Pulley Block A of mass 4m is attached by a light string to block B of mass 2m. The string passes over a pulley with negligible friction and of negligible mass. Block A is held a distance h above the ground, as shown. The blocks are released from rest, and block A reaches the ground two seconds later. The value of h is most nearly
a. 13.3 m b. 6.7 m c. 3.3m d. 2 m
Answers
The value of h is most nearly 6.7 m. option B is the correct answer
From the question, we have
Body mass m1 = 4 kg
mass of the body on the ground m2 = 2 kg
descent time t = 2s
From Newton's second law,
T - W₁ = m₁ a
-T + W₂ = m₂ a
Solving, we get
a = -3.27 m / s²
y = y₀ + v₀ t + ½ a t²
0= y₀ + 0 +½ a t²
y₀ = ½ 3.27 2²
y₀ = 6.54 m
The value of height is most nearly 6.7 m
Kinematics:
The net force, the mass, and the acceleration of a body are related by Newton's second law.
∑ F = m a
Kinematics investigates how objects move while searching for connections between position, speed, and acceleration.
y = v₀ t + ½ a t²
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Related Questions
based on this passage, which of the following might be true about the early history of modern physics? select it had a very practical component select it was uninteresting to most people select none of these select it was often combined with many topics studied in philosophy select it was underdeveloped and primitive
Answers
True statement about the early history of modern physics is option A: it had a very practical component.
The early history of physics could explain everything out of others, thus it had a practical component. The minds of almost all thinkers are left with the patterns of scientific reasoning and apotheosis in modern physics. From the time of the early renaissance to the nineteenth century, physics represented the ultimate expression of scientific investigation for almost all thinkers. The unchanging principles of all motion and life on earth are being derived from its static laws. By the nineteenth century, it seemed that most of science had already been "cleared up," and only a few remaining details remained.
This cosmology was overthrown by the idea of a universal morphing of kinds, which completely altered it. The very view of science held by most people was among the things that had to change in light of Darwin’s work.
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blocks a and b of masses m and 3m, respectively, are on a horizontal surface of negligible friction. a horizontal force fa is exerted on block a, as shown. if the force exerted by block b on block a has a magnitude f, the magnitude of fa is
Answers
If the force exerted by block b on block a has a magnitude f, the magnitude of fa is is f, because according to the newtons thied law of motion, the every force there is equal and opposite reaction.
Friction is the force resisting the relative motion of sturdy surfaces, fluid layers, and material factors sliding towards each specific. There are numerous styles of friction: Dry friction is a strain that opposes the relative lateral movement of two stable surfaces in touch.
Friction is a shape of contact pressure. It exists between the surfaces that are in touch. The frictional force relies upon on the character of the floor in contact. The rougher the ground, the extra the friction is involved. The frictional force is proportional to the urgent pressure, that is the burden of the body. it's miles impartial of the place of the touch.
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looking at waves a and b. which description correctly describes the waves?; which example is not a part of the electromagnetic spectrum?
Answers
Electromagnetic waves are transverse waves composed by the perpendicular oscillating electric and magnetic fields.
EM waves have both Electrical and magnetic features.
they travel in the velocity of light (3*10⁸ ms⁻¹)
Electromagnetic spectrum is obtained according to their wave length and the frequency. Due to wave length range it's categorized. Here is the decreasing order of wave length and increasing order of different wave types in electromagnetic spectrum
Examples,
Radio WaveMicro WaveIR waveLight WaveUV raysX raysGamma raysCosmic raysWhen electromagnetic radiation interacts with single atoms and molecule, its behavior also depends on the amount of energy per quantum(photon)it carries wave number =1/wavelength in cm speed of light=wavelength x frequency energy = Planck's constant x frequency.
Therefore, electromagnetic spectrum depends on wavelength and frequency
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A nozzle with a radius of 0.21 cm is attached to a garden hose with a radius of 0.95 cm that is pointed straight up. The flow rate through hose and nozzle is 0.45 L/s. Randomized Variables r, = 0.21 cm r= 0.95 cm O=0.45 L/S 50% Part (a) Calculate the maximum height to which water could be squirted with the hose if it emerges from the nozzle in m. Grade Summary h2= Deductions 0% Potential 100% sin() cos t an() ( 7 8 9 HOME Submissions cotan asin() acos M ^ Attempts remaining: 7 4 5 6 (3% per attempt) atan acotan sinh( * 1 2 3 = detailed view cosh tanh cotanh + - 0 END Degrees O Radians NO BACKSPACE CLEAR Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 4 Feedback: 0% deduction per feedback. 50% Part (b) Calculate the maximum height (in cm) to which water could be squirted with the hose if it emerges with the nozzle removed, assuming the same flow rate.
