Answer:
[tex]5^{\circ}[/tex]
Step-by-step explanation:
[tex]~~~~~~~\tan \theta = \cot 85^{\circ}\\\\\implies \tan \theta = \tan\left(90^{\circ} - 85^{\circ} \right)\\\\\implies \tan \theta = \tan 5^{\circ}\\\\\implies \theta = 5^{\circ}[/tex]
Randy and trey take turns cleaning offices on the weekends. it takes randy at most 4 hours to clean the offices. it takes trey at most 6 hours to clean the offices. what is the greatest amount of time it would take them to clean the offices together?
Answer:
2.4 hours
Step-by-step explanation:
Because 1 hour Randy clean 1/4 of the room and Trey is 1/6. So we add both together and get that they clean 5/12 of the office in one hour. So 2.4 hours is the greatest amount of time it would take them to clean offices together
Is this correct? If not then whats the answer?????
(image below)
Answer:
6
Step-by-step explanation:
Mean no. of runs per game =
= Total no. of runs/ total no. of games
= 9+8+4+0+7+6+4+5+9+8 / 10
= 60 / 10
= 6
Answer the question in the screen shot
Using the continuity concept, as the value of the function has to be equal to the limit, it is found that the value of k is of k = -4.
When a function is continuous?A function is said to be continuous at x = a if, and only if:
[tex]\lim_{x \rightarrow a} f(x) = f(a)[/tex]
In this problem, we have to check at x = -2, hence:
[tex]\lim_{x \rightarrow -2} f(x) = f(-2)[/tex]
[tex]k = \lim_{x \rightarrow -2} f(x)[/tex]
For the limit, we have to check the lateral conditions, hence:
[tex]\lim_{x \rightarrow -2} f(x) = \lim_{x \rightarrow -2} \frac{x^2 - 4}{x + 2} = \lim_{x \rightarrow -2} \frac{(x - 2)(x + 2)}{x + 2} = \lim_{x \rightarrow -2} x - 2 = -2 -2 = -4[/tex]
Hence, from the continuity condition, k = -4.
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Write functions for each of the following transformations using function notation. Choose a different letter to
represent each function. For example, you can use R to represent rotations. Assume that a positive rotation occurs in
the counterclockwise direction.
• translation of a units to the right and b units up
reflection across the y-axis
• reflection across the x-axis
• rotation of 90 degrees counterclockwise about the origin, point O
• rotation of 180 degrees counterclockwise about the origin, point O
• rotation of 270 degrees counterclockwise about the origin, point O
Answer:
Step-by-step explanation:
1) = f(x - a) + b
Coordinate change
(x, y) → (x + a, y + b)
2) RFy(x, y) = f(-x)
Coordinate change
(x, y) → (-x, y)
3) RFx(x, y) = -f(x)
Coordinate change
(x, y) → (-y, x)
4) RCCW90(x, y) = f⁻¹(-x)
Coordinate change
(x, y) → (-y, x)
5) RCCW180(x, y) = -(f(-x))
Coordinate change
(x, y) → (-x, -y)
6) A 270 degrees counterclockwise rotation gives;
RCCW270(x, y) = -(f⁻¹(x))
Coordinate change
(x, y) → (y, -x)
Step-by-step explanation:
1) Horizontal translation a units right = f(x - a)
The vertical translation b units up = f(x) + b
Therefore, we get; = f(x - a) + b
The coordinate change
(x, y) → (x + a, y + b)
2) A reflection across the y-axis = RFy(x, y) = f(-x)
The coordinate change
(x, y) → (-x, y)
3) A reflection across the x-axis gives RFx(x, y) → (x, -y)
Therefore, in function notation, we get;
RFx(x, y) = -f(x)
4) A 90 degrees rotation counterclockwise, we get RotCCW90(x, y) → (-y, x)
In function notation RotCCW90(x, y) = INVf(-x) = f⁻¹(-x)
5) A 180 degrees counterclockwise rotation about the origin gives;
(x, y) → (-x, -y)
Therefore, we get;
In function notation RotCCW180(x, y) = -(f(-x))
6) A 270 degrees counterclockwise rotation gives RotCCW270(x, y) → (y, -x)
In function notation RotCCW270(x, y) = -(f⁻¹(x))
Does anyone know the answer
Answer: two units to the left, four units down and reflected across the y axis
If a = 7 - 4√3, find the value of a + 1/a
Answer:
Step-by-step explanation:
To calculate a+1/a, we first need to calculate for a.
