Answer:38.9
Step-by-step explanation:
Help me please and thxx
Option C).
What is -8/15 of 21/12
Answer:
-14/15
Step-by-step explanation:
"of" means multiply, thus:
-8/15 * 21/12
-8 * 21 / 15 * 12
-2 * 7 / 15
-14/15
Answer:
-14/15
Step-by-step explanation:
So first you need to get rid of the negative sign. Don't worry you will add it back later!
So, you will do
-8/15×21/12
Once you cross cancel, you will have
-2/5x7/3
That would be equivalent to
-14/15
That's your answer!
Hope this helped :)
I WILL GIVE BRAINIEST PLS HELP
∠2 and ∠8 are _____________ because they are _______________________.
supplementary/consecutive angles
congruent/consecutive angles
congruent/alternate interior angles
supplementary/alternate interior angles
Answer:
congruent/alternate interior angles
Step-by-step explanation:
just took the quiz
In the Kite ABCD, AB = 5√2mm AP= 5mm, PD = 7mm, find the area to the nearest mm2.
The area of the kite ABCD will be 60 square millimeters.
What is Geometry?It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
In the Kite ABCD, AB = 5√2mm = 7.07 mm, AP= 5mm, PD = 7mm
Then the area of the kite ABCD will be
Area = 2(area of triangle APB and area of triangle APD)
The side length of PB will be
AB² = AP² + PB²
PB² = AB² – AP²
PB² = 7.07² – 5²
PB² = 50 – 25
PB² = 25
PB = 5 mm
Then the area will be
Area = 2[(1/2 × 7 × 5) + (1/2 × 5 × 5)]
Area = 60 square mm
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If y varies inversely as x, and y = 58 when x = 9, find y when x = 261.
Answer:
y = 2
Step-by-step explanation:
Y varies indirectly with x (as x gets bigger, y gets smaller)
You have to find k, the constant of proportionality.
y = [tex]\frac{k}{x}[/tex]
Plus in the x & y values you are given
58 = [tex]\frac{k}{9}[/tex] Multiply both sides by 9 to solve for k
k= 522
Now plug in the new value of x to solve for y
y = [tex]\frac{522}{261}[/tex]
y = 2
the sum of twice the number x and 25 more than three times the number y
Answer:
Correct expression:
[tex]2x + 3y + 25[/tex]
The graph of quadratic function f has zeros of -8 and 4 and a maximum at (-2,18). What is the value of a in the function’s equation?
To find the equation of a parabola given the vertex and the zeroes, we can use the intercept form equation to help us:
[tex]y=a(x-r)(x-s)[/tex]
r and s = intercepts/zeros of the graphSolving the QuestionWe're given:
Zeros: -8, 4Maximum: (-2, 18)[tex]y=a(x-r)(x-s)[/tex]
⇒ Plug in the given information:
[tex]y=a(x-(-8))(x-4)\\18=a(-2-(-8))(-2-4)\\18=a(-2+8)(-2-4)\\18=a(6)(-6)\\18=a(-36)\\1=-2a\\\\a=-\dfrac{1}{2}[/tex]
Answer[tex]a=-\dfrac{1}{2}[/tex]
What is the area of the figure?
Answer:
21.5
Step-by-step explanation:
break the shape down to make two shapes: a triangle and rectangle.
triangle = A=bxh/2
3x5=15/2=7.5
Rectangle = A=bxh
2x7=14
7.5+14= 21.5
Hope this helps :)
Answer:
21.5
Step-by-step explanation:
(all steps provided in image attached)
If the zeros of a quadratic equation are
7 and 4, what would be the factors?
Answer:
The factors are (x-7) and (x-4)
Step-by-step explanation:
We are finding the factors of a function from the zeros
The zeros are 7 and 4
We can use the zero product property which is
(x-b)(x-c) = 0 where b and c are the zeros
(x-7) (x-4) =0
The factors are (x-7) and (x-4)
You are working in a lab and you need a solution of 22% acid. In the cupboard, you find a 10% and a 30% solution, but not a 22% solution. You will have to make your own 22% solution. You will need liters of the 10% and liters of the 30% to make 15 liters of a 22% solution?
The volume of 10% solution will be 6 l and 9 litre of the 30 % solution will be taken.
What is Volume ?Volume is the space occupied by a three dimensional object .
