P(x) Q(x) = R(x); if P(x)
72 Am
R(x); if P(x)=x+2 and R(x) = x³ - 3x² - 6x-2, what is Q(x)?

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

"If the 2 is quantity use multiply it again"

NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

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[tex]\large\bold{SOLUTION} \\ [/tex]

GIVEN :-

FIND :-

By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .

[tex] \bold{Formula:}[/tex]

[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]

Now let's start solving :-

[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]

[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]

[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]

[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]

Therefore, the area of the space that needs to be covered is 100.80ft² .

[tex] \underline{ \rule{185pt}{3pt}}[/tex]

7h-15h+40=-72

40+72=15h-7h

112=8h

h=14

[tex]\textsf {21 cm}[/tex]

[tex]\textsf {If it is correct to the nearest centimeter, then the least side length}\\\textsf {would be 8 - 1 = 7 cm. }[/tex]

[tex]\textsf {Then, the least possible perimeter would be :}[/tex]

[tex]\mathsf {7 \times 3}[/tex]

[tex]\textsf {21 cm}[/tex]

One complete period of a non-transformed cotangent function is π.

The period of the function is defined as the interval after which the function value repeats itself.

For example, f(T+x)=f(x)

where T is the period of the function.

Here given that there is a non-transformed function cotangent function.

We have to find the period of the function in which interval the value of the function will repeat.

So for the function y=f(x)=cot x

the period of the function is π. means after π the value of the cotangent repeats.

cot(π+x)=cot x

Then one cycle of the cotangent graph lies between 0 and π.

Therefore One complete period of a non-transformed cotangent function is π.

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Step-by-step explanation:

1. let n=2, then, n+2= 2+2=4 so 2^2= 4 and 4^2=16 then 16-4=12 which is an even number

2. let n=4, the. n+3=4+3=7, and 4^2=16 and 7^2=49 then 49-16 =33 which is an odd number

please follow me

(a) The fraction of books that are fiction is 2/3.

(b) The fraction of books that are non-fiction is 1/3.

To find the fraction of fiction and non-fiction books on a bookshelf:

Given: A bookshelf has 96 books. 64 of the books are fiction and the rest are non-fiction books. (a)Fraction of fiction books =?

(b)Fraction of non-fiction books =?

Now,

As given, we have,

The total number of books on a bookshelf = 96

Out of 96, the total number of fiction books = 64

So,

The remaining number of books = non-fiction books = 96-64 = 32

(a) Fraction of fiction books = fiction books/total books

= 64/96

On simplification,

= 2/3

(b) Fraction of non-fiction books = non-fiction books/total books

= 32/96

= 1/3

Therefore, the fraction of fiction and non-fiction books is 2/3 and 1/3 respectively.

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the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

To do this, we can think on the situation as a right triangle, where the hypotenuse is 4 miles, the angle that we look at measures 10.5°, and the change in elevation (let's call it x) will be the opposite cathetus to that angle.

Then we can use the relation:

Sin(a) = (opposite cathetus)/(hypotenuse)

Replacing what we know, we get:

sin(10.5°) = x/4mi

x = sin(10.5°)*4mi = 0.73mi

So the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

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when you subtract a negative number from any platitude number the equation changes to addition so you would add the value of the negative number to 1.

To subtract a negative number from one you will need to set it up like this

1- (-x) x equals the negative number you're talking about

so we use the method KCC (keep change change)

So we KEEP the positive one, CHANGE the subtraction sign in to a plus sign "+" then CHANGE the negative number to a positive

lets say the negative number is 2

1-(-2)

1+ (+2)

1+2 = 3

Answer:

HI i no  answer of this quetion but what grade are in school

The transformation occurs from function g is a vertical translation 6 units down.

A function f, usually with some geometrical underpinning, that maps a set X to itself, i.e. f : X → X.

Given:

g(x) = 4x + 6

g(x) = 0

4x + 6=0

x= -6/4

Now,

f(-6/4) = 2 - 1

=-1

By seeing g(x), we can say that  function g is a vertical translation 6 units down.

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Answer:15

Step-by-step explanation:

Start off using Java. As u progress you cant move over to C and the then transfer to python.

Answer:

Step-by-step explanation:

Answer:

200:1, Bryn is correct.

