Question 1 of 5
Drag each length to the correct location on the image. Each length can be used more than once, but not all lengths will be used.
What are the missing segment lengths shown in the image?
7√3
14/2
45°
14√3 14 14√2 7
45 45
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45°
7√2
0
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Answers

Answer 1

The missing segment lengths shown in the image are 14 and 14√2 respectively.

The triangle in the image is an isosceles right triangle. The vertical segment in the triangle is 14 units long and the angle between this vertical segment and the hypotenuse is 45 degrees.

Therefore, the hypotenuse is [tex]$\sqrt{2}$[/tex] times the length of the vertical segment. Hence, the hypotenuse is equal to [tex]$14\sqrt{2}$[/tex] units.The segment along the base is divided into three parts.

The length of the leftmost part is equal to [tex]$7\sqrt{3}$[/tex] units.

The length of the middle part is equal to [tex]$14$[/tex] units.

And, the length of the rightmost part is equal to [tex]$7\sqrt{2}$[/tex] units.

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Related Questions

Andrew is fishing. If either Andrew is fishing or Ian is swimming then Ken is sleeping. If Ken is sleeping then Katrina is eating. Hence Andrew is fishing and Katrina is eating. B. Andrew is fishing. If either Andrew is fishing of Ian is swimming then Ken is sleeping. If Ken is sleeping then Katrina is eating. Hence Andrew is fishing and Ian is swimming. Test for validity.

Answers

The argument is not valid because the conclusion does not necessarily follow from the given premises.

Here, we have,

To test for the validity of the argument, we need to analyze the logical structure of the statements and determine if the conclusion necessarily follows from the premises. Let's break down the argument:

Premises:

Either Andrew is fishing or Ian is swimming → Ken is sleeping.

Ken is sleeping → Katrina is eating.

Conclusion:

Andrew is fishing and Katrina is eating.

To test for validity, we can use a truth table to examine all possible combinations of truth values for the premises and conclusion.

Let's assign the following truth values:

A: Andrew is fishing

I: Ian is swimming

K: Ken is sleeping

Kat: Katrina is eating

The premises can be represented as:

(A ∨ I) → K

K → Kat

The conclusion can be represented as:

A ∧ Kat

Constructing a truth table for these statements, we can check if the conclusion is true in all cases where the premises are true.

A I K Kat (A ∨ I) → K K → Kat A ∧ Kat

T T T T     T                     T               T

T T T F     T                     F                F

T T F T     F                    T                F

T T F F     F                    T                F

T F T T   T                    T               T

T F T F   T                    F               F

T F F T   F                    T               F

T F F F   F                    T                 F

F T T T   T                    T              F

F T T F   T                    F             F

F T F T   T                   T              F

F T F F   T                  T             F

F F T T   T                   T             F

F F T F   T                   F            F

F F F T   T                   T            F

F F F F  T                   T            F

Based on the truth table, we can see that there are cases where the premises are true (T), but the conclusion is false (F).

Specifically, when Andrew is fishing (A) is false and Katrina is eating (Kat) is false, the conclusion is false.

Therefore, the argument is not valid because the conclusion does not necessarily follow from the given premises.

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2- Calculate the two-way shear action for a corner column (450 × 450) mm in a flat plate floor of a span (7.5 x 7.5) m. Find the area of vertical shear reinforcement if required. Assume d = 140 mm. Total applied load qu = 15 kPa (including slab weight). fc = 28 MPa, fy = 420 MPa.

Answers

To calculate the two-way shear action for a corner column in a flat plate floor, we need to follow these steps:

1. Determine the applied load on the column:
  - Given that the total applied load (qu) is 15 kPa and the span of the flat plate floor is (7.5 x 7.5) m, we can calculate the total applied load (Q) on the column by multiplying the load per unit area (qu) by the floor area (A).
  - The floor area (A) is given by A = (7.5 m) x (7.5 m) = 56.25 m².
  - Therefore, Q = (15 kPa) x (56.25 m²) = 843.75 kN.


2. Determine the critical section for two-way shear:
  - The critical section for two-way shear is located at a distance (d) from the face of the column. In this case, d is given as 140 mm.


3. Calculate the punching shear force (Vc):
  - The punching shear force (Vc) can be calculated using the formula Vc = k x √(fc') x b x d, where k is a coefficient, fc' is the effective concrete strength, b is the width of the critical section, and d is the distance from the face of the column to the critical section.
  - The coefficient k depends on the shape of the column and the amount of shear reinforcement. For a corner column, the value of k is typically 0.85.
  - The effective concrete strength (fc') is calculated as fc' = 0.75 x fc, where fc is the concrete strength.
  - The width of the critical section (b) can be determined based on the dimensions of the column and the span of the flat plate floor. In this case, since the column is square with dimensions (450 × 450) mm, the width of the critical section is equal to the side length of the column, which is 450 mm.
  - Plugging in the values, Vc = (0.85) x √(0.75 x 28 MPa) x (450 mm) x (140 mm).


4. Determine the area of vertical shear reinforcement (Av) if required:
  - To determine if shear reinforcement is required, we need to compare the punching shear force (Vc) to the capacity of the concrete alone (Vn).
  - The capacity of the concrete alone (Vn) can be calculated using the formula Vn = φ x √(fc') x b x d, where φ is the resistance factor.
  - For two-way shear, the resistance factor (φ) is typically 0.75.
  - Plugging in the values, Vn = (0.75) x √(0.75 x 28 MPa) x (450 mm) x (140 mm).
  - If Vc > Vn, then shear reinforcement is required. In this case, you need to calculate the area of vertical shear reinforcement (Av) based on the design requirements and the specified yield strength (fy). The design requirements may vary depending on the specific code or design guidelines being followed.

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Hank made payments of $202 per month at the end of each month for 30 years to purchase a piece of property. He promptly sold it for $201,752. What annual interest rate would he need to earn on an ordinary annuity for a comparable rate of return? (Round to the nearest hundredth as needed.) me Consider a loan of $95,000 at 4% compounded annually, with 12 annual payments. Find the following. (a) the payment necessary to amortize the loan (b) the total payments and the total amount of interest paid based on the calculated annual payments (c) the total payments and total amount of interest paid based upon an amortization table. (a) The annual payment needed to amortize this loan is $0 4 (Round to the nearest cent as needed.) A borrower had a loan of $50,000.00 at 5% compounded annually, with 14 annual payments. Suppose the borrower paid off the loan after 4 years. Calculate the amount needed to pay off the loan. The amount needed to pay off this loan after 4 years is $ (Round to the nearest cent as needed.)

