Question below...........................

Question Below...........................

Answers

Answer 1

[tex]\boxed{\sf PE=mgh}[/tex]

[tex]\boxed{\sf KE=\dfrac{1}{2}mv^2}[/tex]

[tex]\boxed{\sf ME=KE+PE}[/tex]

#1

[tex]\\ \sf\longmapsto PE=60(0)(10)=0J[/tex]

[tex]\\ \sf\longmapsto KE=\dfrac{1}{2}(60)(8)^2=30(64)=1920J[/tex]

[tex]\\ \sf\longmapsto ME=1920+0=1920J[/tex]

#2

[tex]\\ \sf\longmapsto PE=60(10)(1)=600J[/tex]

[tex]\\ \sf\longmapsto KE=600J[/tex]

[tex]\\ \sf\longmapsto ME=1200J[/tex]

Now

[tex]\\ \sf\longmapsto \dfrac{1}{2}mv^2=600\implies 30v^2=600\implies v^2=20\implies v=4.2m/s[/tex]


Related Questions

g A 150-kg object and a 450-kg object are separated by 4.90 m. (a) Find the magnitude of the net gravitational force exerted by these objects on a 39.0-kg object placed midway between them. 130000000000 Incorrect: Your answer is incorrect. Draw a picture of the three objects, including the forces exerted on the third. N (b) At what position (other than an infinitely remote one) can the 39.0-kg object be placed so as to experience a net force of zero from the other two objects

Answers

Answer:

BBbbb

Explanation:

B is the correct answer:))))

70 POINT!!!
IF YOU DON'T KNOW THE ANSWER DO NOT PUT A COMMENT BELOW

THERE ARE TWO QUESTIONS YOU HAVE TO ANSWER
QUESTION 1: Identify any variables that are present as dependent variables, independent variables, and constants in your experimental group and your control group.
QUESTION 2: How does knowing the properties of matter help you separate the substances in mixtures?

Answers

Answer:

1) Dependent variable: Type of separation method used

   Independent variables: Substance that separated out

  Constants: Sand, pepper, and salt

2) you can use the properties of matter to decide on a method to separate out a particular substance based on its unique properties. For example, knowing pepper has a very small mass allows you to use the charge of the static electricity to separate out those particles. Additionally, knowing the solubility of salt allows you to add water to the mixture to be able to remove it from the sand, since the salt dissolves in the water which is poured away.

For a certain transverse standing wave on a long string, an antinode is at x = 0 and an adjacent node is at x = 0.20 m. The displacement y(t) of the string particle at x = 0 is shown in the figure, where the scale of the y axis is set by ys = 4.3 cm. When t = 0.90 s, what is the displacement of the string particle at (a) x = 0.30 m and (b) x = 0.40 m ? What is the transverse velocity of the string particle at x = 0.30 m at (c) t = 0.90 s and (d) t = 1.3 s?

Answers

The expressions for the traveling and standing wave to find the results for the questions about the displacement and speed of the particle are:

       a) For time zero, the displacement at position x = 0.30 m is y = 3.04 cm

     b) For time zero, the displacement at position x = 0.40 m is: y = 0

      c) For the point x = 0.30 and time t = 0.9s, the velocity of the particle is:

          v = 9.11 cm / s

      d) For the point x = 0.30 and time t = 1.3s, the velocity of the particle is:

          v = 9.65 cm / s

The traveling wave is a disturbance in the medium that moves at constant speed, in the case of a transverse wave the expression for the perpendicular oscillation is:

         y = A sin (kx - wt)

Where y is the oscillation perpendicular to the direction of the displacement, A the amplitude, k in wave number and w the angular velocity.

Standing waves are formed when a traveling wave collides with an obstacle and is reflected, in this case the sum of the two waves gives a wave that does not shift in time and fulfills the relationship

           [tex]\frac{\lambda}{2} = \frac{L}{n}[/tex]  

Where λ is the wavelength, L the distance between the reflection points and n the number of nodes.

Indicates that for the standing wave the distance between an antinode and the node is x = 0.20 m, therefore

               [tex]\frac{\lambda}{4} = \frac{L}{1}[/tex]  

              λ = 4L

              λ = 4 0.20

              λ = 0.80 m

The wave number.

              k = [tex]\frac{2\pi }{\lambda }[/tex]  

              k = [tex]\frac{2 \pi }{0.80 }[/tex]  

              k = 2.5π i m⁻¹

In the associated traveling wave, from the graph we can see that the period of the wave is:

             T = 2.8 s

the angular velocity is related to the period.

