solve for x -
[tex]\bold{x {}^{2} + 5x + 6 = 0}[/tex]

ty! ~​

Answers

Answer 1

[tex] {x}^{2} + 5x + 6 = 0 \\ \\ {x}^{2} + 2x + 3x + 6 = 0 \\ \\ x(x + 2) + 3(x + 2) = 0 \\ \\ (x + 2)(x + 3) = 0 \\ \\ x + 2 = 0 \\ \\ x = - 2 \\ \\ x + 3 = 0 \\ \\ x = - 3.[/tex]

The value of x = -2 and -3 .

Answer 2

Answer:

hope it helps...

it has both co ordinate and factorization

Solve For X -[tex]\bold{x {}^{2} + 5x + 6 = 0}[/tex]ty! ~

Related Questions

Y-6.37x=-3 which of the following function notation corresponds to the equation below

Answers

Wheres the other part of the question

f(x)=1/x at x=1 find slope of tangent

Answers

Answer:

f'(1)=-1

Step-by-step explanation:

You can just find the derivative using the power rule for d/dx (x^-1)=-1x^-2=-1/x^2 then find f'(1)=-1.

I used the limit definition of the derivative to find the slope in the picture attached

Group of 5 people can do a piece of work in 6hrs- Calculate the time a group of 8 people working half the rate of first group could take​

Answers

The time taken by a group of 8 people working half the rate of the first group is 7.5 hours.

What is a fraction?

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:

A Group of 5 people can do a piece of work in 6hrs.

5 people, at a rate of 1, and the time taken is 6 hours

Work done is 30

8 people, at a rate of 1/2, and the time taken is x hours

8(1/2)x = 30

x = 60/8 = 7.5 hours

Thus, the time taken by a group of 8 people working half the rate of the first group is 7.5 hours.

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6 out of 11 players played well on the baseball team. What percent is it?

Answers

It would be 54.5% or 55%. If you divide 6/11 you get .545 so you move the decimal place 2 to the left and that’s how you get the percentage.

Answer: 54%

Step-by-step explanation:

You will need to divide these numbers.

[tex]6/11=0.54[/tex]

After you divide that, simplify that to a percentage by multiplying it by 100.

[tex]0.54 *100=54%[/tex]%

I hope this helps!!

Angles A and B are complementary. If sin A = 4x + 10 and cos B = 2x + 16, what is the value of x? (1 point) 3 4 13 22

Answers

Answer: 3

Step-by-step explanation:

The sine of an angle is equal to the cosine of its complement, so

[tex]4x+10=2x+16\\\\2x+10=16\\\\2x=6\\ \\ x=3[/tex]

I REQUIRE HELP IMMEDIATELY

Answers

All the equations have been solved

What is a Quadratic Equation ?

A quadratic equation is what can be represented by

ax² +bx+c = f(x)

It is given to solve the given quadratic equations

1.  x² = 25

x = ± 5

2. 16x² = 25

x² = 25/16

x = ± 5/4

3. (3x+2)²= 25

9x² +4+12x = 25

9x² +12x -21 = 0

3x(3x+7) -3(3x+7) = 0

x =1

x = -7/3

4. x² = 11x

x² -11x = 0

x (x-11) = 0

x = 0, 11

5. 3x²= 14x

3x² -14x = 0

x (3x - 14) = 0

x = 0 , 14/3

6. x²+2x = 3

x²+2x -3 = 0

x (x+3) -1(x+3) = 0

x = 1 ,-3

7.x²+2x -5 = 0

determined from the formula for the roots

x=−1±√6

x=1.44949

x=−3.44949

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North
A
72°
80m
115m
B
NOT TO
SCALE
The diagram shows the positions of three points A, B and C in a field.
(a)
Show that BC is 118.1 m, correct to 1 decimal place.

Answers

Using the cosine rule, BC = √(115² + 80² - 2(115)(80)(cos 72) ≈ 118.1 m (1 decimal place).

