Answer:
1 1/5 [tex]\geq[/tex] x OR one and on fifth is greater than or equal to x.
Step-by-step explanation:
2/5 [tex]\geq[/tex] x - 4/5
To isolate x, we need to add 4/5 to each side:
6/5 [tex]\geq[/tex] x is what we get
We can simplify it to:
1 1/5 [tex]\geq[/tex] x
Add 4/5 to both sides
X <= 6/5
X <= 1 1/5
Un cazador se encuentra en la parte mas alta de un arbol. Para averiguar a que altura se encuentra, deja caer una bola, observando que demora 4 segundos. Encuentra el alto del arbol (g=10m/s2)
Answer:
80 m
Step-by-step explanation:
La velocidad inicial de la pelota es 0 m/s.
La altura del árbol es s.
El tiempo necesario es de 4 segundos.
Podemos aplicar una de las ecuaciones de movimiento de Newton:
[tex]s = ut + \frac{1}{2}gt^2[/tex]
donde u = velocidad inicial
t = tiempo empleado
g = aceleración debido a la gravedad
Por lo tanto:
[tex]s = 0 * 4 + (1/2 * 10 * 4^2)\\\\s = 0 + 80 \\\\s = 80 m[/tex]
El árbol tiene 80 metros de altura.
Find the length of the third side to the nearest tenth.
5
1
Answer:
square root of 26 (sorry couldn't get the symbol)
Step-by-step explanation:
C^2 = A^2 + B^2 (Pythagoras Theorem)
C^2 = 5^2 + 1^2
C^2 = 26
take square root of both sides
C =
[tex] \sqrt{26} [/tex]
A beverage manufacturer performs a taste-test and discovers that people like their fizzy beverages best when the redius of the bubbles is about 0.7 mm. According to the formula below, what would be the volume of one of these bubbles?
Answer:
0.267[tex]mm^3[/tex]
Step-by-step explanation:
Radius of the Bubble = 0.7 mm
Volume of the bubble is given by the formula :
[tex]r=\sqrt[3]{\frac{3V}{4\pi } }[/tex]
Taking cube on both sides
[tex]V=\frac{4\pi\times r^3 }{3}\\\\ V=\frac{4\times3.14\times(0.7)^3}{3}\\\\V=\frac{12.56\times 0.064}{3}\\\\ V=\frac{0.804}{3}\\\\V=0.267mm^3[/tex]
A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 8.8 m/s at an angle of 23 SE from the window. It hits the ground 5s later. (A) how far horizontally from the building does the ball land on the ground? (B) find the height that the ball was thrown from
Answer:
a)40.5m
b)139.5m
Step-by-step explanation:
Considering downward as 'positive' y-direction
[tex]x_i=0\\y_i=0\\v_i=8.8m/s\\a_x=0\\a_y=g\\\theta = 23\degree\\t=5s[/tex]
First is to resolve initial velocity into x and y component:
[tex]v_x_i=v_icos\theta = 8.8 \times cos(23)= 8.1m/s\\v_y_i=v_isin\theta = 8.8 \times sin(23)= 3.4m/s\\[/tex]
a) in order to find horizontal position of the ball:
[tex]x_f=x_i+v_x_it+\frac{1}{2} a_xt^2[/tex]
[tex]x_f= 8.1\times5=40.5m[/tex]
b) To find the height that the ball was thrown from(vertical position):
[tex]y_f=y_i+v_y_it+\frac{1}{2} a_yt^2\\y_f=(3.4\times 5)+(\frac{1}{2} \times9.8\times5^2)\\y_f=139.5m[/tex]
what is the rule for the reflection?
Answer:
(x,y)→(x,−y)
Step-by-step explanation:
I did it before
find the 7th term of the geometric progression which begins:
2, -6, 18...
