range of the function f(x) = -x^2 - 5

STEP

1

:

           5

Simplify   —

           4

Equation at the end of step

1

:

  1          5

 (— +  a) -  —  = 0

  3          4

STEP

2

:

           1

Simplify   —

           3

Equation at the end of step

2

:

  1          5

 (— +  a) -  —  = 0

  3          4

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1   Adding a whole to a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        a     a • 3

   a =  —  =  —————

        1       3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1 + a • 3     3a + 1

—————————  =  ——————

    3           3  

Equation at the end of step

3

:

 (3a + 1)    5

 ———————— -  —  = 0

    3        4

STEP

4

:

Calculating the Least Common Multiple :

4.1    Find the Least Common Multiple

     The left denominator is :       3

     The right denominator is :       4

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

3 1 0 1

2 0 2 2

Product of all

Prime Factors  3 4 12

     Least Common Multiple:

     12

Calculating Multipliers :

4.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions :

4.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (3a+1) • 4

  ——————————————————  =   ——————————

        L.C.M                 12    

  R. Mult. • R. Num.      5 • 3

  ——————————————————  =   —————

        L.C.M              12  

Adding fractions that have a common denominator :

4.4       Adding up the two equivalent fractions

(3a+1) • 4 - (5 • 3)     12a - 11

————————————————————  =  ————————

         12                 12  

Equation at the end of step

4

:

 12a - 11

 ————————  = 0

    12  

STEP

5

:

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 12a-11

 —————— • 12 = 0 • 12

   12  

Now, on the left hand side, the  12  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  12a-11  = 0

Solving a Single Variable Equation:

5.2      Solve  :    12a-11 = 0

Add  11  to both sides of the equation :

                     12a = 11

Divide both sides of the equation by 12:

                    a = 11/12 = 0.917

a = 11/12 = 0.917

Answer:

11/12

Step-by-step explanation:

You want to subtract 5/4 minus 1/3 but you cant so you have to find the greatest denominator first which would be 12 because 3x4=12.

Since you multiplied 4x 3 to get 12 then you will multiply the 5 by 3 and the 1 by 4 to get this -> 5/4= 15/12     1/3= 4/12

Then subtract 15/12- 4/12= 11/12

a=11/12

[tex]\begin{cases} x = -4\implies &x+4=0\\ x=-5\implies &x+5=0\\ x = 0\implies &x=0\\ x=\frac{1}{3}\implies &x -\frac{1}{3}=0\\ &3\left( x -\frac{1}{3} \right)=3(0)\\ &3x-1=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x+4)(x+5)(x)(3x-1)=\stackrel{\textit{original equation}}{0} \\\\\\ (x^2+9x+20)(x)(3x-1)=y\implies (x^3+9x^2+20x)(3x-1)=y \\\\\\ (3x^4+27x^3+60x^2)+(-x^3-9x^2-20x)=y[/tex]

[tex]3x^4+27x^3+60x^2-x^3-9x^2-20x=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 3x^4+26x^3+51x^2-20x=y~\hfill[/tex]

Answer:

3/1

Step-by-step explanation:

rise/run

9514 1404 393

Answer:

  3

Step-by-step explanation:

The line goes through the origin (0, 0) and point (1, 3), which is 3 units up and 1 to the right of the origin.

  slope = rise/run = 3/1 = 3

The slope of the line is 3.

Answer:

The leverage of an observation is determined by how far the values of the independent variables are from their means.

Answer:

it would take 4 dollars to get one pint. if that's what your asking.

Step-by-step explanation:

divide 12 by 3 or multiply 3 by 4 which gives you 12. your answer is 4 if i understand correctly.

Answer: second one is the correct answer

Step-by-step explanation:

Using the probability table, it is found that:

a) There is a 0.25 = 25% probability that this couple spends 45 dollars or more.

b) The expected amount the couple actually has to pay is $36.85.

From the table, the probabilities of each total cost are:

[tex]P(X = 30) = P(X = 15|Y = 15) = 0.2[/tex]

[tex]P(X = 35) = P(X = 15|Y = 20) + P(X = 20|Y = 15) = 0.15 + 0.15 = 0.3[/tex]

[tex]P(X = 40) = P(X = 15|Y = 25) + P(X = 20|Y = 20) + P(X = 25|Y = 15) = 0.05 + 0.15 + 0.05 = 0.25[/tex]

[tex]P(X = 45) = P(X = 20|Y = 25) + P(X = 25|Y = 20) = 0.1 + 0.1 = 0.2[/tex]

[tex]P(X = 50) = P(X = 25|Y = 25) = 0.05[/tex]

Item a:

This probability is:

[tex]P(X \geq 45) = P(X = 45) + P(X = 50) = 0.2 + 0.05 = 0.25[/tex]

There is a 0.25 = 25% probability that this couple spends 45 dollars or more.

