Question 2 (4 points)
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A 14,000kg freight train, coasting at 8.1m/s, strikes another car, and the two move
forward together at 3.6m/s.
What is the mass of the second car?
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The length of the segment that will represent the 400 million years is 8.8 cm.

The given parameters:

The length of the segment that will represent the 400 million years is calculated as follows;

4.54 billion years ------------- 1 m

400 million years ------------- ?

[tex]\frac{1 \ m}{4.54 \times 10^9 \ years} \times 400 \times 10^6 \ years = 0.088 \ m[/tex]

The length of the segment in centimeters (cm) is calculated as follows;

[tex]= 0.088 \ m \times 100 \ cm\\\\= 8.8 \ cm[/tex]

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Answer:

333.5 MJ

Explanation:

ΔV = m·g·Δh

     = 8500 · 9.81 · (15000-11000)

     = 8500 · 9.81 · 4000

     = 333 540 000

     ≈ 333.5 ·10⁶J = 333.5 MJ

The change in potential energy is 333.5 MJ

Potential energy is defined as the energy possessed by an object because of its position relative to other objects, tension within itself, its electric charge, or other factors. Any object that is raised above its rest position has energy stored in it, so it is called potential energy because it has the potential to do work when released.

It can be expressed as:

P.E.= mgh

where, m is the mass of an object measured in grams 'g'

g is the acceleration due to gravity which is [tex]9.8 m/s^2[/tex]

h is the height measured in meter 'm'

Here,

the given information is

m= 8500kg

Δh= [tex]h_2 - h_1[/tex] = 15000-11000 = 4,000m

So, P.E. = 850 x 9.8 x 4000 = 333 540 000=  333.5 ·10⁶J = 333.5 MJ

Thus, the change in potential energy is 333.5 MJ

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The Rayleigh criterion allows finding the result for the diameter of the telescope that allows solving the separation of the star and the planet is:

The Rayleigh criterion is used to find the separation of two points, it is based on the fact that the diffraction maximuum pattern of the first object coincides with the first minimum of the second object.

By entering in the diffraction ratio for slits you will find.

           sin θ  = [tex]\frac{\lambda}{a}[/tex]  

In general in diffraction experiments the angles are very small,

           [tex]tan \theta = \frac{y}{x} = \frac{sin \theta}{cos \theta} \\sin \theta = \frac{y}{x}[/tex]

For the case of circular apertures, when solving in polar coordinates, a constant appears.

        [tex]\frac{y}{x} = 1.22 \frac{\lambda}{D}[/tex]

       [tex]D = 1.22 \frac{\lambda \ x}{y}[/tex]

Where λ is the wavelength of light and D is the diameter of the aperture.

They indicate that the separation between the star and the planet is 1 AU and the distance from the system to the Earth is 3 parce.

Let's reduce the parce to astronomical units

       x = 3 pc (  [tex]\frac{206264 AU}{1 pc}[/tex] )

       x = 6.18 10⁵ AU

Let's calculate

          D = [tex]D = 1.22 \ \frac{550 \ 10^{-9 } \ 6.18 \ 10^5 }{1}[/tex]  

          D = 0.415  m

In conclusion, using the Rayleigh criterion we can find the result for the diameter of the telescope that allows solving the separation of the star and the planet is:

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The total distance covered is 24 Km and Peter was not moving between the points marked 10 mins and 30 mins on the graph. His displacement according to the graph is zero.

The distance time graph shows the distance covered plotted on the vertical axis against the time taken plotted on the horizontal axis. Using this graph, the total distance covered can easily be obtained.

The total distance covered is 12 km + 12 km since equal distance was covered to and fro. Hence the total distance covered is 24 km. Perter was not moving between the points marked 10 mins and 30 mins on the graph.

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The efficiency of the process is 42%

From the question given above, the following data were obtained:

Useful energy = 250 watt

Wasteful energy = 600 watt

The efficiency of the process can be obtained as illustrated below:

[tex]efficiency \: = \frac{useful \: energy}{wasteful \: energy} \times 100 \\ \\ efficiency \: = \frac{250}{600} \times 100 \\ [/tex]

Therefore, the efficiency of the process is 42%

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Answer:

Its actually 29%

Explanation:

Took the Test

Answer:

First aid refers to the emergency or immediate care you should provide when a person is injured or ill until full medical treatment is available.

Explanation:

Answer:

The answer to your question is the number decreases by 4.

Explanation:

I hope this helps and have a great day!

Answer

An Achievement test is an assessment of developed knowledge or skill. ... Achievement tests are developed to measure skills and knowledge learned in a given grade level, usually through planned instruction, such as training or classroom instruction. Achievement tests are often contrasted with aptitude tests.

Explanation:

The direct proportions rule allows to find the result for the energy produced by a solar cell is:

        E = 1,728 J

The efficiency of a solar cell is the percentage of incident energy that transforms into electricity.

The direct  proportions rule or three rule stable that if two quantities are proportional the product remains constant.

