Six atoms of the peptide bond group are always planar due to the ____________. Dipole of amide linkage of a peptide bond is due to partially ___________charged carbonyl oxygen and partially ___________ charged amide nitrogen. Select one: a. phi and psi angles; negatively; positively b. trans position between amide hydrogen and carbonyl oxygen; positively; negatively c. resonance structure; negatively; positively d. resonance structure; positively; negatively e. trans position between amide hydrogen and carbonyl oxygen; negatively; positively

Answer:

phsical

Explanation:

it is a phisical cuz your only changing the shape not the chemical structure

Answer:16.38085

Explanation:Aline the decimals then start multiplying.

Answer:

If it is not proven and if it isn't backed up by any facts or has been proven to be false.

Answer:

Helium is the second element on the periodic table. It is located in period 1 and group 18 or 8A on the righthand side of the table. This group contains the noble gases, which are the most chemically inert elements on the periodic table. Each He atom has two protons and usually two neutrons and two electrons.

Explanation:

thoughtco.com

Answer:

period 1 and group 18 or 8A on the righthand side of the table.

Explanation:

Answer:

Q1: NO

Q2: NO

Explanation:

Step 1: Given data

Percentage by mass of nitrogen: 46.68%

Percentage by mass of oxygen: 53.32%

Step 2: Divide each percentage by the mass of the element

N: 46.68/14.01 = 3.332

O: 53.32/16.00 = 3.332

Step 3: Divide both numbers by the smallest one (in this case is the same)

N: 3.332/3.332 = 1

O: 3.332/3.332 = 1

The empirical formula is NO. Its molar mass is 30.01 g/mol.

Step 4: Calculate "n"

n = molar mass of the molecular formula / molar mass of the empirical formula

n = (30.01 g/mol) / (30.01 g/mol) = 1

Step 5: Determine the molecular formula

We do so by multiplying the empirical formula by "n".

NO × 1 = NO

Explanation:

loosing or gaining one or more electrons

Answer:

The answer is

Explanation:

To find the rate in cm/year we must first convert 200 m into cm

1 m = 100 cm

if 1 m = 100 cm

Then 200 m = 200 × 100 = 20 ,000 cm

So the rate is

Reduce the fraction with 10,000

We have the final answer as

Hope this helps you

Answer:

2 CM/year just now got 100 Edge.

Explanation:

Answer:

The value is [tex]P = 7.8 *10^{6} \ Pa [/tex]

Explanation:

From the question we are told that

The internal volume is [tex]V_i = 2.40 \ L = 2.40 *10^{-3} \ m^3[/tex]

The mass of the compound contained is [tex]m = 542 \ g[/tex]

The temperature is [tex]T = 21^o C = 21 + 273 = 294 \ K[/tex]

The critical temperature of silane is [tex]T_c = 269.7 \ K[/tex]

The critical pressure of silane is [tex]P_c = 48.4 bar = 48.4 *10^{5} \ Pa[/tex]

Generally the number of moles of silane inside the cylinder is mathematically represented as

[tex]n = \frac{m}{M}[/tex]

here M is the molar mass of silane with value [tex]M = 32 g/mol[/tex]

So

[tex]n = \frac{542}{32}[/tex]

=> [tex]n = 16.4 \ mol[/tex]

Generally the molar volume of silane in the cylinder is mathematically represented as

[tex]Vn = \frac{V_i}{n}[/tex]

=> [tex]Vn = \frac{2.40 *10^{-3}}{16.4}[/tex]

=> [tex]Vn = 1.42*10^{-4} \ m^3 / mol[/tex]

Generally from Soave-Redlich-Kwon we have that

[tex]P = \frac{RT}{V_n - b} - \frac{a}{V_n (V_n + b)}[/tex]

Here b is a constant which is mathematically represented as

[tex]b = 0.08664 * \frac{R T_c }{P_c}[/tex]

substituting [tex]8.314 J/mol\cdot K[/tex] for R we have \

[tex]b = 0.08664 * \frac {8.314* 269.7}{48.4*10^{5}}[/tex]

[tex]b = 4.0139 *10^{-5} m^3/mol[/tex]

a is also a constant which is mathematically represented as

[tex]a = 0.42748 * \frac{(R * T_c)^2}{P_c} * (1 + m [1-\sqrt{T_r} ])^2[/tex]

Here [tex]T_r[/tex] is the reduced temperature which is mathematically represented as

[tex]T_r = \frac{T}{T_c}[/tex]