Item b:

The expected value is the sum of each outcome multiplied by it's respective probability.

Hence:

[tex]E(X) = 0.2(30) + 0.3(35) + 0.25(40) + 0.9[0.2(45) + 0.05(50)] = 36.85[/tex]

The expected amount the couple actually has to pay is $36.85.

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Answer:

is there a question asked or no?

Answer:

D

Step-by-step explanation:

I know this is super late and you probably don't need this, but for anyone who needs it, here is the answer!
Answer:

D and C

Step-by-step explanation:

We are doing the elimination method. We are subtracting so we can eliminate the x variable
 x + y = 8
- (x - y = 2)
---------------------
0x + 2y = 6
(0x is there just to show that x is eliminated but the equation is now just 2y = 6)
now solve for y (divide 2 on both sides)
y = 3

Now we can use Y to find x. Use any equation (either x + y = 8 or x - y = 2) and then plug in the y value.

x - 3 = 2.

Add 3 on both sides and you get
x = 5

Now! From the question we see that x is canoe speed and y is water current speed. And since x is 5 and y is 3, the answer is D and C since the water current is 3 and canoe speed is 5. Hope this helps!!

Answer:

The answer is 60 and 80

Step-by-step explanation:

Given that

The cost of 1 m ribbon = Rs.75

The cost of 7/5 m ribbon

→ (7/5)×75

→ (7×75)/5

→7×15

→₹ 105

The cost of 7/5 m ribbon is ₹105.

Answer:

the first one is true

Step-by-step explanation:

√36>5 = 6>5

7<√10 = 7<3.162

√9>√25 = 3>5

Therefore, the first one is correct

Answer:

y = 3x - 7

Step-by-step explanation:

For an equation in the format y = ax + b, a is the slope and b is the y intercept.

Answer:

A. exponential growth or decay function is a function that grows or shrinks at a constant percent growth rate. The equation can be written in the form f(x) = a(1 + r)x or f(x) = abx where b = 1 + r. ... r is the percent growth or decay rate, written as a decimal, b is the growth factor or growth multiplier.

Answer:4.1 i think correct if im worng sorry

Step-by-step explanation:

Answer:

x = 146°

Step-by-step explanation:

this shape is a rhombus and one property is that adjacent angles are supplementary

therefore, 'x' + 34 = 180

'x' = 180-34

'x' = 146

Answer:

True

Step-by-step explanation:

For instance, twins are born on the same day but imagine ten people instead of two being born on the same day.

Answer:

[tex]5x^2 - 4[/tex]

Step-by-step explanation:

For shifted down a function you have to follow the next structured:

[tex]f(x) - c[/tex]

In our case is:

[tex]x^2 - 4[/tex]

Now for compressed or shrink a graph you have to multiply by a factor in the input something like this:

[tex]f(cx)[/tex]

In our case is:

[tex]5x^2[/tex]

Maybe you can think, why 5 and not [tex]\frac{1}{5}[/tex] instead?. Well, when you multiply by [tex]\frac{1}{5}[/tex] this dilate or stretch the graft because the output of each value is smaller, example:

[tex]f(x) = x^2\\g(x) = \frac{1}{5} x^2[/tex]

Then evaluate for a number, for example 5:

[tex]f(5) = 25\\g(5) = 5[/tex]

the output of [tex]g(x)[/tex] is 5 steps a far from the answer of [tex]f(x)[/tex] this in a graph is illustrate as a stretching.

So the opposite happen when you multiply by a integer number, the graph is compressed because the output take the "faster steps".

So combine the two transformation and get [tex]5x^2 - 4[/tex]

Answer:

67 i thing so if it wrong sorry and ill answer  it again ight

Step-by-step explanation:

Answer:

B. y = 3x^2 + 3x - 3

Step-by-step explanation:

Find the function rule.

y = 3 x ^2 + 3 x − 3

\table[[x,y],[-1,-3],[0,-3],[3,33]]

The quadratic function to model the values in the table is,

⇒ y = 3x² + 3x - 3

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The values of x and y in the table are,

⇒ x = - 1, 0, 3

⇒ y = - 3, - 3, 33

Now, We know that;

The standard form of the quadratic equation is,

⇒ y = ax² + bx + c

Put x = - 1, y = - 3;

⇒ - 3 = a (- 1)² + b (- 1) + c

⇒ - 3 = a - b + c  .. (i)

Put x = 0, y = - 3;

⇒ - 3 = a (0)² + b (0) + c

⇒ - 3 = c

Put x = 3, y = 33;