Answers
The greatest height that the water can depart through the two points using fluid mechanics expressions is as follows:
1) y = 0.20 m is the maximum height that the water can exit the hose at.
2) The water shoots out of the nozzle at a maximum height of 68.6 meters.
When the water exits the hose, the pressure is atmospheric, and it is the same when it reaches its greatest point. P1 = P2
12 v12 + g y1 = 12 v22 + g v2
At the highest point of trajectory the velocity must be =zero.
y₂- y₁ = [tex]v^{2} /2g[/tex]
Let's calculate
Δy = 0.2 m.
Using Bernoulli's equation, the speed of the water is the highest point=0.
Δy = 68.6m
What law contains the Bernoulli equation?The law of energy conservation is the foundation of Bernoulli's principle, to the fullest extent possible. At various sites when liquid is flowing under a constant pressure differential, the whole energy of the liquid—including pressure energy, potential energy, and kinetic energy—is equalized.
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❧ What is the dispersion of White Light?
Answers
When white light is passed through a glass prism it splits into its spectrum of colours (in order violet, indigo, blue, green, yellow, orange and red) and this process of white light splitting into its constituent colours is termed as dispersion.
What causes the dispersion of white light?Cause of Dispersion: When white light passes through a glass prism, its constituent colours (red, orange, yellow, green, blue, indigo, violet) travel with different speeds in the prism because refractive index is color dependent. This causes the dispersion of light.The bending of the colors when they pass through the prism depends on its wavelength. So violet color has a shortest wavelength as a result it bends the most and followed by indigo, blue, green, yellow, orange and red respectively.The splitting of light into its component colors is called dispersion of light. Dispersion of white light can be done by a glass prism. The inclined refracting surface of a glass prism shows this phenomena.When a prism is placed in a room and a beam of white light is allowed to fall on one of its refracting faces. It is found that light coming out from the other face of the prism is split into seven colors (violet, indigo, blue, green, yellow, orange, red).To learn more about White light refer to:
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(figure 1) shows five identical light bulbs a-e connected to a battery. initially, some of the bulbs light up because the two terminals of each bulb are connected to opposite terminals of the battery. if any wire in the circuit is cut, some bulbs may go out. figure1 of 1 part a part complete which bulbs, if any, go out when a single cut is made at location a? check all that apply. a b c d e none previous answers correct part b which bulbs, if any, go out when a single cut is made at location b? check all that apply. which bulbs, if any, go out when a single cut is made at location ?check all that apply. a b c d e none request answer part c which bulbs, if any, go out when a single cut is made at location c? check all that apply.
Answers
Figure shows five identical light bulbs a-e connected to a battery.
Part A: The potential at points 1 and 3 is different because of the internal resistance of B, so B is already glowing.
Part B: If a cut is made at point b, then no bulb will go out because C is already fused.
Part C: If a cut is made on C, then no bulb will go out because D and E were already fused.
What is the potential difference?When two places in a circuit contain different amounts of charge carriers' energy, this is referred to as a potential difference.
Part A:
Use the concept of potential difference to understand this question.
The bulb will only be lit when there is some potential difference. If the potential difference is zero, then the bulb will not light.
First, redraw the diagram and shown it below:
The potential at points 1 and 3 is different because of the internal resistance of B, so B is already glowing.
Part B
The potential at points 3 and 4 is the same because there is no resistance between them and the potential across C is 3 and 4. So, the potential difference is zero across C and it was already fused.
So, if a cut is made at point b, then no bulb will go out because C is already fused.
Part C
The potential at points 2, 4, 5, and 6 is the same. The potential across D and E is 5 and 6. The potential difference is zero across them, so they were already fused.
If a cut is made on C, then no bulb will go out because D and E were already fused.
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The complete question is as follows:
Many satellites move in a circle in the Earth's equatorial plane. They are at such a height above the Earth's surface that they always remain above the same point. Such an orbit is said to be geosynchronous. Find the altitude of these satellites above the Earth's surface.
Answers
a) The altitude of these satellites above the Earth's surface is h = 3,588 10⁷ m , b) by the curve of the planet; consequently, the signals cannot reach these places
What is law of universal gravitation?
