For this visualization, a bar chart would be the best choice.
A bar chart is an effective way to visually compare different categories or groups. In this case, the data analyst can create a bar chart where each bar represents a city, and the height of the bar corresponds to the population of that city. The analyst can include only the top ten most populous cities in North Carolina and color the bars differently based on whether the population is below or above 250,000 people. By doing so, it becomes easy to identify which cities fall below the threshold, as they will have shorter bars compared to those above the threshold. The clear distinction between the bar heights allows for quick visual comparison and provides a straightforward representation of the population distribution among the top ten cities in North Carolina.
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Two cars drive from one end to the other, in opposite directions. Each goes at a constant speed. One car takes 30 seconds to get from one end to the other. The other takes 50 seconds. They both reach the end at the same time. Draw a graph and use it to find how far the cars are from each end of the track when they pass one another.
The first car is at a Distance 1/80 units away from the starting end of the track when they pass. The second car is 79/80 units away from the starting end of the track when they pass.
Let's represent the distance traveled by the first car as a function of time, and the distance traveled by the second car as another function of time. We'll assume that the track is of length 1 unit (for simplicity).
The first car's distance as a function of time can be represented by the equation:
d1(t) = t/30
The second car's distance as a function of time can be represented by the equation:
d2(t) = 1 - t/50
To find when the cars pass each other, we need to find the time at which their distances are equal. So we set d1(t) = d2(t) and solve for t:
t/30 = 1 - t/50
Simplifying the equation:
50t = 30 - 30t
80t = 30
t = 30/80 = 3/8
Therefore, the cars pass each other at t = 3/8 seconds. To find the distance from each end of the track when they pass, we substitute this time value into either d1(t) or d2(t):
d1(3/8) = (3/8)/30 = 1/80
The first car is 1/80 units away from the starting end of the track when they pass. Since the track is of length 1 unit, the second car is 1 - 1/80 = 79/80 units away from the starting end of the track when they pass.
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Tom needs to paint a fence that is made of 5 panels. He has red, yellow, green, blue, and white paint. In how many ways can Tom paint the fence if no two neighboring panels can be painted the same color?
Answer: In how many ways can Tom paint the fence if no two neighboring panels can be painted the same color?
Step-by-step explanation:
There are a total of 120 ways to paint the fence with no two neighboring panels painted the same color.
To see why, consider the first panel. Tom can paint it any of the 5 colors. Without loss of generality, assume that he paints it red.
For the second panel, he can choose any of the 4 remaining colors (since he cannot use red again). Without loss of generality, assume that he paints it yellow.
For the third panel, he can choose any of the 3 remaining colors (since he cannot use red or yellow again). Without loss of generality, assume that he paints it green.
For the fourth panel, he can choose any of the 2 remaining colors (since he cannot use red, yellow, or green again). Without loss of generality, assume that he paints it blue.
For the fifth panel, he can choose the only remaining color (since he cannot use red, yellow, green, or blue again). Without loss of generality, assume that he paints it white.
Therefore, there are 5 × 4 × 3 × 2 × 1 = 120 ways to paint the fence with no two neighboring panels painted the same color.
{Hope This Helps! :)}
What is the area of ΔABC such that b = 28 cm, c = 14 cm, and m∠A = 30°? Round the answer to three decimal places.
98 cm2
169.741 cm2
193.654 cm2
196 cm2
The Area of ΔABC is 98 cm2.
The area of the triangle, we can use the formula:
A = 0.5 * b * c * sin(A)
where A is the angle between sides b and c.
Given that b = 28 cm, c = 14 cm, and m∠A = 30°, we can calculate sin(A) as follows
sin(A) = sin(30°) = 0.5
Substituting the values in the formula, we get:
A = 0.5 * 28 * 14 * 0.5 = 98 cm2
Therefore, the area of ΔABC is 98 cm2.
Hence, the correct option is: 98 cm2.
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A rectangle has a length of 7 millimeters and an area of 203 square millimeters. What is the width? What is the perimeter?