⇒ 33 = a (3)² + b (3) + c

⇒ 33 = 9a + 3b - 3

⇒ 36 = 9a + 3b

⇒ 36/3 = 3a + b

⇒ 3a + b = 12  .. (ii)

From (i);

⇒ - 3 = a - b + c

⇒ - 3 = a - b - 3

⇒ a - b = 0 .. (iii)

Solve for (i) and (iii), we get;

⇒ a = 3, b = 3

Hence, The quadratic function to model the values in the table is,

⇒ y = ax² + bx + c

⇒ y = 3x² + 3x - 3

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Answer:

1234567891011121314151617181920

Answer:

He saved $143.00

Step-by-step explanation:

$650 x .22= 143

Answer: the difference if that 5.4 is not a negative number they are relatied because it takes them both 5.4 ,3 moves to get to 0

Step-by-step explanation:

Answer:

A Obtuse, B Acute, C Right        I think its right

Step-by-step explanation:

The dimensions for the plot that would enclose the most area are a length and a width of 125 feet.

In this question we shall use the first and second derivative tests to determine the optimal dimensions of a rectangular plot of land. The perimeter ([tex]p[/tex]), in feet, and the area of the rectangular plot ([tex]A[/tex]), in square feet, of land are described below:

[tex]p = 2\cdot (w+l)[/tex] (1)

[tex]A = w\cdot l[/tex] (2)

Where:

In addition, the cost of fencing of the rectangular plot ([tex]C[/tex]), in monetary units, is:

[tex]C = c\cdot p[/tex] (3)

Where [tex]c[/tex] is the fencing unit cost, in monetary units per foot.

Now we apply (2) and (3) in (1):

[tex]p = 2\cdot \left(\frac{A}{l}+l \right)[/tex]

[tex]\frac{C}{c} = 2\cdot (\frac{A}{l}+l )[/tex]

[tex]\frac{C\cdot l}{c} = 2\cdot (A+l^{2})[/tex]

[tex]\frac{C\cdot l}{c}-2\cdot l^{2} = 2\cdot A[/tex]

[tex]\frac{C\cdot l}{2\cdot c} - l^{2} = A[/tex] (4)

We notice that fencing costs are directly proportional to the area to be fenced. Let suppose that cost is the maximum allowable and we proceed to perform the first and second derivative tests:

FDT

[tex]\frac{C}{2\cdot c}-2\cdot l = 0[/tex]

[tex]l = \frac{C}{4\cdot c}[/tex]

SDT

[tex]A'' = -2[/tex]

Which means that length leads to a maximum area.

If we know that [tex]c = 8[/tex] and [tex]C = 4000[/tex], then the dimensions of the rectangular plot of land are, respectively:

[tex]l = \frac{4000}{4\cdot (8)}[/tex]

[tex]l = 125\,ft[/tex]

[tex]A = \frac{(4000)\cdot (125)}{2\cdot (8)} -125^{2}[/tex]

[tex]A = 15625\,ft^{2}[/tex]

[tex]w = \frac{15625\,ft^{2}}{125\,ft}[/tex]

[tex]w = 125\,ft[/tex]

The dimensions for the plot that would enclose the most area are a length and a width of 125 feet.

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Given equation

[tex]\\ \sf\longmapsto 42=6b[/tex]

[tex]\\ \sf\longmapsto 6b=42[/tex]

[tex]\\ \sf\longmapsto b=\dfrac{42}{6}[/tex]

[tex]\\ \sf\longmapsto b=7[/tex]

Option D

Answer:

4.30 naira

Step-by-step explanation:

Splitting in half, we have that they both get 3.60 naira each. Adding 70 kobo to 3.60 naira, we have 4.30 naira. Since we need Tayo's share to be 70 kobo more than Bisi's, we give Tayo the bigger share and the left cash to Bisi (2.90 naira).

Tayo will get 3.95 more than the naira of the given shares.

In mathematics, an expression is a combination of numbers, variables, and operators (such as addition, subtraction, multiplication, and division) that can be evaluated to obtain a value.

Let's call the amount that Visit gets "x".

According to the problem, Tayo gets 70 kobos (0.70 nairas) more than Visit. So, Tayo gets:

x + 0.70

The total amount of money shared between them is 7.20 naira. So, we can set up an equation:

x + (x + 0.70) = 7.20

Simplifying this equation, we get:

2x + 0.70 = 7.20

Subtracting 0.70 from both sides, we get:

2x = 6.50

Dividing both sides by 2, we get:

x = 3.25

To find out how much Tayo gets, we can use the equation we came up with earlier:

x + 0.70

Substituting x = 3.25, we get:

3.25 + 0.70 = 3.95

Therefore, Tayo will get 3.95 more than the naira.

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Answer:

564x2=1128 men

Step-by-step explanation:

Answer:

there are1139 women are working in the factory