Recent findings lend strong support to the theory that a black hole lies at the center of the Milky Way and of many of the 100 billion other galaxies estimated to exist in the universe.
(A) that a black hole lies at the center of the Milky Way and of
(B) that a black hole lies at the Milky Way's center and
(C) that there is a black hole lying at the Milky Way’s center and
(D) of a black hole lying at the Milky Way's center and
(E) of a black hole that lies at the center of the Milky Way and of

Answers

Answer 1

Recent findings have revealed strong evidence amount for the theory that there is a black hole that lies at the center of the Milky Way and of many other galaxies in the universe.

Recent scientific studies have provided strong evidence for the theory that there is a black hole lying at the center of the Milky Way and of many other galaxies in the universe. This theory is supported by findings such as the detection of gravitational waves caused by the collision of two black holes, which is indicative of the existence of black holes in the universe. Additionally, the discovery of high-energy X-ray emissions from regions near the center of the Milky Way suggests the presence of a supermassive black hole. These findings, combined with other evidence, provide strong support for the theory that a black hole lies at the center of the Milky Way and of many other galaxies in the universe.

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Related Questions

Cual es la propiedad de 6÷1=6

Answers

propiedad de identidad

math hw pls fast, What is the similarity ratio of the dilation?

Answers

Answer: the ratio is 1/2

SOMEONE HELP ME QUICK I WILL GIVE BRAINLIEST

Answers

Answer: 1. 8, 2. 1680

Step-by-step explanation:

1. area is length times width, so 6 times 7 is 30. To find the missing one just do 40 divided by 5, which equals 8.

2. to find the total area do length x width x length x width. so 5 x 6 x 7 x 8 which equals 1680.

got ya nose
354 times 23

Answers

Answer:

8142

Step-by-step explanation:

Answer: 354x23=8142

because if you brake 300+50+4 and multiply 300x23, 50x23, and 4x23, then you get 8142

Which sequence shows the numbers in order from least to greatest? a) 7.2/3 < √65 < |-7.82| b) 7.2/3 < |-7.82| < √65
c. |-7.82| < √65 < 7.2/3
d. √65 < |-7.82| < 7.2/3

Answers

The sequence from least to greatest is d) √65 < |-7.82| < 7.2/3.

To calculate this, we first need to find the square root of 65, or √65. This can be done using the formula √a = b, where a is the number to be square rooted and b is the result of the square root. In this case, a = 65, so we calculate √65 = 8.062257748. Next, we need to find the absolute value of -7.82, which is |-7.82| = 7.82. . To calculate this, the absolute value formula is used, which is |x| = |x|. Finally, 7.2/3 is the greatest of the three numbers. To calculate this, first convert 7.2/3 to a decimal by dividing it by 3. Then divide 7.2 by the result to get the final answer.Finally, we find 7.2/3, which is equal to 2.4. Therefore, the sequence from least to greatest is √65 < |-7.82| < 7.2/3, or 8.062257748 < 7.82 < 2.4.

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SEE IMAGE!! PLS HELP ASAPP
Find the quotient. If possible, rename the quotient as a mixed number. Select the answer that is in simplest form.

2 3

4 ÷ 3 = ?
A.
7

12
B.
11

12
C.
3

4

Answers

Answer:11/12

Step-by-step explanation:

is 3x-2y=-5 & 3x-2y=8 parallel perpendicular intersecting but not perpendicular

Answers

If you solve 3x - 2y = -5 for slope-intercept form, you'd have:

     y = 3/2 x + 5/2

 

If you solve 3x - 2y = 8 for slope-intercept form, you'd have:

     y = 3/2 x - 4

Since the slopes are the same, but the y-intercepts are different, these lines are parallel.

From his eye, which stands 1.55 meters above the ground, Tyler measures the angle of elevation to the top of a prominent skyscraper to be 57^{\circ} ∘ . If he is standing at a horizontal distance of 112 meters from the base of the skyscraper, what is the height of the skyscraper? Round your answer to the nearest hundredth of a meter if necessary.

