Answer:
a. 1.8 kV b. 30 A c. power input = 3.6 kW, power output = 3.6 kW
Explanation:
a. Since turns ratio N₁/N₂ = V₁/V₂ where N₁ = number of turns of primary coil = 80 turns, N₂ = number of turns of secondary coil = 1200 turns, V₁ = voltage in primary circuit = 120 V and V₂ = voltage in secondary circuit = unknown
So, V₂ = N₂V₁/N₁
= 1200 × 120 V/80
= 1800 V
= 1.8 kV
b. Also, N₁/N₂ = I₂/I₁ where I₁ = current in primary circuit = unknown and I₂ = current in secondary circuit = 2.0 A
So, I₁ = N₂I₂/N₁
= 1200 × 2.0 A/80
= 30 A
c. The power input of the transformer P₁ = I₁V₁
= 30 A × 120 V
= 3600 W
= 3.6 kW
The power output of the transformer P₂ = I₂V₂
= 2 A × 1800 V
= 3600 W
= 3.6 kW
a) The voltage applied across the secondary circuit is 1.8 kV
b) The current in the primary circuit is 30 A
c) The power input and output of the transformer are 3.6 kW and 3.6 kW.
What is transformer?A transformer transfers electric energy from one AC circuit to one or more other circuits, either stepping up or stepping down the voltage.
a) Turns ratio N₁/N₂ = V₁/V₂ where N₁ = number of turns of primary coil = 80 turns, N₂ = number of turns of secondary coil = 1200 turns, V₁ = voltage in primary circuit = 120 V
Substitute the values and we get the voltage in secondary circuit is
V₂ = N₂V₁/N₁
V₂ = 1200 × 120 V/80
V₂ = 1800 V
V₂ = 1.8 kV
Thus, the voltage applied across the secondary circuit is 1.8 kV
b) Turn ratio also represented as N₁/N₂ = I₂/I₁ where I₂ is the current in secondary circuit = 2.0 A
Put the values, we have current in primary circuit is
I₁ = N₂I₂/N₁
I₁ = 1200 × 2.0 A/80
I₁ = 30 A
Thus, the current in the primary circuit is 30 A
c) The power input of the transformer P₁ = I₁V₁
P₁ = 30 A × 120 V
P₁ = 3600 W
P₁ = 3.6 kW
The power output of the transformer P₂ = I₂V₂
P₂= 2 A × 1800 V
P₂= 3600 W
P₂= 3.6 kW
The power input and output of the transformer are 3.6 kW and 3.6 kW.
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Please help! 100 points!
What are some ways that the nitrogen cycle overlaps with or influences the oxygen and carbon cycles?
Are any of these interactions between the cycles positive?
Are any negative?
What about when the nitrogen cycle is thrown off balance by the Haber-Bosch process and others like it?
How can that influence the oxygen and carbon cycles?
Are there other cycles involved that have not been mentioned in this question?
What does this discussion suggest about the nature of the Earth as one large system?
Answer:
1.Nitrification happens when soil organisms change over ammonium into nitrate. Much of the cover between the carbon cycle and the nitrogen cycle happens within the soil, in forms conducted by soil organisms. Organisms break down supplements, construct modern compounds for their possess development, and inevitably pass on.
The second question im not sure sorry- the positive and negative one ;(
3. Many human activities have a significant impact on the nitrogen cycle. Burning fossil fuels, application of nitrogen-based fertilizers, and other activities can dramatically increase the amount of biologically available nitrogen in an ecosystem. As nitrogen makes up 78% of the atmosphere, there is no shortage of it – it just isn't in a form plants and animals can use.
4. Carbon makes its way through living things as carbon-based compounds, like vitality particles, fats and proteins, in the long run cycling its way back into the environment. Nitrogen is basically found within the air as well and enters the environments as supplements for plants. Water, nitrogen and carbon cycles. Carbon moves from the air and back by means of creatures and plants. Nitrogen moves from the environment and back by means of living beings. Water moves on, over, or underneath the surface of the Soil.
5. Carbon cycle, Nitrogen cycle, Nutrient cycle, Oxygen cycle, Phosphorus cycle, Sulfur cycle, Rock cycle, Water cycle.
6. Wind, water, and ice disintegrate and shape the arrive. Volcanic movement and seismic tremors change the scene in a sensational and frequently savage way. And on a much longer timescale, the development of earth's plates gradually reconfigures seas and landmasses. Each one of these forms plays a part within the Cold and Antarctica.