a = 7 - 4 * [tex]\sqrt[2]{3}[/tex]
square root of 3 = 1.73
a = 7 - 4 * 1.73
a = 7 - 6.9
a = 0.1
0.1 + 1 / 0.1 = 0.1 + 10 = 10.1
Now, in case 4 wasn't being multiplied with the square root of 3, and instead, it was four root of 3, I am gonna do the calculations again:
a = 7 - [tex]\sqrt[4]{3}[/tex]
a = 7 - 1.31
a = 5.69
5.69 + 1 / 5.69 = 5.69 + 0.17 = 5.86
Hope I Helped!
Charlie owns a computer repair service. For each computer, they charge $50 plus $45 per hour of work. A linear equation that expresses the total amount of money Charlie earns per computer is y=50+45x. What are the independent and dependent variables? What is the y-intercept and the slope?
Answer:
The independent variable (x) is the amount of time John fixes a computer. The dependent variable (y) is the amount, in dollars, John earns for a computer.
y-intercept: (0,50)
Slope: 45
Find sin (ABC + 60) NEED QUICK 100 PPOINTS
Answer:
B
Step-by-step explanation:
using the addition identity for sine
sin(A + B) = sinAcosB + cosAsinB
using the sine and cosine ratios in the right triangle
sinABC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{4}{5}[/tex]
cosABC = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{3}{5}[/tex]
using the exact values
sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] , cos60° = [tex]\frac{1}{2}[/tex]
Then
sin(ABC + 60)
= sinABC cos60 + cosABC sin60
= ( [tex]\frac{4}{5}[/tex] × [tex]\frac{1}{2}[/tex] ) + ([tex]\frac{3}{5}[/tex] × [tex]\frac{\sqrt{3} }{2}[/tex] )
= [tex]\frac{4}{10}[/tex] + [tex]\frac{3}{10}[/tex] [tex]\sqrt{3}[/tex]
= [tex]\frac{2}{5}[/tex] + [tex]\frac{3}{10}[/tex] [tex]\sqrt{3}[/tex]
sin<ABc
Perpendicular/Hypotenuse4/5cos<ABC
Base/Hypotenuse3/5Now
sin(<ABC+60)sin<ABC ×cos60+cos<ABC×sin604/5(1/2)+3/5(√3/2)2/5+3/10√3how many ounces of a 16% alcohol solution must be mixed with 2 ounces of a 20% alcohol solution to make a 17% alcohol solution?
Answer:
x = 6
Step-by-step explanation:
.16x + 2 * .02 = (x + 2) * .17
.16x + .4 = .17x + .34
.06 = .01x
6 = x
let g(x) be a vertical shift of f(x)=-x up 4 units followed by a vertical stretch by a factor of 3. Write the rule for g(x).
A function assigns the values. The function g(x) can be written as g(x) = -3x + 12.
What is a Function?A function assigns the value of each element of one set to the other specific element of another set.
Given the function f(x)=-x, now since a transformed function g(x) is produced by shifting the function 4 units upwards and vertical stretch by a factor of 3. Therefore, g(x) can be written as,
Vertical Shift by 4 units,
f(x)+4
Vertical stretch by a factor of 3
g(x) = 3(f(x) + 4)
g(x) = -3x + 12
Hence, the function g(x) can be written as g(x) = -3x + 12.
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Prove: 45= m/ZXY
Complete the proof. Number your reasons in the textbox below.
Step-by-step explanation:
since the two angles from a straight line, they make a linear pair and linear pairs are supplementery. by the angle addition postulate, you can determine that the two angles sum to 180. substituting the one angle mearsure that you are guven and using a bit of simple arithmetic and the subtraction property of equality, you can determine that the other angle,angle YXZ, is 45 degrees. I hope this is helpful
me QR goes through points Q(0, 1) and R(2, 7). Which equation represents line QR?
y-1=6x
y-1=3x
y-7=2x-6
y-7=x-2
We write the equation in the form of directional.
y -1 = 6x ⇔ y = 6x + 1
y - 1 = 3x ⇔ y = 3x + 1
y - 7 = 2x - 6 ⇔ y = 2x - 6 + 7
y = 2x + 1
y - 7 = x - 2 ⇔ y = x - 2 + 7
y = x + 5
Equations cleverly arranged .
