Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not.

[tex]\sqrt{4x-3}=5[/tex]

Let's see

[tex]\boxed{\sf log_aa=1}[/tex]

Now

[tex]\\ \rm\Rrightarrow log_{10}0.0001)[/tex]

[tex]\\ \rm\Rrightarrow log_{10}10^{-4}[/tex]

[tex]\\ \rm\Rrightarrow -4log_{10}10[/tex]

[tex]\\ \rm\Rrightarrow -4[/tex]

Answer:

This has already been answered correctly, but I'll add an additional perspective.  The log of (0.0001 to the base 10 is -4.

Step-by-step explanation:

log(base 10) says give us an exponent, x, that would be required to make [tex]10^{x}[/tex] equal to a specified number, in this case 0.0001.

[tex]10^{0}[/tex] = 1

[tex]10^{1}[/tex] = 10

[tex]10^{-1}[/tex] = 0.1

[tex]10^{-2}[/tex] = 0.01

[tex]10^{-4}[/tex] = 0.0001

The log of (0.0001) to the base 10 is -4.

Answer: $625

Step-by-step explanation:

Total beverage sales = $2,500

Beverage cost = 25%

So, $2,500 x 25% = $2,500 x 0.25 = $625

Answer:

Step-by-step explanation:

We got two shapes in the given figure,on the right we got a rectangle and on the left we have a square.

Area of rectangle:-

Area of square :-

Total area :-

Answer:

Step-by-step explanation:

you have two rectangles, the bigest has the base of 6cm and the height of 4cm, the area is 6 * 4 = 24cm ^ 2, the other rectangle has the base of 6 - 4 = 2 and the height of 5 - 4 = 1, 2*1=2.

we add the dimensions and we have the area of ​​the complete figure 24 + 2 =

26 cm ^ 2

The coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2). Then the correct option is D.

The complete options are given below.

1. (-11/2) -(11/2)

2.(-5/2)-(3/2)

3.(-5/2-(11/2)

4. (-11/2) -(-3/2)

Let C be the mid-point of the line segment AB.

A = (x₁, y₁)

B = (x₂, y₂)

C = (x, y)

Then the midpoint will be

x = (x₁ + x₂) / 2

y = (y₁ + y₂) / 2

The end points are given below.

(-3, -7) and (-8, 4)

We have

(x₁, y₁) = (-3, -7)

(x₂, y₂) = (-8, 4)

Then the mid-point will be

x = (- 3 - 8) / 2

x = -11 / 2

y = (-7 + 4) / 2

y = -3/2

Then the coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2).

Then the correct option is D.

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Answer:

x > 9

Step-by-step explanation:

for this inequality, we want to isolate x, so that we know the inequality of x

5x + 3 > 48

     - 3      -3        {subtract 3 from both sides to get x alone}

5x > 45

/5      /5                {divide both sides by 5 to find 1x}

x > 9

So , x > 9 is the inequality in terms of x {is the solution}

hope this helps! :)

Answer:

[tex]\huge\boxed{\sf x > 9}[/tex]

Step-by-step explanation:

5x + 3 > 48

Subtract 3 to both sides

5x > 48 - 3

5x > 45

Divide 5 to both sides

x > 9

[tex]\rule[225]{225}{2}[/tex]

The equation which relates the mass and length according to the task content is; l = (3/10)m.

From the task content, it follows that the proportional relationship is direct. Hence, the constant of proportionality k can be evaluated as follows;

l = k × m

Hence, k = l/m = 9/30 = 3/10.

Therefore, the proportional relationship is given by the equation; l = (3/10)m

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Answer:

The dog is 16 years old.

Step-by-step explanation:

X/4 + 6 = X/8 + 8

X/4-X/8 = 8-6

0.125X = 2

X = 2/0.125

X = 16

Answer:

16 years old

Step-by-step explanation

Dividing the dog’s age by 4 and adding 6

D÷4  + 6

dividing the dog’s age by 8 and adding 8

D÷8  + 8

equating both

D÷4  + 6 = D÷8 + 8

=> D÷4 - D÷8  = 2

multiplying by 8 both sides

=> 2D - D = 16

=> D = 16

hence, the dog is 16 years old

#1

Correct version

[tex]\\ \rm\Rrightarrow (x^3+2x^2-x)-(3x^3-3x^2+2x-4)[/tex]

[tex]\\ \rm\Rrightarrow x^3+2x^2-x-3x^3+3x^2-2x+4[/tex]

