Square A"B"C"D" is the final image after the rule was applied to square ABCD. On a coordinate plane, a square A double-prime B double-prime C double-prime D double-prime has points (negative 5, negative 3), (negative 3, negative 1), (negative 1, negative 3), (negative 3, negative 5). What are the coordinates of vertex A of square ABCD? (–1, –6) (–1, –2) (–1, 6) (–2, 1)

Answer:

1)

Volume of pyramid = 1/3(Ab)(h)

Where Ab is the area of base, h is height

Volume of cone = 1/3(Ab)(h)

a) Their formula for finding volume is same. Also, their painting heads are same.

b) Pyramids have a tetragonal base while cones have a polygonal base

2) Pyramids

Volume of cone = (1/3) πr²h

Since Area of a circle = πr²

So

Volume of pyramid = (1/3)(A)(h)

So we can use the formula of a circle in cone's formula

Answer:

i dont know but i want points

Step-by-step explanation:

hehehe

Answer:

The lower limit is 72.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is more than 2 standard deviations from the mean, it is unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

In this question, we have that:

[tex]n = 100, p = 0.8[/tex]

So

[tex]\mu = 0.8, s = \sqrt{\frac{0.8*0.2}{100}} = 0.04[/tex]

He would be suspicious if the number of normal births in the sample of 100 births fell below the lower limit of "usual." What is that lower limit?

2 standard deviations below the mean is the lower limit, so X when Z = -2.

Proportion:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]-2 = \frac{X - 0.8}{0.04}[/tex]

[tex]X - 0.8 = -2*0.04[/tex]

[tex]X = 0.72[/tex]

Out of 100:

0.72*100 = 72

The lower limit is 72.

Answer:

78.5 cm^2

Step-by-step explanation:

The area of a circle is found by

A = pi r^2

A = pi (5)^2

A = 25pi

Letting pi = 3.14

A = 25(3.14)

A =78.5 cm^2

Letting  pi be the pi button

A =78.53981634

Rounding to the nearest tenth

78.5

Answer:

78.5 cm²

Step-by-step explanation:

The area of a circle can be found using the following formula.

a=πr²

We know the radius of the circle is 5 centimeters.

r=5

Substitute 5 in for r.

a=π(5²)

Evaluate the exponent. 5² is equal to 5*5, which equals 25.

a=π(25)

Multiply 25 and pi

a=78.5398163397

Round to the nearest tenth. The 3 in the hundredth place tells use to leave the 5 in the tenths place as is.

a≈78.5

Add appropriate units. Area always uses units², and the units in this case are centimeters.

a≈78.5 centimeters²

The area of the circle is about 78.5 square centimeters.

Answer: the percentile is 74%

Step-by-step explanation:

The given data distribution is arranged in increasing order as:

0.1 0.2 0.2 0.3 0.4 0.4 0.4 0.5 0.5 0.6 0.6 0.8 0.9 0.9 0.9 1.1 1.3 1.7 1.8 1.9 2.3 2.4 2.5 2.6 2.7 3.1 3.5 3.5 3.7 3.8 4.8 5.2 7.4 7.9 8.2 8.6 9.3 11.2 11.3 11.4 12.1 12.6 13.1 13.3 13.6 13.8 14.6 15.6 15.7 25.6

The total number of values given in the data is 50

Percentile = number of values in the distribution lesser than the given value × 100/ total number of values in the distribution

Considering the data speed of 11.2 Mbps, the number of data speed lower than 11.2 is 37

Percentile = (37 × 100)/50 = 74%

Answer:

4a

Step-by-step explanation:

The mean is found by adding all of the data set together and then dividing by the amount of individual pieces of data in the set.

(2+3+3+8) = 16

16/4=4

The answer is 4a.

