Physics College

Returning to the scene of the (possible) crime, you estimate that the bathtub in which Polly was found contained around 0.3 m3 (around 80 gallons), which corresponds to 300 kg (since the density of water is 1000 kg/m3), of water as you scoop the water out of the tub. The temperature of this water is 7oC. You assume that the water was initially at its lowest temperature, 2oC, which you find by turning on the cold tap only.
With these measurements, first determine the amount of heat that transferred from Polly and the external environment to warm the cold water. The specific heat of water is about 4186 J/(kgoC). Give your answers in units of kilojoules (kJ).

Answers

Answer 1

This indicates that to increase the temperature of the water in the bathtub from 2°C to 7°C, roughly 62,760 kJ of heat energy were added.

What is the water's temperature?

While scientists typically use the Centigrade (or Celsius) scale, where water freezes at 0 degrees and boils at 100 degrees, we typically measure temperature in the United States using the Fahrenheit scale, where water freezes at 32 degrees and boils at 212 degrees.

According to the data given, the bathtub once held 300 kg of water at 2°C.

we can use the specific heat capacity of water and the formula:

Q = m * c * ΔT

The specific heat capacity of water is 4.184 J/(g°C), or 4184 J/(kg°C). Therefore, the amount of heat energy absorbed by the water is:

Q = 300 kg * 4184 J/(kg°C) * (7°C - 2°C)

Q = 62,760 kJ

To know more about specific heat visit:-

https://brainly.com/question/28852989

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