How to Use the Cosine Rule?

If we are given a triangle with two known sides and an included angle, the cosine rule that can be used to find the side opposite to the given angle is: a = √(b² + c² - 2bc(cos A)

We are given the following:

a = BCA = 72°b = 115 mc = 80 m

Plug in the values

BC = √(115² + 80² - 2(115)(80)(cos 72)

BC ≈ 118.1 m (1 decimal place)

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please help with this problem
thanks so much

Answers

Answer:

5/17

Step-by-step explanation:

If we do the multiplication first, we get:

[tex]\frac{4-(12\div-12)}{13+(-8\div-2)}[/tex]

If we do the division next, we get:

[tex]\frac{4+1}{13+4} = 5/17[/tex]

Question is attached………

Answers

Answer:

d. 11:15

Step-by-step explanation:

1) officer1: distance 75 miles, velocity 60mil/h; officer2: distance 25 miles, velocity 55mil/h;

2) time, which is spent officer1 is: 75/60=1.25[h]=75 [min]. If the officer1 leaves his office at 10:00, the arrival time is 11:15;

3) time which is spent officer2 is: 25/55=5/11[h]≈27[min]. The arrival time is 10:27.

4) finally, the both officers are in the required location at 11:15.

Triangle P Q R is shown. Angle P Q R is a right angle. The length of hypotenuse P R is q, the length of P Q is r, and the length of Q R is p.,
Which cosine ratios are correct for ΔPQR? Check all that apply.

cos (P) = StartFraction r Over q EndFraction
cos (P) = StartFraction p Over q EndFraction
cos (Q) = StartFraction r Over p EndFraction
cos (R) = StartFraction r Over p EndFraction
cos (R) = StartFraction p Over q EndFraction

Answers

The cosine ratios which are correct for the ΔPQR are CosineP = r/q and CosineR = p/q.

We have,

Δ PQR,

Length of hypotenuse PR = q

The length of PQ = r,

And the length of QR = p

NOw,

We know that Trigonometric ratios of CosineΘ;

CosineΘ = Base/Hypotenuse

So,

CosineP = r/q

And,

CosineR = p/q

So, from the above find out values we can say that these values are given in option (a) and option (d).

Therefore, the cosine ratios which are correct for the ΔPQR are CosP = r/q and CosR = p/q.

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Find m angle angle KML

Answers

Answer:

52

Step-by-step explanation:

this is a triangle whose 2 sides are equalfirst take 180 which is the sum of interior angle minus 76 which is the angle givenyou will get 104 which is the other 2 anglesdivide by 2 since they are equal to get 52

Please create an example using exponential growth and exponential decay

Answers

Answer:

f(x)=4^x exponential growth,  -6^x exponential decay Step-by-step explanation:

Which of these correctly explains the solution of the system of equations shown below?
2 x + 3 y = 6
x + 3 y = 12

Answers

using elimination method

2x + 3y = 6 -----(1)

-

x + 3y = 12-------(2)

———————

x = 12

substitute x as 12 into equation (1) or (2), let's choose equation (1)

2(12) + 3y = 6

24 + 3y = 6

collect like terms

3y = 6 - 24

3y = 18

divide both sides by 3 ( to make y the subject of formula )

3y = 18

— —

3 3

y = 6

therefore X = 12 and y = 6

Hope this helps eh

Good luck ✅.

Select the correct answer. Which number best represents the slope of the graphed line? A linear function on a coordinate plane passes through (minus 6, minus 7), and (4, minus 2) also intercepts the x-axis at 8 units and the y-axis at minus 4 units. A. B. C. D.

Answers

The number best represents the slope of the graphed line is 1/2.

We have given the two points,

(-6,-7) and (4,-2) and slope-intercept is 8 units

What is the slope-intercept form of a line?

