solve for x
....................

On solving the provided question, we can say that   relation between tangential speed and angular speed, v = r * w; v: tangential speed; r: radius; w: angular speed

The length of a circle or sphere, in more contemporary use, is the same as its radius in classical geometry, which is one of the line segments from its center to its circumference. The Latin word radius, which also refers to the spokes of a wagon wheel, gave rise to the term. The distance a circle's center is from any point on its perimeter is its radius. Usually, "R" or "r" is used to indicate it. A radius is a line segment that has one endpoint in the center and one on the circumference of a circle. Circular diameter equals radius The diameter of a circle is the segment that traverses its center and has ends that are on the circle.

relation between tangential speed and angular speed

v = r * w

v: tangential speed

r: radius

w: angular speed

the radius is

r = d/2

d is the diameter

[tex]v = (d * w)/2\\w = 2*v/d\\w = (2*9 mile/h)/(58 feet)\\w = (2*9 mile/h)/(0.011 miles) = 1636 rad/h\\w = 1636/60 = 27.2 rad/min\\[/tex]

the angular speed is in radians,

[tex]n = v/(π*d)[/tex]

n = (9 mile/h)/(π*0.011 mile) = 260 rev/h

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Answer:

Step-by-step explanation: Yes, that is correct. The solution to the system of equations is (x, y) = (-7, 0) which is not in the given options, so none of them are the correct answer.

Answer:

both sides are equal to: [tex]8\sqrt{2}[/tex]

Step-by-step explanation:

Trigonometric functions are defined as the ratios between sides based on some angle. There's three main trig functions you want to remember which are defined as:

[tex]sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}}\\\\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}[/tex]

and then there are three other trig functions, which are simply the reciprocals:

[tex]csc(\theta)= \frac{\text{hypotenuse}}{\text{opposite}}=\frac{1}{sin(\theta)}\\\\sec(\theta) = \frac{\text{hypotenuse}}{\text{adjacent}}=\frac{1}{cos(\theta)}\\\\cot(\theta) = \frac{\text{adjacent}}{\text{opposite}}=\frac{1}{tan(\theta)}[/tex]

Now in our case we have the angle of 45 degrees and we have the hypotenuse with length 16, and we want to either solve for the opposite (x) or adjacent side (y)

Let's solve for the adjacent side, in which case we want a trig function defined using the hypotenuse and adjacent side, which is our cosine function.

[tex]cos(45)=\frac{y}{16}\implies cos(45)*16=y[/tex] and from here we can use a calculator or the unit circle which gives us an exact value. Using the unit circle, we can determine that: [tex]cos(45)=\frac{\sqrt{2}}{2}[/tex] and plugging that into our equation we get: [tex]y=\frac{\sqrt{2}}{2}*16=8\sqrt{2}[/tex] and we can use a calculator to approximate this: 11.313

Now we can also use the trig functions to find "x", which is the opposite side. In this case we want to use a trig function which is defined using the opposite and hypotenuse side, which is our sine function: [tex]sin(45)=\frac{x}{16}\implies sin(45)*16=x[/tex] and the cool thing about this, is that sin(45) and cos(45) are actually equal, so our "x" and "y' side are exactly equal: [tex]x=8\sqrt{2}[/tex]

We can verify this using the Pythagorean Theorem: [tex](8\sqrt{2})^2+(8\sqrt{2})^2=16^2\\\\(8^2*\sqrt{2}^2)+(8^2+\sqrt{2}^2)=256\\\\(64*2)+(64*2)=256\\\\128+128=256\\\\256=256[/tex]

The measurement closest to the area of the circle in meters is 379.94 sq. meters.

An object's area is how much space it takes up in two dimensions. It is the measurement of the quantity of unit squares that completely cover the surface of a closed figure. The square unit, which is frequently expressed as square inches, square feet, etc., is the accepted unit of area.

The word "area" refers to a free space. A shape's length and width are used to compute its area. The majority of forms and things have corners and edges. When computing the area of a certain form, both the length and width of these edges are taken into account.

