also work function is given by: W = eV
where, W = work function
e = charge of electron = [tex]1.6 * 10^{-19} C[/tex]
V = stopping potential = 1.15v
Putting these values in above equation we get W = [tex]1.84 * 10^{-19}[/tex] eV.
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A venturi meter is measuring the flow of water in a pipe having cross-sectional area
of 0.0038 m², a throat with cross-sectional area of 0.00031 m² is connected to it.
If the pressure difference is measured to be 2.4 kPa, what is the speed of the water
in the pipe?
The speed of the water is 0.069 m/s
How do you determine the speed of the water?To determine the speed of the water in the pipe, you can use the Bernoulli equation, which relates the pressure, velocity, and height of a fluid in a system. In this case, the Bernoulli equation can be written as:
P + 1/2*rho*v^2 + rho*g*h = constant
where P is the pressure, rho is the density of the water, v is the velocity of the water in the pipe, g is the acceleration due to gravity, and h is the height of the fluid above a reference point.
Since the pressure difference between the two points in the pipe is known, you can rearrange the Bernoulli equation to solve for the velocity of the water in the pipe:
v = √((2*(P1 - P2))/rho)
where P1 is the pressure at the throat and P2 is the pressure at the cross-sectional area of the pipe.
Plugging in the values given in the question, we have:
v = √((2*(2.4 kPa - 0))/1000 kg/m^3)
= √(4.8 kPa/1000 kg/m^3)
= √(0.0048 Pa/kg/m^3)
= 0.069 m/s
Therefore, the speed of the water in the pipe is approximately 0.069 m/s.
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9.4 the average pressure and shear stress acting on the surface of the 1-m-square flat plate are as indicated in fig. p9.4. determine the lift and drag generated. determine the lift and drag if the shear stress is neglected. compare these two sets of results.
The lift and drag if the shear stress is neglected, than the values of forces F0 = 1.1955 KN & F1 = 8.014 KN.
The average pressure and shear stress acting on the surface of the 1-m-square flat plate.
P1 = 2.3 * 3 = 6.9 KN/m^2
P2 = -1.2 KN/m^2
T1 = 7.6 * 10^-2 * 2 = 0.152 KN/m^2
T2 = 0.058 KN/m^2
Now,
Drag force
F0 = F1sinα - F2sinα + FS1cosα+FS2cosα
= P1Asinα - P2sinα + T1Acosα + T2Acosα
= Asinα(P1-P2) + Acosα(T1 + T2)
= 1.sin(T)[6.9-(-1.2)] + 1. cos (T)[0.152 + 0.058]
= 0.98714 + 0.20843
= 1.1955 KN
Lift force
F1 = F1cosα - F2cosα - FS1sinα - FS2sinα
= P1cosα - P2Acosα - T1Asinα - T2Asinα
= Acosα(P1 - P2) - A.sinα(T1 + T2)
= 1. cos(T)(6.9 - (-1.2)) - 1. sin(T)(0.152 + 0.058)
= 8.014 KN
Therefore, the lift and drag if the shear stress is neglected, than the values of forces F0 = 1.1955 KN & F1 = 8.014 KN.
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all points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to all points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to general plane motion translation rotation about a fixed axis none of the above
All points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to general plane motion.
The general plane motion refers to the movement of a rigid body in two dimensions, where the body can translate (move in a straight line) and rotate about a fixed axis. When a rigid body is subjected to general plane motion, all points on the body will move with the same velocity and acceleration, as the body is rigid and does not deform.
This is in contrast to translation, which refers to movement in a straight line, and rotation about a fixed axis, which refers to rotation around a fixed point. In these cases, the points on the body will not necessarily move with the same velocity and acceleration, as the body is able to deform and rotate.
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8
Figure 2.24 shows a model of a skyscraper which Omar made
for the school exhibition. It is mounted on a firm plastic base
and has a total weight, W, of 4.0 N. Omar applies a force Fas
shown to test the stability of his model.
