Answer:
13 hours, 16 minutes, 41 seconds
Explanation:
Distance of Saturn from the Sun
= 890,700,000 miles
[tex] = 8.907\times 10^8 \: miles\\
= 8.907\times 10^8 \times 1.61 \times 10^3 \:meters\\
= 14.34027\times 10^{11}\: m\\
= 1. 434027\times 10^{12}\: m\\\\
\because Time = \frac{Distance}{Speed} \\
\therefore Time = \frac{1.434027\times 10^{12}}{3\times 10^8}\\
\therefore Time = 4.78009 \times 10^{12-8}\\
\therefore Time = 4.78009 \times 10^{4} \:seconds \\
\therefore Time = 47800.9 \:seconds\\
\therefore Time = 47801 \:seconds\\
\therefore Time = 13h\: 16m\: 41s\\[/tex]
Saturn is 890,700,000 miles from the Sun. This distance in the scientific notation would be 1.434×10¹² metes.
If the speed of light is 3.0 x 108 meters/second, then it would take 4780 seconds for light from the Sun to reach Saturn.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The generally considered unit for velocity is a meter per second.
As given in the problem Saturn is 890,700,000 miles from the Sun
1 mile = 1.61 x 10³ meters
890,700,000 miles = 890,700,000×1.61×10³ meters
=1.434×10¹² metes
As given If the speed of light is 3.0 x 10⁸ meters/second
Time = distance /speed
= 1.434×10¹² metes / 3.0 x 10⁸ meters/second
= 4780 seconds
Thus, the distance in the scientific notation would be 1.434×10¹² metes and it would take 4780 seconds for light from the Sun to reach Saturn.
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The rifles in the figures are being fired horizontally (straight outward, off platforms). The bullets fired from the rifles are all identical, but the rifles propel the bullets are different speeds. The speed of each bullet and the height of each platform are given. All the bullets miss their targets and hit the ground. Rank the time it takes the bullets to hit the ground. Explain your reasoning.
Answer:
t = √ 2y₀ / g
if they are at the same height, all the bullets must carry the target, since when advancing the height decreases
Explanation:
In this exercise we see that the bullets are fired horizontally so the time it takes to reach the ground is
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
as they are fired horizontally their vertical velocity is zero and the height upon reaching the ground is zero y = 0
0 = y₀ - ½ g t²
t = √ 2y₀ / g
from here we can see that the time it takes for the bullets to hit the floor depends only on the initial height
Therefore, all the bullets that come out of the same height reach the ground at the same time, but at a different distance, so if one misses the target, everything must fail since reaching the target is below the initial height.
The horizontal distance traveled by the bullets is
x = v₀ₓ t
v₀ₓ =v₀
x = v₀ √2y₀/g
For a more precise calculation we should know the height of the target and the bullets, but if they are at the same height, all the bullets must carry the target, since when advancing the height decreases
The deep scattering layer (DSL):_________
a) was discovered by Charles Darwin
b) is only seen at night
c) is a biological phenomenon that can be detected with sonar
d) is not a biological phenomenon
e) is a chemical boundary in the water
Answer:
C
Explanation:
Because its a region of high biological productivity with a lot of water organism allowing for high reflectivity of sonar pulse mimicking ocean bottom
The pacefic ocean has a surface area of about 166 241 700km^2 and an average depth of 3940 m. Estimate the volume of the Pacific ocean in cubic centimetres
Answer:
[tex] \lim_{(x,y) \to \(0,0)} \frac{2x {y}^{2} }{ {x}^{2} {y}^{2} } [/tex]
Explanation:
[tex]\lim_{(x,y) \to \(0,0)}[/tex]
if a car is traveling with a velocity of 20 m/s, how long will it take to reach 4000m
The magnitude of average acceleration in half time period in a simple harmonic motion is
(A) 2 ω2A /π
(B) ω2A /2 π
(C) ω2A /√2 π
(D) Zero
Answer:
Option A - 2ω²A/π
Explanation:
The displacement of simple harmonic motion is usually given as;
x = Asinωt
Where;
A is amplitude
ω is angular frequency
Now, average acceleration in half time period is given as;
a_av = d²x/dt² = -ω²A sinωt
Thus;
a_av = ∫a(t)dt/(∫dt) with both numerator and denominator between the boundaries of T/2 and 0.