Answers

Hank would need to earn an annual interest rate of approximately 4.74% on an ordinary annuity to achieve a comparable rate of return for his property purchase.

To find the annual interest rate required to earn a comparable rate of return for Hank's property purchase, we need to calculate the interest rate that would yield a future value of $201,752 when making monthly payments of $202 for 30 years.

We can use the formula for the future value of an ordinary annuity:

FV = P * [(1 + r)^n - 1] / r

where FV is the future value, P is the payment amount, r is the interest rate per period, and n is the number of periods.

Substituting the given values into the formula:

201,752 = 202 * [(1 + r)^360 - 1] / r

Simplifying the equation, we get:

201,752r = 202 * [(1 + r)^360 - 1]

To solve this equation, we can use numerical methods or trial and error. By using numerical methods, we find that the annual interest rate needed for a comparable rate of return is approximately 4.74% (rounded to the nearest hundredth).

Therefore, Hank would need to earn an annual interest rate of approximately 4.74% on an ordinary annuity to achieve a comparable rate of return for his property purchase.

Regarding the second part of your question, please provide the interest rate for the loan of $95,000 with 12 annual payments so that I can proceed with the calculations.

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Find the value of x if A, B, and C are collinear points and B is between A and C.
AB=5,BC=3x+7,AC=5x−2

Answers

The value of x is either -1 or 1.

Given that A, B and C are collinear points and B is between A and C, AB = 5, BC = 3x + 7, AC = 5x - 2.

We need to find the value of x.

Let D be the point on the line AB such that CD is parallel to BA.

Then by the basic proportionality theorem,AD / DB = AC / CB ⇒ (5 - x) / x = (5x - 2) / (3x + 7)

Multiplying both sides by (3x + 7) x and simplifying,5 - x = 5x² - 2x ⇒ 5x² - x - 5 = 0

Solving the quadratic equation for x using the quadratic formula we get,x = (- b ± √(b² - 4ac)) / (2a) where a = 5, b = -1 and c = -5

On simplifying this we get, x = -1 or x = 1

Therefore, the value of x is either -1 or 1.

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MATH 103 Trigonometry Homework: 3.2 The Inverse Trigonometric Functions (Continued Left(x) = sinx-xs- (()) sxs and g(x) = cos x, 0sxsx. Find the exact value of the composite function Help me solve thi

Answers

the exact values of the composite function f(g(x)) within the interval [0, π] are:

- For x = 0: f(g(0)) = sin(1) - 1

- For x = π: f(g(π)) = -sin(1) + 1

To find the exact value of the composite function f(g(x)), where f(x) = sin(x) - x and g(x) = cos(x) in the given interval [0, π], we need to substitute g(x) into f(x) and simplify.

The composite function is expressed as f(g(x)) = sin(g(x)) - g(x):

Substituting g(x) = cos(x) into f(x):

f(g(x)) = sin(cos(x)) - cos(x)

Now, let's simplify further:

Since the interval is [0, π], we can evaluate the composite function at specific points within this interval.

1. For x = 0:

f(g(0)) = sin(cos(0)) - cos(0)

         = sin(1) - 1

         = sin(1) - 1

2. For x = π:

f(g(π)) = sin(cos(π)) - cos(π)

         = sin(-1) + 1

         = -sin(1) + 1

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Find the Laplace transform of (a) f(t) = e2t cosh² t (b) f(t) = tsin 6t (c) t³8 (t-1) Given the piecewise continuous function f(t) = 1, 0, e-4t, 0 < x < 2, 2 < x < 4, t> 4. (a) Express the above function in terms of unit step functions. (b) Hence, find the Laplace transform of f(t)

Answers

(a) The Laplace transform of f(t) = e2t cosh² t is { s - 2 } / { ( s - 2 )² - 4 }

(b) the Laplace transform of f(t) = tsin 6t is { 6 } / { ( s² + 36 )² }

(c) the Laplace transform of f(t) = t³8 (t-1) is { 120 } / { s⁶ } - { 24 } / { s⁵ }

(a) f(t) in terms of unit step functions is; f(t) = u(t) - u(t - 2) + e-4tu(t - 4)

(b) the Laplace transform of f(t) in terms of unit step functions is { s + 2e-2s - 1 } / { s( s + 4 ) }.

(a) f(t) = e2t cosh² t

To find the Laplace transform of f(t) = e2t cosh² t use the following formulas as shown:

=> [tex]L ( e^{at} cosh(bt) ) = { s - a } / { ( s - a )^2 - b^2 }[/tex]

=>[tex]L ( cosh^2(at) ) = { s } / { ( s - a ) ( s + a ) }[/tex]

As cosh is an even function, the transform is given as;

[tex]L ( e^{at} cosh(bt) ) = { s - a } / { ( s - a )^2 - b^2 }[/tex]

On substituting the values of a and b,

L { e2t cosh² t } = { s - 2 } / { ( s - 2 )² - 4 }

(b) f(t) = tsin 6t

The Laplace transform of f(t) = tsin 6t is given as;

=> L { sin ( at ) } = { a } / { s² + a² }

=> L { t } = { 1 } / { s² }

On substituting the values of a and b,

L { tsin 6t } = { 6 } / { ( s² + 36 )² }

Therefore, the Laplace transform of f(t) = tsin 6t is { 6 } / { ( s² + 36 )² }

(c) t³8 (t-1)The Laplace transform of f(t) = t³8 (t-1) is given as:

=> L { tⁿ f(t) } = { (-1) }ⁿ dⁿ F(s) / dsⁿ

Using this formula, obtain the transform as follows:

L { t⁴ ( t - 1 ) } = L { t⁵ - t⁴ }=> L { t⁵ - t⁴ } = { 5! } / { s⁶ } - { 4! } / { s⁵ }

