Simplify C (9, 3)

3!
6!9!

9!
3!

9!
6!3!

3!
9!

The percentage change from 48 to 90 is 87.5%.

A percentage is a value or ratio that may be stated as a fraction of 100. If we need to calculate a percentage of a number, we should divide it's entirety and then multiply it by 100.

In this case, 48 to 90 represents a increase. The increase will be:

= 90 - 48

= 42

The percentage increase will be:

= Increase / Original number × 100

= 42 / 48 × 100

= 87.5%

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Answer:

Step-by-step explanation:

354

Answer:

Step-by-step explanation:

Step 1:

Start by setting it up with the divisor 12 on the left side and the dividend 6 on the right side like this:

 12 ⟌ 6    

Step 2:

The divisor (12) goes into the first digit of the dividend (6), 0 time(s). Therefore, put 0 on top:

      0    

 12 ⟌ 6    

Step 3:

Multiply the divisor by the result in the previous step (12 x 0 = 0) and write that answer below the dividend.

       0    

 1 2 ⟌ 6    

       0    

Step 4:

Subtract the result in the previous step from the first digit of the dividend (6 - 0 = 6) and write the answer below.

      0    

 12 ⟌ 6    

  - 0    

   6    

You are done.

The answer is the top number and the remainder is the bottom number.

Therefore, the answer to 6 divided by 12 calculated using Long Division is:

0

6 Remainder

The 12 terms of the series will be -

3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25

The formula to calculate the nth term of an Arithmetic Sequence is -

a(n) = a + (n - 1)d

a - first term of A.P.

d - Common difference of A.P.

n - position of term

We have -

a[1] = 3

a[12] = 25

Then, using the formula to calculate the nth term, we get -

a(n) = a + (n - 1)d

a[1] = 3

AND

a(12) = 3 + 11 x d

25 = 3 + 11d

22 = 11d

d = 2

So, the terms of the series will be -

3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25

Hence, the 12 terms of the series will be -

3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25

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The total number of small boxes is 2.1 and the large boxes is 6.3.

Given;

To build a house, a contractor has to purchase nails. Both small and large boxes of nails are provided. There are 150 nails in each small box and 400 in each large box. The contractor purchased 3 more tiny boxes than large boxes. Totaling 2850 nails.

To calculate the proportion of small and large boxes that were bought,

Let's assume the small boxes as 's' and the big boxes as '3s'.

∴ s(150) + 3s(400) = 2850

  150s + 1200s = 2850

  1350s = 2850

  s = 2850/1350

  s = 2.1

∴ 3s = 2.1 * 3

      = 6.3

Hence, the total number of small boxes is 2.1 and the number of large boxes is 6.3.

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Answer:

The number of small boxes purchased are 3 and the number of large boxes purchased are 6.

Step-by-step explanation:

Let the small boxes bought be x

Therefore the large boxes will be 2x

Total nails bought = 2850

Nails in x small boxes = 150x

Nails in 2x large boxes = 400. 2x = 800x

2850 = 150x + 800x

2850 = 950x

x= 2850/950 =  3

2x = 2x3= 6

The required permutations are given as 168 letters will be formed.

Given that,
How many different 8-letter permutations can be formed from 6 identical h's and two identical t's is to be determined.

In arithmetic, combination and permutation are two different ways of grouping elements of a set into subsets. In combination, the components of the subset can be recorded in any order. In a permutation, the components of the subset are listed in a distinctive order.

Here,
A total number of combinations = 8!
The number of repetitions,  = 5!.2!
Permutation of letters = 8!/[5!.2!]

Thus, the required permutations are given as 168 letters will be formed.

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Lance had a gross pay of $117.5 working on Friday and Saturday

To determine his gross pay, we have to find the number of hours he worked and multiply it by his hourly wage.

This can be done by;

4pm - 9pm = 5 hours.

But he had a non-paid 30 minutes break which will give us his work hours on Friday as 4 hours 30 minutes or 4.5 hours.

On Saturday, he worked from 12pm - 6pm which will give us a work time of 6 hours. He also took a non-paid 30 minutes lunch and his total work time on Saturday is 5 hours 30 minutes or 5.5 hours.

If we add the total numbers of hours worked, we will get

4.5 + 5.5 = 10 hours.

Now we can multiply this by the hourly wage.

10 * 11.75 = 117.5

His gross pay is $117.5

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1.62 is the volume (in cm3) of 2 troy ounces of pure gold .

What is full answer for density?