For this issue we must use the law of universal gravitation, with Newton's second law
F = m a
G m M / r² = m a (1)
Centripetal acceleration
a = v² / r
How the speed (speed) module is constant
v = d / t
Circle the distance in a complete orbit with a time (T) called period
d = 2π r
v = 2π r / T
a = (4π² r² / T²) / r
We substitute in equation 1
G M / r² = 4π² r / T²
G M / r³ = 4π² / T²
r = ∛ GM T² / 4π²
R is the distance from the center of the earth, the distance from the surface is
R = Re + h
Re + h = ∛ GM T²/ 4π²
h = ∛(G M T²/4π²) - Re
Let's reduce to SI units
T = 1 day (24h / 1 day) (3600s / 1h)
T = 86400 s
Let's calculate
h = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (8.6400 10⁴)² / 4π²) - 6.37 10⁶
h = ∛ (75.42 10²¹) - 6.37 10⁶
h = 4,225 10⁷ - 0.637 10⁷
h = 3,588 10⁷ m
b) In the attached you can see that for very large latitudes the linear path from the satellite to the earth is interrupted, by the curve of the planet; consequently, the signals cannot reach these places.
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Which one of the following temperatures is equal to 5 degrees Celsius? 41k, 278k, 0k, 465k
Answers
Answer:
5°C is equal to 278 K.
Explanation:
0 degrees Celsius is equal to 273.15 Kelvins. The basic formula is °C + 273.15 = K. Kelvin to Celsius: Add 273.
you now take three pieces of string from the previous problem and tie two of them together to make a string of double the mass density. you tie the single string and double string together and to two lamp posts that are 40 m apart as seen below. the interface is centered between the posts and the tension is 1.2 n. you briefly shake the string interface at 5 hz. By how many seconds does it win the race?
Answers
Taking three pieces of string from the previous problem and tie two of them together to make a string of double the mass density, V₁ = [tex]\sqrt{2}[/tex]V₂ it wins the race.
What is the mass density?An object's mass per unit volume is referred to as its mass density. The units that can be used to describe this characteristic are pounds per square foot (lb/ft²) and kilograms per square meter (kg/m³).
Given that,
tension = 1.2 N
Frequency = 5 Hz.
Length = 40 m
Let, mass density of thin string = m
mass density of thick string = 2m
As we know,
V₁ = [tex]\sqrt{F/m}[/tex]
V₂ = [tex]\sqrt{F/2m}[/tex]
Now,
V₁/V₂ = [tex]\sqrt{F/m} / \sqrt{F/2m}[/tex]
or, V₁/V₂ = [tex]\sqrt{2} /1[/tex]
or, V₁ = [tex]\sqrt{2}[/tex]V₂
Thus, speed of the thin string is [tex]\sqrt{2}[/tex] times greater than the speed of the thick string. So, it will comes first.
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A thermos contains m1 = 0.89 kg of tea at T1 = 31° C. Ice (m2 = 0.075 kg, T2 = 0° C) is added to it. The heat capacity of both water and tea is c = 4186 J/(kg⋅K), and the latent heat of fusion for water is Lf = 33.5 × 104 J/kg. show answer No Attempt 50% Part (a) Input an expression for the final temperature after the ice has melted and the system has reached thermal equilibrium.Part (b) What is the final temperature in Kelvin?
Answers
The final temperature in Kelvin was 295.52 K.
Explain about the temperature in Kelvin?The difference between a kelvin (K), a division of the kelvin scale, and a degree on the Celsius scale is where zero is. The zero point on the Kelvin scale is at absolute zero, while the zero point on the Celsius scale is the freezing point of water. As a result, 0oK is equivalent to -273.15oC, while 0oC is equivalent to 273.15 kelvins.
The Standard International (SI) unit of thermodynamic temperature is the kelvin, which is also sometimes referred to as the degree Kelvin (symbol, o K). The formal definition of a kelvin is 1/273.16 (3.6609 x 10 -3) of the thermodynamic temperature of pure water's triple point (H 2 O).
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find the work done be the force field f in moving an object along the curve pictured in the graph. do this by computing the work on each piece-wise smooth portion of c.
Answers
Find the amount of labor necessary to move an object along the specified orientated curve given the force field F. y = 3x2 on the parabola from (0, 0) to F = (y, x) (4, 48).