             [tex]w=\frac{2\pi}{T} \\w = \frac{2\pi }{2.8}[/tex]  

             w = 0.714π  rad/s

indicate the maximum displacement that is the amplitude of the wave.

              A = [tex]y_s[/tex]  

             A = 4.3 cm

Let's write the equation of the traveling wave.

              y = 4.3 sin [π (2.5 x - 0.714 t)]

with this expression we can answer the questions.

a) the displacement of the particle for x = 0.30 m

            y = 4.3 sin (π (2.5 0.30 - 0.714 t))

            y = 4.3 sin π( 0.75 - 0.714 t(

Remember that the angles must be in radians.  For time t = 0 the displacement is

              y = 4.3  0.707

              y = 3.04 cm

 

b) The displacement for x = 0.4m

              y = 4.3 sin (π 2.5 0.4)

              y = 0 cm

c) the transverse velocity of the wave at x = 0.30 m for the time of t = 0.90s

the speed of the wave is

              [tex]v= \frac{dy}{dt} \\v= A w cos ( kx - wt)[/tex]  

              v = 4.3 0.714π cos π(2.5 0.3 - 0.714 t)

              v = 9.65 cos π(0.75 - 0.714 t)

For time t = 0.90 s the velocity is:

            v = 9.65 cos π(0.75 - 0.714 0.9)

            v = 9.65 0.9436

            v = 9.11 cm / s

d) The velocity for time t = 1.3 s

           v = 9.65 cos π(0.75 - 0.714 1.3)

           v = 9.65 0.9999

           v = 9.65 cm / s

In conclusion, using the expressions for the traveling and standing wave, we can find the results for the questions about the displacement and speed of the particle are:

      a) For time zero, the displacement at position x = 0.30 m is y = 3.04 cm

     b) For time zero, the displacement at position x = 0.40 m is: y = 0

      c) For the point x = 0.30 and time t = 0.9s, the velocity of the particle is:

          v = 9.11 cm / s

      d) For the point x = 0.30 and time t = 1.3s, the velocity of the particle is:

          v = 9.65 cm / s

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Describe what you think energy is in physics and what does it do.

Answers

In Physics, energy can be defined as the ability and capacity to do work by an object or physical body.

What is energy?

In Physics, energy can be defined as the ability to do work. Thus, energy must be possessed or transferred to a physical object (body) before it can be used in doing a work or heating a system.

The types of energy.

Generally, there are two (2) main types of energy and these are;

Potential energy (P.E): it is an energy that is possessed by an object or body due to its height (position) above the Earth surface.Kinetic energy (K.E): it is an energy possessed by an object or body due to its motion.

For example, you require a sufficient amount of energy to move a crate of egg across a given distance.

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Answer:. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another. ... All forms of energy are associated with motion.

Explanation:. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another. ... All forms of energy are associated with motion.

Suppose the student in (Figure 1) is 68kg, and the board being stood on has a 12kg mass. What is the reading on the left scale? What is the reading on the right scale?

Answers

The equilibrium conditions allow to find the results for the balance forces are:

F₁ = 225.4 N F₂ = 558.6 N

When the acceleration is zero we have the equilibrium conditions for both linear and rotational motion.

            ∑ F = 0

            ∑ τ = 0

           

Where F are the forces and τ the torques.

The torque  is the product of the force and the perpendicular distance to the point of support,

The free-body diagrams are diagrams of the forces without the details of the bodies, see attached for the free-body diagram of the system.

We write the translational equilibrium condition.

           F₁ - W₁ - W₂ + F₂ = 0

We write the equation for the rotational motion, set our point of origin at scale 1, and the counterclockwise turns are positive.

         F₂ 2 - W₁ 1 - W₂ 1.5 = 0[tex]\frac{W_1 \ 1 + W_2 \ 1.5}{2}[/tex]

Let's calculate F₂

         F₂ = [tex]\frac{W_1 \ 1 + W_2 \ 1.5 }{2}[/tex]  

         F₂ = (m g + M g 1.5)/ 2

         F₂ = [tex]\frac{(12 + 68 \ 1.5 ) \ 9.8}{2}[/tex]  

         F₂ = 558.6 N

We substitute in the translational equilibrium equation.