Full expression gives;
(2/T)(ω²A∫sin(ωt) dt between the boundaries of T/2 and 0.
Now, integrating gives;
(2/T)(ω²A × 1/ω)[-cos(ωt)] between the boundaries of T/2 and 0.
Plugging in the boundary conditions gives us;
(2/T)(ω²A × 1/ω)[-cos(ωT/2) + cos0]
Simplifying gives;
(2ωA/T)[-cos(ωT/2) + 1]
In simple harmonic motion, we know that ω = 2π/T
Thus we have;
(2ωA/T)[-cos(2π/2) + 1]
(2ωA/T)[-cos(π) + 1]
This gives;
(2ωA/T)[1 + 1]
= (4ωA/T)
Now, from earlier ω = 2π/T
Thus, T = 2π/ω
So, we have;
a_av = (4ωA/(2π/ω))
a_av = 2ω²A/π
What is a main difference between a mixture and a pure substance?
O A mixture is only a liquid, but a pure substance can be in any state.
A mixture looks the same throughout, but a pure substance does not.
A mixture can vary in composition, but a pure substance has a set composition.
A mixture can be made up of a single compound, but a pure substance cannot.
оо
Answer:
C- A mixture can vary in composition, but a pure substance has a set composition
Explanation:
The main difference between a mixture and a pure substance is: A mixture can vary in composition, but a pure substance has a set composition ( option c )
MixtureA mixture is a substance which contains two or more constituents which can easily be separated by a physical means. It consists of two or more different substances, not chemically joined together.
SubstanceA pure substance consists only of one element or one compound.
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During which step of the scientific method does a scientist make an educated
guess about the outcome of an experiment?
A. Collect data
B. Form a hypothesis
C. Analyze the results
O D. Design an experiment
SUBNA
Answer:B. Form a hypothesis
The highest speed attained by a cyclist on level ground is 105 km/h. To attain this speed, the cyclist used a streamlined recumbent bike. Starting from rest, he gradually built up his speed by pedaling furiously over a distance of 3.2 km. If his acceleration was uniform over this distance, what was the acceleration and how long did the cyclist take to build up his final speed
Answer:
The acceleration is 0.133 m/s²
The time taken to build the final speed is 219.32 s
Explanation:
Given;
final speed of the cyclist, v = 105 km/h = 29.17 m/s²
distance traveled by the cyclist, d = 3.2 km = 3,200 m
initial speed, u = 0
Apply the following kinematic equation to determine the acceleration of the cyclist;
v² = u² + 2as
(29.17 )² = 0 + (2 x 3200)a
850.89 = 6400a
a = (850.89 ) / (6400)
a = 0.133 m/s²
The time taken to build up the final speed is given by;
v = u + at
29.17 = 0 + (0.133)t
t = 29.17 / 0.133
t = 219.32 s
Which of the following is one way creativity can help scientists? (20 points) +Brainiest
a
By ensuring they follow the scientific method
b
By increasing the amount of time it takes to complete scientific experiments
c
By making sure they only try things that have already been proven
d
By leading them to ask more questions about the natural world
Could someone tell me if this is right or give me the answers so i can re write them! That would be so helpful:)
Answer:
Those are all right
Explanation:
Answer:
They are right! Nice job!
Explanation:
if 1 foot is 30.28 centimeters.how many cm is 130 feet
Answer:3,936.4
Explanation:
If 1 foot is 30.28 centimeters multiply 30.28 by 130
electricity is one kind of
Answer:
I think electricity is one kind of energy
launch a rocket ship weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 164 km/h ; at the end of the first 1.00 min , its speed is 1640 km/h . Part APart complete What is the average acceleration (in m/s2) of the rocket during the first 8.00 s? aav = 5.69 m/s2 Previous Answers Correct Part BPart complete What is the average acceleration (in m/s2) of the rocket between 8.00 s and the end of the first 1.00 min? aav = 7.88 m/s2 Previous Answers Correct Part CPart complete Assuming the acceleration is constant during each time interval (but not necessarily the same in both intervals), what distance does the rocket travel during the first 8.00 s? Express your answer with the appropriate units. x = 182 m Previous Answers Correct Part D Assuming the acceleration is constant during each time interval (but not necessarily the same in both intervals), what distance does the rocket travel during the interval from 8.00 s to 1.00 min? Express your answer with the appropriate units.