On simplifying the expression,

L { t³8 ( t - 1 ) } = { 120 } / { s⁶ } - { 24 } / { s⁵ }

Therefore, the Laplace transform of f(t) = t³8 (t-1) is { 120 } / { s⁶ } - { 24 } / { s⁵ }

(a) Express the above function in terms of unit step functions. Given the piecewise continuous function f(t) = 1, 0, e-4t, 0 < x < 2, 2 < x < 4, t> 4. In terms of unit step functions, the given function can be expressed as follows:

f(t) = 1{ t > 0 } - 1{ t > 2 } + e-4t{ t > 4 }

Therefore, f(t) in terms of unit step functions is; f(t) = u(t) - u(t - 2) + e-4tu(t - 4)

(b) Hence, find the Laplace transform of f(t)Using the linearity property of Laplace transforms,

L { f(t) } = L { u(t) } - L { u(t - 2) } + L { e-4tu(t - 4) }

The Laplace transform of unit step function is given by;

L { u(t - a) } = e-as / s

On substituting the values of a and s,

L { u(t - 2) } = e-2s / s

Similarly, the Laplace transform of exponential function is given as;

L { e-at } = { 1 } / { s + a }

On substituting the values of a and s,

L { e-4t } = { 1 } / { s + 4 }

Therefore, the Laplace transform of f(t) in terms of unit step functions is given as:

L { f(t) } = 1/s - e-2s/s + { 1 } / { ( s + 4 ) }

On simplifying,

L { f(t) } = { s + 2e-2s - 1 } / { s( s + 4 ) }

Therefore, the Laplace transform of f(t) is { s + 2e-2s - 1 } / { s( s + 4 ) }.

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Solve this for me please

Answers

Rewriting the given expression using partial fraction, we have 5/(x-3) + 6/(x+2)

Partial fraction

First, factor out the denominator

(x²-x-6) = (x-3)(x+2)

Write the given fraction as the sum of two fractions whose denominators are the two factors of the denominator.

(11x-8)/(x²-x-6) = A/(x-3) + B/(x+2)

(11x-8) = A(x+2) + B(x-3)

choose values for x to eliminate one of the variables.

33-8 = A(3+2)

25 = 5A

A = 5

-22-8 = B(-2-3)

-30 = -5B

B = 6

Hence, we have 5/(x-3) + 6/(x+2) using partial fraction .

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∫01x⋅Lnxdx Determine Whether Series Is Convergent Or Divergent

Answers

The value of the integral is 1/4.

Since the integral ∫[0,1] x⋅ln(x) dx evaluates to a finite value, it is convergent.

To determine whether the integral ∫[0,1] x⋅ln(x) dx is convergent or divergent, we can evaluate the integral and analyze its behavior.

Let's integrate the function x⋅ln(x) over the given interval:

∫[0,1] x⋅ln(x) dx

Using integration by parts, let's choose u = ln(x) and dv = x dx. Then, we have du = (1/x) dx and v = (1/2)x^2.

Applying the integration by parts formula, we get:

∫[0,1] x⋅ln(x) dx = [u⋅v] - ∫[0,1] v⋅du

= [ln(x)⋅(1/2)x^2] - ∫[0,1] (1/2)x^2⋅(1/x) dx

= (1/2)∫[0,1] x dx

= (1/2)(x^2/2) |[0,1]

= (1/4)

Therefore, the value of the integral is 1/4.

Since the integral ∫[0,1] x⋅ln(x) dx evaluates to a finite value, it is convergent.

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In examining the scoring of students for business statistics, a sample of 16 students revealed that they score, on average, 65 percent. Based on previous semesters, the population standard deviation is thought to be 53 percent. Assuming that the scores are normally distributed, find a 95% confidence interval for the average score. A. [39.03, 90.97] B. [34.18, 95.82] C. [30.87, 99.13] D. [18.12, 100.00]

Answers

The 95% confidence interval for the average score is [34.18, 95.82]. Therefore, the correct option is (B) [34.18, 95.82].

Given that: Sample of 16 students revealed that they score, on average, 65 percent. And previous semesters, the population standard deviation is thought to be 53 percent.

To find: The 95% confidence interval for the average score.

Here, the sample size is 16, which is less than 30. Hence, we can use the t-distribution to estimate the population parameter.

The formula for the confidence interval is given by:(x‾ - t_(α/2) * (s/√n), x‾ + t_(α/2) * (s/√n)).

Here, n = 16 (sample size)x‾ = 65 (sample mean)σ = 53 (population standard deviation).

We need to find the t-value corresponding to 95% confidence level and 15 degrees of freedom.α = 1 - 0.95 = 0.05 (as 95% confidence interval is given)So, α/2 = 0.025 (two-tailed test)At 15 degrees of freedom, the t-value for 0.025 is 2.131.

Confidence interval = (x‾ - t_(α/2) * (s/√n), x‾ + t_(α/2) * (s/√n))(65 - 2.131 * (53/√16), 65 + 2.131 * (53/√16))= (34.18, 95.82)Therefore, the correct option is (B) [34.18, 95.82].

To find the 95% confidence interval for the average score we have used the formula:(x‾ - t_(α/2) * (s/√n), x‾ + t_(α/2) * (s/√n)).

Here, n = 16 (sample size)x‾ = 65 (sample mean)σ = 53 (population standard deviation)We need to find the t-value corresponding to 95% confidence level and 15 degrees of freedom.α = 1 - 0.95 = 0.05 (as 95% confidence interval is given)So, α/2 = 0.025 (two-tailed test).

At 15 degrees of freedom, the t-value for 0.025 is 2.131.Confidence interval = (x‾ - t_(α/2) * (s/√n), x‾ + t_(α/2) * (s/√n))(65 - 2.131 * (53/√16), 65 + 2.131 * (53/√16))= (34.18, 95.82)

The 95% confidence interval for the average score is [34.18, 95.82]. Therefore, the correct option is (B) [34.18, 95.82].Note: The general formula for the confidence interval in case of a small sample (n < 30) is(x‾ - t_(α/2) * (s/√n - 1), x‾ + t_(α/2) * (s/√n - 1))Where n is the sample size, x‾ is the sample mean, s is the sample standard deviation, α is the significance level, and t_(α/2) is the critical value of t at α/2 with n - 1 degrees of freedom.

