Answer:
Step-by-step explanation:
Hello!
Given the data for the variables:
Y: Selling price of a house on the shore of Tawas Bay
X₁: Number of bathrooms of a house on the shore of Tawas Bay.
X₂: Square feet of a house on the shore of Tawas Bay.
X₃: Number of bedrooms of a house on the shore of Tawas Bay.
The multiple regression model is Y= α + β₁X₁ + β₂X₂ + β₃X₃ + εi
a. Using software I've entered the raw data and estimated the regression coefficients:
^α= a= -5531.01
Represents the mean selling price of the houses when 0 bathrooms, 0 square feet and 0 bedrooms.
^β₁= b₁= -1386.21
Represents the modification of the mean selling price of the houses when the number of bathrooms increases in one unit and the square feet and number of bedrooms remain unchanged.
^β₂= b₂= 60.28
Represents the modification of the mean selling price of the houses when the square feet increase in one unit and the number of bathrooms and bedrooms remain unchanged.
^ β₃= b₃= 54797.08
Represents the modification of the mean selling price of the houses when the number of bedrooms increase in one unit and the number of bathrooms and square feet of the houses remain unchanged.
^Y= -5531.01 -1386.21X₁ + 60.28X₂ + 54797.08X₃
b)
R²= 0.55
R²Aj= 0.49
The coefficient of determination gives you an idea of how much of the variability of the dependent variable (Y) is due to the explanatory variables. Each time you add another explanatory variable to the regression the coefficient increases regarding of real contribution of the new variable. This could lead to thinking (wrongly) that the new variables are good to explain the dependent variable.
The adjusted coefficient of determination is a correction made to the raw coefficient of determination to have a more unbiased estimation of the effect the independent variables have over the dependent variable.
⇒ As you can see both coefficient are around 50%, which means that these explanatory variables
c)
The standard error estimate, this is the estimate of the population variance of the errors. In the ANOVA is represented by the Mean Square of the errors (MME)
Se²= MME= 3837640577.01
Se= 61948.6931
d) and f)
For the hypotheses tests for each slope the t- and p-values are:
α: 0.05
β₁: [tex]t_{H_0}= \frac{b_1-\beta_1 }{Sb_1}[/tex] t= -0.06; p-value: 0.9528 ⇒ Do not reject H₀, the test is not significant.
β₂: [tex]t_{H_0}= \frac{b_2-\beta_2 }{Sb_2}[/tex] t= 2.56; p-value: 0.0180 ⇒ Reject H₀, the test is significant.
β₃: [tex]t_{H_0}= \frac{b_3-\beta_3 }{Sb_3}[/tex] t= 2.28; p-value: 0.0326 ⇒ Reject H₀, the test is significant.
e)
H₀: β₁= β₂= β₃
H₁: At least one βi is different from the others ∀ i=1, 2, 3
α: 0.05
F= 9.03
p-value: 0.0004
⇒ Reject H₀, the test is significant.
I hope it helps!
NOT SURE NEED HELP PLEASE
Answer:
bh
6, 17
102
51
Step-by-step explanation:
Answer:
1/2 (bh)
1/2(17)(6)
51
round 3, 942,588 to the nearest thousand
Answer:
3, 943,000
Step-by-step explanation:
3, 942,588
The 2 is in the thousands place
We look at the hundreds place
There is a 5, that means we round up
2 becomes a 3
3, 943,000
Peter, Gordon and Gavin share £36 in a ratio 2:1:1. How much money does each person get?
Answer:
Peter gets 18£
Gordon and Gavin each get 9£
Answer:
peter = 18 Gordon = 9 Gavin = 9
Step-by-step explanation:
2+1+1 = 4
36 div 4 = 9
2 times 9 = 18
1 times 9 = 9
The answer and how to solve it.
Answer:
B
Step-by-step explanation:
1. Determine the value of 'p' in the equation 4p = 48
2. Simplify the fraction 60/144
3. What is the surface area of a cube with side lengths of 3cm?
1) sorry i don't know =(
2)- 5/12 is the simplified fraction for 60/144.
3)A=54cm²
Which of the following expressions represents "the sum of n and the sum of 8 and 6"? n(8 + 6) n + (8 + 6) (n + 6)8
which one of the following solids produces these two-dimensional shape when sliced horizontally?