Calculate the minimum value of F required to cause the model
to rotate about point P.
Answer:
j
Explanation:
Seperate visual images may appear continues due to
Separate visual images may appear continuous due to iconic memory.
option A is the correct answer.
What is Iconic memory?
Iconic memory is the visual sensory memory register which stores visual images after the extinction of a physical stimulus.
Iconic memory is part of the visual memory system, which includes long-term memory and visual short-term memory.
Images are processed in the iconic memory in the following ways. Once the stimulus of a perceived image is seen or perceived, iconic memory begins.
The automatic recognition of the visual stimulus display is processed by the occipital lobe and transferred to iconic memory, where it remains for only milliseconds before being transferred to visual working memory or being discarded.
The persistence of vision in known to be caused by iconic memory.
Thus, we can conclude that separate visual images may appear continuous due to persistence in vision caused iconic memory. So option A is the correct answer.
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a uniform rod of length l oscillates as a pendulum about a pivot that is a distance x from the center.
According to the given statement x = L / 2√3 in terms of l, is the oscillation period a minimum.
What is oscillation formula ?
In systems that can be characterized by Hooke's law, F = kx, where x is the displacement from equilibrium or deformation and k is the system's force constant, the simplest oscillations occur.
Briefing:
T = 2π√I/mgx
I stands for the moment of inertia about the oscillation axis.
m is the bodily mass.
x is the separation of the mass center from the pivot point.
g stands for gravitational acceleration.
Here , Moment of inertia of a rod about the axis through pivot is given by
I = ML²/12 + Mx²
As the axis of rotation passes past the pivot, we have measured the rod's moment of inertia with respect to it.
The Pendulum's Time Period is shown by
[tex]$$T=2 \pi \sqrt{\frac{\frac{M L^2}{12}+M x^2}{M g x}} \Rightarrow T=2 \pi \sqrt{\frac{L^2+12 x^2}{12 g x}}$$[/tex]
Time period will be minimum if [tex]$\mathrm{L}^2+12 \mathrm{x}^2 / 12 \mathrm{gx}$[/tex] is minimum
[tex]$$\begin{aligned}& \frac{d}{d x}\left(\frac{L^2+12 x^2}{12 g x}\right)=0 \\& \frac{12 g x(24 x)-\left(L^2+12 x^2\right) 12 g}{144 g^2 x^2}=0\end{aligned}$$[/tex]
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of the following options, which is not one of the temperaments first proposed by thomas and chess (1977)? a. the easy babyb. the difficult babyc. the slow to warm up babyd. the secure baby
The following options, the secure baby is not one of the temperaments first proposed by Thomas and chess (1977)
Thomas and Chess said that there are three general types of temperaments in children:
• Easy,
• Slow-to-warm
• Difficult.
1. Easy children are generally happy, active children from birth and adjust easily to new situations and environments.
2. Slow-to-warm children are generally mellow, less active babies from birth, and can have some difficulty adjusting to new situations.
3. Difficult children do have not regular habits and biological routines (examples-eating, sleeping), have difficulty adjusting to new conditions, and often show negative moods very intensely. As the category name suggests, these children are the most difficult for caregivers to satisfy and maintain the energy and happiness to care for on a daily basis.
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The jumper has a mass of 55 kg, and the bridge's height above the river is 150 m. The rope has an unstretched length of 8 m and stretches a distance of 5 m before bringing the jumper to a stop. Determine the maximum speed of the jumper and the spring constant of the rope. In your calculation, use g 10 N/kg. m/s Vmax k = N/m E.
Now suppose the jumper has a mass of 80 kg. Do you think the maximum speed of the jumper will increase, decrease, or stay the same? Will the rope need a larger, smaller, or the same spring constant to bring the jumper to a stop in the same distance as part D?
The speed of jumper is 54.22 m/s and spring constant of the rope is 6468N/m.
Given data:
The mass of jumper is, m = 55 kg.
The height of bridge above the river is, h = 150 m.
The length of unstretched rope is, L = 8m.