Answers

Answer:  ≈ 174.01

Thus, The Sky Scraper  ≈  174.01

Step-by-step explanation:

From his eye, which stands 1.55 meters above the ground, Tyler measures the angle of elevation to the top of a prominent skyscraper to be 57∘

∘. If he is standing at a horizontal distance of 112 meters from the base of the skyscraper, what is the height of the skyscraper? Round your answer to the nearest hundredth of a meter if necessary.

1 - Draw Diagrams, Label Knowns:

Unknowns: X

2 - Identify: OPPOSITE, ADJACENT, HYPOTENUSE

3 -  WHAT FUNCTION USES THE OPPOSITE AND THE ADJACENT?

SOH - CAH - TOA

NOW SHOWING WORK:

tan 57 = opposite/adjacent =  x/112

tan 57 = x/112

tan 57/1  = x/112

112 tan 57 = x         ( Cross Multiply)

x = 172.464875    (Now, type into the calculator)

So, Now we ADD:

1.55, the distance from the ground to his eye.

172.464875  +   1.55  =  174.014875

≈ 174.01     (Round to The Nearest HUNDREDTH)

Thus, the Sky Scraper is ≈ 174.01 meters tall.

So, your answer would be :  

Sky Scraper  ≈  174.01

Hope I have explained it and helped you in your studies!

The height of the skyscraper is given by H = 174.01 m

What are trigonometric relations?

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

We can start by drawing a right triangle, where the horizontal distance from Tyler to the base of the skyscraper is one leg, the height of the skyscraper is the other leg, and the line of sight from Tyler's eye to the top of the skyscraper is the hypotenuse.

Then we can use trigonometry to solve for the height of the skyscraper.

Let the height above the ground from his eye = 1.55 m

Now , the angle of elevation θ = 57°

The horizontal distance from the base of the skyscraper = 112 m

Now , from the trigonometric relations ,

tan θ = opposite / adjacent

So , tan 57° = x / 112

Multiply by 112 on both sides , we get

x = 172.46 m

Now , the total height of the skyscraper = 172.46m + 1.55 m

So , height H = 174.01 m

Hence , the skyscraper has a height of 174.01 m

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The weight gains of beef steers were measured over a 140 -day test period. The average daily gains (lb/day) of 9 steers on the same diet were as follows: 23
3.89 3.51 3.97 3.31 3.21 3.36 3.67 3.24 3.27
Determine the mean and median

Answers

The weight gains of beef steers were measured over a 140 -day test period .then mean is 3.545 and median is 3.435

Given

3.89 3.51 3.97 3.31 3.21 3.36 3.67 3.24 3.27

mean = 3.89+3.51+3.97+3.31+3.21+3.36+3.67+3.24+3.27 /10

= 35.45/10

= 3.545

average is the sum of all terms present in the question divided by the number of terms that is the way of calculating average

Solving (a): The mean = 3.545

This is calculated as:

median = 10+1 /2 term

 = 11/2

=5.5 term

So, we have:

median = 3.435

The weight gains of beef steers were measured over a 140 -day test period .then mean is 3.545 and median is 3.435

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What is the shape of the bases for the following polyhedron?
a. triangle
b. square
c.rectangle
d.circle

Answers

The shape of the bases for the following polyhedron depend on the type of polyhedron. For example, a triangular prism would have triangular bases, a square pyramid would have square bases, a rectangular prism would have rectangular bases, and a cone would have circular bases.

The shape of the bases for a polyhedron depend on the type of polyhedron. Polyhedra can have a variety of shapes, such as triangular, square, rectangular, and circular. For example, a triangular prism would have triangular bases, a square pyramid would have square bases, a rectangular prism would have rectangular bases, and a cone would have circular bases.

The shape of the bases for the following polyhedron depend on the type of polyhedron. For example, a triangular prism would have triangular bases, a square pyramid would have square bases, a rectangular prism would have rectangular bases, and a cone would have circular bases.