They indicate that the length of the solar cell is l = 12 cm = 0.12m. Let's find the area of ​​the solar cell.

        A = l²

        A = 0.12²

        A = 1.44 10⁻² m²

Let's use a direct proportion rule. If 1 m² receives 1000J of energy, how much does an area of ​​1.44 10⁻² m² receive?

        Energy_cell = 1000 J ( [tex]\frac{1.44 \ 10^{-2}}{1}[/tex] )

        Energy_ cell = 14.4 J

Let's use another direct ratio rule for efficiency.

       [tex]Energy_{produced} = Energy_{cell} \frac{12}{100} \\Energy_{produced} = 14.4 0.12 \\Energy_{produced} = 1.728 J[/tex]

In conclusion using the direct proportions rule we can find the result for the energy produced by a solar cell is:

        E = 1,728 J

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The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =[tex]\sqrt{\frac{T}{\mu } }[/tex]

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = [tex]\frac{d}{t}[/tex]  

           v = [tex]\frac{4 L}{t}[/tex]  

           v = [tex]\frac{4 \ 2.28 }{0.849}[/tex]  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = [tex]\frac{m}{L}[/tex]  

            [tex]\mu = \frac{0.2}{2.28}[/tex]  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

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Answer:

Equal reaction from the pair in every action there's an equal and opposite reaction

The item will keep moving at a consistent speed if the object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg.

All mass-bearing objects are attracted by gravitational force. Because it consistently attempts to bring masses together rather than push them apart, the gravitational force is referred to as attractive.

As we know, the gravitational force is given by:

[tex]\rm F = \dfrac{Gm_1m_2}{r^2}[/tex]

Where G is the gravitational constant.

m1 and m2 are masses.

r is the distance between the masses.

It is given that:

An object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg.

As we know,

An object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg and the item will keep moving at a consistent speed.

Thus, the item will keep moving at a consistent speed if the object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg.

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Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]d = \frac{m}{v} \\ [/tex]

m is the mass

v is the volume

From the question

m = 200g

v = 100 mL

We have

[tex]d = \frac{200}{100} = 2 \\ [/tex]

We have the final answer as

Hope this helps you

The maximum mass of a load that can be lifted by the jack and the distance covered are:

m = 160.2 Kg

h = 25 cm

Given that a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while the diameter of the larger piston is 2.0m.

The parameters given are

[tex]F_{1}[/tex] = 250

[tex]A_{1}[/tex] = Area of the small piston = π[tex]r^{2}[/tex]

[tex]A_{1}[/tex] = 22/7 x [tex]0.4^{2}[/tex]

[tex]A_{1}[/tex] = 0.5 [tex]m^{2}[/tex]

[tex]F_{2}[/tex] = ?

[tex]A_{2}[/tex] = Area of the large piston = π[tex]r^{2}[/tex]

[tex]A_{2}[/tex] = π x 1

[tex]A_{2}[/tex] = 3.14 [tex]m^{2}[/tex]

To calculate the force on the large piston, we will use the below formula

[tex]F_{1}[/tex]/ [tex]A_{1}[/tex] = [tex]F_{2}[/tex] / [tex]A_{2}[/tex]

Substitute all the parameters into the equation

250/0.5 =  [tex]F_{2}[/tex]/3.14

[tex]F_{2}[/tex] = 1570 N

To calculate the maximum mass of a load that can be lifted by the jack, let us apply Newton second law

F = mg

1570 = 9.8m

m = 1570/9.8

m = 160.2 Kg

.(take g=9.81ms^-2)​

If the applied force moves through a distance of 25cm, the distance through which the load is lifted will be

[tex]F_{1}[/tex]/ 0.25[tex]A_{1}[/tex] = [tex]F_{2}[/tex] / [tex]A_{2}[/tex]h

250/0.125 = 1570/3.14h

make h the subject of the formula

6280h = 1570

h = 1570/6280

h = 0.25 m

Therefore, the distance through which the load is lifted is 25 cm

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Answer:

......the answer is 496.4

D. :)

lmk if im right or wrong

Answer:

D. 5ºC

Explanation:

Not B, because 1k= -457.87 fahrenheit. That means it is also not C. Since the icicles are melting, then that means it is not A either.

5ºC=about 41ºF

Answer:

Avoid heavy strenuous exercise for the 24 hours prior to testing. Do not exercise at all on the day of testing to ensure you are well rested. Wear appropriate clothing for the conditions (e.g. shorts/track pants and t-shirt/singlet/sports top) and non-slip athletic footwear with laces securely fastened

Answer:

Frictional force is produced when two bodies are rubbed against each other. It is the force that oppose the motion and therefore it stops or slow down a moving body.It depends upon the roughness or smoothness of the surface of the body in contact.Rough surface have more friction that the smooth surface. Similarly, the heavier body produces more friction than a lighter body. Frictional force acts in the opposite direction of the motion of the body.

Machine translators:

Level of accuracy can be very low.

Accuracy is also very inconsistent across different languages.

Machines can't translate context.