How can you determine the work a force field performs along a curve?A variable force's infinitesimal work can be defined in terms of the force's components and the displacement along the path,
How do you assess the force field F's work?(c) Next, determine the work that the force field F performed on the object to move it through the field by moving it along the vector d. W = F d is the formula for work.
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What are three ways you could cause the acceleration of a moving car?; What are the 3 different ways you can accelerate?; What causes the acceleration of a car?; What are the ways to accelerate?
Answers
The three ways to acceleration a moving vehicle are to depress the accelerator pedal, depress the brake, push the vehicle, or exert external force.
The rate at which the velocity of an object varies in relation to time is known as acceleration. Accelerations exist in vector quantities (in that they have magnitude and direction). The object's acceleration is determined by the direction of the net force acting on it. The size of the net balance of all external forces acting on the item is, in accordance with the materials used to create it, inversely proportional to its mass, but the magnitude of the net resultant force is directly proportional to the net force.
A moving object's rate of change in direction and speed over time is called acceleration. It is said to be accelerating when anything goes faster or slower. Due to the frequent change in direction, motion on a circle accelerates even while the speed is constant.
Therefore, applying the brake, pushing the car, or applying external force are the four ways to accelerate a moving vehicle. The three other methods are pressing the accelerator pedal.
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To derive the formulas for the major characteristics of motion as functions of time for a horizontal spring oscillator and to practice using the obtained formulas by answering some basic questions.
A block of mass m is attached to a spring whose spring constant is k. The other end of the spring is fixed so that when the spring is unstretched, the mass is located at x=0. . Assume that the +xdirection is to the right.
The mass is now pulled to the right a distance Abeyond the equilibrium position and released, at time t=0, with zero initial velocity.
Assume that the vertical forces acting on the block balance each other and that the tension of the spring is, in effect, the only force affecting the motion of the block. Therefore, the system will undergo simple harmonic motion. For such a system, the equation of motion is
a(t)=-\frac{k}{m}x(t),
and its solution, which provides the equation for x(t), is
At what time t_1 does the block come back to its original equilibrium position (x=0) for the first time?
Express your answer in terms of some or all of the variables: A, k, and m.
Answers
The system will undergo simple harmonic motion, so at time,
t₁ = π/2( [tex]\sqrt{k/m}[/tex])
What is simple harmonic motion?Simple harmonic motion is described as the periodic motion of a point along a straight line with an acceleration that is always toward a fixed point on that line and a distance from that point that is proportional to that acceleration.
The equation of motion for the simple harmonic oscillation of spring mass system is,
a(t) = -k/m x(t)
here, a(t) = is the acceleration at any time
k = is the spring constant, and
m = mass
The equation for displacement is given as,
x(t) = A cos ([tex]\sqrt{k/m}[/tex])t
here,
x(t) = is the displacement at any time.
A = is the amplitude of oscillations,
The velocity is given by,
v(t) = dx(t)/dt
The general expression of velocity for a simple harmonic motion is,
v(t) = v(max) sin ([tex]\sqrt{k/m}[/tex])t
v(max) = is the maximum velocity.
The kinetic energy is given as,
K(t) = 1/2 m[v(t)]²
Now, use the equation of position:
or, x(t) = A cos ([tex]\sqrt{k/m}[/tex])t
or, 0 = A cos ([tex]\sqrt{k/m}[/tex]) t₁
or, t₁ = π/2( [tex]\sqrt{k/m}[/tex])
Thus, the position of particle at time t₁ is 0. The cosine function is zero first time at angle π/2. The time can be calculated by substituting the values in the position function.
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Assuming bicycle tires are perfectly flexible and support the weight of bicycle and rider by pressure alone, calculate the total area of the tires in contact with the ground. The bicycle plus rider has a mass of 62.0 kg, and the gauge pressure in the tires is 3.50×105 Pa.
Answers
The total area of tires in contact with the ground is [tex]17.36 cm^2[/tex] when mass of bicycle rider is 62 kg and pressure of tires is [tex]3.5*10^5 pascal[/tex]
Pressure is the amount of force exerted on surface per unit area. It can also be defined as the force-to-area ratio (over which the force is acting).