[tex]y-y_{1}=m\left(x-x_{1}\right)[/tex]

y = y coordinate of the second point

[tex]y_1[/tex] = y coordinate of point one

m = slope

x = x coordinate of the second point

[tex]x_{1}[/tex]= x coordinate of point one

Therefore the

[tex]slope=\frac{y_2-y_1}{x_2-x_!}[/tex]

[tex]=\frac{-2-(-7)}{4-(-6)} \\=\frac{5}{10}\\ =\frac{1}{2}[/tex]

Therefore the correct option is 1/2.

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A woman passed gas silently. I said "it stinks", and she said "I apologize. Excuse me". Why did she say both of those things?

Answers

She says “I apologise” because she feels bad that she made a bad smell and she says “excuse me” because she wants you to accept her apology

According to the U.S. Census​ Bureau, the mean of the commute time to work for a resident of CA is 21.5 minutes. Assume that the standard deviation of the commute time is 4.8 minutes to complete parts​ (a) through​ (c).

Part 1
​(a) What minimum percentage of commuters in has a commute time within standard deviations of the​ mean?

enter your response here​% ​
(Round to one decimal place as​ needed.)

Answers

Using Chebyshev's Theorem, the minimum percentage of commuters in has a commute time within 2 standard deviations of the​ mean is of 75%.

What does Chebyshev’s Theorem state?

When we have no information about the population distribution, Chebyshev's Theorem is used. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.At least 89% of the measures are within 3 standard deviations of the mean.An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].

Hence, the minimum percentage of commuters in has a commute time within 2 standard deviations of the​ mean is of 75%.

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Please help me answer this question genius

Answers

(i) The Maclaurin's series is:

1 ₊ x ₊ x²/2! . 1 ₋ 3x⁴/4! ₊ ...........

(ii) Integral of limit o to 1∫ e^sinx is 0

Maclaurin's expansion is as follows:

y(x) = y₀ ₊ x y₁(0) ₊ x²/2! y₂(0) ₊ x³/3! y₃(0) ₊ ........

y = e^sinx

y(0) = e^sin0

y(0) = 1

Differentiate y with respect to x

y₁(x) = e^sinx . cos x

y₁(0) = 1 [i.e y₁ = cosx.y]

y₁(0) = 1

Differentiate y₁ with respect to x

y₂(x) = cosc . y₁ ₋ sinx . y

∴ y₂(0) = 1 ₋ 0 = 1

Differentiate y₂ with respect to x

y₃ = cosx . y₂ ₋ (2 sinx ₊ cosx)y₁

y₃(0) = 1 ₋(0 ₊ 1)1

y₃(0) = 0

Differentiate y₃ with respect to x

y₄ = cosx . y₃ sinx . y₃ ₋ (2sinx ₊ cosx)y₂ ₋ (2cos x ₋ sinx) y₁

y₄(0) = 0 ₋ (3 . 0 ₊ 1)1 ₋ (2 ₋ o) 1

y₄(0) = -3

∴ From maclaurin's equation we get:

e^sinx = 1 ₊ x . 1 ₊ x²/2! . 1 ₊ x³/3! (0) ₊ x⁴/4! (₋3) ₊ ....

           =1 ₊ x ₊ x²/2! . 1 ₋ 3x⁴/4! ₊ ...........

Hence we get the the series expansion as 1 ₊ x ₊ x²/2! . 1 ₋ 3x⁴/4! ₊ ...........

(ii) limit 0 to 1∫e^sinx

integration formula ∫e^x dx = e^x + c

                    limit 0 to 1 ∫e^sinx = [e^sinx + c ]limit 0 to 1

                                                 = e^sin0 ₋ e^sin1

                                                 = 1 ₋ 1

                                                 = 0

Hence we get the answer as 0

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Emily is shopping at the toy store. In that store all dolls are sold at the same price and all dresses are sold at the same price. If Emily buys one doll and one dress, it will cost her $21.00. If Emily buys two dolls and three dresses, it will cost her $51.00. What is the price of one doll at that store?​

Answers

Answer:

$12.