The stretched length is, L' = 5m.
In this problem, when the jumper will jump then the only potential energy of the jumper will get converted into the spring potential energy of the rope. So we can say that the relation will be,
potential energy of jumper = spring potential energy of rope.
Here, k is the spring constant.
Solving as,
mgh = 1/2 KI²
55 × 90.8 × 150 = 1/2 × k × 5 × 5k
k = 6468 N/m
Now, apply the third kinematic equation of motion to calculate the final speed of jumper as,
v² = U² + 2as
We get U= 54.22 m/s.
Thus, we can conclude that the speed of jumper is 54.22 m/s and the spring constant of the rope is 9187.5 N/m.
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a bat flies towards a moth at 8.0 m/s while the moth is flying towards the bat at 4.6 m/s. the bat emits a sound wave of 50.4 khz. ef picup part description answer save status a. what is the frequency of the wave detected by the bat after the wave reflects off the moth? (include units with answer) format check click here to check your answer 9.09 pts.100% 2% try penalty 1 hint available
the frequency of the wave detected by the bat after the wave reflects off the moth is 54.24 KHz .
Calculation :
given ,
speed of sound(v) = 343 m/s
speed of bat(v bat) = 8.0 m/s
speed of moth (V moth) = 4.6 m/s
real frequncy of moth = 50.4 KHz
the first apparent heard by moth is :
f moth = [tex]\frac{V+Vmoth}{V-Vbat}*f[/tex]
apparent frequently heard by the bat when the sound is reflected from the moth :
fbat : [tex](\frac{V+Vbat}{V-Vmoth}) (\frac{V+Vmoth}{V-Vbat} )f[/tex]
f bat = [tex](\frac{343+8}{343-4.6} )(\frac{343+4.6}{343-8} )(50.4)[/tex]
= 54.24
Frequency is the number of occurrences of a repeating event per unit time. [1] For clarity, also called temporal frequency, which is different from angular frequency. Frequency is measured in Hertz (Hz) and corresponds to one event per second. Duration is the reciprocal of frequency because duration is the time interval between events. [2]
For example, if the heart beats 120 times per minute (2 hertz), the period T (the interval between repeated beats) is 0.5 seconds (60 seconds divided by 120 beats). value). Frequency is an important parameter used in science and engineering to describe the speed of vibrations and vibrational phenomena such as mechanical vibrations, audio signals (sound), radio waves, and light.
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3. A 7.0-kg bowling ball is rolling down the alley with a velocity of 2.0 m/s. For each impulse, shown in Figures 9-3a and 9-3b, find the resulting speed and direction of motion of the bowling ball
(a) The resulting speed and direction of motion of the bowling ball in first graph is 0.71 m/s upward.
(B) The resulting speed and direction of motion of the bowling ball in second graph is 0.71 m/s downward.
What is the impulse of the ball in the first graph?,The impulse experienced by an object is the product of applied force and time of motion.
The impulse of object is also equal to the change in momentum of the object.
J = ΔP = Ft
For the first graph;
J = 5 N x ( 2 - 1 ) s
J = 5 N x 1 s
J = 5 Ns = 5 kg m/s
The speed of the object is calculated as;
v = J / m
where;
m is the mass of the objectv = ( 5 kg m/s ) / ( 7 kg )
v = 0.71 m/s, upward
The impulse experienced by the object in the second graph is calculated as;
J = -5 N x 1 s
J = - 5 Ns = - 5kg m/s
v = J / m
v = - 5 kg m/s / 7 kg = - 0.71 m/s = 0.71 m/s, downward
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astronomers observe galaxies and categorize them according to four different kinds of shapes: elliptical, spiral, barred-spiral, and irregular. in addition to shape, each of the four different galaxy types can be described by other common characteristics. match the following characteristics with their corresponding galaxy type.
Matching of the characteristics with their corresponding galaxy type is as follows.
Elliptical galaxy (E): Round, no disk, very little gas and dust, only old stars.