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find the slope of the line passing through points -1,5 and -5,7

Answers

Answer:

-1/2

Step-by-step explanation:

use slope formula

it'd be:

\frac{5-7}{-1+5} =\frac{-2}{4} =\frac{x}{y} -1/2\\

There are 31 players on the softball team. They are traveling to the District Championship in 8 cars. There are 4 players in each of the first 7 cars. How many players on the softball team are traveling in the eighth car?

Answers

Answer: 3 players

Step-by-step explanation: Hello! You know that there are 31 players on the softball team, there are 8 cars in total for everyone to drive in, and there are 4 players in each car for the first 7 cars.  What you have to find out is how many players are traveling in the eighth car.  The first thing that you want to know is how many players are already in the cars.  You already know that 4 players are in each of the 7 cars.  To know how many players are in the 7 cars, multiply the 4 players by the 7 cars.  4 x 7 = 28.  28 players are in the first 7 cars.  You know that there are 31 players in total.  To find the number of players in the last car, subtract the number of players in the first 7 cars from the total amount of players.  31 - 28 = 3.  There are 3 players on the softball team in the eighth car.  Hope this helps!

from the smith chart, find the normalized input admittances corresponding to the following normalized input impedances:

Answers

The normalized input admittances are the inverse of the normalized input impedances and can be found on the Smith Chart.

The Smith Chart is a graphical tool used to quickly calculate the reflection coefficient, impedance, admittance, and other characteristics of a transmission line. To find the normalized input admittances corresponding to the normalized input impedances, we first need to find the normalized reflection coefficient for the given normalized input impedances. This can be done by locating the given normalized impedance on the Smith Chart and then determining the normalized reflection coefficient from the radial and angular coordinates. Once the normalized reflection coefficient has been determined, the normalized input admittance can be found by using the formula Y = 1/Z. The normalized input admittance is then located on the Smith Chart in the same manner as the normalized input impedance, using the radial and angular coordinates.

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f(x) is a direct variation function f(3)= 12 f(x)= ? f(2)= ?

Answers

The function f(x) will be : f(x) = 4x and f(2) = 8.

What are algebraic expressions?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.

Given is that f(x) is a direct variation function .

Direct variation of {y} with {x} means that as {x} increases, {y} increases uniformly with it. Mathematically -

        {K} = y/x = constant

Scale factor {K} is a dimensionless value that indicates the constant ratio value indicating direct variation.

It is given that -

f(3) = 12

We can write the slope of f(x) as -

m = (12 - 0)/(3 - 0)

m = 12/3

m = 4

So, f(x) will be -

f(x) = 4x

and

f(2) will be -

f(2) = 8

Therefore, the function f(x) will be : f(x) = 4x and f(2) = 8.

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example 3
include critical numbers, sign chart , intervals of increasing / decreasing

show work and upload pics of work

include critical numbers, sign chart , intervals of increasing / decreasing

SHOW YOUR WORK

Answers

The critical points, sign chart and intervals of increase and decrease is plotted for the function f(x) = x³/4 - 3x.

Critical points - (−2,4) and (2,−4)

Interval of increase - (−∞,−2)∪(2,∞)

Interval of decrease - (-2,2)

What is a function?

In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.

A continuous function f with x in its domain has a critical point at that point xx if it satisfies either of the following conditions -

f'(x) = 0,

f'(x) is undefined

The given function is f(x) = x³/4 - 3x

So, f'(x) = 3x²/4 - 3

In the graph of the function, only two points are there on the graph where f'(x) = 0, which is -

(x,f(x))=(−2,4)

(x,f(x))=(2,−4)

A sign chart tells you when the value of a function f(x) is negative or positive, which is the same as when the graph of f(x) is below or above the x-axis, respectively.

Draw a solid line when the y-value of the function is greater than zero, which is when f(x)>0.

Draw a dashed line when the y-value of the function is less than zero, which is when f(x)<0.

