Sam theows a ball up into the air and watches it come down. The equation for the height, h, in relation to time,t , is h=5f^2+25t. What is the range for height of the ball

Answers

Answer 1

Answer:

h = 5t²+ 25t

from projectiles

h = u²sin²∆ / 2g

taking the angle to be ∆

and range is u²sin2∆/g

Therefore integrate the equation h= 5t²+25t

R = 5t³/3 + 25t²/2 + t


Related Questions

Need help asap!!!!

Determine the measure of the unknown angle or arc. Show your work.

Answers

28.

Arc BC = 107 degrees

---Since the given angle is on the center of the circle, the arc has the same measure.

Angle BAC = 53.5 degrees

---Since this is an inscribed angle, the measure of the angle is half of the corresponding arc.

29.

Arc BC = 92 degrees

---Since we are given an inscribed angle, the corresponding arc is double the measure of the angle.

Hope this helps!

The following chart is data over an 8-month period that shows how much a company spent in advertising and the sales revenue for that month

MONTH

ADVERTISING $

SALES $

March

900

56000

April

2700

89200

May

3150

98500

June

1300

54000

July

3400

97000

Aug

1500

56000

Sept

2300

93000

Oct

2250

79000

What is the correlation coefficient? (round to 2 decimals) describe how you utilized excel to arrive at this number (recommended) or show the formula you utilized to arrive at this answer

Is it a positive or negative correlation?

Would you say it is a strong correlation, weak correlation, or no correlation? What is the indicator that led you to that conclusion?

What is the linear equation (y = mx + b form) that best approximates the relationship between advertising dollars spent(x) and sales revenue(y) based on the above 8 months of data? (round to 2 decimals for the slope and the y intercept) describe how you utilized excel to arrive at this equation (recommended) or show the formula you utilized to arrive at your equation

What sales revenue would the company expect for the following advertising spending? Round to nearest cent show calculation

3000

2100

1300

If you were in charge of the advertising department how much would you spend on each of the next 4 months on advertising and how and why did you arrive at your decision?

Nov

Jan

Feb

March

Please give a brief explanation as to how and why you came up with your advertising spending for the above 4 months.

Answers

To calculate the correlation coefficient, we can use Excel's CORREL function or we can use the following formula:

r = (n Σ(xy) - Σx Σy) / sqrt[(n Σx^2 - (Σx)^2) (n Σy^2 - (Σy)^2)]

where n is the number of data points, Σ represents the sum of the values, x and y are the variables (advertising and sales), and xy is the product of x and y for each data point.

Using Excel's CORREL function, we get a correlation coefficient of 0.92. This indicates a strong positive correlation between advertising spending and sales revenue.

The linear equation that best approximates the relationship between advertising dollars spent(x) and sales revenue(y) can be found using Excel's LINEST function or we can use the following formula:

y = mx + b

where m is the slope (change in y divided by change in x) and b is the y-intercept (the point where the line intersects the y-axis).

Using Excel's LINEST function, we get the equation: y = 20.49x + 43720.61

Therefore, the slope (m) is 20.49 and the y-intercept (b) is 43720.61.

To calculate the expected sales revenue for the given advertising spending, we can use the linear equation:

For 3000: y = 20.49(3000) + 43720.61 = 98910.61
For 2100: y = 20.49(2100) + 43720.61 = 83842.60
For 1300: y = 20.49(1300) + 43720.61 = 58706.58

If I were in charge of the advertising department, I would consider the trend in the data and set advertising spending for each month based on the linear equation. Assuming that the trend in advertising spending and sales revenue continues, I would spend the following amounts on advertising for the next 4 months:

Nov: $2,100
Jan: $2,250
Feb: $2,500
March: $2,750

I arrived at these values by extrapolating from the trend in the data, while also taking into account the available budget and any external factors that may affect sales. By gradually increasing the advertising spending, I would aim to maximize sales while minimizing costs.

25
The concert that Georgia wants to go to offers discounted tickets to groups that buy
more than 12 tickets. Georgia doesn't know what the discount on the tickets will be,
but she knows each ticket will cost less than the regular price of a ticket to the
concert, $9.50. Which statement is true?
A
B
C
D
The inequality that represents the number of tickets, t, Georgia can buy at the
discounted price is t > 12.
The inequality that represents the number of tickets, t, Georgia can buy at the
discounted price is t < 9.50.
The inequality that represents the price, p, of each of the discounted tickets
is p < 12.
The inequality that represents the price, p, of each of the discounted tickets
is p > 9.50.