Given,
Mass of the bicycle rider = 62.0 kg
pressure in tires = [tex]3.50*10^5\ N/m^2[/tex] (1 pascal = 1 [tex]N/m^2[/tex])
From definition of pressure,
[tex]P=\frac{F}{A}.....i[/tex]
Where, p=pressure ,F= force applied and A= area perpendicular to force
Force can be determined by formula,
[tex]F=mg....ii[/tex]
Where, m= mass and g= gravitational acceleration=9.8m/s^2
substituting eq.ii in eq.i,
[tex]P=\frac{mg}{A}\\\\A=\frac{mg}{P}\\\\A=\frac{62*9.8}{3.5*10^5}\\\\A=\frac{607.6}{3.5*10^5}\\\\A=0.001736m^2=17.36cm^2[/tex]
Thus, the area of tires in contact with the ground is [tex]17.36 cm^2[/tex]
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This one is a challenge
A motorcycle traveled north along a straight path for 2.22 hours with an average velocity of 67.8 km/h, stopped for 20.0 min, then traveled north for 3.33 hours with an average velocity of 77.7 km/h.
What is the average velocity for the trip?
What is the displacement for the entire trip?
Answers
Where
Vavg - average velocity
dx - total displacement
dt - total change in time (in fact the amount of time spent from the beginning of the motion)
dx = 2.22*67.8 + 3.33*77.7 = 409.3 km
(Since motorcycle traveled in the same direction - North)
dt = 2.22 + 3.33 + 0.33 = 5.9
Vavg = 409.3 / 5.9 = 69.4 km/h
Answer:
Explanation:
1 track section:
V₁ = 67.8 km/h
t₁ = 2.22 h
2nd track section:
V₂ = 0 km/h
t₂ = 20.0 min = (1/3) h ≈ 0.33 h
3 track section:
V₃ = 77.7 km/h
t₃ = 3.33 h
___________
V - ?
D - ?
Length of 1 track section:
D₁ = V₁·t₁ = 67.8·2.22 ≈ 150.5 km
Length 2 sections of track:
D₂ = V₂·t₂ = 0·0.33 = 0 km
Length 3 sections of track:
D₃ = V₃·t₃ = 77.7·3.33 ≈ 258.7 km
Summary path:
D = D₁ + D₂ + D₃ = 150.5 + 0 + 258.7 = 409.2 km
Total time:
t = t₁ + t₂ + t₃ = 2.22 + 0.33 + 3.33 = 5.88 h
Average speed:
V = D / t = 409.2 / 5.88 ≈ 69.6 km/h
total internal reflection can occur when light is traveling from air to its interface with water air to its interface with glass glass to its interface with air water to its interface with glass click here to check your answer 11.11 pts.100% 25% try penalty
Answers
The total internal reflection can occur when light is traveling from glass to its interface with air.
Total internal reflection occurs when light moves from denser to rarer and the angle of incidence is greater than the critical angle.
Total Internal Reflection occurs when light travels from water to air, but it does not occur when light travels from air to water. Total Internal Reflection would occur for light travelling from water to air, but not for light travelling from water (n=1.333) to crown glass (n=1.52). TIR occurs when the angle of refraction approaches 90 degrees before the angle of incidence approaches 90 degrees. Light can only bend away from the normal if the angle of refraction is greater than the angle of incidence. Because light only bends away from the normal when passing from a denser medium to a denser medium, this would be a necessary condition for total internal reflection.
Thus, TIR occurs when light is travelling from glass towards air.
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A 20.0cm massless spring with spring constant 340N/m is suspended from the ceiling. A student carefully hangs a 450g mass from the free end. How long is the spring now?
Answers
After hanging the mass, the length of the spring is 21.3 cm using Hooke's law.
What is Hooke's law?According to the physics principle known as Hooke's Law, the force required to expand or compress a spring by a given distance is inversely proportional to that distance.
The first traditional example of an explanation of elasticity is Hooke's law. Elasticity is the quality of a substance or item that allows it to return to its original shape after distortion. A restoration force is a capacity to restore the original shape after experiencing distortion.
Given,
Equilibrium length of the massless spring = 20 cm
Spring constant k = 340 N/m
The spring is suspended from the ceiling.
Mass at the free end = 450 g
= 0.45 kg
A force is applied vertically downward on the spring due to the suspended mass which is equivalent to the weight of the mass i.e.
F = mg ... (1)
This force is balanced by the spring. If the spring is extended by a length of due to the suspension of the mass then by Hooke's law,
F = kx ... (2)
From equation (1) and (2)
mg = kx
x = mg/k
Put all the values
x = (0.45)(9.8)/(340)
= 0.013 m
= 1.3 cm
So, the length of the spring is
l = 20 + 1.3
= 21.3 cm
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The spring is compressed by 10 cm. It launches the block across a frictionless surface with speed 0.50. The two springs in are identical to the spring of Figure a. They are compressed by the same 10 cm and used to launch the same block. What is the block's speed now?
