Round 38.856 to the nearest tenth

Answers

Answer 1
38.9 is the answer to the question
Answer 2

Answer:38.9

Step-by-step explanation:


Related Questions

In the Kite ABCD, AB = 5√2mm AP= 5mm, PD = 7mm, find the area to the nearest mm2.

Answers

The area of the kite ABCD will be 60 square millimeters.

What is Geometry?

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

In the Kite ABCD, AB = 5√2mm = 7.07 mm, AP= 5mm, PD = 7mm

Then the area of the kite ABCD will be

Area = 2(area of triangle APB and area of triangle APD)

The side length of PB will be

AB² = AP² + PB²

PB² = AB² – AP²

PB² = 7.07² – 5²

PB² = 50 – 25

PB² = 25

 PB = 5 mm

Then the area will be

Area = 2[(1/2 × 7 × 5) + (1/2 × 5 × 5)]

Area = 60 square mm

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You are working in a lab and you need a solution of 22% acid. In the cupboard, you find a 10% and a 30% solution, but not a 22% solution. You will have to make your own 22% solution. You will need liters of the 10% and liters of the 30% to make 15 liters of a 22% solution?

Answers

The volume of 10% solution will be 6 l and 9 litre of the 30 % solution will be taken.

What is Volume ?

Volume is the space occupied by a three dimensional object .

The concentration of solution required is 22% acid

The concentration of solution available is 10% and 30%

The total volume required is 15 liters

The formula for making a mixture is

Concentration = ( m₁x₁ +m₂x₂) / (x₁+x₂)

22 = (10 * x + 30 *(15 -x))/( 15)

10 x + 450 - 30x =330

-20x = -120

x = 6

The volume of 10% solution will be 6 l

and 9 litre of the 30 % solution will be taken.

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the sum of twice the number x and 25 more than three times the number y

Answers

Answer:

Correct expression:

[tex]2x + 3y + 25[/tex]

sam and jose mowed 2/3 of the yard. jose mowed 3/4of that amount. whta part of the yard did jose mow?

Answers

Answer:

09

Step-by-step explanation:

34

If the zeros of a quadratic equation are
7 and 4, what would be the factors?

Answers

Answer:

The factors are (x-7) and (x-4)

Step-by-step explanation:

We are finding the factors of a function from the zeros

The zeros are 7 and 4

We can use the zero product property which is

(x-b)(x-c) = 0  where b and c are the zeros

(x-7) (x-4) =0

The factors are (x-7) and (x-4)

They should be (x-7) and ( x - 4 )

The graph of quadratic function f has zeros of -8 and 4 and a maximum at (-2,18). What is the value of a in the function’s equation?

Answers

Quadratic Function Equations

To find the equation of a parabola given the vertex and the zeroes, we can use the intercept form equation to help us:

[tex]y=a(x-r)(x-s)[/tex]

r and s = intercepts/zeros of the graph

Solving the Question

We're given:

Zeros: -8, 4Maximum: (-2, 18)

[tex]y=a(x-r)(x-s)[/tex]

⇒ Plug in the given information:

[tex]y=a(x-(-8))(x-4)\\18=a(-2-(-8))(-2-4)\\18=a(-2+8)(-2-4)\\18=a(6)(-6)\\18=a(-36)\\1=-2a\\\\a=-\dfrac{1}{2}[/tex]

Answer

[tex]a=-\dfrac{1}{2}[/tex]

3x squared + 6 x cube - 9x squared y when factorused​

Answers

[tex]3x ^{2} \: + \: {6x}^{3} \: - \: 9 {x}^{2} y[/tex]

Factor the expression with the common factor that is "3x²".

[tex] \boxed{ \bold{3 {x}^{2} \: \times \: (1 \: + \: 2x \: - \: 3y)}}[/tex]

MissSpanish

Answer:

[tex]\boxed{3x²(1 + 2x - 3y)}[/tex]

Step-by-step explanation:

3x squared + 6 x cube - 9x squared y

To factor

Solution:

A process when algebraic expression is expressed as a product of two or more expressions is factorisation.

ATP,

Square = a²

Cube = a³

3x² + 6x³ - 9x²y

We can see that 3x^2 is common in this expression.

So rewrite as:

[tex]3x²(1 + 2x - 3y)[/tex]

Done!

experimental verification​

Answers

See below for the verification of ∠ACD =  ∠ABC + ∠BAC

How to verify the angles?

The following proof works for both triangles.

The sum of angles in a triangle is 180 degrees.