The concentration of solution required is 22% acid
The concentration of solution available is 10% and 30%
The total volume required is 15 liters
The formula for making a mixture is
Concentration = ( m₁x₁ +m₂x₂) / (x₁+x₂)
22 = (10 * x + 30 *(15 -x))/( 15)
10 x + 450 - 30x =330
-20x = -120
x = 6
The volume of 10% solution will be 6 l
and 9 litre of the 30 % solution will be taken.
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Solve the system of equations by substitution.
x + y = A system of equations. StartFraction 3 over 8 EndFraction x plus StartFraction one-third EndFraction y equals StartFractions 17 over 24 EndFraction.
x + 7y = 8
(, )
A will have a value of 2. The value of A is found by the substitutional equation system.
What is the system of two equations?A set of two linear equations with two variables is called a system of linear equations. They create a system of linear equations when evaluated collectively.
The given equation in the problem is;
Equation 1: [tex]\rm \frac{3}{8} + \frac{1}{3} y= \frac{17}{24}[/tex]
Equation 2: [tex]x+7y=8[/tex]
Rearrange equation 2 as;
x=8-7y
Substitute the value of x;
[tex]\rm \frac{3}{8} + \frac{1}{3} y= \frac{17}{24} \\\\ \frac{3}{8}(8-7y)+\frac{1}{3}y=\frac{17}{24} \\\\ \frac{-21}{8} y+\frac{1}{3} = \frac{17}{24}-3 \\\\ \frac{-63y+8y}{24}=\frac{17-72}{24}\\\\ \frac{-55 \ y}{24} = - \frac{55}{24}\\\\ y= 1[/tex]
Substitute the value of y in equation 2 as;
x+7y=8
x+7(1)+8
x=8-7
x=1
The system of equations by substitution obtained the value of A is;
x + y = A
1+1=A
A=2
Hence the value of A will be 2.
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4. Angles A and B are supplementary. If mA = 67, find mB
Answer:
113 degrees
Step-by-step explanation:
Two angles are called supplementary when they add up to 180 degrees
[tex]180 = x + y \\ 180 = 67 + y \\ y = 180 - 67 \\ y = 113 \\ therefore \: mB \: = 113[/tex]
Please help solve for x..
Answer:
x = 1 or x = -1
Step-by-step explanation:
Given equation:
[tex]x^{100}-4^x \cdot x^{98}-x^2+4^x=0[/tex]
Factor out -1:
[tex]\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0[/tex]
Divide both sides by -1:
[tex]\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0[/tex]
Rearrange the terms:
[tex]\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:[/tex]
[tex]\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0[/tex]
Factor the first two terms and the last two terms separately:
[tex]\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0[/tex]
Factor out the common term [tex](x^{98}-1)[/tex] :
[tex]\implies (4^x-x^2)(x^{98}-1)=0[/tex]
Zero Product Property: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).
Using the Zero Product Property, set each factor equal to zero and solve for x (if possible):
[tex]\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}[/tex]
Therefore, the solutions to the given equation are: x = 1 or x = -1
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2.
(07.02 LC)
Which statement is true for the equation 4x − 4x − 5 = −5? (5 points)
It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.
which choice is equivalent to the the expression
square root of -64
The equivalent expression of square root of -64 is 8i
How to determine the equivalent expression?We have:
square root of -64
Rewrite as:
√-64
Expand
√64 * √-1
Take the square root of 64
8√-1
In complex numbers
√-1 = i
So, we have:
8i
Hence, the equivalent expression of square root of -64 is 8i
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How do I solve the following system of inequalities graphically on the set of axes below?
y> x-3 y≥− 6/1 x+4
sam and jose mowed 2/3 of the yard. jose mowed 3/4of that amount. whta part of the yard did jose mow?
Answer:
09
Step-by-step explanation:
34
On a coordinate plane, a solid straight line has a negative slope and goes through (negative 2, 2) and (2, negative 8). Everything above and to the right of the line is shaded. The line has an equation of y greater-than-or-equal-to negative five-halves x minus 3.
Which linear equality will not have a shared solution set with the graphed linear inequality?
y > Two-fifthsx + 2
y < Negative five-halvesx – 7
y > Negative two-fifthsx – 5
y < Five-halvesx + 2
The linear inequality [tex]y \leq 5/2(x + 2)[/tex] will not have a shared solution set with the graphed linear inequality. the correct option is D.