Required width is 29 millimeters and perimeter is 72 millimeters.
What is width of rectangle?Given, Length of rectangle (L) = 7 millimeters
Area of the rectangle = 203 square millimeters
We know that, area of rectangle = Length × Width = L × W
According to the problem,
[tex]\sf L\times W = 203[/tex]
[tex]\sf \Rightarrow 7\times W=203[/tex]
[tex]\sf \Rightarrow W = \dfrac{203}{7}[/tex]
[tex]\sf \Rightarrow W = 29[/tex]
So, Width of rectangle = 29 millimeters
What is perimeter of rectangle?Perimeter of rectangle = 2 × (Length + Width)
[tex]\sf = 2\times(L+W)[/tex]
[tex]\sf = 2\times(7+29)[/tex]
[tex]\sf = 2\times36[/tex]
[tex]\sf = 72 \ millimeters[/tex]
So, perimeter of rectangle = 72 millimeters
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Why does a method to swap two array elements work correctly when a method to swap two integer values does not?
A method to swap two array elements works correctly because it is designed to swap the entire elements at two different indexes in an array.
The method receives two integer values representing the indexes of the elements to be swapped and then proceeds to swap the elements themselves.
On the other hand, a method to swap two integer values does not work correctly because integers are passed by value, which means that the method receives a copy of the integer values rather than the original values themselves. Thus, the method only swaps the copies and not the original values, and as a result, the original values remain unchanged.
To overcome this issue, one can use a workaround such as passing the integer values as references instead of values. This way, the method receives a reference to the original value, and any changes made to the reference will affect the original value as well. However, this approach can be more complex and less efficient than simply swapping array elements.
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the figure shown represents a plot of land and is drawn using a scale in which 1 cm equals 2 miles. one square mile is 640 acres. how large is the actual plot of land, in acres?
The area of the actual plot of land, in acres is given by 320000 acres.
Here given the figure is a Trapezium.
We know that the area of the Trapezium with parallel sides of length ' a ' and ' b ' and height between them is ' d ' is given by = (1/2)*(1 + b)*d
We know that, 1 cm = 2 miles.
So, 10 cm = 20 miles
15 cm = 15*2 = 30 miles
Here in given trapezium the length of parallel sides are 10 cm and 15 cm. that is 20 miles and 30 miles respectively.
Height between them is = 10 cm = 20 miles.
So the area of the land is = (1/2)*(20 + 30)*20 = 50*10 = 500 square miles.
we know that 1 square miles = 640 acres
So the area in acres = 500*640 = 320000 acres.
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The question is incomplete. The complete question will be -
"The figure shown represents a plot of land and is drawn using a scale in which 1 cm equals 2 miles. one square mile is 640 acres. how large is the actual plot of land, in acres?"
Beetles may be the most varied order of animals. New beetle species are authenticated, completely unpredictably, at a typical rate of one every 7.0months. A supplement to a guide is planned to be published after 20 new species have been discovered.
a)What are the expected value and standard deviation of the number of months (treated as a continuous measure of time) until the supplement is published?
b)What is the probability that the supplement will be published within 10 years (120.0 months)?c)Recalculate the answer to b) using normal approximation and compare (that was certainly easier, was it not?).
a) The standard deviation of T is the square root of the variance, which is SD(T) = sqrt(980) ≈ 31.3 months.
The rate of discovery of new beetle species can be modeled by a Poisson process with rate parameter λ = 1/7.0 new species per month. Let T be the time (in months) until 20 new species are discovered. Then T follows a gamma distribution with shape parameter k = 20 and rate parameter λ. The expected value of T is E(T) = k/λ = 20/(1/7.0) = 140 months. The variance of T is Var(T) = k/λ^2 = 20/(1/7.0)^2 = 980 months^2.