Point Q = (0,1)
b factor , not only fits the last equation
In the drawing have engraved points Q and R are tangent linear function appropriate to that point . This graphics solution . y = 3x + 1
Answer b
We check choice by the system of equations , where substitute wartoćsi points Q and R to the model equations linear function
The result of equations confirmed our choice Answer b
The expression 2 (a + b) = -8.1 for certain values of a and b. Find the value of the following expressions for the same values of a and b: 4a+4b
If we put a=0 and b=-4.05 then the expression 4a+4b becomes -16.2 and when we put a=-4.05 and b=0 then the expression becomes -16.2.
Given 2 (a + b) = -8.1
Because no relationship between a and b is given so we can put any value of one variable to determine the value of another variable.
If we put a=0 in 2(a+b) =-8.1 then b=-4.05
If we put b=0 then a =-4.05.
We need to put these values in 4a+4b
when a=0 b=-4.05
4a+4b=4*0+4*-4.5
=-16.2
when b=0 and a=-4.05
4a+4b=4*-4.05+4*0
=-16.2
Hence for a=0,b=-4.5 the value of 4a+4b equals -16.2 and for a=-4.05 and b=0 the function equals -16.2.
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1. (08.01 MC)
The graph shows two lines. A and B
Answer:
Part A:
A pair of linear equations can only have one solution or infinitely many solutions. In this case, there would only be one solution as they intersection at only one point.
Part B:
The solution would be (3, 4) because it is the point of intersection between the two linear lines.
Answer the following
The set A satisfying the given inequality is A = (-[tex]\infty[/tex], -10].
What are some properties of an inequality relation?Following are some facts which are true for an inequality relation:
Equal numbers can be added or subtracted from both sides of an inequality without affecting the inequality sign.The Inequality sign is unchanged if both sides are multiplied or divided by a positive number, but when multiplied or divided by a negative number the inequality sign is reversed.[tex]\frac{5x-2}{8} - \frac{3x-5}{10} &\ge& x+y\\\\\Rightarrow\;\; \frac{13}{40}x + \frac{1}{4}&\ge& x+y\\\\\Rightarrow\;\;\;\;\;\; -\frac{27}{40}x &\ge & y - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\;\; -x &\ge & \frac{40}{27}\left( y-\frac{1}{4} \right).\hspace{1cm}(1)[/tex]
Since y ∈ B, -2 ≤ y ≤ 7. So,
[tex]\;\;\;\;\;\;\;\,-2 - \frac{1}{4}\; \le\; y - \frac{1}{4} \;\le\; 7 - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\; -\frac{9}{4}\; \le\; y - \frac{1}{4} \;\le\; \frac{27}{4}\\\\\Rightarrow\;\;\; -\frac{9}{4}\cdot \frac{40}{27} \;\le\; \frac{40}{27} \left( y-\frac{1}{4} \right) \;\le \;\frac{27}{4}\cdot \frac{40}{27}\\\\\Rightarrow\;\;\;\;\;\;\;\; -\frac{10}{3} \;\le\; \frac{40}{27}\left( y - \frac{1}{4} \right)\; \le\; 10.[/tex]
The set {-x | inequality (1) holds ∀ y ∈ B} is [10, [tex]\infty[/tex]) i.e.
10 ≤ -x ≤ [tex]\infty[/tex].
Multiplying -1 throughout gives
-10 ≥ x ≥ -[tex]\infty[/tex].
x, thus, lies in the range A = (-[tex]\mathbf{\infty}[/tex], -10}.
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Disclaimer: The question was incomplete. Please find the full content below.
QuestionFind the set A such that for x ∈ A
[tex]\frac{5x - 2}{8} - \frac{3x - 5}{10} \ge x + y[/tex]
∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.
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Ving tools to form the correct answer on the graph.
Graph the line that represents this equation:
y + 2 =
(x+2)
Drawing Tools
Select
Point
Line
Click on a tool to begin drawing.
10
N
27
The graph of the equation is shown in the attached picture which is a straight line.