Answer:

2/3 * 460 = 306 and 2/3

Multiply 460 by 2/3 by first multiplying 460 by 2, then divide that by 3:

460 x 2 = 920

920 /3 = 306 2/3

The answer is 306 2/3

Answer:

3x-5=2x+6

x-5=6

x=11

Answer:-8

Step-by-step explanation:

8 - 2 × 8

8 - 16

-8

Answer:

21.b

22.c

Step-by-step explanation:

idk how to explain it lol I did mental math

Answer:

Part a

Null hypothesis: [tex] \mu = 69.3[/tex]

Alternative hypothesis: [tex]\mu \neq 69.3[/tex]

Part b

[tex] z = \frac{69.8- 69.3}{\frac{11.2}{\sqrt{140}}}= 0.528[/tex]

Step-by-step explanation:

For this case we have the following info given :

[tex] \bar X = 69.8[/tex] the sample mean

[tex] n= 140[/tex] represent the sample size

[tex] s = 11.2[/tex] represent the standard deviation

Part a

And we want to test if the true mean is equal to 69.3 so then the system of hypothesis:

Null hypothesis: [tex] \mu = 69.3[/tex]

Alternative hypothesis: [tex]\mu \neq 69.3[/tex]

Part b: Find the statistic

The statistic is given by:

[tex] z= \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And replacing the info we got:

[tex] z = \frac{69.8- 69.3}{\frac{11.2}{\sqrt{140}}}= 0.528[/tex]

Answer:

0.534

Step-by-step explanation:

p(0 losses) = 0.7² = 0.49

p(1 loss) = 2 x 0.3 x 0.7 = 0.42

p(2 losses) = 0.09

This is a conditional probability problem. If the number of people hospitalized is 0 or 1, then the  total loss will be less than 1. However, if two people are hospitalized, the probability that the  total loss will be less than 1 is 0.5. we need to exclude the 50% x 0.09 chance of a double loss costing more than 1. So

P(Cost < 1)

= 0.49 + 0.42 +0.045

= 0.955

P(0 losses | Cost < 1)

= P(0 losses and Cost < 1) / P(Cost < 1)

= 0.49 / 0.955 = 0.513

P(1 loss | Cost < 1)

= 0.42 / 0.955 = 0.440

P(2 losses | Cost < 1) = 0.045 / 0.955 = 0.047

Now take the expectation:

E[X] = (0)(0.513) + (1)(0.440) + (2)(0.047)

= 0.440 + 0.094

= 0.534

Answer:

The value of the function f(x) at x=a can be determined by substituting a instead of x into the function expression.

1. When x=-1, then

f(-1) = 2 * (-1)^3 - 3 * (-1)^2 + 7 = -2 - 3 + 7 = 2.

2. When x=1, then

f(1) = 2 * 1^3 - 3 * 1^2 + 7 = 2 - 3 + 7 = 6.

3. When x=2, then

f(-1) = 2 * 2^3 - 3 * 2^2 + 7 = 16 - 12 + 7 = 11.

Step-by-step explanation:

Answer:

f(−1) =✔ 2

f(1) = ✔ 6

f(2) =✔ 11

Step-by-step explanation:

Answer:

(0,34)

Step-by-step explanation:

For each rise of 14 in the x direction, this graph rises by -8 in the y direction. This means that, when x is 0, and the graph intersects the y axis, the y value will be 50-8-8=34. Therefore, the y intercept of this line is (0,34). Hope this helps!

Answer:

The answer is (0,34)

Answer:

8

Step-by-step explanation:

y²+by+16= (y+4)²

y²+by+16= y²+2*4*y+4²

y²+by+16= y²+8y+16

by=8y

b=8

[tex]answer \\ = 5 \sqrt{3} \\ please \: see \: the \: attached \: picture \: for \: \: full \: solution \\ hope \: it \: helps[/tex]

Answer:

[tex]5 \sqrt{3} [/tex]

First answer is correct

Step-by-step explanation:

[tex] \frac{5}{x} = \cos(60) \\ \frac{5}{x} = \frac{1}{2} \\ x = 10 \\ \frac{y}{x} = \sin(60 ) \\ \frac{y}{10} = \frac{ \sqrt{3} }{2} \\ 2y = 10 \sqrt{3} \\ y = \frac{10 \sqrt{3} }{2} \\ y = 5 \sqrt{3} [/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

Step-by-step explanation:

factor out the numerator and demoninator

(m-2)(m-1)/m(m-1)

= (m-2)/m

Answer:

2

Step-by-step explanation:

Given the system of equations:

[Tex]x^2+y^2=9\\9x+2y=16[/tex]

Comparing [Tex]x^2+y^2=9[/tex] with the general standard equation of a circle [Tex](x-h)^2+(y-k)^2=r^2[/tex].