Answer:
a7=1458
Step-by-step explanation:
2; -6; 18... a geometric progression
a1=2; a2=-6; a3=18
r=a2/a1=-6/2
r= -3
a7=a1*r⁶
a7=2*(-3)⁶=2*729
a7=1458
Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to point A, the cheetah traveled at an average rate of 40 mph. Can we say that this cheetah’s average rate was 55 mph? The average rate for the trip is equal to the total distance traveled divided by the total time traveled. The following equations represent the distance traveled on each leg of the trip. First leg of trip: d=r_1 t_1 Second leg of trip: d=r_2 t_2 Write an equation for the average rate for the trip. Remember, the cheetah runs from point A to point B and back to point A.
Answer:
No.
[tex]\text{Average rate} = \dfrac{\text{Total distance}}{\text{Total time}} = \dfrac{r_{1}t_{1} + r_{2}t_{2}}{t_{1} + t_{2}}\\\\= \text{50.91 mi/h}[/tex]
Step-by-step explanation:
First leg: d = r₁t₁
Second leg: d = r₂t₂
r₁t₁ = r₂t₂
Total distance: 2d = r₁t₁ + r₂t₂
Total time: t = t₁ + t₂
1. Equation for average rate
[tex]\text{Average rate} = \dfrac{\text{Total distance}}{\text{Total time}} = \dfrac{r_{1}t_{1} + r_{2}t_{2}}{t_{1} + t_{2}}[/tex]
2. Average rate
Since r₁t₁ = r₂t₂,
[tex]t_{1} = \dfrac{r_{2}t_{2}}{r_{1}} = \frac{40}{70}t_{2} = \frac{4}{7}t_{2}\\\\\text{Average rate} = \dfrac{2r_{2}t_{2}}{\frac{4}{7}t_{2} + t_{2}} = \dfrac{2 \times 40t_{2}}{\frac{4t_{2}+ 7t_{2}}{7}}= 80t_{2} \times\frac{7}{11t_{2}} = \dfrac{560}{11}\\\\= \textbf{50.91 mi/h}[/tex]
We cannot say truthfully that the average rate is 55 mi/h.
The average rate of a body is the total distance travelled divided by the total time.
The cheetah runs at an average rate of 50.91mph, not 55mph
Let
[tex]d \to[/tex] distance
[tex]r \to[/tex] average rate
[tex]t \to[/tex] time
Given that:
[tex]d = r_1t_1 = r_2t_2[/tex]
So, we have:
[tex]r_1 = 70[/tex]
[tex]r_2 = 40[/tex]
The average rate (r) is calculated as follows:
[tex]r = \frac{Total\ Distance (D)}{Total\ Time (T)}[/tex]
Where:
[tex]D=d + d[/tex]
[tex]D = r_1t_1 + r_2t_2[/tex]
and
[tex]T =t_1 + t_2[/tex]
So, the average rate is:
[tex]r =\frac{r_1t_1 + r_2t_2}{t_1 + t_2}[/tex]
Recall that:
[tex]D = r_1t_1 + r_2t_2[/tex]
[tex]r_1t_1 = r_2t_2[/tex]
Make [tex]t_2[/tex] the subject
[tex]t_2 = \frac{r_1t_1}{r_2}[/tex]
Substitute values for [tex]r_1[/tex] and [tex]r_2[/tex]
[tex]t_2 = \frac{70t_1}{40}[/tex]
So, we have:
[tex]r =\frac{r_1t_1 + r_2t_2}{t_1 + t_2}[/tex]
[tex]r = \frac{70t_1 + 40 \times \frac{70t_1}{40}}{t_1 + \frac{70t_1}{40}}[/tex]
[tex]r = \frac{70t_1 + 70t_1}{t_1 + \frac{70t_1}{40}}[/tex]
[tex]r = \frac{140t_1}{t_1 + \frac{70t_1}{40}}[/tex]
Factor out t1
[tex]r= \frac{140t_1}{t_1(1 + \frac{70}{40})}[/tex]
[tex]r = \frac{140}{(1 + \frac{70}{40})}[/tex]
[tex]r = \frac{140}{\frac{40+70}{40}}[/tex]
[tex]r= \frac{140}{\frac{110}{40}}[/tex]
Rewrite as:
[tex]r = \frac{140 \times 40}{110}[/tex]
[tex]r = 50.91mph[/tex]
Hence, the cheetah's average rate is 50.91mph, not 55mph
Read more about distance, average rates and time at:
https://brainly.com/question/22457482
Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!