Given that,

diameter = 22m

radius = 22/2 = 11m

The area of the circle is:

A = πr²

Substituting the value of π = 3.14 and r = 11 we have:

A = (3.14)(11)²

A = 379.94

Hence, the measurement closest to the area of the circle in meters is 379.94 sq. meters.

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Based on the information, it should be noted that the difference between the scores of the girls and boys aren't significant.

From the information, the average score for boys was 48.4 with standard deviation 12.96 and the girls had an average score

of 48.9 with standard deviation 11.85.

The computed upper limit = 2.1119

The computed lower limit = -3.1119

Since the interval (-3.1119, 2.1119) contains the between the value 0 thus the difference of boys and girls scores isn't significant.

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Answer:

96

Step-by-step explanation:

z-scores are defined as: [tex]z=\frac{x-\mu }{\sigma}[/tex], and this may look a bit confusing at first but by looking at the numerator and then denominator we can get a more understandable definition.

The numerator is first finding the difference between the statistic and the mean. It then divides by the standard deviation, so essentially it's telling us  how far the statistic is from the mean in terms of standard deviation.

We can actually rewrite the equation to express this:

[tex]z=\frac{x-\mu }{\sigma}\\\\z\sigma = x-\mu\\\mu + z\sigma=x[/tex]

So in essence, how many standard deviations the statistic is away from the mean.

Now this may seem very off topic compared to what the problem is asking, but we want to convert the top 5% to a z-score. Now let's first convert this top 5% to a percentile. To be in the top 5% you just need to be in the 95th percentile and using technology we can convert this into a z-score which is approximately 1.645.

So this means the 95th percentile is 1.645 standard deviations away and in this case above (since it's positive) from the mean.

The good thing is we know the standard deviation and mean, now let's just apply it: [tex]76+1.645(12)=95.74[/tex]. We now want to round this to the nearest integer of 96, and now we have our answer!

Answer: $169.15

Step-by-step explanation: 15 percent of 199 is 29.85, and 199-29.85 is 169.15

Using the system of equations, we found the number of adult tickets sold as 82 and the number of child tickets sold as 42.

What is the system of equations?

A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, often known as a system of equations or an equation system.

Given,

Number of tickets sold = 124

Cost of one adult ticket = $ 12.50

Cost of one child ticket = $ 6.50

Total money received = $ 1298

We can write a system of equations using the above information.

Number of adult tickets sold = x

Number of child tickets sold = y

x + y = 124

12.5x + 6.5y = 1298

Solving the above equations, we can find x and y.

Multiplying the first equation by 6.5

6.5x+ 6.5y = 806

12.5x + 6.5y = 1298

Subtracting the equations,

-6x = -492

x = 82

Substituting the above value in any one of the equation

82 + y = 124

y = 42

Therefore from the system of equations, the number of adult tickets sold is 82 and the number of child tickets sold is 42.

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The amount of investment at a rate of 2.75% and 4.75% will be $13,800 and $4,200m, respectively.

Simple interest is the concept that is used in many companies such as banking, finance, automobile, and so on.

The formula for interest is written as,

I = (PRT)/100

Where P is the principal, R is the rate of interest, and T is the time.

Let 'x' be the amount of investment at a rate of 4.75%. Then the amount of investment at a rate of 2.75% is ($18,000 - x). Then the equation is given as,

(18,000 - x) × 0.0275 + 0.0475x = 579

495 - 0.0275x + 0.0475x = 579

0.02x = 84

x = $4,200

Then the value of ($18,000 - x) is given as,

$18,000 - x = $18,000 - $4,200

$18,000 - x = $13,800

The amount of investment at a rate of 2.75% and 4.75% will be $13,800 and $4,200m, respectively.

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Answer:

Step-by-step explanation:

The surface area of a rectangular box can be calculated as follows:

Surface area = 2lw + 2lh + 2wh

Where l is the length, w is the width, and h is the height.

