Show work, can someone help me out having trouble with this problem

can u please tell if the figure is a right angled triangle??...cuz in order to find the perimeter, Pythagoras theorem must be applied but it's only for right angled triangle...so specify please

Answer:

Area of a triangle = 1/2 * base * height

here ,

base = 120 ft

height = 25 ft

Area = 1/2* 120*25

= 60 * 25

= 1500 ft²

Answer 2

Answer:

1/2 * base * height

so 1/2 * 25 * 120

= 1500

Construct OD and BD. Then, in quadrilateral ABOD, angles ODA and OBA are right angles and thus angle DOB is 130 degrees (since angles in a quadrilateral add to 360 degrees).

So, this means arc DB also measures 130 degrees. Hence, by the inscribed angle theorem, angle BCD is 65 degrees.

Answer:

25 < t < 350

Step-by-step explanation:

The mean lifetime of a bulb ranges from 25 to 350 hrs but the question is unclear.

Answer:

-3/2

Step-by-step explanation:

First, you divide by taking the reciprocal of -2/5 which is -5/2.

Second, you get the answer which is -5/4.

Add that with -1/4 and you will get -6/4.

Simplify to get the answer which is -3/2.

Answer:

[tex]-\dfrac{3}{2}[/tex]

Step-by-step explanation:

Given expression:

[tex]\dfrac{\dfrac{1}{2}}{-\dfrac{2}{5}}+\left(-\dfrac{1}{4}\right)[/tex]

To divide fractions, flip the second fraction (make the numerator the denominator, and the denominator the numerator) then multiply it by the first fraction:

[tex]\implies \dfrac{1}{2} \times -\dfrac{5}{2}+\left(-\dfrac{1}{4}\right)[/tex]

To multiply the fractions, multiply the numerators and multiply the denominators:

[tex]\implies \dfrac{1 \times (-5)}{2 \times 2} +\left(-\dfrac{1}{4}\right)[/tex]

[tex]\implies -\dfrac{5}{4} +\left(-\dfrac{1}{4}\right)[/tex]

Apply the rule -a + (-b) = -a - b :

[tex]\implies -\dfrac{5}{4} -\dfrac{1}{4}[/tex]

As the denominators are the same, subtract the numerators and put the answer over the same denominator:

[tex]\implies \dfrac{-5-1}{4}[/tex]

[tex]\implies -\dfrac{6}{4}[/tex]

Simplify by dividing the numerator and denominator by the highest common factor:

[tex]\implies -\dfrac{6 \div 2}{4 \div 2}[/tex]

[tex]\implies -\dfrac{3}{2}[/tex]

Step-by-step explanation:

Brackets is the bigger version of parentheses, you first solve the questions inside the parentheses, then move onto brackets.

For example, this question:

[tex]x=-1\\y=-2\\z=3[/tex]

[tex]5x-y[7-4(z-y)][/tex]

plug in x, y, and z.

[tex]5(-1)-(-2)[7-4(3-(-2))][/tex]
[tex]5(-1)-(-2)[7-4(5)][/tex]

[tex]5(-1)-(-2)[7-20][/tex]

[tex]5(-1)-(-2)[-13][/tex]

[tex]-5-(-2)[-13][/tex]

[tex]-5-26[/tex]

[tex]-31[/tex]

I hope you understand better now.

Answer:

pounds (£)

Step-by-step explanation:

pounds are used in countries such as the UK and South Georgia

Total number of multiple-choice questions that Desiree has to answer in Aptitude test = 50

Points given for every correct Answer = +3

Points deducted for every Incorrect Answer = -1

For every question unanswered ,

points Deducted = -0.5

Total Points Obtained by Desiree after Answering all the questions = 110

Number of Answers that Desiree answered correctly = x questions

Number of Incorrect Answers = (50 - x) questions

Then,the Equation representing above situation

→ 3 × x + ( -1 ) × ( 50 - x ) = 110

⇒3x - 50 + x = 110 ----------- equation that represents the given situation

⇒ 4x - 50 = 110

Adding 50, on both sides

→ 4x - 50 + 50 = 110 + 50

⇒ 4x = 160

Dividing both sides by, 4 we get

x = 40

Number of correct answers given by Desiree= 40 questions

Number of Incorrect Answers = 50 - 40

= 10 Questions .

Answer:

Desiree is given an aptitude test with 50 multiple-choice questions. For every correct answer, Desiree will get 3 points. For every wrong answer, 1 point will be deducted. For every question unanswered, 0.5 points is deducted. Desiree did not leave any questions unanswered and gets 110 points on the test.

If x is the number of questions Desiree answered correctly, then the equation that represents the given situation is

3(50 - x) + x = 110

and the equation will have

no solution

.