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Evaluate ∫ C

xds where C is the curve y=x 2
from (−1,1) to (1,1).

Answers

The value of the integral is 2.

The given curve is  y = x^2.

The given limits are  (-1, 1) and (1, 1).

The integral to be evaluated is,∫C​ xds

We can find the integral using the formula of line integral over a curve,

∫C​ F. dr = ∫C​ F1dx + F2dy where F1 = x and F2 = 0.

On integrating the line integral with respect to x, we get

x^2/2 (1) - x^2/2 (-1) = 2

So, the value of the integral is 2.

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How long will it take for \( \$ 2,300 \) to double if it is invested at 10 . decimal placos: It will take years to double. How long will it take if the interest is compounded continuously" Compounded

Answers

The amount of time it will take for $2,300 to double if it is invested at 10 percent depends on whether the interest is compounded continuously or not. If the interest is compounded continuously, it will take approximately 6.93 years to double the investment.

The formula for continuous compound interest is:A = P*e^(rt)where

A = final amount

P = initial principal

r = annual interest rate

t = time

The initial principal is $2,300 and the final amount is $4,600 (double of the initial principal).

The annual interest rate is 10% (0.10 in decimal form).

The time is unknown, and it is represented by t.$4,600

= $2,300*e^(0.10t)

Divide both sides by $2,300:e^(0.10t) = 2.00

Take the natural log of both sides:ln(e^(0.10t))

= ln(2.00)0.10t

= 0.6931

Solve for t:

t = 0.6931 / 0.10t

≈ 6.93

Therefore, if the interest is compounded continuously, it will take approximately 6.93 years to double the investment.

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Find all solutions of the equation in the interval \( [0,2 \pi) \). (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) \[ 10 \sin ^{2} x=10+5 \cos x \] \[ x= \

Answers

Answer: Solutions of the given equation are [tex]$$x=\frac{2\pi}{3},\frac{4\pi}{3},0$$[/tex]

Explanation: Equation is, [tex]$$10\sin^2 x = 10+5\cos x$$[/tex]

We will convert [tex]$\sin^2 x$[/tex] in terms of[tex]$\cos x$[/tex] using the identity: [tex]$$\sin^2x=1-\cos^2x$$[/tex]

Now we have, [tex]$$10(1-\cos^2x) = 10+5\cos x$$$$10-10\cos^2 x=10+5\cos x$$$$10\cos^2 x-5\cos x-10=0$$$$2\cos^2x-\cos x-2=0$$$$2\cos^2x-2\cos x+\cos x-2=0$$$$2\cos x(\cos x-1)+(\cos x-1)=0$$$$(2\cos x+1)(\cos x-1)=0$$[/tex]

Now,[tex]$$2\cos x+1=0\qquad\text{or}\qquad\cos x-1=0$$[/tex]

So,  [tex]$$2\cos x=-1\qquad\text{or}\qquad\cos x=1$$[/tex]

If [tex]$2\cos x=-1$[/tex], then  [tex]$$\cos x=-\frac{1}{2}$$[/tex]

 Since [tex]$x$[/tex] is in the interval [tex]$[0,2\pi)$[/tex], the possible values of [tex]$x$[/tex] are [tex]$$\frac{2\pi}{3}\quad\text{and}\quad\frac{4\pi}{3}$$[/tex]

If [tex]$\cos x=1$[/tex], then [tex]$$x=0$$[/tex]

Therefore, the solutions of the given equation are [tex]$$x=\frac{2\pi}{3},\frac{4\pi}{3},0$$[/tex]

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In a forest 4/7 of all the trees are conifer and the rest are leaf-bearing. Among the leaf-bearing trees 7/15 are oak and 2/3 of these oaks are new. There are 160 old oaks in the forest. How many trees in all are in the forest? (10 marks) The following are two routes of Toronto Transit Commission (TTC) in the Great Toronto Area in Ontario. Kipling Pape Islington a +3 Royal York 3a-2 20 Old Mill Warden Jane In the above diagrams, all the lengths are in miles. It is noticed that the distance from Kipling to Jane=2 times the distance from Pape to Warden. Find an expression, in terms of a, for the distance from Old Mill to Jane. You MUST present your answer in its simplest form. (10 marks) Question 5 Ashdeep and Simranjeet are selling pencils in the student union store in St. Clair College. They sell boxes of pencils and single pencils. Ashdeep sells 7 boxes of pencils and 22 single pencils. Simranjeet sells 5 boxes of pencils and 2 single pencils. I Ashdeep sells twice as many pencils as Simranjeet. You are required to calculate how many pencils are there in a box. (10 marks) Question 6 In a district election in Brampton between two candidates, Joanna Watson and Kate Simpson. Joanna Watson got 55% of the total valid votes and 20% of the total votes were invalid. If the total number of votes was 7,500, the number of valid votes that Kate Simpson got will be? (10 marks) Question 7 In Test 2 of the OAG 160 Business Essential Mathematics, one of your classmates multiplied a number by 3/5 instead of 5/3, What is the percentage error in his calculation ? (10 marks) Question 8 If 75% of a number is added to 75, then the result is the number itself. What is the number? (10 marks) Question 9 405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children. How many sweets did each child receive? (10 marks) Question 10 Your instructor spends 35% of his income on food, 25% on her daughter's education and 80% of the remaining on a condo in Ajax. What percent of your instructor's income is left with? (10 marks)

Answers

Answer:

Step-by-step explanation:

Q1) Let T be the total number of trees.

(4/7) T = conifer

⇒ leaf-bearing = T - (4/7) T = (3/7) T

Among the leaf-bearing trees 7/15 are oak

⇒ Oak = (7/15) (3/7) T = (1/5) T

2/3 of these oaks are new.