In the graph it can be seen that the graph is below zero up to x = -3.464 and between x = 0 and x = 3.464. In these intervals the sign chart is dashed. The graph is above the x-axis between x = -3.464 and x = 0 and when x>3.464. In these areas the sign chart is solid.

In the graph it can be clearly seen that the graph is increasing from point -∞ up to -2 and from 2 to ∞.

Also in the graph it can be clearly seen that the graph is decreasing from point -2 up to 2 .

Therefore, the critical points, sign chart and intervals of increase and decrease is found.

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8th grade geometry
First box options are is, is not. And the second box options are will, will not.

Answers

i. The tangent ratio for ΔRBK is 16/ 38.4

ii. The tangent ratio for ΔHMK is 8/ 19.2

What is a tangent of an angle?

Trigonometric functions are set of functions that are applicable when the side or angle of a triangle is to be determined. Some basic trigonometric functions are: Sine, Cosine, Tangent etc.

The tangent of an angle relates its opposite side to the reference angle with the adjacent side to the same angle.

So that;

Tan θ = opposite/ adjacent

In the given question,

1. From ΔRBK, the tangent ratio is given as;

tan θ = opposite/ adjacent

            = RB/ BK

but BK = BM + MK

           = 19.2 + 19.2

          = 38.4

So that;

tan θ = 16/ 38.4

2. From ΔRBK, the tangent ratio is given as;

tan θ = opposite/ adjacent

        = HM/ MK

tan θ = 8/ 19.2

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When an employer asks for "how many years of basic math experience do you have" on an application do you include school years? If so how many?

Answers

Answer:

Step-by-step explanation:

When an employer asks for "how many years of basic math experience do you have" on an application, it is generally understood that they are asking for the amount of time you have spent working with basic math concepts in a professional setting. This would typically include time spent working in roles that required the use of basic math skills, such as data entry, accounting, or similar positions.

However, if you have no professional experience in a math-related field but you have studied math in school, you can mention that you have a certain number of years of education in math and that you are familiar with basic math concepts.

It's up to you how many years of math classes you want to include, but it's not necessary to include all the years you've studied math since primary school, it's better to just mention that you have a certain level of education in math, or give an estimate of the number of years that you have studied it in a higher level education like college or university.

It's important to be honest and transparent in your application, but also to highlight the skills and experience that make you a good fit for the role.

(07.01 mc) a coolant is injected into engine fluid, causing the temperature of the engine fluid to decrease with respect to time at a rate that is proportional to the difference of the fluid's instantaneous temperature, t, and the fluid's original temperature, to. select the differential equation that represents the relationship.

Answers

The differential equation that represents the relationship is

     dT/dt = - k * ( T - T0 ) from the condtion - dT/dt ∝ ( T - T0 ).

Given:

The engine fluid temperature rate of change, dT/dt

- dT/dt ∝ ( T - T0 )   [proportional to the difference of the fluid's instantaneous temperature, T, and the fluid's original temperature, T0.]

The Differential Equation that represents the relationship.

The framework is already set, there is only one thing that changes the proportionality to an equation. And that is a proportionality constant.

Let's call it 'k'

Since this is a directly proportional set up, the constant 'k' will be multiplied to the term of ( T - T0 )

                            - dT/dt = k * ( T - T0 )

And to make this look like a typical equation, multiply both sides by a -1 to get:

                           ∴ dT/dt = - k * ( T - T0 )

As expected, this comes to represent the same thermodynamic effect you'd see in Newton's Law of Cooling; it is expected because most of all fluids exhibit this cooling effect when interacting with other fluids of differing temperatures.

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Is this right? The equivalent of 8.55 in fraction form?