Answers

The correct statement is D. The inequality that represents the price, p, of each of the discounted tickets is p > 9.50.

Georgia wants to go to a concert.

The concert offers discounted tickets to groups that buy more than 12 tickets.

The price of each discounted ticket is less than the regular price of $9.50.

Now, let's break down each statement:

A. The inequality that represents the number of tickets, t, Georgia can buy at the discounted price is t > 12.

This statement is not necessarily true based on the information given. We know that the concert offers discounted tickets to groups that buy more than 12 tickets, but it doesn't provide any information about the maximum number of tickets Georgia can buy at the discounted price. The number of tickets Georgia can purchase could be more or less than 12.

B. The inequality that represents the number of tickets, t, Georgia can buy at the discounted price is t < 9.50.

This statement is incorrect. The inequality t < 9.50 doesn't make sense in this context because it implies that the number of tickets Georgia can buy is less than the price of a ticket, which is not relevant.

C. The inequality that represents the price, p, of each of the discounted tickets is p < 12.

This statement is incorrect as well. The inequality p < 12 suggests that the price of each discounted ticket is less than 12, but we don't have any information about the exact discount amount or the range of prices for the discounted tickets.

D. The inequality that represents the price, p, of each of the discounted tickets is p > 9.50.

This is the correct statement. We know that each discounted ticket costs less than the regular price of $9.50. Therefore, the price of each discounted ticket, represented by p, must be less than $9.50. Hence, the correct inequality is p < 9.50, or equivalently, p > 9.50.

In summary, the correct statement is D. The inequality that represents the price, p, of each of the discounted tickets is p > 9.50.

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Please please please help!!

Match these:

Common internal tangent
point of tangency
Center
chord
secant
diameter
common external tangent
radius
semi-cirele
Major arc
Minor arc

Answers

From the figure, the blanks are filed as follows

Common internal tangent: is matched to line HJ

point of tangency: is matched to G

Center: is matched to A

chord: is matched to line GK

secant: is matched to line CD

diameter: is matched to line EF

common external tangent = line KF

radius: is matched to line BF

semi-circle = arc EGF

Major arc: is matched to arc CDK

Minor arc: is matched to arc CK

What is point of tangency?

In geometry the point of tangency is the point where a line or curve touches a circle or other curved shape at exactly one point without crossing over or intersecting it at another point.

At the point of tangency the tangent line is perpendicular to the radius of the circle that intersects it.

In the figure, the point of tangency is at F E G and K

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17. Write the equation of a line that is perpendicular to the given line and that passes through the
given point.

Answers

Answer:

y = 5x + 17

Step-by-step explanation:

gradient of perpendicular = - 1/ (-1/5) = - (-5) = 5.

equation of line, gradient 5, through (-2, 7) is

y - 7 = 5 (x - -2) = 5 (x + 2) = 5x + 10

y = 5x + 10 + 7

y = 5x + 17

if y=sin x² cot 2x. find dy/dx​

Answers

The expression y = sin(x²) cot(2x) when differentiated is 2xcot(2x)cos(x²) - 2csc²(2x)sin(x²)

How to differentiate the expression

From the question, we have the following parameters that can be used in our computation:

y=sin x² cot 2x

Express properly

So, we have the following representation

y = sin(x²) cot(2x)

When each term of the expression are differentiated using the first principle and the product rule, we have

sin(x²) ⇒ 2xcot(2x)cos(x²)

cot(2x) ⇒ -2csc²(2x)sin(x²)

So, the solution is 2xcot(2x)cos(x²) - 2csc²(2x)sin(x²)

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In ΔPQR, sin P = 0.5, sin R = 0.3 and r = 13. Find the length of p.

Answers

The length of side p is approximately 21.67

In triangle PQR, we are given the values of sin P, sin R, and the length of side r. We need to find the length of side p.

We can use the law of sines to solve this problem. The law of sines states that the ratio of the length of a side of a triangle to the sine of the opposite angle is constant. Mathematically, it can be represented as:

p / sin P = r / sin R

Plugging in the given values, we have:

p / 0.5 = 13 / 0.3

Cross-multiplying, we get:

0.3p = 13 * 0.5

0.3p = 6.5

Dividing both sides by 0.3, we find:

p ≈ 21.67

Therefore, the length of side p is approximately 21.67.

