Question 1
Describe the motion of an object that is being affected by the four (4)
components of forces on a solid surface, in water and in air.
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Dark and light interference patterns on a screen after light waves have gone through a slit is NOT an example of diffraction

The process by which wave energy disperses perpendicular to the predominant direction of wave propagation is known as wave diffraction. Wave diffraction is particularly interested in abrupt changes in boundary conditions, such as those at breakwater roundheads, where diffraction transfers wave energy into the shadow zone.

Waves spread out when they go through an aperture or around objects, which is known as diffraction. It happens when the aperture's or obstacle's size is of the same order of magnitude as the wave's wavelength.

When waves go from one medium to another, they may refract, changing their direction. A shift in speed and wavelength always accompany refraction. Diffraction is the wave's bending.

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Answer:

Chun's spring exercise would be an anaerobic process which is the correct answer would be an option (A).

The rate-limiting phases in anaerobic processes are the hydrolysis conversion rate and the rate at which methanogenesis uses soluble substrates. The overall amount of solids converted is affected by the hydrolysis of colloidal and solid particles, although neither the process operation nor stability is affected.

Anaerobic means "without oxygen," so this sort of exercise causes the body to break down glucose without the use of oxygen.

At the end of his 100-meter sprint, Chun's muscles are burning.

So Chun's spring workout would involve anaerobic activity.

Therefore, Chun's spring exercise would be an anaerobic process.

Hence, the correct answer would be an option (A).

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Answer:

Option A

Explanation:

The mass of calcium in given density and volume is 0.5133g.

ρ = m / V

where

ρ is density,

m is mass,

V is volume,

Given,

ρ = 1.54g/ml

V = 3 ml

m = ?

Putting values,

1.54 g/ml = m / 3ml

m = 0.5133g

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).

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The average speed of Maria and Kuba in km/h is 120 km/h.

The average speed of Maria and Pierre in km/h is 8 km/h.

The average speed of Maria and Kuba in km/h is calculated as follows;

v = distance / time

distance = 30 km

time = 15 minutes = 15/60 = 0.25 hour

v = 30 km / 0.25 hr

v = 120 km/h

The average speed of Maria and Pierre in km/h is calculated as follows;

v = distance / time

distance = 2000 m = 2 km

time = 900 seconds = 900  / 3600  = 0.25 hour

v = 2 km / 0.25 hr

v = 8 km/h

Thus, the average speed of Maria and Kuba in km/h is 120 km/h.

The average speed of Maria and Pierre in km/h is 8 km/h.

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Flute, Clarinet, Saxophone, Piccolo, Tenor Sax oboe

Piccolo

Flute

Clarinet

Saxophone (all registers)

Oboe

English Horn

Bassoon

Answer:

firstly

kinetic and potential are two types of mechanical energy

The free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

Free body diagram refers to the formation of a system showing all the possible forces that are being exerted on the body isolating it from the surrounding.

System refers to the object of inspection i.e. the thing that is being noted down a system can be anything from an object to multiple objects and even surrounding whereas surrounding is everything else that is not a part of the system.

We have been already given all the required inputs that will help us to create a free body diagram including:

Friction force on the body being = 12 Newton

Weight of the body = 15 Newton

Normal acting on the body = 9 Newton

To create the free body diagram we simply isolate or from the surrounding and consider it to be a system then help of the vectors we will create the system consisting of the body and all the possible forces that acting on it.

We now draw the vectors for friction force weight of the body and normal acting on the body to get our required free body diagram.

Therefore, the free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

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The speed of the camera hits the ground it depend on height and g.

An object in free fall is one that is under the influence of gravity and is accelerating towards the earth's surface. Freefall formulae may be used to characterize this motion, allowing us to solve for the components of the object's motion at different time frames. This time range can be when the item is released, when it reaches the Earth's surface, or anyplace in between.

energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.

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a. The electric field component Ex = -A V/m

b. The electric field component Ey = 2By V/m

c. The electric field component Ez = -2Bz V/m

Electric potential is the work done in moving a unit charge from one point to the other.

Electric field is the force per unit charge acting on a charged particle or at a point.

Given that the electric potential in a certain region is given by V(x ,y ,z) = Ax - B(y² - z²) where A and B are constants.

We know that electric field E(x,y,z) = -gradV(x,y,z)

This implies that the electric field components are

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dx = d[Ax - B(y² - z²)]/dx

= Adx/dx - dB(y² - z²)]/dx

= A - 0

= A

Ex = -dV(x,y,z)/dx

= -A

So, the electric field component Ex = -A V/m

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dy = d[Ax - B(y² - z²)]/dy

= Adx/dy - dB(y²/dy - Bdz²)]/dy

= 0 - 2By - 0

= -2By

Ey = -dV(x,y,z)/dy

= -(-2By)

= 2By

So, the electric field component Ey = 2By V/m

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dz = d[Ax - B(y² - z²)]/dz

= Adx/dz - dB(y²/dz + Bdz²)]/dz

= 0 - 0 + 2Bz

= 2By

Ez = -dV(x,y,z)/dz

= -2Bz

So, the electric field component Ez = -2Bz V/m

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Answer:

It states that the magnitude of force is directly proportional to the product of charges at points and inversely proportional to the square of their separation distance

Explanation:

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Answer:

It states that the magnitude of force is directly proportional to the product of charges at points and inversely proportional to the square of their separation distance

Explanation:

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The value of function at x = 0 is -15 while at x = 3 it is 27.