Answer:
D
Step-by-step explanation:
5. The value of 25sqare -24sqare
Answer:
49
Step-by-step explanation:
25²-24²
625-576
=49
use calculator lah dehh
A county real estate appraiser wants to develop a statistical model to predict the appraised value of houses in a section of the county called East Meadow. One of the many variables thought to be an important predictor of appraised value is the total number of rooms in the house. Consequently the appraiser decided to fit the simple linear regression model, ^y=β0+β1x , where y= the appraised value of the house (in thousands of dollars) and x= the number of rooms. Using data collected for a sample of n = 74 houses in East Meadow, the following results were obtained:
Answer:
Step-by-step explanation:
Hello!
The statistical model predicts the appraised value of houses in a section of the county East Meadow (Y) in relationship with the number of rooms of the house (X)
For a sample of n=64 houses the simple linear regression was estimated:
^Y= 74.80 + 24.93X
Range of X: 5 - 11
Range of Y: 160 - 300 ($ thousands of dollars)
Interpretation of the estimates of the y-intercept and the slope
y-intercept:
74.80 thousand dollars is the estimated average value of a house in a section of the county East Meadow when the house has zero rooms.
Slope:
24.93 [tex]\frac{thousand dollars}{rooms}[/tex] is the modification of the estimated average value of a house in a section of the county East Meadow when the number of rooms increases on one.
I hope this helps!
What is the value of -(3/4) to the power of -4
The answer would be -3 13/81 (simplified)
Martin wants to use coordinate geometry to prove that the opposite sides of
a rectangle are congruent. He places parallelogram ABCD in the coordinate
plane so that A is (0,0), B is (a,0), Cis (a, b), and Dis (0, b).
What formula can he use to determine the distance from point D to point A?
Answer:
Option (B)
Step-by-step explanation:
Coordinates of the vertices of the rectangle were A(0, 0), B(a, 0), C(a, b) and D(0, b)
Formula to determine the distance between two points with the vertices (x, y) and (x', y') is,
d = [tex]\sqrt{(x-x')^2+(y-y')^2}[/tex]
For the length of AD,
AD = [tex]\sqrt{(0-0)^2+(b-0)^2}[/tex]
= [tex]\sqrt{b^2}[/tex]
= b
Therefore, Option (B) will be the answer.
The Hartnett Corporation manufactures baseball bats with Pudge Rodriguez's autograph stamped on them. Each bat for $35 and has a variable cost of $22. there are $97,500 in fixed costs involved in the production process.
Find the sales (in units) needed to earn a profit of $300,000.
Answer:
Find the sales (in units) needed to earn a profit of $262,500
Step-by-step explanation:
hope this is helpful to you bro
What’s the correct answer for this question? Select all that Apply
Answer:
B and G
Step-by-step explanation:
Square and rectangle
3(5 − 2 x) = −2(6 – 3 x) − 10 x
Answer:
15-6x= -12-4x
15-2x= -12
-2x= -27
x= -13.5
Step-by-step explanation:
A baseball player comes up to bat 3 times during a league game. He either gets a hit or gets an out. What is the probability that the player gets 3 hits in the three bats ?
Answer:
Since there are 2 possibilities for each bat (hit or out), the amount of total possibilities is 2 * 2 * 2 = 8. There is only one possibility out of those eight that gives us three hits, therefore the probability is 1 / 8 or 0.125.
Find the function y1 of t which is the solution of 121y′′+110y′−24y=0 with initial conditions y1(0)=1,y′1(0)=0. y1= Note: y1 is a linear combination of the two independent solutions of this differential equation that you found first. You are not being asked for just one of these. You will need to determine the values of the two constant parameters c1 and c2. Similarly for finding y2 below. Find the function y2 of t which is the solution of 121y′′+110y′−24y=0 with initial conditions y2(0)=0,y′2(0)=1. y2= Find the Wronskian W(t)=W(y1,y2). W(t)= Remark: You can find W by direct computation and use Abel's theorem as a check. You should find that W is not zero and so y1 and y2 form a fundamental set of solutions of 121y′′+110y′−24y=0.
Answer:
Step-by-step explanation:
The original equation is [tex]121y''+110y'-24y=0[/tex]. We propose that the solution of this equations is of the form [tex] y = Ae^{rt}[/tex]. Then, by replacing the derivatives we get the following
[tex]121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)[/tex]
Since we want a non trival solution, it must happen that A is different from zero. Also, the exponential function is always positive, then it must happen that
[tex]121r^2+110r-24=0[/tex]
Recall that the roots of a polynomial of the form [tex]ax^2+bx+c[/tex] are given by the formula
[tex] x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}[/tex]
In our case a = 121, b = 110 and c = -24. Using the formula we get the solutions
[tex]r_1 = -\frac{12}{11}[/tex]
[tex]r_2 = \frac{2}{11}[/tex]
So, in this case, the general solution is [tex]y = c_1 e^{\frac{-12t}{11}} + c_2 e^{\frac{2t}{11}}[/tex]
a) In the first case, we are given that y(0) = 1 and y'(0) = 0. By differentiating the general solution and replacing t by 0 we get the equations
[tex]c_1 + c_2 = 1[/tex]
[tex]c_1\frac{-12}{11} + c_2\frac{2}{11} = 0[/tex](or equivalently [tex]c_2 = 6c_1[/tex]
By replacing the second equation in the first one, we get [tex]7c_1 = 1 [/tex] which implies that [tex] c_1 = \frac{1}{7}, c_2 = \frac{6}{7}[/tex].
