Solve by factoring 6x^2-x-13

In explicit representation, a sequence is represented in terms of the first term while in recursive representation, a sequence is represented in terms of the previous term.

What are Recursive Formulas?

A recursive formula refers to a formula that defines each term of a sequence using the preceding term(s). The recursive formulas define the following parameters:

What are Explicit Formulas?

Explicit formulas are always used to represent any term of the sequence, without writing the other terms of the sequence. The meaning of "explicit" is direct, something that can be directly found without knowing the other terms of sequence. The explicit formula helps to easily find any terms of the sequence, without knowing its previous term.  

Eg, the sequence: 2, 4, 6, 8, 10, . . .

Explicit Representation An = 2 + 2(n - 1)

Recursive representation f(n) = 2 + f(n - 1)

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The angle which is complementary to angle BAC is ∠ACB which is option (a) .

From the figure we can see that ΔABC is right angled triangle at B .

∠BAC and ∠ACB on adding gives the right angle ∠CBA .

Hence , on adding ∠ACB  to ∠BAC  , we get the sum 90° so , ∠ACB is the complementary to angle BAC .

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Step-by-step explanation:

If theres 168 frames in six seconds, to find out how many there are per second, we simply need to divide 168 by 6. This equals 28. If you know how many there are for 6, and you want to find out how many for 1, you know you're dividing 6 by 6. So you have to do the same to the amount of frames.

If sinx =0.6 and AB =12, then area of triangle ABC is equal to 96 units².

As given in the question,

In triangle ABC,

AB = Perpendicular side

BC = Base

AC = Hypotenuse

sinx = 0.6

AB = 12

sinx = AB / AC

⇒0.6 = 12/AC

⇒AC = 12 /0.6

⇒ AC = 20

Using Pythagoras theorem,

AB² + BC² = AC²

⇒ BC² = 20² -12²

⇒BC = 16

Area of ΔABC = (1/2)× AB×BC

                       = (1/2)×12×16

                       = 96 units²

Therefore, if sinx =0.6 and AB =12, then area of triangle ABC is equal to 96 units².

The complete question is:

If sin x = 0.6 and AB = 12 as shown in the diagram , what is the area of ΔABC ?

a. 96 units²

b. 28.8 units²

c. 31.2 units²

d. 34.6 units²

e. 42.3 units²

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Answer:

Step-by-step explanation:

e

The population of Texas will be 2.9 × 10³.

Population of Austin, Texas = 9.64 × 10.

The population of the state of Texas is 30 times that of Austin.

Therefore the population of Texas will be:

= 30 × 9.64 × 10

= 2900

= 2.9 × 10³

Therefore, the population of Texas will be 2.9 × 10³.

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Answer: A

Step-by-step explanation:

The explicit formula has the benefit of making it simple to locate any term in the sequence. The recursive formula only includes one addition or multiplication operation, hence this formula's drawback is that it has more operations overall.

We discovered that a recursive rule is a rule that repeatedly alters a prior number in order to reach a subsequent number. As an illustration, our formula for counting numbers is recursive since each number is equal to the preceding number plus 1.

A recursive function is one that generates a series of phrases by repeating or using its own prior term as input.

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Answer:

Step-by-step explanation:

add 2 to both sides,

10x-2=102
    +2   +2

now it is 10x=104

now divide 10 from both sides.

10x/10=104/10

x=10.4

Using the rule of exponents, the expression is 12x^4 × 35y^5

The rules of exponents are given as:

Given the expression;

3x^3 * 7y^2 * 4x * 5y ^3

collect the like bases

3x³ × 4x × 7y² × 5y³

Add the powers

12x^3 + 1 × 35^ 2 + 3

We then have;

12x^4 × 35y^5

Thus, using the rule of exponents, the expression is 12x^4 × 35y^5

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Basically you are correct its C , ut go with your gut!

The simplification of the given inequalities gives;

1) m > -1/80

2) x < -1/3

1) The multiplicative property of inequality states that both sides of an inequality can be multiplied or divided by the same number and an equivalent inequality can be formed.

