Answer: 2:3
Step-by-step explanation:
common factor of 42 and 63: 21
42/21= 2
63/21= 3
find the common factor to find the ratio!
therefore the ratio is 2:3
x(y − 3) + n(3 − y)
The probability of a drawing a blue marble from a box of 18 marbles is 2/3. How many green marbles should be added to the box in order to reduce the probability to 1/2?
Answer:
6 green marbles should be added.
Step-by-step explanation:
If the probability of drawing a blue marble from 18 marbles is 2/3 then there are 12 blue marbles because 18 times 2/3 is 12. This means that to reduce this probability to 1/2 you need to add 6 more marbles to the total amount to get it to 24. Now the probability of getting a blue marble is 12/24 which is 1/2.
please help me find the HCF of this
Answer: a
Step-by-step explanation:
[tex]a^{2}=a \cdot a\\a^{2}+ab=a(a+b)[/tex]
Therefore, the HCF is a.
Answer:
a
Step-by-step explanation:
Factorizing both terms :
a² = a × aa² + ab = a × (a + b)The HCF of the terms is a.
Find the indicated side of the
right triangle.
30°
X
X
60
= [?]√]
7
Enter
Answer:
[tex]7\sqrt{3}[/tex]
Step-by-step explanation:
This is a special triangle with the angles being 30-60-90. The adjacent side to the angle of 30 degrees has a length of x * sqrt(3). The opposite side has a length of x. Since the opposite side has a length of 7 here you simply plug that into x * sqrt(3) to find the length of the adjacent side of the angle 30 degrees which gives you 7 * sqrt(3)
This is all the questions I need answers to:
A two-digit locker combination has two non-zero digits and no two digits are the same. Event A is defined as choosing an even digit for the first number, and event B is defined as choosing an odd digit for the second number.
If a combination is picked at random, with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?
A. 4/9
B. 1/2
C. 5/9
D. 5/8
A locker combination consists of two non-zero digits, and each combination consists of different digits. Event A is defined as choosing an even number as the first digit, and event B is defined as choosing an even number as the second digit.
If a combination is picked at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
A. 1/6
B. 5/18
C. 1/2
D. 5/9
A jar contains 5 red marbles and 8 white marbles.
Event A = drawing a white marble on the first draw
Event B = drawing a red marble on the second draw
If two marbles are drawn from the jar, one after the other without replacement, what is P(A and B) expressed in simplest form?
A. 3/13
B. 10/39
C. 5/12
D. 8/13
A bag contains 5 blue marbles, 8 green marbles, 4 red marbles, and 3 yellow marbles.
Event A = drawing a green marble on the first draw
Event B = drawing a blue marble on the second draw
If Jasmine draws two marbles from the bag, one after the other and doesn’t replace them, what is P(B|A) expressed in simplest form?
A. 2/19
B. 1/6
C. 4/19
D. 5/19
A jar contains 3 pink balls, 6 blue balls, and 3 red balls.
Event A = drawing a red ball on the first draw
Event B = drawing a pink ball on the second draw
If two balls are drawn from the jar, one after the other without replacement, what is P(A and B) expressed in simplest form?
A. 3/44
B. 4/9
C. 3/11
D. 1/4
House numbers along a street consist of two-digit numbers. Each house number is made up of non-zero digits, and no digit in a house number is repeated.
Event A is defined as choosing 8 as the first digit, and event B is defined as choosing a number less than 6 as the second digit.
If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?
A. 1/9
B. 5/72
C. 5/8
D. 2/3
House numbers along a street consist of two-digit numbers. Each house number is made up of non-zero digits, and no digit in a house number is repeated.
Event A is defined as choosing 8 as the first digit, and event B is defined as choosing a number less than 6 as the second digit.
If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?
A. 2/7
B. 5/14
C. 5/13
D. 6/13
A two-digit locker combination is made up of two non-zero digits. Digits in a combination are not repeated and range from 3 through 8.
Event A = choosing an odd number for the first digit
Event B = choosing an odd number for the second digit
If a combination is chosen at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
A. 1/5
B. 3/14
C. 5/18
D. 2/5
A locker combination consists of two non-zero digits. The digits in a combination are not repeated and range from 2 through 9.
