Standard form question

Standard Form Question

Answers

Answer 1

Answer:

 1.64×10^7 km

Step-by-step explanation:

The Pythagorean theorem can be used to find the hypotenuse of this right triangle.

  QR² = PQ² +PR²

Expressing the given distances as multiples of 10^7 km, we have ...

  QR² = 0.36² +1.6² = 0.1296 +2.5600 = 2.6896

  QR = √2.6896 = 1.64

The shortest distance between planets Q and R is 1.64×10^7 km.


Related Questions

Based on the equation 6x + 2y = 30, what is the missing value in the table?

Answers

Answer:

x =5

Step-by-step explanation:

hope this helps you

please mark as brainliest

Answer:15

Step-by-step explanation:6x +2y=30

2(3x+y) =30

3x+y=30÷2

3x+y=15

Find the missing side length in the image below

Answers

find the area and volume of the trapezoids first

PLEASE HELP !!

A line is defined by the equation y = x-6. The line passes through a point whose y-coordinate is 0. What is the x-
coordinate of this point?
45

Answers

Answer:

The x-coordinate of this point would be 6.

Step-by-step explanation:

write an equation of a vertical line that pases through the point (-4, 4)​

Answers

Answer:

x = -4

Step-by-step explanation:

Answer:

Step-by-step explanation:

In a recent survey for an upcoming city mayoral election, people were asked to name the political party they identified with and also the
the candidate they were going to vote for.
• Of the 150 people who identified themselves as Democrats, 133 said they would vote for the Democratic candidate. The rest said to
vote for the Republican.
. Of the 160 people who identified themselves as Republican, 142 said they would vote for the Republican candidate. The rest said ti
vote for the Democrat.
Complete the two-way frequency table for this situation.
B I u X
x
Font Sizes
A
А
E E 3 E3
Identify Party
Democrat Republican Total
Democratic
Voted
Republican
Total
Characters used: 89 / 15000
Submit

Answers

This question is solved using relative frequency concepts, finding the following two way frequency table, with the - separating the values:

0.4290 - 0.0540 - 0.4839

0.0581 - 0.4581 - 0.5161

0.4871 - 0.5121 - 1

-------------------------------------------------------------------------------

Relative frequency:

The relative frequency of a to b is given by a divided by b.

-------------------------------------------------------------------------------

Democratic:

Total of 150 + 160 = 310 voters.

Of the 150 Democrats, 133 voted for the Democrat and 150 - 133 = 17 voted for the Republican.

The frequencies are:

[tex]\frac{133}{310} = 0.4290, \frac{17}{310} = 0.0548[/tex]

Proportion of democratic voters is:

[tex]\frac{150}{310} = 0.4839[/tex]

Thus, the first line is: 0.4290 - 0.0540 - 0.4839

-------------------------------------------------------------------------------

Republican:

Of the 160 Republicans, 142 voted for the Republican and 160 - 142 = 18 voted for the Democrat.

The frequencies are:

[tex]\frac{18}{310} = 0.0581, \frac{142}{310} = 0.4581[/tex]

The proportion of republican voters is:

[tex]\frac{160}{310} = 0.5161[/tex]

Thus, the second line is: 0.0581 - 0.4581 - 0.5161

-------------------------------------------------------------------------------

Third line:

0.4290 + 0.0581 = 0.4871

0.0540 + 0.4581 = 0.5121

0.4839 + 0.5161 = 1

Thus, the third line is: 0.4871 - 0.5121 - 1

-------------------------------------------------------------------------------

Two-way frequency table:

The two-way frequency table is:

0.4290 - 0.0540 - 0.4839

0.0581 - 0.4581 - 0.5161

0.4871 - 0.5121 - 1

A similar question is given at: https://brainly.com/question/24337228

Answer:

Democratic 133 18 151

Republican 17 142 159

Total        150 160 310

Step-by-step explanation:

A store has x packages of 4 markers and y packages of 12 markers. The store has a total of 192 markers in
stock. If there are 21 packages of 4 markers in the store, how many packages of 12 markers are there?