We are given the surface area (500 ft2) and the length and width (16 ft and 7 ft respectively), so we can use these values to solve for the height:

500 = 2 * 16 * 7 + 2 * 16 * h + 2 * 7 * h

500 = 224 + 32h + 14h

500 = 238h + 224

276 = 238h

h = 276 / 238

h = 1.16 ft

So the height of the box is approximately 1.16 feet.

The value of x for the given circle will be going to be 50°.

A circle is a geometrical figure which becomes by plotting a point around a fixed point by keeping a constant distance.

In our daily life, we always see circle objects for example our bike wheel.

Area of circle = πr² and the perimeter of circle = 2πr

where r is the radius of the circle.

Angles of Intersecting Chords Theorem

When two chords cross inside of a circle, the resulting angle's measure is equal to the product of the lengths of the arcs it intercepts and its vertical angle, divided by two.

So, angle x = (190° + 40°)/2  = 115°

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Selma needs to leave the money in the new account for at least one year, option A. 1 to recover the penalty paid.

Assuming Selma wants to recover the penalty paid using the extra interest earned in the new account, she needs to calculate the amount of time it will take for the new account's interest to make up for the penalty paid.

Let P be the initial amount of money in Selma's current account. The penalty for closing the account is 5% of P, which is 0.05P.

If Selma leaves the money in the current account for one year, she will earn simple interest of 5% of P, which is 0.05P. So at the end of the year, the balance in the current account will be P + 0.05P = 1.05P.

If Selma transfers the money to the new account, it will earn compound interest of 8% per year, compounded quarterly. The quarterly interest rate is 8%/4 = 2%.

After one quarter, the balance in the new account will be:

P*(1 + 2%/4) = P*1.02

After two quarters, the balance will be:

P1.02(1 + 2%/4) = P*1.02^2

After three quarters, the balance will be:

P1.02^2(1 + 2%/4) = P*1.02^3

After four quarters (i.e., one year), the balance will be:

P1.02^3(1 + 2%/4) = P*1.02^4

So at the end of one year, Selma will have 1.05P in the current account and P*1.02^4 in the new account.

To recover the penalty of 0.05P, Selma needs the balance in the new account to be at least 1.05P. That is,

P*1.02^4 >= 1.05P

Simplifying, we get:

1.02^4 >= 1.05

Taking the fourth root of both sides, we get:

1.02 >= 1.05^(1/4)

Using a calculator, we get:

1.02 >= 1.01298

So Selma needs to leave the money in the new account for at least one year to recover the penalty paid.

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Answer: The  range of f(x) is [tex]f(x)\geq -2[/tex]

Step-by-step explanation:

The given function is

[tex]f(x)+2=\frac{1}{6}|x-3|[/tex]

It can be written as

[tex]f(x)=\frac{1}{6}|x-3|-2[/tex]                ...(1)

The function is in the form of

[tex]g(x)=a|x-h|+k[/tex]               ...(2)

Where, a is scale factor and (h,k) is vertex of the graph.

On comparing (1) and (2), we get

[tex]a=\frac{1}{6}[/tex]

[tex]h=3[/tex]

[tex]k=-2[/tex]

The value of a is [tex]\frac{1}{6}[/tex] . So, the graph compressed vertically. The value of a is positive, therefore the graph of f(x) opens upward.

We know the absolute value is always greater than or equal to 0.

[tex]|x-3|\geq 0[/tex]

[tex]\frac{1}{6}|x-3|\geq \frac{1}{6}(0)[/tex]

[tex]\frac{1}{6}|x-3|\geq 0[/tex]

[tex]\frac{1}{6}|x-3|-2\geq 0-2[/tex]

[tex]f(x)\geq -2[/tex]

hope you've understood...

Answer:15n + 3 = 153

Step-by-step explanation:

15n + 3 = 153

product of 15 and a number n is 15n, and 3 more gets the plus 3, and it said all of this is 153

n=10 also as subtract 3 both sides then get 15n=150 get n by itself by dividing both sides by 15 and get n=10

By using the substitution method, the value of a is equal to 10 and the value of b is equal to -1.

In order to solve the given system of equations, we would apply the substitution method. From the information provided in the image attached above, we have the following system of equations:

2a + 7b = 13      .......equation 1.