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Consider a Poisson probability distribution with λ = 5.1. Determine the following probabilities.
a) exactly 5 occurrences
b) more than 6 occurrences
c) 3 or fewer occurrences
Click the icon to view a partial table of Poisson probabilities.
a) The probability of exactly 5 occurrences is
(Round to four decimal places as needed.)

Answers

The probability of exactly 5 occurrences is (Rounding to three Decimal places), we get P(X ≤ 3) ≈ 0.251.

a) The probability of exactly 5 occurrences is given by the Poisson probability mass function:

P(X = 5) = (e^(-λ) * λ^5) / 5! = (e^(-5.1) * 5.1^5) / 120 ≈ 0.1755

Rounding to four decimal places, we get P(X = 5) ≈ 0.1755.

b) The probability of more than 6 occurrences can be calculated as the complement of the probability of 6 or fewer occurrences:

P(X > 6) = 1 - P(X ≤ 6) = 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6))

Using the Poisson probability mass function and the given value of λ, we can calculate each of the probabilities:

P(X = 0) ≈ 0.006

P(X = 1) ≈ 0.031

P(X = 2) ≈ 0.079

P(X = 3) ≈ 0.135

P(X = 4) ≈ 0.174

P(X = 5) ≈ 0.1755

P(X = 6) ≈ 0.1493

Substituting these values into the formula, we get:

P(X > 6) ≈ 1 - (0.006 + 0.031 + 0.079 + 0.135 + 0.174 + 0.1755 + 0.1493) ≈ 0.249

Rounding to three decimal places, we get P(X > 6) ≈ 0.249.

c) The probability of 3 or fewer occurrences is given by the cumulative distribution function:

P(X ≤ 3) = ∑ P(X = k), for k = 0, 1, 2, 3.

Using the Poisson probability mass function and the given value of λ, we can calculate each of the probabilities:

P(X = 0) ≈ 0.006

P(X = 1) ≈ 0.031

P(X = 2) ≈ 0.079

P(X = 3) ≈ 0.135

Adding these probabilities, we get: P(X ≤ 3) ≈ 0.251

Rounding to three decimal places, we get P(X ≤ 3) ≈ 0.251.

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What is the five-number summary for {34, 47, 51, 11, 7, 9, 13, 49, 22}?

Answers

Answer:

47
Step-by-step explanation:

Choose the correct answers given the following table representing a quadratic function. Complete Steps 1-2 in order.

Please See images to Answer Problems

X: 2, 6, 7, 9
Y: 12, -4, -3, 5

1. Find the other zero of the function given that one zero is 4. (image 1.1)
2. Choose the correct graph of the quadratic function represented in the table. (image 1.2 & 1.2.2)

Answers

The other zero of the function given that one zero is 4 include: B. 8.

The correct graph of the quadratic function represented in the table is: graph A.

What is a quadratic function?

In Mathematics and Geometry, the standard form of a quadratic function is represented by the following equation;

ax² + bx + c = 0

Next, we would create a system of equation by using the data points provided in the table above;

a(2)² + b(2) + c = 12

4a + 2b + c = 12     .....equation 1.

a(6)² + b(6) + c = -4

36a + 6b + c = -4     .....equation 2.

a(7)² + b(7) + c = -3

49a + 7b + c = -3     .....equation 3.

By solving the system of equations simultaneously, the values of a, b, and c are as follows;

a = 1

b = -12

c = 32

Therefore, the required quadratic function is given by;

ax² + bx + c = 0

x² - 12x + 32 = 0

x² - 8x - 4x + 32 = 0

x(x - 8) - 4(x - 8) = 0

(x - 4)(x - 8) = 0

x = 4 or x = 8

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Question
A group consisting of 10 children and adults went to a movie theater. Children's tickets cost $5 each and adults' tickets cost $8 each, and the total cost for the 10 people was $62. How many children were in the group?

Answers

The answer should be 6 children.

Answer:

There are 6 children in the group and 4 adults

Step-by-step explanation:

Because the adult ticket cost $8, so there are 4 adults and a total of $32 for adults.

Then I took 62-32=$30

$30 (total for children price) / $5 (the children's tickets) = 6 children

Someone please help me.

Answers

Answer:

the correct answer is the fifth one 1-3x

find the next three terms in the sequence 0, 3 ,8, 15 ,24,....​

Answers

Answer: 35, 48, 63

Step-by-step explanation:

This sequence is known as an arithmetic progression sequence.