People affect the physical environment in numerous ways: overpopulation, contamination, burning fossil powers, and deforestation. Changes like these have activated climate alter, soil disintegration, destitute discuss quality, and undrinkable water. Earth's surface is the as it were territory accessible to the human race. Understanding the forms by which that environment has been made and persistently changed is critical to decide the causes of natural degradation.
A water distiller which is used to purify water. The distiller boils water and then condenses most of the water vapour back to water. (a) The water distiller is filled with 5.0 kg of water at 20 °C The specific heat capacity of water = 4 200 J/Kg °C Calculate the energy needed to raise the temperature of the water to 100 °C ___________________________________________________________________
Answer:
Energy needed 1680kJExplanation:
The quantity of heat required to raise the temperature of water to 100 degrees is expressed as
[tex]Q= mc(T2-T1)[/tex]
Given data
mass of water = 5kg
initial temperature T1= 20 °C
final temperature T2= 100 °C
Specific heat capacity of water= 4 200 J/Kg °C
[tex]Q= 5* 4 200(100-20)\\Q= 21000(80)\\Q= 1680000\\Q= 1680kJ[/tex]
What are some advantages
and disadvantages to using
superconductors as electric
transmission lines
Answer:
Insulators show very high resistance to electricity. Conductors like copper show some resistance. Another class of materials show no resistance at all when cooled to very low temperatures, cooler than the coolest deep freezer. Called superconductors, they were discovered in 1911.
Explanation: i looked it up
A car starts from rest and attains a velocity of 30m/s in 5 sec . calculate the total distance travel by that car and acceleration
Answer:
Acceleration (a) = 6 m/s²
Total distance travel by car(s) = 75 meter
Explanation:
Given:
Initial velocity (u) = 0
Final velocity (v) = 30 m/s
Time (t) = 5 sec
Find:
Total distance travel by car(s) = ?
Acceleration (a) = ?
Computation:
v = u +at
30 = 0 + a(5)
30 = a(5)
Acceleration (a) = 6 m/s²
Total distance travel by car(s) = ut +1/2(a)(t)²
Total distance travel by car(s) = 1/2(a)(t)²
Total distance travel by car(s) = (0.5)(6)(5)²
Total distance travel by car(s) = 75 meter
what is the wavelength of radio waves transmitted by an FM station at 90MHz where 1M=10^6, and speed of radiowave is 3*10^8m/s
Answer:
λ = 3.33 m
Explanation:
Given:
Frequency = f = 9 × 10⁷ Hz
Speed = v = 3 × 10⁸ m/s
Required:
Wavelength = λ = ?
Formula:
v = fλ
Solution:
Putting the givens in the formula
v = fλ
λ = [tex]\frac{v}{f}[/tex]
λ = [tex]\frac{3*10^8}{9*10^7}[/tex]
λ = 0.33 × 10¹
λ = 3.33 m
potential energy is frequintly converted into kenetic energey. kenetic energey
Answer:
When an object falls, its gravitational potential energy is changed to kinetic energy. ... Gravitational potential energy for a mass m at height h near the surface of the Earth is mgh more than the potential energy would be at height 0. (It's up to you where you choose height 0.)
Explanation:
Answer:
Qwertyujiknb vcdxrftyhbvcdxrft6y7uij
Explanation:
Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the machine?
Answer:
80 Percent
Explanation:
E=energy output/energy input×100
E=8000/10000×100
E=0.8×100
E=80 percent.
Mark brianliest if my answer suit your question
If the machine put, in 8000 J, and the user puts 10,000 J of work then the efficiency of the machine will be equal to 80%.
What is Work?Work is a physics term used to describe the transfer of energy that takes place when an object changes above a distance because of an external force, at least some of which is given in the vector of the dislocation. The element of the force acting all along the path multiplied by the length of the path can be used to calculate work if the force is constant.
Mathematically, this idea is expressed as W = fd, where W is the effort and f is the force multiplied by d, the distance. Work is completed whenever the force is applied at an angle with about the displacement.
As per the data provided in the question,
Total input energy = 10,000 J
Total output energy = 8,000 J
Then, the efficiency (η) of the machine will be,
η = (output energy/input energy) × 100
η = 8000/10000 × 100
η = 80%.
