Scientists have been able to develop a nuclear fusion plant to generate energy.

True or False

Answers

Answer 1

Answer: true

Explanation:


Related Questions

A long straight wire carrying current I is moving with speed v toward a small circular coil of radius r containing N turns, which is attached to a voltmeter as shown. The long wire is in the plane of the coil. (Only a small portion of the wire is shown in the diagram.) The radius of the coil is 0.02 m, and the coil has 11 turns. At a particular instant I = 3 amperes, v = 3.3 meters per second, and the distance from the wire to the center of the coil x = 0.17 m. (a) What is the magnitude of the rate of change of the magnetic field inside the coil? You will need to calculate this algebraically before you can get a number. Write an expression for the magnetic field due to the wire at the location of the coil. Use the approximate formula, since the wire is very long. Remember the chain rule, and remember that v = dx/dt. dB/dt = T/S (b) What is the magnitude of the voltmeter reading? Remember that this includes all 11 turns of the coil. volts

Answers

The magnitude of the rate of change of the magnetic field inside the coil  9.57*10^-5 T /s,  voltmeter reading is  1.386*10^-6 V

Given that radius of the coil is  r = 0.02m

Number of turns in the coil is  N  = 11

current in the coil is  I  = 3.0A

velocity  is  v  = 3.3 m/s

distance from the wire to the center of the coil is  x  = 0.17m

db. / dt.  = B. v / x

       B  = 2(μ_0 N i / )3πx

           = 2 * 4π*10^-7 * 11 * 3.0A / 4π*0.17m

           = 5.12*10^-6 T

     dB / dt  = 5.12*10^-6 * 3.3m/s / 0.17 m

                  = 9.57*10^-5 T /s

b ) voltmeter reading is  V  = n A dB / dt

                                         = 11*π ( 0.02)^2 * 9.57*10^-5 T/s

                                        = 1.386*10^-6 V

An electro magnetic field, often known as an EM field or EMF, is a non-quantum (classical) field created by accelerating electric charges. [1] The classical equivalent of the quantum electrodynamics' quantized electromagnetic field tensor, it is the field that classical electrodynamics describes. Charges and currents are affected by the electromagnetic field, which interacts with them and moves at the speed of light (in fact, this field can be compared to light). One of the four basic forces of nature is its quantum counterpart (the others are gravitation, weak interaction and strong interaction.)

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determine the force in members ge gc and bc state if the members are in tension or compression 10 10 10 10 1000 lb

Answers

The force in members ge gc and bc state if the members are in tension or compression Fge = 666.66 lb (C),Fgc = 417.4 lb (T),Fbc = 333.33 lb (T)

The forces:

∑Fy = 0        

Va+Vb = 1000

∑Fx = 0

MOD = 0

Va*30 - 1000*10 = 0

Va=333.33 lb

Vd=666.67 lb

take section X-X

∑Fx = 0

Fge+ Fgc cos45 + Fbc = 0

∑Fy = 0

Fgc cos45 - 333.33 = 0

Fgc = 333.33/cos45

Fgc = 471.4 lb

MOG = 0

333.33*10 - Fbc*10=0

Fbc = 333.33 lb

From equation above

Fge+471.4*cos45+333.33 = 0

Fge = -666.66 lb

Answer

Fge = 666.66 lb (C)

Fgc = 417.4 lb (T)

Fbc = 333.33 lb (T)

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An object starts with an initial height of 5 meters above the ground. It is thrown upward with an initial velocity of 4 m/s. What is the maximum height the object reaches? What is the object's final velocity as it hits the ground? (use g=9.8 m/s^2)

Answers

The maximum height the object reaches be 5.81 m.

The object's final velocity as it hits the ground be 10.67 m/s.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

An object starts with an initial height of 5 meters above the ground. It is thrown upward with an initial velocity of 4 m/s.

So, maximum height obtained by it be: H  = 5 m + (4²/2×9.8) m = 5.81 m.

The object's final velocity as it hits the ground = √(2gH)

= √(2×9.8×5.81) m/s

= 10.67 m/s.