Thus, applying that to 8m > -1/10, gives;

Multiply both sides by 1/8 to get;

8m * 1/8 > -1/10 * 1/8

m > -1/80

2) The division property of equality states that if both sides of an equation are divided by a common real number that is not equal to 0, the quotients remain equal.

Thus, applying that to -9/2x > 3/2 gives;

Divide both sides by -9/2 to get;

x < -1/3

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Answer: an integer rational number

Step-by-step explanation:it's not a natural or a whole number, but it as integer as well as it repeats

The answer is -0.5.

The source is from calculator soup.

The value of x is -14.

Rewriting the equation mentioned in question to solve for the value of x -

4(x + 2) -2 (x - 10) = 0

Performing multiplication with brackets on Left Hand Side of the equation

4x + 8 - 2x + 20 = 0

Performing addition and subtraction on Left Hand Side of the equation

2x + 28 = 0

Shifting 28 to other side of equation

2x = - 28

Shifting 2 to other side of equation as denominator

x = - 28/2

Performing division to find the value of x

x = -14

Hence, the value of x is -14.

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Answer:

3 and 2

Step-by-step explanation:

complementary means they add up to 90 degrees. Angle 3 and 2 equal 90 degrees,

The solution of the third degree polynomilal x³ - 4x² - 7x + 10 = 0 will be ( x - 5 )(x + 2 )( x - 1 ).

A polynomial in mathematics is an expression made up of coefficients and indeterminates and involves only the operations of multiplication, addition, subtraction, and non-negative integer exponentiation of variables.

Given equation is x³ - 4x² - 7x + 10 = 0. The equation will be solved as,

x³ - 4x² - 7x + 10 = 0

x³ - 3x² - 10x - x² + 3x + 10 = 0

( x² - 3x - 10) ( x - 1 ) = 0

( x² -5x + 2x - 10 ) ( x-  1) = 0

( x - 5 )( x + 2 )( x - 1 ) = 0

Therefore, the solution of the third degree polynomilal x³ - 4x² - 7x + 10 = 0 will be ( x - 5 )(x + 2 )( x - 1 ).

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The catcher at home plate had to throw the ball 60 cm to reach the 2nd baseman at second base.

The hypotenuse of a right triangle is formed by the line from home plate to 2nd base. The triangle's two sides are each 60 feet long.

We can calculate the length of the hypotenuse using the Pythagorean theorem:

Diagonal² = side² + side²

Side= 60 feet

Diagonal = √s² + s²

Put the value in formula;

(√s² + s²)² = 60² + 60²

2s² = 2 ×60²

Further simplify;

s² = 60²

Taking root on both sides;

s = 60 feet.

Thus, the side of the square field is 60 feet.

Therefore, a catcher at home plate ought to throw the ball 60 cm to reach the 2nd baseman at second base.

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Answer:

B. Vertical angles.

look at the image attached.

Answer:

f(g(x)) = 3x + 4

Step-by-step explanation:

to find f(g(x)) substitute x = g(x) into f(x)

f(g(x))

= f(x - 2)

= 3(x - 2) + 10

= 3x - 6 + 10

= 3x + 4

Answer:

[tex]f\left[g(x)\right]=3x + 4[/tex]

Step-by-step explanation:

Given functions:

[tex]\begin{cases}f(x)=3x+10\\g(x)=x-2\end{cases}[/tex]

Function composition is an operation that takes two functions and produces a third function.

The given composite function f[g(x)] means to substitute the function g(x) in place of the x in function f(x):

[tex]\begin{aligned}f\left[g(x)\right] & = f(x-2)\\& = 3(x-2)+10\\& = 3x-6+10\\& = 3x+4\end{aligned}[/tex]

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Value of s is 1.8.

The midpoint of a line is a point that bisects the line into equal parts. It is equidistant from both end points of the line.

As B is the midpoint of AC,

2AB = AC

∴ 2(10s + 2) = 40

∴ 20s + 4 = 40

∴ 20s = 36

∴ x = 1.8.

Now, AB = 10s + 2

Substituting the value of s,

∴ AB = 10(1.8) + 2

∴ AB = 20 units

Thus, the value of s is 1.8 and the length of AB is 20 units.