8b = 2 - a          .......equation 2.

From equation 2, we have:

a = 2 - 8b         .......equation 3.

By using the substitution method to substitute equation 3 into equation 1, we have the following:

2(2 - 8b) + 7b = 13

4 - 16b + 7b = 13

4 - 9b = 13

9b = 4 - 13

9b = -9

b = -1

a = 2 - 8b

a = 2 - 8(-1)

a = 2 + 8

a = 10.

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Answer: The answers are both B and C

Answer: The sales tax is $2.5 and her total cost of the shirt is $47.5.

Step-by-step explanation:

Answer:

Step-by-step explanation:

I do not know bro. If I was a robot i'd know. I don't. I'm different.

Answer:

[tex]\dfrac{\text{d}y}{\text{d}x}=\cos(x)[/tex]

Step-by-step explanation:

Differentiating from First Principles is a technique to find an algebraic expression for the gradient at a particular point on the curve.

[tex]\boxed{\begin{minipage}{5.6 cm}\underline{Differentiating from First Principles}\\\\\\$\text{f}\:'(x)=\displaystyle \lim_{h \to 0} \left[\dfrac{\text{f}(x+h)-\text{f}(x)}{(x+h)-x}\right]$\\\\\end{minipage}}[/tex]

The point (x + h, f(x + h)) is a small distance along the curve from (x, f(x)).

As h gets smaller, the distance between the two points gets smaller.

The closer the points, the closer the line joining them will be to the tangent line.

To differentiate y = sin(x) using first principles, substitute f(x + h) = sin(x + h) and f(x) = sin(x) into the formula:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{\sin(x+h)-\sin(x)}{(x+h)-x}\right][/tex]

Use the sin addition formula to expand sin(x + h).

[tex]\boxed{\sin(A + B) = \sin A \cos B + \cos A \sin B}[/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{\sin(x)\cos(h)+\cos(x)\sin(h)-\sin(x)}{(x+h)-x}\right][/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{\sin(x)\cos(h)-\sin(x)+\cos(x)\sin(h)}{h}\right][/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{\sin(x)(\cos(h)-1)+\cos(x)\sin(h)}{h}\right][/tex]

Separate the sin(x) and cos(x) terms into two fractions:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{\sin(x)(\cos(h)-1)}{h}+\dfrac{\cos(x)\sin(h)}{h}\right][/tex]

When h gets really small, we can use the small angle approximation to rewrite cos(h).

[tex]\boxed{\cos (h) \approx 1-\dfrac{1}{2}h^2}[/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{\sin(x)\left(1-\dfrac{1}{2}h^2-1\right)}{h}+\dfrac{\cos(x)\cdot h}{h}\right][/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{\sin(x)\left(-\dfrac{1}{2}h^2\right)}{h}+\dfrac{\cos(x)\cdot h}{h}\right][/tex]

Cancel the common factor, h:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[-\dfrac{1}{2}h\sin(x)+\cos(x)\right][/tex]

As h → 0, the first term → 0:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\cos(x)[/tex]

No The triangles' are not congruent

The length of the corresponding sides should be equal and the length of sides is gotten using the equation:

The length of line in an ordered pair is calculated using the formula

d = √{(x₂ - x₁)² + (y₂ - y₁)²}

where

d = distance between the points

x₂ and x₁ = points in x coordinates

y₂ and y₁ = points in y coordinates

distance between points A(2, -8), B(-5, -2), C(-7, 3); and ΔDEF: D(-9, 7), E(-11, 12), F(-2, 1) are calculated as follows:

AB =√{(-2 + 5)² + (-8 + 2)²} = 6.71

DE = √{(-9 + 1)² + (7 - 12)²} = 9.43

BC = √{(-5 + 7)² + (-2 - 3)²} = 5.39

EF = √{(-11 + 2)² + (12 - 1)²} = 14.21

AC = √{(2 + 7)² + (-8 - 3)²} =  14.21

DF = √{(-9 + 2)² + (7 - 1)²} = 9.22

Examining the figures showing the side lengths shows that the two triangles are not congruent