[tex]\\ \rm\Rrightarrow x^3+5x^2-3x+4[/tex]

#2

[tex]\\ \rm\Rrightarrow (x^2-3x+2)(x+1)[/tex]

[tex]\\ \rm\Rrightarrow x(x^2-3x+2)+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-3x^2+2x+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-2x^2-x+2[/tex]

Answer:

1. 4

2. 10

3. 14

Step-by-step explanation:

A = -6

B = 0

C = 4

D = 8

1. BC = |0 - 4| = 4

2. AC = |-6 - 4| = |-10| = 10

3. AD = |-6 - 8| = |-14| = 14

Answer:

1.  BC = 4

2.  AC = 10

3.  AD = 14

Step-by-step explanation:

Ruler Postulate

The distance between any two points on a number line is their difference.

Question 1

Given:

Therefore, using the Ruler Postulate:

⇒ BC = |b - c|

⇒ BC = |0 - 4|

⇒ BC = |-4|

⇒ BC = 4

Question 2

Given:

Therefore, using the Ruler Postulate:

⇒ AC = |a - c|

⇒ AC = |-6 - 4|

⇒ AC = |-10|

⇒ AC = 10

Question 3

Given:

Therefore, using the Ruler Postulate:

⇒ AD = |a - d|

⇒ AD = |-6 - 8|

⇒ AD = |-14|

⇒ AD = 14

The transformation is non-rigid because the side lengths are not preserved.

The drop-down menus and the image of the triangles are not given.

However, the question can still be solved using the available parameters.

The given parameters are:

Pre-image: 6, 10, 8

Image: 3, 5, 8

See that the side lengths of the image and the pre-image are not the same

This means that the transformation is a non-rigid transformation

Hence, the complete statement is the transformation is non-rigid because the side lengths are not preserved.

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The least to greatest slope, the segments are B, C and A.

Given that,

Segments A, B, and C on the graph below represent the water level of the tank every minute since it started filling.

A graph shows the water level needed to fill the tank on the y axis per unit of time on the x axis.

The segment's slope indicates how quickly the water level is rising. The slope, which is determined by the segment's angle with the positive x axis, is the ratio of rise to run.

slope of segment A = 60₋10/2 = 25

slope of segment B = 80₋60/4 = 5

slope of segment C = 110₋80/3 = 10

We can see that section B has the least slope, followed by segment C, and then segment A, which has the greatest slope.

B, C, and A are the segments in descending order of least to greatest slope.

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Answer:

[tex]7\sqrt{3}[/tex]

Step-by-step explanation:

This is a special triangle with the angles being 30-60-90. The adjacent side to the angle of 30 degrees has a length of x * sqrt(3). The opposite side has a length of x. Since the opposite side has a length of 7 here you simply plug that into x * sqrt(3) to find the length of the adjacent side of the angle 30 degrees which gives you 7 * sqrt(3)

Answer:

-5x=-23

Or

X=23/5

Step-by-step explanation:

Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

Helpful fact:  Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

Option 1.  m∠R > 90°

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

Option 2.  m∠S + m∠T < 90°

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) >  m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

Option 3.  m∠S = m∠T

Not necessarily.  While m∠S could equal m∠T, it doesn't have to.  

Example 1:  m∠S = m∠T = 10°;  By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2:  m∠S = 15°, and m∠T = 10°;  By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

Option 4.  m∠R > m∠T

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

Option 5.  m∠R > m∠S

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

Option 6.  m∠S > m∠T

Not necessarily.  While m∠S could be greater than m∠T, it doesn't have to be.  (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

Answer: Option 1, 2, 4, & 5  or  

A. m∠R > 90°;  B. m∠S + m∠T < 90°;  D. m∠R > m∠T;  & E. m∠R > m∠S

Step-by-step explanation:   Trust Me!  

If you are working on Edge the answer is correct. The proof is down below. I hope someone finds this helpful.

If you found any of my answers helpful please like and subscribe. I mean choose my answer as Brainliest. I would appreciate it!

Good luck everyone!  :)

Answer:

18, 36, 54

Step-by-step explanation:

Find the least common multiple of 6 and 9:

Multiples of 6: 6, 12, 18, ......

Multiples of 9: 9, 18, 27, ......

We see that 18 is the least common multiple of 6 and 9.

Additional multiples of 18 are 36 and 54.