Answers

Sh363gdbzej3yve truly urban urge Heydyeh hdye

what us 10 to the power of two​

Answers

the answer is

10² ( ten square )

step by step :

10² = 10 × 10

= 100

Answer: 100

Step-by-step explanation: 10*10=100

find the form of the general solution of y^(4)(x) - n^2y''(x)=g(x)

Answers

The differential equation

[tex]y^{(4)}-n^2y'' = g(x)[/tex]

has characteristic equation

r ⁴ - n ² r ² = r ² (r ² - n ²) = r ² (r - n) (r + n) = 0

with roots r = 0 (multiplicity 2), r = -1, and r = 1, so the characteristic solution is

[tex]y_c=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}[/tex]

For the non-homogeneous equation, reduce the order by substituting u(x) = y''(x), so that u''(x) is the 4th derivative of y, and

[tex]u''-n^2u = g(x)[/tex]

Solve for u by using the method of variation of parameters. Note that the characteristic equation now only admits the two exponential solutions found earlier; I denote them by u₁ and u₂. Now we look for a particular solution of the form

[tex]u_p = u_1z_1 + u_2z_2[/tex]

where

[tex]\displaystyle z_1(x) = -\int\frac{u_2(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx[/tex]

[tex]\displaystyle z_2(x) = \int\frac{u_1(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx[/tex]

where W (u₁, u₂) is the Wronskian of u₁ and u₂. We have

[tex]W(u_1(x),u_2(x)) = \begin{vmatrix}e^{-nx}&e^{nx}\\-ne^{-nx}&ne^{nx}\end{vmatrix} = 2n[/tex]

and so

[tex]\displaystyle z_1(x) = -\frac1{2n}\int e^{nx}g(x)\,\mathrm dx[/tex]

[tex]\displaystyle z_2(x) = \frac1{2n}\int e^{-nx}g(x)\,\mathrm dx[/tex]

So we have

[tex]\displaystyle u_p = -\frac1{2n}e^{-nx}\int_0^x e^{n\xi}g(\xi)\,\mathrm d\xi + \frac1{2n}e^{nx}\int_0^xe^{-n\xi}g(\xi)\,\mathrm d\xi[/tex]

and hence

[tex]u(x)=C_1e^{-nx}+C_2e^{nx}+u_p(x)[/tex]

Finally, integrate both sides twice to solve for y :

[tex]\displaystyle y(x)=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}+\int_0^x\int_0^\omega u_p(\xi)\,\mathrm d\xi\,\mathrm d\omega[/tex]

Students at a virtual school are allowed to sign up for one math class each year. The numbers of students signing up for various math classes for the next school
year are given in the following table:
Grade Geometry Algebra II Pre-Calculus AP Statistics Total
10th
150
75
25
5
255
11th
50
100
75
20
245
12th
10
50
100
65
225
Total 210
225
200
90
725
Part A: What is the probability that a student will take AP Statistics? (2 points)
Part B: What is the probability that a 12th-grader will take either Pre-Calculus or AP Statistics? (2 points)
Part C: What is the probability that a student will take Algebra II given that he or she is in the 11th grade? (2 points)
Part D: Consider the events "A student takes Algebra II and "A student is a 10th-grader. Are these events independent? Justify your answer. (4 points)

Answers

A well formatted table of the distribution is attached below :

Answer:

0.124

0.733

0.408

Step-by-step explanation:

Using the table Given :

1.) P(AP Statistics) = 90 / 725 = 0.124

2.) P(12th grade ; Precalculus or AP Statistics) = (100 + 65) / 225 = 165 /225 = 0.733

3.) P(Algebra 11 | 11th grade) = P(Algebara11 n 11th grade) / P(11th grade) = 100 / 245 = 0.408

how to solve this trig

Answers

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

[tex] \displaystyle \large{ cos \theta = - \frac{1}{2} }[/tex]

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

[tex] \displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }[/tex]

Find Q3

[tex] \displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }[/tex]

Both values are apart of the interval. Hence,

[tex] \displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }[/tex]

Second Question

Isolate sin(4 theta).

[tex] \displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }[/tex]

Rationalize the denominator.

[tex] \displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }[/tex]

The problem here is 4 beside theta. What we are going to do is to expand the interval.

[tex] \displaystyle \large{0 \leqslant \theta < 2 \pi}[/tex]

Multiply whole by 4.

[tex] \displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}[/tex]

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

[tex] \displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }[/tex]

Find Q4

[tex] \displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }[/tex]

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

[tex] \displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}[/tex]

Hence:-

For Q3

[tex] \displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }[/tex]

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

[tex] \displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }[/tex]

Therefore:-

[tex] \displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }[/tex]

Then we divide all these values by 4.

[tex] \displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }[/tex]

Let me know if you have any questions!

A manager for an insurance company believes that customers have the following preferences for life insurance products: 20% prefer Whole Life, 10% prefer Universal Life, and 70% prefer Life Annuities. The results of a survey of 200 customers were tabulated. Is it possible to refute the sales manager's claimed proportions of customers who prefer each product using the data

Answers

Answer:

Yes the sales manager claims can be refuted based on the calculated percentages

Step-by-step explanation:

From the table attached below

Total number of customers = 200

Calculated percentages

customers that prefer whole life insurance = 90 = 90/200 = 45%

customers that prefer universal life insurance = 15 = 15/200 = 7.5%

customers that prefer Annuities = 95 = 95/200 = 47.5

Expected percentages:

whole life = 20%

Universal life = 10%

Life Annuities = 70%

Round 5,821 to the nearest thousands place:

Answers

Answer:

6000 hope this helps

if the question is 5,422 then the round figure is 5000

but the question is 5,821 its above 5500 will be 6000

Solve for the value of x

Answers

Answer:

Step-by-step explanation:

This is the Law of Cosines. Use the following formula:

[tex]5.1^2=3.3^2+3.3^2-2(3.3)(3.3)cos(x)[/tex] and simplify to

26.01 = 10.89 + 10.89 - 21.78cos(x) and a bit more to

4.23 = -21.78cos(x) and finally to

-.194214876 = cos(x) and use the 2nd button along with the cos button to find that the missing angle is 101.2 degrees

Which equation results from isolating a radical term and squaring both sides of the equation for the equation
Vc-2-vc=5

Answers

Answer:

[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{c-2} - \sqrt c = 5[/tex]

Required

Isolate radical, then square both sides

We have:

[tex]\sqrt{c-2} - \sqrt c = 5[/tex]

Isolate radical

[tex]\sqrt{c - 2} = 5 + \sqrt c[/tex]

Square both sides

[tex](\sqrt{c - 2})^2 = (5 + \sqrt c)^2[/tex]

[tex]c - 2 = 25 + 2 * 5 * \sqrt c + c[/tex]

[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]

A runner’s distribution of times for running 1,000 meters has a mean of 4.5 minutes with a standard deviation of 0.75 minutes. One of the runner’s times has a z-score of –1.08. Which of the following statements is the best interpretation of this z-score?

This runner’s time was faster than the mean time by 0.75 standard deviations.
This runner’s time was faster than the mean time by 1.08 standard deviations.
This runner’s time was slower than the mean time by 0.75 standard deviations.
This runner’s time was slower than the mean time by 1.08 standard deviations.

Answers

Answer:

I believe it is (C).

This runner’s time was slower than the mean time by 0.75 standard deviations.

ED2021

Answer:

B) This runner’s time was faster than the mean time by 1.08 standard deviations.

