Represent each of the following quantities with combinations of units in the correct si form, using an appropriate prefix: (a) mm-mn (b) mg/mm (c) km/ms (d) kn/(mm)2

Option D) is the correct answer. The Closed Universe model of the fate of the universe, if correct, is most likely to predict a second Big Bang.

The Closed Universe Model describes a hypothetically ever-expanding universe that contains a sufficient amount of matter in it a so that the gravitational pull due to the stored mass is enough to reverse the observable expansion of the universe through its gravitational contraction.

It is predicted that according to this model, the closed universe will folds back on itself like a saddle.

This could result in a second Big Bang.

According to Albert Einstein, the general shape of the universe depends upon the average density of matter and energy in the universe. For a closed universe, the ratio of average density to critical density ( for which the universe is flat) is more than one.

Hence, the Closed Universe Model is most likely to predict a second Big Bang.

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The one that  represents a car with positive acceleration is graph number III.

The term velocity has to do with the change of displacement with time. The acceleration is the change in velocity with time. We know that the slope of the velocity time graph is the acceleration. Uniform velocity occurs when the displacement increases in equal amounts in equal time intervals thereby leading to a straight line graph.

Hence a positive acceleration is only possible when the velocity is increasing in  equal amounts in equal time intervals

We can see from the graphs that the one that  represents a car with positive acceleration is graph number III.

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Considering the definition of speed, the average speed of the plane is 681.6 m/s.

speed ​​is a quantity that expresses the relationship between the space traveled by an object.

In other words, speed can be defined as the amount of space traveled per unit of time with which a body moves and can be calculated using the expression:

speed= distance traveled÷ time

In this case, you know:

So, in both cases you know the distance traveled and the speed. Therefore, you must calculate the time in which each part of the trip is made, in order to later know the total time. For this, the definition of speed is used:

So, you know:

Replacing in the definition of speed:

speed= 1,090,000 m÷ 1599,1784 s

speed= 681.6 m/s

In summary, the average speed of the plane is 681.6 m/s.

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3.27 m/s is the highest height the drone can drop the cargo from.

The greatest height is equal to V²/2g, where V stands for velocity and g for gravity, and where 9.8 m/s2 = 82/2(9.8) = 3.27 m/s.

A home run is baseball's best delight. Projectile motion, a typical sort of two-dimensional motion, is what the ball is doing as it curves toward the stands. If air resistance is assumed to be nonexistent, a decent description of such motion may frequently be given.

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The speed of the tape, in metres per minute is 1.44 meter per minute

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

With the above formula, we can obtain the speed of the tape. Details below

The following data were obtained from the question:

The speed of the tape can be obtained as illustrated below:

Speed = distance / time

Speed = 260 / 180

Speed = 1.44 meter per minute

Thus, the speed of the tape is 1.44 meter per minute

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45gram of ampicillin would be needed.

Final concentration of ampicillin solution = 100mg/ml

It means that 1 ml of solution will have 100 mg ampicillin

So, 450 ml of solution will have = 450 * 100 = 45000 mg ampicillin

45000 mg = 45 gram

Hence, to make 450 ml of solution 45 gram of ampicillin would be needed.

Ampicillin: at a final concentration of 100ug/ml, add 1 ml of ampicillin (at a concentration of 100 mg/ml) per liter of agar.

Add 10 mL of d H2O to 1 g of Amp powder.

When powder is completely dissolved, vortex.

Use a sterile 0.22 mm filter to sterilize.

Store at -20 °C and aliquot 1 mL of the amp solution into a 1.5 mL tube.

How is ampicillin 50 mg/mL produced?

Ampicillin sodium salt 500 mg can be dissolved in water to a final volume of 10 ml to create a 50 mg/ml stock solution.

With 1 mL, 1.8 mL, 3.5 mL, and 6.8 mL of each of the following: 250 mg, 500 mg, 1 g, and 2 g vials

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The displacement of the spring with a force constant of 80 N/m is 2.5 m.