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An object rotates describing a horizontal circumference when subjected to a centripetal force F. What centripetal force will act on the object if the radius of the circle is doubled and the kinetic energy of the object is halved? A) F/4 B) F/2 C) F D) 4F please explain this to me : (
Answer:
Option A: F/4
Explanation:
Centripetal force, [tex]F = \frac{mv^{2} }{r}[/tex]
Where v = speed
r = radius
Since Kinetic Energy, [tex]E_{k} = 0.5 mv^{2}[/tex]
Writing centripetal force in terms of kinetic energy, [tex]F = \frac{2 E_k}{r}[/tex]
If the initial radius of the circle, r₁ =r
The doubled radius, r₂ = 2r
If the initial kinetic energy, [tex]KE_1 = E_{k}[/tex]
The halved kinetic energy, [tex]KE_2 = 0.5E_{k}[/tex]
Therefore, the new Centripetal force becomes:
[tex]F_{2} = \frac{2(0.5 E_k)}{2r} \\F_{2} = \frac{0.5 E_k}{r}\\F_{2} =\frac{1}{4} * \frac{2 E_k}{r}\\Since, F = \frac{2 E_k}{r} \\F_{2} =\frac{1}{4} * F\\F_{2} =\frac{F}{4}[/tex]
Why would you expect sodium (Na) to react strongly with chlorine?
Answer:
Na is a alkaline metal, it can very easy give an electron, and form positive ion. Cl is a very strong non-metal(halogen), and it is able to take electron, and form negative ion. Positive and negative ion can attract to each other and form ionic bond.
Which objects would sink in honey, which has a density of 1.4 g/cm³? Check all that apply.
Answer:
any object that has density more than 1.4
Explanation:
The object that has density more than 1.4 is denser than the honey
1. Calculate the total binding energy of 12
6 C.
Answer in units of MeV.
2. Calculate the average binding energy per nucleon of 24
12Mg.
Answer in units of MeV/nucleon.
3. Calculate the average binding energy per nucleon of 85
37Rb.
Answer in units of MeV/nucleon.
4. Find the binding energy per nucleon of 238
92U.
Answer in units of MeV/nucleon.
5. Calculate the total binding energy of 20
10Ne.
Answer in units of MeV.
6. Calculate the total binding energy of 40
20Ca.
Answer in units of MeV.
Answer:
1. B = 79.12 MeV
2. B = -4.39 MeV/nucleon
3. B = 2.40 MeV/nucleon
4. B = 7.48 MeV/nucleon
5. B = -18.72 MeV
6. B = 225.23 MeV
Explanation:
The binding energy can be calculated using the followng equation:
[tex] B = (Zm_{p} + Nm_{n} - M)*931 MeV/C^{2} [/tex]
Where:
Z: is the number of protons
[tex]m_{p}[/tex]: is the proton's mass = 1.00730 u
N: is the number of neutrons
[tex]m_{n}[/tex]: is the neutron's mass = 1.00869 u
M: is the mass of the nucleus
1. The total binding energy of [tex]^{12}_{6}C[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV [/tex]
2. The average binding energy per nucleon of [tex]^{24}_{12}Mg[/tex] is:
[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]
Where: A = Z + N
[tex] B = \frac{(12*1.00730 + 12*1.00869 - 24.305)}{(12 + 12)}*931.49 MeV/u = -4.39 MeV/nucleon [/tex]
3. The average binding energy per nucleon of [tex]^{85}_{37}Rb[/tex] is:
[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]
[tex] B = \frac{(37*1.00730 + 48*1.00869 - 85.468)}{85}*931.49 MeV/u = 2.40 MeV/nucleon [/tex]
4. The binding energy per nucleon of [tex]^{238}_{92}U[/tex] is:
[tex] B = \frac{(92*1.00730 + 146*1.00869 - 238.03)}{238}*931.49 MeV/u = 7.48 MeV/nucleon [/tex]
5. The total binding energy of [tex]^{20}_{10}Ne[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV [/tex]
6. The total binding energy of [tex]^{40}_{20}Ca[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV [/tex]
I hope it helps you!
The velocity and acceleration of a body are 90km/hr and 2m/s^2 respectively. find the distance travelled by it in half minute.
Answer:
1,650 meters
Explanation:
Start by converting the velocity to m/s. There are 3600 seconds in a minute and 1000 meters in a kilometer, so 90km/hr=25m/s. Half a minute is 30 seconds, so:
[tex]d=v_ot+\dfrac{1}{2}at^2 \\\\d=(25)(30)+\dfrac{1}{2}(2)(30)^2 \\\\d=750+900=1650m[/tex]
Hope this helps!
SERE
At which temperature does the motion of atoms and molecules stop?
0°C
ОС
0°K
ОК
Answer: 0 Kelvin, or 0°K.
Explanation:
The Kelvin scale is used primarily in scientific applications due to the unit's lack of negative values.
0 Kelvin is equivalent to "absolute zero", or the temperature at which molecules and atoms no longer physically move.
0 Celsius on the other hand is a system based on the freezing and boiling points of water. 0 Celsius is the freezing point and 100 Celsius is the boiling point.
Calculate the weight of an object on earth surface having 600km from surface of earth?
Your question seems to contradict itself. You said "on Earth surface" and then you said "600 km from surface of the Earth" ... both in the same sentence.
I'll assume that the object is actually 600 km from surface of the Earth, because that makes the question (and the answer) more interesting.
We know that the weight of any object is (mass) x (gravity). Those are the two numbers we need in order to calculate the object's weight. Mysteriously, you haven't told us either one. We'll call the object's mass ' M ' (clever, eh ?), and we'll calculate the value of gravity up there where the object is located.
We now that the acceleration of gravity is inversely proportional to the square of the distance between the centers of two objects. When an object is on the Earth's surface, it's 6,371 km from Earth's center, and the acceleration of gravity there is 9.8 m/s².
The object in the question is 600 km farther from Earth's center, so the acceleration of gravity there is
(9.8 m/s²) · (6371 / 6971)² = 8.2 m/s².
So the object's weight is (8.2 M) Newtons.
This is about 84% of its weight on Earth's surface.
(Notice that the astronauts aboard the International Space Station are NOT "weightless". The strength of gravity up there where they are is around 84% of what it is down on the ground. The question of why they float, and why their muscles waste away, is a topic for another Brainly question.)
The ________ of a particle for a given ‘Interval of time’ is defined as the ratio of total distance travelled to the total time taken.
uniform speed
average speed
uniform velocity
average velocity
Answer:
The average speed of a particle for a given ‘Interval of time’ is defined as the ratio of total distance travelled to the total time taken.
Explanation:
To find the average speed we take the total
distance traveled divided by the time interval.
Which force does not operate at a distance of 1 m?
A. Weak nuclear
O B. Electric
C. Gravitational
D. Magnetic
Answer:
A
Explanation:
1a. Assuming 100% efficient energy conversion, how much water stored behind a 50cm high hydroelectric dam would be required to charge a 50 ampere-minute 12 volt battery with 600j of energy stored in it
Answer:
7.22 m³ of water should be stored behind the hydroelectric dam.
Explanation:
First we find the total energy that can be stored in the battery. For that purpose we use the formula:
P = VI
where,
P = Power delivered by battery
V = Voltage of Battery = 12 volts
I = Current in Battery
Multiplying both sides by time interval (t), we get:
Pt = VIt
where,
Pt = (Power)(Time) = Total Energy Stored in Battery = E = ?
It = Current Rating of Battery = (50 A.min)(60 s/min) = 3000 A.s
Therefore,
E = (12 volt)(3000 A.s)
E = 36000 J
Now, we have to find the energy required to fully charge the battery:
Energy Required = ΔE = Total Energy Capacity(E) - Already Stored Energy
ΔE = 36000 J - 600 J
ΔE = 35400 J
Now, this energy must be equal to the potential energy of water stored behind hydroelectric dam to fully charge the battery, provided that the conversion efficiency is 100 %.
Therefore,
ΔE = mgh
where,
m = mass of water behind hydroelectric dam
g = 9.8 m/s²
h = height of dam = 50 cm = 0.5 m
Therefore,
35400 J = m(9.8 m/s²)(0.5 m)
m = (35400 J)/(4.9 m²/s²)
m = 7224.5 kg
Now, to find the volume of stored water, we use:
ρ = m/V
V = m/ρ
where,
ρ = density of water = 1000 kg/m³
V = Volume of water behind dam = ?