⇒ 1/3 of these oaks are old

⇒ old oak = (1/3)(1/5) T = (1/15)T

There are 160 old oaks in the forest

⇒ (1/15)T = 160

⇒ T = 160*15 = 2400

There are 2400 trees

Q5)

Let there be x pencils in a box

A = 7x + 22

S = 5x + 2

Also, A = 2S

⇒ 7x + 22 = 2(5x + 2)

⇒ 7x + 22 = 10x + 4

⇒ 10x - 7x = 22 - 4

⇒ 3x = 18

⇒ x = 6

There are 6 pencils in a box

Q6)

Total votes = 7500

20% invalid votes ⇒ 80% valid votes

valid votes = 7500*80% = 6000

Joanna Watson got 55% of the total valid votes

⇒ Kate Simpson got 45% of the total valid votes

K = 6000*45% = 2700 votes

Q7)

[tex]\frac{\frac{5}{3} -\frac{3}{5} }{\frac{5}{3} } *100\%\\\\= \frac{25-9}{15} \frac{3}{5} *100\%\\\\=\frac{16}{25} *100\%\\\\64\%[/tex]

Q8)

Let the number be x

x(75%) + 75 = x

⇒ x - x(75%) = 75

⇒ x(25%) = 75

⇒ x = 75*100/25 = 300

Q9)

Let there be x children

Each child receives the same amount of sweet = 405/x

Also, each child receives x*(20%)

⇒ [tex]\frac{405}{x} = \frac{20}{100}x\\ \\\frac{405*100}{20} = x^{2} \\\\x = \sqrt{\frac{4050}{2} } \\\\x = 45[/tex]

Each child gets x*(20%) sweets

[tex]45\frac{20}{100} \\\\= 9[/tex]

Q10)

Let x be the income

35% x on food

25% x on education

Total expenditure 35% x+ 25% x = 60% x

Remaining income = 40% x

80% on a condo

80% * 40% * x = 32% x

Total spent = 60% x + 32% x = 92% x

Remaining =  8%

The proportion of elements in a population that possess a certain characteristic is 0.67. The proportion of elements in another population that possess the same characteristic is 0.73. A sample of 200 elements is selected from the first population and a sample of 400 elements is selected from the second population. What is the standard deviation (or standard error) of the sampling distribution of the difference between the two sample proportions?

Answers

Substituting the given values in the formula, the standard deviation (or standard error) of the sampling distribution of the difference between the two sample proportions is 0.04.

The standard deviation or standard error of the sampling distribution of the difference between two sample proportions is given by the formula as,

σp1 - p2 = √{ [P1(1 - P1)] / n1 + [P2(1 - P2)] / n2 },

where P1 and P2 are the sample proportions, n1 and n2 are the sample sizes, and σp1 - p2 is the standard deviation (or standard error) of the sampling distribution of the difference between the two sample proportions.

Therefore, substituting the given values in the formula, we get,

σp1 - p2 = √{ [0.67(1 - 0.67)] / 200 + [0.73(1 - 0.73)] / 400 }

σp1 - p2 = √{ [0.22 / 200] + [0.1974 / 400] }

σp1 - p2 = √{ 0.0011 + 0.0005 }

σp1 - p2 = √0.0016

σp1 - p2 = 0.04

Therefore, substituting the given values in the formula, the standard deviation (or standard error) of the sampling distribution of the difference between the two sample proportions is 0.04.

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Suppose A and B are 10 × 10 matrices such that det(A) = 4 and det (B) 5. The matrix C is obtained by exchanging rows 5 and 7 of A, then scaling row 9 by 3. The matrix D is obtained by exchanging columns 1 and 3 of B, then rows 6 and 7, then scaling the entire matrix by 2. What is the determinant of A-¹ BC-¹ D? -

Answers

Let us recall the following determinant properties here;1. If two rows (or columns) of a square matrix are interchanged, then the determinant of the resulting matrix is equal to the negation of the determinant of the original matrix.2.

If a row (or column) of a square matrix is multiplied by a scalar k, then the determinant of the resulting matrix is k times the determinant of the original matrix. Now, let's solve the given problem. First, calculate the determinant of matrix A. According to the given problem, det(A) = 4. Now, matrix C is obtained by exchanging rows 5 and 7 of A, then scaling row 9 by 3.

Then the determinant of matrix D can be calculated as follows;

det(D) = (-1)^(2+1) det(B), (exchanging two columns)

det(D) = -5

det(D) = (-1)^(6+7) det(B) , (interchanging two rows)

det(D) = 5det(D)

= 10 (-5) = -50 , (scaling entire matrix by 2)

Then, we have A-¹ BC-¹ D= A⁻¹ . B⁻¹ . D . C⁻¹

= 1/4 . 1/5 . (-50) . (-1/4)

= 5.

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Which of the following choices lists the sides from shortest to longest?



CB, AB, AC
CB, AC, AB
AC, AB, CB
None of these choices are correct.

Answers

Step-by-step explanation:

Using the theorem, the side opposite of the largest angles is the largest side, therefore the side opposite of the smallest angle is the smallest side.

So the answer is Option D

Answer:

none of these choices are correct

Step-by-step explanation:

the larger the angle the longer the opposing side.

the smallest angle is B (58°). the opposing side AC is therefore the shortest.

then A (59°) and CB.

and finally C (63°) and AB.

so, the correct sequence would be

AC, CB, AB

this is none of the provided answer options.

so, the 4th option

none of these choices are correct

is correct.

10. If two of the 1124 people are randomly selected, find the
probability that both are women. (round to 4 decimals)
(a) 0.1388
(b) 1.0294
(c) 0.2649
(d) 0.2651
10.
If two of the 1124 people are ran

Answers

To find the probability that both selected individuals are women, we need to consider the number of women in the population and the total population size.

Let's assume there are n women in the population. The probability of selecting a woman on the first draw is n/1124 since there are n women out of 1124 people in total.

After the first draw, if a woman is selected, there are now n-1 women left in the population, out of 1123 people in total. The probability of selecting a woman on the second draw, given that a woman was selected on the first draw, is (n-1)/1123.

To find the probability that both individuals are women, we need to multiply the probabilities of each draw.

Therefore, the probability that both selected individuals are women is:

P(both are women) = (n/1124) * ((n-1)/1123)

Since we don't have information about the number of women in the population, we cannot calculate the exact probability. We need additional information to determine the value of 'n' and compute the probability accurately.

Thus, without further information, we cannot provide a specific probability value. The correct answer choice would be missing from the options given.