Displacement can be defined as the difference between the final and initial position of a object in motion.

To calculate the displacement of the spring, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the displacement of the spring is 2.5 m.

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Answer:

V1 = 700 cos 69.8 i + 700 sin 69.8 j           vector components of V1

V1 = 241.7 i + 656.9 j          in miles/hour

V2 = 620 cos 107  i + 620 sin 107 j

V2 = -181.3 i + 592.9 j

V = V1 - V2 = 423 i + 64 j        rate of planes separation

1.9 V = 803.7 i + 121.6 j     miles   separation of planes after 1.9 hr

D = (803.7^2 + 121.6^2)^1/2 = 812.8 miles

Answeratomic number 14 , 14, protons , and 14 electrons

Explanation:

By unit conversion, Steve's peak speed in kilometers per hour is 2.844 km/h.

We need to know about unit conversion to solve this problem. The unit conversion can be used to convert a unit to another unit. It can be defined as

a = xb

where a is unit a, b is unit b and x is the constant of conversion.

From the question above, we know that

v = 79.5 cm / s

The unit conversion that we used is (1 cm = 10¯⁵ km) and (1 second = 1/3600 hour)

Hence, the speed in kilometers per hour is

v = 79.5 cm / s

v = 79.5 x 10¯⁵ km/ (1/3600) h

v = 711/250 km.h

v = 2.844 km/h

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Answer:

I think the answer is coconut

Explanation:

please make my answer as brainelist

Jaycie must complete 10 pushups to do 200 J of work if a force of 10 N is required to raise her center of gravity by 2 m.

W = F * d

W = Work done

F = Force

d = Distance

F = 10 N

d = 2 m

W = 10 *2

W = 20 J

This is the amount of work done to complete one push up.

Number of push ups to be completed to do 200 J of work = 200 / 20

Number of push ups to be completed = 10

The amount of work done is a measure of force used to move an object to a certain distance. Its unit if Joules.

Therefore, Jaycie must complete 10 pushups to do 200 J of work

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(a) The plane must fly at an angle of N 35.5° E to immediately approach the lake.

(b) The velocity of the plane is 245.6 km/h.

(c) The time taken is 1.02 hours.

Lake displacement from the starting position, D = 250 km N 30° E

As the x-axis, let's choose the line connecting the plane's beginning point with the lake, which is located in the direction N 30° E.

D = 250 ^i km

The plane's airspeed,

v(p) = 210 km/h

From the east comes the wind. Therefore, using the coordinate system described above, the wind speed,

v(w) = 40 [ cos ( − 30° ) ^i + sin ( − 30°) ] km/h

v(w) ≈ ( 36.64 ^i − 20 ^j ) km/h

(a) To eliminate the perpendicular component of the wind velocity, move the plane in the direction θ with respect to the x-axis.

v(p) = 210 ( cos(θ) ^i + sin(θ) ^j ) km/h

In order for the y-component of the plane velocity to cancel out the y-component of the wind velocity, the correct angle must be calculated.

Therefore,

210 sin(θ) km/h = 20 km/h

sin(θ) = 20 / 210

θ ≈ 5.5°

Therefore, the aircraft should fly 5.5 degrees off of the x-axis. This means that the plane must fly at an angle of N 35.5° E to immediately approach the lake.

(b) The velocity relative to the ground is:

v = v(w) + v(p)

v = 210 ( cos 5.5° ^i + sin 5.5° ^j ) km/h + ( 36.64 ^i − 20 ^j ) km/h

v ≈ ( 209 ^i + 20 ^j ) km/h + ( 36.64 ^i − 20 ^j ) km/h

v = 245.6 ^i km/h

The plane is moving at a speed of 245.6 km/h relative to the ground.

(c) From the starting point, the time taken to reach the lake is:

time = distance/ speed

T = 250 km / 245.6 km/h

T ≈ 1.02 h

Therefore, from the starting position, it will take around an hour to get to the lake.

