solve for x (3x-1)°, 71°​

Answer:

36.166

Step-by-step explanation:

Answer:

Percent increase

1. [tex]60[/tex] %

2. [tex]50[/tex] %

3. [tex]74.42[/tex] %

4. [tex]11.46[/tex] %

5. [tex]220[/tex] %

Step-by-step explanation:

1. $5 to $8

[tex]\frac{8-5}{5} * 100 = 60[/tex] %

2. From 20 students to 30 students

[tex]\frac{30-20}{20} * 100 = 50[/tex] %

3. From 86 books to 150 books

[tex]\frac{150-86}{86} * 100 = 74.42[/tex] %

4. From $3.49 to $ 3.89

[tex]\frac{3.89-3.49}{3.49} * 100 = 11.46[/tex] %

5. From 5 mile to 16 mile

[tex]\frac{16-5}{5} * 100 = 220[/tex] %

Answer:

0.39%

hope this helps

Answer:

15

15

15

15

15 Liaoning dude

Answer:

56

Step-by-step explanation:

F ∝ a

72 ∝ 9   write this using = :

72 = k9  find k

72/9 = 8

so: if a is 7

7 x 8 = 56

9. Answer:

30

10. Answer:

2

11. Answer:

4

12. Answer:

4

13. Answer:

-1

Tip:

Use photomath, its an app

Answer:

True

Step-by-step explanation:

Answer:

The answer is True

Step-by-step explanation:

Answer: median and 42!

Step-by-step explanation:

Answer:

h(3) = - 1

Step-by-step explanation:

To evaluate h(3), that is x = 3 in the interval x ≥ 1 , then

h(x) = - x + 2 , thus

h(3) = - 3 + 2 = - 1

Then h(3) = - 1

Answer:

once

Step-by-step explanation:

Answer:1.75

ep-by-step explanation:7 divided by 4=1.75

The prove for QA/QR = QB/QS is shown below.

Two triangles are said to be comparable if their two sides are in the same ratio as the two sides of another triangle and their two sides' angles inscribed in both triangles are equal.

If two triangles have an equal number of corresponding sides and an equal number of corresponding angles, then they are comparable.

1) Given

2) <Q is congruent to <Q

by reflexive property of congruence

3) <QBA is congruent to <QSR

by alternate interior angles theorem

4) Triangle QBA is similar to triangle QSR

by AA theorem

5) QA/QR=QB/QS

by CPSP (corresponding parts of similar polygons are proportional)

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Answer:

B.2

Step-by-step explanation:

Answer:

B. 2

Step-by-step explanation:

By thousandth with a "th" we are referring to decimal places. The 4 is in the tenths place, the 3 is in the hundredths place, and the 2 is in the thousandths place

Answer:

4,3

Step-by-step explanation:

i think im sure

Answer:

Multiplication (Option A)

Step-by-step explanation: Please brainliest if correct!

Step-by-step explanation:

==============================================================

Explanation:

The solution occurs where the two lines intersect. From this intersection point, draw a vertical line upward until you reach the x axis. We arrive somewhere between -5 and -6. A good estimate is to say that we're at the midpoint, so x = -5 & 1/2 is one possible estimate

Since only choice D has this x value, this must mean choice D is the answer. The y coordinate of y = -3 & 1/4 seems to fit as well since we can draw a horizontal line from the point of intersection to the y axis, and arrive somewhere just a little below -3.

Answer:

$8-$6+$8-$3=$7

hope this helps have a good day or night:)

The result of dividing 153.87 by 23 is approximately 6.6847826087.

Given that we need to determine that what is 153.87 divided by 23,

To justify this answer, we can perform the division calculation:

  6.6847826087

--------------

23 | 153.87

    138

    -----

     158

     138

     -----

      208

      207

      -----

        10

The division is performed by dividing 23 into 153.87. We start by dividing 23 into 153, which gives us 6 as the whole number part of the quotient. We then subtract 138 (6 multiplied by 23) from 153, which leaves us with a remainder of 15.

To obtain a decimal approximation, we bring down the decimal point from the dividend (153.87) and continue the division process.

We add a zero after the decimal point in the dividend and divide again. This time, 23 goes into 158 (the new dividend) 6 times, giving us a partial quotient of 0.6.

The remainder is 158 minus 138 (6 multiplied by 23), which equals 20.

We bring down another zero and continue dividing.

23 goes into 208 (the new dividend) 9 times, resulting in a partial quotient of 0.69. The remainder is 208 minus 207 (9 multiplied by 23), which equals 1.

At this point, we can either stop or continue dividing to obtain more decimal places.

Therefore, the result of dividing 153.87 by 23 is approximately 6.6847826087.

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Answer:

Angle F ~ Angle T. FG ~ ST. FE ~ TR.

Step-by-step explanation:

Answer:

<f=<t FG=TS FE=TR

Step-by-step explanation:

hope this helps

Answer:

27,4,5

Step-by-step explanation:

27³=3

4×5=20

27+4+5=36

Answer:

D

Step-by-step explanation:

D is the only one that makes sense

Answer:

Anything with a 4x for slope. It could be y=4x + any number.

Step-by-step explanation:

Answer:

$18,000

Step-by-step explanation:

Trust me it's right

Answer:

If you were solving the right triangle, it would be:

m∠A = 46°

m∠B = 44°

m∠C = 90°

AB = 32

BC ≈ 23

AC ≈ 24

Step-by-step explanation:

To solve this right triangle, you can use trigonometric ratios to solve for the sides. To find the angle measures:

m∠A = 46° (given)

m∠B = x

m∠C = 90° (given)

180 - (46 + 90) = x

180 - 136 = x

44 = x

m∠B = 44°

To find the side measures, you can use tangent, sine, cosine, and the Pythagorean Theorem.

Recall that:

tangent = opposite side/adjacent side

sine = opposite side/hypotenuse

cosine = adjacent side/hypotenuse

So:

sin46 = BC/32

BC = 32 (sin46)

BC ≈ 23

tan46 = BC/AC

AC = BC/tan46

AC = (23.01887361...) (tan46)

AC ≈ 24

Answer:

Step-by-step explanation:

See the drawing attached

The similarity theorem that proves the two given triangles are similar is: B. AA similarity theorem.

Recall:

The angle-angle similarity theorem (AA) states that if two angles in one triangle are of the same measure with two corresponding angles in another triangle, both triangles are similar to each other.

In the image given:

[tex]\angle F[/tex] in [tex]\triangle ETF[/tex] is congruent to [tex]\angle U[/tex] in [tex]\triangle VTU[/tex] ([tex]\angle F = \angle U = 78[/tex])

[tex]\angle ETF = \angle VTU[/tex] (vertical angles are equal)

This implies that two angles in [tex]\triangle ETF[/tex] are congruent to two corresponding angles in [tex]\triangle VTU[/tex].

Therefore, both triangles can be proven to be similar by the angle-angle similarity theorem (AA).

Learn more about angle-angle similarity theorem (AA) here:

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Answer:

0=−21/20

0Step-by-step explanation: