Q3, A ball of mass 5.0 kg moving with a Velocity of 10.0 ms collides
with a 15.0 kg ball moves with a Velocity of 4 ms! If both balls
Stick together after Collision, Calculate their Common Velocity after Impact if they initially moves in The Same direction, and Opposite direction.

The good continuation is an application of the Gestalt principle.

According to the Law of Good Continuation, figures with smooth edges are more likely to be perceived as continuous than those with abrupt or sharp angles.

One rule of civil engineering is that while designing a highway, traffic should move in one direction and be as free of interruptions as feasible.

Instead of having 90-degree angles that require stops and starts, exit ramps typically incorporate curves to prevent motorists from having to halt. Applying the Gestalt concept to a good continuation

Hence the good continuation is an application of the Gestalt principle.

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Answer:

If theta is equal to 90, then both projectiles strike at the same distance from the projection point and projectiles are in air for the same time interval.

Explanation:

The true statement about the accuracy and precision of measuring tools is Tools cannot be both accurate and precise. The correct option is C.

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Accuracy compares the experimental value to the theoretical value.

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is C.

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Answer:  Solar Photovoltaic (PV) cells generate electricity by absorbing sunlight and using that light energy to create an electrical current. There are many PV cells within a single solar panel, and the current created by all of the cells together adds up to enough electricity to help power your school, home and businesses.

                              --Cited from Solar Schools

(a) The initial speed must the object be launched so that it reaches

the surface of Planet 2 with zero speed is  √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) An inequality between M₁ and M₂ that represents when (a)

can occur is { M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

(c)  if R₁ = R₂, then M₁ must be greater than M₂ is proved.

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/R²

Given, Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius R₂. The two planets are a distance of L apart, measured from surface to surface. An object is launched with some initial speed from the surface of Planet 1 directly towards Planet 2. For this problem, assume that Planets1 and 2 are stationary.

If v is the launch velocity, then initial total energy will be

T.E  = 1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L)

The final total energy will be

T.E  =0 + ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

From energy conservation principle, we get

1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L) = ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

v = √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) an inequality between M₁ and M₂  so that object reaches the surface of Planet 2 with zero speed is

[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}] =0

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

Thus, this is an inequality between M₁ and M₂.

(c) If R₁ = R₂, then

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L) / R (R+L)   ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L)  ≥ 0

M₁L - M₂L  ≥ 0

M₁ ≥ M₂

M₁ must be greater than M₂.

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Answer:

the anser is b

Explanation:

If the force applied on the object is in the direction of its motion, the speed of the object increases. If the force is applied in the direction opposite to the direction of motion, then it results in a decrease in the speed of the object.

He would measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops(option A).

The absolute zero refers to the temperature at which the gas seems to stop moving. Recall that temperature is the measure of the average kinetic energy of the molecules of a gas. We now have to consider the options and see the one that connects temperature and speed of molecules.

Hence, if Guillaume Amontons first took a stab at measuring absolute zero in 1702, he would measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops.

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Answer:

A Rechargeable Battery

Explanation:

That is roughly what happens when a secondary cell is recharged (rechargeable battery.) Electric current transforms one chemical species with a lower energy level into another with a higher energy level. When the battery is loaded, this energy can be released. Strictly speaking, no conversion occurs: chemical energy is electrical energy! The energy of electrons in any particular substance, such as metal, are due to electron interactions with the nuclei in the substance and with each other. Electrons, in particular, occupy certain energy levels in metals. Because each metal has a distinct highest occupied energy level, electrons can alter their energies by traveling from one metal to another. An electrical current is made up of this movement!

Answer:

[tex]28.0\; {\rm N}[/tex] to the right.

Explanation:

Since the sign is not moving, the net force on this sign should be [tex]0\; {\rm N}[/tex]. For that, the horizontal component ([tex]x[/tex]-component) of external forces on this sign should be [tex]0\; {\rm N}[/tex].

Sources of external forces on this sign include tension from the wires, as well as gravitational pull (weight) from the earth. The gravitational pull from the earth is entirely vertical ([tex]y[/tex]-component,) with a magnitude of [tex]0\; {\rm N}[/tex] in the horizontal direction. Thus, the only external forces on this sign in the [tex]x[/tex]-component would be from the two wires.

The question states that the [tex]x[/tex]-component of the force from the first wire is [tex]28.0\; {\rm N}[/tex] to the left. Thus, for the net force in the [tex]x[/tex]-direction to be [tex]0\; {\rm N}[/tex], the force from the other wire in the [tex]x\![/tex]-component needs to be [tex]28.0\; {\rm N}\![/tex] to the right (same magnitude but opposite direction.)

By counting the number of crests that pass a point in a specific amount of time, one may determine the frequency of a waveform. Option a is correct.

A sound pressure wave's frequency, also known as pitch, is the number of times it repeats itself every second.

The frequency of the sound is the inverse of the period. If the wavelength of a wave is short. The wave will indeed have a lower frequency. A longer wavelength denotes a lower frequency.