Answer:
$12 million
Step-by-step explanation:
Vertex form of a quadratic equation:
y=a(x-h)^2+k
where (h,k) is the vertex.
The vertex is (5,12), and it is a maximum since a is negative.
Therefore, the maximum value is $12 million.
Guess my rule. PLS HELP ME I BEG
Answer:
12,22,2002, 4x, 5x
Step-by-step explanation:
The rule is x2 +2
Not sure on the last 4
Sorry I answered late.
if f(x)=1/2x-2 what is f(14)
Answer:
Hi there!
The correct answer is: 5
Step-by-step explanation:
Essentially they replace x with 14, so all you have to do is plug 14 into the equation. 14 multiplied by 1/2 is 7, because it's the same thing as 14 divided by 2. Then you minus 2 from 7, and you get 5.
What is $ 1.20 x 5 =? My brain is not working! LOL!
Answer:
6.25
Step-by-step explanation:
=1.20*5
=6.25
Answer:
6
Step-by-step explanation:
1.20 x 5 = 6
6/5 = 1.20
Using the slope and the yintercept, graph the line represented by the following equation. Then select the correct graph. 2y+4=0
Pleas help !!!
Choices
X= -1
Y = -1
X = 1
Y= 1
Answer:
x=-1
Step-by-step explanation:
The axis of symmetry is along the vertex
The vertex is at (-1,-2)
The x coordinate is -1
x=-1
Help please picture attached !!! Factoring expression
Answer:
(x+y)^3
Step-by-step explanation:
125 is the third power of five and 216 is the third power of 6
so we can rewrite the expression as (x+y)^3
One number is 9 more than another number. The sum of the numbers is 25. What is one of the numbers?
Answer:
16? maybe
Step-by-step explanation:
i justed counted from 9 to 25,l
Answer:
8 or 17
Step-by-step explanation:
The system of equations for this is:
x = 9 + y
x + y = 25
Find the value of y by plugging the first equation into the second.
9 + y + y = 25
9 + 2y = 25
2y = 16
y = 8
One of the numbers is 8.
OR
Find the value of x by plugging the value of y into one o the equations.
x = 9 + 8
x = 17
or
x + 8 = 25
x = 17
One of the numbers is 17.
Only need answer A answered please
HEY MATE HERE IS UR ANSWER
The graph of the function is the set of all points (x,y) in the plane that satisfies the equation y=f(x) y = f ( x ) . ... A vertical line includes all points with a particular x value. The y value of a point where a vertical line intersects a graph represents an output for that input x value.
FOLLOW ME AND MARK AS BRAINLIEST AND CHAT INBOX
attachment need help asap
Answer:
c because the x value is equal to the y value
Step-by-step explanation:
Answer:
x=y
Step-by-step explanation:
They are both opposite each other.
Parallel to each other
Simplify the following expressions by using distributive property. 3x^2(4x-3)
Answer:
12x^3-9x^2
Step-by-step explanation:
[tex]3x^2(4x-3)= \\\\3x^2(4x)+3x^2(-3)= \\\\12x^3-9x^2[/tex]
Hope this helps!
