Richards Corporation uses the FIFO method of process costing. The following
information is available for October in its Fabricating Department:
Units:
Beginning Inventory: 80,000 units, 60% complete as to materials and 20%
complete as to conversion.
Units started and completed: 250,000.
Units completed and transferred out: 330,000.
Ending Inventory: 30,000 units, 40% complete as to materials and 10%
complete as to conversion.
Costs:
Costs in beginning Work in Process - Direct Materials: $37,200.
Costs in beginning Work in Process - Conversion: $79,700.
Costs incurred in October - Direct Materials: $646,800.
Costs incurred in October - Conversion: $919,300.
Calculate the equivalent units of materials.

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: [ - 10,- 8] \cup[ - 2,0] \cup[2,5][/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

The intervals in which a function is decreasing has a negative slope. and for given graph, the required intervals are :

[tex]\qquad \tt \rightarrow \: [ - 10,- 8] \cup[ - 2,0] \cup[2,5][/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

An opportunity cost of 9 percent, is $42.

We have given that,

The present value of $100 is to be received 10 years from today,

assuming an opportunity cost of 9 percent,

present value =$100

N=10 years

I/y=9

PV= FV/(1+r)^n

Where FV is the future value.

Use the given values in the formula we get,

Therefore the correct answer is 42.

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Answer:

No.

Step-by-step explanation:

This problem in scientific notation would be 9.3 * 10^10.

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\texttt {\:Thomas's age = 44 years } [/tex]

[tex]\texttt {\:Hulian's age = 36 years } [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \textsf{Assume Thomas's age be ' x ' } [/tex]

[tex] \textsf{and that of Huilan's age be y } [/tex]

[tex] \texttt{we have two conditions :} [/tex]

[tex]\qquad \tt \rightarrow \:y = x + 8[/tex]

it can be simplified as : -

[tex]\qquad \tt \rightarrow \:y - x= 8 \: \: \: \: \: \: \: \: \: - (1)[/tex]

[tex] \texttt{Next condition } [/tex]

[tex]\qquad \tt \rightarrow \:x + y = 80 \: \: \: \: \: \: \: - (2)[/tex]

`` Add both equations ``

[tex]\qquad \tt \rightarrow \:y - x + x + y = 8 + 80[/tex]

[tex]\qquad \tt \rightarrow \:2y = 88[/tex]

[tex]\qquad \tt \rightarrow \:y = 44[/tex]

[tex] \large \textsf{For x :} [/tex]

[tex]\qquad \tt \rightarrow \:y - x = 8[/tex]

[tex]\qquad \tt \rightarrow \:44 - x = 8[/tex]

[tex]\qquad \tt \rightarrow \:x = 44 - 8[/tex]

[tex]\qquad \tt \rightarrow \:x = 36[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

[tex]\fbox {36 years old}[/tex]

Step-by-step explanation:

Let :

⇒ Age of Huilan = x

⇒ Age of Thomas = x - 8

Then :

⇒ x + x - 8 = 80

⇒ 2x = 88

⇒ x = 44

Thomas's age :

⇒ x - 8

⇒ 44 - 8

⇒ 36 years old

Answer:

B

Step-by-step explanation:

because > means greater than or more than

and < means less than

the answer is B because 3 is more than 2 and the same time less than 5

Answer:

(3, 0) and (−1, −8)

Equation's:

2x − (x² − 9) = 6

2x - x²  + 9 = 6

-x² + 2x + 9 - 6 = 0

-x² + 2x + 3 = 0

x² - 2x - 3 = 0

x² - 3x + x - 3 = 0

x(x - 3) + 1(x - 3) = 0

(x + 1)(x - 3) = 0

x = -1, x = 3

If x = -1, then y = (-1)² - 9 = -8

If x = 3, then y = (3)² - 9 = 0

(x, y) = (-1, -8), (3, 0)

The range, the mean, and standard deviation are mathematically given as

Participants ranged in age from 4 to 26.24 ( M = 26.24 , SD = 8.04 ). Option D.

Given the data presented below the given

A look at the result shows that the lowest and highest values are between 1s and 58, with a mean and standard deviation of 26.10 and 8.90, respectively.

Participants' ages varied from 18 to 58 (m-26.14, std dev = 8.01), hence option (d) is accurate.

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The first term will be 4 and the common ratio will be 2. And the nth term will be given as [tex]\rm a_n = a_{n -1} \cdot 2[/tex].

The complete question is attached below.

Let a be the first term and r be the common ratio. Then the geometric sequences will be

[tex]\rm a_n = a_{n -1} \cdot r[/tex]

The geometric sequence is given below.

4, 8, 16, 32, 64,................

Then the first term will be 4 and the common ratio will be 2.

And the nth term will be given as [tex]\rm a_n = a_{n -1} \cdot 2[/tex].

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Answer: B -60

Step-by-step explanation: When you plug in -60 into the equation it all equals out into -12 = -12, which is true. All of the other solutions don't work.