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Answer:

300 widgets

Step-by-step explanation:

Each time the widgets sold goes up by 100, the profits goes up by 400. This shows a ratio/slope of 4 if we were to graph this. To find out when they break even you need to subtract $400 from the first row to get to zero and the equivalent amount of widgets. If each widget is $4 then subtract 100 from 400 to get 300 widgets

well, we know the table has linear relationship, so let's use it to get the Profit function then, to get the equation of any straight line, we simply need two points off of it, so let's use those two points in the picture below.

[tex](\stackrel{x_1}{500}~,~\stackrel{y_1}{800})\qquad (\stackrel{x_2}{700}~,~\stackrel{y_2}{1600}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1600}-\stackrel{y1}{800}}}{\underset{run} {\underset{x_2}{700}-\underset{x_1}{500}}} \implies \cfrac{1600 -800}{700 -500} \implies \cfrac{ 800 }{ 200 }\implies 4[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{800}=\stackrel{m}{4}(x-\stackrel{x_1}{500}) \\\\\\ y-800=4x-2000\implies y=4x-1200[/tex]

how many bucks will they lose by selling "0" items?

well, let's find out by setting x = 0.

[tex]\stackrel{profit}{y}=4(0)-1200\implies y=-1200~\hfill \stackrel{\textit{they'd be losing}}{\text{\LARGE 1200}}[/tex]

how many will they need to sell to break-even?

well, to break-even that means no loses, no profits but no loses either, so-called breaking-even, you simply sell enough to cover costs, at that point the profit = y = 0, so

[tex]\stackrel{profit}{0}=4x-1200\implies 1200=4x\implies \cfrac{1200}{4}=x\implies \text{\LARGE 300}=x[/tex]

Answer: x=18

Step-by-step explanation:

2x+8x=180 ==> angles CDE(8x) and ABC(2x) are opposite supplementary angles meaning that they add up to 180 degrees.

10x=180

10x/10=180/10

x=180/10

x=18

Answer:

total of 50 employees

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

9 multiple choice questions and 2 short answer questions

===========================================================

Explanation:

x = number of multiple choice

y = number of short answers

The statement "It takes about 2 minutes to answer a multiple choice question and about 6 minutes to complete a short answer question" means it takes 2x+6y minutes to answer x multiple choice and y short answer questions. We want this total to be 30 minutes or less.

Therefore, [tex]2x+6y \le 30[/tex] is one constraint.

---------------

Another constraint is that [tex]0 \le x \le 9[/tex] since the most multiple choice questions you can answer is 9.

Because there are 3 short answer questions, this means another constraint is [tex]0 \le y \le 3[/tex]

---------------

The list of constraints is:

[tex]\begin{cases}2x+6y \le 30\\0 \le x \le 9\\0 \le y \le 3\\\end{cases}[/tex]

If you were to graph and shade these regions on the xy grid, then you should get a pentagon with the following corner points

A = (0, 0)

B = (0, 3)

C = (6, 3)

D = (9, 2)

E = (9, 0)

We'll plug the coordinates of each vertex into the objective function P(x,y) = 3x+5y which will compute the number of points total after answering x multiple choice and y short answer questions. This computes the maximum points possible.

Plug in the coordinates of point A to get P(0,0) = 0

Repeat for point B to get P(0,3) = 15

Now move onto point C to get P(6,3) = 33

Then point D is P(9,2) = 37 and point E gets us P(9,0) = 27

---------------

Summary:

P(0,0) = 0

P(0,3) = 15

P(6,3) = 33

P(9,2) = 37

P(9,0) = 27

We see that x = 9 and y = 2 produce the largest P(x,y) value of 37

Therefore, you should answer 9 multiple choice questions and 2 short answer questions. This will yield 37 points if you were to get all of those questions correct. In other words, the most points possible are 37 when given 30 minutes.

---------------

Side note:

If you had unlimited time, then the most points possible are 9*3+3*5 = 27+15 = 42 which is the total number of points on the exam.

Getting a 37 out of 42 is a grade of about 37/42 = 0.881 = 88.1%

The maximum score is achieved at the corner point (9, 0), where the student answers 9 multiple-choice questions and 0 short-answer questions. The score at this point is 27, which is the maximum score the student can achieve in the given time.