      3 - 0 = 3

      8 - 3 = 5

      15 - 8 = 7

      24 - 15 = 9

Using this pattern, we will add 11 to 24 for the next term in the sequence. Then, we will continue this pattern for the next two terms.

➜ The pattern is resulting odd numbers from subtracting two terms in a row; 3, 5, 7, 9, [11], [13], [15].

      24 + 11 = 35

      35 + 13 = 48

      48 + 15 = 63

Find the value of x.
132⁰
106°
819

X =

Answers

Answer:

Step-by-step explanation:

132 + 106 + 81 + x = 360

319 + x = 360

x = 41

132 + 106 + 81 + X =360°
X=41

You are interested in constructing a 90% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 423 randomly selected caterpillars observed, 52 lived to become butterflies. a. With 90% confidence the proportion of all caterpillars that lived to become a butterfly is between and .

Answers

To construct a confidence interval for the proportion of all caterpillars that lived to become a butterfly, we can use the following formula:

Confidence interval = sample proportion ± margin of error

where the sample proportion is the number of caterpillars that lived to become a butterfly divided by the total number of observed caterpillars, and the margin of error is calculated using the following formula:

Margin of error = critical value × standard error

The critical value can be found using a z-table or calculator, and is based on the level of confidence and the degrees of freedom (which is n - 1 for a proportion). For a 90% confidence interval with 422 degrees of freedom, the critical value is approximately 1.645.

The standard error can be calculated using the following formula:

Standard error = sqrt((sample proportion × (1 - sample proportion)) / sample size)

Plugging in the values we have, we get:

Sample proportion = 52 / 423 = 0.123
Standard error = sqrt((0.123 × (1 - 0.123)) / 423) = 0.024

So the margin of error is:

Margin of error = 1.645 × 0.024 = 0.039

Therefore, the 90% confidence interval for the proportion of all caterpillars that lived to become a butterfly is:

0.123 - 0.039 < p < 0.123 + 0.039

0.084 < p < 0.162

So with 90% confidence, the proportion of all caterpillars that lived to become a butterfly is between 0.084 and 0.162.

Therefore, the answer is between 0.084 and 0.162.

Craig invests $800 into an account with a 2.5% interest rate that is compounded quarterly. How much money will he have in this account if he keeps it for 10 years?

Answers

First you have to take 800 and multiply it by 1.025 ten times so after doing the calculations you end up with 1,024.06 after rounding

PLEASE HELP!!
A ball is thrown into the air with an initial velocity of 16 ft/sec and an initial height of 96 feet. Given the position function, answer the following. s(t)= -16t^2 + 16t + 96

Answers

part a.

The average velocity on the interval [0,2] is -16 ft/sec

part b.

The instantaneous velocity when t=2  is found as -48 ft/sec

part c.

Time taken to reach the ground is 3 seconds.

part d.

velocity of the ball when it hits the ground is found as  80 ft/sec downward.

How do we calculate?

The average velocity on the interval [0,2] is determined by :

average velocity = change in distance / change in time

change in distance :

s(2) - s(0) = (-16(2)^2 + 16(2) + 96) - (-16(0)^2 + 16(0) + 96) = -32

where the change in time:

2 - 0 = 2

average velocity = -32/2

average velocity = -16 ft/sec

b. The instantaneous velocity :

s'(t) = -32t + 16

and  t=2:

s'(2) = -32(2) + 16 =

s'(2)=  -48 ft/sec

the velocity of the ball when it hits the ground is at time = 3

s'(t) = -32t + 16

s'(3) = -32(3) + 16 =

s'(3)  =  -80 ft/sec

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Triangle xyz has vertices x(-2,1), y(3,-1) and z(1,4) what are the vertices of its image after a dialation with a scale factor of 4

Answers

The vertices of the triangle XYZ after a dilation with a scale factor of [tex]4[/tex] are [tex]X'(-8, 4)[/tex], [tex]Y'(12, -4)[/tex], and [tex]Z'(4, 16)[/tex].

To find the vertices of the image after a dilation with a scale factor of [tex]4[/tex], we need to multiply the coordinates of each vertex by the scale factor.

Given the triangle with vertices [tex]X(-2,1), Y(3,-1), and \ Z(1,4)[/tex], we can apply the dilation to each vertex.