So, we have:

∠ABC + ∠BAC + ∠ACB = 180

Make ∠ACB the subject

∠ACB = 180 - ∠ABC - ∠BAC

The sum of angles on a straight line is 180 degrees.

So, we have:

∠ACD + ∠ACB = 180

Make ∠ACB the subject

∠ACB = 180 - ∠ACD

Substitute ∠ACB = 180 - ∠ACD in ∠ACB = 180 - ∠ABC - ∠BAC

180 - ∠ACD = 180 - ∠ABC - ∠BAC

Subtract 180 from both sides

- ∠ACD = - ∠ABC - ∠BAC

Multiply both sides by -1

∠ACD =  ∠ABC + ∠BAC

Hence, ∠ACD =  ∠ABC + ∠BAC has been verified

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Help me please and thxx

Answers

X = 8√3 , Y = 4√3

Option C).

What is -8/15 of 21/12

Answers

Answer:

-14/15

Step-by-step explanation:

"of" means multiply, thus:

-8/15 * 21/12

-8 * 21 / 15 * 12

-2 * 7 / 15

-14/15

Answer:

-14/15

Step-by-step explanation:

So first you need to get rid of the negative sign. Don't worry you will add it back later!

So, you will do

-8/15×21/12

Once you cross cancel, you will have

-2/5x7/3

That would be equivalent to

-14/15

That's your answer!

Hope this helped :)

What is the area of the figure?

Answers

Answer:

21.5

Step-by-step explanation:

break the shape down to make two shapes: a triangle and rectangle.
triangle = A=bxh/2

3x5=15/2=7.5

Rectangle = A=bxh

2x7=14

7.5+14= 21.5

Hope this helps :)

Answer:

21.5

Step-by-step explanation:

(all steps provided in image attached)

Please help solve for x..

Answers

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

[tex]x^{100}-4^x \cdot x^{98}-x^2+4^x=0[/tex]

Factor out -1:

[tex]\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0[/tex]

Divide both sides by -1:

[tex]\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0[/tex]

Rearrange the terms:

[tex]\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:[/tex]

[tex]\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0[/tex]

Factor the first two terms and the last two terms separately:

[tex]\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0[/tex]

Factor out the common term [tex](x^{98}-1)[/tex] :

[tex]\implies (4^x-x^2)(x^{98}-1)=0[/tex]

Zero Product Property:  If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the Zero Product Property, set each factor equal to zero and solve for x (if possible):

[tex]\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}[/tex]

Therefore, the solutions to the given equation are: x = 1 or x = -1

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Solve the system of equations by substitution.
x + y = A system of equations. StartFraction 3 over 8 EndFraction x plus StartFraction one-third EndFraction y equals StartFractions 17 over 24 EndFraction.
x + 7y = 8
(, )

Answers

A will have a value of 2. The value of A is found by the substitutional equation system.

What is the system of two equations?

A set of two linear equations with two variables is called a system of linear equations. They create a system of linear equations when evaluated collectively.

The given equation in the problem is;

Equation 1: [tex]\rm \frac{3}{8} + \frac{1}{3} y= \frac{17}{24}[/tex]

Equation 2: [tex]x+7y=8[/tex]

Rearrange equation 2 as;

x=8-7y

Substitute the value of x;

[tex]\rm \frac{3}{8} + \frac{1}{3} y= \frac{17}{24} \\\\ \frac{3}{8}(8-7y)+\frac{1}{3}y=\frac{17}{24} \\\\ \frac{-21}{8} y+\frac{1}{3} = \frac{17}{24}-3 \\\\ \frac{-63y+8y}{24}=\frac{17-72}{24}\\\\ \frac{-55 \ y}{24} = - \frac{55}{24}\\\\ y= 1[/tex]

Substitute the value of y in equation 2 as;

x+7y=8

x+7(1)+8

x=8-7

x=1

The system of equations by substitution obtained the value of A is;

x + y = A

1+1=A

A=2

Hence the value of A will be 2.

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what is 1,000,000,000 divided by -1,000

Answers

-1000000 that is the answer

hope this helps!

A man 1.8 m tall observes the angle of elevation of a tree to be 26 degrees, if he is standing bf 16 m from the tree find the height of the tree

Answers

The height of the tree is the man's height plus x.