         F₁ = W₁ + W₂ - F₂

         F₁ = (m + M) g - F₂

         F₁ = (12 +68) 9.8 - 558.6

         F₁ = 225.4 N

In conclusion using the equilibrium conditions we can find the forces of the balance are:

F₁ = 225.4 N F2 = 558.6 N

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9. The acceleration (a)-time (t) graph of a particle moving in a straight line is as shown in figure. At time t = 0, the velocity of particle is 10 m/s. What is the velocity at t = 8 s?
(1) 2 m/s
(2) 4 m/s
(3) 10 m/s
(4) 12 m/s​

Answers

Answer:Acceleration - time graph for a particle moving in a straight line is as shown in figure. Change in velocity of the particle from t = 0 to t = 6s is:-.

1 answer

·

Top answer:

Change in velocity = (sum of area of graph) = ( 12 × 4 × 4 ) + ( 12 × ( + 2) ( - 1) ) - 4 = 8 - 4 = 4 x

Explanation:

Over half the global population faces a shortage of clean water. Which example is a point source water pollutant? pesticide run-off from farmers’ fields a sewer pipe draining directly into a river road oil washing into sewer drains, and eventually reaching waterways erosion from a denuded slope after a heavy rainfall

Answers

An example of a point source water pollutant is a sewer pipe draining directly into a river.

According to the United States Environmental Protection Agency, a  point source pollution is defined as;  “any single identifiable source of pollution from which pollutants are discharged, such as a pipe, ditch, ship or factory smokestack.”

Hence, an example of a point source water pollutant is a sewer pipe draining directly into a river. The pollution is coming from an easily identifiable source which is a sewer pipe connected to a river directly.

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5 What is the maximum speed at which a car round a curve of 25m radius on a level road if the coefficient of static friction between the tires and the road is 0.80?​

Answers

Hi there!

On a level road:

∑F = Ff (Force due to friction)

The net force is the centripetal force, so:

mv²/r = Ff

Rewrite the force due to friction:

mv²/r = μmg

Cancel out the mass:

v²/r = μg

Solve for v:

v = √rμg

v = √(25)(9.81)(0.8) = 14.01 m/s

A solenoid 91.0 cm long has a radius of 1.50 cm and a winding of 1300 turns; it carries a current of 3.60 A. Calculate the magnitude of the magnetic field inside the solenoid.

Answers

The magnitude of the magnetic field inside the solenoid is [tex]6.46 \times 10^{-3} \ T[/tex].

The given parameters;

length of the solenoid, L = 91 cm = 0.91 mradius of the solenoid, r = 1.5 cm = 0.015 mnumber of turns of the solenoid, N = 1300 current in the solenoid, I = 3.6 A

The magnitude of the magnetic field inside the solenoid is calculated as;

[tex]B = \mu_0 nI\\\\B = \mu_o(\frac{ N}{L} )I\\\\[/tex]

where;

[tex]\mu_o[/tex] is the permeability of frees space = 4π x 10⁻⁷ T.m/A

[tex]B = (4\pi \times 10^{-7}) \times (\frac{1300}{0.91} ) \times 3.6\\\\B = 6.46 \times 10^{-3} \ T[/tex]

Thus, the magnitude of the magnetic field inside the solenoid is [tex]6.46 \times 10^{-3} \ T[/tex].

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How are the two types of power plants similar how are they different

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Answer:

iIn a nuclear plant, the heat source is from the nuclear reaction whereas in a thermal power plant it is from the combustion of coal. The difference is in the inlet steam parameters to the turbine in a nuclear plant. Thermal power plants use steam at superheated conditions. ... The nuclear plant uses a 'wet steam turbine'.

Explanation:

The heat source in a nuclear power plant is the nuclear reaction, whereas the heat source in a thermal power plant is coal combustion. The difference is in the turbine's input steam characteristics.

What is a power plant?

Power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.

Nuclear power bare a form of thermal power plant. You have a reactor where fission takes place and heat is generated, a heat exchanger that transports this heat to where it is needed.

Thermal power plant equipment converts this heat into electric energy, usually via a steam turbine.

The reactor, heat exchanger, and thermal conversion technology all have different designs and technologies, but the overall architecture is quite similar to other types of thermal power plants.

The heat source in a nuclear power plant is the nuclear reaction, whereas the heat source in a thermal power plant is coal combustion. The difference is in the turbine's input steam characteristics.

Hence, the two types of power plants differ in  difference is in the turbine's input steam characteristics.

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A cylindrical region of radius R contains a uniform magnetic field parallel to its axis. The field is zero outside the cylinder. If the magnitude of the field is changing at the rate dB/dt, the electric field induced at a point 2R from the cylinder axis is:

Answers

The magnitude of the induced electric field is (RdB/dt)/4

The induced electric field is gotten from

-∫E.dl = dФ/dt where E = induced electric field, dl = path length vector, Ф = magnetic flux through cylindrical region = AB where A = area of magnetic flux = πR² where R = radius of cylindrical region and B = magnetic field.

So, -∫E.dl = dФ/dt

-∫E.dl = dAB/dt

-∫Edlcos0 = AdB/dt (where E.dl = Edlcos0 = Edl since E and dl are parallel to each other.)

So -∫Edl = πR²dB/dt

-E∫dl = πR²dB/dt (∫dl = 2πr since the integral is the circumference of the path)

-E(2πr) = πR²dB/dt (we integrate dl from r = 0 to 2R)

-E2π(2R - 0) = πR²dB/dt

-E4πR= πR²dB/dt

E = πR²dB/dt ÷ 4πR

E = -(RdB/dt)/4

So, the magnitude of the induced electric field is (RdB/dt)/4

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At what speed must the electron revolve round the nucleus of
the hydrogen in its ground state in order that it may not be pulled into the
nucleus by electrostatic attraction

Answers

Explanation:

I think this is it, give it a try

A 45 kg figure skater is spinning on the toes of her skates at 1.1 rev/s. Her arms are outstretched as far as they will go. In this orientation, the skater can be modeled as a cylindrical torso (40 kg, 20 cm average diameter, 160 cm tall) plus two rod-like arms (2.5 kg each, 71 cm long) attached to the outside of the torso. The skater then raises her arms straight above her head. In this latter orientation, she can be modeled as a 45 kg, 20-cm-diameter, 200-cm-tall cylinder.

What is her new rotation frequency, in revolutions per second?

Answers

Answer: HOPE THIS HLEP YOU

Explanation:

Students are asked to create roller coasters for marbles. Their goal is to design a coaster with the tallest possible hill that a marble released from a height of 1.5 m (meters) can clear. The marbles will experience some air resistance and friction as
they move.

What should the students keep in mind as they build their designs?

a)The hill can be taller than 1.5 m (meters), because the marble will be moving faster than its initial velocity allowing it to travel higher than its release height.

b)The hill can be taller than 1.5 m (meters), because the marble will gain mechanical energy as it moves allowing it to travel higher than its release height.

c)The hill should be a little less than 1.5 m (meters) high, because the marble will lose mechanical energy as it moves, preventing it from reaching its release
height.

d)The hill can be exactly 1.5 m (meters) high, because mechanical energy is always
conserved allowing the marble to travel to its release height.

Answers

Answer:

Kinetic Energy.

Explanation:

The movement of a roller coaster is accomplished by the conversion of potential energy to kinetic energy. The roller coaster cars gain potential energy as they are pulled to the top of the first hill. As the cars descend the potential energy is converted to kinetic energy.

Since the marble will loose mechanical energy, the hill should be a little less than 1.5 m (meters) high.

A roller coaster is used to demonstrate the conversion of mechanical energy. In a roller coaster, potential energy is converted to a kinetic energy hence it conveniently serves as a device for demonstrating energy conversions.

As the students make their design, they must bear in mind that the hill should be a little less than 1.5 m (meters) high, because the marble will lose mechanical energy as it moves, preventing it from reaching its release

height.

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Given the force diagram of the basketball, what can you tell about the basketball motion?

Answers

Newton's laws allow to find the result for the movement of the basketballl:

On the vertical axis the ball is on the ground. On the horizontal axis the ball is accelerating in the direction of the pushing force.

Newton's laws establish the relationship between the forces on objects:

The 1st law states that if the net force is zero the object is stationary or with constant speed. The 2nd law gives a relation of the force with the mass and the acceleration of the body. The 3rd. Law states that the force appears in pairs, one on each body with the same magnitude, but in the opposite direction.

