Radon-222 3.8 days

How many half lives have occurred if 12.5% of Rn-222 remains?

I need someone to explain how you do this to me?

Answers

Answer 1

3 half-lives have occured

Further explanation

Given

Half-life Radon-222 = 3.8 days

12.5% of Rn-222 remains

Required

Half-lives  occurred

Solution

General formulas used in decay:  

[tex]\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}[/tex]

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

12.5% of Rn-222 remains ⇒ Nt/No = 0.125

Input the value :

[tex]\tt 0.125=\dfrac{1}{2}^{t/3.8}\\\\\dfrac{1}{2}^3=\dfrac{1}{2}^{t/3.8}\\\\3=t/3.8\\\\t=11.4\rightarrow 3~half-lives[/tex]


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Answers

Answer:

B. Gradualism

Explanation:

A pan containing hot water is left on the counter and becomes cool mainly due to....
A. water molecules moving apart.
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Answers

Answer:

C. heat from the water moving through the cooler air  

I think it's C because when something cools down, it has to reach a point of thermal equilibrium with the matter (in this case air) around it. So heat transfer happens through convection from the heat in the pan to the cooler surrounding air. The heated air becomes less dense and rises, while cooler air, sinks to the surface of the water, gets heated, and rises. This convection cycle keeps happening until the water in the pan is around the same temperature with the air around it.

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