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Answer: 5. 9000 meters

6. 0.12626 miles

7. 26.78 meters

8. 1 mile per minute

9. 468 km per hour

Explanation:

5. 1000 m=1 km

9 km * 1000 m/1 km=

9 * 1000/1 = 9000 meters

6. 63360 inches = 1 mile

8000 inches * 1 mile/63360 inches=

8000/63360=0.12626 miles

7. 100 cm=1 m

2678 cm * 1 m/100 cm=

2678 * 1/100=

2678/100=26.78 meters

8. 60 minutes=1 hour

60 mph * 1 hour/60 minutes=

60 * 1/60=1 mile per minute

9. 1000 m=1 km

1 hour=60 minutes

1 minute=60 seconds

60 seconds * 60 minutes/1 hour=

60 * 60/1=3600 seconds

130 meters * 3600 seconds/1 second=

130 * 3600/1=468000 meters per hour

468000 m* 1 km/1000 m=

468000 * 1/1000=468 km per hour

Partial pressure of helium =275.7 torr

Given data,

275 mL is the flask one volume.

Helium's pressure is 752 torr.

The second flask's volume is 475 mL.

722 torr is the argon pressure.

Partial pressure is equal to what?

As,

V2 is equal to 275 + 475 = 750 mL.

Using helium:

P₁V₁ = P₂V₂

P₂ = P₁V₁ /V₂

P₂ = 752 torr. 275 mL / 750 mL

P₂ = 206800 torr. mL /750 mL

P₂ = 275.7 torr

Therefore, Partial pressure of helium =275.7 torr

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A stone that is thrown with an initial velocity of 7.0 m/s and the acceleration of the stone is constant and has the value of -9.8 m/s2, then the velocity of the stone is 2.1 m/s

The vector quantity of velocity (v) can be denoted by the equation v = s/t. This also quantifies displacement (or change in position, s), over the change in time (t). Speed (or rate, r) is a scalar number, denoted by the equation r = d/t, that quantifies the distance travelled (d) over the change in time (t).

Here are the three equations:

S = ut + 1/2at^2,

v = u + at,

v^2 = u^2 + 2as.

The data obtained from the question is:

Initial velocity (u) = 7 m/s

Time (t) = 0.50 s

Final velocity (v) =?

Since the stone is thrown upward, it means that this stone is going in a direction against gravity.

Thus, the value of the acceleration due to gravity will be found out in negative i.e – 9.8 m/s²

Thus, we can obtain the final velocity of the stone after time 0.50 s as follows:

Initial velocity (u) = 7 m/s

Time (t) = 0.50 s

Acceleration because to gravity (g) = – 9.8 m/s²

Final velocity (v) =?

v = u + gt

v = 7+(– 9.8 × 0.5)

v = 7 – 4.9

v = 2.1 m/s

Therefore, the final velocity of the stone calculated after 0.5 s is 2.1 m/s.

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in that scenario, the signaling rate is exclusively constrained by the channel bandwidth according to Nyquist's analysis of the theoretical capacity of a noiseless channel.

• What signaling rate can be accomplished over a channel with a certain bandwidth, a given signal power, and in the presence of noise was addressed by Shannon.

• Channel without errors The temperature of a material is defined as the average kinetic energy of its atoms or molecules, plus any other energy that can be transferred. In theory, the lower limit of temperature would be when all particles have zero energy

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With the use of second equation of motion formula, its position at time 3.7 s is 16.43 meters

A position is a point where an object can be located. The length between two positions is known as distance.

Given that a ball starts from rest at the initial position xi = 0. The ball has a constant acceleration of 2.4m/s², to know its position time 3.7 s, we will use the formula

X2 - X1 = ut + 1/2 × a × t²

Where

Substitute all the parameters into the formula

X2 - 0 = 0 + 1/2 × 2.4 × 3.7²

X2 = 1.2 × 13.69

X2 = 16.43 m

Therefore, its position at time 3.7 s is 16.43 meters

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By the vector, the force in the y component is  -16.18 newtons.