Which value of f 3f+5=32 a true statement
Choose 1 answer
A
f=6
B
f=8
C
f=9
D
f=12
Answer:
C. f = 9
Step-by-step explanation:
→Subtract 5 from both sides:
3f + 5 = 32
- 5 - 5
_________
3f = 27
→Divide both sides by 3:
f = 9
Answer:
C f=9
Step-by-step explanation:
Trust me, I got the answer right.
please I really need help
Answer:
-8
Step-by-step explanation:
m∠3 + m∠5 = 180 (interior angles are supplementary)
-4x + 5 + (-13x + 39) = 180
-4x + 5 -13x +39 = 180
-17x = 180 - 5 - 39
-17x = 136
x = 136/(-17) = -8
18 POINTS! At the AoPS office, mice vary inversely with cats, that is, mice=k/cats, for some value of k. When there are 3r-19 cats, there are 2r+1 mice, and when there are 6r-27 mice, there are r-5 cats. Find k. Please help, and do not answer with an "I don't know" or "Sorry, this is too hard." Thank you all!
Answer:
k=30
Step-by-step explanation:
The number of mice vary inversely with cats. This is written as:
[tex]Mice \propto \dfrac{1}{Cat} \\Mice = \dfrac{k}{Cat}[/tex]
When there are 3r-19 cats, there are 2r+1 mice
[tex]2r+1 = \dfrac{k}{3r-19}\\$Cross multiply$\\k=(3r-19)(2r+1)[/tex]
When there are 6r-27 mice, there are r-5 cats.
[tex]6r-27 = \dfrac{k}{r-5}\\$Cross multiply$\\k=(6r-27)(r-5)[/tex]
Taking the values of k above, we have:
[tex]k=(3r-19)(2r+1) =(6r-27)(r-5)\\(3r-19)(2r+1) =(6r-27)(r-5)\\6r^2+3r-38r-19=6r^2-30r-27r+135\\$Collect like terms\\6r^2-6r^2+3r+30r-38r+27r-19-135=0\\22r-154=0\\22r=154\\$Divide both sides by 22\\r=7[/tex]
Therefore:
[tex]k=(3r-19)(2r+1) \\=(3*7-19)(2*7+1)\\=(21-19)(14+1)\\=2*15\\k=30[/tex]
Which equation represents the line that passes through (-8.11) and
(4,7/2)?
Answer:
[tex]y=-5/8x+6[/tex]
Step-by-step explanation:
[tex]m=\frac{7/2 - 11}{4--8}[/tex]
[tex]m=\frac{-15/2}{12}[/tex]
[tex]m=-5/8[/tex]
[tex]y=-5/8x+b[/tex]
[tex](-8,11)[/tex]
[tex]11=-5/8 \times -8+b[/tex]
[tex]b=11-(-5/8)(-8)[/tex]
[tex]b=6[/tex]
Help please !!!!!!!!!!!!!!!!!!!!!!!
Answer:
∠J and ∠K form a linear pair.
Step-by-step explanation:
If angles J and K are supplementary and adjacent, then they form what is known as a linear pair.
"Definition: Two angles that are adjacent (share a leg) and supplementary (add up to 180°)" -mathopenref
El que responda bien 5 estrellas y un gracias 7u7
Answer: AB=12
Los triangulos BCD y ADE son iguales por tener dos lados y el angulo comprendido respectivamente iguales. por tanto AE=DC=4
Luego AB = AE+EB = 4+8 = 12
What are the ordered pairs of the
solutions for this system of equations?
f(x) = x2 – 2x + 3; f(x) = -2x + 7
Hey there! :)
Answer:
(2, 3) and (-2, 11).
Step-by-step explanation:
To solve this system of equations, we can set both equations equal to each other:
x² -2x + 3 = -2x + 7
Combine like terms:
x² -4 = 0
Factor using difference of squares:
(x - 2)(x + 2) = 0
Therefore, x = 2 and -2. Plug both of these into an equation to solve for the 'y' value:
f(x) = -2(2) + 7
f(x) = -4 + 7
f(x) = 3
------------------
f(x) = -2(-2) + 7
f(x) = 4 + 7
f(x) = 11
Therefore, the two ordered pairs are (2, 3) and (-2, 11).