V = (7224.5 kg)/(1000 kg/m³)
V = 7.22 m³
state the principle of conservation of energy
Answer:
Principal of Conservation of Energy states that " Energy is neither created nor destroyed. However, It is just converted to other forms of energy"
why the shape of the earth is spherical
Answer:
The Earth is massive enough that the pull of gravity maintains its roughly spherical shape. Most of its deviation from spherical stems from the centrifugal force caused by rotation around its north-south axis. This force deforms the sphere into an oblate ellipsoid.
A 50 - N x m torque acts on a wheel with a moment of inertia 150 kg x m² . If the wheel starts from rest , how long will it take the wheel to make one revolution ?
Answer:
t = 6.17 s
Explanation:
For a 1 revolution movement, [tex]\triangle \theta = 2\pi[/tex]
Torque, [tex]\tau = 50 Nm[/tex]
Moment of Inertia, [tex]I = 150 kg m^2[/tex]
If the wheel starts from rest, [tex]w_{0} = 0 rad/s[/tex]
The angular displacement of the wheel can be given by the formula:
[tex]\triangle \theta = \omega_0 t + 0.5 \alpha t^2[/tex]................(1)
Where [tex]\alpha[/tex] is the angular acceleration
[tex]\tau = I \alpha\\\alpha = \frac{\tau}{I} \\\alpha = 50/150\\\alpha = 0.33 rad/s^2[/tex]
To get t, put all necessary parameters into equation (1)
[tex]2\pi = 0(t) + 0.5(0.33)t^2\\2\pi =0.5(0.33)t^2\\t^2 = \frac{4 \pi}{0.33} \\t^2 = 38.08\\t = 6.17 s[/tex]
If there are a boys pulling a rubber
with the same amount of force what will happen?
Answer:
The rubber will expand to its maximum and then tear in the middle.
Explanation:
Answer:
Hey!
Well if they continue to pull the rubber band, it would eventually rip apart right in the middle as the force could not be contained by the elastic fibres and had reached its maximum extension!
Explanation:
HOPE THIS HELPS!!
*
A light year is
1 Point
O 365 days
O The distance light travels in a year
O The distance from Earth to Proxima Centauri
Helppp now is my final exammmm pleaseeee
Answer:
2.The Distance Light Travels In A Year
Explanation:
A Light Year Is Nothing But The Distance That The Light Travels In Onw Year
Answer:
Shown from explanation.
Explanation:
Light year is the distance light travels in one year and you can calculate that.
Light travels 3× 10^8m in 1 second; so you calculate the number of seconds in 365days and multiply by 3× 10^8m.
Light year was a unit of measure derived by man for expressing planetary distances due to their so huge distance which goes beyond our scale of measure.
A) Is it possible for an object that, object with zero acceleration have velocity? If yes give an example if not give its proof.
Answer:
Yes, in case of uniform velocity
Explanation:
This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.
Since, acceleration is defined as the rate of change of velocity.
Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.
a = ΔV/t = 0/t
a = 0 m/s²
So, the acceleration of the body is 0 m/s², but it has a uniform velocity
Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.
In a hydroelectric power station, how much potential energy is lost by 100tonnes of water flowing down through the pipes, falling a vertical distance of 200metres? [1tonne=1000kg.]
Answer:
196000000 J
Explanation:
Potential Energy: This can be defined as the energy of a body due to its position in the gravitational field.
From the question,
P.E = mgh.................. Equation 1
Where P.E = potential Energy, m = mass of the water, h = height, g = acceleration due to gravity.
Given: m = 100 tonnes = (100×1000) = 100000 kg, h = 200 m
Constant: g = 9.8 m/s²
Substitute into equation 1
P.E = 100000(200)(9.8)
P.E = 196000000 J.
Note: When a object falls through a height he losses its potential energy.
Hence the potential energy lost = 196000000 J = 196 MJ.
Concrete and steel expand to almost the same amount when they are heated. Explain why you think this is lucky?
Answer:
While making a bridge or a building, the first thing that comes to our mind is that these are always made by the combination of concrete and steel. Concrete is cheap, but it has the property of breaking when it is twisted or under tension. Steel is expensive, If we made the whole thing with it, it will cost a lot. To provide strength under a reasonable cost, we use the combination of concrete and steel. Another postive point which they have together is that they both expand equally under heat, because they have the same coefficient of thermal expansion. It proves really useful, because if they had different coefficients of thermal expansions, one would expand more than the other, which will create tensions in the mixture and would break it easily. In the case, many cracks would start to appear in the bridge or buildings, which will eventually break them.