Event A = the first digit is an odd number
Event B = the second digit is an odd number
If a combination is picked at random with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?
A. 3/8
B. 3/7
C. 1/2
D. 4/7
There are 15 tiles in a bag. Of these, 7 are purple, 5 are black and the rest are white.
Event A = drawing a white tile on the first draw
Event B = drawing a purple tile on the second draw
If two tiles are drawn from the bag one after the other and not replaced, what is P(B|A) expressed in simplest form?
A. 1/5
B. 1/3
C. 7/15
D. 1/2
I know theres a lot here but please hurry :) thx 100 points to the first person to answer all correctly! thx :)
The is probability P(B|A) expressed in simplest form is 1/2 (Option B) See computation below.
How do we derive the above?P (A) = [[tex][\mathrm{C}_{5}^{1} \mathrm{C}_{8}^{1}]/ \mathrm{A}_{9}^{2}[/tex]
= ('5 x 8)/(9 x 8)
P (A) = '5/9
P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]
= ('5 x 4)/(9 x 8)
= '5/18
P(B|A) = P (AB)/P(A)
= ('5/18)/('5/9)
P(B|A) = 1/2
How do we derive P(A and B) in the simplest form?From the above we already have P (AB)
this is given as
P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]
= ('5 x 4)/(9 x 8)
P(AB) = '5/18
How do we derive P(A and B) in the simplest form where a jar contains 5 red marbles and 8 white marbles?Note that:
Event A = drawing a white marble on the first draw
Event B = drawing a red marble on the second draw
P(A) = 8/13; while
P (B) = (5/12) because the first marble was not replaced, thus reducing th sample to 12.
Thus
P(A and B) = P(A)*P(B) = 8/13 * 5/12
P(A and B) = 10/39 (Option B)
If Jasmine draws two marbles from the bag, one after the other and doesn’t replace them, what is P(B|A) expressed in simplest form?Event A - Probability of Drawing a Green Marble is 8/20
Event B - Probability of Drawing a Blue Marble is 5/19
Thus P(B|A) = (8/20) * (5/19)
= [tex]\frac{8 * 5 }{20 * 19}[/tex]
= 40/380; divide numerator and denominator by 20
P(B|A) = 2/19 (Option A)
Event A = Probability of Drawing a red ball = 3/12
Event A = Probability of Drawing a pink ball without replacing the read in Event A = 3/11
Thus P (B and A) =
3/12 x 3/11
P (B and A) = 3/44 (Option A)
If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?The conditions given are as follows:
The house number comprises of nonzero digits and are of two digits ranging from 1 to 9.As per the condition, the First digit 8 can be selected in 9 ways; and Second digits is less than 6 can be selected in waysThe sum total of ways thus is
9 x 8
= 72 ways........X
Recall that
Event A is defined as selecting 8 as the first numeral
The only way to select this is one way
Event B is defined as choosing a number less than 6 as the second digit, that is 1, 2, 3, 4, 5
Thus, the possible number of ways to fill second digit = 5/8
Thus, the possible number of ways to form two digits 'AnB' =
('AnB') = 1 x 5 = 5 .................y
Hence Probability (AnB) = 5/72 (Option B)
Given that the non-zero digits are in a combination are not repeated and range from 3 through 8, thus the odd numbers between 3 and 8 are:
3, 5, 7
total numbers is 3, 4, 5, 6, 7, 8
Hence; Event A = choosing an odd number for the first digit = 3/6
Event B = choosing an odd number for the second digit (recall that the numbers are not repeated) = 2/5
= [tex]\frac{2*3}{3*6}[/tex]
= 6/30
= 1/5 (Option A)
If a combination is picked at random with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?