Answers

Answer:

[tex]\frac{171}{20}[/tex] is equal to 8.55

Step-by-step explanation:

[tex]\frac{171}{20}[/tex] in decimal form is 8.55

[tex]\frac{17}{2}[/tex] in decimal form is 8.5

[tex]\frac{55}{8}[/tex] in decimal form is 6.875

[tex]\huge\text{Hey there!}[/tex]

[tex]\textbf{Let us say:}[/tex]

[tex]\mathsf{8.55 \rightarrow \dfrac{8.55}{1}}[/tex]

[tex]\textbf{This method should make this question easier to solve (in some cases}\\\textbf{of course)}[/tex]

[tex]\mathsf{8.55 \rightarrow \dfrac{8.55}{1}}[/tex]

[tex]\mathsf{= \dfrac{8.55}{1}\times\dfrac{100}{100}}[/tex]

[tex]\mathsf{= \dfrac{8.55\times100}{1\times100}}[/tex]

[tex]\mathsf{= \dfrac{855}{100}}[/tex]

[tex]\mathsf{= \dfrac{855\div5}{100\div5}}[/tex]

[tex]\mathsf{= \dfrac{151}{21}\rightarrow 8 \dfrac{11}{20}}[/tex]

[tex]\huge\text{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{Option\ A. \ \dfrac{171}{20}}}\huge\checkmark[/tex][tex]\textsf{What you have chosen as the answer to this question is correct}\ \heartsuit[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The two-way table given shows the results from the lunch orders from an upperclassman barbecue.


11th Graders 12th Graders
Hamburger 72 39
Hotdog 65 24
Chicken Wings 23 27


A segmented bar chart was created showing the lunch preference by grade. What percent would the bar for 12th graders show for preferring chicken wings?

Answers

The percentage of 12th graders preferring chicken wings is 30%.

What is the percentage?

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

From the given information total number of 12th graders are,

(39 + 24 + 27)

= 90.

The number of 12th graders preferring chicken wings is 27.

Therefore, The percentage  bar for 12th graders shows for preferring chicken wings is,

= (27/90)×100%.

= 30%.

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A company's cereal boxes advertise 9.65 ounces of cereal. In fact, the amount of cereal in a randomly selected box follows a Normal distribution with meanμ=9.70μ=9.70ounces and standard deviationσ=0.03σ=0.03ounces. What is the probability that a randomly selected box of the cereal contains less than 9.65 ounces of cereal? Show your work.

Answers

The probability that a randomly selected box of the cereal contains less than 9.65 ounces of cereal is 0.4608.

The probability that a randomly selected box of the cereal contains less than 9.65 ounces of cereal is 0.4608.

P(x < 9.65) = P(Z < (9.65 - 9.70) / 0.03)

= P(Z < -0.17)

= 0.4608

The first step is to calculate the Z-score for 9.65 ounces. To calculate the Z-score, you subtract the mean (9.70 ounces) from the value (9.65 ounces) and then divide by the standard deviation (0.03 ounces). The Z-score in this case is -0.17. The next step is to use a Z-table to find the probability of a Z-score less than -0.17. The probability is 0.4608. Therefore, the probability that a randomly selected box of the cereal contains less than 9.65 ounces of cereal is 0.4608.

The probability that a randomly selected box of the cereal contains less than 9.65 ounces of cereal is 0.4608.

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Please help me please

Answers

Hong rode the scooter for 61 minutes.

What is the algebra?

Algebra is a branch of mathematics that deals with mathematical equations and their properties. It is a way to represent and solve problems using mathematical symbols, letters and numbers.

We can use algebra to solve for the number of minutes Hong rode the scooter. Let x be the number of minutes Hong rode the scooter.

We know that the total bill is the sum of the start fee and the per-minute fee.

So, we can set up the equation as:

Total bill = start fee + per-minute fee

In this case:

10.88 = 6 + (x * 0.08)

We can then solve for x by isolating it on one side of the equation:

10.88 = 6 + (x * 0.08)

10.88 - 6 = x * 0.08

4.88 = x * 0.08

x = 4.88 / 0.08

x = 61

So, Hong rode the scooter for 61 minutes.