Answers
The block's speed when two springs used to launch the same block is 0.71 m/s.
The problems not complete, look at the attachment to see the picture. In picture (2) two springs paralleled. The constant for two paralleled springs
k = k₁ + k₂
k = 25 + 25
k = 50 N/m
When the springs compressed, the conservation energy law applies.
K.E block + P.E springs = K.E' block + P.E' springs
The block initially stop.Kinetic energy for the block before launching is zero.
K.E block = 0The potential energy for spring before launching
P.E springs = 0.5 × k × Δx²The kinetic energy for the block after launching
K.E' block = 0.5 × m × v²The potential energy for spring after launching is zero.
P.E' springs = 0Δx = 10 cm = 0.1 mm = 1 kg
0 + 0.5 × k × Δx² = 0.5 × m × v² + 0
k × Δx² = m × v²
50 × 0.1² = 1 × v²
0.5 = v²
[tex]v = \sqrt{0.5}[/tex]
v = 0.71 m/s
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What is the speed of the wave if its wavelength is 3.0 m?; What is the wavelength of a wave with a speed of 12 m/s and a frequency of 3hz?; How do you find frequency when given wavelength and speed?; How do you find frequency of a wave?
Answers
The wavelength and speed of a wave are known, these can be used to find the frequency of a wave using the equation f=vλ f = v λ.
Wavelength can always be determined by measuring the distance between any two corresponding points on adjacent waves. In longitudinal waves, wavelength measurements are made by measuring the distance from one compression to the next or from one rarefaction to the next.
Forms of electromagnetic radiation such as radio waves, light waves, and infrared waves create characteristic patterns as they travel through space. Each wave has a specific shape and length. The distance between peaks is called the wavelength.
Wavelength is the distance between two wave crests and the same for wave troughs. Frequency is the number of oscillations that pass through a particular point in one second, measured in cycles per second this article discusses the relationship between wavelength and frequency.
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5. The moon orbits at a speed of about 1000 m/s around the earth at a radius of about
384,000,000 meters. Use this information to find an approximate value for the mass of
the earth. (Remember that G is 6.67E-11)
Answers
Actually, they are a long way away. On average, the distance to the Moon is 238,855 miles (384,400 km).
How do you determine the Moon's orbital speed around the Earth?Using the formula v=2rT, where r is the distance between the earth and the moon and T is the period of time that the moon revolves around the earth, we can attempt to answer this question.
How can the orbit of the Moon be used to compute the Earth's mass?All that is left to do is use G = 6.6 x 10-8 and substitute pi = 3.14159, the Moon's period in seconds, T, and its distance from the Earth's center, R.
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Which force is greater when a bug hits a windshield?
Answers
Answer:
Below
Explanation:
The forces are equal..but opposite........the bug just doesn't handle it as well
In a period of 1.00 s, 5.00×1023 nitrogen molecules strike a wall with an area of 8.00cm2. Assume the molecules move with a speed of 300 m/s and strike the wall head-on in elastic collisions. What is the pressure exerted on the wall? Note: The mass of one N2 molecule is 4.65×10−26kg.
Answers
A wall with an area of 8 cm² is struck by 5.00 x 10²³ nitrogen molecules over the course of 1 s. Assume that the molecules are moving at a speed of 300 m/s and colliding with the wall in an elastic manner. The pressure acting on the wall is 17.43 kPa.
Mass in motion is a definition of momentum. Mass and velocity are multiplied to determine momentum. That is, p = mv where p,m, and v denotes momentum, mass, and velocity.
Given the change in the time period, Δt is 1 second, the number of nitrogen molecules is 5.00×10²³ molecules, the change in velocity Δv is 300 m/s, and the area is 8×10⁻⁴ m².
The momentum of one molecule is given as 2mΔv. Then, the momentum of N molecules is 2NmΔv.
The force exerted on the wall by nitrogen molecule is written as,
[tex]\begin{aligned}\text{Force F}&=\frac{\Delta\text {momentum}}{\Delta t}\\&=\frac{2Nm\Delta v}{\Delta t}\end{aligned}[/tex]
Then, the pressure exerted by nitrogen molecule on the wall is,
[tex]\begin{aligned}P&=\frac{F}{A}\\&=\frac{2Nm\Delta v}{\Delta t\times A}\\&=\frac{2\times 5\times10^{23}\times4.65\times10^{-26}\times300}{8\times 10^{-4}\times 1.00}\\&=\mathrm{17.43\;kPa}\end{aligned}[/tex]
Therefore, the required answer is 17.43 kPa.