Prove that (2n+1)^2 - (2n+1)^2 is a multiple of 8 for all positive integer values of n
Answer:
(2n + 1)[(2n + 1) � 1]
(2n + 1)(2n + 1 � 1)
(2n + 1)(2n), or 2n(2n + 1)
2n is an EVEN NUMBER, and adding 1 to an even number creates an ODD number
Therefore, 2n(2n+1)=EVEN NUMBER ODD NUMBER=EVEN NUMBER
Step-by-step explanation:
IF (-6, 4) is the endpoint of a line segment, and (-2, -1) is its midpoint, find the other endpoint.
A) (2,-6)
B) (-14, 14)
9 (-16, 12)
D) (2,9)
A midpoint has coordinates of [tex](-2, -1)[/tex] we will call them [tex](x_m, y_m)[/tex].
The coordinates of a midpoint are constructed from coordinates of enpoints [tex](x_1,y_1),(x_2,y_2)[/tex], namely as a divided sum.
[tex]
x_m=\frac{x_1+x_2}{2}\implies x_1=2x_m-x_2 \\
y_m=\frac{y_1+y_2}{2}\implies y_1=2y_m-y_2
[/tex]
Now insert the numbers.
[tex]
x_1=2(-2)-(-6)=2 \\
y_1=2(-1)-4=-6
[/tex]
The result is an endpoint at [tex](2,-6)[/tex].
Rahul was given 32 problems for home work. He has worked out . $ of them on Monday and . % of them on Tuesday . Find the number of problems left unsolved.
Answer: **Incomplete question**
Step-by-step explanation: Your question is incomplete, and missing very important details. However I would attempt to use assumed values in place of the omitted ones so that after explaining, it would be pretty much easy to figure out the solution.
If Rahul was given a total of 32 questions and he has worked out for example 25% of them on Monday and then 50% of them on Tuesday, to find the number of problems left, we would need to find the number of questions represented by the percentage indicated.
If he has worked out 25% of them on Monday, then that means he had done the following
Percentage done = 25% (or 25/100 which equals 0.25)
Number of problems solved = 32 * 25%
Number of problems solved = 32 * 0.25
Number of problems solved = 8
Further he solved 50% of them on Tuesday
Percentage done = 50% (or 50/100 which equals 0.50)
Number of problems solved = 32 * 50%
Number of problems solved = 32 * 0.5
Number of problems solved = 16
This means he has now solved a total of
8 + 16 = 24
If therefore he has solved 24 problems, then the number of problems left is derived simply as
Unsolved problems = 32 - 24
Unsolved problems = 8
Please remember that the use of 25% and 50% are simply assumptions in order to make explaining the solution easier. Please insert the correct values of the percentage as appropriate.
2y/5y cube + 4y square + 6y
Answer:
here down is the answer
(2y/5y)^3+4y^2+6y
8y^3/125y^3 +16y^2+6y
8/125+16y^2+6y
8/125+16y^2+6y=0
16y^2+6y+8/125=0
it is in the form of quadratic equation
formula :
x=(-b+-square root of b^2-4ac) /2a
here a=16,b=6&c=8/125
x=(-b+-square root of b^2-4ac)/2a
x=(-6+-square root of 36-4.09)/2a here 4.09 came by calculation
x=(-6+-31.91)/2
so
x=(-6+31.91)/2 first (+);
x=25.91/2
x=12.955;
x=(-6-31.91)/2 then(-);
x=-37.91/2
x=-18.955 ;
ans is = 12.955&-18.955;
Write the equation in standard form: 3x + 1 = 2y
3x + 2y = 1
3x + 2y = –1
3x – 2y = –1
3x – 2y = 1
Answer:
3x+2y=-1
Step-by-step explanation:
moving the numbers around, the outcome will have to be different
// have a great day //
Answer:
c) 3x - 2y = -1
Step-by-step explanation:
Given equation,
→ 3x + 1 = 2y
Conversion into standard form,
→ 3x + 1 = 2y
→ 3x + 1 - 2y = 0
→ 3x - 2y = -1
Hence, option (c) is correct.