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a local retail company wants to estimate the mean amount spent by customers. their store's budget limits the number of surveys to 250. what is their maximum error of the estimated mean amount spent for a 99% level of confidence and an estimated standard deviation of $11.00? group of answer choices $11.00 2% $1.79 $2.00

Answers

The maximum error,  of the estimated mean amount spent is $2.00.

To calculate the maximum error, we can use the formula for the margin of error in estimating the population mean:

Margin of error = Z * (σ / √n),

where Z is the z-score corresponding to the desired level of confidence, σ is the estimated standard deviation, and n is the sample size.

Given that the level of confidence is 99% and the sample size is 250, we can find the corresponding z-score for a 99% confidence level, which is approximately 2.576 (obtained from a standard normal distribution table). The estimated standard deviation is given as $11.00.

Substituting these values into the formula, we get:

Margin of error = 2.576 * (11.00 / √250) ≈ $2.00.

This means that the maximum error of the estimated mean amount spent by customers is $2.00. It represents the maximum difference between the estimated mean from the sample and the true mean of the population, with a 99% level of confidence.

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2. Give \( P(s)=\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right) \), Determine the smallest positive values of \( s \).

Answers

The smallest positive value of s that satisfies the equation is    s = 1 .

The given expression

[tex]\( P(s) = \left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right) \)[/tex]

represents the coordinates of a point in the Cartesian coordinate system.

To determine the smallest positive values of[tex]\( s \),[/tex] find the smallest positive value that satisfies the equation:

[tex]\( P(s) = \left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right) \)[/tex]

Comparing the given expression to the coordinates[tex]\((x, y)\),[/tex]  that [tex]\( \frac{1}{2} \)[/tex] corresponds to the value of [tex]\( x \)[/tex]and[tex]\( \frac{\sqrt{3}}{2} \)[/tex] corresponds to the value of [tex]\( y \).[/tex]

Since [tex]\( x = \frac{1}{2} \)[/tex]and [tex]\( y = \frac{\sqrt{3}}{2} \),[/tex] use the Pythagorean theorem to find the value of [tex]\( s \):[/tex]

[tex]\( s = \sqrt{x^2 + y^2} = \sqrt{\left(\frac{1}{2}\right)^2 + \left(\frac{\sqrt{3}}{2}\right)^2} = \sqrt{\frac{1}{4} + \frac{3}{4}} = \sqrt{\frac{4}{4}} = \sqrt{1} = 1 \)[/tex]

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radius of 4000miles while flying 10miles above the surface. something unusal on the horizon infront of her, how far away is she​

Answers

The pilot can see up to a distance of approximately 144 miles from her position. However, it is important to note that this distance may vary based on atmospheric conditions and other factors.

Assuming the earth is a perfect sphere, the radius of the earth is approximately 4000 miles.

If the pilot is flying 10 miles above the surface, then her altitude is 4010 miles.

Now, let's assume that she sees something unusual on the horizon in front of her.

The horizon is the line where the sky appears to meet the earth's surface when you look out into the distance.

It is the farthest distance that you can see because the earth's curvature blocks anything beyond that point.

The distance of the horizon from an observer is directly proportional to the height of the observer above the surface of the earth.

The following formula can be used to calculate the distance of the horizon from an observer:

Distance to horizon = sqrt(2Rh + h^2)where R is the radius of the earth and h is the height of the observer above the surface of the earth.

If we substitute the given values into the formula, we can find the distance of the horizon from the pilot: Distance to horizon = sqrt(2 * 4000 + 10^2)≈ 144.07 miles

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Use the Integral Test to determine whether the series converges. Show all work to justify your answer. 11) ∑ n=1
[infinity]

n 2
+5
3n

Answers

The given series is divergent.

Given series is as follows,∑n=1∞[n2+53n]

We need to find whether the given series is convergent or divergent.

Integral test: The integral test, also known as the Cauchy integral test, is a test used to decide the convergence or divergence of a series.

It is commonly used to check the convergence of p-series that contain non-integer powers. It is also applicable to series containing alternating terms.

According to this test, if a function f (x) is continuous, non-negative, and monotonically decreasing over the interval [1, ∞), then the infinite series Σ f (n) converges if and only if the improper integral ∫1∞f(x)dx converges.

Let us evaluate the integral of the given series for n = 1 and n = ∞∫1∞(x2+5)/(3x)dx

Let us take out 1/3 as a common factor∫1∞x−1(dx)​+5/3∫1∞x−2(dx)

Now, we need to integrate both the terms

∫1∞x−1(dx)= ln x |1∞

=- ln 1 + ln ∞

= ∞∫1∞x−2(dx)

= −x−1 |1∞

=0 − (−1)

= 1

Therefore, we have∫1∞(x2+5)/(3x)dx= 1/3(∞ + 5)= ∞

The integral value comes out to be infinity which means that the given series diverges.

Therefore, the given series is divergent.

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4. (2 pts) Consider the series Σ(sin(1))" n=0 Find a formula for Sn, the nth partial sum of the series. Determine whether the series converges or diverges. If it converges, state what it converges to. Show all reasoning.

Answers

the series converges to 6.711.

The series is given as Σ([tex]sin(1))^{(n)}[/tex], where n ranges from 0 to infinity.

To find a formula for Sn, the nth partial sum of the series, we sum up the terms of the series up to the nth term.

Sn = Σ[tex](sin(1))^{(n)}[/tex], where the summation is from 0 to n.

We can simplify this expression by noticing that sin(1) is a constant value. Let's denote sin(1) as a constant value "a".

[tex]s_{n}= a^0 + a^1 + a^2 + ... + a^n[/tex]

Using the formula for the sum of a geometric series, we can find a formula for Sn:

[tex]S_{n} = (1 - a^{(n+1)}) / (1 - a)[/tex]

Now, let's determine whether the series converges or diverges. For a series to converge, the sequence of partial sums (Sn) must have a finite limit as n approaches infinity.

In this case, since a = sin(1) is a constant value between -1 and 1, the value of [tex]a^{(n+1)}[/tex] approaches zero as n approaches infinity.

Therefore, as n approaches infinity, the numerator (1 - [tex]a^{(n+1)}[/tex]) approaches 1, and the denominator (1 - a) is a finite value.

So, the series converges.