=> [tex]T_r = 1.09[/tex]

m is a constant which is mathematically represented as

[tex]m = 0.480 + 1.574w - 0.176w^2[/tex]

=>           [tex]m  =  0.480 + 1.574 (0.094) - 0.176(0.094)^2[/tex]

=> [tex]m = 0.626[/tex]

So

[tex]a = 0.42748 * \frac{(8.314 * 269.7)^2}{48.4*10^{5}} * (1 + 0.626 [1-\sqrt{1.09} ])^2[/tex]

[tex]a = 0.4198[/tex]

From   [tex]P =  \frac{RT}{V_n - b} - \frac{a}{V_n (V_n + b)}[/tex] we have

[tex]P = \frac{8.314 * 294}{1.42*10^{-4} - 4.0139 *10^{-5} } - \frac{0.626}{1.42*10^{-4} (1.42*10^{-4} + 4.0139 *10^{-5} )}[/tex]

[tex]P = 7.8 *10^{6} \ Pa [/tex]

Answer:

Everything you can hold, taste, or smell is made of matter. Matter makes up everything you can see, including clothes, water, food, plants, and animals. It even makes up some things you cannot see, such as air or the smell of perfume.

Answer:

[tex][OH^-]=9.24x10^{-3}M[/tex].

[tex]pH=11.97[/tex].

Explanation:

Hello,

In this case, since the ionization of methylamine is:

[tex]CH_3NH_2(aq)+H_2O(l)\rightleftharpoons CH_3NH_3^+(aq)+OH^-(aq)[/tex]

The equilibrium expression is:

[tex]Kb=\frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}[/tex]

And in terms of the reaction extent [tex]x[/tex] which is equal to the concentration of  OH⁻ as well as that of CH₃NH₃⁺ via ice procedure we can write:

[tex]3.7x10^{-4}=\frac{x*x}{024-x}[/tex]

Whose solution for [tex]x[/tex] via quadratic equation is 9.24x10⁻³ M since the other solution is negative so it is avoided. Therefore, the concentration of OH⁻ is:

[tex][OH^-]=x=9.24x10^{-3}M[/tex]

With which we can compute the pOH at first:

[tex]pOH=-log([OH^-])=-log(9.24x10^{-3})=2.034[/tex]

Then, since pH and pOH are related via:

[tex]pH+pOH=14[/tex]

The pH turns out:

[tex]pH=14-pOH=14-2.034\\\\pH=11.97[/tex]

Best regards.

Answer:

Cu+HNO3

Explanation:

Answer:

Explanation:

A pipette is used to measure an exact volume of liquid; a pipette can only measure it's exact recommended volume (it can't measure more or less).

Hence, a 2-mL volumetric pipette can only measure 2 ml and would be recorded as 2.00 (ml). This is because simple volumes are usually recorded in two decimal places.

Answer:

it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma

Answer:

See attached picture.

Explanation:

Hello,

In this case, considering that Lewis structures are drawn in order to show up the bonding among equal or different atoms via their valence electrons, since hydrogen has one valence electron, silicon four and phosphorous five, the most suitable way to draw and attain the octet for both silicon and phosphorous is by bonding them via a double bond, one hydrogen bonded to the phosphorous and two hydrogen atoms bonded to the silicon as shown on the attached picture, wherein you can count eight electrons for both phosphorous and silicon.

Best regards.

Answer:

E

Explanation:

burning a substance changes it chemically.

Answer:

[tex]P=35.16[/tex]

[tex]Z=4.6[/tex]

Explanation:

Hello,

In this case, since the VdW equation is:

[tex]P=\frac{nRT}{V-n*b}-a(\frac{n}{V} )^2[/tex]

Since the moles are 10.0 moles, the temperature in K is 300.15 K and the volume is liters is also 4.860 L (1 dm³= 1L), the pressure exerted by the ethane is:

[tex]P=\frac{10.0mol*0.082\frac{atm*L}{mol*K}*300.15K}{4.860mol-10.0mol*0.0651\frac{L}{mol} }-5.507\frac{atm*L^2}{mol^2}(\frac{10.0mol}{4.86L} )^2\\\\P=58.48atm-23.3atm\\\\P=35.16[/tex]

Thus the compression factor turns out:

[tex]Z=\frac{PV}{RT}=\frac{23.3atm*4.86L}{ 0.082\frac{atm*L}{mol*K}*300.15K}\\\\Z=4.6[/tex]

Regards.

Answer:

[H⁺] = 0.000048936M

pH = 4.31

Explanation:

Acetic acid, CH₃COOH, dissociates in water as follows:

CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)

And Ka is defined as:

Ka = 1.76x10⁻⁵ =  [H⁺] [CH₃COO⁻] / [CH₃COOH]

Where [] are equilibrium concentrations of the species.

The 0.000185M of acetic acid will decreases X, and X of [H⁺] and [CH₃COO⁻] will be produced. That means Ka is:

1.76x10⁻⁵ =  [X] [X] / [0.000185 - X]

3.256x10⁻⁹ - 1.76x10⁻⁵X = X²

3.256x10⁻⁹ - 1.76x10⁻⁵X - X² = 0

Solving for X:

X = -0.000066M → False solution. There is no negative concentrations.

X = 0.000048936

As [H⁺] = X,

[H⁺] = 0.000048936M

And pH = -log [H⁺]

Answer:

The value is [tex]x = 0.151 \ e [/tex]

Explanation:

From the question we are told that

The bond length is [tex]l = 1.93\ \r a = 1.93 *1 *10^{-10} =1.93 *10^{-10}\ m [/tex]

The bond dipole moment is [tex] \mu = 1.40 d = 1.40 * 3.33564 *10^{-30} = 4.6699 *10^{-30} \ C \cdot m[/tex]

Generally the dipole moment is mathematically represented as

[tex]\mu = Q * l[/tex]

Here Q is the partial negative charge on the bromine atom

So

[tex]Q = \frac{\mu}{ l}[/tex]

=> [tex]Q = \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }[/tex]

=> [tex]Q = 2.42 *10^{-20} C [/tex]

Generally

1 electronic charge(e) is equivalent to [tex]1.60*10^{-19} C[/tex]

So x electronic charge(e) is equivalent to [tex]Q = 2.42 *10^{-20} C [/tex]

=> [tex]x = \frac{2.42 *10^{-20}}{1.60*10^{-19} }[/tex]

=>     [tex]x  =  0.151  \ e [/tex]

Answer:

It is B. Steel

Explanation:

Answer:

Defenitly B !!

( Steel )

Explanation:

Answer:

Filtration

Explanation:

Filtration is a separation technique used in the laboratories to separate two elements or compounds by using a filter paper and a beaker.

Drierite is also know as calcium sulphate and silicon is made up of silica.

The filtration equipment are taken to separate these two components. The separation method is used in the second beaker by pouring the mixture through a filtering funnel and using a filter paper. The solid remaining of silicon remains on the filter paper separating the two.

Answer:5.5

Explanation:

Answer:

9.8 joules

Explanation:

due to acceleration due to gravity

Answer:

Explanation:

The scientific method describes the processes by which scientists gain knowledge about the world. It's characterized by six key elements: questions, hypotheses, experiments, observations, analyses, and conclusions. These elements are interrelated steps, so they don't always function in the same order.

Answer:

Atoms of the same element are exactly alike in all respects and are different from atoms of other elements.

Explanation:

One of the postulates of the Dalton's atomic theory is that 'Atoms of the same element are exactly alike in all respects and are different from atoms of other elements.'

Hence, if carbon dioxide from two sources are obtained and analysed, the mass percentage of carbon in both samples should be exactly the same since they both contain atoms of carbon. The atoms of carbon in the both samples are exactly the same in all respects in accordance with the Dalton's atomic theory, hence the observation.

Answer:

Density is mass/volume d=m/v   so volume = m/d or mass divided by density.

That would be 23 / 0.7893 = 29.1397 or 29.14 mL.  Grams cancels out

Explanation:

The volume of ethanol is 20.27 g/ml.

The area occupied by a three-dimensional object is its volume. It can be determined using density and mass. Liters are used to measure it. The overall weight of a thing is its mass. M designates it.

The mass per unit volume is known as density. The capital letter D and the symbol rho stand for density. You can figure it out by dividing the mass by the volume.

rho = m / V

rho = density

m = mass

V = volume

Given the mass of the sample of ethanol weighs 16 g

The density of 0.7893 g/mL

Putting the values in the equation

Volume = 16 / 0.7893 = 20.27

Thus, the volume of ethanol is 20.27 g/ml.

To learn more about volume, refer to the link:

https://brainly.com/question/16940422

#SPJ2

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

The molar solubility should be 6.4 × 10^-10 M

Here

CaF2 will dissociate should be

CaF2 ⇌Ca2+ + 2F-

where,

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

Now

NaF will also dissociate like

NaF ⇌ Na+ + F-

Here

Na+ = 0.25M

F- = 0.25M

Now

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

Learn more about solution here: https://brainly.com/question/14619461