We need to know about vectors to solve this problem. Vector has magnitude and also direction. Force is included in the vector. It can be written as

F = Fx i + Fy j + Fz k

where s is displacement, Fx is force on x-axis, Fy is displacement on y-axis and Fz is displacement on z-axis.

From the question above, we know that

|F| = 232 N

θ = 184⁰

The force on y-axis is

Fy = |F| . sin(θ)

Fy = 232 . sin(184)

Fy = -16.18 newtons

The negative force is caused by the direction of the force.

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Measurement refers to the strategy that's utilized to relegate a number to a specific parameter / indicator / characteristics of an article that's assist utilized to compare with other measured numbers. For example, measurement of inflation is done as a rate alter in cost. Here, inflation may be a macroeconomic pointer. Assist, current expansion can be compared with the past. Similarly, efficiency of an worker is also measure in terms of unit / quality created in a given time period. Further, it is utilized to compare with standard productivity level.

Each estimation gives numerical result and numerical result of estimation changes with the sort of estimation and information. For example, estimation of area gives information in square meter or square feet. But, estimation of GDP provide the information in terms of Million / Billion or Trillion. Hence, with the change of information types, measurement unit changes. For exactness and standardization of comes about, standard units of estimation are settled and practiced over the globe.

Representation of information figures as a portion of estimation can moreover be done in:

Table form

Charts

Graphical representation

Above representation helps in comparative analysis.

Types of information can too be:

Discrete

According to the information sorts, suitable estimation procedure is adopted. Staffing Experts need to know the appropriate estimation strategy to degree the execution of workers against the benchmark standards. They ought to too know the measurement of credentials of potential recruits. It is their ethical obligation to select as it were those who can convey the leading comes about for the company. It can as it were be done through proper measurement. Client Company contracts staffing Experts to bring in able initiates to the company. Presently, it is the ethical obligation of Staffing Experts to degree the candidates without any bias / prejudice.

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The ratio of the masses of the toy cars is 1 : 3 : 6.

When the mass of object increases, the force of gravitational attraction between them also increases.

The ratio of the masses of the toy cars is calculated as follows;

Ratio of masses = 0.3 kg/0.3 kg :  0.9 kg/0.3kg :  1.8 kg/0.3 kg

Ratio of masses = 1 : 3 : 6

Thus, the ratio of the masses of the toy cars is 1 : 3 : 6.

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The initial speed of the ball will be 25.73 m/s.

Speed is described as the rate at which an object's position changes in any direction.

The distance traveled relative to the time it took to travel that distance is how fast something is moving. Speed is a scalar quantity because it just has a direction and no magnitude.

Speed=distance/time

According to the question :

Maximum height can be achieved in time t will be -

⇒1/2(4.90)

= 2.45 seconds

and, the time [tex]V_y[/tex]=0

So by considering the motion from that time on and since [tex]V_0y-gt\\[/tex]

[tex]V_0y[/tex]=9.81 m/[tex]s^{2}[/tex] (2.45 seconds)

⇒24.03 m/s

So,

[tex]V_0[/tex]= 24.03/sin [tex]69^{0}[/tex]

⇒25.73 m/s.

Hence, its initial speed was 25.7 m/s.

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2520.43N would a 3.50 in x 0.50 in steel bar weigh if it were 18 in long.

According to the relationship between density and volume, both are inversely proportional. It means that any change in density, no matter how tiny, will probably result in a change in the volume of that particular substance, be it an element or a compound.

The relationship between a substance's mass and volume is expressed by its density. The substance with more mass is denser if the volumes of the two substances are equal.