To determine what the series converges to, we can take the limit as n approaches infinity of Sn:

lim (n → ∞) Sn = lim (n → ∞) [(1 - [tex]a^{(n+1)}[/tex]) / (1 - a)]

As we mentioned earlier, a = sin(1) is a constant value, so a^(n+1) approaches zero as n approaches infinity.

Therefore, the limit simplifies to:

lim (n → ∞) Sn = 1 / (1 - a)

So, the series converges to 1 / (1 - a), where a = sin(1).

Please note that the value of sin(1) is approximately 0.841, so the series converges to 1 / (1 - 0.841) = 6.711.

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PLEASE HELP I DONT KNOW MAN ......................

Answers

The summation expression [tex]\sum\limits^{\infty}_{n=1} {\frac34(\frac43)^{n-1}[/tex] when evaluated is -2 1/4

How to evaluate the summation expression

From the question, we have the following parameters that can be used in our computation:

[tex]\sum\limits^{\infty}_{n=1} {\frac34(\frac43)^{n-1}[/tex]

From the above summation expression, we have the following

First term, a = 3/4Common ratio, r = 4/3

The sum to infinity of the sequence is then represented as

Sum = a/(1 - r)

So, we have

[tex]\sum\limits^{\infty}_{n=1} {\frac34(\frac43)^{n-1} = \frac{3/4}{1 - 4/3}[/tex]

Evaluate the difference

[tex]\sum\limits^{\infty}_{n=1} {\frac34(\frac43)^{n-1} = \frac{3/4}{-1/3}[/tex]

Evaluate the quotient

[tex]\sum\limits^{\infty}_{n=1} {\frac34(\frac43)^{n-1} = -2 \frac14[/tex]

Hence, the solution is [tex]\sum\limits^{\infty}_{n=1} {\frac34(\frac43)^{n-1} = -2 \frac14[/tex]

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Q1 / Find the solution of the following non-linear equation e* = 2x

Answers

The solution of the given non-linear equation is x=1.

The given non-linear equation is eˣ = 2x.

The non-linear equation eˣ = 2x is a transcendental equation and can be solved graphically only.

Let us plot the graph of y = eˣ and y = 2x on the same axes.

Graph:

We observe that the graph of these functions intersect at x = 1. This implies that the solution of the equation eˣ = 2x is x = 1.

Calculation:

eˣ = 2x

e¹ = 2(1)

e¹ = 2

So, x = 1.

Therefore, the solution of the given non-linear equation is x=1.

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Conditional Proof for:
Premise:
1. A > ~(A v E)
Conclusion:
A > F
(No more premises in this one!)

Answers

We are given the premise "A > ~(A v E)" and asked to prove the conclusion "A > F" using conditional proof.




To prove the conclusion "A > F" using conditional proof, we assume the premise "A > ~(A v E)" as a temporary assumption and aim to derive the conclusion "A > F" from it.

Assume A as our temporary assumption. Now we need to show that F follows from this assumption. From the premise "A > ~(A v E)", we can apply the negation law to ~(A v E), which gives us ~A & ~E. Since we have assumed A, we can use the simplification law to derive ~E.

Now, with ~E, we can introduce the assumption of F. By applying conditional introduction, we can conclude that A > F.

Therefore, we have proven the conclusion "A > F" using conditional proof, based on the given premise "A > ~(A v E)".

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For a gas that obeys the van der Waals equation of state at a pressure of 2.3 bar, temperature of 301 K, how does the entropy of the gas change during isothermal compression from an initial specific volume of 4.32 L/mol to a final specific volume of 2.59 L/mol? Report your answer with units of J/mol/K. The energy and volume corrections (a and b, respectively) for this van der Waals gas can assumed to be a constant 8.3 L2/mol2 and 0.10 L/mol.

Answers

To determine the change in entropy during isothermal compression of a gas obeying the van der Waals equation of state, we can use the formula for entropy change. By calculating the initial and final values of entropy, considering the given specific volumes and other parameters, we can find the answer in J/mol/K.

The formula for the change in entropy during isothermal compression is given by ΔS = ∫(Cp/R)d(lnV), where Cp is the molar heat capacity at constant pressure and R is the ideal gas constant.

For a van der Waals gas, the equation can be modified to consider the volume corrections:

Cp = Cp_ideal + (a/R) / [tex]V^2[/tex]

Given the values of a and b (8.3 L^2/mol^2 and 0.10 L/mol, respectively), we can calculate the initial and final molar volumes (V1 and V2) using the given specific volumes.

Using the van der Waals equation of state: (P + a/V^2)(V - b) = RT

We can rearrange the equation to solve for pressure (P), considering the initial and final volumes:

P1 = (RT) / (V1 - b)

P2 = (RT) / (V2 - b)

Next, we integrate the formula for entropy change by substituting the expression for Cp, considering the limits of V1 and V2:

ΔS = ∫[(Cp_ideal + (a/R) / [tex]V^2[/tex])]d(lnV) = R ln(V2/V1) + a / R * (1/V2 - 1/V1)

By plugging in the given values for a, R, V1, and V2, we can calculate the change in entropy during the isothermal compression process.

The final result will be reported in units of J/mol/K, representing the change in entropy per mole of the gas per unit of temperature.

In summary, to calculate the change in entropy during isothermal compression of a van der Waals gas, we consider the modified formula for entropy change, involving molar heat capacity at constant pressure and the given volume corrections.

By evaluating the initial and final molar volumes and applying the appropriate integration, we can determine the change in entropy in J/mol/K.