What is inequality?Inequality is defined as the relation which makes a non-equal comparison between two given functions.
On a coordinate plane, a solid straight line has a negative slope and goes through (-2, 2) and (2, -8).
m = (-8 -2)/ (2 +2)
m = -10/ 4
m = -5/2
The line has an equation of y greater-than-or-equal-to negative five-halves x minus 3.
[tex]y \geq -5/2 (x-3)[/tex]
The linear inequality [tex]y \leq 5/2(x + 2)[/tex] will not have a shared solution set with the graphed linear inequality.
Thus, the correct option is D.
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Answer:
its b the guy above me is wrong
Step-by-step explanation:
PLEASE ANSWER ASAP!!!!!! WILL GIVE BRAINLIEST!!!
Answer ya so 1 is the answer
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
Given expression:
[tex]\sf \left(\dfrac{3a^{-2}b^6}{2a^{-1}b^5} \right)^2[/tex]
To find the value of the expression when a = 3 and b = -2, substitute these values into the expression:
[tex]\implies \sf \left(\dfrac{3(3)^{-2}(-2)^6}{2(3)^{-1}(-2)^5} \right)^2[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}[/tex]
[tex]\sf \implies \left(\dfrac{3\left(\dfrac{1}{3^2}\right)(-2)^6}{2\left(\dfrac{1}{3^1} \right)(-2)^5} \right)^2[/tex]
[tex]\sf \implies \left(\dfrac{3\left(\dfrac{1}{9}\right)(-2)^6}{2\left(\dfrac{1}{3} \right)(-2)^5} \right)^2[/tex]
[tex]\sf \implies \left(\dfrac{\left(\dfrac{3}{9}\right)(-2)^6}{\left(\dfrac{2}{3} \right)(-2)^5} \right)^2[/tex]
[tex]\sf \implies \left(\dfrac{\left(\dfrac{1}{3}\right)(-2)^6}{\left(\dfrac{2}{3} \right)(-2)^5} \right)^2[/tex]
[tex]\textsf{Apply exponent rule} \quad (-a)^n=a^n,\:\: \textsf{ if }n \textsf{ is even}[/tex]
[tex]\textsf{Apply exponent rule} \quad (-a)^n=-a^n,\:\: \textsf{ if }n \textsf{ is odd}[/tex]
[tex]\sf \implies \left(\dfrac{\left(\dfrac{1}{3}\right) (2^6)}{\left(\dfrac{2}{3} \right) (-(2^5))} \right)^2[/tex]
[tex]\sf \implies \left(\dfrac{\left(\dfrac{1}{3}\right) (64)}{\left(\dfrac{2}{3} \right) (-32)} \right)^2[/tex]
[tex]\sf \implies \left(\dfrac{\left(\dfrac{1 \times 64}{3}\right)}{\left(\dfrac{2 \times -32}{3} \right)} \right)^2[/tex]
[tex]\sf \implies \left(\dfrac{\dfrac{64}{3}}{\dfrac{-64}{3}} \right)^2[/tex]
When dividing fractions, flip the second fraction and multiply it by the first:
[tex]\implies \sf \left( \dfrac{64}{3} \times \dfrac {3}{-64} \right)^2[/tex]
[tex]\implies \sf \left( \dfrac{64 \times 3}{3 \times (-64)}\right)^2[/tex]
[tex]\implies \sf \left( \dfrac{192}{-192}\right)^2[/tex]
[tex]\implies \sf \left(-1\right)^2[/tex]
[tex]\textsf{Apply exponent rule} \quad (-a)^n=a^n,\:\: \textsf{ if }n \textsf{ is even}[/tex]
[tex]\sf \implies 1^2=1[/tex]
Brian ordered 3 large cheese pizzas and a salad. The salad cost $4.95. If he spent a total of $47.60 including the $5 tip, how much did each pizza cost? (Considering there's no tax) Please I really need help
Answer:
Each pizza was $12.55.
Step-by-step explanation:
et's take it piece by piece.
Salad and the tip together is 4.95 + 5 = 9.95, right?
47.60 - 9.95 = 37.65 spent on pizza
37.65/3 = 12.55
Graph the linear equation. Find three points that solve the equation, then plot on the graph.
-3x + 2y = 2
Step-by-step explanation:
I have done it go and check it once
What is value of x? Enter your answer in the box.