A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?
Answer:
The electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
Explanation:
Given
[tex]Radius,\ r = 0.03m\\Charge,\ q =7.6\µC[/tex]
Required
Find the electric flux
Electric flux is calculated using the following formula;
Ф = q/ε
Where ε is the electric constant permitivitty
ε [tex]= 8.8542 * 10^{-12}[/tex]
Substitute ε [tex]= 8.8542 * 10^{-12}[/tex] and [tex]q =7.6\µC[/tex]; The formula becomes
Ф = [tex]\frac{7.6\µC}{8.8542 * 10^{-12}}[/tex]
Ф = [tex]\frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}[/tex]
Ф = [tex]\frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}[/tex]
Ф = [tex]\frac{7.6}{8.8542} *10^{12-6}}[/tex]
Ф = [tex]0.85834970974 *10^{12-6}}[/tex]
Ф = [tex]0.85834970974 *10^{6}}[/tex]
Ф = [tex]8.5834970974 *10^{5}}[/tex]
Ф = [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
Hence, the electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]
A 1.00 kg block of ice, at -25.0°C, is warmed by 35 kJ of energy. What is the final temperature of the ice?
Answer:
-8.4°C
Explanation:
From the principle of heat capacity.
The heat sustain by an object is given as;
H = m× c× (T2-T1)
Where H is heat transferred
m is mass of substance
T2-T1 is the temperature change from starting to final temperature T2.
c- is the specific heat capacity of ice .
Note : specific heat capacity is an intrinsic capacity of a substance which is the energy substained on a unit mass of a substance on a unit temperature change.
Hence ; 35= 1× c× ( T2-(-25))
35= c× ( T2+25)
35 =2.108×( T2+25)
( T2+25)= 35/2.108= 16.60°{ approximated to 2 decimal place}
T2= 16.60-25= -8.40°C
C, specific heat capacity of ice is =2.108 kJ/kgK{you can google that}
To solve this we must be knowing each and every concept related to energy. Therefore, -8.40°C is the final temperature of the ice.
What is energy?In physics, energy is the capacity to accomplish work. It can be potential, kinetic, temperature, electrical, chemical, radioactive, or in other forms.
There is also heat and work—energy inside the process of being transferred through one body to the other. Energy is always classified according to its type once it has been transmitted. As a result, heat transported could become thermal energy, whereas labor done may emerge as mechanical energy.
H = m× c× (T2-T1)
35= 1× c× ( T2-(-25))
35= c× ( T2+25)
specific heat capacity of ice is =2.108 kJ/kgK
35 =2.108×( T2+25)
( T2+25)= 35/2.108= 16.60°
T2= 16.60-25= -8.40°C
Therefore, -8.40°C is the final temperature of the ice.
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why the weight of a body decreases with increases in distance from the earth's surface
because as the distance increases the gravitational force decreases so the weight of a body decreases
Answer:
Weight of the body decreases with increase in distance from the Earth because weight is inversely proportional to distance from the Earth which means Weight of the body decreases with increase in distance from the Earth and vice versa. Also Weight is "gravitational force exerted on the body" so as the distance from the Earth increases , the "gravitational force" decreases.
a 1000 kg rhinoceros running at its top speed of 15 m/s has a kinetic energy of a.bc X 10^ J. What are the values of a.b.c. and d?
Answer:
K.E = 1.13 × 10^5 J
When compared to;
K.E = a.bc X 10^d J
We can observe that;
a = 1
b = 1
c = 3
d = 5
Explanation:
Given;
Mass of rhinoceros m = 1000kg
Velocity v = 15m/s
The kinetic energy of the body at this speed is;
K.E = 0.5×mv^2 ........1
Substituting the values of m and v into equation 1;
K.E = 0.5×1000×15^2
K.E = 112500 J
K.E = 1.13 × 10^5 J
When compared to;
K.E = a.bc X 10^d J
We can observe that;
a = 1
b = 1
c = 3
d = 5
4. ____________ occurs when one object slides over another.
a. Sliding friction
b. Static friction
c. Rolling friction
d. Net force
Answer:
A. Sliding friction
Explanation:
Sliding friction is weaker than static friction
Answer:
Rolling Friction
Explanation:
I know this because the definition of rolling friction is : type of friction that happens when one body rolls over another