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79=2x+3y solve for y

Answers

The results of the x-intercept and y-intercept results from above (39.5, 0) and (x1, y1) and (x2, y2) (0,26.333)

How to solve y?Here, we'll explain how to solve arithmetic issues with the formula 2x + 3y = 79 and offer answers.We'll start by figuring out the x-intercept and y-intercept of the equation 2x + 3y = 79 and then showing you the result.Then, we'll demonstrate how to obtain the coordinates for the graph plot for the equation 2x + 3y = 79 so that we may depict it on a graph.The slope of 2x + 3y = 79 will then be calculated and shown to you once we have solved 2x + 3y = 79 for both x and y.locate x-interceptWhere the graph veers off the x-axis is known as the x-intercept. We first set y1=0 and then solve for x to determine the x-intercept.

2x + 3y = 79

2x + 3(0) = 79

x1 = 39.5 y1 = 0

the y-intercept

Where the graph crosses the y-axis is known as the y-intercept. We first solve for y before setting x2=0 to determine the y-intercept.

2x + 3y = 79

2(0) + 3y = 79

y2 = 26.333

x2 = 0

To draw a straight line on a graph, you must get two graph points. The format for the plot coordinates is (x1,y1) and (x2,y2).

Thus, we can obtain the graph plots for 2x + 3y = 79 as follows using the results of the x-intercept and y-intercept results from above:

(39.5, 0) and (x1, y1) and (x2, y2) (0,26.333)

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The distribution of age for players of a certain professional sport is strongly skewed to the right with mean 26.8 years and standard deviation 4.2 years. Consider a random sample of 4 players and a different random sample of 50 players from the population. Which of the following statements is true about the sampling distributions of the sample mean ages for samples of size 4 and samples of size 50 ? A Both will be skewed to the right, and the mean for size 50 will be closer to 26.8 than the mean for size 4. B Both will be skewed to the right, and the standard deviation for size 50 will be closer to 4.2 than the standard deviation for size C. Both will be approximately normal, and the mean for size 50 will be closer to 26.8 than the mean for size D. Only the sampling distribution for size 4 will be approximately normal, and the standard deviation for both will be 4.2. E Only the sampling distribution for size 50 will be approximately normal, and the mean for both will be 26.8.

Answers

The true statement about the sampling distributions is: Both will be approximately normal, and the mean for size 50 will be closer to 26.8 than the mean for size 4.

Thus, option (C) is correct.

According to the Central Limit Theorem, for a large enough sample size, the sampling distribution of the sample mean tends to follow a normal distribution, regardless of the shape of the population distribution.

Therefore, both sampling distributions of size 4 and size 50 will be normal.

Moreover, the mean of the sampling distribution of the sample mean will be equal to the population mean.

Since the population mean is given as 26.8 years, the mean for both size 4 and size 50 will be 26.8 years.

Thus, option (C) is correct.

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Given that alpha and beta are acute. Sin alpha = 1/√10 and Sin beta = 1/√5, prove without using calculator and table that Sin (alpha + beta) = 1/√2​

Answers

If ∠A and ∠B are acute angles such that cos A = cos B we have proved that ∠A = ∠B since AC = BC and angles opposite to equal sides of a triangle are equal.

What are the definitions of two acute angles?

Image outcome

An acute angle has a degree that is less than 90 degrees, i.e. less than a right angle. Acute angle degrees include 12°, 35°, 48°, 65°, 80°, and 89°. An acute angle triangle (also known as an acute-angled triangle) is a triangle with all of its internal angles being acute angles. Remember that an acute angle is one that is less than 90°. Because all three angles are less than 90°, ABC is an acute angle triangle or acute-angled triangle.

The sine function for the angle yields the ratio of the length of the opposing side to the length of the hypotenuse.

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the number of guests at a theme park can be modeled by function p(t) where t is measured in hours. p is a solution to the logistic differential equation dp over dt equals p over 2 minus p squared over 60000 comma where p(0)

Answers

Answer: 10,000 guests per hour

A fair coin is flipped 30 times. Let X denote the number of heads among the first 20 coin flips and Y denote the number of heads among the last 20 coin flips: Compute the correlation coefficient of X and Y.