Answer:
A) a_av = 5.695 m/s²
B) a_av = 7.88 m/s
C) x_f = 182.24 m
D) x_f = 13029.12 m
Explanation:
A) Initial velocity at 0 seconds; v_i = 0 m/s
Final velocity at 8 seconds;v_f = 164 km/h = 45.56 m/s
So, formula for average acceleration is;
a_av = change in velocity/change in time.
Thus, for the first 8 seconds;
a_av = (45.56 - 0)/(8 - 0)
a_av = 45.56/8
a_av = 5.695 m/s²
B) From part A, we now want to find the average acceleration from 8 seconds to 1 minute (60 seconds)
After the 60 seconds, the speed is 1640 km/h = 455.56 m/s
Thus;
Average acceleration is;
a_av = (455.56 - 45.56)/(60 - 8)
a_av = 7.88 m/s
C) Now we are told the acceleration is constant and we want to find the distance the rocket travels during the first 8 seconds.
So, distance formula we will use is;
x_f = x_i + ½(v_i + v_f)t
So at this stage, v_i = 0 m/s and v_f = 45.56 m/s and x_i = 0 m
Thus;
x_f = 0 + ½(0 + 45.56)8
x_f = 182.24 m
D) Now we want to find the distance the rocket travels during the 8 seconds to 1 minute (60 seconds) interval.
From part B, v_i = 45.56 m/s and v_f = 455.56 m/s
Also, x_i = 0 while time interval(t) = 60 - 8 = 52 s
Thus;
x_f = 0 + ½(45.56 + 455.56)52
x_f = 13029.12 m
What is the key difference between acentralized electrical distribution grid versus a distributed electrical distribution grid? I am using the textbook provided but I can not find an answer
The electricity generated by centralized generation is distributed through the electric power grid to multiple end-users. Centralized generation facilities include fossil-fuel-fired power plants, nuclear power plants, hydroelectric dams, wind farms, and more.
A 10 kg package is delivered to your house. Use one complete sentence to describe an example of how work is done on the package as it gets brought inside. Make sure to use proper spelling, grammar, and other language mechanics. In your explanation, make sure to use the terms related to the formula for work (W = Fd).
Answer:
Hey :)
Explanation:
Work is a net force applied through a distance in order to displace an object, commonly abbreviated as W. A net force is the sum of all forces acting on an object. Work is mass times acceleration and distance so to find out the work you simply calculate the acceleration of the box being brought in. Next find the distance it was carried to get in the house. Then find out the mas of the box and finally multiply those sums together to get the amount of work put in to bring the package inside.
hope this helps :) xo
Question 2 (1 point)
The direction of the result of the cross product of two vectors is perpendicular to the
plane containing the two vectors, specified by the right hand rule.
True
ОО
False
A car is on a cruise control driving in a circle. Which are constant and which are changing? Speed, Velocity. Is the car accelerating?
Answer:
Only the speed is constant.
The acceleration and velocity are changing.
Explanation:
The velocity of an object refers to its speed in a specific direction. Due to the fact that the car is driving in a circle, the direction of the car is changing. This makes the car not to have a constant velocity as this value changes each time the car makes a bend on the circular path. (which is pretty much all the time).
The acceleration is a direct derivative of the velocity of the car. As a result, if the velocity is changing, the acceleration is also changing.
Speed is a scalar quantity. This means it does not deal with the direction of the car. It only deals with how fast the car is moving. The car is on cruise control. this means that the speed of the car does not change.
The observation of a "wet spot" on a hot highway in the summer is caused by:_________.
a. dispersion
b. diffraction
c. refraction
d. reflection.