Step-by-step explanation:

1) if price of one doll is 'x', of one dress is 'y', then the condition 'buys one doll and one dress, it will cost her $21.00' can be written as x+y=21;

2) the condition 'buys two dolls and three dresses, it will cost her $51.00' can be written as 2x+3y=51;

3) it is possible to make up the system:

[tex]\left \{ {{x+y=21} \atop {2x+3y=51}} \right. \ = > \ \left \{ {{x=12} \atop {y=9}} \right.[/tex]

4) the price of one doll is 12$.

Help is needed with this math problem!

Answers

Answer:

expression for (g + h)([tex]x\\[/tex]) = [tex]2x[/tex] + [tex]3x^2\\[/tex] and for (g - h)([tex]x[/tex]) = [tex]2x[/tex] - [tex]3x^2[/tex]

value of (g .h)(2) = 24

Step-by-step explanation:

function operations: Functions with overlapping domains can be added, subtracted, multiplied and divided. If f(x) and g(x) are two functions, then for all x in the domain of both functions we can find the sum, difference, product and quotient

given :

g([tex]x[/tex]) = [tex]2x[/tex]

h([tex]x[/tex]) = [tex]3x^2[/tex]

we know that ;

(g + h)([tex]x[/tex]) = g([tex]x[/tex]) + h([tex]x[/tex])

              =  [tex]2x[/tex]  + [tex]3x^2[/tex]

similarly;

(g - h)([tex]x[/tex]) = g([tex]x[/tex]) - h([tex]x[/tex])

             =  [tex]2x[/tex] - [tex]3x^2[/tex]

now,  

(g . h)([tex]x[/tex]) = 2([tex]3x^2\\[/tex])

             = 6[tex]x^2\\[/tex]

for (g .h)(2) = 6([tex]2^2[/tex])

                  = 6 × 4

                  = 24

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PWhat are the x- and y-intercepts of the line y = 4x + 12?
A. x-intercept = 3; y-intercept = -12
B. x-intercept = -3; y-intercept = 12
C. x-intercept = -12; y-intercept = 3
D. x-intercept = 12; y-intercept = -3
PLEASE HELP

Answers

Answer:

B

Step-by-step explanation:

when x is 0 y=4(0)+12 y=12

y is 0 y=4(-3) +12 = 12=12

The following lots of Commodity Z were available for sale during the year. Beginning inventory 9 units at $50 First purchase 16 units at $50 Second purchase 21 units at $59 Third purchase 16 units at $62 The firm uses the periodic system, and there are 23 units of the commodity on hand at the end of the year. What is the ending inventory balance at the end of the year according to the FIFO method?

Answers

According to the FIFO method, the ending inventory balance for Commodity Z is $1,405

How much inventory is left under FIFO?

FIFO means that earlier inventory is sold first and later inventory would be the last goods left.

Since there were 23 units left, all 16 units from the last purchase and 7 units from the second purchase would be available:

= (16 x 62) + (7 x 59)

= 992 + 413

= $1,405

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Drag each tile to the correect location on the table. Not all tiles will be used. Maych each quadratic function with the attributes of its graph.

Answers

Answer:

I believe you forgot to add a picture

Question 5 of 10
Which function is shown in the graph?

Answers

Answer:

A

Step-by-step explanation:

By looking at the graph you can eliminate B as a choice since the denominator is 1+x which means it would have a vertical asymptote as x=-1 which doesn't correspond with the graph shown. You can also eliminate C since the function doesn't have a vertical asymptote as x=3 since the denominator of the function is 3-x meaning it would be undefined at x=3. It should be A since it appears to approaching 1 with a vertical asymptote at x=1 which corresponds with the denominator 1-x. If you plug in the value 0 as x you get 3 which is what is shown on the graph when x equals 0

Factor
4m^2+16m+16. ​

Answers

Answer:

4(m+2)²

Step-by-step explanation:

Hope this help!!