Let's apply these principles to the ball's motion diagram.

The two vertical forces are in the opposite direction, one is due to the weight of the body and the other is the attraction of the earth to the support of the ball, they are of equal magnitude, not their action-reaction force and reluctant because it is applied to the same body

       In conclusion we can say that the ball is on the ground.

The two horizontal forces are in the opposite direction, the thrust force is greater than the friction therefore using Newton's second law the ball must be accelerating in the direction of the thrust force.

       In conclusion we can say that the ball is accelerating in the direction of the pushing force.

In conclusion using Newton's laws we can find the result for the motion of the basketball:

On the vertical axis the ball is on the ground. On the horizontal axis the ball is accelerating in the direction of the pushing force.

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A 220 g mass is on a frictionless horizontal surface at the end of a spring that has force constant of 7.0
Nm-1. The mass is displaced 5.2 cm from its equilibrium position and then released to undergo simple
harmonic motion.
At what displacement from the equilibrium position is the potential energy equal to the kinetic energy

Answers

The concept of conservation of energy and harmonic motion allows to find the result for the power where the kinetic and potential energy are equal is:

        x = 0.135 cm

Given parameters

The mass m = 220 g = 0.220 kg The spring cosntnate3 k = 7.0 N / m Initial displacement A = 5.2 cm = 5.2 10-2 m

To find

The position where the kinetic and potential energy are equal

 

A simple harmonic movement is a movement where the restoring force is proportional to the displacement, the result of this movement is described by the expression.

          x = A cos wt + fi

          w² = [tex]\frac{k}{m}[/tex]

Where x is the displacement from the equilibrium position, A the initial amplitude of the system, w the angular velocity t the time, fi a phase constant determined by the initial conditions, k the spring constant and m the mass.

The speed is defined by the variation of the position with respect to time.

       v = [tex]\frac{dx}{dt}[/tex]

let's evaluate

       v = - A w sin (wt + Ф)

Since the body releases for a time t = 0 the velocity is zero, therefore the expression remains.

       0 = - A w sin Ф

For the equality to be correct, the sine function must be zero, this implies that the phase constant is zero

        x = A cos wt

Let's find the point where the kinetic and potential energy are equal.

        K = U

        ½ m v² = m g x

       

we substitute

        ½ A² w² sin² wt = g A cos wt

        sin² wt = [tex]\frac{2g}{A}[/tex]  cos wt

let's calculate

      w = [tex]\sqrt{\frac{7}{0.220} }[/tex]  

      w = 5.64 rad / s

      sin² 5.64t = 2 9.8 / 0.052 cos 5.64t

      sin² 5.64t = 376.92 cos 5.64 t

      1 - cos² 5.64t = 376.92 cos 5.64t

      cos² 5.64t -376.92 cos564t -1 = 0

we make the change of variable

       x = cos 5.64t

      x²- 376.92 x - 1 = 0

      x = 0.026

      cos 5.64t = 0.026

   

Let's find the displacement for this time

       x = 5.2 10-2 0.026

       x = 1.35 10-3 m

In conclusion Using the concepts of conservation of energy and harmonic motion we can find the result for the could where the kientic and potential enegies are equal is:

        x = 0.135 cm

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A power plant running at 31 % efficiency generates 270 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant

Answers

The rate of heat energy exhausted to the river is 600.96 MW.

What is efficiency?

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Given parameters:

Efficiency of the power plant; η = 31 %

Output  electric power; O = 270 MW.

We know that, Efficiency of the power plant;

η  = (Output  electric power/ input power)× 100%

⇒ input power = (Output  electric power × 100)/η

⇒ input power = (270 × 100)/31 MW

= 870.96 MW.

So, the rate of heat energy exhausted to the river that cools the plant =  Input power- output power

= (870.96 - 270) MW

= 600.96 MW.

Hence, heat energy exhausted to the river that cools the plant  is 600.96 MW.

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Two point particles, with masses m and 2 m, are separated by some distance Lin an uniform gravitational field. The center of gravity of this two particle system is:________
А. located L/2 distance away from either mass and on the line joining the two particles.
B. located 1/3 distance away from 2 m and on the line joining the two particles.
C. located L/4 distance away from 2 m and on the line joining the two particles.
D. located L/3 distance away from mand on the line joining the two particles.
E. located L/4 distance away from m and on the line joining the two particles.
F. located where the mass 2 m is located.