Event A = the first digit is an odd number
Event B = the second digit is an odd number
The numbers from 2 to 9 are:
2,3,4,5,6,7,8,9
The odd numbers between 2 and 9 are:
3,5,7,9
P (A) = 4/8
P (B) = 3/7
P(B|A) = (3/7)/(4/8)
P(B|A) = 3/7
Event A = drawing a white tile on the first draw
Event B = drawing a purple tile on the second draw
P(B|A) = (P(AnB)/P(A)
|n| = 15 * 14 = 210
| A| = 3*14 = 42
| AnB| = 3*7 = 21
P (A) = 42/210 = 6/30
P (AnB) = 21/210 = 1/10
P(B|A) = (1/10)/6/30)
P(B|A) = 1/10 * 30/6
P(B|A) = 30/60
P(B|A) = 1/2 (Option D)
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What is (-2)-(-2 1/6) and how do i get that answer?
Answer:
1/6
Step-by-step explanation:
-2 - (-2 1/6)
multiply the number in the parentheses by -1
-2 + 2 1/6
-2 + 2 cancels out
Leaving 1/6 as your answer.
Consider the transformation shown. 2 triangles are shown. The first is labeled pre-image and the second is labeled image. Both triangles have congruent angle measures. The pre-image has side lengths of 6, 10, and 8. The image has side lengths of 3, 5, and 4. Use the drop-down menus to complete the sentence. The transformation is because the preserved.
The transformation is non-rigid because the side lengths are not preserved.
How to complete the drop-down menus?The drop-down menus and the image of the triangles are not given.
However, the question can still be solved using the available parameters.
The given parameters are:
Pre-image: 6, 10, 8
Image: 3, 5, 8
See that the side lengths of the image and the pre-image are not the same
This means that the transformation is a non-rigid transformation
Hence, the complete statement is the transformation is non-rigid because the side lengths are not preserved.
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Which equation is equivalent to the given equation?
-4(X - 5) + 8x = 9x - 3
Answer:
-5x=-23
Or
X=23/5
Step-by-step explanation:
what 1 - 2/9 - 1/3 - 1/6 =
Answer:
5/18
Step-by-step explanation:
The LCD of 9, 3, and 6 is 18.
1 - 2/9 - 1/3 - 1/6 =
= 18/18 - 4/18 - 6/18 - 3/18
= 5/18
Answer: 5/18
Step-by-step explanation:
1/1 - 2/9 - 1/3 - 1/6
18 - 4 - 6 - 3/18
5/18
Calculate the AREA of the shape below. Give your answer in cm²
Answer:
[tex] \boxed{\bf 26\: cm^2} [/tex]Step-by-step explanation:
We got two shapes in the given figure,on the right we got a rectangle and on the left we have a square.
Area of rectangle:-
[tex]\bf 5 \times 2[/tex][tex]\bf 10 \:cm^{2} [/tex]Area of square :-
[tex]\bf 4 \times 4[/tex][tex]\bf 16 \: {cm}^{2} [/tex]Total area :-
[tex]\bf 10 + 16[/tex][tex]\boxed{\bf 26 \: {cm}^{2} }[/tex]_________________________Answer:
26 cm^2Step-by-step explanation:
you have two rectangles, the bigest has the base of 6cm and the height of 4cm, the area is 6 * 4 = 24cm ^ 2, the other rectangle has the base of 6 - 4 = 2 and the height of 5 - 4 = 1, 2*1=2.
we add the dimensions and we have the area of the complete figure 24 + 2 =
26 cm ^ 2
What is the solution to this equation?
8x-5(x-3) = 18
OA. x=5
OB. x = 1
OC. x = 11
OD. x=7
Answer:
x=1
Step-by-step explanation:
8x-5(x-3) = 18
The first step is to distribute
8x -5x+15 = 18
Combine like terms
3x+15 = 18
Subtract 15 from each side
3x+15-15=18-15
3x=3
Divide by 3
3x/3 =3/3
x=1
Find the Value of log10 (0.0001). Rescue me!
Let's see
[tex]\boxed{\sf log_aa=1}[/tex]
Now
[tex]\\ \rm\Rrightarrow log_{10}0.0001)[/tex]
[tex]\\ \rm\Rrightarrow log_{10}10^{-4}[/tex]
[tex]\\ \rm\Rrightarrow -4log_{10}10[/tex]
[tex]\\ \rm\Rrightarrow -4[/tex]
Answer:
This has already been answered correctly, but I'll add an additional perspective. The log of (0.0001 to the base 10 is -4.