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a 3.8 kgkg block of wood sits on a frictionless table. a 3.0 gg bullet, fired horizontally at a speed of 520 m/sm/s , goes completely through the block, emerging at a speed of 190 m/sm/s .
what is the speed immediately after it exits the block

Answers

The speed of the bullet immediately after it exits the block is 190 m/s.

What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or even the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as that of the duration of the time interval gets closer to zero. The average speed of an object in a period of time is indeed the distance travelled by object divided by duration of the interval. Velocity and speed are not the same thing. The dimensions of speed are time divided by distance.

The speed immediately after the bullet exits the block is 190 m/s. This can be determined using the conservation of momentum principle, which states that the total momentum of an isolated system remains constant. In this case, the system is the bullet and the block of wood.
Before the bullet enters the block, the momentum of the system is equal to the momentum of the bullet, which is given by:
p_i = m_b * v_b = (3.0 g) * (520 m/s) = 1560 g m/s
After the bullet exits the block, the momentum of the system is equal to the momentum of the bullet and the block, which is given by:
p_f = m_b * v_b + m_w * v_w = (3.0 g) * (190 m/s) + (3.8 kg) * (0 m/s) = 570 g m/s
By conservation of momentum, we can set the initial and final momentum equal to each other and solve for the velocity of the bullet after it exits the block:
p_i = p_f
1560 g m/s = 570 g m/s + (3.8 kg) * v_w
v_w = 190 m/s
Therefore, the speed of the bullet immediately after exiting the block is 190 m/s.

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A mass oscillates on a spring with a period T and an amplitude 0.48 cm. The mass is at the equilibrium position x = 0 at t = 0, and is moving in the positive direction. Where is the mass at the times (a) t = T/8, (b) t = T/4, (c) t = T/2 and (d) t = 3T/4? (e) Plot your results for parts (a)through (d) with the vertical axis representing position and the horizontal axis representing time.

Answers

On a spring, mass oscillates with an amplitude and a time T. at T=3t/4 the mass will be at 0.48cm away from its mean postion.

What is SHM?

Simple harmonic motion is described as the periodic motion of a point across a single direction with an acceleration that is always toward a fixed point in that lines and a distance from that point that is proportional to that acceleration.

Briefing:

Mass at the time t = 3T/4

Given T=T, A=0.48cm

φ = -π/2 , x=0, t=0

ω = 2π/T

The position of SHM is given by:

x(t) = Acos(ωt+φ)

x(3T/4) = 0.48cos((2π/T)(3T/4)+(-π/2))

x = 0.48cos(π) = -0.48

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Which describes an object in a projectile motion?; What is projectile motion ?; What direction does gravity act on a projectile?; How do you describe a path in projectile motion?

Answers

Projectile motion is the movement of an object in the curved path toward the ground as it has both a horizontal force and the downward force of gravity acting on it.

Projectile motion is the movement of an item thrown or projected into the air, situation to only the acceleration of gravity. The item is referred to as a projectile, and its path is referred to as its trajectory.

The path of a projectile is parabolic. at some point in the motion, the acceleration of the projectile is steady and acts vertically downwards being identical to g.

Projectile movement is the movement of an item thrown up within the air at a perspective from the horizontal (or floor) with the item shifting below gravitational acceleration pointed vertically downwards, Now depending on the perspective of projection.

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A roller coaster car may be approximated by a block of mass m
m
. The car, which starts from rest, is released at a height h
h
above the ground and slides along a frictionless track. The car encounters a loop of radius R
R
, as shown. Assume that the initial height h
h
is great enough so that the car never loses contact with the track.

Answers

At height h , potential energy of coaster car  having mass m = mgh .

The car will lose potential energy and gain kinetic energy.

height lost by car when it is at the top of loop of radius R

= h - 2R

potential energy lost = mg ( h - 2R )

kinetic energy gained = mg ( h - 2R )

kinetic energy = 0 + mg ( h - 2R )

= mg ( h - 2R )

b )

For the car to remain in contact with the track , if v be the minimum velocity

centripetal force at top = mg

m v² / R = mg

v² = gR

kinetic energy = 1/2 mv²

= 1/2 m x gR

= mgR /

If h be the minimum height that can give this kinetic energy

mg ( h - 2R ) = mgR / 2

h - 2R = R / 2

h = 2.5 R

Therefore, the height of the roller coaster will be 2.5 R.