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The reaction that converts a saturated dicarboxylic acid into an unsaturated one
Spell out the full name of the enzyme.
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The reaction that converts a saturated carboxylic acid into an unsaturated one is the succinate dehydrogenase enzyme.
What is acid?Any material that tastes sour when dissolved in water is an acid. It also alters the color of some indicators (such as reddening blue litmus paper), reacts with some metals (such as iron) to release hydrogen, combines with bases to create salts, and facilitates a number of chemical activities (acid catalysis).
Sulfuric, nitric, hydrochloric, and phosphoric acids, as well as organic chemicals, belong to the carboxylic acid, ammonium sulfate, and phenol groups, are examples of acids.
Acids are also inorganic entities known as alkaline solutions. These chemicals have one or more hydrogen atoms, which are discharged as positively charged ions in solution.
The full name of the enzyme is succinate dehydrogenase enzyme.
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Describe the motion of a particle with position (x, y) as t varies in the given interval. (For each answer, enter an ordered pair of the form x, y.) x = 1 + sin(t), y = 5 + 6 cos(t), 1/2 Sts 2n The motion of the particle takes place on an ellipse centered at (x,y) = ( As t goes from 1/2 to 21, the particle starts at the point (x,y) (O and moves clockwise three-fourths of the way around the ellipse to (x,y) = Need Help? Read It
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The particle moves along an ellipse with its center at (1,5). As t changes from π/2 to 2π, the particle begins at the location (6,1) and travels clockwise three-fourths of the way around the ellipse to (5,7).
According to the Pythagorean identity, sin²θ+cos²θ=1. The equation of the ellipse when the horizontal axis (main axis) is parallel to the y-axis is given as [tex]\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1[/tex] where (h,k) is the ellipse center, a is the major axis length, and b is the minor axis length.
Given x = 1 + sin(t) and y = 5 + 6 cos(t), π/2 ≤ t ≤ 2π. Then,
[tex]\begin{aligned}x& = 1 + \sin(t)\\\sin t&=x-1\end{aligned}[/tex]
and
[tex]\begin{aligned} y&= 5 + 6 \cos(t)\\\cos t&=\frac{y-5}{6}\end{aligned}[/tex]
Then, using Pythagorean identity,
[tex]\begin{aligned}\cos^2t+\sin^2t&=1\\\left(\frac{y-5}{6}\right)^2+\left(\frac{x-1}{1}\right)^2&=1\end{aligned}[/tex]
Comparing the above equation with the equation of an ellipse, we can tell, the center (h,k) is (1,5). Here, a is 6 and b is 1. So the radius of the vertical axis (major axis) is 6 and the radius of the horizontal axis (minor axis) is 1.
As t starts from π/2 to 2π, the particle starts at the point,
(5+1, 1) = (6,1)
And the particles move three-fourths of the ellipse in a clockwise direction to,
(5, 1+6) = (5,7)
Therefore, the blanks can be filled with (1,5), (6,1), and (5,7).
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a mass m at the end of a spring oscillates with a frequency of 0.78 hz . when an additional 730 g mass is added to m, the frequency is 0.65 hz . What is the value of m?
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The value of mass m = 0.506kg
Initial frequency = 0.78Hz
additional mass = 730 g = 0.73kg
New frequency = 0.65 Hz
F = 1/2π [tex]\sqrt{x\\}k/m[/tex]
0.78 = 1/2π [tex]\sqrt{k/m}[/tex]
additional mass,
0.65 = 1/2π [tex]\sqrt{k/m+0.65}[/tex]
1.44 = k/m / k/m+0.73
1.44 = m+0.73 / m
1.44m -m = 0.73
1.44m = 0.73
mass m = 0.506kg
a measurement used in physics to express the inertia, a quality that all matter has in common. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilograms is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one kilogramme times one square metre per second. The kilogramme is determined by precise measurements of Planck's constant, while the second and metre are already defined in terms of other physical constants.
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suppose the ball is dropped. what force is exerted on it while it is? identify the reaction force in this case as in free body diagram
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When a ball is dropped, the gravitational force that the Earth's gravitational field produces when the object descends downhill is exerted.