3. What are the roots of the polynomial y = x³ - 8?

Answers

Step-by-step explanation:

x^3 is a perfect cube, 8 is a perfect cube, so we use difference of cubes.

[tex] {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )[/tex]

Cube root of x^3 is x.

Cube root of 8 is 2

So

a=x

b= 2.

[tex](x - 2)( {x}^{2} - 2x + 4)[/tex]

Set these equations equal to zero

[tex]x - 2 = 0[/tex]

[tex]x = 2[/tex]

[tex] {x}^{2} - 2x + 4 = 0[/tex]

If we do the discriminant, we get a negative answer so we would have two imaginary solutions,

Thus the only real root is 2.

If you want imaginary solutions, apply the quadratic formula.

[tex]1 + i \sqrt{ 3 } [/tex]

and

[tex]1 - i \sqrt{3} [/tex]

Simplify cube root of 5 over fourth root of 5 . (5 points) 5 to the power of 1 over 4 5 to the power of 1 over 12 5 to the power of 7 over 12 5 to the power of 4 over 3

Answers

Answer:

[tex] {5}^{ \frac{1}{12} } = \sqrt[12]{5} [/tex]

Step-by-step explanation:

[tex] \frac{ \sqrt[3]{5} }{ \sqrt[4]{5} } = {5}^{ \frac{1}{3} } \div {5}^{ \frac{1}{4} } = {5}^{ \frac{4}{12} } \div {5}^{ \frac{3}{12} } = {5}^{ \frac{1}{12} } = \sqrt[12]{5} [/tex]

THIS IS THE ANSWER: 5 to the power of one-twelfth (Take a look at the image if this does not make sense) :))

:))

:)))   HAPPY SLAPPY!!!!

:))))

"UPDATE" : This was correct on my test. Also I realized to see the image in this answer keep your cursor on the side of your screen, not on the image :D

PLEASE HELP ASAP I WILL GIVE BRAINLYEST!!!

Answers

Answer:

Step-by-step explanation:

the numerator goes in side of the radical

9. The regular admission price at a museum is
$4.50 per adult and $2.75 per child. This week,
there is a special offer that allows 1 child to get
in for half price with each paying adult. How
much would the total admission price be for
3 children and 2 adults?

Answers

Answer:

$14.4

Step-by-step explanation:

there are 2 adults so 2 children will get the discount

4.50 + 4.50 + 1.375 + 1.375 + 2.75 = $14.5

Answer:

Step-by-step explanation:






What are the solution(s) to the quadratic equation 50 - x² = 0?
x = +2√5
x = ±6√3
x=+5√2
no real solution

Answers

No real solution is the answer

The solutions to the quadratic equation 50 - x² = 0 are x = ±5√2.

What is quadratic equation?

A quadratic equation is a second-order polynomial equation in a single variable x , ax2+bx+c=0. with a ≠ 0 .

The solution(s) to the quadratic equation 50 - x² = 0 can be found by setting the equation equal to zero and solving for x.

50 - x² = 0

To solve this equation, we can rearrange it as follows:

x² = 50

Taking the square root of both sides, we have:

x = ±√50

Simplifying the square root of 50, we get:

x = ±√(25 × 2)

x = ±√25 × √2

x = ±5√2

Therefore, the solutions to the quadratic equation 50 - x² = 0 are x = ±5√2.

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41. Which of the following pairs of groups
shows the greatest percent difference?
A. 12 and College
B. 9-11 and 12
C. 8 and 9-11
D. 6-7 and 8

42. If 33.1 million people are 14% of the
population, what is the total population?
A. 4.6 million
B. 42.3 million
C 236.4 million
D. 463.4 million

43. What percent of the population is at or
above the poverty level?
A. 86%
B. 66.9%
C. 33.1%
D. 14%

Answers

Answer:

C

C

B

8 abd 9-11

236.4 million

66.9%

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