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Which phrase best defines momentum?
A. the change in velocity of an object over time
B. the amount of matter in an object
C. the distance traveled by and object over time
D. the motion of an object

Answers

Answer: the motion of an object

Explanation:

I just took the test

Answer:the motion of an object

Explanation:

I finished the sample work

car b is stopped at a light when car a crashes into it moving with speed v. if the coefficient of restitution is 0, find the speeds of the two cars at the end of the impact in terms of p and v.

Answers

Both the cars A as well as car b has zero speed after the impact.

Car b is stopped at the light when car a is crashes into it which is moving with a speed V the coefficient of restitution is given to be zero.

Because the coefficient of restitution is zero it means that the collision is perfectly inelastic in nature.

So, if the car a was moving with a speed v.

As it is already mentioned that after the collision ka bi has come to rest Swasthya the impact the speed of car b is new and because the collision is perfectly inelastic the speed of car a will also be zero.

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What are the indicators of motion in relation to a reference point?; What are the terms used in describing the motion?; How do you described the motion of the object?; What is describing motion and give example?; Why is it important to identify a reference point for any description of motion?; What describes the rate of motion and the direction?

Answers

Indicators of motion in relation to a reference point include distance, displacement, speed, velocity, acceleration, and deceleration.

The terms used in describing motion include linear motion, angular motion, rotational motion, and oscillatory motion.

To describe the motion of an object, one would use words such as move, accelerate, decelerate, rotate, and vibrate.

Describing motion is the process of quantifying changes in position, direction, and velocity over time. For example, when a ball is thrown, one can describe its motion by noting its initial position, the direction of its throw, and how fast it is moving.

It is important to identify a reference point for any description of motion because it provides context for the motion. Without a reference point, it would be impossible to accurately quantify motion.

Speed and velocity describe the rate of motion, and direction describes the orientation of motion.

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a 0.35-kgkg croquet ball is initially at rest on the grass. when the ball is struck by a mallet, the average force exerted on it is 230 nn.

Answers

The mallet is in contact with the croquet ball in the grass for 0.005 seconds long.

The mass of the croquet ball = 0.35 kg

The speed at which the ball struck = 3.1 m/s

The force exerted on the ball = 230 N

The total time when the mallet is in contact with the ball can be found using the formula,

                    F = mv/t

where F is the force

           m is the mass of the ball

           v is the speed at which the ball is struck

           t is the time

Let us rearrange it,

                  t = mv/F

Let us substitute the known values in the above equation, we get

                 t = 0.35 x 3.1 / 230

                   = 1.085 / 230

                   = 0.005 seconds

The total time when the mallet is in contact with the ball is 0.005 seconds

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b(4+a) ;where a = 6 and b - 2

Answers

= 2(4+6)

= 2×10

= 20

HOPE IT HELPS !!!!!!!!

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A stick of length 2L and negligible mass has a point mass m affixed to each end. The stick is arranged so that it pivots in a horizontal plane about a frictionless vertical axis through its center. A spring of force constant k is connected to one of the masses. The system is in equilibrium when the spring and stick are perpendicular. The stick is displaced through a small angle theta. a) Determine the restoring torque when the stick is displaced from equilibrium through the small angle theta b) Determine the magnitude of the angular acceleration of the stick just after it has been released c) Write the differential equation whose solution gives the behavior of the system after it has been released d) Write the expression for the angular displacement theta of the stick as a function of time t after it has been released from rest
Answers:
a. τ = FLcos\Theta = FL = -kL2\Theta
b. a = -ke/2m
n
c. d2\Theta/dt2 = -k\Theta /2m
d. \Theta=\Theta0 cos (k/2m)1/2t
Please explain all the steps in arriving at the answers.

Answers

A stick of length 2L and negligible mass has a point mass m affixed to each end. The stick is arranged so that it pivots in a horizontal plane about a friction less vertical axis through its center, thus calculated values are:

(A) Torque (τ) = F × L cosθ

(B) α = - Kθ/2m

(C) d²θ/dt² = -Kθ/2m

(D)  θ = cos ⁻¹ ( kθ t/2Lm)

What is torque?