Step-by-step explanation:

Each 10 m is represented by a 5cm length on the diagram.  We first note that 100 cm = 1 meter.   5 cm is (0.5 cm)*(1 meter/100 cm) =0.05 meters.

The 0.05 meters on the diagram represents 10 meters on the actual building.  The ratio is (10 meters/0.05 meters) or 200:1.  This is what Bryn believes is the ratio.  

Answer:

534

Step-by-step explanation:

The solution is in the image

Answer:

x = ± [tex]\sqrt{2}[/tex] , x = ± i

Step-by-step explanation:

f(x) = [tex]x^{4}[/tex] - x² - 2

to find the zeros , equate f(x) to zero , that is

[tex]x^{4}[/tex] - x² - 2 = 0

using the substitution u = x² , then

u² - u - 2 = 0 ← in standard form

(u - 2)(u + 1) = 0 ← in factored form

equate each factor to zero and solve for u

u - 2 = 0 ⇒ u = 2

u + 1 = 0 ⇒ u = - 1

convert u back into terms of x

x² = 2 ( take square root of both sides )

x = ± [tex]\sqrt{2}[/tex]

x² = - 1 ( take square root of both sides )

x = ± [tex]\sqrt{-1}[/tex] = ± i

Answer: Positive or negative square root of 2, ±i

Proof o fvalidity is shown below.

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Answer:  [tex]\textsf{y = -1/4x - 4}[/tex]

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Given: [tex]\textsf{Slope = -1/4, Point through = (4, -5)}[/tex]

Find:  [tex]\textsf{Equation for the line that passes through the given point}[/tex]

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

Plug in the values

Simplify and solve for y

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.

The remainder when f(x) = 2x³ + 2x² - 3x - 3 is divided by x - 2 is 15.

We know that the remainder theorem states that if a polynomial p(x) is divided by a linear polynomial q(x) whose zero is x = a, then the remainder is given by r = p(a).

Here p(x) = f(x) = 2x³ + 2x² - 3x - 3 and q(x) = x - 2. First, we have to find the zero of q(x).

Now, q(x) = 0

i.e. x - 2 = 0

i.e. x = 2.

So, the zero of q(x) is 2, i.e. a = 2.

Then by the remainder theorem,

r = p(a) = f(2) = 2(2)³ + 2(2)² - 3(2) - 3 = 2 × 8 + 2 × 4 - 6 - 3 = 16 + 8 - 9 = 16 - 1 = 15

We can conclude that the remainder when f(x) = 2x³ + 2x² - 3x - 3 is divided by x - 2 is 15.

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Answer:

b = 2

Step-by-step explanation:

using the tangent ratio in the right triangle and the exact value

tan30° = [tex]\frac{1}{\sqrt{3} }[/tex] , then

tan30° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{b}{a}[/tex] = [tex]\frac{b}{2\sqrt{3} }[/tex] = [tex]\frac{1}{\sqrt{3} }[/tex] ( cross- multiply )

b × [tex]\sqrt{3}[/tex] = 2[tex]\sqrt{3}[/tex] ( divide both sides by [tex]\sqrt{3}[/tex] )

b = 2

Answer:

Given that a = 2√3.

Let's find value of b...

The number of units that will maximize revenue will be 672 units.

From the given information, p = 336 - 0.5x. The revenue function will be:

= (336 - 0.5x)x

= 336x - 0.5x²

This will be equated to 0. This will be:

336x - 0.5x² = 0

0.5x² = 336x

0.5x = 336

x = 336/0.5

x = 672

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The table is a function and the relation f(x) = 5x + 14 has a greater value when x = 9

The table of values is given as:

Input (x) 2 5 9 12

Output (y) 20 15 12 8

In the above table of values, each x value have a unique y value.

This means that the table is a one-to-one relation

A one-to-one relation is a function

Hence, the table is a function.