A certain kind of relationship called a function binds inputs to essentially one output.

A function can be regarded as a computer, which is helpful.

The machine will only accept specified inputs, described as the function's domain, and will potentially produce one output for each input.

A 2-column table with 5 rows.

  x                  f(x)

 -3                  33

 -2                  17

  0                 -15

  2                  -7

  3                  27

At x = 0 value of function is -15

At x = 3 value of function is 27

Hence "The value of function at x = 0 is -15 while at x = 3 it is 27".

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Answer:

60m/s

Explanation:

Given acceleration,  and time of acceleration, the problem is as simple as placing your givens into the proper kinematics equation:

[tex]v_{f} =v_{o} +a t[/tex]  

plug in your numbers and:

[tex]v_{f} =(15)+(4.5)(10)[/tex]

[tex]v_{f} =60 m/s[/tex]

The object is moving at a constant velocity between time 4 s to 6 s. The correct answer is option A

This is the graph of velocity plotted against time. The slope of the graph is acceleration and the area under the graph is total distance travelled by the body.

Acceleration means increase in speed which is the positive slope of the graph between t = 0 s and t = 4 s

Between t = 4 s and t = 6 s the velocity is constant and acceleration = 0 because the slope of the graph is zero.

Deceleration means decrease in speed. That is, the body is slowing down. This happened between t = 6 s and t = 9 s

Therefore, the object is moving at a constant velocity between time 4 s to 6 s

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If a centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet, then the radius of its orbit would be  1.3×10⁸ meters.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem If a centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet, then we have to find the radius of its orbit,

The centripetal force acting on the satellite = m×v² / r

                                                               185  =1050× 4800² / r

                                                                     r =1.3×10⁸ meters

Thus, the radius of the orbit would be 1.3×10⁸ meters.

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If a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .

In this question Equation of Motion under gravity can be used :

v ² - u ² = 2 g h ............. Eq. 1

Here ,

u = 13 . 2 m / s

v = 0 m / s

g = - 9.8 m / s ² ( -ve as motion is against the gravity )

Now , we can use the values of u , v and g in Eq 1 .

v ² - u ² = 2 g h

0² - ( 13.2 ) ² = 2 x ( - 9.8 ) x h

0 - 174.24 = - 19.6 x h

- 174.24 = - 19.6 x h

h = 8.89 m

Hence , if a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .

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The density of the given details is ρ = 2.5 g/ml.

To find density

Using formula,

ρ = m / V

Given,

m = 55g

V = 22ml

ρ = ?

Putting values,

ρ = 55 g / 22.0 mL

ρ = 2.5 g/ml

The density of an area refers to the quantity of things—which may include people, animals, plants, or objects—there are in it. Divide the number of objects by the area's measurement to determine density. A country's population density is calculated by dividing its total population by its area, expressed in square kilometers or miles.

There are two types of density: absolute density and relative density. The ratio of a material's density to the density of a reference material is known as its relative density, also referred to as specific gravity.

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The forces responsible for the states of aggregation of matter are the intermolecular forces.

Intermolecular forces are the interactions that occur between molecules given their nature, this depends on the characteristics of the molecules that are going to join. The types of unions are classified according to the polarity of the molecules and the types of bonds that occur can be covalent or ionic.

Some bonds are stronger than others, this also determines the characteristics and temperatures to which they have to be exposed to change their states of aggregation.

Therefore, we can confirm that the forces responsible for the states of aggregation of matter are the intermolecular forces.

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The acceleration is computed at 16.625ms⁻²;

The Magnitude of Net Force = 814.625 N; and

The Magnitude of upward force exerted by tail fin = 1,294.825 N. See the explanation below.

Mass of the salmon fish = 49 kg

Length of the Salmon Fish = 1.5 m

g = 9.8 ms⁻²

[A] salmon's acceleration during the time interval N:

Downward Force on the fish is equal to the Force due to gravity and is given as:

F₂ = mg

= 49 * 9.8

= 480.2 N

The direction of movement of the fish is upward and the acceleration is constant. We are given two different velocities of fish at two different instances.

When the head breaks out of the water surface first:

Initial velocity = v₁ = 3 m/s

When two third of its body length is out = d = 1 m

Final Velocity = v₂ = 6.5 m/s

Using the third equation of motion:

2*a*d = v₂² - v₁²

a = (6.5² - 3²)/2*1

a = 16.625 ms⁻²

[B] magnitude of force F during this interval N = ?