Spiral galaxy (S): Central bulge, flattened disk, spiral arms, gas, dust, young stars.
Barred-spiral galaxy (SB): Elongated central structure, flattened disk, spiral arms, gas and dust, young stars.
Irregular galaxy (Irr): Asymmetric, often with gas, dust, and young stars.
Galaxies are huge collections of gas, dust, and stars. Gravity and dark matter shape and held them together. Scientists have segmented galaxies into 4 main types. These are of spiral, elliptical, peculiar, and irregular shape.
In the given question two columns of matching are not given. The rest part of the question is
Drag the appropriate items to their respective bins.
-Round, no disk, very little gas and dust, only old stars.
-Central bulge, flattened disk, spiral arms, gas, dust, young stars.
-Elongated central structure, flattened disk, spiral arms, gas and dust, young stars.
-Asymmetric, often with gas, dust, and young stars.
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fgure 24-30 shows a system of three charged particles. if you move th particle of charge from pooint a to point d
A) Moving the three-particle system from A to D has no effect on its electric potential energy.
B) When a particle is transferred from A to D, the total electric force exerted on it produces negative work.
C) When your force is shifted from A to D, it does not produce any work.
D) The values will be zero, negative, and zero if the particle is transferred from B to C.
comprehension of the potential energy idea.The total energy resulting because of all the charges present in the system determines the total potential energy for moving a charge from one location to another. Therefore, total potential energy is positive for two positive charges.
recognizing the idea of completed work.or work done, we just take into account the polarity of charges. The effort completed for equal polarity is found to have a positive regardless of its value. Our force's course determines the job that is accomplished by our force. The work done will be negative for the opposing path and force direction.
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The complete question is -
The figure shows a system of three charged particles. If you move the particle of charge from point A to point D, are the following quantities positive, negative, or zero: (a) the change in the electric potential energy of the three-particle system, (b) the work done by the net electric force on the particle you moved (that is, the net force due to the other two particles), and (c) the work done by your force? (d) What are the answers to (a) through (c) if, instead, the particle is moved from B to C?
two football players collide head-on in midair, moving along the same horizontal direction, while trying to catch a thrown football. the first player is 86.5 kg and has an initial velocity of 6.15 m/s (in the positive direction), while the second player is 118.5 kg and has an initi
Final Velocity = 4.65 m/s
From the question, we have
Mass of player one M1= 98.5kg
Initial Velocity U1= 6.05m/s
Mass of player two M2= 119kg
Initial velocity U2= -3.50m/s
Final Velocity = V
Utilizing the idea of linear momentum conservation,
M1U1 + M2U2 = (M1+M2)V
98.5*6.05 + 119*3.50 = (98.5+119)*V
595.925 + 416.5 = 217.5V
1012.425 = 217.5V
V = 1012.425/217.5
V = 4.65 m/s
Principle of conservation of linear momentum:
According to the conservation of momentum, the total momentum before and after a collision will be the same if there is no external force acting on the colliding objects.
Complete question:
Two football players collide head-on in midair while trying to catch a thrown football. The first player is 98.5 kg and has an initial velocity of 6.05 m/s, while the second player is 119 kg and has an initial velocity of −3.50 m/s. What is their velocity (in m/s) just after impact if they cling together? (Indicate the direction with the sign of your answer.)
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at one particular moment, a 19.0 kg toboggan is moving over a horizontal surface of snow at 3.70 m/s. after 8.25 s have elapsed, the toboggan stops. use a momentum approach to find the magnitude of the average friction force (in n) acting on the toboggan while it was moving.
The average friction force acting on the toboggan is 8.25 N.
This is the force which acts between the surfaces when one body is moved on the surface of another body. Friction force opposes the motion of a body.
We are given,
[tex]V_{i[/tex]= 3.70 m/s
[tex]V_{f[/tex] = 0
Δv = [tex]V_{f[/tex]- [tex]V_{i[/tex]= 0 - 3.70 = -3.70m/s
Momentum is the product of mass and velocity.