b) The probability that the supplement will be published within 10 years (120 months) is equal to the probability that T ≤ 120. Using the cumulative distribution function (CDF) of the gamma distribution, we can compute this probability as follows:
P(T ≤ 120) = F(120) = ∫[0,120] f(t) dt
where f(t) is the probability density function (PDF) of the gamma distribution, given by:
f(t) = λ^k * t^(k-1) * e^(-λt) / Gamma(k)
where Gamma(k) is the gamma function. Substituting the values of k, λ, and t, we get:
f(t) = (1/7.0)^20 * t^19 * e^(-t/7.0) / Gamma(20)
Using numerical integration or a software program, we can compute the integral:
P(T ≤ 120) ≈ 0.981
Therefore, the probability that the supplement will be published within 10 years is approximately 0.981, or 98.1%.
c) Alternatively, we can approximate the gamma distribution by a normal distribution using the central limit theorem, since the sample size (k = 20) is relatively large. The mean and standard deviation of the normal approximation are given by:
μ = E(T) = 140 months
σ = SD(T) = sqrt(980) ≈ 31.3 months
Using the standard normal distribution, we can standardize the random variable Z = (T - μ) / σ and compute the probability as follows:
P(T ≤ 120) = P(Z ≤ (120 - μ) / σ) ≈ P(Z ≤ (120 - 140) / 31.3) ≈ P(Z ≤ -0.64)
Using a standard normal table or a software program, we can find that the probability of Z being less than or equal to -0.64 is approximately 0.261. Therefore, the probability that the supplement will be published within 10 years using the normal approximation is approximately 0.261, which is lower than the exact probability obtained in part b). This is because the gamma distribution is not exactly symmetric and has a longer tail than the normal distribution, which makes the normal approximation less accurate in the tails of the distribution.
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Factorise: (x-y/xy)^3
The factorized form of the expression[tex](x - y/xy)^3[/tex] is:
[tex]x^3 - 3x + 3/x - 1/x^3[/tex]
To factorize the expression [tex](x - y/xy)^3,[/tex] we can start by simplifying the expression inside the parentheses.
The term y/xy can be simplified to 1/x, so the expression becomes:
[tex](x - 1/x)^3[/tex]
Now, let's apply the cube of a binomial formula, which states that
[tex](a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3.[/tex]
Using this formula, we have:
[tex](x - 1/x)^3 = x^3 - 3x^2(1/x) + 3x(1/x)^2 - (1/x)^3[/tex]
Simplifying further, we get:
[tex](x - 1/x)^3 = x^3 - 3x + 3/x - 1/x^3[/tex]
Therefore, the factorized form of the expression[tex](x - y/xy)^3[/tex] is:
[tex]x^3 - 3x + 3/x - 1/x^3[/tex]
Please note that in this factorization, we simplified the term y/xy to 1/x based on the assumption that y is not equal to zero.
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Madeline has $680 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
She buys a new bicycle for $318.67.
She buys 2 bicycle reflectors for $12.89 each and a pair of bike gloves for $30.57.
She plans to spend some or all of the money she has left to buy new biking outfits for $78.20 each.
Write and solve an inequality which can be used to determine x, the number of outfits Madeline can purchase while staying within her budget.
The inequality is x + $318.67 + $12.89 + $30.57 + $78.20 ≤ $680. The value of 'x' is $226.78.
Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
Let 'x' be the remaining amount. Then the inequality is calculated as,
x + $318.67 + $12.89 + $30.57 + $78.20 ≤ $680
Simplify the inequality, then we have
x + $318.67 + $12.89 + $30.57 + $78.20 ≤ $680
x + $453.22 ≤ $680
x ≤ $226.78
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Use properties to rewrite the given equation. Which equations have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p? Select two options. 2.3p – 10.1 = 6.4p – 4 2.3p – 10.1 = 6.49p – 4 230p – 1010 = 650p – 400 – p 23p – 101 = 65p – 40 – p 2.3p – 14.1 = 6.4p – 4
The options that have the same solution as the rewritten equation 2.3p - 10.1 = 6.49p - 4 are:
Option 2) 2.3p - 10.1 = 6.49p - 4
Option 5) 2.3p - 14.1 = 6.4p - 4
Both of these options are equivalent to the rewritten equation and have the same solution.