Step-by-step explanation:

Answer:

[tex]\frac{4}{60}[/tex] = [tex]\frac{1}{15}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

The value of x if both lines intersect is 2/3

The equation in mathematics is the relationship between the variables and the number and establishes the relationship between the two or more variables.

Given the equation of a line that passed through the points (0, 4) and (1, 1) expressed as h(x) = -3x +4

The equation of the second line g(x) passing through the points (-2, 2) and (0, 2) is g(x) = 2

If the lines intersect, then h(x) = g(x)

Substituting the functions to get the value of "x"

-3x + 4 = 2

Subtract 4 from both sides

-3x + 4 - 4 = 2 - 4

-3x = - 2

Divide both sides by - 3

x = 2 / 3

Hence the value of x if both lines intersect is 2/3

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Answer:

2/3

Step-by-step explanation:

edge23

Answer:

4 secs

Step-by-step explanation:

Since they have to be synchronized, their parabolic equations must be equal to one another

3(t^2 + 9 - 6t) - (t^2 + 25 - 10t) - t + 2 = 0

2t^2 - 9t + 4

(2t - 1)(t - 4) = 0

t = 1/2, 4

From the options, the answer is 4

The gymnasts will be at the same height during their flips at two different times: 1/2 seconds and 4 seconds.

so, correct option is: C.

Here, we have,

To determine when the gymnasts will be at the same height during their flips, we need to find the time (x) at which the equations for y are equal.

The given equations are:

y = –(x – 5)² + 3

y = –3(x – 3)² + x + 1

Setting the two equations equal, we have:

–(x – 5)² + 3 = –3(x – 3)² + x + 1

Expanding the squared terms:

–(x² – 10x + 25) + 3 = –3(x² – 6x + 9) + x + 1

Simplifying the equation:

–x² + 10x – 25 + 3 = –3x² + 18x – 27 + x + 1

Combining like terms:

–x² + 10x – 22 = –3x² + 19x – 26

Rearranging the equation:

2x² - 9x + 4 = 0

To solve this quadratic equation, we can factor it:

(2x - 1)(x - 4) = 0

Setting each factor equal to zero:

2x - 1 = 0 or x - 4 = 0

Solving for x:

2x = 1 or x = 4

Dividing by 2:

x = 1/2 or x = 4

Therefore, the gymnasts will be at the same height during their flips at two different times: 1/2 seconds and 4 seconds.

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Answer:

y = 3/4x + 2

Step-by-step explanation:

let me know if you want an explanation :))

Step-by-step explanation:

area of rectangle= 12×6

=72ft^2

A2=9ft^2 whereby the base of the hole is 3ft

height is 6ft

therefore the square is 18 ft

The system of equations are:

$12p + $3a = $258

a - p = 6

Where:

Two linear equations would be derived from the question. The linear equations would be a function of the phones and accessories sold. These equations are known as simultaneous equations and they would have to be solved together in order to determine the required values.

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Answer:

x = 9

Step-by-step explanation:

x-2 = 7

you solve by adding 2 to both sides to maintain equality. and you add by 2 to cancel out the -2 to isolate the x.

x = 9

Answer:

answer= 3

hope this helps if not I'll try to do it again

Answer:

the answer will be 36

Step-by-step explanation:

if you divide 24 by 8 it will be 3 so then you multiply 12 times 3 and it's 36

The fraction of their student loan will be left to spend is half of their loan.

A number expressed quotient, in which numerator is divided by denominator is called a fraction.

Let the loan amount be $100.

Expenses for food is given that two fifths of their loan

i.e.

= 2/5 × 100

= $40

Now,

Remaining part will be = $100- $40 = $60

So,

Expenses for travel are given that one sixth of their loan,

i.e.

= 1/6 × 60

= $10

So,

Remaining part will be = $60 - $10 = $50

Hence, the fraction of their student loan will be left to spend is half of their loan.

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Answer:

B or 40.67mph

Step-by-step explanation:

To solve we will use formula distance over total time, so are distance is 183miles and are time is 4 hours and 30 minutes. If we put that in hours we get 4.5 hours. Now we simply divide 183/4.5 to get about 40.67 .

Answer:

B: 3/4a + 1/2b - 3

Step-by-step explanation:

Assuming the dilation is centered at the origin, the scale factor is 1/3.