We are assuming that F is the net force consisting of both the upward and the downward force.

According to Newton's 2nd law of motion, Force is given as:

F = ma

F = 49 kg * 16.625

F = 814.625 N

Magnitude of upward Force = Fₓ

Force Fₓ exerted by the tail fin of the fish is given by

F = Fₓ - F₂

=>   Fₓ = F + F₂

Fₓ = 814.625 + 480.2

Fₓ = 1294.825 N

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Answer: B 2m

Explanation:

The distance of tiger's leap from the base of rock is 5.58 m

It is a question of two dimensional motion

The time of motion in two dimensional motion is given by:

t= [tex]\sqrt{2y/g}[/tex]

where y is the height and g is  the acceleration due to gravity

y is given to be 7.5m and let us assume g to be 9.8 m/s^2

t = [tex]\sqrt{2 * 7.5/9.8}[/tex]

 = 1.24s

Using time and speed,

We know that distance is the product of speed and time,

Distance= speed x time

speed is given to be 4.5 m/s

distance from the base of rock = 4.5 x 1.24

                                                    = 5.58m

Hence the distance of tiger's leap from the base of rock is 5.58 m

Disclaimer:

The acceleration due to gravity is assumed to be 9.8 m/s^2

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The potential energy of a body with given mass and height is, P.E. = 8,820 J.

P.E. = mgh

where,

m is the mass in kilograms,

g is the acceleration due to gravity

h is the height in meters

Given data,

mass = 30 kg

height = 30m

acceleration due to gravity = 9.8 m / s²

P.E. = ?

Using formula,

P.E. = mgh

Putting values,

P.E. = 30 x 9.8 x 30

P.E. = 8,820 J

Potential energy is a form of energy that is stored but is dependent on the relative positions of different system components. Stretching or compressing a spring increases its potential energy. A steel ball has more potential energy when it is raised above the surface of the earth than when it is brought to Earth.

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(a) The acceleration of the 1,400-kg boat is 0.30 m/s².

(b) The boat move 60 m in 20.0 s

(c) The velocity at the end of that time will be 6 m /s

It is given that mass of the boat = 1400 kg , forward push on the boat by the propeller = 1,725 N and resistive force of water = 1300 N

(a) Let the acceleration of the boat be "a" .

The net force on the boat will be

F(net) = F(push) - F(R)

         = 1725 - 1300

         = 425 N

Using Newton's second law of motion , we get

F(net) = ma

       a = F(net) / m

          = 425 / 1400

          =  0.30 m/s²

(b) Let the distance moved by the boat be "d" .

It is given that it starts from rest which means that u = 0

Now using the kinematic equation  s = ut + 1/2at² .   ...(1)

Putting a = 0.30  , t = 20 and u = 0  in equation (1) , we get

     s = 0 (20) + 1/2 (0.30)(20)²

        = 0 + 1/2 (0.30 × 400)

        =  120 /2

        = 60 m

(c) Let the final velocity of the boat be "v" .

Using the kinematic equation v = u + at     ..(2)

Putting a = 0.30  , t = 20 and u = 0  in equation (2) , we get

   v = 0 + (0.30)(20)

      = 6 m /s

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The final velocity of a ball that accelerates uniformly at -2.00m/s² and moved at 0.20 m/s for 7.00 s is 14.2m/s.

The final velocity of a moving body can be calculated using the following formula:

a = v - u/t

Where;

According to this question, a ball accelerates uniformly at −2.00 m/s². If the ball was initially moving at 0.20 m/s and the ball travels for 7.00 s, the final velocity is as follows:

-2 = (v - 0.2)/7

-14 = v - 0.2

v = 14.2m/s

Therefore, final velocity of a ball that accelerates uniformly at -2.00m/s² and moved at 0.20 m/s for 7.00 s is 14.2m/s.

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Explanation:

 If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Answer:

The force of the book pulling up on Earth

Explanation:

I did the study island

If the ball is thrown straight up into the air with an initial velocity of 20m/s, it will be in the air for 4.08 s

a = v / t

a = Acceleration

v = Velocity

t = Time

v = 20 m / s

a = 9.81 m / s²

t = 20 / 9.81

t = 2.04 s

This is the time taken to reach the farthest height the ball will raise. It takes the equal amount of time to reach the point from where it was thrown from.

T = 2t

T = Total time taken

T = 2 * 2.04

T = 4.08 s

Therefore, the ball will be in the air for 4.08 s

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Answer:

Question 1;

[tex]{ \bf{boyle s \: law}}[/tex]

Question 2;

[tex]{ \tt{a = \frac{1}{22} }} \\ \\ { \tt{a = 0.05}}[/tex]

Question 3;

Answer:

The most common causes of a generator producing no power are the loss of residual magnetism in the alternator and a failed AVR or another excitation component. If the voltage is around 50-70V on each phase, then it is likely the AVR needs replacement.