We determine the volume, V, corresponding to the given amount of gold. We do this by dividing the given mass, m, by the density, d, such that

               V = m/d

  m = 31.03 g

   d = 19.3 g/ml

We proceed with the solution

  V = m/d

     = 31.03/19.3

      ≈ 1.62 ml

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The third quartile (upper quartile) of the data is 38

What is the Median?

The center value or middle value of a data set is the median.

What are the Upper Quartiles?

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

The given data is 33, 25, 42, 25, 31, 37, 46, 29, 38

Order the data set given as:

25, 25, 29, 31, 33, 37, 38, 42, 46

Upper Quartile = 25, 25, 29, 31, 33, 37, 38, 42, 46 = 38

Therefore, the third quartile (upper quartile) of the data is 38

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A loss of 8 points is the situation which is represented by integer -8.

A number system is defined as a system of writing to express numbers.

The situation that could be represented by -8 is option C, a loss of 8 points.

The negative sign indicates a decrease or loss in value.

A distance of 8 meters above sea level represents a positive number because the distance is above.

A rise in temperature of 8 degrees is also positive as it is increasing.

A gain of $8 is also represents the positive value.

-8 represents a loss of 8 points.

The negative sign denotes a decrease or loss in value.

Hence, a loss of 8 points is the situation which is represented by integer -8.

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Step-by-step explanation:

[tex]- 4u + 3 + 6u =5 + 10u \\ ⇒ - 4u + 6u- 10u = 5 - 3 \\ ⇒ - 8u = 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ ⇒u = - \frac{2}{8} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = - \frac{1}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

The time taken in minutes to fill a tank having a capacity or work of 1.5m³ is 1.2 minutes;

What are Time and Work?

According to fundamental mathematical concepts, time may be described as the amount of time that a specific activity occurs, whereas work can be described as the collection of actions carried out in order to attain a specific activity or outcome. It should go without saying that time is needed to accomplish a task. It implies that time and work have a certain relationship.

The task completed is calculated as the sum of the number of people participating in the work and the number of days it took to finish. The fundamental time and work equation is W = N X D.

W is the amount of work done.

N is the number of people.

D is the number of days or hours needed.

In the question, It is given that:

water flowing off a certain pipe is 75 liters per minute;

and;

the tank has a capacity of 1.5m³

First converting the Efficiency in liters per second,

So,

water flowing off a certain pipe is 75 liters per minute;

So, dividing it by 60 ;

Water flowing off the pipe = 1.25;

Now using the work-time relationship:

Efficiency × Time = work;

So,

1.25×Time = 1.5

⇒Time = 1.2

So, the time taken in minutes to fill a tank having a capacity of 1.5m³ is 1.2 minutes;

Hence,

the time taken in minutes to fill a tank having a capacity of 1.5m³ is 1.2 minutes;

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Answer:

[tex]b=\frac{-4i-2}{i}[/tex]

So the answer is...

A ) -2

Step-by-step explanation:

Take a look at the attachment...

Hope this helps! :)

As per the given ratio, the number of boys in the school is 133.

Ratio:

Ratio refers the relationship between two things when it is expressed in numbers or amounts.

Given,

The ratio of girls to boys in the school is 3 to 1.

Here we need to find the number of boys in the school if the total number of students is 400.

Let x be the number of boys in the school.

So, the here we have the ratio from girls to boys and we have to convert it into boys into girls, then we get,

=> girls to boys ratio = 3:1

So, boys to girls ratio = 1:3

We know that the total number of students are 400

Therefore, the number of boys in the school is,

=> 1/3 x 400 = 133

So, the number of boys in the school is 133.

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Answer:

66

Step-by-step explanation:

180 - 114)  These angles are supplemental.  They add to 180

66

Answer:

m<6=66°

Step-by-step explanation:

Because m<2 and m<3 are both on a straight line, we know they must add to 180°:

m<2 + m<3 =180

We know m<3=114°, so:

m<2 +114 = 180

m<2 = 66

Since AB|CD, m<2 and m<6 are corresponding angels, making them equal, and so m<6=66°.

Answer:

300kg

Step-by-step explanation:

125/100=x/240

30000=100x

x=300

Answer:

Step-by-step explanation: do your work

it 5x=_2

Answer:

7/5

Step-by-step explanation:

trust me

Any piece of luggage must have a length, width, and height combined that is less than or equal to 150 cm. A traveler requests to take a package with the maximum permitted volume. if the length and width are to be equal, then the dimensions would be 48*96*72

Any piece of luggage must have a length, breadth, and height combined that is 216 cm or less.

L+W+H=216 (because we want the max volume, we may ignore the "less than part" and set them equal) (since we want the max volume, we can ignore the "less than part" and set them equal)

L = W if the length and width are equal.