Answer: Refraction
Explanation:
The observation of a wet spot on a hot highway in the summer season is caused by refraction. Therefore, option (C) is correct.
What is refraction?Refraction can be defined as the redirection of light as it passes from one medium to another medium. The redirection of light is caused by a change in the medium or by the wave's change in speed.
Refraction of light can be described as an observed phenomenon, but other waves such as sound waves and water waves also experience refraction.
Refraction of light obeys Snell's law that the ratio of the sines of the angle of incidence and refraction must be equal to the ratio of phase velocities in the two media to the refractive index of the two media.
When the sunlight makes a blacktop hot highway. The appearance of the wet spot is bright because of the refraction of light from the sky.
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1. You are driving to the grocery store at 20 m/s. You are 110 m from an intersection when the traffic light turns red. Assume that your reaction time is negligible and that your car brakes with constant acceleration. What magnitude braking acceleration will bring you to a stop exactly at the intersection?
Answer:
-1.82m/s²
Explanation:
Given that the reaction time (t) is negligible and car brakes with constant acceleration.
Initial Velocity (u) = 20m/s
Distance(d) from Intersection when light turns red = 110m
Hence, the magnitude of braking acceleration that will bring the car to rest at exactly the intersection :
Using the motion equation:
v² = u² + 2as
Where v = final velocity at the intersection
u = initial velocity ; s = distance to intersection ; a = acceleration of the car
Exactly at the intersection ; v = 0
0 = 20² + 2×a×110
0 = 400 + 220a
-400= 220a
a = - 400 / 220
a = - 1.818
a = - 1.82 m/s²
- stands for negative acceleration (deceleration)
A single atom of an element has 11 protons, 11 electrons, and 12 neutrons. Which element is it?
Оy
O Na
OMg
O Se
A marathon runner runs at a steady 15 km/hr. When the runner is 7.5 km from the finish, a bird begins flying from the runner to the finish at 30 km/hr. When the bird reaches the finish line, it turns around and flies back to the runner, and then turns around again, repeating the back-andforth trips until the runner reaches the finish line. How many kilometers does the bird travel?
Answer:
The value is [tex]D = 15 \ km [/tex]
Explanation:
From the question we are told that
The speed of the marathon runner is [tex]v = 15 \ km /hr[/tex]
The distance from the distance from the finish is [tex]d = 7.5 \ km[/tex]
The speed of the bird is [tex]v_b = 30 \ km / hr[/tex]
Generally the time taken for the runner to reach the finish is mathematically represented as
[tex]t = \frac{d}{v}[/tex]
[tex]t = \frac{7.5}{15}[/tex]
[tex]t = \frac{1}{2}[/tex]
So the distance covered by the bird is
[tex]D = v_b * t[/tex]
[tex]D = 30 * \frac{1}{2}[/tex]
[tex]D = 15 \ km [/tex]
Calculate the magnitude and direction of the electric field (in N/C) 2.2 m from a long wire that is charged uniformly at λ = 3.6 ✕ 10−6 C/m. (Assume the wire goes through the origin and the point in question is located on the +z-axis. Express your answer in vector form.).
Answer:
29.5*10^3 k N/C
Explanation:
Using
E = λ/2πEor x k
So = 18*10^9 x 3.6 ✕ 10−6 / 2.2 x k
= 29.5*10^3 k N/C
A car traveling with an initial velocity of 10 m/s accelerates at a constant rate of 2.2 m/s^2 for 2 seconds. What distance does the car travel during this process
2.5 better than the first one more game to go hard but I 46 the bucks
Answer:
hsiahdjjsdhishshdakyeacs4y9yssig
Explanation:
ntesgs7thsjv6wlubx4euc
Consider two positively charged particles, one of charge q0 (particle 0) fixed at the origin, and another of charge q1 (particle 1) fixed on the y-axis at (0,d1,0). What is the net force F⃗ on particle 0 due to particle 1? Express your answer (a vector) using any or all of k, q0, q1, d1, i^, j^, and k^.