The term "torque" refers to the twisting force that an engine exerts as it works, and it expresses the rotating force. Everyday activities like turning a doorknob, opening a drink bottle, using a tool, or peddling a bicycle all involve torque.

(A)

General equation of torque (τ) will be product of force and perpendicular distance.

τ = F × (perpendicular distance)

In this case, restoring torque. Hence, force F we taken as restoring force, and the perpendicular distance x-axis is component of L.

or, τ = F × [tex]L_{x-axis}[/tex]

or, τ = F × L cosθ

(B)

Angular acceleration general equation is:

α = Δω/Δt

here,  Δω = change in angular velocity.

Δt = change in time

As we know, acceleration = force/mass

now, angular acceleration = angular force / mass of body

so, α = - Kθ/2m

(C)

f(t) = α × (t²/2)

or, f(t) = - Kθ/2m × (t²/2)

or, f(t) = - Kθ t² / 4m

now differentiating with respect to t:

or, dθ/dt = -Kθ t/2m

differentiating again with respect to t:

d²θ/dt² = -Kθ/2m

(D)

The expression for angular displacement:

cos θ = adjacent side / opposite side

or, cos θ = adjacent side / 2L

or, θ = cos ⁻¹ ( kθ t/2Lm)

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part a part complete what is the amplitude of this wave? express your answer in centimeters to two significant figures. a

Answers

The particle's maximum displacement from its mean position is measured by its amplitude, which in the graph equals 6 cm. The wavelength is 1.20 nm, and the frequency is 1.67 hz.

A periodic wave's wavelength, or the distance over which the wave's shape repeats, is its spatial period. It is the separation between adjacent spots on a wave that correspond to the same phase. Displacement refers to the idea that something has moved or been shifted. The term "displacement" refers to a shift in an object's position. The following equation serves as a mathematical definition of it: is used to describe the final position's value.

f = 1/T f = 1/0.6 f = 1.67 mHz is the frequency.

Wavelength and frequency are combined to form the wave's speed.

v = f (lamda) lamda = v/f

lamda = v/f

lamda = 2/1.67

lamda = 1.20m

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The complete question is -

part a part complete what is the amplitude of this wave? express your answer in centimeters to two significant figures.

A) What is the amplitude of this wave?

B) What is the frequency of this wave? Express your answer to three significant figures and include the appropriate units.

C) What is the wavelength of this wave?

Dario, a prep cook at an Italian restaurant, spins a salad spinner 20.0 times in 5.00 seconds and then stops spinning it. The salad spinner rotates 6.00 more times before it comes to rest. Assume that the spinner slows down with constant angular acceleration. What is the angular acceleration of the salad spinner as it slows down? Express your answer numerically in radians per second per second.ω = θ / t ω = 20 * 2 * π / 5.00 ω = 8π ω = 25.13272 radians/s now I can solve for α using a kinematic equation: ω2f = ω20 + 2α(θ) 02 = 25.132722 + 2 * α * (2 * π * 6.00) 0 = 631.6536 + 75.39816α 75.39816α = -631.6536 α = -8.37757 radians/s2

Answers

The angular acceleration, which is frequently denoted by the symbol and stated in radians per second per second, is the rate at which the angular velocity changes over time. = t and = 0 for the scenario when the angular velocity is constant (nonvarying).

In layman's words, what is angular acceleration?

A spinning object's change in angular velocity per unit of time is expressed quantitatively as angular acceleration, also known as rotational acceleration. It is a vector quantity with either one of two predetermined directions or senses and a magnitude component.

What is the basic angular acceleration formula?

The rate at which angular velocity changes is referred to as angular acceleration. Angular acceleration is written as the equation: =t = t, where is the change in angular velocity and t is the change in time.

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A certain force 1 gives an object an acceleration of 6×10^6 m. Another force F2 gives the same object an acceleration of 15×10^6 m. What is the acceleration of the object if the two forces act on the object at 90°to each other?​

Answers

The total acceleration of the object is 3×10^6 m/s.