In a simple scenario, the ball falls in accordance with the direction of force of gravity, which is always downward. Gravitational acceleration on Earth is 9.8 m/s2 (g=9.8 m/s2). In essence, this indicates that the ball's velocity will increase by 9.8 m/s for every second while it is falling.
You should follow the steps below to determine the net force in one dimension. List every force influencing the thing. by depicting the object's free body in a diagram. Diirection upward is favorable, while diirection downhill is adverse. The net response force downward is obtained by subtracting the positive and negative forces from each other.
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Consider a pendulum swinging. Which type(s) of energy is/are associated with the pendulum in the following instances: i. the moment at which it completes one cycle, just before it begins to fall back towards the other end, ii. the moment that it is in the middle between the two ends, iii. just before it reaches the end of one cycle (just before instant i.).
i. potential, ii. kinetic, iii. potential and kinetic
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In the following situations, the type(s) the energy is/are related to the pendulum: potential kinetic potential,kinetic
When someone is kinetic, what does that mean?When an organism moves as a result of a stimulation like light, this is known as kinesis. Being able to use one's own internal kinesis power is what it means to be kinetic. Kinetics have such a supernatural ability, just like Telekinetics, Psychokinetics, and those who have Extra Sensory Perception.
What is it that makes kinetic energy move?Kinetic energy is the energy that any item has with a result of motion. An item can only be accelerated through the application of a force. Applying force requires effort on our part. Following completion of the work, energy is transmitted to the object, which then moves at the a new, consistent rate.
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Figure shows objects with charges. Show from which object the electrons flows. State why. In
which of these figures do you get a static electric spark? Draw the spark on the figure.
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It is to be noted that the electron flows occur in Figures (a) and (d).
What is the rationale for the above answer?The total number of electrons in the left plate is equal to the total number of positive charges in the right plate in Figure (a). As a result, no electron flow occurs here. A static electric spark does not occur.
The left plate in Figure (b) has three negative charges and three positive charges. The right plate, on the other hand, has five negative charges and one positive charge. As a result of the neutralization effect, the plates now have additional negative charges. As a result of the extra electrons present, a static electric spark occurs.
The identical thing happens in Figure (c) as it does in Figure (b). As a result, an entire static electric spark happens here as well. The complete negative charges on the right plate are flowing toward the ground in Figure (d). As a result, the left side plate has total negative charges while the right side plate has total positive charges.
As a result, we can see that the electrons flow in Figures (a) and (d). While figures (b) and (c) show static electric sparks.
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Each item below can be used to measure the distances of astronomical objects. Rank them according to how far away each method works, from nearest to farthest.
1. Cepheids
2. Radar ranging
3. White dwarf supernovae
4. Parallax
Radar ranging, parallax, Cepheids, white dwarf supernovae
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Each item below can be used to measure the distances of astronomical objects. Rank them according to how far away each method works, from:
Radar ranging > parallax > Cepheids > white dwarf supernovae
The plain displacement or the difference in apparent course of an item as seen from specific factors not on a immediately line with the item. especially : the angular distinction in direction of a celestial frame as measured from two points on the earth's orbit.
Parallax is the discovered displacement of an item due to the trade of the observer's point of view. In astronomy, it's far an irreplaceable tool for calculating distances of some distance away stars.
Parallax mistakes is whilst the pointer of a device looks like it is at a special analyzing when study to the aspect in comparison to when examine face-on. This is because of the gap among the size and the pointer.
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Stanley Milgram Shock experiment participants gave intense electric shocks to strangers if they were asked to do so by the experimenter No shocks were actually delivered but the participants believed that they were delivering the shocks and kept shocking the stranger (who was really an actor seated in another room) as punishment for responding incorrectly to a word problem
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The Milgram Experiment with Shock By Saul McLeod, 2017 update One of the most well-known experiments on obedience in psychology was conducted by Yale University psychologist Stanley Milgram.
He conducted an experiment that looked at the tension between following orders and one's conscience. Stanley Milgram, a social psychologist at Yale University, conducted the Milgram experiment (or experiments) on compliance to authoritative persons. November 5, 2018 revision. Stanley Milgram, a psychologist, investigated the ideas of submission and authority in a number of research in the 1960s. His studies comprised giving study participants orders to shock an actor in a different room with shocks of increasing voltage; the actor would scream at first and then go silent as the shocks grew stronger.
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