The function is given as:

f(x) = 5x + 14

This gives

f(9) = 5 * 9 + 14

Evaluate

f(9) = 59

From the table, we have:

y = 12 when x = 9

Hence, the relation f(x) = 5x + 14 has a greater value when x = 9

We have

f(x) = 5x + 14

This gives

5x + 14 = 64

Subtract 14 from both sides

5x = 50

Divide by 5

x = 10

Hence, the value of x when f(x) = 64 is 10

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Answer:

Hey there : y= 3x - 3

Answer:

y = [tex]\frac{3}{2}[/tex] x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = [tex]\frac{3-0}{0-(-2)}[/tex] = [tex]\frac{3}{0+2}[/tex] = [tex]\frac{3}{2}[/tex]

the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = [tex]\frac{3}{2}[/tex] x + 3 ← equation of line

Answer:

{-3, 2, -5, 1, 6}

Step-by-step explanation:

The domain is the set of input values.

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Answer:  [tex]\textsf{x}^2\textsf{ - 14x + 24}[/tex]

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Given:  [tex]\textsf{x = 12 and x = 2}[/tex]

Find: [tex]\textsf{Determine the quadratic equation}[/tex]

Solution:  In order to determine the quadratic equation we need to move the integers onto the side where x is and then distribute.

Move the integers

Create and expression and distribute

Therefore, after completing the steps we were able to determine that the quadratic equation that will have solutions of x = 12 and x = 2 is x^2 - 14x + 24.

1.  m³

2. cm³

3. s³

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

1. Volume is measure in m³

2.  volume of a rectangular pencil case in cm³

3. V = s x s x s or s³

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Let's take this problem step-by-step:

Let's convert the equation back into the standard form:

     ⇒ standard form: (x-h)² +(y-k)² = r²

       [tex]x^2+y^2-8x+10y + 37 = 0\\\rm \hookrightarrow x^2 - 8x + y^2+10y = -37\\\rm \hookrightarrow (x^2 - 8x) + (y^2 + 10y) = -37\\\rm \hookrightarrow (x^2-8x+16) + (y^2+10y+25) = -37 + 16 +25\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 4\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 2^2[/tex]

Based on the equation found

  ⇒ center: (4, -5)

   ⇒ radius: 2

Answer:

Hope that helps!

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Answer:

9,000 minutes (150 hours)

Step-by-step explanation:

You have 3,600 points total; you need to divide it by 2 points.
3,600 ÷ 2 = 1,800

So, now you need to multiply the 1,800 points by 5 minutes.

1,800 × 5 = 9,000

Another way:

You can figure out how long it takes to get 1 point. If 2 points takes 5 minutes, divide 5 by 2.

5 ÷ 2 = 2.5

Now you need to figure out how long it would take to get 3,600 points. If each point takes 2.5 minutes, just multiply.

3,600 × 2.5 = 9,000

It would take 9,000 minutes (which is equivalent to 150 hours) to get to 3,600 points.

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: length = 11 \: \: in[/tex]

[tex]\qquad \tt \rightarrow \: width = 4 \: \: in[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

Let the measures be :

[tex] \textsf{\large Area of rectangle :} [/tex]

[tex]\qquad \tt \rightarrow \: Area = length \sdot width [/tex]

[tex]\qquad \tt \rightarrow \: 44 = x \sdot(x + 7)[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 7x = 44[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 7x - 44 = 0[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 11x - 4x - 44 = 0[/tex]

[tex]\qquad \tt \rightarrow \: x(x + 11) - 4(x + 11) = 0[/tex]

[tex]\qquad \tt \rightarrow \: (x + 11)(x - 4) = 0[/tex]

possible values of x = -11 and 4

[tex] \textsf{But the acceptable value of x = 4} [/tex]

[ length or width of rectangle can't be negative ]

[tex]\qquad \tt \rightarrow \: length = x + 7 = 4 + 7 = 11 \: \: in[/tex]

[tex]\qquad \tt \rightarrow \: width = x = 4 \: \: in[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Step-by-step explanation:

[tex] - \frac{3}{4} x + 2 \frac{1}{4 } = \frac{1}{2} x + 1[/tex]

[tex] - \frac{3}{4} x + \frac{9}{4} = \frac{1}{2} x + \frac{2}{2} [/tex]

[tex] \frac{ - 3x + 9}{4} = \frac{2x + 4}{4} [/tex]

[tex] - 3x + 9 = 2x + 4[/tex]

[tex] - 3x - 2x = 4 - 9[/tex]

[tex] - 5x = - 5[/tex]

[tex]x = \frac{ - 5}{ - 5} [/tex]

[tex]x = 1[/tex]

The answer is C.