simplify this please help

The system of equations which is used to find out the cost of each item (i.e cotton candy and funnel cake) bought by two families McCartney and Lennon Family is

3c + 2f = $24

2c + 4f = $32

We have given that

McCartney family bought

total number of bags of cotton = 3

total number of funnel cakes = 2

total cost of 3 bags and 2 funnel cakes is $24.

Lennon Family bought

total number of bags = 2

total number of funnel cake = 4

total cost of 2 bags and 4 funnel= $32

we have to find out the system of equations which used to find the cost of each item.

let the cost of each funnel cake be f and cotten candy be c .

then, using the above data we get

3c + 2f = $24 ---(1)

2c + 4f = $32 --(2)

Hence, equation (1) and (2) make a system of linear equations which is used to determine the cost of each item.

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Complete question:

HEME At the circus, the McCartney family bought 3 bags of cotton candy and 2 funnel cakes for $24. The Lennon Family bought 2 bags of cotton candy and 4 funnel cakes for $32. Which system of equations could be used to find the cost of each item? Let f represent funnel cake and c represent cotton candy

A shareholders' group, in lodging a protest, claimed that the mean tenure for a chief executive office (CEO) was at least nine years.

a) The hypotheses that can be used to challenge the validity of the claim made by the shareholders' group.

H₀ : u ≤ 9

Hₐ : u > 9

So, the correct option is option (A).

b) T- statistic value is -2.571 for a sample of 90 companies.

c) The critical value for t i.e P-value is 0.0059

d) P-value < α = 0.01, implies reject the null hypothesis. We can conclude that the mean tenure of a CEO is significantly lower than 9 years. The claim of the shareholders group is not valid. So, the correct option is option(D).

We have given that,

x-bar= 7.27 , σ = 6.38, n = 90

a) Test that the mean tenure for a chief executive officer (CEO) was atleast nine years .

Null and alternative hypothesis is

H₀ : u <= 9

Hₐ : u > 9

b) test statistic:

t =( x-bar - μ ) /σ/√n

=> t = (7.27 - 9 )/6.38/90

=> t = - 1.73/0.67251

=> t = -2.571

c) P-value :

P-value = P( tₙ₋₁ < t) = P(t₉₀₋₁ < t )

=> P-value = P( t₈₉< - 2.571)

=>P-value = P( t₈₉ >2.571)

=> P-value = 1 - P( t₈₉< 2.571)

P-value = 1 - 0.9941 = 0.0059

d) Significance level, = 0.01

we see that p-value= 0.0059 < 0.01

Decision : Reject the null hypothesis H₀

We have no evidence to support the claim.

Hence, we calculate all the required result.

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Complete Question :

A shareholders' group, in lodging a protest, claimed that the mean tenure for a chief executive office (CEO) was at least nine years. A survey of companies reported in The Wall Street Journal found a sample mean tenure of x = 7.27 yearsfor CEOs with a standard deviation of

s = 6.38 years.

(a)Formulate hypotheses that can be used to challenge the validity of the claim made by the shareholders' group. multiple choice:

i)H0: μ ≤ 9

Ha: μ > 9

ii)H0: μ ≥ 9

Ha: μ < 9

iii) H0: μ > 9

Ha: μ ≤ 9

iv)H0: μ < 9

Ha: μ ≥ 9

v) H0: μ = 9

Ha: μ ≠ 9

(b)Assume 90 companies were included in the sample. What is the test statistic? (Round your answer to three decimal places.)

c)What is the p-value for your hypothesis test? (Round your answer to four decimal places.)

p-value =

(d) At = 0.01,what is your conclusion? MULTIPLE CHOICE:

The value after double integration is 45.73

We can evaluate rectangle integrals in any order we like in Cartesian coordinates. We treat the other integral as a constant regardless of which integral we assess first; this is something to keep in mind while choosing the order of integration.