Change in momentum,
Δ momentum = m Δv = 19 kg × (-3.70m/s) = 70.3 kg m/s
The average friction force [tex]F_{f[/tex] takes 8.25 seconds to bring the toboggan to a stop.
so impulse = [tex]F_{t[/tex] = [tex]F_{f[/tex]×8.25
Impulse is equal to Δ momentum, so Ff(8.25) = 70.3
[tex]F_{f[/tex] = 8.25 N
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when a car moves towards a listener, the sound of its horn seems relatively group of answer choices low pitched (low frequency) high pitched (high frequency) normal (no change in frequency)
When an automobile approaches a listener, the noise of its horn appears to be somewhat higher in pitch than usual.
When someone hears the horn of an approaching automobile, the frequency you hear is higher than the frequency heard by a passenger in the car because the sound you hear has wave crests that are wider apart due to the distance that the car covers in one period.
The Doppler effect is a shift in sound wave frequency that happens when the originator of the sound waves moves relative to a motionless listener. As the generator of sound waves gets closer to the listener, the frequency & pitch of the sound increase.
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which of the following is not an input that the lifted index uses? view available hint(s)for part a which of the following is not an input that the lifted index uses? predicted max temperature of the day at the surface temperature at 500 mb average humidity in the lowest kilometer predicted max humidity of the day
The predicted max humidity of the day is not an input that the lifted index uses. LI is easier and faster to calculate. the lifted index can be used to forecast thunderstorms.
The lifted index (LI) is the temperature differential between the environment Te(p) and an adiabatically raised air parcel Tp(p) at a certain pressure height in the troposphere (the lowest layer of the atmosphere where most weather occurs), typically 500 hPa (mb). The temperature is expressed in degrees Celsius. When the value is positive, the atmosphere (at that height) is stable; when it is negative, the atmosphere is unstable. Although the lifted index can be used to forecast thunderstorms, convective available potential energy (CAPE) is widely regarded as a superior metric of instability and is favored by many meteorologists for convection forecasting. However, LI is easier and faster to calculate without a computer, whereas CAPE involves integration from one level to the next.
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bob's car ran out of gas 3.4 km from the nearest gas station. if it requires a 500 n force to push his car, how much work will bob do to get his car to the gas station? (1.7 MJ or 1.7 10 j)
The mileage of the car is calculated by dividing the number of miles traveled by the amount of gas used. Car's Gas Mileage is 147.0
How do you calculate how far you can go on a tank of gas?Gas Run Out.Turn on your hazard lights and safely pull your car over to the right shoulder.If you have emergency gear, such as a reflective triangle, set it up as needed.Go for a stroll to the closest gas station.Place a roadside assistance call.How to Calculate Your Car's Gas MileageThe outcome is your car's normal miles per gallon, which you can calculate by dividing the distance traveled by the number of petrol tanks you filled up.For instance, your car would average 25 miles per gallon if you traveled 200 miles on 8 gallons of gas.Car's Gas Mileage = 500/3.4
=147.0
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in comparing two unequal forces on a rigid body, is it possible to have the larger force produce less torque than the smaller force?
It is not possible to have the larger force produce less torque than the smaller force for a rigid body because they will produce the same zero torque.
What is torque?
Torque can be defined as a rotational effect caused by an applied force on an object.
In other words torque refers to the twisting force that causes motion or the the turning effect of an applied force.
Mathematically, the formula for an applied torque is given as;
τ = Fr
where;
F is the applied forcer is the perpendicular distance of the objectFor a rigid body, the resultant torque applied to such body will be zero. Hence, both large force and small force will produce the same torque (twisting effect).
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No astronomical object that produces a continuous visible spectrum of light has ever been observed. However, there are many astronomical objects that produce emission or absorption spectra. Read the following descriptions of astronomical objects, and then sort the labeled images into the appropriate bins according to the type of spectrum each object produces
Emission spectrum:
- Emission nebula
- Planetary nebula
Absorption spectrum:
- Sun
- Atmosphere on Titan
Spectroscopy is a highly valuable method of astronomical investigation. Astronomers can determine the composition, density, and temperature of celestial bodies by interpreting the light they emit or absorb.