This means the coordinates of the point (8,4) are [tex]\boxed{\left(\frac{8}{3}, \frac{4}{3} \right)}[/tex]

The probability of selecting a jack, replacing the card, and then selecting a king is 1/169

In a standard deck of cards, we have:

Total = 52

Jack = 4

King = 4

The probability of each is:

P(Jack) = 4/52

P(King) = 4/52

So, we have:

P = 4/52 * 4/52

Simplify

P = 1/13 * 1/13

Evaluate

P = 1/169

Hence, the probability is 1/169

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Answer:

I exactly don't have or know the answer

Answer: [tex]f(x)=-\frac{1}{2}x+1[/tex]

Step-by-step explanation:

The slope is [tex]\frac{-1-1}{4-0}=-\frac{1}{2}[/tex], which matches the second option.

Linear function that is represented by the graph is f(x)= -1/2 x+1.

Here, we have,

From the graph,

y - intercept of the linear function is 1 , i.e. c = 1

and there are two points on the line (-4, 3), (4, -1)

We can get the equation of line by applying slope-intercept formula,

Slope of the line,

m = y₂ -y₁ / x₂-x₁

so, we get,

m = -1 -3 / 4 + 4

   = -4/8

   = -1/2

Now applying slope-intercept formula,

y = mx+c

Putting the values,

=> y = -1/2 x + 1

=>f(x) = -1/2 x + 1.

Therefore, linear function that is represented by the graph is

f(x) = -1/2 x + 1.

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The given statement is false.

What is the effect of a row operation on a determinant?

The factor by which a row operation intends to change the determinant is not equal to the determinant of the elementary matrix corresponding to that row operation. Rather, when a row is scaled up by a factor in a matrix, the determinant of that matrix also scales up by that factor.

Similarly, the factor by which a row operation changes the determinant is equal to the factor times the determinant of the elementary matrix corresponding to that row operation.

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Answer:

6 to 9 meals

Step-by-step explanation:

9 If he feeds 2 pounds per meal. 18÷2 =9

6 if he feeds 3 pounds per meal. 18÷3=6

The molarity of the resulting solution is 3.99 × 10⁻⁴ M. The correct option is the third option 3.99 × 10⁻⁴ M

From the question, we are to determine the molarity of the resulting solution

From the given information,

Number of moles = 5.99 × 10⁻⁶ mol

Volume = 1.50 × 10⁻² L

Using the formula,

Molarity = Number moles / Volume

∴ Molarity = (5.99 × 10⁻⁶) / (1.50 × 10⁻²)
Molarity = 3.99 × 10⁻⁴ M

Hence, the molarity of the resulting solution is 3.99 × 10⁻⁴ M. The correct option is the third option 3.99 × 10⁻⁴ M

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Answer:

The answer is 3.99 × 10–4 M

Step-by-step explanation:

I just did the assignment on Edge :)

[tex]\boxed{\sf x = \dfrac{c}{b} \quad or \quad \dfrac{-b}{a}}[/tex]

Explanation:

Given expression: (ab)x^2 + (b^2 - ac)x + (-bc) = 0

Here given:

Apply quadratic formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \quad when \ ax^2 + bx + c = 0[/tex]

Insert values:

[tex]\sf x = \dfrac{-(b^2 - ac) \pm \sqrt{(b^2 -ac)^2-4(ab)(-bc)} }{2(ab)}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac \pm \sqrt{\left(b^2-ac\right)^2+4abbc} }{2ab}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac \pm \sqrt{b^4+2b^2ac+a^2c^2} }{2ab}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac \pm \sqrt{\left(b^2+ac\right)^2} }{2ab}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac \pm( b^2+ac )}{2ab}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac +( b^2+ac )}{2ab} \quad or \quad \dfrac{-b^2 + ac -( b^2+ac )}{2ab}[/tex]

[tex]\sf x = \dfrac{2ac}{2ab} \quad or \quad \dfrac{-2b^2}{2ab}[/tex]

[tex]\sf x = \dfrac{c}{b} \quad or \quad \dfrac{-b}{a}[/tex]

Apply quadratic formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-(b^2 - ac) \pm \sqrt{(b^2 -ac)^2-4(ab)(-bc)} }{2(ab)}[/tex]

[tex]\\ \sf\Rrightarrow x= \dfrac{-b^2 + ac \pm \sqrt{\left(b^2-ac\right)^2+4abbc} }{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-b^2 + ac \pm \sqrt{b^4+2b^2ac+a^2c^2} }{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-b^2 + ac \pm \sqrt{\left(b^2+ac\right)^2} }{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-b^2 + ac \pm( b^2+ac )}{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-b^2 + ac +( b^2+ac )}{2ab} \quad or \quad \dfrac{-b^2 + ac -( b^2+ac )}{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{2ac}{2ab} \quad or \quad \dfrac{-2b^2}{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{c}{b} \quad or \quad \dfrac{-b}{a}[/tex]