Answer:
[tex]F_{10} = - \frac{k_{q1}* qo }{d_{1} ^{2} } j[/tex]
Explanation:
The net force ( F ) on particle 0 due to particle 1 can be expressed as
[tex]F_{10} = \frac{K_{q1}*qo }{r_{10} ^{3} } r_{10}[/tex]
k = coulomb constant
[tex]r_{10}[/tex] = distance between charge o and charge 1
to get the vector form ( attached below ) we substitute [tex]d_{1}[/tex] for [tex]r_{10}[/tex] and [tex]- d_{1} j[/tex] for [tex]r_{10}[/tex]
The net force on [tex]q_{0}[/tex] by [tex]q_{1}[/tex] is , [tex]F=-K\frac{q_{0}*q_{1}}{r^{2} }j[/tex]
The force between two charges is given by Coulomb force law.
[tex]F=K\frac{q_{0}*q_{1}}{r^{2} }[/tex]
Where K is Coulomb constant, [tex]K=9*10^{9}Nm^{2}/C^{2}[/tex]
and r is the distance between both charges.
Here given that, [tex]q_{0}[/tex] is located as (0, 0, 0) and [tex]q_{1}[/tex] is located at [tex](0,d_{1}, 0)[/tex]
The force on [tex]q_{0}[/tex] by [tex]q_{1}[/tex] in the negative y - axis.
So that , Direction of force is, [tex]-j[/tex]
Hence, the net force on [tex]q_{0}[/tex] by [tex]q_{1}[/tex] is , [tex]F=-K\frac{q_{0}*q_{1}}{r^{2} }j[/tex]
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A cheetah is running at a speed of 19.5 m/s in a direction of 69° north of west. Find the cheetahs velocity component due north and due west.
Answer:
The cheetahs velocity component due north is 6.99 m/s
The cheetahs velocity component due west is 18.21 m/s
Explanation:
Given;
speed of the cheetah, v = 19.5 m/s
direction of the cheetah's speed, θ = 69°
Find the attached document for explanation
1. Classify What type of heat transfer occurs
when you roast a marshmallow by holding it
campfire?
over a co
Answer:
Convection
Explanation:
because it tis the transfer of energy through a fluid or gas
When you roast a marshmallow by holding it campfire, the heat transfer in the process of radiation.
What is thermal radiation ?Thermal radiation is a process in which energy, in the form of electromagnetic radiation, is emitted from a heated surface in all directions and moves at the speed of light directly to its site of absorption. Thermal radiation does not move through an intermediary medium.
From the longest infrared rays through the visible light spectrum to the shortest ultraviolet rays, thermal radiation spans the entire electromagnetic spectrum. The temperature of the emitting surface controls the distribution and intensity of radiant radiation within this range.
When you roast a marshmallow by holding it campfire, the heat transfer by the process of radiation through air.
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Which of the following quantities represent mass?
a. 12.0 lbs.
b. 0.34 g.
c. 120 kg.
d. 1600 kN.
e. 0.34 m.
f. 411 cm.
g. 899 MN.
Answer:
Explanation:
a ) 12.0 lbs - mass
b ) .34 g - mass
c ) 120 kg - mass
As lbs , g and kg are units of mass , these things represent mass . lbs is FPS unit of mass and kg is SI unit . g is CGS unit of force .
d ) 1600 kN It represents force because kN or kilonewton is unit of force .
e ) it represents , length or distance because m or metre is unit of length .
f ) 411 cm It represents length or distance because cm is smaller unit of length
g ) 899 MN or million newton . Like d ) It also represents force . Million newton is higher unit of force .
There are two ways that an object can get in motion. What are they?
Answer:
pull or pushExplanation:
According to Newton's first law of motion "An object will continue to stay or remain at rest or continue to be in constant motion "unless acted upon by an external force"
F= ma
Basically a force is a pull or a push
so in other words the two ways by which an object can get in motion is by
1. A pull force
2. A push force
what part of the stem cell provides instructions for building the heart
a. ribosomes
b. DNA
c. RER
d. lysosomes
position (m)
80!
В
с
60
40
20
A
- 20
-40
10
20
30
40
50
time (sec)
Answer:
hola bb como estas dime bb en que te ayudo
Explanation:
