They could complete the job together in 2.4 days
The known parameters are;
The number of days it would take Michelle to complete the landscaping job = 6 days
The number of days it would take Danielle to complete the landscaping job = 4 days
The unknown parameter;
The number of days can the job be completed if they work together
The process of finding the solution;
The rate at which Michelle works = 1/6 of the landscaping work per day
The rate at which Danielle works = 1/4 of the landscaping work per day
Method;
Find their combined work rate, from which the time would take them to complete the job together can be found
Let, C, represent their combined work rate
Therefore, we have;
C = (1/6 + 1/4) = 5/12 of the landscaping (work) job/(per) day
The number of days they could complete the, 1, job = 1 job(work)/(5/12 (work)job/day) = 12/5 days = 2.4 days
∴ The number of days they could complete the job together = 2.4 days.
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The definition of a circle
Answer:
a round plane figure whose boundary (the circumference) consists of points equidistant from a fixed point (the center)
Explanation:
Oxford dictionary definition
Step-by-step explanation:
a circle is a shape consisting of all points in a plane that are at a given distance from a given point the center
a circular wire with radius 14 cm is cut and made straight then what will be its length?
We have to find the circumference
[tex]\\ \rm\longmapsto C=2\pi r[/tex]
[tex]\\ \rm\longmapsto C=2\dfrac{22}{7}(14)[/tex]
[tex]\\ \rm\longmapsto C=44(2)[/tex]
[tex]\\ \rm\longmapsto C=88cm[/tex]
The height h, in feet, of a projectile t seconds after launch is modeled by the equation h=32t-16t^2.
Complete question is;
The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t – 16t². How long after launch does the projectile return to the ground?
Answer:
2 seconds
Step-by-step explanation:
We are told that the height function is given by;
h = 32t – 16t²
Now, the velocity will be the derivative of the height equation.
Thus;
v(t) = dh/dt = 32 - 32t
Now, for projectiles, at max height, v = 0.
Thus;
32 - 32t = 0
32t = 32
t = 32/32
t = 1 s
It will take the same time it took to get to Max height as it will to get to ground from that height.
Thus, total height = 1 + 1 = 2 seconds
HURRY PLEASEEEEE!!!!!!
Juan scored 24 points in the first half of the basketball game, and he scored p points in the second half of the game. Write this in variable/constant form.
Answer:
24+p=t
Step-by-step explanation:
If he scored 24 points in the first half, and p in the next half, he scored a total of t points.
A flag has a perimeter of 5 metres. The length of the flag is 600 mm more than the
width of the flag. The length is represented by L and the width is represented by W.
Which of the linear systems in the choices represents the description?
O2L + 2W = 5
L - 600 = W
O2L + 2W = 5000
L - 600 = W
OL+W = 5000
W + 600 = L
O L x W = 5000
L + 600 = W
Answer:
The first two.
Step-by-step explanation:
See that L is 600mm MORE than W.
From there, you can note that L = W+600
or rearrange the formula and get W= L-600
Then, see that the perimeter of a flag is 2L + 2W
(Because there are two four sides to a rectangle, 2 width, 2 length)
It must total to be 5 meters, or 5000mm
Thus,
2L + 2W = 5000
Line m has no y-intercept, and its x-intercept is (3,0). line n has no x-intercept, and its y-intercept is (0-,4).
the equation of line m is ___ , and the equation of line n is ____.
type the correct answer in each box.
Answer:
x=3 and y=4
Step-by-step explanation:
please verify the answer
i need help with this question pls! :)
Hi there!
[tex]\large\boxed{\text{9 quarters}}[/tex]
We can let x = dimes and y = quarters.
We know that one dime = $0.10 and a quarter = $0.25, so:
$3.05 = $0.10x + $0.25y
And:
17 = x + y
Solve the system of equations. We can rearrange the bottom equation to create an expression equal to y:
17 - x = y
Substitute this into the top equation for y:
3.05 = 0.10x + 0.25(17 - x)
Distribute and simplify:
3.05 = 0.10x + 4.25 - 0.25x
3.05 = 4.25 - 0.15x
Solve for x:
-1.2 = -0.15x
x = 8
Find y using the above expression:
17 - 8 = y
y = 9
Se desea pintar un cuadrado inscrito en una circunferencia de radio R=3cm como se muestra en la figura. Calcular el área del cuadrado
El área del cuadrado es de 3 centímetros cuadrados.
Dado que se desea pintar un cuadrado inscrito en una circunferencia de radio R=3cm como se muestra en la figura, para calcular el área del cuadrado se debe realizar el siguiente cálculo:
Radio = diámetro / 2 3 = X/2 X = 6Hipotenusa del triángulo interno: 6 cmAplicando teorema pitagórico: lado al cuadrado mas lado al cuadrado es igual a hipotenusa al cuadrado.
L^2 + L^2 = 62L^2 = 6L^2 = 6/2L = √ 3L = 1.732Área de un cuadrado = L x L = L^2 = 3Por lo tanto, el área del cuadrado es de 3 centímetros cuadrados.
Aprende más en https://brainly.com/question/16405529
El área del cuadrado es de 18 centímetros cuadrados.
El procedimiento de resolución se basa en conocer que la Medida de la Diagonal de un Cuadrado inscrito es igual a la Medida del Radio del Círculo, lo cual permite determinar el valor de la medida del Cuadrado en función del Radio del Círculo. Finalmente, determinamos el Área del Cuadrado mediante su fórmula conocida.
Dado que existe un cuadrado inscrito en un círculo, la medida de la diagonal del cuadrado es igual a la medida del radio del círculo. Además, conocemos que un cuadrado está formado por 4 triángulos rectángulos con configuración angular 45-45-90. Entonces, la medida del lado del cuadrado se calcula mediante la siguiente relación geométrica:
[tex]l = \sqrt{2}\cdot R[/tex] (1)
Donde:
[tex]R[/tex] - Radio del círculo, en centímetros.
[tex]l[/tex] - Longitud del lado del cuadrado, en centímetros.
Por otra parte, la ecuación de área del cuadrado es igual a:
[tex]A = l^{2}[/tex] (2)
Donde [tex]A[/tex] es el área del cuadrado, en centímetros cuadrados.
Si sabemos que [tex]R = 3\,cm[/tex], entonces el área del cuadrado es:
[tex]l = \sqrt{2}\cdot (3\,cm)[/tex]
[tex]l = 3\sqrt{2}\,cm[/tex]
[tex]A = (3\sqrt{2}\,cm)^{2}[/tex]
[tex]A = 18\,cm^{2}[/tex]
El área del cuadrado es de 18 centímetros cuadrados.
He aquí una pregunta relacionada sobre el área del cuadrado: https://brainly.com/question/23915250
1. Determine the measure of the unknown angles indicated by letters. Justify your answers with
the properties or theorems you used
Answer:
hello,
Step-by-step explanation:
a)
In an isocele triangle, base's angles have the measure:
42+2a=180
2a=180-42
a=69(°)
b)
in a triangle, an external angle has for measure the sum of the angles not adjacents.
55+b=132
b=77 (°)
c)
in a quadrilater the sum of the (interior) angles is 2*180=360 degrees.
90+90+68+c=360
c=360-90-90-68
c=112 (°)
ailey is shopping at a department store during a 20% off everything sale. She also has a coupon for $5.00 off the sale amount. Hailey wants to keep her total under $65.00 before tax, so she creates this inequality:
0.80x − $5.00 ≤ $65.00.
Which inequality represents all possible solutions for x?
A.
x ≤ $75.00
B.
x ≤ $76.25
C.
x ≤ $86.25
D.
x ≤ $87.50
Answer:
D
Step-by-step explanation:
0.8x-5<=65
0.8x<=70
x<=700/8=87.5
Answer:
D
Step-by-step explanation:
i need help plzzzz!!!!!
Step-by-step explanation:
x+2>7
x>7-2
x>5
2x+5>_ 15
2x>_ 15-5
2x>_ 10
2x/2>_ 10/2
x>_5
In a survey of women in a certain country the mean height was 62.9 inches with a standard deviation of 2.81 inches answer the followinv questions about the specified normal distribution
The question is incomplete. The complete question is :
In a survey of women in a certain country ( ages 20-29), the mean height was 62.9 inches with a standard deviation of 2.81 inches. Answer the following questions about the specified normal distribution. (a) What height represents the 99th percentile? (b) What height represents the first quartile? (Round to two decimal places as needed)
Solution :
Let the random variable X represents the height of women in a country.
Given :
X is normal with mean, μ = [tex]62.9[/tex] inches and the standard deviation, σ = [tex]2.81[/tex] inches
Let,
[tex]$Z=\frac{X - 62.9}{2.81}$[/tex] , then Z is a standard normal
a). Let the [tex]99th[/tex] percentile is = a
The point a is such that,
[tex]$P(X<a)=0.99$[/tex]
[tex]$P \left( Z < \frac{a-62.9}{2.81} \right) = 0.99$[/tex]
From standard table, we get : [tex]P( Z < 2.3263) =0.99[/tex]
∴ [tex]$\frac{(a-62.9)}{281} = 2.3263$[/tex]
[tex]$a= (2.3263 \times 2.81 ) +62.9$[/tex]
= 6.536903 + 62.9
= 69.436903
= 69.5 (rounding off)
Therefore, the height represents the [tex]99th[/tex] percentile = 69.5 inches.
b). Let b = height represents the first quartile.