We want that x to be constant; we can easily integrate with respect to y. So we will evaluate y first. We get:

[tex]\int\limits^ \int\limits^ \frac{6x}{1+xy} dA=6\int\limits^6_0 \int\limits^1_0 {\frac{x}{1+xy} } \, dydx[/tex]

[tex]or, 6\int\limits^6_0 {[In(1+xy)}_{0} ^{1} ]} \, dx[/tex]

[tex]or, 6\int\limits^6_0 {In(1+x)} } \, -In 1dx[/tex]

[tex]or, 6\int\limits^6_0 {In(1+x)} } \, dx[/tex]

[tex]or,[(1+x)In(1+x)-(1-x)]^{6} _{0}[/tex]

[tex]or,[7In7-In1-7+1]\\or,6(7In7-6)\\or,45.73[/tex]

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this letter in each box that contains the exercise's number. Factoring polynomials can be a tricky process, but it can be done with practice and a few key steps.

The first step is to identify if the polynomial is a prime or a composite. A prime polynomial cannot be factored, while a composite polynomial can be factored into two linear factors. Then, look for two numbers that can be multiplied together to give the constant term, and two numbers that add together to give the coefficient of the x-term. Once you have identified these numbers, factor out the greatest common factor and then separate the remaining terms into two binomials. Finally, use the distributive property to factor the binomials and simplify. The answers are: A. (x+2)(x+3) E. (x+1)(x+6) D. (x+4)(x+5) U. (x+4)(x+3) C. (x+2)(x+6) R. (x+1)(x+15) S. (x+1)(x+12) N. (x+3)(x+5) I. (x-3)(x+5) W. (x-5)(x+3) T. (x-3)(x-5) F. (x+7)(x-4) K. (x+4)(x-7) H. (x-7)(x-4) L. (x-11)(x+3) B. (x-3)(x+11)

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Answer:

y < -1x + 2

y [tex]\geq \\[/tex] 2x + 4

Step-by-step explanation:

The steps taken to find the two inequalities are on the GraphInequalities worksheet.  The derived equations are graphed on DESMOS and attached, for comparison.

The basic steps are to find the slopes of the two lines and to identify the y-intercepts from the graph.  The inequalities can be assigned based on the darkened areas and presence of either a solid or dashed line.  All are outlined in the worksheet.

The expressions presented in options A and D are equivalent to the given expression.

Knowing some of the main power rules.

An algebraic expression is considered equivalent when they are equal.

Thus, for solving this question, you should:

Let's solve each option.

        [tex]\frac{7^2}{7^{-2}}[/tex]= 7² *7²= [tex]7^4[/tex] - this equation is equivalent to the given algebraic expression.

        [tex]\frac{7^6}{7^{-2}}=7^6*7^2=7^8[/tex] - this equation is not equivalent to the given algebraic expression.

        [tex]7^{-12}=\frac{1}{7^{12}}[/tex] - this equation is not equivalent to the given algebraic expression.

        (7²)2= [tex]7^4[/tex] - this equation is equivalent to the given algebraic expression.

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Answer:

Step-by-step explanation:

The value of the function h(x) = -3(x - 1) + 4 when x is -5 is 19.

It is important to note that a function is the statement that illustrates the variables given. In this case, two or more components are taken into consideration to describe the scenario.

In this situation, the function is given a :

h(x) = -3(x - 1) + 4

When x = -5. This will be:

h(-5) = -3(-5 - 1) + 4

= -3(-6) + 1

= 18 + 1

= 19

The value is 19.

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Answer:

the answer is number three

Step-by-step explanation:

820×10 = 8200

We are 67% confident that the proportion of students who are tell me that they did their homework over the weekend.0.087 with a margin of error of 0.0175

In statistics, a confidence interval describes the likelihood that a population parameter would fall between a set of values for a given percentage of the time.

Confidence ranges that include 95% or 99% of anticipated observations are frequently used by analysts.

87/1000 = 0.087

We have a 67% confidence level that the percentage of left-handed students is 0.087, with a 0.0175 margin of error.

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The conclusion that can be made from the given observations is that the dew factor temperature is 90% of the air temperature.

Humidity is the quantity of water vapor withinside the air. If there is lots of water vapor withinside the air, the humidity might be high.

The temperature have to upward push so as for air to come to be saturated with water vapor.

The air holds little water vapor and is rather dry.

The quantity of water vapor withinside the air is 90% of what the air can hold.

The dew factor temperature is 90% of the air temperature.