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On solving the provided question we can say that the equation is p + 1.25p = 1225 => 2.25p = 1225 => p = 544.44

A formula is a formula that connects two statements and uses the equal sign (=) to indicate equality. A formula that proves the equality of two formulas is called an equation in algebra. For example, in the expression 3x + 5 = 14, the equal sign separates the variables 3x + 5 and 14. The relationship between the two sentences on either side of the letter is represented by a mathematical formula. In many cases, only one variable can also act as a symbol. For example, 2x – 4 = 2. 

the equation is

p + 1.25p = 1225

2.25p = 1225

p = 544.44

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The domain and the range of the ordered pairs in interval notations are as follows: 1) Domain = [0,4], Range = [1,5]   ; (2) Domain [-1,-4], Range =[0,-3]

The domain of a function is the collection of all conceivable values that may be used as inputs, or alternatively, it is the whole array of possible values for independent variables.

The range of a function is the set of every possible value for the dependent variable's outcomes, or the whole set of all possible values when the domain is substituted.

In a set of ordered pairs (x,y), the domain (input) refers to all the x-values and the range refers to all the y-values.

From the points on the graph given:

(0,1) (1,2) (2,3) (3,4) (4,5)

Domain: (0, 1, 2, 3, 4)

Range: (1, 2, 3, 4, 5)

(-1,0) (-2,-1) (-3,-2) (-4,-3)

Domain: ( -1, -2, -3, -4)

Range: (0, -1, -2, -3)

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A. There are 25^26 possible simple substitution ciphers.

(a) A simple substitution cipher is a substitution of one letter for another. In a simple substitution cipher, each letter in the alphabet can be mapped to one of the 25 other letters. Therefore, for each letter in the alphabet, there are 25 possible substitutions. The total number of possible simple substitution ciphers is the number of possible substitutions for each letter, raised to the power of the number of letters in the alphabet:

25^26 = 25 × 25 × 25 × ... × 25 (26 times)

So, there are 25^26 possible simple substitution ciphers.

(b) (i) If no letters are fixed, then each letter can be mapped to one of the 25 other letters. Therefore, the number of simple substitution ciphers that leave no letters fixed is:

25 × 24 × 23 × ... × 2 × 1 = 25!

(ii) If at least one letter is fixed, then for each letter in the alphabet, there are 24 possible substitutions. Therefore, the number of simple substitution ciphers that leave at least one letter fixed is:

25 × 24 × 23 × ... × 2 × 1 = 25!

(iii) If exactly one letter is fixed, then there are 26 possible letters that could be fixed. For each of these 26 possibilities, there are 24 possible substitutions for each of the remaining 25 letters. Therefore, the number of simple substitution ciphers that leave exactly one letter fixed is:

26 × 24^25 = 26 × 24 × 24 × ... × 24 (25 times) = 26 × 24!

(iv) If at least two letters are fixed, then the number of ways to choose the two fixed letters, multiplied by the number of ways to arrange the other 24 letters, gives the number of ciphers that have exactly two fixed letters. The number of ways to arrange 24 letters is 24!, and there are 26 choose 2 ways to choose two letters from 26:

26 choose 2 × 24! = 325 × 24!

However, this counts ciphers with exactly two fixed letters twice: once for each of the two fixed letters. So, to find the number of ciphers with at least two fixed letters, we need to subtract the number of ciphers with exactly two fixed letters and divide by 2:

(25! - 325 × 24!) / 2 = (25! - 325 × 24!) / 2.

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Answer:

f(-7) = 15

Step-by-step explanation:

Subsitute x = - 7 into f (X) = - 3 (x+2)

f(-7) = -3 x (-7+2)

calculate the sum or difference

f(-7) =-3 x (-5)

determine the sign for multiplication or division

f(-7)=3x5

calculate the product or quotient

f(-7)=15

final awnser f(-7)=15

The APY for the account would be 3.045%.

What is continuous compounding?