If an integer is divisible by 6 and by 9 , then the integer must be divisible by 54.

Consider the statement as a contradiction.

The assertion exists that any natural number divisible by 6 and 9 exists also divisible by 54.

Let us consider divisible to mean that the outcome of the division of the number and 54 provides another natural number. We can take the prime factors of 6 and 9 which are {2,3} and {3,3}. We can consider that the product [tex]$2 \times 3 \times 3=18$[/tex] exists a number that exists divisible by 6 and 9 but exists not divisible by 54. Another instance exists the product of [tex]$2 \times 2 \times 3 \times 3=36$[/tex] which exists also not divisible by 54.

Therefore, the correct answer is option e) 54.

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Answer: No solution

Step-by-step explanation:

Both of these equations have the same number as to coefficient of x (-6) but have a different constant (-8 and 8). This means that there are no solutions to this system of equations.

Answer:

2/5

Step-by-step explanation:

22/11=2

55/11=5

Answer:

Option B is correct

Answer:

B there is enough raspberries to make 4 pie they can 6 pies if they 2 more of raspberries

Answer:

2 hours

Step-by-step explanation:

you can write two linear equations and then set them equal to each other to see when they intersect. so for the first equation which will be representing the junior space cadets distance from his house. this can be written as

d = 50t + 50

where t represents time and d represents distance. there is 50 being added to the equation since he had already been traveling for an hour

the second equation which will represent his sister Gwen can be represented as

d = 75t

Now we set them equal to each other

50t + 50 = 75t

50 = 25t

2 = t

Answer:

x=1

Step-by-step explanation:

8x-5(x-3) = 18

The first step is to distribute

8x -5x+15 = 18

Combine like terms

3x+15 = 18

Subtract 15 from each side

3x+15-15=18-15

3x=3

Divide by 3

3x/3 =3/3

x=1

Answer:

A

Step-by-step explanation:

Given:

[tex]8-3x > 2(3x-5)[/tex]

Simplify by distributing:

[tex]8-3x > 6x-10[/tex]

Add 10 to left side and add 3x to the right side:

[tex]18 > 9x[/tex]

The correct answer is option A which is the graph of f(x) is vertically compressed by a factor of 7 and shifted 16 units down.

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

Given functions are:-

When we plot the graph of the two functions given in the question we will see that the graph of the function F(x) = x²-16 is compressed by the factor 7 and the vertex of the graph shifted to the 16 points down.

Therefore the correct answer is option A which is the graph of f(x) is vertically compressed by a factor of 7 and shifted 16 units down.

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Answer:

5/18

Step-by-step explanation:

The LCD of 9, 3, and 6 is 18.

1 - 2/9 - 1/3 - 1/6 =

= 18/18 - 4/18 - 6/18 - 3/18

= 5/18

Answer: 5/18

Step-by-step explanation:

1/1 - 2/9 - 1/3 - 1/6

18 - 4 - 6 - 3/18

5/18

[tex]f(x) = {x}^{2} - 3x + 2 [/tex]

put x = (-1)

[tex] f( - 1) = {( - 1)}^{2} - 3 \times ( - 1) + 2 \\ \\ 1 + 3 + 2 \\ \\ 6.[/tex]

put x = (z)

[tex] f(z) = {z}^{2} - 3 \times z + 2 \\ \\ {z}^{2} - 3z + 2 \\ \\ {z}^{2} - 2z - z + 2 \\ \\ z(z - 2) - 1(z - 2) \\ \\ (z - 1)( z -2 ) \\ \\ (z - 1) = 0 \: \: , \: \: (z - 2) = 0\\ \\ z = 1 \:, \: 2[/tex]

put x = (x+1)

[tex]f(x + 1) = {x}^{2} - 3x + 2 \\ \\ {(x + 1)}^{2} - 3 (x + 1) + 2 \\ \\ {x}^{2} + 1 + 2x - 3x - 3 + 2 \\ \\ {x}^{2} - x \\ \\ x(x - 1) \\ \\ x(x - 1) = 0 \\ \\ x - 1 = \frac{0}{x} \\ \\ x - 1 = 0 \\ \\ x = 1.[/tex]

put x = (√2 + 1 )

[tex]f( \sqrt{2} + 1) = {x}^{2} - 3x + 2 \\ \\ {( \sqrt{2} + 1) }^{2} - 3( \sqrt{2} + 1) + 2 \\ \\ 2 + 1 + 2\sqrt{2} - 3 \sqrt{2} - 3 + 2 \\ \\ 3 - 1 \sqrt{2} - 1 \\ \\ 2 - \sqrt{2} \\ \\ 2 - 1.4 (optional \: \: \: steps)\\ \\ 0.6 \: \: [/tex]

The path straight to the end of the hike is 6 km farther than past the scenic lookout.