The density of the steel is = [tex]283lbs/in^3[/tex]

Length = 18 in

[tex]A_x[/tex] is= 3.50 in x 0.50 in

= 1.75 in

Volume = v= 1.75 x 18

[tex]v=31.5in^3[/tex]

Mass of steel m = lv

m=18x31.5

m=567 lbs

1 pound= 0.453592 kg

567 pound = 257.187 kg

Weight = m x g

=257.187 x 9.8

=2520.43N

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The map of the world temperature zones gives;

23. Zone A = The North Frigid zone

Zone B = The North Temperate zone

Zone C = The Torrid

Zone D = The South Temperate zone

Zone E = The South Frigid zone

24. Zone C, the Torrid zone

25. Zone C, the Torrid zone

26. The Torrid zone

23. The five temperature zones of the world based on the annual temperatures are;

The north frigid zone

The north temperate zone

The torrid zone (tropics)

The south temperate zone

The south frigid zone

Each of the five zones shown on the map are;

Zone A = The North Frigid zone

Zone B = The North Temperate zone

Zone C = The Torrid zone Tropics

Zone D = The South Temperate zone

Zone E = The South Frigid zone

24. The name of the temperature zone that includes the equator is; Zone C, the Torrid zone (The tropics).

The Equator is located around the horizontal line that runs around the center of the Earth at 0 ° latitude.

25. The zone that has the greatest amount of human habitable land mass is; Zone C, the Torrid zone, which covers 40% of the geographic surface of the Earth.

26. The zone that has the highest temperature all year round is the zone farthest from the north and south Frigid zone which is the Torrid zone

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Answer:

Explanation:

The molarity of the zn(no3)2zn(no3)2 is 0.148 M

This is the Equation used Zn(s)+2HNO3(aq)⟶Zn(NO3)2(aq)+H2(g)

The mass in grammes of one mole of a chemical is its molar mass. The number of entities that are present in a material

A substance's molar mass is the volume of the material that contains one mole of the substance. Its basic definition is the weight of a single mole of a material. The atomic mass of each substance is multiplied by the subscript of that element in the chemical formula to determine the molar mass.

e.g. atoms, molecules, ions, is defined as a mole.

Any material has 6.022 x 1023 molecules in a mole.

Hence the molarity is 0.148M

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The object will fall a distance during its final second in the air of: 81.967 m

The free fall formulas and the procedures we will use are:

Where:

Information of the problem:

Applying the time formula we get:

t = √[ (2*h) / g]

t = √[ (2* 127 m) / 9.8 m/s²]

t = √[ 254 m / 9.8 m/s²]

t = √[ 25.918 s²]

t = 5.090 s

Calculating time traveled before the final second and we have:

t(final second) = t - 1 s

t(final second) = 5.090 s - 1 s

t(final second) = 4.090 s

Applying the height formula we get:

h = (g * t²)/2

h(final second) = (9.8 m/s² * (4.090 s)²)/2

h(final second)  = (9.8 m/s² * 16.7281 s²)/2

h(final second) = 163.935 m/2

h(final second) = 81.967 m

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

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The typical patterns of GDP, both in the long run and in the short run, will be fluctuate.

GDP can be defined as across domestic product in which the markets are the company economy is being measured. It is relation to the monetary policy and the market value of the good which is being brought or sold in the market

There will be a GDP that will be running for the long run and also in the short run depending on the economic condition. This determines to start the good for the services retailing provided is in the flow or not, this depends on the flow of money in the market.

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The distance the ball rolls up to before it stops is 110.25m.

Newton’s third equation of motion can be used to determine the distance the ball rolls up to before it comes to a halt.

Given data:

Initial velocity of the ball, u = 21m/s

Final velocity of the ball, v = 0

Acceleration of the ball, a = -2m/s^2

To find:

Distance the ball rolls, S = ?

Formula:

v^2 = u^2 + 2aS

Calculation:

0 = 21^2 + 2 (-2) S

S = 441 / 4

S = 110.25m

Result:

The distance the ball rolls up to is 110.25m before it stops.

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