The frequency of a waveform is found by determining the number of crests passing a point in a given time.

Hence option a is correct.

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The acceleration will be constantly equal to 1 m/s².Option c is correct.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = 350 N

Friction force,f=350 N

F=f

Because the frictional and applied forces on the two boxes are of equal strength, both move at the same pace. As a result, the acceleration will be constantly equal to 1 m/s².

Hence option c is correct.

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That depends on where YOU are when you measure it.

If you're motionless in the laboratory, then you measure the particles flying apart at 1.6c .

If you're riding on one of the particles, you measure the other one flying away from you at less than c

The force of gravity on a 1–kilogram box located at a point from the center of Earth is 2.36 N

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.

Given, a 1 kg box located at a point 1.3 × 10⁷ m from the center of Earth. The Earth has the acceleration due to gravity, g =  9.81 m/s².

Force of gravity F = GMm/R²

where G = gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg² and R is the distance between two masses.

The Mass of Earth M= 5.98 × 10²⁴ kg

Substituting the values, we get

F =  (6.67 x 10⁻¹¹ N.m²/kg² x 1kg x  5.98 × 10²⁴ kg)/ ( 1.3 × 10⁷ m)²

F = 2.36 N

Therefore,  the force of gravity on a 1–kilogram box located at a point from the center of Earth is 2.36 N

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Answer:

1 / f = 1 / o + 1 / i = (i + o) / o * 1

f = o * i / (o + i) = 60 * 30 / (60 + 30) = 1800 / 90 = 20 cm

Both the object and image are in positive space for a mirror

Answer:

Temperatures expressed in the Kelvin scale are D.) 273° higher than temperatures in the Celsius scale.

Explanation:

This answer is 110% correct guaranteed!

⭐⭐⭐⭐⭐ +

The most electronegative atoms are located in the seventeenth group of the periodic table.

The term electronegativity refers to the ability of an atom to attract the electrons of a bond towards itself.  The more electronegative atom will have the electron pairs closer to itself.

Hence, in this case, the blue atom is more electronegative. The most electronegative atoms are located in the seventeenth group of the periodic table.

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The I3 will be 158 A.

To calculate I3 firstly, V4 has to be calculated,

[tex]V_{4} =I_{4} R_{4}[/tex]

[tex]V_{4} = V_{2} / R_{4} + R_{5} * R_{4}[/tex]

[tex]V_{4} = 12 * 135 / 135+61[/tex]

[tex]V_{4} = 8.26V[/tex]

For I3,

[tex]I_{3} = R_{1} /(R1+R3 + (R1+R3)(R2+R6) * (V2 - V1 (R1+R2+R6/R1)[/tex]

[tex]I3=(61)/((61)(50)+(61+50)(141+141)) (12 -18 (1+(141+141)/61)) = -.158 A[/tex]

Hence, the current through I3 will be 158 A.

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a. The value of H is 11.51 m

b. The total kinetic energy as she reaches the ground is 6.21 kJ.

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

Given is a skier (m=55.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. Value of h = 6.50 m and D = 11.4 m.

Time taken to reach the ground after take off is

t = √2h/g

t = √(2x6.50) /9.81

t =1.15 s

The speed at that time is

speed = distance /time

v = 11.4 /1.15

v = 9.913 m/s

a. From energy conservation principle,

v = √2g(H-h)

Plug the values, we get

9.913 = √(2 x 9.81 (H - 6.5)

Squaring both sides and solving, we have

H = 11.51 m

Thus, the value of H is 11.51 m.

b. The energy at the ground will be only potential energy

Total kinetic energy at the ground = mgH

T.K.E = 55 x 9.81 x 11.51

T.K.E =6.21 kJ

Thus, the total kinetic energy is 6.21 kJ.

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When a ball is thrown up by doing work, the velocity of the ball will be 2.6 m/s.

It states that the Work done in moving a body is equal to the change in kinetic energy of the body

Kinetic energy = 1/2 mv²

Given is a ball of mass m = 0.750 kg and the work done on ball W = 2.50 J

The ball is initially at rest. So, initial velocity is zero. Then, change in kinetic energy will be

W= ΔK.E = K.Ef - K.Ei

According to work energy theorem, work done is

W = 2.5J  = 1/2 x 0.750 x (v)² -0

v =2.6 m/s

Thus, the velocity of the ball is 2.6 m/s

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Answer:

The last one - each  vector pointing towards the center of the circle must be the same length for uniform circular motion

a. Ball P

Density is define as mass per unit volume or the quantity per unit volume, unit area, or unit length.

If [tex]m_{1}[/tex] is mass ,  [tex]V_{1}[/tex] is volume and [tex]D_{1}[/tex]  is density of ball P

[tex]m_{2}[/tex]  is mass ,  [tex]V_{2}[/tex] is volume and [tex]D_{2}[/tex] is density  of ball Q

It is given that  ,

[tex]V_{1}[/tex] = [tex]V_{2}[/tex];

But  [tex]m_{1}[/tex]= [tex]2m_{2}[/tex]

Based on above equation we have:

[tex]\frac{D_{1} }{D_{2} } = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{2m_{2} }{V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 2[/tex]

Thus, density of ball P is twice that of Q.