To rewrite the given equation, we can combine like terms and simplify:
2.3p - 10.1 = 6.5p - 4 - 0.01p
First, let's simplify the right side of the equation:
6.5p - 4 - 0.01p = 6.49p - 4
The equation becomes:
2.3p - 10.1 = 6.49p - 4
Now, we can compare the rewritten equation to the options provided:
2.3p - 10.1 = 6.4p - 42.3p - 10.1
= 6.49p - 4230p - 1010
= 650p - 400 - p23p - 101
= 65p - 40 - p2.3p - 14.1
= 6.4p - 4.
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for the next 21 days that sasha travels to work, what is the probability that sasha will experience a delay due to traffic on at least 3 of the days?
The probability of experiencing exactly k delays in n days is given by:
P(X = k) = (nCk) * p^k * (1 - p)^(n - k)
To calculate the probability that Sasha will experience a delay due to traffic on at least 3 of the next 21 days, we need to consider the probability of experiencing a delay on each individual day and then use the binomial distribution.
Let's assume that the probability of experiencing a delay on any given day is p. The probability of not experiencing a delay on a single day is 1 - p.
Using the binomial distribution formula,
In this case, we want to find the probability of experiencing at least 3 delays, which means we need to calculate the probabilities for k = 3, 4, 5, ..., 21 and sum them up.
P(at least 3 delays) = P(X = 3) + P(X = 4) + P(X = 5) + ... + P(X = 21)
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For the system shown, what is the value of x+2y?
x+1/3y=0
6x-2y=6
Answer:
Let x = 6-2y/6
substitute into equation 2
6(6-2y/6)-2y = 6
6-4y = 6
-4y= -12
y = 3
From equation 2
6x-2y =6
substitute y=3
6x-2(3)= 6
6x = 12
x= 2
substitute both into the given equation
x+2y
2+2(3)= 8
Therefore x+ 2y= 8
a six-sided die is thrown 50 times. the numbers of occurrences of each face are shown below. can you conclude that the die is not fair?
To determine if the die is fair or not, we can perform a chi-square goodness-of-fit test. The null hypothesis for this test is that the observed frequencies match the expected frequencies, assuming the die is fair.
We can set the expected frequency for each face to be 50/6 = 8.33 (since there are six faces on the die and 50 total throws).
Next, we calculate the chi-square test statistic by comparing the observed frequencies to the expected frequencies. Using the formula:
χ² = ∑((O - E)² / E), where O is the observed frequency and E is the expected frequency.
Once we have the test statistic, we compare it to the critical value from the chi-square distribution with (number of categories - 1) degrees of freedom (in this case, 6 - 1 = 5) at a chosen significance level (e.g., 0.05). If the test statistic exceeds the critical value, we reject the null hypothesis and conclude that the die is not fair.
It's not possible to perform the chi-square test without the observed frequencies for each face of the die. Please provide the observed frequencies for each face, and I can help you analyze the data to determine if the die is fair or not.
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My kitchen is working properly but was showing 10: 06, which is the wrong time, when I left to walk to my friend's house for coffee. My friend's clock, which was correct, was showing 10:28 when I arrived and 11:55 when I left. I walked home at the same speed as when I went, and when I arrived home my clock was showing 11:55. I then adjusted my clock to show the correct time. How many minutes back did I have to move my clock?
According to the given information, the friend's clock showed that 1 hour and 27 minutes had passed between the time we left and the time we arrived. The kitchen clock needs to be adjusted 1 hour and 5 minutes back, which is equal to 65 minutes.
When we left the house, the kitchen clock was showing 10:06, but according to the friend's clock, the correct time was 10:28.
Therefore, we left the house 22 minutes before the correct time. When we arrived at the friend's house, their clock showed 11:55, which means that 1 hour and 27 minutes had passed since we left our house.
However, the kitchen clock was only showing 10:28 + 22 minutes = 10:50, which means that the kitchen clock was slow by 1 hour and 5 minutes.