Step-by-step explanation:
log(base 10) says give us an exponent, x, that would be required to make [tex]10^{x}[/tex] equal to a specified number, in this case 0.0001.
[tex]10^{0}[/tex] = 1
[tex]10^{1}[/tex] = 10
[tex]10^{-1}[/tex] = 0.1
[tex]10^{-2}[/tex] = 0.01
[tex]10^{-4}[/tex] = 0.0001
The log of (0.0001) to the base 10 is -4.
y=-6x-8
y=-6x+8
Solve the system of linear equations
Answer: No solution
Step-by-step explanation:
Both of these equations have the same number as to coefficient of x (-6) but have a different constant (-8 and 8). This means that there are no solutions to this system of equations.
Maria is on a hike. if she hikes to the scenic lookout on the following map first, she will have to hike farther than if she went straight to the end of the hike. 3 connected points on a coordinate plane. the point labeled, "maria," is at 4, -4. the point labeled, "end," is at -5, 5. a solid line connect the points "maria" and "end." the point labeled, "scenic lookout," is at 2, 3. dashed lines connect "maria" to "scenic lookout" and connect "scenic lookout" to "end." coordinate values on the map are in kilometers. how much shorter is the path straight to the end of the hike than past the scenic lookout? round your final answer only to the nearest kilometer. \text{km}kmstart text, k, m, end text
The path straight to the end of the hike is 6 km farther than past the scenic lookout.
How to determine the difference in the parts?The map is not given, but the question can still be answered
From the question, the positions are given as::
Maria = (4, -4)
Scenic = (2, 3)
End = (-5, 5)
The distance between Maria and the end point is calculated using:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]Route\ 1 = \sqrt{(4 + 5)^2 + (-4 -5)^2}[/tex]
[tex]Route\ 1 = 13[/tex]
The distance between Maria and the scenic lookout is calculated using:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]Route\ 2 = \sqrt{(4 - 2)^2 + (-4 -3)^2}[/tex]
[tex]Route\ 2 = 7[/tex]
The distance between both routes is:
Distance = 13 - 7
Evaluate
Distance = 6
Hence, the path straight to the end of the hike is 6 km farther than past the scenic lookout.
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Lindsey is a member of the swim team at a local university. She has been working hard to perfect her dive for an upcoming swim meet. Lindsey's dive can be modeled by the quadratic equation y = – 16x2 + 33x + 45, where x is time in seconds, and y is Lindsey's height in the air in feet.
1. At what time will Lindsey be 30 feet in the air?
2. How high is the diving board? Explain your thinking.
Answer:
1. [tex]x = 2.45s[/tex]
2. The diving board is 45 ft high.
Step-by-step explanation:
• When Lindsey is 30 feet in the air, y = 30.
[tex]30 = -16x^2 + 33x +45\\\\-16x^2 + 33x +15 = 0\\\\16x^2 - 33x -15 = 0\\[/tex]
Using quadratic formula, solve for x:
[tex]x = \frac{33 + \sqrt[]{(-33)^2 - 4(16)(-15)} }{2(16)}[/tex]
[tex]x = 2.45s[/tex]
• If we calculate the height of Lindsey in the air when she is standing on the diving board, we can find the height of the diving board above the ground.
When she is standing on the board, x = 0 as no time has passed after jumping.
[tex]y = -16(0)^2 + 33(0) +45\\\\y = 45 ft[/tex]
(Giving 80 points, Please do not answer if you don't know. The second and third answer are not 4 btw)
Point A is on the point −6 and Point B is on the point 0. Let's use the Ruler Postulate to find the length of AB¯¯¯.
AB=|a−b|
AB=|−6−0|
AB=|−6|
AB=6
The length of AB¯¯¯¯ is 6. We can also write this as AB=6 or mAB¯¯¯¯=6.
Find the Length of CD¯¯¯¯
Now, let's find the length of CD¯¯¯¯. Point C is on the point 4 and Point D is on the point 8.