The first equation is an equation of a circle centred at (0,0) with a Radius of 3.

The second equation 9x+2y=16 is a straight line equation.

A straight line can only intersect a circle at a maximum of 2 points.

Therefore the greatest possible number of solutions to the equations in the system is 2.

Answer:

2

Step-by-step explanation:

and jj is gay of outer banks

Answer:

The probability of selecting two red balls is 0.132.

Step-by-step explanation:

In a bag there are 10 balls in a bag, 4 red balls and 6 black balls.

The conditions of selecting a ball are:

It is also provided that only one ball can be picked at a time.

Now, it is given that two balls are picked.

The number of ways to select a red ball in the first draw is: [tex]{4\choose 1}=4\ \text{ways}[/tex]

Compute the probability of selecting a red ball in the first draw as follows:

[tex]P(\text{First ball is Red})=\frac{{4\choose 1}}{{10\choose 1}}=\frac{4}{10}=0.40[/tex]

Now as a red ball is selected it will not be replaced.

So, there are 9 balls in the bag now.

The number of ways to select a red ball in the second draw is: [tex]{3\choose 1}=3\ \text{ways}[/tex]

Compute the probability of selecting a red ball in the second draw as follows:

[tex]P(\text{Second ball is Red})=\frac{{3\choose 1}}{{9\choose 1}}=\frac{3}{9}=0.33[/tex]

Compute the probability of selecting two red balls as follows:

[tex]P(\text{Two Red balls})=P(\text{First ball is Red})\times P(\text{Second ball is Red})[/tex]

                            [tex]=0.40\times 0.33\\\\=0.132[/tex]

Thus, the probability of selecting two red balls is 0.132.

Answer:

28 and 32

Step-by-step explanation:

they have the most

Answer:

Option 2

Step-by-step explanation:

The question states "the width of the rectangle is 4 less than half the length."  Since we are looking for the value of w, w will be equal to the expression we create.  We start with half the length and than subtract 4 from it.  This is because it says 4 less than half the length, not half of 4-length or another variation.  In many of these problems the best way to solve them is by working backwards.

Answer:

Option 2

Step-by-step explanation:

Translating these words into math, we get w = 1/2l - 4 which is Option 2.

Answer:

(a) all men = 3.6351 * 10^ -7

(b) all women = 2.3483* 10^ -4

(c) 8 men and 4 women = 0.0308

(d) 6 men and 6 women= 0.2170

Step-by-step explanation:

A jury pool has 15 men and 21 women, from which 12 jurors will be selected.

Total = 36 people

Probability of

(a) all men

= 15C12/36C12

= 455/1251677700

= 3.6351 * 10^ -7

(b) all women

= 21C12/36C12

= 293930/1251677700

= 2.3483* 10^ -4

(c) 8 men and 4 women

=( 15C8 * 21C4)/36C12

= (6435*5985)/1251677700

= 38513475/1251677700

= 0.0308

(d) 6 men and 6 women

= (15C6 * 21C6)/(36C12)

= (5005*54264)/1251677700

= 271591320/1251677700

= 0.2170

Answer:

The situations c, d and e are Inferential statistics.

Step-by-step explanation:

Inferential statistics is used to determine reasons for a situation or phenomenon. It helps to draw conclusions grounded on extrapolations, and is hence fundamentally dissimilar from descriptive statistics that only summarizes the data that has truly been measured.

Descriptive statistics are short-term descriptive coefficients that condenses a given data set, which can be a demonstration of the whole or a sample of a whole population.

All descriptive statistics are either central tendency measure or variability measure. Measures of central tendency define the epicenter position of a distribution for a data set.  