To find the total acceleration, we can use the Pythagorean Theorem, which states that the square of the hypotenuse of a right triangle (c) is equal to the sum of the squares of the other two sides (a and b). In this case, the magnitudes of the two accelerations (a and b) are 6×10^6 m/s^2 and 15×10^6 m/s^2, respectively.

Therefore, we can use the formula a^2 + b^2 = c^2 to find the magnitude of the total acceleration:

6×10^6 m/s^2 + 15×10^6 m/s^2 = c^2

c = sqrt(6×10^6 m/s^2 + 15×10^6 m/s^2)

= sqrt(21×10^6 m/s^2)

= 3×10^6 m/s

So, the total acceleration of the object is 3×10^6 m/s. This is the result of the two forces acting on the object at 90 degrees to each other.

The total acceleration of the object is 3×10^6 m/s.

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Answer:

1.5x10⁷ m/s²

Explanation:

Acceleration is a vector, so this is a case of vector addition.  Let R = resultant vector.

R² = a-F₁² + a-F₂²

R = √(6x10⁶)² + (15x10⁶)²

R = √2.25x10¹⁴ = 1.5x10⁷ m/s²

one end of a spring is attached to a wall. a 20 n pull on the other end causes the spring to stretch by 2.6 cm .

Answers

One end of a spring is attached to a wall and its other end is pulled by a 20N force. The spring is strething until it reach 2.6 cm. Based on Hooke's Law, the spring constant is 769.23 N/m.

Hooke's Law states that when a spring is compressed or extended by a force, the force is proportional to the length strecth.

Spring constant represents the spring's stiffness. It describes the force needed per unit of spring extension. Spring constant and force have relationship where:

F = -k.x

F = force working on the spring

k = the spring constant

x = the spring's displacement from its equilibrium position

Based on the case, we know that:

F  = 20N

x = 2.6 cm = 0.026m

k = ?

We will use the spring constant formula to find the spring constant:

F = k.x

k = F/x

k = 20N/0.026m

k = 769.23 N/m

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Complete Question:

One end of a spring is attached to a wall. A 20N pull on the other end causes the spring to strecth by 2,6 cm. What is the spring constant?

The depth of snow after n hours of a snowstorm is

Answers

The depth of snow was 0.8 inches when the storm began and 2.5 inches after the first hour of the storm describes the sequence of numbers generated by the function.

A polynomial function exists as a function that examines only non-negative integer powers or only positive integer exponents of a variable in a formula like the quadratic equation, cubic equation, etc.

Given, depth of the snow after n hours of a snowstorm exists represented by the function f(n+1) = f(n) + 0.8 where, f(0) = 2.5

To find, which statement explains the sequence of numbers rendered by the function.

Given function f(n + 1) = f(n) + 0.8 where f(0) = 2.5

Hence, the depth of snow was 0.8 inches when the storm began and 2.5 inches after the first hour of the storm describes the sequence of numbers generated by the function.

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A parallel plate capacitor using a dielectric material having a dielectric constant of 2.5 has a plate separation of 1-mm. If another material having a dielectric constant of 4.0 is used and the capacitance is to be unchanged, what must be the new spacing between the plates?

Answers

The new spacing between the plates is 1.6mm

What is capacitor?

A capacitor is a device that uses the accumulation of electric charges on two nearby surfaces that are electrically isolated from one another to store electrical energy in an electric field. It has two terminals and is a passive electrical component. The effect of a capacitor is known as capacitance.

What is dielectric constant?

A substance or material's capacity to hold electrical energy is indicated by its dielectric constant. It is a measurement of how much electric flux a substance can hold or concentrate.

Dielectric constant k = 2.5

Separation between the plates d = 1 mm

Dielectric constant k ' = 4

let new separation between the plates = d '

We know C = k A / d

In both cases C ,A are constant .

So, ( k ' / k ) = ( d ' / d)

d ' = d ( k ' / k )

= 1.6 mm

The new spacing between the plates is 1.6mm

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A sailor strikes the side of his ship just below the waterline. He hears the
echo of the sound reflected from the ocean floor directly below 2.02 s later
How deep is the ocean at this point? (Speed of sound in water=1500m/s)

Answers

At this location, the ocean lies 1515 meters deep.

What does "sound" mean in physics?