What is a straight line?A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:
[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have a graph of a equation:
y + 2 = (x+2)
or
y = x
The above equation is a linear equation or straight line equation the slope of the equation is 1.
m = 1
The y-intercept of the equation is 0.
We can plot the equation y = x by using the slope and y-intercept.
Thus, the graph of the equation is shown in the attached picture which is a straight line.
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Five hundred ten of 650 high school students said that pizza was their favorite food in the school cafeteria.
what is the margin of error? round to four decimal places.
0.0005
0.0003
0.0161
0.0322
If Five hundred ten of 650 high school students said that pizza was their favorite food. The margin of error is 0.0322.
Margin of errorGiven:
Sample proportion=Five hundred ten=510
Sample size=650
Hence:
Margin of error=z×√p×(1-p)/n
Margin of error=2√510/650× (1-510/650)÷650
Margin of error=2√0.78461538×(1-0.78461538)÷650
Margin of error=2√0.78461538×0.21538462÷650
Margin of error=2√0.168994085÷650
Margin of error=2√0.0002599909
Margin of error=0.0322
Therefore the correct option is D.
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The first term of an arithmetic sequence is 1 and the sum of the first four terms is 100. Find the first four terms
Answer:
1, 17, 33, 49
Step-by-step explanation:
given the first term is 1 then the next 3 terms are
1 + d, 1 + 2d, 1 + 3d ( d is the common difference )
the sum of the first 4 terms is 100 , then
1 + 1 + d + 1 + 2d + 1 + 3d = 100 , that is
4 + 6d = 100 ( subtract 4 from both sides )
6d = 96 ( divide both sides by 6 )
d = 16
1 + d = 1 + 16 = 17
1 + 2d = 1 + 2(16) = 1 + 32 = 33
1 + 3d = 1 + 3(16) = 1 + 48 = 49
the first 4 terms are
1, 17, 33, 49
Answer:
see the file attached!!!!
Consider the steps for determining the quotient of ¹24 + x4
12
X-4
The quotient will be
expression.
Complete the statements to choose a numerator and denominator to represent the quotient.
The numerator of the simplified quotient is
The denominator of the simplified quotient is
The simplified form of the expression has a numerator (x + 9)(2x + 1) and the denominator (x + 7) and the expression doesn't exist at (x = 9).
How to illustrate the quotient?The given expression is:
= [(3x² - 27x)/(2x² + 13x - 7)]/(3x/4x² - 1)
Firstly, factorize the expression 4x² - 1.
4x² - 1 = (2x - 1)(2x + 1)
Then, factorize 2x² + 13x - 7.
2x² + 13x - 7 = 2x² + 14x - x - 7
2x(x + 7) - 1(x + 7)
= (2x - 1)(x + 7)
Then, factorize the equation 3x² - 27x.
3x² - 27x = 3x(x - 9)
The factorized terms will be substituted into the equation. This will be:
= [3x(x - 9)/(2x - 1)(x + 7)] / 3x[(2x - 1)(2x + 1)]
= (x + 9)(2x + 1)/(x + 7)
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7% tax on a $3 soda with an $8 burger
Step-by-step explanation:
please mark me as brainlest
If tan 0 = 4/3 and 0 lies in the third quadrant, which is the correct ratio for cos 0?
4/5
-3/5
-4/5
3/5
[tex] \frac{ - 3}{5} \\ [/tex]
because , in the third quadrant , the value of cos is negative. Moreover , we can find the third side of the triangle using Pythagoras theorem.
then ,
[tex] \cos(\theta) = \frac{base}{hypotenuse} \\ \\ \dashrightarrow \: \cos(\theta) = \frac{ - 3}{5} [/tex]
hope helpful.
The answer is cos 0 = -3/5
To calculate the answer:Given :
tan 0 = 4/3 and is in the 3rd quadrant
this implies that both the perpendicular and base are negative.