Therefore ,

Ball  P will have a greater density than Q

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The work done by the force to stretch the spring is determined as 12.5 J.

The work done by the force to stretch the spring is calculated as follows;

W = ¹/₂Fx

F = kx

W = ¹/₂F(F/k)

W = ¹/₂F²/k

W = ¹/₂ x (50²)/100

W = 12.5 J

Thus, the work done by the force to stretch the spring is determined as 12.5 J.

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NGC 300 is different from our solar system because of its smaller size.

NGC 300 galaxy is different from our solar system because of its size. NGC 300 is smaller than our solar system which means that it has less number of stars as compared to our solar system.

So we can conclude that NGC 300 is different from our solar system because of its smaller size.

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Answer:

c

Explanation:

Answer:

c

Explanation:

im smart

The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.

Using the formula

μ = viscosity = 0. 06 Pas

d =  diameter = 120mm = 0. 12m

V =  velocity = 1m/s and 3m/s

ρ = density = 0.9

a. Velocity = 1m/s

friction factor = 0. 52 × [tex]\frac{0. 06}{0. 12* 1* 0. 9}[/tex]

friction factor = 0. 52 × [tex]\frac{0. 06}{0. 108}[/tex]

friction factor = 0. 52 × 0. 55

friction factor [tex]= 0. 289[/tex]

b. When V = 3mls

Friction factor = 0. 52 × [tex]\frac{0. 06}{0. 12 * 3* 0. 9}[/tex]

Friction factor = 0. 52 × [tex]\frac{0. 06}{0. 324}[/tex]

Friction factor = 0. 52 × 0. 185

Friction factor [tex]= 0.096[/tex]

Loss When V = 1m/s

Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter

Head loss = 0. 289 × [tex]\frac{1}{2*6. 6743 * 10^-11}[/tex] × [tex]\frac{1^2}{0. 120}[/tex] × [tex]\frac{1}{100}[/tex]

Head loss =  1. 80 × 10^8

Head loss When V = 3m/s

Head loss = [tex]0. 096[/tex] × [tex]\frac{1}{1. 334 *10^-10}[/tex] × [tex]\frac{3^2}{0. 120}[/tex] × [tex]\frac{1}{100}[/tex]

Head loss = 5. 3× 10^8

Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss  when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.

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The unit vector along r(t) will be 3t–4t^2+2

A vector is a quantity with direction and magnitude that is especially useful for locating one location in space in relation to another. A quantity or phenomena with independent qualities for both size and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields weight are a few examples of vectors in nature.

Given the the position of particle as a function of particle of time is given by: r(t)=3tî–4t^2j+2k. Where î & j are unit vector along the x-axis and y-axis respectively.

We have to find the unit vector along r(t)

To find the unit vector along r(t) we have to put the value of (i,j,k) = (1,1,1) in r(t)

So,

r(t) = 3tî–4t^2j+2k

r(t) = 3t(1)–4t^2(1)+2(1)

r(t) = 3t–4t^2+2

Therefore the unit vector along r(t) will be 3t–4t^2+2

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The speed at which the medicine leaves the needle is  2.462 m/s

When an incompressible, ideal fluid is flowing through a tube or pipe, the total energy remains constant.

p₁ /ρg + v₁²/2g +z₁ = p₂ /ρg + v₂²/2g +z₂

Where, p/ρg = pressure energy

            v²/2g = kinetic energy

                   z = potential energy

Given is during an injection, pressure in the barrel of syringe is 1.03  atm while pressure in the needle section is 1.00 atm. Assuming the syringe lays horizontally and mass density of the liquid medicine ρ =1000 kg/m³.

The fluid is initially at rest.

Using the Bernoulli's equation, we have

v₁² -  v₂²= 2 x (p₂ -p₁) / ρ

Substituting the values, we get

0 -  v₂² = 2 x (1.00 -1.03) x 1.01 x 10⁵ /1000

v₂² = 6.06

v₂ = 2.462 m/s

Thus, the speed at which the medicine leaves the needle is 2.462 m/s

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Answer:

45° to min.

1° ----> 60 min

45° ----> ?.

45 * 60

2700 min

Bobby and Alice are pushing a stalled car in the same direction. The mass of the car is 2,000 kg. Bobby applies 400 N to the car while Alice applies 300 N. A force created by friction is 500 N in the opposite direction is the acceleration of the car is 0.1 m/sec.

An acceleration, fee at which pace adjustments with time, in phrases of each velocity and direction. A factor or an item shifting in a direct line is expanded if it hurries up or slows down.

Is summarized via way of means of the equation: Force (N) = mass (kg) × acceleration (m/s²).The mass = 2000 kg and force= 1200 N. So mass / force = 2000/1200 = 0.1 m/sec.

Thus, the acceleration of the car s 0.1 m/sec.

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