To maximize the student's score in the given 30 minutes, we need to create an objective function and constraints based on the time available and the number of questions.

Let:

x = Number of multiple-choice questions to answer

y = Number of short-answer questions to answer

Objective Function (Score):

The score can be calculated as the sum of points obtained from multiple-choice questions and short-answer questions:

Score (S) = 3x (for multiple-choice questions) + 5y (for short-answer questions)

Constraints:

1. Time Constraint: The total time taken to answer all the questions should not exceed 30 minutes:

Time for multiple-choice questions + Time for short-answer questions ≤ 30

2. Number of Questions Constraint: The student can't answer more questions than available:

Number of multiple-choice questions (x) ≤ 9 (total number of multiple-choice questions available)

Number of short-answer questions (y) ≤ 3 (total number of short-answer questions available)

Now, let's consider the time taken to answer each type of question:

- Time for multiple-choice questions: 2 minutes per question

- Time for short-answer questions: 6 minutes per question

Based on the above information, the time constraint can be written as an equation: 2x + 6y ≤ 30

Now, we need to maximize the score (S) by selecting the values of x and y that satisfy the above constraints. This is a linear programming problem that can be solved using various optimization techniques, such as the graphical method, simplex method, or linear programming software.

Since this is a simple problem with a small number of variables and constraints, we can use the graphical method to find the maximum score. We will graph the feasible region defined by the constraints and find the corner points of the feasible region. Then, we will calculate the score (S) at each corner point and select the one with the highest score.

The feasible region will be bounded by the lines:

2x + 6y ≤ 30 (Time constraint)

x ≤ 9 (Number of multiple-choice questions constraint)

y ≤ 3 (Number of short-answer questions constraint)

The corner points of the feasible region are the intersection points of these lines.

Now, calculate the score (S) at each corner point:

For (0, 0): S = 3(0) + 5(0) = 0

For (0, 3): S = 3(0) + 5(3) = 15

For (9, 0): S = 3(9) + 5(0) = 27

The maximum score is achieved at the corner point (9, 0), where the student answers 9 multiple-choice questions and 0 short-answer questions. The score at this point is 27, which is the maximum score the student can achieve in the given time.

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Answer: x<1 or x>5

Step-by-step explanation:

|-x+3|>2

-x+3>2

-x+3-3>2-3

-x>-1

x<1

-x+3<-2

-x+3-3<-2-3

-x<-5

x>5

x<1 or x>5

Answer:

The lines are the same, they are just in a different position.

A reflection is a type of rigid transformation. Rigid transformations do not

change the size nor the length of the pre-image.

In other words, the pre-image and the image in a rigid transformation are congruent.

Step-by-step explanation:

Hope this helps.  

Part (a)

We need to consider

[tex]x=\frac{1}{k\pi}, k \in \mathbb{Z}[/tex]

[tex]f\left(\frac{1}{k\pi} \right)=\tan (k\pi)

[/tex]

tan(x) has a period of pi, so this is equal to tan(0)=0.

Part (b)

We need to consider

[tex]x=\frac{4}{(4n+1)\pi}, n \in \mathbb{Z} \\ \\ f \left(\frac{4}{(4n+1)\pi} \right)=\tan \left(\frac{(4n+1)\pi}{4} \right) \\ \\ =\tan \left(\pi n+\frac{\pi}{4} \right) \\ \\ =1[/tex]

Part (c)

We see that 1/x approaches infinity, and hence the limit does not exist.

The chord of a circle is defined as the line segment connecting any two points on its circumference.

VU is not a radius it is a chord.

The chord of a circle is defined as the line segment connecting any two points on its circumference. It should be noted that the diameter of a circle is the longest chord passing through its center.

A circle chord is a straight line with both ends on a circular arc. A secant line, or simply secant, is the infinite line extension of a chord. A chord is a segment of a line that connects two points on a curve, such as an ellipse.

A radius is a segment with ends at the center and circumference of a circle. VU, on the other hand, is a chord because it has both endpoints on the circle.

Therefore, VU is not a radius it is a chord.

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