Let's start with vertex [tex]X(-2,1)[/tex]:

The new x-coordinate,[tex]\(x'\)[/tex], can be obtained by multiplying the original x-coordinate by the scale factor: [tex]\(x' = 4 \times (-2) = -8\)[/tex].

Similarly, the new y-coordinate, [tex]\(y'\)[/tex], is obtained by multiplying the original y-coordinate by the scale factor: [tex]\(y' = 4 \times 1 = 4\)[/tex].

Thus, the image of vertex X is [tex]X'(-8, 4)[/tex].

Now let's apply the same process to vertices [tex]Y(3,-1) \ and \ Z(1,4):[/tex]

For vertex Y:

[tex]\(x' = 4 \times 3 = 12\)\\\y' = 4 \times (-1) = -4\)[/tex]

The image of vertex Y is Y'(12, -4).

For vertex Z:

[tex]\(x' = 4 \times 1 = 4\)\\\(y' = 4 \times 4 = 16\)[/tex]

The image of vertex Z is [tex]Z'(4, 16)[/tex].

Therefore, the vertices of the triangle XYZ after a dilation with a scale factor of [tex]4[/tex] are [tex]X'(-8, 4)[/tex], [tex]Y'(12, -4)[/tex], and [tex]Z'(4, 16)[/tex].

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Using the box-and-whisker plot shown, find the maximum, minimum, and median values.

maximum = 4, minimum = –4, median = 0

maximum = 6, minimum = –4, median = 4

maximum = 8, minimum = –4, median = 6

maximum = 8, minimum = –8, median = 4

Answers

The maximum, minimum, and median values include the following: D. maximum = 8, minimum = –8, median = 4.

What is a box-and-whisker plot?

In Mathematics and Statistics, a box plot is sometimes referred to as box-and-whisker plot and it can be defined as a type of chart that can be used to graphically or visually represent the five-number summary of a data set with respect to locality, skewness, and spread.

Based on the information provided about the data set, the five-number summary for the given data set include the following:

Minimum (Min) = -8.

First quartile (Q₁) = -4.

Median (Med) = 4.

Third quartile (Q₃) = 6.

Maximum (Max) = 8.

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50
Select the correct answer.
S
The spread of data set X is greater than the spread of data set Y, and the data sets are normally distributed. Which statement is true?
OA. The mean of data set X is greater than the mean of data set Y.
The median of data set X is less than the median of data set Y.
The standard deviation of data set X is greater than the standard deviation of data set Y.
The range of data set X is less than the range of data set Y.
The mode of data set X is greater than the mode of data set Y.
B.
O C.
O D.
OE
entum. All rights reserved.
Reset
Next

Answers

If the spread of data set X is greater than the spread of data set Y, and the data sets are normally distributed. The statement that  is true is: C. The standard deviation of data set X is greater than the standard deviation of data set Y.

What is data set?

A data set standard deviation is often used to calculate its spread. As a result the standard deviation of data set X will be higher than the standard deviation of data set Y if the spread of data set X is bigger than the spread of data set Y.

The standard deviation may or may not have the same distribution as the the following :

The  meanThe medianThe  range and mode based on the fact that they are not directly related to the dispersion of a data collection.

Therefore the correct option is C.

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Determine tan (A) and tan (B).

Answers

Answer:

tan (A) = 1/2. tan (B) = 2

Step-by-step explanation:

tan θ = opposite/adjacent

for tan(A), the opposite is 5. adjacent is 10. hypotenuse is 5√5.

tan (A) = 5/10 = 1/2.

for tan (B), the opposite is 10, adjacent is 5. hypotenuse is 5√5.

tan(B) = 10/5 = 2

sam had some money.
He spent £4.50 on a chocolate bar and £3.00 on cold coffee.
He has two fifth of his money left.
How much money did he start with?

Answers

Sam started with £5.

Now, we need to find out how much money Sam has left after spending £4.50 on chocolate and £3.00 on cold coffee. To do this, we can add the two amounts that he spent and subtract the total from his original amount of money:

£4.50 + £3.00 = £7.50

Original amount - £7.50 = Two-fifths of the original amount

Now, we know that Sam has two-fifths of his original amount of money left. We can use this information to set up an equation:

2/5 x Original amount = Amount of money left

We can solve for the original amount by multiplying both sides by 5/2:

Original amount = (5/2) x Amount of money left

Plugging in the amount of money Sam has left, we get:

Original amount = (5/2) x Amount of money left

Original amount = (5/2) x (Original amount - £7.50)

Simplifying the right side of the equation, we get:

Original amount = (5/2) x Original amount - (5/2) x £7.50

Original amount - (5/2) x Original amount = (5/2) x £7.50 (3/2) x Original amount = (15/2)

Original amount = £5

Therefore, Sam started with £5.