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Answer: x < 5/3

Step-by-step explanation:

-(4x + 20) < −7(x + 15/7) ............................ Question

-4x - 20 < -7(x + 15/7) ................................ Distribute

-4x - 20 < -7x - 15 ...................................... Distribute

-4x - 20 + 20 < -7x - 15 + 20 ................... Add 20 to both sides

-4x < -7x + 5 ............................................... Simplify

-4x + 7x < -7x + 5 + 7x ............................. Add 7x to both sides

3x < 5 .......................................................... Simplify

3x / 3 < 5 / 3 .............................................. Divide both sides by the same factor

x < 5/3 ......................................................... Simplify

Answer:

11.25. or 11.3 miles

Step-by-step explanation:

Because Ash Ave. and Maple are parallel, this means that you have a pair of similar right triangles. Therefore, you can set up a proportion and solve for the length of Ash Ave.

6 miles/9 miles = 7.5 miles/x miles

x=11.25 miles

Answer:

[tex]y > 3+\frac{x}{2}[/tex]

Hope this helps!

Answer: x<2y-6

Step-by-step explanation:

x-2y<-6

=(x-2y)+6<-6+6

=x-2y+6<0

=(x-2y+6)+(2y-6)<2y-6

=x-2y+6+2y-6<2y-6

=x-2y+2y+6-6<2y-6

=x<2y-6

Answer:

8

Step-by-step explanation:

(4/5)/(1/10)

To solve, flip the second fraction, and instead of dividing, multiply:

(4/5)/(1/10) = (4/5) * (10/1)

Multiply straight across:

(4/5) * (10/1) = (4 * 10)/(5 * 1) = 40/5

SImplify. Divide:

40/5 = 8

8 is your answer.

Hope it helps

The inverse matrix R⁻¹ does not exist

The inverse of a matrix written as A⁻¹ is such that when the inverse matrix multiplies A, the result is the identity matrix.

Given the matrix [tex]R = \left[\begin{array}{ccc}0&0\\1&3\end{array}\right][/tex], to determine if this matrix has an inverse it must satisfy the following condition.

For a matrix A to have an inverse, its determinant must not be equal to zero. That is det(A) ≠ 0

So, to determine if the above matrix has an inverse, its determinant must not equal zero.

So, the determinant of the matrix det(R) = 0 × 3 - 0 × 1

= 0 - 0

= 0

Since the determinant equals zero, thus we see that its inverse R⁻¹ does not exist

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Answer:

y = 21

Step-by-step explanation:

You need to find k

y = x

54 = 9k  Divide both sides by 9

6 =k

y = 6(3.5)

y = 21

Answer:

Grey dice.                  White dice

Step-by-step explanation:

Flip them around, this one really got me lol

the truth table of expression (A+B).A is T ,T ,F,F . A truth table has one column for each input variable (such as P and Q) and a final column that lists all potential outcomes.

Truth tables are mathematical tables that are used in logic, specifically in relation to Boolean algebra, Boolean functions, and propositional calculus. They contain the functional values of logical expressions on each of their functional arguments, or more specifically, for each combination of values that their logical variables can take.

given

( A+B) . A

A          B      (A + B)      (A+B).A

T           T         T                  T

T           F         T                 T

F           T         T                 F

F           F         F                 F

So , the truth table of expression (A+B).A is T ,T ,F,F .

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The probability of acceptance of Jim at both the University as per given acceptance rate is equal to 0.135.

As given in the question,

Acceptance rate of Jim application at University x is equal to 30%

Acceptance rate of Jim application at University y is equal to 45%

Probability of acceptance of application in University x is:

P(x) = 30 /100

      = 0.30

Probability of acceptance of application in University y is:

P(y) = 45 /100

      = 0.45

Probability of acceptance of application at both the University is:

P(x and y) = P(x) × P(y)

                = 0.30 × 0.45

                = 0.135

Therefore, the probability of acceptance application at both the University is equal to 0.135.

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The linear equation that represents the total cost of the gas will be y = 15.7x.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The cost of two gallons of gas is $31.40. Then the rate (slope) is given as,

m = $31.40 / 2

m = $15.7 for each gallon

Let 'x' be the number of gallons of gas and 'y' be the total cost. Then the equation is given as,

y = 15.7x

The linear equation that represents the total cost of the gas will be y = 15.7x.