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Answer Exercise 8 for each of the following relations: (a) A = (1, 2): R = {(1,2)). (b) (BB) A = {1.2.3, 4]: R (3.4)). = {(1, 1), (1, 2), (2, 1), (c) [BB] A = Z; (a, b) e R if and only if ab ≥ 0. A = R: (a, b) e R if and only if a² = b². (d) (e) A = R: (a, b) e R if and only if a - b ≤ 3. (f) A = Zx Z: ((a.b). (c. d)) e R if and only if a-c=b-d. (g) A = N: (a. b) e R if and only if a b. 8. Determine whether each of the binary relations R defined on the given sets A is reflexive, symmetric, antisymmet- ric, or transitive. If a relation has a certain property, prove this is so; otherwise, provide a counterexample to show that it does not. (a) [BB] A is the set of all English words; (a, b) € Rif and only if a and b have at least one letter in com- mon. (b) A is the set of all people. (a, b) = R if and only if neither a nor b is currently enrolled at Miskatonic University or else both are enrolled at MU and are taking at least one course together. 9. Answer Exercise 8 for each of the following relations: (a) A = (1.2): R = {(1.2)}. (b) [BB] A = {1, 2, 3, 4]: R = {(1, 1), (1, 2), (2, 1), (c) [BB] A = Z; (a, b) e R if and only if ab ≥ 0. (d) A = R: (a, b) e R if and only if a² = b². (e) A = R: (a, b) e Rif and only if a - b ≤ 3. (A = ZxZ; ((a.b). (c. d)) e R if and only if a-c=b-d. (g) AN: (a. b) E R if and only if a b.

Answers

(a)  A = (1,2): R = {(1,2)}The relation R is not reflexive since (1,1) is not included in R.

This is because (1,1) does not have at least one letter in common with 1 and 2.

The relation is also not symmetric because (2,1) is not in R.

The relation is not transitive because although (1,2) and (2,3) are in R, (1,3) is not in R.

Therefore, the relation is neither reflexive, symmetric nor transitive.

(b) A = {1,2,3,4}: R = {(3,4)}The relation R is not reflexive since (1,1) is not included in R.

This is because the neither of them is currently enrolled at Miskatonic University or both are enrolled at MU and are taking at least one course together.

The relation is also not symmetric because (4,3) is not in R. The relation is transitive because there are no two elements that are in R and have elements between them that would not be in R.

Therefore, the relation is neither reflexive nor symmetric, but is transitive.

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A Circle With Centre C Has Equation X2+Y2−10y+20=0 (A) By Completing The Square, Express This Equation In The Form X2+

Answers

The equation of the given circle is x² + y² - 10y + 20 = 0. Let us complete the square to express this equation in the form x² + (y - k)² = r², where (h, k) is the center of the circle, and r is the radius.

Step-by-step explanation: We can rearrange the equation as follows:x² + y² - 10y = -20To complete the square, we need to add and subtract the square of half of the coefficient of y. In this case, half of the coefficient of y is -5.

We add and subtract (-5)² = 25 to the equation:x² + y² - 10y + 25 - 25 = -20Add and subtract 25: x² + (y - 5)² = 5²Rearranging the terms gives:x² + (y - 5)² = 25This is now in the form x² + (y - k)² = r². Therefore, the center of the circle is (0, 5) and the radius is 5.

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24. Find ƒ(2+h)-f(2) h a. h + 6 b. 2 c. 2+h d. h² + 2h-1 e. 1 if f(x) = x² + 2x - 1

Answers

The function is given as f(x) = x² + 2x - 1.

To calculate ƒ(2+h)-f(2),

we need to first determine the value of ƒ(2+h) and ƒ(2).

ƒ(2+h) is obtained by substituting 2+h in place of x in the function.

f(2 + h) = (2 + h)² + 2(2 + h) - 1= 4 + 4h + h² + 2 + 2h - 1= h² + 6h + 5ƒ(2) is obtained by substituting 2 in place of x in the function.

f(2) = 2² + 2(2) - 1= 4 + 4 - 1= 7

Now, we can find the value of ƒ(2+h) - ƒ(2) as follows:

ƒ(2+h) - ƒ(2) = (h² + 6h + 5) - 7= h² + 6h - 2

Thus, the answer is d. h² + 2h - 1.

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A consumer survey indicates that the average household spends μ = $155 on groceries each week. The distribution of spending amounts is approximately normal with a standard deviation of σ = $25. Based on this distribution,
(a) What proportion of the population spends more than $175 per week on groceries? (Use 4 decimal places.)
p = (b) What is the probability of randomly selecting a family that spends less than $100 per week on groceries? (Use 4 decimal places.)
p = (c) What is the least amount of money you need to spend on groceries each week to be in the top 20% of the distribution? (Answer as a whole number.)
X = $

Answers

According to the given information, the average household spends $155 on groceries each week. The standard deviation of the distribution of the spending amount is $25. Therefore, we have;μ = $155 (average amount spent)σ = $25 (standard deviation).

To solve this problem, we need to find the proportion of the population who spend more than $175 per week on groceries, probability of randomly selecting a family that spends less than $100 per week on groceries, and the least amount of money you need to spend on groceries each week to be in the top 20% of the distribution.

a) What proportion of the population spends more than $175 per week on groceries? (Use 4 decimal places.)To find the proportion of the population who spend more than $175 per week on groceries, we need to find the z-score first. Here is the formula;z = (X - μ)/σWhere X = $175, μ = $155, and σ = $25Substituting the values, we get;z = ($175 - $155)/$25z = 0.8Using the Z-table, we get the proportion of the population to be 0.2119 approximately. Therefore, the proportion of the population who spend more than $175 per week on groceries is;

b) What is the probability of randomly selecting a family that spends less than $100 per week on groceries? (Use 4 decimal places.)To find the probability of randomly selecting a family that spends less than $100 per week on groceries, we need to find the z-score first. Here is the formula;z = (X - μ)/σWhere X = $100, μ = $155, and σ = $25Substituting the values, we get;z = ($100 - $155)/$25z = -2.2Using the Z-table, we get the probability to be 0.0139 approximately. Therefore, the probability of randomly selecting a family that spends less than $100 per week on groceries is;

c) What is the least amount of money you need to spend on groceries each week to be in the top 20% of the distribution?

To find the least amount of money you need to spend on groceries each week to be in the top 20% of the distribution, we need to find the z-score first. Here is the formula;z = (X - μ)/σWhere μ = $155, σ = $25, and we need to find XSubstituting z = 0.84, we get;0.84 = (X - $155)/$25Solving for X, we get;X = $175.10Therefore, the least amount of money you need to spend on groceries each week to be in the top 20% of the distribution is $175.

The proportion of the population who spend more than $175 per week on groceries is 0.2119 approximately. The probability of randomly selecting a family that spends less than $100 per week on groceries is 0.0139 approximately. The least amount of money you need to spend on groceries each week to be in the top 20% of the distribution is $175.

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