The number of cookies sold that would be in the shape of the dog in the next 51 cookies is 21.
What is probability?Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution. Knowing the total number of outcomes is necessary before we can calculate the likelihood that a specific event will occur.
The probability of cookies sold in shape of dog is:
P = 35/85
The number of cookies sold that would be in the shape of the dog in the next 51 cookies is:
N = 51 (P)
N = 51 (35/85)
N = 21
Hence, the number of cookies sold that would be in the shape of the dog in the next 51 cookies is 21.
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the bakery made $600 Donuts they made 384 more Donuts than Bagels the bakery made 216 Bagels
The bakery made 384 donuts and 216 bagels
What is bakery?
A bakery is a business that produces and sells baked goods, such as bread, cakes, pastries, and cookies.
Let's use the variable "x" to represent the number of bagels made.
From the problem, we know that:
The number of donuts made is 384 more than the number of bagels made, so the number of donuts is x + 384.
The bakery made 216 bagels.
We also know that the bakery made a total of 600 donuts. So, we can set up an equation to represent the total number of pastries made:
x + 384 + 216 = 600
Simplifying and solving for x:
x + 600 = 600
x = 600 - 600 + 384
x = 384
So, the bakery made 384 + 216 = 600 pastries in total.
Therefore, the bakery made 384 donuts and 216 bagels.
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which number below is most unlike the others ?? 102, 203, 506, 608
What is the end behavior of f(x)?
f(x) = -252x+6x³ +30x² - 864
as x→→∞, f(x) → ∞ and as x→∞, f(x) →∞
as x-x, f(x) → ∞ and as a →∞, f(x) →→∞
as x-x, f(x) → ∞ and as a →x, f(x) →∞
as x→→∞, f(x) →→∞ and as x →∞, ƒ(x) →→∞
Answer: 27
Step-by-step explanation:
Look at the image below.
Answer: 28 (look at the image for the solution)
Step-by-step explanation:
Answer:
A = base x height
A = 7 x 4
A = 28
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A travel club can spend at most 10 nights in two cities on a trip. The club needs to reserve four rooms each night and wants to spend no more than 4200 on hotels and fuel. The estimated fuel cost is 200 can the club spend 3 nights in city a and 6 nights in city b? 7 nights in city a and 3 nights in city b? justify your answer using a system of linear equations
To solve this system, we must first determine the number of available rooms in each city, as well as the per-night cost of hotel rooms. Without that information, we can't tell if the club can spend three nights in city A and six nights in city B, or seven nights in city A and three nights in city B.
Let's start by defining the variables we'll need to solve this problem:
Assume that x is the number of nights spent in City A.
Let y represent the number of nights in City B.
To determine whether the club can spend three nights in city A and six nights in city B, or seven nights in city A and three nights in city B, we must first determine whether the total cost of hotels and fuel for each scenario is less than or equal to $4200.
Given that the estimated cost of fuel is $200, the cost of hotels must be less than or equal to $4000.
The following equations calculate the cost of hotels for each scenario:
3x + 6y = cost of hotels for spending 3 nights in city A and 6 nights in city B7x + 3y = cost of hotels for spending 7 nights in city A and 3 nights in city BWe also know that the club can only spend a total of 10 nights, so x + y must be less than or equal to 10.
Finally, we must ensure that the club can book four rooms each night. This means that the number of rooms required per night in each city is four times the number of nights. As a result, we must have:
4x ≤ number of available rooms in city A4y ≤ number of available rooms in city BWhen we combine all of these constraints, we get the following system of linear equations:
3x + 6y + 200 ≤ 4200 (cost constraint for spending 3 nights in city A and 6 nights in city B)
7x + 3y + 200 ≤ 4200 (cost constraint for spending 7 nights in city A and 3 nights in city B)
x + y ≤ 10 (total number of nights constraint) (total number of nights constraint)
A city with 4x available rooms (room constraint for city A)
4y rooms available in city B (room constraint for city B)
To solve this system, we must first determine the number of available rooms in each city as well as the cost of hotel rooms per night. We can't tell if the club can spend three nights in city A and six nights in city B, or seven nights in city A and three nights in city B, without that information.
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Find the values of x and y.
please help meeeeh:
Find the first four terms and stated term given the arithmetic sequence, with a, as the 1" term.
an = 25 - 10n, a5
an = 11 + 9n, a6
an = 65 - 35n, a9
Answer:
The nth term of an arithmetic sequence is given by an = a + (n – 1)d ... Step 1: First, calculate the difference between each pair of adjacent terms.
Step-by-step explanation:
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