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Answer:

£12000

Step-by-step explanation:

1 year = 1.5%

4 years = 6%

6% = 0.06

200000 times 0.06 = £12000

So, Katy will get £12000 interest rate at the end of 4 years.

If you can, please give me a Brainliest; thank you, and have a good day!

Answer:

£3,137

Step-by-step explanation:

First year: £200000 x 1.5% = £3,000

Second year: £203,000 x 1.5% = £3,045

Third year: £206,045 (because of 203,000+3,045) x 1.5% = £3,090.675

Last year: £209,135.675 x 1.5% = approximately £3,137

Answer:

a) [tex]\frac{5}{6}[/tex]

b) 18

Step-by-step explanation:

The unit rate is [tex]\frac{5}{18}[/tex].

This means that in 1 hour, you will travel [tex]\frac{5}{18}[/tex] of a mile.

distance = rate x time

d = [tex]\frac{5}{18}[/tex] x 3

d = [tex]\frac{5}{18}[/tex] [tex](\frac{3}{1})[/tex]

d = [tex]\frac{15}{18}[/tex]           Divide the numerator and denominator by 3 to simplify.

d = [tex]\frac{15}{18}[/tex] ÷ [tex]\frac{3}{3}[/tex] = [tex]\frac{5}{6}[/tex]

d = rate x time

5 = [tex]\frac{5}{18}[/tex]t  Multiply both sides by [tex]\frac{18}{5}[/tex]

[tex]\frac{18}{5}[/tex] [tex](\frac{5}{1})[/tex] = [tex]\frac{18}{5}[/tex][tex](\frac{18}{5})[/tex]t

18 = t

Answer:

there were 91,487.414 gallons of water in the tank before the leak.

Step-by-step explanation:

To find out the number of gallons of water that was in the tank before the leak, you can use the following equation:

Number of gallons before the leak = Number of gallons after the leak + Number of gallons leaked

Plugging in the values given in the problem, we get:

Number of gallons before the leak = 91,468 gallons + 19.414 gallons

Solving this equation gives us:

Number of gallons before the leak = 91,487.414 gallons

So there were 91,487.414 gallons of water in the tank before the leak.

The value of angle x that extends from the given polygon is 61°.

How to find the value of x?

The angle of straight line will be 180°

119° + x = 180°

x = 180° - 119°

x = 61°

Hence, the value of x that extends from the given polygon is 61°.

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Rounding to the nearest dollar, Ashley would need to invest $1,062 to reach $2,080 in 16 years at an interest rate of 5.6% compounded continuously.

Compound interest (CI) is calculated as CI = P(1 + r/100)n - P. To calculate the compound interest value, first compute the amount and then deduct the principal from it.

To find the amount Ashley needs to invest, we can use the formula for continuously compounded interest:

A = P * e^(rt)

where A is the final amount, P is the principal (the initial investment), r is the interest rate, and t is the time in years.

We know that A = $2,080 and r = 5.6% = 0.056, and we want to solve for P. We can rearrange the formula to solve for P:

P = A / e^(rt)

Plugging in the values, we get:

P = $2,080 / e^(0.056 * 16)

The value of e^(0.056 * 16) can be calculated using a calculator or computer, and it is approximately 1.96. Plugging this in, we get:

P = $2,080 / 1.96 = $1062.24

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Answer:

are you stupif? no dumas

Step-by-step explanation:

False, the zip codes of a sample of 345 customers at pet shop are not an example of qualitative variables

The zip codes of a sample of 345 customers at a pet shop are an example of quantitative variables because they are numerical values that can be measured and compared. Qualitative variables, on the other hand, are categorical variables that describe a characteristic or attribute of a person, place, or thing, such as gender, color, or nationality. They cannot be measured numerically and are often described using words or labels.

Qualitative Variables: Qualitative variables are variables that are not numerical or quantifiable. Examples of qualitative variables include gender, race, eye color, ethnicity, nationality, marital status, and religious preference.

Quantitative Variables: Quantitative variables are variables that are numerical or quantifiable. Examples of quantitative variables include height, weight, age, income, income level, GPA, number of children, and number of hours worked.

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