CD=|c−d|
CD=|4−8|
CD=|−4|
CD=4
The length of CD¯¯¯ is 4. We can also write this as CD=4 or mCD¯¯¯=4
Your Turn
1. What is the length of BC¯¯¯? 4
2. What is the length of AC¯¯¯¯?
3. What is the length of AD¯¯¯¯?
Answer:
1. 4
2. 10
3. 14
Step-by-step explanation:
A = -6
B = 0
C = 4
D = 8
1. BC = |0 - 4| = 4
2. AC = |-6 - 4| = |-10| = 10
3. AD = |-6 - 8| = |-14| = 14
Answer:
1. BC = 4
2. AC = 10
3. AD = 14
Step-by-step explanation:
Ruler Postulate
The distance between any two points on a number line is their difference.
Question 1
Given:
Point B = 0Point C = 4Therefore, using the Ruler Postulate:
⇒ BC = |b - c|
⇒ BC = |0 - 4|
⇒ BC = |-4|
⇒ BC = 4
Question 2
Given:
Point A = -6Point C = 4Therefore, using the Ruler Postulate:
⇒ AC = |a - c|
⇒ AC = |-6 - 4|
⇒ AC = |-10|
⇒ AC = 10
Question 3
Given:
Point A = -6Point D = 8Therefore, using the Ruler Postulate:
⇒ AD = |a - d|
⇒ AD = |-6 - 8|
⇒ AD = |-14|
⇒ AD = 14
Find the coordinates of the midpoint of the segment whose endpoints are given W (-3,-7) and X (-8,4)
1. (-11/2) -(11/2)
2.(-5/2)-(3/2)
3.(-5/2-(11/2)
The coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2). Then the correct option is D.
The complete options are given below.
1. (-11/2) -(11/2)
2.(-5/2)-(3/2)
3.(-5/2-(11/2)
4. (-11/2) -(-3/2)
What is the midpoint of line segment AB?Let C be the mid-point of the line segment AB.
A = (x₁, y₁)
B = (x₂, y₂)
C = (x, y)
Then the midpoint will be
x = (x₁ + x₂) / 2
y = (y₁ + y₂) / 2
The end points are given below.
(-3, -7) and (-8, 4)
We have
(x₁, y₁) = (-3, -7)
(x₂, y₂) = (-8, 4)
Then the mid-point will be
x = (- 3 - 8) / 2
x = -11 / 2
y = (-7 + 4) / 2
y = -3/2
Then the coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2).
Then the correct option is D.
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albert worked for 8 hours and earned $24. how much does albert earn for 24 hours
Answer:
$72
Step-by-step explanation:
i need help finding this for clever
Answer:
The dog is 16 years old.
Step-by-step explanation:
X/4 + 6 = X/8 + 8
X/4-X/8 = 8-6
0.125X = 2
X = 2/0.125
X = 16
Answer:
16 years old
Step-by-step explanation
Dividing the dog’s age by 4 and adding 6
D÷4 + 6
dividing the dog’s age by 8 and adding 8
D÷8 + 8
equating both
D÷4 + 6 = D÷8 + 8
=> D÷4 - D÷8 = 2
multiplying by 8 both sides
=> 2D - D = 16
=> D = 16
hence, the dog is 16 years old
Casey picked 6 pounds of strawberries. Karen picked 48 ounces of blueberries. Jude picked 2 pounds of raspberries. They are going to make berry pies. The table shows the amount of berries needed for 1 pie.Select all of the true statements below.
A.
Together, Karen and Jude picked the same weight of fruit as Casey picked.
B.
Casey picked 2 times the weight of fruit that Karen picked.
C.
There are enough berries to make 6 berry pies.
D.
If they make as many pies as they can with the berries they picked, there will be 4 pounds of strawberries left over.
E.
To make 8 berry pies, they will need 1 more pound of blueberries and 2 more pounds of raspberries.
Answer:
Option B is correct
Answer:
B there is enough raspberries to make 4 pie they can 6 pies if they 2 more of raspberries
Which of the following is equivalent to 8-3x > 2(3x - 5) ?
