Saima travels 2.5 km in 21.2 seconds. What as Saima's initial speed if her final velocity is 10.7 m/s?

Answer:

34.104

Explanation:

the time * acceleration = final velocity.

so 3.48s * 9.8m/s (gravity) = 34.1 m/s

Answer:

A

Explanation:

Một đại lượng vectơ là một lực. Đại lượng vectơ là đại lượng có cả độ lớn và hướng, như chúng ta đã dạy trong phần trước. Bạn phải xác định cả độ lớn (kích thước hoặc số) và hướng của lực tác dụng lên một vật thể để mô tả hoàn toàn nó.

Answer:

I think it's D) the Coriolis Effect

Explanation:

Answer: THE ANSWER IS D) the Coriolis effect.

Explanation: I GOT A 100 ON THE TEST

Answer:

The answer is False

Answer:

50km/hour

Explanation:

the average speed and the speed are the same

speed- the rate something moves or operates

Can I have brainlist please

The Speed are distance covered by the object in unit time.The S.I unot of speed is metre per second written as m/sec.It is a scalar quantity.

The speed is measured in metres per second ( ms- ¹ )

Where denoted by s

The distance travelled is measured in metres (m) and denoted by d

t is the amount of time spent and measured in seconds s

Answer:

A. Fusion Reactions

Explanation:

Answer:

add 44m/s and 22m/s then multiply it by 11

Explanation:

A race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds, Acceleration is -2 m/s² (deceleration), and distance is 242 meters.

To solve this problem, it is given:

Initial velocity ([tex]\(v_i\)[/tex] ) = 44 m/s

Final velocity ([tex]\(v_f[/tex] ) = 22 m/s

Time ([tex]\(t\)[/tex] ) = 11 s

We have two tasks: finding the acceleration (a) and then using it to calculate the distance (d).

1. Calculate Acceleration (a):

[tex]\[a = \frac{v_f - v_i}{t} \\\\= \frac{22 \, \text{m/s} - 44 \, \text{m/s}}{11 \, \text{s}} \\\\= -2 \, \text{m/s}^2\][/tex]

The negative sign indicates deceleration (slowing down).

2. Calculate Distance (d):

Using the kinematic equation:

[tex]\[d = v_i \cdot t + \frac{1}{2} \cdot a \cdot t^2\][/tex]

Plugging in the values:

[tex]\[d = (44 \, \text{m/s}) \cdot (11 \, \text{s}) + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (11 \, \text{s})^2\][/tex]

Calculating the first part:

[tex]\[d = 484 \, \text{m} - 121 \, \text{m} \\\\= 363 \, \text{m}\][/tex]

Calculating the second part:

[tex]\[d = 363 \, \text{m} + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (121 \, \text{s}^2) \\\\= 363 \, \text{m} - 121 \, \text{m} \\\\= 242 \, \text{m}\][/tex]

The total distance the race car moves during this time is 242 meters.

Thus, acceleration is -2 m/s² (deceleration), and distance is 242 meters.

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The answer is D

I took the quiz lol

Answer:

seismic waves

Explanation:

i think thats the answer

The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.

We have to find the acceleration using;

v = u - at

v = final velocity = 0 m/s

u = initial velocity = 35.6m/s

a = acceleration = ?

t = time = 0.35 s

u = at

a = u/t = 35.6m/s / 0.35 s

a = 101.7 ms-2

The force on the driver =  75kg ×  101.7 ms-2 = 7629 N

Using the principle of conservation of momentum;

Momentum before collision = momentum after collision

m1u1 +m2u2 = m1v1 + m2v2

Hence

(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2

13.12 = 4.8 + 2.3v2

13.12 - 4.8 = 2.3v2

v2 = 13.12 - 4.8/2.3

v2 = 3.6 m/s

Using the principle of conservation of linear momentum;

m1u1 + m2u2 = m1v1 + m2v2

(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v

v = 79.98 + 55.1/10.1

v = 13.37 m/s

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Answer:

i think its A

Explanation:

I hope this helps :)

Answer:

A Wave red

Explanation:

Answer:

Answer: Wave E

Explanation:

Why because if you put each in a strait line it would have been longer

hope it helps

The fundamental frequency, wavelength of the wave, and mass per unit

length of the string, determines the tension in the string.

Reasons:

From a similar question, we have;

Fundamental frequency, f₁ = 146.8 Hz

Oscillating length on the D-string, λ₁ = 0.61 m

Mass of the string = 1.5 × 10⁻³ kg.