To adjust the kitchen clock to the correct time, we need to move it back by 1 hour and 5 minutes, which is equal to 65 minutes. Therefore, the correct time on the kitchen clock should be 10:06 - 1 hour and 5 minutes = 9:01. By adjusting the clock back by 65 minutes, it will now show the correct time of 11:55 when we return home.
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Find the height of the figure with the volume V=480pi cubic cm
The value of the height is 10/3 cm
How to determine the heightFirst, we need to know that the formula for calculating the volume of a cylinder is expressed as;
V = πr²h
Such that the parameters are expressed as;
V is the volume of the cylinder.r is the radius of the cylinderh is the height of the cylinderπ takes the constant value of 3.14Now, substitute the values, we have that;
r = 12cm
Volume = 480π cm³
Then,
480π = 144π × h
divide both sides by the coefficient of h, we get;
h = 480π/144π
h = 40/12
h = 20/6
h = 10/3 cm
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Pls answer 40pts Drag the tiles to the correct boxes to complete the pairs.
Match each quadratic function to its graph.
f(x) = -2(x + 3)2 − 1
f(x) = -2(x + 3)2 + 1
f(x) = 2(x + 3)2 + 1
f(x) = 2(x − 3)2 + 1
Answer:
Step-by-step explanation:
f(x) = -2(x+3)^2 -1 would be the fourth graph because its translated 3 to the left, negative, and 1 down
f(x)=2(x+3)^2+1 would be the first graph since it's translated 3 to the left, positive, and shifted 1 up
f(x)=-2(x+3)^2+1 would be the second graph since it's translated 3 to the right, negative, and shifted 1 up
f(x)=2(x-3)^2+1 would be the third graph since it's translated 3 to the right, positive, and shifted 1 up
Tim brought $40. 50 to the state fair. He bought a burger, a souvenir, and a pass. The burger was
1
4
as much as the souvenir, and the souvenir cost
2
3
the cost of the pass. Tim had $2. 00 left over after buying these items. What was the cost of each item?
The cost of the burger was approximately $2.19, the cost of the souvenir was approximately $8.
let's first assign variables to the cost of each item. let b be the cost of the burger, s be the cost of the souvenir, and p be the cost of the pass.
from the problem, we know that:
b + s + p = 40.50 (total cost of all three items)b = (1/4)s (the burger cost one-fourth the price of the souvenir)
s = (2/3)p (the souvenir cost two-thirds the price of the pass)b + s + p + 2.00 = 40.50 (tim had $2.00 left over)
we can use substitution to solve for the unknown variables.
substituting b = (1/4)s and s = (2/3)p into the first equation, we get:
(1/4)s + s + (2/3)p = 40.50
multiplying both sides by 12 to eliminate the fractions, we get:
3s + 12s + 8p = 486
simplifying, we get:
15s + 8p = 486
substituting s = (3/2)p into the above equation, we get:
15(3/2)p + 8p = 486
simplifying further, we get:
37p = 486
solving for p, we get:
p = 486/37
p ≈ 13.14
now that we know the cost of the pass, we can use the second equation to find the cost of the souvenir:
s = (2/3)p = (2/3)(13.14) ≈ 8.76
finally, we can use the first equation to find the cost of the burger:
b = (1/4)s = (1/4)(8.76) ≈ 2.19 76, and the cost of the pass was approximately $13.14.
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it's a good deal bro take it
Answer:
3/4
Step-by-step explanation:
9/12
divide top and bottom by 3
3/4
what is 24.790000 to 2 significant figures ?
Answer:
25.
Step-by-step explanation:
The first thing we must note are thr rules of significant figures:
RULES FOR SIGNIFICANT FIGURES
1. All non-zero numbers ARE significant
2. Zeros between two non-zero digits ARE significant.
3. Leading zeros are NOT significant
4. Trailing zeros to the right of the decimal ARE significant
From this, we see the total amount of sig figs in 24.790000, which is every number, To round this to two sig figs, we just need to round to two places, which ends up being the tens and ones place to the left of the decimal. The answer would then be 25., with the decimal mark to denote that there are only two sig figs.