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Hot custard in heated at a temperature of 194°F. It is then allowed to cool in the refrigerator at a temperature of 41°F. The custard cools to 140°F in 20 minutes. What will be the temperature of the custard after 80 minutes?

guys pls help

Answers

To solve this problem, we can use Newton's Law of Cooling, which states that the rate of cooling of an object is proportional to the difference in temperature between the object and its surroundings.

Let T(t) be the temperature of the custard at time t. Then we have:

T'(t) = k(T(t) - 41)

where k is a constant of proportionality. We know that T(0) = 194 and T(20) = 140, so we can solve for k:

k = (T(0) - 41) / (T(0) - T(20)) = (194 - 41) / (194 - 140) = 3.25

Now we can use this value of k to find T(80):

T'(t) = 3.25(T(t) - 41)
T'(t) / (T(t) - 41) = 3.25
ln|T(t) - 41| = 3.25t + C
T(t) - 41 = e^(3.25t + C)
T(t) = e^(3.25t + C) + 41

Using the initial condition T(0) = 194, we can solve for C:

194 = e^C + 41
C = ln(153)

So the temperature of the custard after 80 minutes is:

T(80) = e^(3.25*80 + ln(153)) + 41 = 51.33°F

Therefore, the temperature of the custard after 80 minutes is 51.33°F.

I need helppp with this please

Answers

When we use Gauss-Jordon elimination method, the final product is as follows

[tex]\left[\begin{array}{cccc}1&0&0&-1\\0&1&0&-3\\0&0&1&-2\end{array}\right][/tex]

How do we solve the matrix using Gauss-Jordon elimination method?

The augmented matrix that represents a linear equation is as follow;

-5  7   7   -30

1    -4   4    3

2   -4   6    -2

Using Gauss-Jordon elimination method, we reduce every number to zero's and 1 except the values at the edge;

Divide row 1 by -5           Subtract row 1 from row 2

1   -7/5   -7/5   6                 1   -7/5    -7/5   6

1    -4      4      3                 0  -13/5   27/5  -3

2   -4      6     -2                 2    -4       6      -2

 R₃ - 2R₁                                    R₂ = -5R₂ ÷ 13

1    -7/5     -7/5     6                   1    -7/5     -7/5     6

0  -13/5    -27/5   -3                   0     1      -27/13   15/13

0   -6/5    44/5   -14                  0   -6/5    44/5   -14

R₁ + 7R₂ ÷ 5                                   R₃ + 6R₂÷5

1     0     -56/13  99/13                1     0     -56/13  99/13  

0     1    -27/13   15/13                 0     1    -27/13   15/13

0   -6/5    44/5   -14                   0     0    82/13    -164/13

   13R₃/ 82                                     R₁ + 56R₃/13

1     0    -56/13  99/13                  1     0     0        -1

0     1    -27/13   15/13                  0    1   -27/13  15/13  

0     0      1          -2                      0     0      1      -2

R₂ + 27R₃/13

1     0     0        -1

0     1     0        -3

0     0      1      -2

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Find mLEBF.
(20x10)
(3x+15)°
A
G
B
60°
JE
E

Answers

Check the picture below.

[tex]60+\stackrel{ \measuredangle ABC }{(3x+15)}+(20x-10)~~ = ~~180\implies 65+23x=180 \\\\\\ 23x=115\implies x=\cfrac{115}{23}\implies x=5 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ \measuredangle EBF }{(3x+15)}\implies 3(5)+15\implies \text{\LARGE 30}^o[/tex]

10) Determine which point is a solution of the linear inequality.
92 + 3y < 6
O (1, -1)
O (2, -2)
• (1,1)
• (1,3)

Answers

Step-by-step explanation:

To determine which point is a solution of the linear inequality 92 + 3y < 6, we can substitute the values of each point into the inequality and check if the inequality holds true.

Let's evaluate the inequality for each point:

1. Point (1, -1):

92 + 3(-1) < 6

92 - 3 < 6

89 < 6

The inequality is not true for this point.