We have;

[tex]\displaystyle f_1 \cdot \lambda _1 =\mathbf{ \sqrt{\frac{T}{m/L} }}[/tex]

Therefore;

[tex]\displaystyle T = \mathbf{\frac{f_1^2 \cdot \lambda _1^2 \cdot m }{L}}[/tex]

Which gives;

[tex]\displaystyle T = \frac{146.8^2 \times 0.61^2 \times 1.5 \times 10^{-3} }{0.61 } \approx \mathbf{19.718}[/tex]

The tension to which the D-string must be tuned, T ≈ 19.718 Newtons

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The parameters given in a similar question obtained online are;

The fundamental frequency of the tone, f₁ = 146.8 Hz

The oscillating length on the D-string, λ₁ = 0.61 m

The mass of the string = 1.5 × 10⁻³ kg.

The car accelerates 60 mph in 6.3 seconds. Thus, the acceleration is [tex]\frac{60}{6.3}[/tex]. [tex]f=ma[/tex], so [tex]4106 = m(\frac{60}{6.3})[/tex], so [tex]m=431.13[/tex].

Answer:

D: The ability to do work or cause change.

Explanation:

Energy can be defined as the ability to do work. We apply energy in basically everything we do in life, energy is needed to walk or move from one position to another, it is required to eat and do other basic things of life. The body system converts the food that is being consumed into energy, this energy can be switched from one form to another.

There are various forms of energy which include solar energy, wind energy, electrical energy, mechanical energy, kinetic energy, potential energy, etc. This form of energy can be converted from one form to another but cannot be destroyed.

Hope this helps :)

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{35}{5200} = 0.006730 \\ [/tex]

We have the final answer as

Hope this helps you

The acceleration of both the rocks is only due to the gravitational force acting on them. Even though the speed of thrown rock would be greater than that of dropped rock, the acceleration of both the rocks would be g downwards.

Answer:

1.80

Explanation:

38.4=-12.5(a)-1/2(-9.80)(a)^2

a= acceleration
^2 is the exponent

Answer:

I can't see the picture, can you right down the same thing that is the picture in the comments so I can help you.

Explanation:

Thx.

Answer:

Fundamental quantities

Answer:

No

Explanation:

It doesn't depend on the density

Answer:No. If you take all your masses and and squeeze them into a tiny volume,

The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

The impulse experienced by the ball is calculated as follows;

[tex]Ft = \Delta P[/tex]

where;

[tex]Ft[/tex] is impulse

[tex]\Delta P[/tex] is change in momentum

The time of motion of the ball is calculated as follows;

[tex]t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s[/tex]

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

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Using the appropriate arithmetic operation, the amount of potatoes and cabbage require for the voyage are 19998 and 26664 respectively.

Total number of passengers = (47 + 32 + 22) = 101

1.)

If each person gets 3 potatoes per day :

Number of potatoes needed per day = (3×101) = 303

Number of potatoes needed for entire voyage = (303 × 66) = 19998 potatoes.

2.)

If each person gets 4 cabbage per day :

Number of cabbage needed per day = (4×101) = 404

Number of cabbage needed for entire voyage = (404 × 66) = 26664 cabbages.

Hence, the number of cabbage needed for the voyage would be 26664 cabbages.

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Answer: Juvenile fish go through various stages between birth and adulthood. When they have developed to the point where they are capable of feeding themselves, the fish are called fry. When, in addition, they have developed scales and working fins, the transition to a juvenile fish is complete and it is called a fingerling.

Explanation:

Correct option is

B

−3m/s

2

Given,

m=10kg

u=10m/s

v=−2m/s

t=4sec

The acceleration is rate of change of velocity,

a=

t

v−u

a=

4

−2−10

a=

4

−12

=−3m/s

2

The correct option is B.

Answer:

1.84 kJ  (kilojoules)

Explanation:

A specific heat of 0.46 J/g Cº means that it takes 0.46 Joules of energy to raise the temperature of 1 gram of iron by 1 Cº.

If we want to heat 50 g of iron from 20° C to 100° C, we can make the following calculation:

Heat = (specific heat)*(mass)*(temp change)

Heat = (0.46 J/g Cº)*(50g)*(100° C -  20° C)

[Note how the units cancel to yield just Joules]

Heat = 1840 Joules, or 1.84 kJ

[Note that the number is positive:  Energy is added to the system.  If we used cold iron to cool 50g of 100° C water, the temperature change would be (Final - Initial) or (20° C - 100° C).  The number is -1.84 kJ:  the negative means heat was removed from the system (the iron).

Answer:

it states that energy can either be gained or lost but it only changes its form.

Explanation:

for example:as a ball is still on the table it posses a potential energy of 100j and a k.e of 0j,as it falls it gains k.e so the midpoint the p.e is equal to the k.e (50j equally) as it approches the ground it completely gains k.e (100j) and the p.e is 0j.

total energy is 100j so it has been converted from p.e to k.e.

hope u have understood.