[tex]\tan 26^{\circ}=\frac{x}{16}\\x = 16 \tan 26^{\circ}[/tex]

So, the height of the tree is [tex]\boxed{(16 \tan 26^{\circ}+1.8) \text{ m}}[/tex]

On a coordinate plane, a solid straight line has a negative slope and goes through (negative 2, 2) and (2, negative 8). Everything above and to the right of the line is shaded. The line has an equation of y greater-than-or-equal-to negative five-halves x minus 3.
Which linear equality will not have a shared solution set with the graphed linear inequality?

y > Two-fifthsx + 2
y < Negative five-halvesx – 7
y > Negative two-fifthsx – 5
y < Five-halvesx + 2

Answers

The linear inequality  [tex]y \leq 5/2(x + 2)[/tex] will not have a shared solution set with the graphed linear inequality. the correct option is D.

What is inequality?

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

On a coordinate plane, a solid straight line has a negative slope and goes through (-2, 2) and (2, -8).

m = (-8 -2)/ (2 +2)

m = -10/ 4

m = -5/2

The line has an equation of y greater-than-or-equal-to negative five-halves x minus 3.

[tex]y \geq -5/2 (x-3)[/tex]

The linear inequality  [tex]y \leq 5/2(x + 2)[/tex] will not have a shared solution set with the graphed linear inequality.

Thus, the correct option is D.

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Answer:

its b the guy above me is wrong

Step-by-step explanation:

If y varies inversely as x, and y = 58 when x = 9, find y when x = 261.

Answers

Answer:

y = 2

Step-by-step explanation:

Y varies indirectly with x (as x gets bigger, y gets smaller)

You have to find k, the constant of proportionality.

y = [tex]\frac{k}{x}[/tex]

Plus in the x & y values you are given

58 = [tex]\frac{k}{9}[/tex]  Multiply both sides by 9 to solve for k

k= 522

Now plug in the new value of x to solve for y

y = [tex]\frac{522}{261}[/tex]

y = 2


Put these types of angles in order, sta rting with the smallest angle size.
Smallest
Obtuse
Acute
Reflex
Right angle
Largest
<<<<
Update

Answers

Answer:

Acute, right angle, obtuse, reflex

Step-by-step explanation:

Answer:

Acute

right angle

obtuse

reflex angle

Step-by-step explanation:

Brian ordered 3 large cheese pizzas and a salad. The salad cost $4.95. If he spent a total of $47.60 including the $5 tip, how much did each pizza cost? (Considering there's no tax) Please I really need help

Answers

Answer:

Each pizza was $12.55.

Step-by-step explanation:

et's take it piece by piece.

Salad and the tip together is 4.95 + 5 = 9.95, right?

47.60 - 9.95 = 37.65 spent on pizza

37.65/3 = 12.55

PLEASE ANSWER ASAP!!!!!! WILL GIVE BRAINLIEST!!!

Answers

Answer ya so  1 is the answer

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

Given expression:

[tex]\sf \left(\dfrac{3a^{-2}b^6}{2a^{-1}b^5} \right)^2[/tex]

To find the value of the expression when a = 3 and b = -2, substitute these values into the expression:

[tex]\implies \sf \left(\dfrac{3(3)^{-2}(-2)^6}{2(3)^{-1}(-2)^5} \right)^2[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}[/tex]

[tex]\sf \implies \left(\dfrac{3\left(\dfrac{1}{3^2}\right)(-2)^6}{2\left(\dfrac{1}{3^1} \right)(-2)^5} \right)^2[/tex]

[tex]\sf \implies \left(\dfrac{3\left(\dfrac{1}{9}\right)(-2)^6}{2\left(\dfrac{1}{3} \right)(-2)^5} \right)^2[/tex]

[tex]\sf \implies \left(\dfrac{\left(\dfrac{3}{9}\right)(-2)^6}{\left(\dfrac{2}{3} \right)(-2)^5} \right)^2[/tex]

[tex]\sf \implies \left(\dfrac{\left(\dfrac{1}{3}\right)(-2)^6}{\left(\dfrac{2}{3} \right)(-2)^5} \right)^2[/tex]

[tex]\textsf{Apply exponent rule} \quad (-a)^n=a^n,\:\: \textsf{ if }n \textsf{ is even}[/tex]

[tex]\textsf{Apply exponent rule} \quad (-a)^n=-a^n,\:\: \textsf{ if }n \textsf{ is odd}[/tex]

[tex]\sf \implies \left(\dfrac{\left(\dfrac{1}{3}\right) (2^6)}{\left(\dfrac{2}{3} \right) (-(2^5))} \right)^2[/tex]

[tex]\sf \implies \left(\dfrac{\left(\dfrac{1}{3}\right) (64)}{\left(\dfrac{2}{3} \right) (-32)} \right)^2[/tex]