The formula for continuous compounding is given by:

A = P[tex]e^{(rt)}[/tex]

where:

A = final amount

P = principal amount

e = the mathematical constant e (approximately 2.71828)

r = annual interest rate

t = time in years

In this case, P = $1000, r = 0.03 (since APR is given), and t = 1 year.

Using the formula, we have:

A = 1000[tex]e^{(0.03*1)}[/tex]

A ≈ $1030.45

So the balance in the account after 1 year is approximately $1030.45.

To find the balance after 5 and 20 years, we simply need to plug in the corresponding values for t:

For t = 5:

A = 1000[tex]e^{(0.03*5)}[/tex]

A ≈ $1160.92

For t = 20:

A = 1000[tex]e^{(0.03*20)}[/tex]

A ≈ $1806.11

To find the APY, we use the formula:

APY = (1 + r/n)ⁿ- 1

where:

n = number of compounding periods per year

Since this is continuous compounding, we take the limit as n approaches infinity:

APY = eʳ - 1

APY = [tex]e^{0.03}[/tex] - 1

APY ≈ 0.03045 or 3.045%

Hence, the APY for the account would be 3.045%.

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The demonstration of magnitude of power given by 80 kg monkey by climbing a 15 meter tree in half a minute is equal to option b.  392 J/S.

Weight 'm' of the monkey is equal to 80kilogram

Height 'h' of the tree is equal to 15 meter

Time 't' taken by monkey to climb a tree = half a minute

                                                                    = 30 minutes

g = 9.8 m/s²

Magnitude of power = ( m × g × h )/ t

⇒ Magnitude of power = ( 80 × 9.8 × 15 )/ 30

⇒ Magnitude of power = 784 / 2

⇒ Magnitude of power = 392 J/S

Therefore, the magnitude of the power for the given weight , displacement and time is equal to option b. 392 J/S.

The above question is incomplete, the complete question is:

A 80 Kg monkey climbs a 15 meter tree in half a minute. What is the magnitude of power the monkey demonstrated?

a. 13.1 J/S

b. 392 J/S

c. 784 J/s

d. 11760 J/s​

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Answer:

(p o q) = 54

(q o p) = 68

Step-by-step explanation:

Another way to write is (p o q)(3) is p(q(3)).  As you can see, you start with the inner function and 3 is an input in the q(x) function.  Then, the output of this becomes the input of p(x) (the outer function), which yields a final output and the answer:

[tex]p(x) = 4x + 2\\q(x)=5x-2\\\\p(q(3))\\\\q(3)=5(3)-2=13\\p(13)=4(13)+2=54[/tex]

You do the same process for (q o p)(3), which can be written as q(p(3)), where you start with p(3) and then plug in this result as the input for q(x):

[tex]p(x)=4x+2\\q(x)=5x-2\\\\q(p(3))\\\\p(3)=4(3)+2=14\\q(14)=5(14)-2=68[/tex]

Answer:

10.5

Step-by-step explanation:

18/3 = 63/x

18 * x = 63

18 * 3.5 = 63

3 * 3.5 = 10.5

On solving the provided question we can say that the expressions are    

a)  1000

b  10

c) 100000.001

d) 99000

In mathematics, it is pοssible to multiply, divide, add, or remove. The construction of an expression is as follows: Expressiοn, number, and mathematical operatοr Numbers, variables, and functions are the building blocks of a mathematical expressiοn (such as addition, subtraction, multiplicatiοn or division etc.)

Expressiοns and phrases can be contrasted. Any mathematical statement with variables, numbers, and an arithmetic οperation between them is called an expression or an algebraic expressiοn. For instance, the expressiοn 4m + 5 has the terms 4m and 5 as well as the variable m of the supplied expressiοn, all of which are separated by the arithmetic sign +.

The expressiοns are

a)10¹⁵/10¹² = 10³ = 1000

b)10¹/10⁰ = 10/1 = 10

c)10⁵ + 10⁻³ = [tex]\dfrac{10^8 +1}{100}[/tex]= 100000.001

d)10⁵ - 10³ = 100000 - 1000 = 99000

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