Find x to the nearest degree
Answer:
56°
Step-by-step explanation:
call the unknown side length L.
then 5² + L² = 9²
L² = 9² - 5²
=81 - 25
= 56
L =√56
(sin x)/√56 = (sin 90)/9
sin x = (√56 X sin 90)/9 = √56 /9
x = sin^-1 (√56 / 9)
= 56.25°
= 56° to nearest degree
beyond struggling pls help
FIND THE FOLLOWING MEASUREMENTS
Check the picture below.
well, ∡CED is the same as ∡CEA and those are right-angles so those are pretty much given, now
[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{29}\\ a=\stackrel{adjacent}{20}\\ o=\stackrel{opposite}{CE} \end{cases} \\\\\\ CE=\sqrt{ 29^2 - 20^2}\implies CE=\sqrt{ 841 - 400 } \implies CE=\sqrt{ 441 }\implies \boxed{CE=21} \\\\\\ \stackrel{\textit{since we know the radius CB=29}}{CB-CE = EB\implies }\boxed{EB=8}[/tex]
Answer:
angle CED 90°. CE = 21. EB = 8.
Step-by-step explanation:
angle CED = 90° (right angle).
the radius (centre to edge) is the same right around the circle.
so that means that distance CD = 29.
draw a line from C to D. notice how that has just become an hypotenuse?
we know that DE = 20.
we have a right-angled triangle.
CE² = hypot² - DE²
= 29² - 20²
= 841 - 400
= 441
CE = √441 = 21.
EB must be radius subtract CE. that is, 29 - 21 = 8.
how many triangles can be formed by connecting three points out of nine on the circumference of a circle
The number of triangles can be formed 84
Triangle:A triangle is a polygon with three sides which consists of three vertices. A triangle can be formed from three given points only if the three points do not lie on a straight line and also form 180 degree angle.
Since the 3 points are distinct and lie on a circle, then it is not possible to have three points such that all three lie on a line.
Hence, we can use these 3 points to form triangles by selecting 3 points. The number of such ways is the number of different triangles we can form. Hence,
Triangles = [tex]C^9_3[/tex]
Triangles = [tex]\frac{9!}{3!(6!)}[/tex]
Triangles = 84
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the quadrilateral is circumscribed about the circle. find the value of x. then find the perimeter of the quadrilateral.
The value of x is: x = 6, while the perimeter of the quadrilateral is calculated as: 52 units.
How to Find the Perimeter of the Quadrilateral?Based on the tangent theorem (two tangents meeting at the same point outside a circle have the length), we have:
x + 2 = 8
x + 2 - 2 = 8 - 2
x = 6
The value of x in the circumscribed quadrilateral is therefore, 6 units.
Using the same theorem the perimeter of the quadrilateral can be found by adding all sides of the quadrilateral as follows:
perimeter = 8 + 8 + 5 + 5 + 9 + 9 + 4 + 4
Perimeter = 52 units.
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Ram Purchased a flat at ₹1. 1 lakh and Prem purchased aplot of land worth ₹ 1. 1 lakh. The respective annual rates at which the prices of the flat and the plot increases were 10% and 5%. After two years they exchanged their belongings and one paid the other the difference. Then who paid to whom by how much?
Prem purchased a plot for ₹1.1 lakh and its price increased at an annual rate of 5%.Ram's flat had a higher value than Prem's plot, Prem paid Ram the difference, which was ₹0.118 lakh or ₹11,800. Ram's flat is more valuable than Prem's plot of land
After two years, the value of Ram's flat would be ₹1.1 lakh + (10% of ₹1.1 lakh × 2 years) = ₹1.43 lakh.
Similarly, the value of Prem's plot of land would be ₹1.1 lakh + (5% of ₹1.1 lakh × 2 years) = ₹1.21 lakh.
Therefore, the difference in value between Ram's flat and Prem's plot of land is ₹1.43 lakh - ₹1.21 lakh = ₹22,000.
Ram would have to pay ₹22,000 to Prem as Ram's flat is more valuable than Prem's plot of land.