2. Point (2, -2):

92 + 3(-2) < 6

92 - 6 < 6

86 < 6

The inequality is not true for this point.

3. Point (1, 1):

92 + 3(1) < 6

92 + 3 < 6

95 < 6

The inequality is not true for this point.

4. Point (1, 3):

92 + 3(3) < 6

92 + 9 < 6

101 < 6

The inequality is not true for this point.

None of the given points satisfy the inequality. Therefore, none of the points (1, -1), (2, -2), (1, 1), or (1, 3) are solutions to the linear inequality 92 + 3y < 6.

Joseph has a bag of 4 marbles. There are 2 green marbles, 1 yellow marble, and 1 purple marble. List 1 List 2 List 3 List 4 G1 G1, G2 G1, G1 G1, G1 G2 G1, Y G1, G2 G1, G2 Y G1, P G1, Y G1, Y P G2, G1 G1, P G1, P G2, Y G1, G1 G2, G1 G2, P G1, G2 G2, G2 Y, G1 G1, Y G2, Y Y, G2 G1, P G2, P Y, P Y, G1 Y, G1 P, G1 Y, G2 Y, G2 P, G2 Y, Y Y, Y P, Y Y, P Y, P Y, G1 P, G1 Y, G2 P, G2 Y, Y P, Y Y, P P, P Which list gives the sample space for pulling 2 marbles from the bag with replacement?

Answers

Answer:

Step-by-step explanation:

There are 5 marbles

Which statements are true about the fully simplified product of (b minus 2 c)(negative 3 b + c)? Select two options. The simplified product has 2 terms. The simplified product has 4 terms. The simplified product has a degree of 2. The simplified product has a degree of 4. The simplified product, in standard form, has exactly 2 negative terms. Mark this and return

Answers

The fully simplified product of (b minus 2 c)(negative 3 b + c) can be found by using the distributive property and combining like terms. The product is -3b^2 + 7bc - 2c^2, which has 3 terms.

Therefore, the statement "The simplified product has 2 terms" is false and the statement "The simplified product has 4 terms" is also false. The degree of each term is the sum of the exponents of the variables,

so the degree of the product is the highest degree among the terms. In this case, the highest degree is 2, which means that the statement "The simplified product has a degree of 2" is true and the statement "The simplified product has a degree of 4" is false.

Lastly, we can count the number of negative terms in the product to determine if the statement "The simplified product, in standard form, has exactly 2 negative terms" is true. We see that there are two negative terms, -3b^2 and -2c^2, so this statement is true.

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This case study is based on Magma printers, a large printing company specializing in newspaper printing. They have 10 state of the art printers in the printing area. The probability of a machine breaking down is 10%. They require at least 8 machines to be functioning in order to meet all the printing requirements for the day. (a) What is the probability that on a given day, no machines break down? (4) (b) What is the probability that all printing requirements on a particular day will be met? (6)​

Answers

a)  Note that the the probability that on a given day, no machines break down is 0.3487

b) the probability that all printing   requirements on a particular day will be met is 0.2323

How is this so ?

a) To find the probability that no machines break down, we can use the binomial distribution with

n = 10 (number of machines) and

p = 0.1 (probability of a machine breaking down).

The probability of no breakdowns  is

P(X = 0), where X is the number of breakdowns.

Using the binomial distribution formula: P(X = k) = (n choose k) * [tex]p^{k}[/tex] * (1 - p)[tex]^{n-k}[/tex]

P(X = 0) = (10 choose 0) * 0.1⁰ * 0.9¹⁰ = 0.3487

So it is right to stay that  the probability that on a given day, no machines break down is 0.3487

(b)

P(8 or more machines are functioning) = P(X = 8) + P(X = 9) + P(X = 10)

P(X = 8) = (10 choose 8) * 0.1⁸ *   0.9² = 0.1937

P(X = 9) = (10 choose 9) * 0.1⁹ * 0.9¹ = 0.0386

P(X = 10) = (10 choose 10) * 0.1¹⁰ * 0.9⁰ = 0.0000001

P(8 or more machines are functioning) = 0.1937 + 0.0386 + 0.0000001 = 0.2323

Hence, the probability that all printing requirements on a particular day will be met is 0.2323 or approximately 23.23%.

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Amy's penny bank is 7/10 full. After she removes 200 pennies, it is 1/2 full. How many pennies can Amy's bank hold?

Answers

1/5 = 200 pennies

5/5 = 1000 pennies

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