Particles that are vibrating make up sound waves. These collide with other particles, causing them tp vibrate, which allows the sound to escape the source. Your ear drums vibrate as a result of air vibrations, which allows you to perceive sound. This vibration is transformed into messages, which proceed to your brain via a nerve.

Briefing:

Let the sound speed in sea water be 1500 m/s.

If he hears the echo 3.5s after the strike,

then the sound would have traveled a distance of:

                         1500 * 2.02 = 3030 m to the bottom and back.

This would mean the ocean is 3030 / 2 = 1515 m deep.

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A water tank is 1/8 full. the tank is 3/4 full when 42 gallons of water are added to the tank. how much water can the tank hold?

Answers

The tank can hold a water of volume 67.2gallons

What is volume?

Volume is defined as the space occupied within the boundaries of an object in three-dimensional space. It is also known as the capacity of the object.

The capacity of an object can be measured in litres, gallon , cm³ e.t.c.

The tank is 1/8 full, when 42 gallons of water is added it is 3/4 full.

Therefore the fraction of water added is 3/4-1/8= 5/8.

This means 5/8 of the tank is 42 gallons. Therefore if 5/8 of the tank = 42gallons,

full tank will be 42× 8/5

= 67.2 gallons

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A motorcycle is travelling at a constant velocity of 30ms. The motor is in high gear and emits a hum of 700Hz. The speed of sound in air is 340ms, and there is no wind.Part AWhat is the period of the sound waves emitted from the motorcycle?Part BWhat is the distance travelled by the motorcycle during one period of the sound oscillation?Part CWhat is the distance travelled by a sound wave in air during one period of oscillation?Part DThe humming of the motorcycle is a sound that is emitted in all directions and, once emitted, it travels in the reference frame of the still air at the speed of sound in air. Consider the emitted sound that is moving directly out in front of the motorcycle

Answers

a) The period of the sound waves emitted from the motorcycle is  [tex]$T=1.43 \times 10^{-3} \mathrm{~s}$[/tex]

b) The distance travelled by the motorcycle during one period of the sound oscillation is  [tex]$d=0.0429 \mathrm{~m}$[/tex]

c)The distance travelled by a sound wave in air during one period of oscillation is  [tex]$\lambda=0.4857 \mathrm{~m}$[/tex]

d)The humming of the motorcycle is a sound that is emitted in all directions and, once emitted, it travels in the reference frame of the still air at the speed of sound in air is  [tex]$f_o=767.7 \mathrm{~Hz}$[/tex].

What is  frequency?'

Frequency is the number of occurrences of a repeating event per unit of time. It is also occasionally referred to as temporal frequency for clarity, and is distinct from angular frequency. Frequency is measured in hertz which is equal to one event per second.

(a)

We know time period is inverse of frequency:

Mathematically:

[tex]$$\begin{aligned}& T=\frac{1}{f} \\& T=\frac{1}{700} \\& T=1.43 \times 10^{-3} \mathrm{~s}\end{aligned}$$[/tex]

(b)

Distance travelled by the motorcycle during one period of sound oscillation:

[tex]$$\begin{aligned}& d=v_s . T \\& d=30 \times 1.43 \times 10^{-3} \\& d=0.0429 \mathrm{~m}\end{aligned}$$[/tex]

(c)

The distance travelled by the sound during the period of one oscillation is its wavelength.

[tex]$$\begin{aligned}& \lambda=\frac{S}{f} \\& \lambda=\frac{340}{700} \\& \lambda=0.4857 \mathrm{~m}\end{aligned}$$[/tex]

(d)

observer frequency with respect to a stationary observer:

According to the Doppler's effect:

[tex]$\frac{f_0}{f_u}=\frac{S+v_0}{S-v_n}$[/tex]

where:

[tex]$f_o \& v_o$[/tex] are the observed frequency and the velocity of observer respectively.

Here, observer is stationary.

[tex]\therefore v_o=0 \mathrm{~m} \cdot \mathrm{s}^{-1}$$[/tex]

Now, putting values in eq. (1)

[tex]$$\begin{aligned}& \frac{f_a}{700}=\frac{340+0}{340-30} \\& f_o=767.7 \mathrm{~Hz}\end{aligned}$$[/tex]

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derive an equation for the tension string connected to the two blocks in terms of ; any physical constants

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The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension.