Perpendicular = -4
Base = -3
Hypotenuse = [tex]\sqrt{(perpendicular)^{2} + (base)^{2} }[/tex]
Hypotenuse = [tex]\sqrt{(-4)^{2} + (-3)^{2} }[/tex]
Hypotenuse = [tex]\sqrt{25} = 5[/tex]
cos 0 = [tex]\frac{Base}{Hypotenuse}[/tex]
cos 0 = -3/5
Therefore, cos 0 = -3/5
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Solve equation
-15+n=-9
If x² + 1/x² = 102, then x -1/x =
a) 10
b) 8
c) 13
d) 12
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:A. \:\: 10[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } = 102[/tex]
[ subtract 2 from both sides ]
[tex]\qquad \tt \rightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } - 2 = 102 - 2[/tex]
[tex]\qquad \tt \rightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } - \bigg( 2 \sdot x \sdot \cfrac{1}{x} \bigg)= 100[/tex]
[ 2 can written like that, as they cancel out each other ]
Apply Identity [ a² + b² -2ab = (a - b)² ]
[tex]\qquad \tt \rightarrow \: \bigg (x - \cfrac{1}{x} \bigg) {}^{2} = 100[/tex]
[tex]\qquad \tt \rightarrow \: x - \cfrac{1}{x} {}^{} = \sqrt{100}[/tex]
[tex]\qquad \tt \rightarrow \: x - \cfrac{1}{x} {}^{} = 10[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
J
Question 1 of 10
Each equation given below describes a parabola. Which statement best
compares their graphs?
x = 5y²
x=3y²
OA. Both parabolas open upward, and x = 3y2 is wider than
x = 5y².
B. Both parabolas open to the right, and x = 3y² is wider than x = 5y².
OC. Both parabolas open upward, and x = 5y2 is wider than
x = 3².
OD. Both parabolas open to the right, and x = 5y² is wider than x = 3y².
SUBMIT
Answer:
D
Step-by-step explanation:
x = 5y²
x = 3y²
Here x is a function of y and so the parabola is open either to right or left.
The coefficient of y² is positive. So the parabola is open to right.
Both parabolas are open to right and x = 5y² is wider than x = 3y².
state whether or not the relation is considered a function?
Answer:
A function is when each input has exactly one output
Step-by-step explanation:
Each input can only have one output, but an output can have multiple inputs.
What is the degree of 069 ?
A. 0
B. 2
C. 3
D. 4
E. none of these
Answer: none
Step-by-step explanation:
PLEASE HELP ASAP
thank you :)
Answer:
y = x/2 -3
Step-by-step explanation:
x - 2y = 6
Slope intercept form is y = mx+b where m is the slope and b is the y intercept
We need to solve for y
Subtract x from each side
x-2y-x = -x+6
-2y = -x+6
Divide each side by -2
-2y/-2 = -x/-2 +6/-2
y = x/2 -3
The slope intercept form is
y = x/2 -3
Answer: slope intercept form is
y = x/2 -3
Step-by-step explanation:
hope this helps ; )
Question 7
points 2
ps
sunshine house cleaners mops 1/5 square feet every 2/3 minute. what is their speed in terms of square feet
tio
per minute?
Their speed in terms of square feet per minute is 3/10 square feet per minute.
We know that the speed formula is the rate at which an object travels a given distance. Speed is defined as the distance traveled by a body in a given amount of time. Speed in the SI is measured in m/s.
Given that the distance = 1/5 square feet.
The time = 2/3 minute.
Speed = distance/time = (1/5)/(2/3) = (1/5)*(3/2) = 3/10
Therefore, we can conclude that their speed in terms of square feet per minute is 3/10 square feet per minute.
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Select the true statement about triangle ABC.
13
5
12
A. sin C = sin A
B. sin C = cos B
C. sin C = tan A
D. sin C = cos A
Answer:
sin C = cos A
Step-by-step explanation:
sinC = opp/hyp
=12/13
cosA = adj/hyp
12/13
Find the range for the given domain: {-2, -1, and 0} and the function is y = 3x2.
The range of the function at domain {-2, -1, and 0} will be { 12 , 3 and 0}.
What is range?
A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.
Given that:-
The range for the given domain: {-2, -1, and 0} and the function is y = 3x².
The range will be the value of y at each given value of the domain.
Domain: { -2, -1, 0 }
y = 3x²
At x = -2 → y = 3 ( -2)² = 12
At x = -1 → y = 3 (-1)² = 3
At x = 0 → y = 3 (0) = 0
Therefore range of the function at domain {-2, -1, and 0} will be { 12 , 3 and 0}.
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