Answers

the correlation coefficient of X and Y is Cov ( X, Y ) = 1/2

X = Number of heads in the first 20 flips

Y = Number of heads in the last 20 flips

Given that X and Y are binomial variables hence

P( probability ) = 1/2

Find Cov( X; Y )

xi = result of the ith flip ∴ X = x1 + x2 + x3 + x4+....x20

yj = result of the  jth flip ∴ Y = y3 + y4 + y5 + y6+ ....x20

covariance of  xi and yi = 1/2 * 1/2 = 1/4   when i = j  and it is = 0 when i ≠ j

hence Cov( X; Y ) can be expressed as

Cov( X; Y ) = ∑^4 ∑^6 ∴ Cov( Xi , Yj ) = 2/4 = 1/2  (  given that i = j )  

Hence he correlation coefficient of X and Y is Cov ( X, Y ) = 1/2

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Mariah made a cylinder out of clay that had a radius of 6 cm and a volume of 72π cm^3. She painted the entire surface of the cylinder purple. How many square centimeters of the cylinder did Mariah paint in terms of π?

Enter the correct answer in the box in terms of π.

Answers

The square centimeters of the cylinder did Mariah paint in terms of π will be 24π cm².

What is the surface area of a right circular cylinder?

Let r be the radius and h be the height of the cylinder. Then the surface area of the cylinder will be given as,

SA = 2πrh square units

Mariah made a cylinder out of clay that had a radius of 6 cm and a volume of 72π cm³. The height of the cylinder is calculated as,

V = πr²h

72π = π x 6² x h

72 / 36 = h

h = 2 cm

Then the surface area of the cylinder is given as,

SA = 2 x π x 6 x 2

SA = 24π square cm

The square centimeters of the cylinder did Mariah paint in terms of π will be 24π cm².

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How do you graph the ellipse? (x - 6)²/36 + (y + 3)²/100 = 1

Drag choices into the boxes to correctly complete the statements.

Answers

Answer:

center: [tex](6, -3)[/tex]

distance from center:

major axis - 10 unitsminor axis - 6 units

connect: [tex](16, -3), (6, -9), (-4, -3), (6, 3)[/tex]

Step-by-step explanation:

Ellipse Equation:

An ellipse has two forms, although they're essentially the same:

[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]

and

[tex]\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1[/tex]

Where a > b, and if the "a^2" is under the [tex](x-h)^2[/tex] then that means the ellipse has a horizontal major axis, but in general the value below this numerator relates to the length of the horizontal axis. Now if "a^2" is under the [tex](y-k)^2[/tex] then that means the ellipse has a vertical major axis, but in general the value below this numerator relates to the length of the vertical axis.

The length of the major axis is defined as 2a and the minor axis as 2b, but the distance from the center to the end points will be half of this, so either "a" or "b" depending on which axis the end point is on.

The other thing to note is that (h, k) is the center of the ellipse.

Analyzing the Equation:

We're given the equation: [tex]\frac{(x-6)^2}{36}+\frac{(y+3)^2}{100}=1[/tex], in this case the bigger value is under the (y+3)^2, so we know that we will have a horizontal major axis. Since the denominator's represent the square of "a" and "b" we first have to take the square root of them. So the following is true:

[tex]a=\sqrt{100}=10\\b=\sqrt{36}=6[/tex]

The "a" gives us the distance from the center to the end point on the major axis while the "b" gives us the distance from the center to the end point on the minor axis, so the distance from the center to the end point on the minor axis is 6 and for the major axis it's 10.

We also know the center is at (6, -3) by looking at the signs and what is being added/subtracted from the x and y values in the equation. We can use this to calculate the end points since the end points on the horizontal major axis can be calculated as: [tex](6\pm10, -3)[/tex] and the end points on the vertical major axis can be calculated as: [tex](6, -3\pm 6)[/tex], which gives us four points: [tex](16, -3), (6, -9), (-4, -3), (6, 3)[/tex] which we can connect to draw a graph.