Answer:
x = 10
Step-by-step explanation:
the ray is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides , that is
[tex]\frac{x+4}{2x +1}[/tex] = [tex]\frac{8}{12}[/tex] = [tex]\frac{2}{3}[/tex] ( cross- multiply )
2(2x + 1) = 3(x + 4) ← distribute parenthesis
4x + 2 = 3x + 12 ( subtract 3x from both sides )
x + 2 = 12 ( subtract 2 from both sides )
x = 10
-5/7 x 1/5
please help
-5/7 x 1/5
-5 x 1 = -5
7 x 5 = 35
-5/35 = -1/7
Happy to help :P
Solve |x| > -9.
1. no solution
2. all reals
3. {x | x < -9 or x > 9}
Answer:
2. All reals
Step-by-step explanation:
It covers everything as absolute value (distance from 0)
If you graph it you will see
Reason:
Absolute value represents distance on a number line. Specifically it's the distance from x to 0.
For example, |-2| = 2 means -2 is 2 units away from 0.
Since |x| represents a distance, we cannot have negative distance. So |x| is either 0 or positive. Furthermore, it means |x| is larger than any negative value you pick.
Therefore, |x| > -9 is true for any x value and it's why we go for "all reals" (aka "all real numbers")
Type the correct answer in the box. Round off your answer to the nearest integer.
Angle A and Angle C are right angles. m
Answer:
59
Step-by-step explanation:
[tex] \sqrt{ {6}^{2} + {5}^{2} } = \sqrt{36 + 25} = \sqrt{61} [/tex]
[tex] \cos(p) = \frac{4}{ \sqrt{61} } [/tex]
[tex]p = {cos}^{ - 1} \frac{4}{ \sqrt{61} } = 59[/tex]
Make sure your calculator is in degree mode.
Put these types of angles in order, sta rting with the smallest angle size.
Smallest
Obtuse
Acute
Reflex
Right angle
Largest
<<<<
Update
Answer:
Acute, right angle, obtuse, reflex
Step-by-step explanation:
Answer:
Acute
right angle
obtuse
reflex angle
Step-by-step explanation:
3x squared + 6 x cube - 9x squared y when factorused
[tex]3x ^{2} \: + \: {6x}^{3} \: - \: 9 {x}^{2} y[/tex]
Factor the expression with the common factor that is "3x²".[tex] \boxed{ \bold{3 {x}^{2} \: \times \: (1 \: + \: 2x \: - \: 3y)}}[/tex]
MissSpanishAnswer:
[tex]\boxed{3x²(1 + 2x - 3y)}[/tex]
Step-by-step explanation:
3x squared + 6 x cube - 9x squared y
To factor
Solution:
A process when algebraic expression is expressed as a product of two or more expressions is factorisation.
ATP,
Square = a²
Cube = a³
3x² + 6x³ - 9x²yWe can see that 3x^2 is common in this expression.
So rewrite as:
[tex]3x²(1 + 2x - 3y)[/tex]Done!
what is 1,000,000,000 divided by -1,000
-1000000 that is the answer
hope this helps!
A man 1.8 m tall observes the angle of elevation of a tree to be 26 degrees, if he is standing bf 16 m from the tree find the height of the tree
The height of the tree is the man's height plus x.
[tex]\tan 26^{\circ}=\frac{x}{16}\\x = 16 \tan 26^{\circ}[/tex]
So, the height of the tree is [tex]\boxed{(16 \tan 26^{\circ}+1.8) \text{ m}}[/tex]
experimental verification
See below for the verification of ∠ACD = ∠ABC + ∠BAC
How to verify the angles?The following proof works for both triangles.
The sum of angles in a triangle is 180 degrees.
So, we have:
∠ABC + ∠BAC + ∠ACB = 180
Make ∠ACB the subject
∠ACB = 180 - ∠ABC - ∠BAC
The sum of angles on a straight line is 180 degrees.
So, we have:
∠ACD + ∠ACB = 180
Make ∠ACB the subject
∠ACB = 180 - ∠ACD
Substitute ∠ACB = 180 - ∠ACD in ∠ACB = 180 - ∠ABC - ∠BAC
180 - ∠ACD = 180 - ∠ABC - ∠BAC
Subtract 180 from both sides
- ∠ACD = - ∠ABC - ∠BAC
Multiply both sides by -1
∠ACD = ∠ABC + ∠BAC
Hence, ∠ACD = ∠ABC + ∠BAC has been verified
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