Let's construct this new equation by swapping L for W.

Arrange H to the left so that H=216-2W when 2W+H = 216

Consequently, what is volume V=L*W*H=W=W2*(216-2W) =216W2-2W3 div./dW=432W-6W?

2\s432W-6W^2=0

72w-w2=0 divided by 6 on both sides.

W = 72 L H = 72 cm

L=2W is the only item that has altered.

Given that L+W+H=216 and that V=L*W*H=2W*W*(216-3W) =432W2-6W, 3W+H=216

864W-18W2 x 3 V prime

Set V prime to 0, solve it by dividing both sides by 18, and you'll get W = 48. dimensions will be

48, 96, and 72 cm in width ,lenght and height

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The next consecutive even integer represented by the statement is a + b + 3.5

The statement in the question is represented as

a+b+1.5 is an even integer

As a general rule of numbering;

In this case, the integers have a difference of 2

This is so because, they are even integers and even integers have a difference of 2

Solving further, we can represent the integer with x

So, we have

Current integer = a+b+1.5

Rewrite properly

This gives

Current integer = a + b + 1.5

Recall that:

even integers have a difference of 2

This means that

Next consecutive integer = Current integer + 2

Substitute the known values in the above equation, so, we have the following representation

Next consecutive integer = a + b + 1.5 + 2

Evaluate the sum in the above equation

Next consecutive integer = a + b + 3.5

Hence, the next integer is a + b + 3.5

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An equation which has an extraneous solution is: C. √x = -5.

In Mathematics, an extraneous solution can be defined as a type of solution (root) to a squared equation or transformed equation that isn't a direct solution (root) of the original equation.

This ultimately implies that, extraneous solutions are numerical values that are obtained when we solve equations that aren't solutions to the original equation as shown below:

Taking the fifth root of both sides of the equation, we have:

[tex]\sqrt[5]{x} = -2\\\\(\sqrt[5]{x})^5 = -2^5\\\\[/tex]

x = -32.

Taking the cubic root of both sides of the equation, we have:

∛(x + 1) = 10

[∛(x + 1)]³ = 10³

x + 1 = 1000

x = 1000 - 1

x = 999.

Taking the fourth root of both sides of the equation, we have:

[tex]\sqrt[4]{x-5} =3\\\\(\sqrt[4]{x-5})^4 =3^4[/tex]

x - 5 = 81

x = 81 + 5

x = 86.

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The number of classes is equal to the number of variables plus 2. A pie chart can be used to summarize the data. The upper and lower class limits must be calculated. correct option is (A).

A Pie Chart is a way of summarizing a set of nominal data or displaying the different values of a given variable. This of chart is a circular divided into a series of of segments. each segment represents a particular category. A pie chart uses percentage to compare information.

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The question was incomplete. Check below the complete question.

When data is collected using a qualitative, nominal variable (in other words, male or female), what is true about a frequency distribution that summarizes the data?

A) The upper and lower class limits must be calculated.

B) Class midpoints can be computed.

C) The "2 to the k rule" can be applied.

D) The number of classes corresponds to the number of a variable's values

The maximum number of people Eddy can invite is 37.

The equation is simply used to show the relationship between the variables given.

In this case, it is going to cost him $150 to cater the party, plus $4 per person for drinks and he only has $300 to spend.

Let the number of persons be represented by p

The equation will be:

150 + (4 × p) = 300

150 + 4p = 300

Collect like terms

4p = 300 - 150

4p = 150

Divide

p = 150 / 4

p = 37.5

The maximum number is 37.

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Answer:

Rule SAS; side angle side

Step-by-step explanation:

Since they give that DM and CM are equal, and BM and AM are equal, you already have two sides. And since you have already marked vertical angles (correct because of intersection), you have 2 sides and 1 angle that are equal. This is enough to prove they are equal so it is the rule SAS or side, angle, side.

Answer: andy drove  280 miles in 3 hours

Step-by-step explanation:  are you seriousseious right now?  

Answer:

3:1

Step-by-step explanation:

bc the lcm is 3

Answer:

the ratio is 3/1

Answer:

3/10

Step-by-step explanation:

4/5 - ½

The l.c.m of the Denominator is 10

=8-5/10

=3/10

In the question various points of x and y re given to plot the graph.

here is the plot attached below:

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Answer: Here's a graph:

Step-by-step explanation:

-5x + 18 < -12

subtract 18 from both sides:

-5x + 18 - 18 < -12 - 18

-5x < -30

divide both sides by -5: [remember, when dividing by a negative number you must FLIP the sign direction]

(-5x)/-5 > (-30)/-5

x > 6

or

(6 , ∞)