The map is not given, but the question can still be answered

From the question, the positions are given as::

Maria = (4, -4)

Scenic = (2, 3)

End = (-5, 5)

The distance between Maria and the end point is calculated using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]Route\ 1 = \sqrt{(4 + 5)^2 + (-4 -5)^2}[/tex]

[tex]Route\ 1 = 13[/tex]

The distance between Maria and the scenic lookout is calculated using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]Route\ 2 = \sqrt{(4 - 2)^2 + (-4 -3)^2}[/tex]

[tex]Route\ 2 = 7[/tex]

The distance between both routes is:

Distance = 13 - 7

Evaluate

Distance = 6

Hence, the path straight to the end of the hike is 6 km farther than past the scenic lookout.

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The  is probability P(B|A) expressed in simplest form is 1/2 (Option B) See computation below.

P (A) = [[tex][\mathrm{C}_{5}^{1} \mathrm{C}_{8}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 8)/(9 x 8)

P (A) = '5/9

P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 4)/(9 x 8)

= '5/18

P(B|A) = P (AB)/P(A)

= ('5/18)/('5/9)

P(B|A)  = 1/2

From the above we already have P (AB)

this is given as

P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]

= ('5 x 4)/(9 x 8)

P(AB) = '5/18

Note that:

Event A = drawing a white marble on the first draw

Event B = drawing a red marble on the second draw

P(A) = 8/13; while

P (B) = (5/12) because the first marble was not replaced, thus reducing th sample to 12.

Thus

P(A and B) = P(A)*P(B) = 8/13 * 5/12

P(A and B) =  10/39 (Option B)

Event A - Probability of Drawing a Green Marble is 8/20

Event B - Probability of Drawing a Blue Marble is 5/19

Thus P(B|A) = (8/20) * (5/19)

= [tex]\frac{8 * 5 }{20 * 19}[/tex]

= 40/380; divide numerator and denominator by 20

P(B|A) = 2/19 (Option A)

Event A = Probability of Drawing a red ball = 3/12

Event A = Probability of Drawing a pink ball without replacing the read in Event A = 3/11

Thus P (B and A) =

3/12 x 3/11

P (B and A) = 3/44 (Option A)

The conditions given are as follows:

The sum total of ways thus is

9 x 8

= 72 ways........X

Recall that

Event A is defined as selecting 8 as the first numeral

The only way to select this is one way

Event B is defined as choosing a number less than 6 as the second digit, that is 1, 2, 3, 4, 5

Thus, the possible number of ways to fill second digit = 5/8

Thus, the possible number of ways to form two digits 'AnB' =
('AnB') = 1 x 5 = 5 .................y

Hence Probability (AnB) = 5/72 (Option B)

Given that the non-zero digits are in a combination are not repeated and range from 3 through 8, thus the odd numbers between 3 and 8 are:

3, 5, 7

total numbers is 3, 4, 5, 6, 7, 8

Hence; Event A = choosing an odd number for the first digit = 3/6

Event B = choosing an odd number for the second digit (recall that the numbers are not repeated) = 2/5

= [tex]\frac{2*3}{3*6}[/tex]

= 6/30

= 1/5 (Option A)

If a combination is picked at random with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?

Event A = the first digit is an odd number

Event B = the second digit is an odd number

The numbers from 2 to 9 are:
2,3,4,5,6,7,8,9

The odd numbers between 2 and 9 are:

3,5,7,9

P (A) = 4/8

P (B) = 3/7

P(B|A) = (3/7)/(4/8)

P(B|A) = 3/7

Event A = drawing a white tile on the first draw

Event B = drawing a purple tile on the second draw

|n| = 15 * 14 = 210

| A| = 3*14 = 42

| AnB| = 3*7 = 21

P (A) = 42/210 = 6/30

P (AnB) = 21/210 = 1/10

P(B|A) = (1/10)/6/30)

P(B|A) = 1/10 * 30/6

P(B|A) = 30/60
P(B|A) = 1/2 (Option D)

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Answer:

B

Step-by-step explanation:

right on edg3