How do we measure tension?

When a body is suspended from items like chains, cables, strings, etc., tension is simply the drawing force at work on the body. T is used to signify it (occasionally also symbolised as Ft).

Tension formula is articulated as

T=mg+ma

Where,

T= tension (N or kg-m/s2)

g = acceleration due to gravity (9.8 m/s2)

m =Mass of the body

a = Acceleration of the moving body

For mass m, the forces are given as

T−mg=ma                                          ...... (1)

Similarly, for mass M, the forces are given as

Mg−T=Ma                                               ...... (2)

From equation (1), we have

T=mg+ma          

Substituting equation (3) in (2) we get

Mg−mg−ma=Ma

g(M−m)=a(M+m)

a=( M+m / M−m )g

T=m×( M+m / M−m )g+mg

T = g( Mm - m² +  m² + Mm / M + m) = g( 2Mm / M+m )

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everything looks red through a red filter because everything looks red through a red filter because the filter reflects red light and transmits other colors. the filter emits red light and absorbs other colors. the filter absorbs red light and emits other colors. the filter transmits red light and absorbs other colors.

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Everything looks red through a red filter because the filter transmits red light and absorbs other colours

The perception of colour is generated because of the difference in the frequencies or wavelengths of light that enter into our eyes. Different colours are characterized by different frequencies.

The colour of light reflected back by an object determines the colour of that object. For example, if an object absorbs all the colours of white light except red, then it will appear red in colour. If the light striking that object does not contain a red component, then no light will be reflected by the object and that object will appear black in colour.

Similarly, a filter works by filtering out one or more colours from light that passes through it. The colour that appears through a filter is the one that is allowed by a filter.

Hence, a red filter will only allow red light to pass through it and will block out the rest.

So, Option (d) is the correct choice.

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a piston presses down on a sealed cylinder filled with gas until the gas occupies a space that is half as big as before. as a result, the pressure on the gas is

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A piston presses down on a sealed cylinder filled with gas until the gas occupies a space that is half as big as before. as a result, the pressure on the gas becomes doubled.

When the piston is pushed down in a cylinder filled with gas What happens to the volume of the gas inside?

When the pressure on the piston is doubled, it moves down until the pressure exerted by the gas equals the pressure exerted by the piston. At this point, the volume of the gas is halved. If the pressure on the piston is again doubled, the volume of gas decreases to one-fourth of its original volume.

What happens to the pressure in a sealed container if the amount of gas in the container increases?

Pressure increases.

Why does the pressure inside a container of gas increase if more gas is added to the container?

The pressure inside a container of gas increases when more gas is added to the container because the volume of the container doesn't change, and the added gas adds more molecules to push against the sides of the container. It is the movement of the gas molecules pushing against the container that causes pressure.

Thus, pressure is doubled.

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Speed of a body spinning about an axis increases from rest to 100 rpm in 5 second if a constant torque is applied. The external torque is then removed and the body comes to rest in 100sec due to friction Find the frictional torque.

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All of the following are internal factors that may negatively affect an individual with dementia EXCEPT A. frustration.

What is dementia's medical condition?

Dementia is a medical condition capable of altering individual skills to remember and also to reason during decision-making, which is due to irreversible degeneration of neuronal cells in the brain that lead to a complete state or a false sense of reality in the individual according to the surrounding environmental conditions.

Dementia medical conditions are often associated with aging because they may lead to different degenerative neuronal problems, which must be treated in a proper clinical setting since the person is unable to live in normal conditions on his or her own.

Therefore, with this data, we can see that dementia medical condition that must be treated in clinical medical settings and it is associated with an irreversible loss of neuronal networks in the brain.

Complete question:

All of the following are internal factors that may negatively affect an individual with dementia EXCEPT:

Frustation

Fear and confusion

False beliefs

Fatigue

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The frictional torque of the spinning body is determined as  ( I × 2.1 ) N/m.

What is frictional torque?

Friction torque is the force between two objects that causes one of them to rotate around an axis.

Also, friction torque is the torque caused by the frictional force that occurs when two objects in contact move.

The frictional torque is calculated by applying the following equation as shown below.

τ = Iα

where;

I is the moment of inertia of the bodyα is the angular acceleration of the body

The angular acceleration of the body is calculated by applying the following equation as shown below.

α = Δω / Δt

α = ( ωf - ωi ) / ( t₂ - t₁)

where;

ωf is the final angular velocity of the body = 100 rpm ωi is the initial angular acceleration of the bodyt₁ is the initial time of motion of the bodyt₂ is the final time of motion of the body

α = ( ωf - ωi ) / ( t₂ - t₁)

ωf = 100 rev/min x 2π rad/rev x 1 min / 60s = 10.5 rad/s

α = ( 10.5 - 0 ) / ( 5 - 0 )

α = 2.1 rad/s²

The frictional torque is calculated as follows;

τ = Iα

τ = ( I × 2.1 ) N/m

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what is the only force that can act on an object in free fall? gravity friction air resistance speed; increasing which factor will cause the gravitational force between two objects to decrease?; what determines the strength of the gravitational force of an object in space; what are the units of mass and weight; which factors affect the gravitational force between two objects select all that apply; if siobhan hits a 0.25 kg volleyball with 0.5 n of force, what is the acceleration of the ball? m/s2; what is the weight, on earth, of a book with a mass of 1.5 kg? 1.5 n 6.5 n 11.3 n 14.7 n

Answers

In Newtonian physics, free fall refers to any motion of a body in which gravity is the only force acting on it.

What are the forces at work on a falling object?

In addition, gravity is pulling something down as it falls. The force of gravity is an unbalanced force at the beginning of the fall. As a result, the object accelerates or picks up speed. It runs into aerodynamic drag or air resistance as it accelerates.

What is the force responsible for an object falling to the ground?

All objects on Earth experience weight, or a gravitational pull that is proportional to their mass and is imposed by the planet's mass. Gravity is measured by the acceleration that it gives to freely falling objects. At Earth's surface the acceleration of gravity is about 9.8 metres (32 feet) per second per second.

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as a care package falls from a high-flying stationary helicopter, its velocity increases and its acceleration___

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A care package drops from a stationary high-flying helicopter with increased velocity and decreased acceleration.

An item that falls through a vacuum is exposed to only one external force, the gravitational force, represented as the weight of the object. An item that is moving simply because of the influence of gravity is said to be free falling and its motion is defined by Newton’s second law of motion. With algebra we can solve for the acceleration of a free falling item. The acceleration is constant and equal to the gravitational acceleration g which is 9.8 meters per square second at sea level on the Earth. The weight, size, and form of the item are not a consideration in characterizing a free fall. A beach ball falls with the same velocity as an airplane in a vacuum.

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planck introduces quantized exchange of energy between the fundamental modes of vibration in the blackbody emitter with the universe.T/F

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Planck introduces quantized exchange of energy between the fundamental modes of vibration  is true statement.

In 1900, Planck proposed that the energy of the oscillators (or "modes of vibration") in a blackbody emitter could only be exchanged in discrete packets or "quanta" rather than continuously. This idea was revolutionary at the time, as it went against the classical laws of physics that had been accepted for centuries. Planck's theory was able to explain the observed blackbody spectrum much more accurately than classical theories, and it laid the foundation for the development of quantum mechanics.

However, it is important to note that Planck's theory did not fully explain the behavior of blackbody emitters. It was later refined and extended by other physicists, including Albert Einstein and Niels Bohr, who developed a more complete theory of quantum mechanics.

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the distances to the nearest 100,000 or so stars can be measured by which of the following techniques? group of answer choices redshift triangulation brightness-distance techniques radar ranging measuring tape

Answers

Triangulation can be used to calculate the separations between the closest 100,000 or so stars.

What is the triangulation method of measuring distance?

A surveying technique called triangulation measures the angles of a triangle made up of three survey control sites. The additional dimensions there in triangle are determined using geometry and the reported length of always one side.

Why is the procedure of triangulation used?

A process of analyzing study results using many data collection methods is known as triangulation. It serves three key functions: to improve validity, to paint a clearer image of a study problem, and to examine various approaches to problem-solving.

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