A. 18>9x
B. 9x<13
C. 11>9x
D. -8x>2
Answer:
A
Step-by-step explanation:
Given:
[tex]8-3x > 2(3x-5)[/tex]
Simplify by distributing:
[tex]8-3x > 6x-10[/tex]
Add 10 to left side and add 3x to the right side:
[tex]18 > 9x[/tex]
In a casual italian restaurant, sales for the week of september 15 are as follows: food sales: $10.000 beverage sales: $ 2.500 total $12.500 a. if the food cost is 30 percent, how much did the food actually cost? b. if the beverage cost is 25 percent of beverage sales, how much did the beverages cost?
Answer: $625
Step-by-step explanation:
Total beverage sales = $2,500
Beverage cost = 25%
So, $2,500 x 25% = $2,500 x 0.25 = $625
Write the rate in lowest terms a printer can print 22 pages in 55 seconds
Answer:
2/5
Step-by-step explanation:
22/11=2
55/11=5
Given lJK , which is an isosceles right triangle, IJ=4 and m
As IJK is isosceles
IJ=JKHypotenuse must not counted counted among equal sides so
IK²=2(LJ)²Apply roots
IK=LJ√2Option C
PLEASE HELP I WILL MARK BRAINLEST
#1
Error at sign shift due to -Correct version
[tex]\\ \rm\Rrightarrow (x^3+2x^2-x)-(3x^3-3x^2+2x-4)[/tex]
[tex]\\ \rm\Rrightarrow x^3+2x^2-x-3x^3+3x^2-2x+4[/tex]
[tex]\\ \rm\Rrightarrow x^3+5x^2-3x+4[/tex]
#2
Not multiplied 3x with x[tex]\\ \rm\Rrightarrow (x^2-3x+2)(x+1)[/tex]
[tex]\\ \rm\Rrightarrow x(x^2-3x+2)+x^2-3x+2[/tex]
[tex]\\ \rm\Rrightarrow x^3-3x^2+2x+x^2-3x+2[/tex]
[tex]\\ \rm\Rrightarrow x^3-2x^2-x+2[/tex]
Progress
Solve for x. Round to the nearest tenth, if necessary
Answer:
x ≈ 1.1
Step-by-step explanation:
using the cosine ratio in the right triangle
cos41° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{0.8}{x}[/tex] ( multiply both sides by x )
x × cos41° = 0.8 ( divide both sides by cos41° )
x = [tex]\frac{0.8}{cos41}[/tex] ≈ 1.1 ( to the nearest tenth )
please help!! The dot plots below show the ages of students belonging to two groups of salsa classes:
Based on visual inspection, which group most likely has a lower mean age of salsa students? Explain your answer using two or three sentences. Make sure to use facts to support your answer.
Im thinking group A but at this point im just plain out confused
a) Write 2 expressions for the area of the shaded region.
b) Find the length of the shaded region if the perimeter is 48cm.
c) Find the area of the shaded region if perimeter is 48cm.
Answer:
(a)9×3=37' 97 and 8 are factors of 37
Pls help asap ily
one hour after junior space cadet had left his house, his sister gwen discovered that he had forgotten his head. if junior was driving at a speed of 50 mph, and gwen drove at a speed of 75 mph, how many hours did it take gwen to restore junior's head to his shoulders?
Answer:
2 hours
Step-by-step explanation:
you can write two linear equations and then set them equal to each other to see when they intersect. so for the first equation which will be representing the junior space cadets distance from his house. this can be written as
d = 50t + 50
where t represents time and d represents distance. there is 50 being added to the equation since he had already been traveling for an hour
the second equation which will represent his sister Gwen can be represented as
d = 75t
Now we set them equal to each other
50t + 50 = 75t
50 = 25t
2 = t
solve the inequality 5x+3> 48
Answer:
x > 9
Step-by-step explanation:
for this inequality, we want to isolate x, so that we know the inequality of x
5x + 3 > 48
- 3 -3 {subtract 3 from both sides to get x alone}
5x > 45
/5 /5 {divide both sides by 5 to find 1x}
x > 9
So , x > 9 is the inequality in terms of x {is the solution}
hope this helps! :)
Answer:
[tex]\huge\boxed{\sf x > 9}[/tex]
Step-by-step explanation:
Given inequality:5x + 3 > 48
Subtract 3 to both sides
5x > 48 - 3
5x > 45
Divide 5 to both sides
x > 9
[tex]\rule[225]{225}{2}[/tex]