Answers

The center of gravity of this two particle system is located 1/3 distance away from 2 m and on the line joining the two particles.

The given parameters:

Mass of the first particle, = mMass of the second particle, = 2mDistance between the two particles, = L

The center of gravity of the two particles when first particle is fixed is calculated as;

[tex]C_G = \frac{m(0 ) \ +2m(L) }{m+ 2m} \\\\C_G = \frac{2mL}{3m} \\\\C_G = \frac{2L}{3}[/tex]

The center of gravity of the two particles when second particle is fixed is calculated as;

[tex]C_G = \frac{m(L) \ + \ 2m(0)}{m + 2m} \\\\C_G = \frac{mL}{3m} \\\\C_G = \frac{L}{3}[/tex]

Thus, the center of gravity of this two particle system is located 1/3 distance away from 2 m and on the line joining the two particles.

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In a thermodynamic process, the internal energy of a system in a container with adiabatic walls decreases by 800 J. Which statement is correct

Answers

The correct statement is, the system performed 800 J of work on its surroundings.

The given parameters:

change in internal energy, ΔU = 800 J

Apply first law of thermodynamics;

ΔU = Q + W

where;

Q is the heat gainedW is the work done on the system by the surrounding

In adiabatic process no heat is gained or lost by the system.

Q = 0

ΔU = W  (work is positive when it is done on the system by its surrounding)

If work is done by the system to the surrounding, the new equation becomes;

ΔU = - W

W = - ΔU

W  = -800 J

This implies that the system performed 800 J of work on its surroundings.

"Your question is not complete, it seems to be missing the following information";

In a thermodynamic process, the internal energy of a system in a container with adiabatic walls decreases by 800 J. Which statement is correct?

a. The system lost 800 J by heat transfer to its surroundings.

b. The system gained 800 J by heat transfer from its surroundings.

c. The system performed 800 J of work on its surroundings.

d. The surroundings performed 800 J of work on the system.

e. The 800 J of work done by the system was equal to the 800 J of heat transferred to the system from its surroundings.

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Mr foster and his students have launched a small rocket. The rocket has just started moving upward due to the thrust

Answers

The thrust force that cause the small rocket can be defined as a push, Thrust is a force or a push.

From Newton's First Law

Newton's first law can be stated as:

A body will continue ti be arrest or uniform motion except acted upon by an external force

If an object, such as the rocket, is at rest then the forces on it are balanced. It takes an additional force to unbalance the forces and make the object move. If the object is already moving, it takes such an unbalanced force, to stop it, change its direction from a straight line path, or alter its speed.

Newton's Second Law

This law of motion is essentially a statement of a mathematical equation. The three parts of the equation are

Mass (m)Acceleration (a), and force (f)

Using letters to symbolise each part, the equation can be written as follows:

F = ma

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Answer:answer in image

Explanation:

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We assume that , the acceleration due to gravity on the surface of the earth, is 32 feet per second per second. If the pendulum is that of a clock that keeps good time when feet, how much time will the clock gain in 24 hours if the length of the pendulum is decreased to 3.97 feet

Answers

The period of the pendulum allows to find the result for how much it advances when the length is reduced is:

           Δt = 1550 s

Simple harmonic motion is an oscillatory motion where the restoring force is proportional to the displacement.

In the case of the simple pendulum, this is fulfilled for small angles minus 15º, the angular velocity of the pendulum is

           w = [tex]\frac{g}{L}[/tex]  

Angular velocity and period are related

           w = [tex]\frac{2pi}{T}[/tex]

We substitute

            T = [tex]2\pi \ \frac{L}{g}[/tex]  

They indicate that for the initial length L₀ and the pendulum marks the exact time, how much time changes if the length is  3.97 feet, therefore the initial length is L₀ = 3.90 feet.

            [tex]T_o^2 = 4 \pi ^2 \ \frac{L_o}{g}[/tex]  

           

The period for the reduced length is:

           [tex]T'^2 = 4\pi ^2 \ \frac{L}{g}[/tex]  

The relationship between the periods is:

            [tex]( \frac{T}{T'}^2 = \frac{L_o}{L} \\T' = \sqrt{\frac{L_o}{L} } \ T[/tex]

Let's calculate

             T ’=  [tex]T \ \sqrt{\frac{3.97}{3.9} }[/tex]  

             T ’= T 1.01795

In the total time of a day.