[tex]\sf \implies \left(\dfrac{\left(\dfrac{1 \times 64}{3}\right)}{\left(\dfrac{2 \times -32}{3} \right)} \right)^2[/tex]

[tex]\sf \implies \left(\dfrac{\dfrac{64}{3}}{\dfrac{-64}{3}} \right)^2[/tex]

When dividing fractions, flip the second fraction and multiply it by the first:

[tex]\implies \sf \left( \dfrac{64}{3} \times \dfrac {3}{-64} \right)^2[/tex]

[tex]\implies \sf \left( \dfrac{64 \times 3}{3 \times (-64)}\right)^2[/tex]

[tex]\implies \sf \left( \dfrac{192}{-192}\right)^2[/tex]

[tex]\implies \sf \left(-1\right)^2[/tex]

[tex]\textsf{Apply exponent rule} \quad (-a)^n=a^n,\:\: \textsf{ if }n \textsf{ is even}[/tex]

[tex]\sf \implies 1^2=1[/tex]

4. Angles A and B are supplementary. If mA = 67, find mB

Answers

Answer:

113 degrees

Step-by-step explanation:

Two angles are called supplementary when they add up to 180 degrees

[tex]180 = x + y \\ 180 = 67 + y \\ y = 180 - 67 \\ y = 113 \\ therefore \: mB \: = 113[/tex]

Type the correct answer in the box. Round off your answer to the nearest integer.
Angle A and Angle C are right angles. m

Answers

Answer:

59

Step-by-step explanation:

[tex] \sqrt{ {6}^{2} + {5}^{2} } = \sqrt{36 + 25} = \sqrt{61} [/tex]

[tex] \cos(p) = \frac{4}{ \sqrt{61} } [/tex]

[tex]p = {cos}^{ - 1} \frac{4}{ \sqrt{61} } = 59[/tex]

Make sure your calculator is in degree mode.

Graph the linear equation. Find three points that solve the equation, then plot on the graph.
-3x + 2y = 2

Answers

Step-by-step explanation:

I have done it go and check it once

2.
(07.02 LC)

Which statement is true for the equation 4x − 4x − 5 = −5? (5 points)

It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.

Answers

Im sure it is the last one. Hope it helps you out :)

-5/7 x 1/5

please help

Answers

-5/7 x 1/5

-5 x 1 = -5

7 x 5 = 35

-5/35 = -1/7

Happy to help :P

Solve |x| > -9.

1. no solution
2. all reals
3. {x | x < -9 or x > 9}

Answers

Answer:

2. All reals

Step-by-step explanation:

It covers everything as absolute value (distance from 0)

If you graph it you will see

Answer:  All reals

Reason:

Absolute value represents distance on a number line. Specifically it's the distance from x to 0.

For example, |-2| = 2 means -2 is 2 units away from 0.

Since |x| represents a distance, we cannot have negative distance. So |x| is either 0 or positive. Furthermore, it means |x| is larger than any negative value you pick.

Therefore, |x| > -9 is true for any x value and it's why we go for "all reals" (aka "all real numbers")

How do I solve the following system of inequalities graphically on the set of axes below?
y> x-3 y≥− 6/1 x+4

Answers

I don't know.

Thank you!!

What is value of x? Enter your answer in the box.​

Answers

Answer:

x = 10

Step-by-step explanation:

the ray is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides , that is

[tex]\frac{x+4}{2x +1}[/tex] = [tex]\frac{8}{12}[/tex] = [tex]\frac{2}{3}[/tex] ( cross- multiply )

2(2x + 1) = 3(x + 4) ← distribute parenthesis

4x + 2 = 3x + 12 ( subtract 3x from both sides )

x + 2 = 12 ( subtract 2 from both sides )

x = 10

which choice is equivalent to the the expression
square root of -64

Answers

The equivalent expression of square root of -64 is 8i

How to determine the equivalent expression?

We have:

square root of -64

Rewrite as:

√-64

Expand

√64 * √-1

Take the square root of 64

8√-1

In complex numbers

√-1  = i

So, we have:

8i

Hence, the equivalent expression of square root of -64 is 8i

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I WILL GIVE BRAINIEST PLS HELP

∠2 and ∠8 are _____________ because they are _______________________.

supplementary/consecutive angles

congruent/consecutive angles

congruent/alternate interior angles

supplementary/alternate interior angles

Answers

Answer:

congruent/alternate interior angles

Step-by-step explanation:

just took the quiz

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