Answer:

B. x = -60

Step-by-step explanation:

8 + x/3 = 1/6 (x-6) - 1

Multiply both sides by 6.

48 + 2x = x - 6 - 6

x = -12 - 48

x = -60

The first option is correct and it best describes the constant difference for the function as a constant second difference of –6.

A function f(x) is the relation between a set of inputs resulting and producing the desired output value of y for each input.

From the given information:

x          f(x)           first difference        second difference   third difference

-2         0                    -                              -                              -

-1         -10            (-10-0)/-1--2 = -10           -                             -

0         -12            (-12 - 10)/0 -- 1= -2     (-2-10)/2 = -6              -

1          -12            (-12--12)/1-0 = 0         (0-2)/2 =  -1              (-1+6)/2 = 5/2

2         -16             (-16--12)/2-1 = -2       (-2-0)/2 = -1              (-1+1)/2 = 0

Therefore, we can conclude that the constant difference for the function is a constant second difference of –6.  

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Answer:

A

Step-by-step explanation:

Answer:

A. 15

Step-by-step explanation:

Hypotenuse = 22

Since the two angles other than the 90° are both

45° , it means that the two legs of the right triangle are of equal length.

So, (x)²+ (x)² = 22²

2x² = 22²

x² = 484/2

x² = 242

x = √242

x = 15.55

x ≈ 15

Answer:

[tex]\boxed {t < 15}[/tex]

Step-by-step explanation:

Given :

⇒ t - 3 < 12

Add 3 to each side :

⇒ t - 3 + 3 < 12 + 3

⇒ t < 15

Answer: t < 15

Step-by-step explanation:  

rearrange the terms                                       t - 3 < 12

calculate the sum or difference                    t < 12 + 3

answer                                                             t < 15                            

a) When x = -2, g(x) = 5.

b) When x = -4, g(x) = 7.

c) When g(x) = 6, x = -3

d) When g(x) = -1, x = 4

The graph is attached with the answer.

When two algebraic expressions are equated using an inequality operator , The statement formed is called In equality.

The given Inequality is 2x + y ≤ 2

in slope intercept form can be written as

y ≤  -2x +2 , here slope is -2 and intercept is 2

As an equation it will be

y = -2x +2

x         y

0 ,       2

1 ,       0

2         -2

The graph is plotted

The area is shaded and the test for the origin is applied , and it lies in the shaded region.

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Answer:

0 m/s

Step-by-step explanation:

The initial value of the sequence is 1

From the graph, we have the following ordered pairs

(x, y) = (1, 1), (2, 4) and (3, 8)

Remove the x values

y = 1, 4, 8

The first value in the above sequence is 1

Hence, the initial value of the sequence is 1

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Answer:

Step-by-step explanation:

Remark. Since 6 has a decimal after it, I take it that is the question number.

y = 16x is the basic formula. x starts at 0. Then you add 16 to each number to get the next number in the sequence. Or you could do it the way I propose it.

x      0     1      2     3     4     5     6     7

y      0     16   32   48   64   80  96  112

Answer:

11

Step-by-step explanation:

for each full cup of sugar, you need 3 one-third measuring cups.

we have 3 full cups so 3×3=9

and another 2 for the 2/3, 9+2=11

so a total of 11 scoops

The mean will be 10.08 and the standard deviation will be 1.27.

The complete question is given below:-

The Mountain States Office of State Farm Insurance Company reports that approximately 84% of all automobile damage liability claims were made by people under 25 years of age. A random sample of twelve automobile insurance liability claims is under study.

Find the mean and standard deviation of this probability distribution.

For samples of size 12, what is the expected number of claims made by people under 25 years of age?

Mean is defined as the ratio of the sum of the number of the data sets to the total number of the data.

Standard deviation is defined as the amount of variation or the deviation of the numbers from each other.

Given that:-

The mean will be calculated by the formula below:-

Mean = [tex]\mu[/tex] = np = 12 x 0.84 = 10.08

The standard deviation will be calculated as:-

Standard deviation = [tex]\sqrt{npq}[/tex] = [tex]\sqrt{12\times 0.84\times 0.16}[/tex] = 1.27

Therefore the mean will be 10.08 and the standard deviation will be 1.27.

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Answer:

56

Step-by-step explanation:

so 7 appetizers times 8 main courses

I do a easy trick where I multiple so

7×8=56

Composite functions occur when we take two functions and input one into the other as x.