             T = 24 hours (3600 s / 2h) = 86 400 s

We calculate

             T ’= 86400 1.01795

              T ’= 87,950 s

Therefore the pendulum moves forward in a time of:

           ΔT = T'- T

           ΔT = 87950 - 86400

           ΔT = 1550 s

In conclusion, using the period of the pendulum we can find the result for how much it advances when the length is change is:

           ΔT = 1550 s

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9
are things that you can achieve quickly.
O A.
Dreams
OB.
Long-term goals
O c.
Short-term goals
OD.
Plans

Answers

Answer:

d

Explanation:

A dreams

.......wkkwkwkwkwkwnwnsksk

Answer:

C. short term goal

Explanation:

took a midterm quiz on canvas, Hope this helps <3

A stone is allowed to fall from the top of the tower 100m high at the same moment another stone is projected vertically upward with a velocity of 25m/s. Where and when will the two cross each other​

Answers

Answer:

both the stone will meet at a distance of 80 m from the top of tower.

Explanation:

let "t" = time after which both stones meet

"S" = distance travelled by the stone dropped from the top of tower

(100-S) = distance travelled by the projected stone.

◆ i) For stone dropped from the top of tower

-S = 0 + 1/2 (-10) t²

or, S = 5t²

◆ ii) For stone projected upward

(100 - S) = 25t + 1/2 (-10) t²

= 25t - 5t²

Adding i) and ii) , We get

100 = 25t

or t = 4 s

Therefore, Two stones will meet after 4 s.

◆ ¡¡¡) Put value of t = 4 s in Equation i) , we get

S = 5 × 16

= 80 m.

Thus , both the stone will meet at a distance of 80 m from the top of tower.

(Hope this helps can I pls have brainlist (crown)☺️)

A 260-kg object and a 560-kg object are separated by 3.10 m. (a) Find the magnitude of the net gravitational force exerted by these objects on a 49.0-kg object placed midway between them.

Answers

C is the correct answer:))))))))

Using the expression for the total energy of this system, it is possible to show that after the switch is closed, d2qdt2=−kq, where k is a constant. Find the value of the constant k.

Answers

The value of the constant K is [tex]\mathbf{K = \dfrac{1}{LC}}[/tex]

According to Kirchhoff's loop rule, the total algebraic sum of potential differences in any loop, combining voltage provided by voltage sources as well as resistive components, must equal zero.

Thus, the relation for Kirchhoff's loop rule can be expressed as:

[tex]\mathbf{\dfrac{q}{c}- L\dfrac{dI}{dt} = 0}[/tex]

We all know that the current in the nonconstant charge flow can be written as:

[tex]\mathbf{I = \dfrac{dq}{dt}}[/tex]

Replacing the current (I) into Kirchhoff's loop rule, we have:

[tex]\mathbf{ L\dfrac{d}{dt} ( \dfrac{dq}{dt})= -\dfrac{q}{c}}[/tex]

[tex]\mathbf{ \dfrac{d^2q}{dt^2}= -\dfrac{q}{Lc} \ \ ---(1)}[/tex]

From the given question, when the switch is closed

[tex]\mathbf{ \dfrac{d^2q}{dt^2}= -kq\ \ ---(2)}[/tex]

Then, the charges on the capacitor start to b, resulting in the rise of the current in the circuit.

By equating both equations (1) and (2);

[tex]\mathbf{K = \dfrac{1}{LC}}[/tex]

Learn more about Kirchhoff's loop rule here:

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A and E are wrong i think please solve this thank you.

Answers

Answer:

I think number 3.

Explanation:

Calculate the altitude above the surface of Earth, in meters, at which the acceleration due to gravity is g

Answers

Answer:

By definition the acceleration due to gravity at the surface is g:

The altitude above the surface is zero for an acceleration of g.

Throwing all over the place will___________the environment.​

Answers

Answer:

pollute the environment

What is gravitation ? ​

Answers

Explanation:

1. Movement, or a tendency to move, toward a center of gravity, as in the falling of bodies to the earth.

2. Movement toward or attraction to something.

"a tentative gravitation toward the prices that we saw before the announcement"

How much force is required to raise a 0.2 kg mass?

Answers

Answer:

1.96 N

Explanation:

⇒This is your full answer

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