Answer:

[tex]\textsf{The center of the ellipse is $\boxed{(6,-3)}$}\;.[/tex]

[tex]\textsf{The endpoints of the major axis are $\boxed{10}$ units from the center}\;.[/tex]

[tex]\textsf{The endpoints of the minor axis are $\boxed{6}$ units from the center}\;.[/tex]

[tex]\textsf{To graph the ellipse, connect $\boxed{(12,-3),(6,-13),(0,-3), \;\textsf{and}\; (6,7)}$ with a smooth curve}\;.[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{7.2 cm}\underline{General equation of an ellipse}\\\\$\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1$\\\\where:\\\phantom{ww}$\bullet$ $(h,k)$ is the center\\ \phantom{ww}$\bullet$ $a$ and $b$ are the radii.\\ \phantom{ww}$\bullet$ $(h\pm a,k)$ and $(h,k\pm b)$ are the vertices.\\ \end{minipage}}[/tex]

Given equation:

[tex]\dfrac{(x-6)^2}{36}+\dfrac{(y+3)^2}{100}=1[/tex]

As b > a, the given ellipse is vertical.

The major axis is the longest diameter and the minor axis is the shortest diameter, therefore:

Major axis = 2bMinor axis = 2aVertices = (h, k±b)Co-vertices = (h±a, k)

Determine the values of h and k:

[tex](x-h)=(x-6) \implies h=6[/tex]

[tex](y-k)=(y+3) \implies k=-3[/tex]

Therefore, the center of the ellipse is:

[tex](h,k)=(6, -3)[/tex]

Calculate the values of a and b:

[tex]a^2=36 \implies a=6[/tex]

[tex]b^2=100 \implies b=10[/tex]

As the major axis is 2b, then the major radius is b.

Therefore, the endpoints of the major axis are "b" units from the center, so they are 10 units from the center.

As the minor axis is 2a, then the minor radius is a.

Therefore, the endpoints of the minor axis are "a" units from the center, so they are 6 units from the center.

To graph the ellipse, connect the vertices and co-vertices with a smooth curve.

Vertices = (h, k±b) = (6, -3±10) = (6, -13) and (6, 7)Co-vertices = (h±a, k) = (6±6, -3) = (0, -3) and (12, -3)

You have 26 cards, labeled with the letters A-Z. The deck is shuffled randomly. You draw cards without replacement. (a) Let I be the number of letters we needed to draw to have seen both A and B. For example, if the 3rd letter is A and the 5th letter is B, then L = 5. What is the PMF of L? (b) Given that we have drawn k many cards already (for some k 0,..., 24) and neither A nor B have yet appeared, what's the probability that these two letters will be drawn consecutively (either AB or BA)? =

Answers

The PMF of the number of letters needed to draw to have seen both A and B is pmf(L=k) = $\frac{1}{26 \choose k-1}$ for k = 2, 3, ..., 26. Given that we have already drawn k many cards and neither A nor B have yet appeared, the probability that these two letters will be drawn consecutively is $\frac{2}{26-k}$.

(a) pmf(L=k) = $\frac{1}{26 \choose k-1}$ for k = 2, 3, ..., 26

(b) P(AB or BA | k cards already drawn) = $\frac{2}{26 - k}$

(a) Since the deck is shuffled randomly, we can assume that each of the 26 letters has an equal probability of being drawn. The probability of drawing A and B before any other letter is $\frac{1}{26 \choose k-1}$.

(b) The probability of drawing AB or BA is $\frac{2}{26-k}$, since there are two possible combinations and we have (26-k) cards left to draw.

The PMF of the number of letters needed to draw to have seen both A and B is pmf(L=k) = $\frac{1}{26 \choose k-1}$ for k = 2, 3, ..., 26. Given that we have already drawn k many cards and neither A nor B have yet appeared, the probability that these two letters will be drawn consecutively is $\frac{2}{26-k}$.

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