Example:

[tex]f(x) = 2x[/tex]

[tex]g(x) = 3x^2[/tex]

[tex](f\circ g)(x)=f(g(x))[/tex]

[tex](f\circ g)(x) = 2(3x^2)[/tex]

We're given:

To find [tex](f\circ g)(x)[/tex], input g into f as x:

[tex]f(x)= 3x +2[/tex]

[tex](f\circ g)(x)=3(x^2+1) +2\\(f\circ g)(x)=3x^2+3 +2\\(f\circ g)(x)=3x^2+5[/tex]

[tex](f\circ g)(x)=3x^2+5[/tex]

Answer:

[tex]A) \ x=-1 \ ^ +_-\frac{\sqrt{13} }{\sqrt{6}}.[/tex]

Step-by-step explanation:

if to solve the given equation, then

D=6²+42=78;

[tex]\left[\begin{array}{ccc}x=\frac{-6-\sqrt{78}}{6} \\x=\frac{-6+\sqrt{78}}{6} \end{array} \ = > \ \left[\begin{array}{ccc}x=-1-\sqrt{\frac{13}{6} } \\x=-1+\sqrt{\frac{13}{6} } \end{array}[/tex]

x y

2,0

1,-2

0,-4

-1,-6

-2,-8

Answer:

s = height above ground

s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)

at t = 0

s = 60 (clearly :)

now when does it hit the bleak earth?

That is when s = 0

4.9 t^2 - 20 t -60 = 0

solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)

t = 6.09 or - 2.01

use t = 6.09

now to do the last part there are two obvious ways to get t at the peak

1. look for vertex of parabola

2. look for halfway between t = -2.01 and t = 6.09

I will do it the hard (11) waay by completing the square

4.9 t^2 - 20 t = -(s-60)

t^2 - 4.08 t = -.204 s + 12.2

t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16

(t-2.04)^2 = -.204(s-80.2)

so

top at 80.2 meters at t = 2.04 s

===============

quick check on time

should be average of 6.09 and -2.01

=4.08 /2 = 2.04 check

Answer:                                                                                                                 I HOPE THAT MY ANSWER WILL HELP U        

Step-by-step explanation:

s = height above ground

s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)

at t = 0

s = 60 (clearly :)

now when does it hit the bleak earth?

That is when s = 0

4.9 t^2 - 20 t -60 = 0

solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)

t = 6.09 or - 2.01

use t = 6.09

now to do the last part there are two obvious ways to get t at the peak

1. look for vertex of parabola

2. look for halfway between t = -2.01 and t = 6.09

I will do it the hard (11) waay by completing the square

4.9 t^2 - 20 t = -(s-60)

t^2 - 4.08 t = -.204 s + 12.2

t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16

(t-2.04)^2 = -.204(s-80.2)

so

top at 80.2 meters at t = 2.04 s

===============

quick check on time

should be average of 6.09 and -2.01

=4.08 /2 = 2.04 check

Based on the characteristics of the function and the image generated by the graphing tool, we conclude that the first choice represents the function [tex]y = \sqrt{x} - 4[/tex].

In this question we have a radical function ([tex]f(x) = \sqrt{x}[/tex]) translated vertically 4 units in the -y direction. The domain of the function is [0, + ∞). A quick and efficient approach consists in graphing the function and comparing with each image to determine the right choice.

We present the graph description in the image attached below and we conclude that the first choice represents the graph of the function.

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The local maximum of the equation y = x³ - 5x + 2 is y = 6.3 which occurs at x = -1.29

An equation is an expression that shows the relationship between two or more numbers and variables.

Given the equation:

y = x³ - 5x + 2

The maximum is at dy/dx = 0, hence:

3x² - 5 = 0

x = -1.29 or x = 1.29

y = (-1.29)³ - 5(-1.29) + 2 = 6.3

The local maximum of the equation y = x³ - 5x + 2 is y = 6.3 which occurs at x = -1.29

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Answer:

k(magnitude of vector a).vector a

Step-by-step explanation:

Given question is based on vectors so,

vectors :- Vectors in math is a geometric entity that has both magnitude and direction. Vectors have an initial point at the point where they start and a terminal point that tells the final position of the point. Various operations can be applied to vectors such as addition, subtraction, and multiplication.

To produce an another vector form a given vector we increase its magnitude only not its direction as we have to produce another vector from a given vector.

as its clear from the graph given in the question that only the magnitude of  vector a is increased to produce another vector b

hence we multiply any constant ('k') with the magnitude of vector a to increase its magnitude.

and finally multiply the increased magnitude with the vector 'a' itself.

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The no. of different groups of players of 6 players , if the position does not matter is given by 5005 ,Option C is the right answer.

Combination is a method of selection of items from a set of distinct objects , when the position doesn't matter .

It is given that

Total number of players = 15 = n

No. of players to be selected = 6 = r

The no. of different groups of players of 6 players , if the position does not matter is given by

[tex]\rm ^nC_r = \dfrac{n!}{r! (n-r)!}[/tex]

So

[tex]\rm ^{15}C_6 = \dfrac{15!}{6! (15-6)!}\\\\\rm ^{15}C_6 = \dfrac{15!}{6! (9)!}\\\\\\^{15}C_6 = \dfrac{15 * 14 * 13* 12 * 11 * 10 }{6 *5* 4 * 3 * 2*1}\\\\ ^{15}C_6 = 5005\\[/tex]

Therefore , The no. of different groups of players of 6 players , if the position does not matter is given by 5005

Option C is the right answer.

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