From the provided situations the Inferential statistics are:

c. The mean of a sample set of scores is calculated to characterize the sample.

d. The sample data from a poll are used to estimate the opinion of the population.

e. A correlational study is conducted on a sample to determine whether educational level and income in the population are related.

Thus, the situations c, d and e are Inferential statistics.

The one that demonstrates inferential statistics would be:

c). The mean of a sample set of scores is calculated to characterize the sample.

d). The sample data from a poll are used to estimate the opinion of the population.

e). A correlational study is conducted on a sample to determine whether the educational level and income in the population are related.

Inferential statistics is denoted as the kind of statistics that is concluded through a small sample employed which will act as the representative of the larger population.

The smaller sample's characteristics are analyzed and deductions are made in general about the entire population.

The above statements exemplify these characteristics by calculating the mean of the sample population and performing a correlational examination.

Thus, options c, d, and e are the correct answers.

Learn more about "Statistics" here:

brainly.com/question/14318705

Answer:

M.

Step-by-step explanation:

Answer:

The 80% confidence interval for the average net change is (8.596, 12.904).

Critical value t=1.638.

Step-by-step explanation:

First, we calculate the mean and standard deviation of the sample:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{4}(12+7+13+11)\\\\\\M=\dfrac{43}{4}\\\\\\M=10.75\\\\\\s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{3}((12-10.75)^2+(7-10.75)^2+(13-10.75)^2+(11-10.75)^2)\\\\\\s=\dfrac{20.75}{3}\\\\\\s=6.92\\\\\\[/tex]

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=10.75.

The sample size is N=4.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.63}{\sqrt{4}}=\dfrac{2.63}{2}=1.315[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=4-1=3[/tex]

The t-value for a 80% confidence interval and 3 degrees of freedom is t=1.638.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=1.638 \cdot 1.315=2.154[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 10.75-2.154=8.596\\\\UL=M+t \cdot s_M = 10.75+2.154=12.904[/tex]

The 80% confidence interval for the average net change is (8.596, 12.904).

Answer:  [tex]\bold{P(B|A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{11}{30}}[/tex]

Step-by-step explanation:

The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)

[tex]P(B|A)=\dfrac{P(B\cap A)}{P(A)}[/tex]

P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)

          (2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)

          (3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)

                    (4, 5), (4, 4), (4, 3), (4, 2), (4, 1)

                              (5, 4), (5, 3), (5, 2), (5, 1)

                                        (6, 3), (6, 2), (6, 1)

       = 30

P(B) = (1, 2), (2, 1)                                   sum = 3

          (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)    sum = 6

          (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)  sum = 9

          (6, 6)                                           sum = 12

      = 12

P(A ∩ B) =  (1, 2), (2, 1)

                  (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

                  (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)

             = 11

Answer:

B. You shouldnt take a random sample of more than 5% of the population size.

Step-by-step explanation:

B. You shouldnt take a random sample of more than 5% of the population size. This is True, so as to avoid the research analysis to be more complex to interpret and analyzed

However, the following are not true statements:

A. Random samples only generate unbiased estimates of long-run proportions, not long-run means. This is False, as there may be sampling error, when picking the sample, which will lead to bias estimates in the long run proportions

C. There is no way that a random sample of 100 people can be representative of all adults living in the United States. This is False, as using the right factors such as gender, age, income, etc, in selecting the sample, 100 people is enough to use as sample of adults living in the United States

D. If this question is voted out, the alternate option is "larger samples are always better than smaller samples, regardless of how the sample was collected." This is False, larger samples are not always better than smaller samples. In fact, they are often difficult to analyze and interpret.

E. Nonrandom samples are always poor representations of the population: This is False, depending on the expected outcome of the research study. Some research studies required the research to use Nonrandom samples to reach verifiable conclusion.

Answer:

R=9

Step-by-step explanation:

the formula for area of a circle is pi r squared

where r denotes the radius of the circle

equating the formula for area with the area of the circle provided

p\i r squared = 81 p\i

r squared = 81

r = radical 81

r =9 inches

Answer:Any legal fraction (denominator not equal to zero) with a numerator equal to zero has an overall value of zero. all have a fraction value of zero because the numerators are equal to zero.