Mistakes are sometimes costly.

Sometimes translation simply doesn't work.

Human translators:

Turnaround time is longer.

Translators rarely work for free.

Unless you use a translation agency, with access to thousands of translators, you're limited to the languages any one translator can work with.

Answer:

b

Explanation:

when the wavelength increase it doesnt affect the frequency of a wave.

Answer: The wavelength increases by a factor of 3

Explanation:

Increasing the angle of inclination of the plane decreases the velocity of the block as it leaves the spring.

Reasons:

The energy given  to the block by the spring = [tex]\mathbf{0.5 \cdot k \cdot x^2}[/tex]

According to the principle of conservation of energy, we have;

On a flat plane, energy given to the block = [tex]0.5 \cdot k \cdot x^2[/tex] = kinetic energy of

block = [tex]0.5 \cdot m \cdot v^2[/tex]

Therefore;

0.5·k·x² = 0.5·m·v²

Which gives;

x² ∝ v²

x ∝ v

On a plane inclined at an angle θ, we have;

The energy of the spring = [tex]\mathbf{0.5 \cdot k \cdot x^2}[/tex]

The energy given to the block = [tex]0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta)[/tex] = The kinetic energy of block as it leaves the spring = [tex]\mathbf{0.5 \cdot m \cdot v^2}[/tex]

Which gives;

[tex]0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta) = 0.5 \cdot m \cdot v^2[/tex]

Which is of the form;

a·x² - b = c·v²

a·x² + c·v² = b

Where;

a, b, and c are constants

The graph of the equation a·x² + c·v² = b  is an ellipse

Therefore;

Please find attached a drawing related to the question obtained from a similar question online

The possible question options are;

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Hi there!

(A)

A grinding wheel is the same as a disk, having moment of inertia of:

[tex]I = \frac{1}{2}MR^2[/tex]

Plug in the given mass and radius (REMEMBER TO CONVERT) to find the moment of inertia:

[tex]I = \frac{1}{2}(0.380)(0.085)^2 = 0.00137 kgm^2[/tex]

(B)

We can use the rotational equivalent of Newton's Second Law to calculate the needed torque:

Στ = Iα = τ₁ - τ₂

Begin by solving for the angular acceleration. Convert rpm to rad/sec:

[tex]\frac{1750r}{min} * \frac{1 min}{60 s} * \frac{2\pi rad}{1 r} = 183.26 rad/sec[/tex]

Now, we can use the following equation:

ωf = wi + αt (wi = 0 rad/sec, from rest)

183.26/5 = α = 36.65 rad/sec²

τ = Iα = 0.0503 Nm

Since there is a counter-acting torque on the system, we must begin by finding that acceleration:

[tex]\frac{1500r}{min} * \frac{1 min}{60 s} * \frac{2\pi rad}{1 r} = 157.08 rad/sec[/tex]

ωf = wi + αt

-157.08/55 = α = -2.856 rad/sec²

τ₂ = Iα = 0.0039 Nm

Now, calculate the appropriate torque using the above equation:

[tex]\Sigma\tau = \tau_1 - \tau_2[/tex]

[tex]\Sigma\tau + \tau_2 = \tau_1[/tex]

[tex]0.0503 + 0.0039 = \large\boxed{0.054 Nm}[/tex]

Answer:

potential energy = mgh

= 400÷1000 × 10× 4÷100

= 0.4 × 10 × 0.04

=4/10 ×10×4/100

= 4/10 × 4/10

=16/100

= 0.16 joules

m1 (400) stretches 4cm

m1 (100g) stretches 1cm

so, m2(800g) stretches 8 cm

potential energy of m2 = mgh

= 800/1000 ×10×8/100

= 0.8 × 0.8

=8/10 ×8/10

= 64/100

=0.64 joules

Ratio of s1 to s2

16/100 ÷ 64/100

= 1:4 ( answer)

Answer:

1. C

2. True

3. D

4. True

Explanation:

While distance refers to “how much land an object has traversed throughout its journey,” displacement measures “how far an object is out of place.” In this post, let's look at the difference between distance and displacement. Thus, option C is correct.

Displacement and distance are two distinct ideas. The total distance travelled is larger than the displacement between those two points if an object changes direction while travelling.

Distance is the length of any path connecting any two places. Displacement is the straight-line distance between any two points when calculated along the shortest route.

Therefore, The direction is ignored when calculating distance. The direction is accounted for in the displacement calculation.

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Answer:

"Narrow the focus of research question"

Explanation:

O Narrow the focus of research question

    This is good! You can still use your question, but focus in on something so you have a proper research project.

O Add another research question

    Would adding another question to an already broad question help? No.

O Use the very first source you find for your project

    If your question is too broad, you should not use whatever you see first as it may be incorrect or does not answer the question

O Change the scope of your project​    

    You could, but if you have a set scope for your project (a) you might not be able to change it (b) you don't need to restart

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

I think the answer would be C

C = They can occur in either direction.

Explanation:

the answer is C. They can occur in either directions