Emission Spectra
- Emission Nebula
- Planetary Nebula
Absorption Spectra
- Titan's Atmosphere
- Sun
Astrophysics is the science that applies the methods and principles of physics and chemistry to the study of celestial bodies and phenomena. As one of the founders of astrophysics put it, astrophysics is about ``determining the nature of celestial bodies, not where they are, not their positions and movements. ”. Stars, galaxies, exoplanets, the interstellar medium, and the cosmic microwave background. Emissions from these objects are examined across all parts of the electromagnetic spectrum, and properties examined include luminosity, density, temperature, and chemical composition. Because astrophysics is such a broad subject, astrophysicists study classical mechanics, electromagnetism, statistical mechanics, thermodynamics, quantum mechanics, relativity, nuclear physics, particle physics, atomic physics, molecular It applies concepts and methods from many fields of physics, such as physics.
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The ____ successfully discovered thousands of extrasolar planets with a spacecraft that searched for transits among some 100,000 stars.
The Kepler Mission successfully discovered thousands of extrasolar planets with a spacecraft that searched for transits among some 100,000 stars.
Kepler mission was initiated by NASA's researcher William Borucki with the main goal of launching a space shuttle containing Kepler space telescope in order to survey and monitor planets and stars in our milky way galaxy as well as those beyond of our solar system. The space craft containing the Kepler space telescope was launched by NASA in March 7th 2009. The Kepler mission successfully identified that there are more than 2600 exoplanets or extrasolar planets that orbits the star outside of our solar system, and some of which were identified to be suitable planets for a form of life to exist.
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Wire 1 of
50 cm
in length forms a one-turn loop, and a bar magnet is dropped through. Wire 2 of
100 cm
in length forms a two-turn loop, and the same magnet is dropped through. Compare the magnitude of the induced voltages in these two cases.
v 2 =2⋅V 1
v 1 −v 2 =0
v 1 −v 2 +10
v 1 =2+v 2
Induced Voltage is an electric potential that is created by an electric field, magnetic field, or current. The induced voltage is produced as a result of electromagnetic induction.
How do you get induced voltage?
The induced voltage is produced as a product of electromagnetic induction. Electromagnetic induction is the procedure of producing emf (induced voltage) by exposing a conductor into a magnetic field. The induced voltage is described by making use of Faraday's law of induction.
How is the voltage induced measured?
the voltmeter with the wire ends connected. Connect a 6 V or 12 V AC power source to the primary coil. Add turns to the transformer's secondary side, then gauge the induced voltage.
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Which of the following experiments could be used to determine the inertial mass of a block? A. Place the block on a rough horizontal surface. Lift one end of the surface up and measure the angle the surface makes with the horizontal at the moment the block begins to slide. B. A Drop the block from different heights and measure the time of fall from each height. C. Place the block on a rough horizontal surface. Give the block an initial velocity and then let it come to rest. Measure the initial velocity and the distance the block moves in coming to rest. D. Use a spring scale to exert a force on the block. Measure the acceleration of the block and the applied force.
Parallel to the ground or to the bottom or top edge of something:
What is a perfectly horizontal surface called?The experiment that could be used to determine the inertial mass of a block is ; ( D ) Using a spring scale to exert a force on the block. Measure the acceleration of the block and the applied force.Inertial mass is the mass of a body that poses an inertial resistance to the acceleration of a body when forces are applied to it. before you inertial mass can be determined, force must be applied to the body at rest .The experiment that is suitable to determine the inertial mass is using a spring scale to apply a force on the block, then take measurement of the acceleration experienced by the block and amount of force applied.=Inertial mass = acceleration / net force appliedHence we can conclude that The experiment that could be used to determine the inertial mass of a block is Using a spring scale to exert a force on the block. Measure the acceleration of the block and the applied force.
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