Ram purchased a flat for ₹1.1 lakh and its price increased at an annual rate of 10%. After two years, the flat's value would be:
1.1 lakh * (1 + 0.1)^2 = 1.1 lakh * 1.21 = ₹1.331 lakh
Prem purchased a plot for ₹1.1 lakh and its price increased at an annual rate of 5%. After two years, the plot's value would be:
1.1 lakh * (1 + 0.05)^2 = 1.1 lakh * 1.1025 = ₹1.213 lakh
After exchanging their properties, the difference in value is:
₹1.331 lakh (flat) - ₹1.213 lakh (plot) = ₹0.118 lakh
Since Ram's flat had a higher value than Prem's plot, Prem paid Ram the difference, which was ₹0.118 lakh or ₹11,800.
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w^(3)-w(w^(2)+2w-1)+2w
copper has a face-centered cubic unit cell. how many atoms of cu are present in each unit cell?
The total number of copper (Cu) atoms in each face-centered cubic (FCC) unit cell is 7 atoms.
Here, we have,
In a face-centered cubic (FCC) unit cell, there are a total of 4 atoms.
Each corner of the unit cell contains 1/8th of an atom,
and since there are 8 corners in a cubic unit cell,
the total contribution from the corners is 8 * 1/8 = 1 atom.
Additionally, there is 1 atom located at the center of each face,
and since there are 6 faces in a cubic unit cell,
the contribution from the faces is 6 * 1 = 6 atoms.
Therefore, the total number of copper (Cu) atoms in each face-centered cubic (FCC) unit cell is 1 + 6 = 7 atoms.
Hence, 7 atoms of cu are present in each unit cell.
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100 POINTS IF YOU DO THIS CORRECT
This stem-and-leaf plot represents the height of the students on Mark’s basketball team. One student’s height is missing from the plot. If the mean height of all the students on the team is 63 inches, what is the unknown height?
in.____
The unknown height of the student on the team, given the stem and leaf plot, would be 60 inches
How to find the unknown height ?To find the unknown height, we first have to list the heights of the known students on the team. From the stem and leaf plot, the heights are :
57, 59, 62, 65, 68, 70
The mean height of all the students is 63 inches which means that if this mean is denoted as x, the unknown height would be:
63 = ( 57 + 59 + 62 + 65 + 68 + 70 + x ) / 7
Solving for x gives:
7 x 63 = ( 381 + x )
441 = 381 + x
x = 441 - 381
x = 60 inches
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There are 240 students in the 6th grade with 12 teachers. How many students per 1 teacher?
A. 13
B. 24
C. 20
D. 30
Answer:
24
Step-by-step explanation:
Answer:
C. 20
Step-by-step explanation:
To find out how many students per teacher, we can divide the total number of students by the total number of teachers:
240 students / 12 teachers = 20 students per teacher.
Therefore, the answer is C. 20.
Write the quadratic equation given the points (-1,0), (-4, 0), and (1, 10).
O g(x) = x² + 5x +4
Og(x)=x²-5x +4
O g(x)=x²-5x - 4
O g(x)
g(x) = x² + 4x + 4
The quadratic equation from the points is g(x) = x² + 5x + 4
Writing the quadratic equation from the pointsFrom the question, we have the following parameters that can be used in our computation:
(-1,0), (-4, 0), and (1, 10).
A quadratic function is represented as
g(x) = a(x - x₁)(x - x₂)
Using the given points, we have
g(x) = a(x + 4)(x + 1)
Next, we have
a(1 + 4)(1 + 1) = 10
This gives
a = 1
So, we have
g(x) = (x + 4)(x + 1)
Expand
g(x) = x² + 5x + 4
Hence, the quadratic equation from the points is g(x) = x² + 5x + 4
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What is the relationship between the two radios 10/24 and 5/12
Answer: These two ratios, 10/24 and 5/12 share a proportional relationship.
Step-by-step explanation:
Because when you divide the denominator and the numerator (10/24) by two they’ll equal the other ratio.