It is given by :
[tex]P( X < b) =0.25[/tex]
[tex]$P \left( Z < \frac{(b-62.9)}{2.81} \right) = 0.25$[/tex]
From the standard normal table,
[tex]P( Z < -0.6745) =0.99[/tex]
∴ [tex]$\frac{(b-62.9)}{2.81}= 0.6745$[/tex]
[tex]$b=(0.6745 \times 2.81) +62.9$[/tex]
= 1.895345 + 62.9
= 64.795345
= 64.8 (rounding off)
Therefore, the height represents the 1st quartile is 64.8 inches.
What is the range of the function on the graph?
Answer:
The range is the set of possible output values, which are shown on the y-axis. Keep in mind that if the graph continues beyond the portion of the graph we can see, the domain and range may be greater than the visible values.
Step-by-step explanation;
The range of a function is the set of y-coordinates of all the points int he graph of the function.
Look at the graph. The vertex is point (2, -3).
The graph does not go lower than that point.
The lowest y-coordinate is -3.
The graph goes up forever on both sides until infinity.
The range is all numbers greater than or equal to -3.
Combine and simplify these radicals.
Answer:
4 sqrt(3)
Step-by-step explanation:
sqrt(3) * sqrt(16)
sqrt(3) *4
4 sqrt(3)
Answer: d
Step-by-step explanation: I took the test
Zoe walks at a speed of 10 miles/h and jogs at a speed of 20 miles/h. She goes to the park to walk 2 miles on a Monday. How long will she take to walk 2 miles?
Answer:
12 minutes
Step-by-step explanation:
Given
[tex]s_1 = 10mi/h[/tex] --- walk speed
[tex]s_2 = 20mi/h[/tex] --- jog speed
[tex]d = 2\ miles[/tex] --- distance
Required
The time to walk the given distance
Time is calculated as:
[tex]Time = \frac{distance}{speed}[/tex]
In this case, the speed is the speed at which she walks.
So, we have:
[tex]Time = \frac{d}{s_1}[/tex]
Substitute known values
[tex]Time = \frac{2mi}{10mi/h}[/tex]
[tex]Time = 0.2hr[/tex]
Convert to minutes
[tex]Time = 0.2 * 60mins[/tex]
[tex]Time =12mins[/tex]
help me with this math question please
Answer:
$44.00 + $85.00 = $129.00
Step-by-step explanation:
The least amount that she needs is $129.00 because we're summing the amount for food and House Rent.
Movies and Shopping are less important.
(PICTURE) please answer whatever you can Its really urgent
What 2 days did he decrease his walking
Answer:
4, 7, 14
Step-by-step explanation:
Because it's were it decreases
Tính giá trị của I = [tex]\lim_{x \to \infty}[/tex] ([tex]\frac{4^{n} - 5.3^{n} + 1}{2.4^{n} + 2}[/tex])
I assume you're supposed to find the limit as n approaches infinity, not x.
You have
[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5.3^n+1}{2.4^n+2} = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-\left(\dfrac{5.3}{5.3}\right)^n+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}} \\\\ = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-1+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}}[/tex]
For |x| < 1, we have lim |x|ⁿ = 0 as n goes to infinity. Then each exponential term converges to 0, which leaves us with -1/0. This means the limit is negative infinity.
On the other hand, perhaps you meant to write
[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5\times3^n+1}{2\times4^n+2}[/tex]
The same algebraic manipulation gives us
[tex]\displaystyle\lim_{n\to\infty}\frac{\left(\dfrac44\right)^n-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2\left(\dfrac44\right)^n+\dfrac2{4^n}} = \lim_{n\to\infty}\frac{1-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2+\dfrac2{4^n}}[/tex]
Again the exponential terms converge to 0, but this time we're left with the limit 1/2.
What is the solution to this inequality?
-16x>-80
A. x < 5
O B. x>-5
O c. x<-5
O D. x>5
Answer:
A
Step-by-step explanation:
Divide both sides with -16. ALWAYS remember that if you divide any number with a negative number, this "< ≤ > ≥" symbols have to change to the opposite direction
what are the domain and range of y= cos x? Select one for domain and one for range
Answer:
Domain = all real numbers
range = -1<= y <= 1
The domain of y=cosx is all real numbers and the range is -1 ≤ y ≤ 1.
What is the domain and range of a function?The range of 'x' of a function is known as the domain of definition of a function and the range of 'y' of a function is known as the range of the function.
How to find the domain and range of a function?The function is continuous for all real values of 'x'.
Hence, the domain of the function is all real numbers.
The upper limit value of cosx =1 and lower limit value of cosx = -1 .
Hence, the range of the function is -1 ≤ y ≤ 1.
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Please help me with my Geometry.
Answer:
it should be 6
Step-by-step explanation:
I could be wrong
Maritza is comparing cell phones plans and notices that verizon offers a plan that is $60 for 10GB of data and $12 for each extra GB of data ore month. Create an expression to model this situation
Answer:
60 + 12 * g, with g representing the number of extra gigabytes
Step-by-step explanation:
First, we know that Maritza has to pay $60 for 10GB of data, no matter what. Therefore, the base cost of the cell phone plan is 60 dollars, and all extra costs must be added to that. Currently, our expression is therefore 60 + something = cost of cell phone plan.
After that, the plan costs $12 for each gigabyte of data past 10 GB. This means that, for example, if Maritza uses 11 gigabytes, the plan will cost 60 (the base amount) + 12 for each gigabyte past 10 GB. There are 11-10=1 extra gigabytes, so the cost is 60 + 12 * 1 = 72 dollars. For each extra gigabyte, 12 dollars are added, so we can represent this as
60 + 12 * g, with g representing the number of extra gigabytes
what is y=2x*2-6x-8 as a graph
Answer:
[tex] \bf \: y = 2 {x}^{2} - 6x - 8[/tex]
It is equation of a parabolla.
It is to be noted that the graph of y = 2x * 2-6x-8 which when simplified is y = -12x² - 12x. is attached accordingly.
What are the qualities of the graph of y = -12x² - 12x?The graph of y = -12x² - 12x is a downward-opening parabola.
It has a concave shape and its vertex is the highest point on the graph. The axis of symmetry is a vertical line passing through the vertex.
The graph may intersect or be tangent to the x-axis at two points, one point, or no points, depending on the discriminant.
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HELP ME PLS!
i need the first 4 examples
Answer:
1) 6а-9b=3(2a-3b)
2)8a-12b=4(2a-3b)
3) 5ab-5ac=5a(b-c)
4) 6ax+6ay=6a(x+y)
Select all the expressions equivalent to 2(x + 3)
2(x + 3) = 2x + 6
1. Correct - 2 * (x + 3) = 2x + 6
2. Correct - (x + 3)2 = 2x + 6
3. Correct - 2x + 6
4. Incorrect - 2x + 3
5. Incorrect - 2x + 3
6. Incorrect - 3x + 6
Hope this helps!
Which is not an equivalent expression
Quadrilateral ABCD is inscribed in this circle. What is the measure of angle a?
Answer:
Step-by-step explanation:
The rule is that opposite angles are supplementary. Therefore, angle A plus angle C = 180:
angle A + 43 = 180 and
angle A = 180 - 43 so
angle A = 137
solve the quadratic equation
give your answer to 2 decimal places
: 3x^2+x-5=0
Given:
The quadratic equation is:
[tex]3x^2+x-5=0[/tex]
To find:
The solution for the given equation rounded to 2 decimal places.
Solution:
Quadratic formula: If a quadratic equation is [tex]ax^2+bx+c=0[/tex], then:
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
We have,
[tex]3x^2+x-5=0[/tex]
Here, [tex]a=3,b=1,c=-5[/tex]. Using the quadratic formula, we get
[tex]x=\dfrac{-1\pm \sqrt{1^2-4(3)(-5)}}{2(3)}[/tex]
[tex]x=\dfrac{-1\pm \sqrt{1+60}}{6}[/tex]
[tex]x=\dfrac{-1\pm \sqrt{61}}{6}[/tex]
[tex]x=\dfrac{-1\pm 7.81025}{6}[/tex]
Now,
[tex]x=\dfrac{-1+7.81025}{6}[/tex]
[tex]x=1.13504167[/tex]
[tex]x\approx 1.14[/tex]
And
[tex]x=\dfrac{-1-7.81025}{6}[/tex]
[tex]x=-1.468375[/tex]
[tex]x\approx -1.47[/tex]
Therefore, the required solutions are 1.14 and -1.47.
(4x-5y) is subtracted from (-10x-y)
Answer:
-14x+4y
this is the correct answer.