So [tex]y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}[/tex]
b) By using y(0) =0 and y'(0)=1 we get the equations
[tex] c_1+c_2 =0[/tex]
[tex]c_1\frac{-12}{11} + c_2\frac{2}{11} = 1[/tex](or equivalently [tex]-12c_1+2c_2 = 11[/tex]
By solving this system, the solution is [tex]c_1 = \frac{-11}{14}, c_2 = \frac{11}{14}[/tex]
Then [tex]y_2 = \frac{-11}{14}e^{\frac{-12t}{11}} + \frac{11}{14} e^{\frac{2t}{11}}[/tex]
c)
The Wronskian of the solutions is calculated as the determinant of the following matrix
[tex]\left| \begin{matrix}y_1 & y_2 \\ y_1' & y_2'\end{matrix}\right|= W(t) = y_1\cdot y_2'-y_1'y_2[/tex]
By plugging the values of [tex]y_1[/tex] and
We can check this by using Abel's theorem. Given a second degree differential equation of the form y''+p(x)y'+q(x)y the wronskian is given by
[tex]e^{\int -p(x) dx}[/tex]
In this case, by dividing the equation by 121 we get that p(x) = 10/11. So the wronskian is
[tex]e^{\int -\frac{10}{11} dx} = e^{\frac{-10x}{11}}[/tex]
Note that this function is always positive, and thus, never zero. So [tex]y_1, y_2[/tex] is a fundamental set of solutions.
What is the measure of angle L in parallelogrami LMNO?
20°
30°
40°
50°
Answer:
40°
Step-by-step explanation:
2x = 3x - 20 add like terms
x = 20 and angle l is equal to 3x minus 20 so 3 × 20 - 20 = 40°
During the late 1980s and the early 1990s the Pepsi Challenge was in full swing. During the challenge, participants were asked to taste cola from both Coke and Pepsi. Once they had tasted both drinks, the participants were asked to report which was better tasting. The results indicated that participants found Pepsi products to be better tasting. What is the dependent variable in this study? coruse hero psyc 255
Answer:
Taste
Step-by-step explanation:
In the challenge, participants were asked to taste cola from both Coke and Pepsi. They were to give a report on which of the two drinks tasted better.
The taste reported by the participants is dependent on the type of cola taken (either Coke or Pepsi).
Therefore, the taste is the dependent variable while the types of cola are the independent variables.
Express the following ratio in it’s simplest form.
25:30
Answer:
5/6
Step-by-step explanation:
Find the factor that divides both numbers...
25/5=5
30/5=6
5/6 is the simplified ratio
P.S. Please give me brainliest, i have only have two!
Answer:
1/3:1/4
Step-by-step explanation:
203/259
write in simplest form
2 hours to 45 seconds
Express ratio
15:1
simplest form
1/3:1/4
The histogram to the right represents the weights (in pounds) of members of a certain high-school debate team. What is the class width? What are the approximate lower and upper class limits of the first class? The class width is_______.
Answer:
Class width = 20
Approximate lower class limit of the first class = 110
Approximate Upper class limit of the first class = 119
Step-by-step Explanation:
The class width of the histogram attached below can be gotten by finding the difference between successive lower class limits.
Thus, class width = 130 - 110 = 20
The approximate lower class limit of the first class is the lowest score we have in the first class = 110
The approximate upper class limit of the first class is the closest highest score that fall within the first class and is below the lower limit of the second class. Thus approximate upper class limit of the first class = 129
Simplify 4^3•4^5.
help asap !
Answer:
D
Step-by-step explanation:
when there are exponents with same bases multiplied by each other, keep the base and add the exponents
4^(3)+4^(5)=4^8
4^8 is D in this question
What is the range of the function in the table
X Y
1 2
2 4
3 3
4 2
A) (1,2,3,4)
B) (1,2) (2,4) (3,3) (4,2)
C) (1,2)
D) (2,3,4)
Answer:
D. (2, 3, 4)
Step-by-step explanation:
The range is the y values. The y values, in numerical order, range from 2 to 4. The 2s do not need to be repeated.
Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!
Answer:
-1, 1
13, 15
Step-by-step explanation:
x and x+2 are the integers
x*(x+2)= 7(x+x+2) -1x²+2x= 14x+14-1x² - 12x -13= 0Roots of the quadratic equation are: -1 and 13.
So the integers pairs are: -1, 1 and 13, 15
A company makes candles in the shape of a right cone. The lateral surface of each candle is covered with paper for shipping and each candle also has a plastic circular base. Find the amount of paper needed to cover the lateral surface of each candle. Then find the total amount of paper and plastic needed for the candle. Round to the nearest tenth. Use 3.14 for π.
Answer:
If we have a cone-shape candle with r=2 cm and h=3 cm, then the amount of paper needed is 18.84 cm^2 and the amount of plastic needed is 12.56 cm^2.
Step-by-step explanation:
The question is incomplete: no numerical values for the dimensions of the cone are given.
A right cone is defined by the radius r of the base and the height h.
The base area is the area of a circle with radius r:
[tex]A_b=\pi r^2[/tex]
The lateral area is calculated as:
[tex]A_l=\pi \cdot r\cdot l[/tex]
As the values for r and h are not given, we will use an example with r=2 and h=3.
Then, the amount of paper needed is:
[tex]A_l=\pi \cdot r\cdot l=3.14\cdot (2\,cm)\cdot (3\, cm)=18.84\,cm^2[/tex]
The amount of plastic needed is:
[tex]A_b=\pi r^2=3.14\cdot (2\,cm)^2=3.14\cdot 4\,cm^2=12.56\,cm^2[/tex]
If a line crosses the y-axis at (0,1) and has a slope of 4/5 what is the equation of the line
Answer:
y = 4/5x + 1
Step-by-step explanation:
y = mx + b
m = slope
b = y-intercept
y = 4/5x + 1
Answer:4y-5x=5
Step-by-step explanation:
Two forces of magnitudes 16 and 20 pounds are acting on an object. The bearings of the forces are N75E and S20E (that is, 75∘ east of north and 20∘ east of south), respectively. How many degrees east of south is the resultant force? (Round to two decimal places and do not enter the ∘ symbol.)
Answer:
20.58
Step-by-step explanation:
Force A = 16 pounds
direction = N75E = 75° in the first quadrant
Force B = 20 pounds
direction = S20E = 180° - 20° = 160° in the fourth quadrants
we resolve the forces into their x and y resultant forces.
For the y axis forces,
-(16 x sin 75°) + (20 x sin 160°) = Fy
-15.45 + 6.84 = Fy
Fy = -8.61 N
For the x axis forces'
(16 x cos 75°) + (20 x cos 160°) = Fx
-4.14 - 18.79 = Fx
Fx = -22.93 N
Resultant force = [tex]\sqrt{(Fx)^{2} + (Fy)^{2} }[/tex] = [tex]\sqrt{(-8.61)^{2} + (-22.93)^{2} }[/tex]
Resultant force = 24.49 N
angle made by the resultant force is,
∅ = [tex]tan^{-1}[/tex] [tex]\frac{Fy}{Fx}}[/tex]
∅ = [tex]tan^{-1}[/tex] [tex]\frac{-8.61}{-22.93}}[/tex]
∅ = [tex]tan^{-1}[/tex] 0.3755
∅ = 20.58
resuelve las siguientes ecuaciones tales que 0° ≤ x ≤ 360°
sen x=sen (π/2-x)
cos x + 2 sen x= 2
csc x = sec x
2 cos x * tan x -1 = 0
4 cos2 x = 3 - 4 cos x
Answer:
4cos=2X
X=3-4COS
X=-1
11. A square with sides
3/8
inch has a total area of:
Answer:
[tex](\frac{3}{8}\,in )^2=\frac{9}{64} \,in^2=0.140625\,\,i^2[/tex]
Step-by-step explanation:
Recall that the formula for the area of a square of side L is: [tex]Area=L^2[/tex]
Therefore, for this case:
[tex]Area=L^2\\Area = (\frac{3}{8} \,in)^2\\Area=\frac{9}{64} \,\,in^2\\Area=0.140625\,\,in^2[/tex]
Multiply or divide as indicated x^10/x^4
Answer:
X^6
Step-by-step explanation:
What’s the correct answer for this question?
Answer:
C:
Step-by-step explanation:
In a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc
So
AQD = ARC AD/2
<AQD = 78/2
<AQD = 39°