Step-by-step explanation:

The runner is FASTER because of the negative z score

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Answers

Could u give us a picture

Which equation does the graph of the systems of equations solve?

two linear functions intersecting at 3, negative 2

−one thirdx + 3 = x − 1
one thirdx − 3 = −x + 1
−one thirdx + 3 = −x − 1
one thirdx + 3 = x − 1

Answers

Answer:

-1/3x+3 = x-1

Step-by-step explanation:

The solution is (3,-2)

Check and see if the point solves the equation

-1/3x+3 = x-1

-1/3(3) +3 = 3-1

-1+3 = 3-1

2=2 yes

Answer:

C

Step-by-step explanation:

Which figure is the pre-image? Which figure is the image after the first transformation? Which figure is the image after the second transformation?

Answers

Answer:

I believe the red one is the first image then the blue then the green because they show the prime sign

Step-by-step explanation:

At a restaurant, the bill comes to $55. You decide to leave a 12
%
tip. How much did you leave for the tip?

Answers

Answer:

$6.60

Step-by-step explanation:

12% = 0.12

12% of $55 = 0.12 x 55

=6.6

So, $6.60

PLEASEEEEEE HELPPPPPPPPP

what are the zeros for this?
f(x) = 2x^2 + 6x + 2

Answers

Answer:

-3/2 ±1/2 sqrt(5) = x

Step-by-step explanation:

f(x) = 2x^2 + 6x + 2

Set the function equal to 0

0 = 2x^2 + 6x + 2

Factor out 2

0 = 2(x^2 + 3x + 1)

Divide by 2

0 = (x^2 + 3x + 1)

Subtract 1 from each side

-1 = x^2 +3x

Complete the square by dividing the x coefficient by 2 and then squaring

(3/2)^2 = 9/4

-1 +9/4 = x^2 +3x+9/4

-4/4+9/4 = (x+3/2) ^2

5/4 = (x+3/2) ^2

Taking the square root of each side

± sqrt(5/4) = sqrt( (x+3/2) ^2)

±1/2 sqrt(5) =  (x+3/2)

Subtract 3/2 from each side

-3/2 ±1/2 sqrt(5) = x

Fill in the blank with a number to make the expression a perfect squared… W squared + 6w +

Answers

Answer:

[tex](a+b)^{2} =a^{2}+2ab+b^{2}[/tex]

[tex](1)w^{2}+2(3)(1)w+3^{2}\\\\=(w+3)^{2}\\\\=(w+3)(w+3)[/tex]

Therefore, [tex]w^{2} +6w+9[/tex] makes a perfect squared.

find the supplement of 158 degrees and 17 minutes

Answers

Answer:

supplement of 158 degree

x+158=180

x=180-158

x=22 degree.

Step-by-step explanation:

Write an expression to represent how many fourths are in 3- fourths?

Answers

Answer:

[tex]\frac{3}{4} =\frac{1}{4} (3)[/tex]

Step-by-step explanation:

like that?

Answer:

3/4

Step-by-step explanation:

Step 1:  Write an expression

A fourth is 1/4

3 fourths means 3 one forths

1/4 + 1/4 + 1/4

3/4

Answer: 3/4

What is the sum of q + r ?

Answers

Answer:

w

Step-by-step explanation:

w

Maybe you have considered buying a term life insurance policy. The expected value of any term life insurance product yields a positive expected value for the insurance company and a negative expected value for you, meaning the insurance company will make profits by selling their insurance products. Would you still buy the term life insurance? Why or why not? Are there other examples other than insurance that uses this same concept?

Answers

Answer:

Yes one should consider to buy the policy as important to have insured plan that help at the time of need.

Step-by-step explanation:

Term of life insurance is a form of life insurance which guarantees the payment of the stated death benefit. If the person des during the plan the term expires.  The policy has no value other than guarantee benefits. The term life insurance will make products by selling products and thus it's necessary to have insurance. Health, age, and life expectancy are some of the points that need to consider for buying plans.

Find the first five terms of the following sequence, starting with n=1. tn=(−1)n+1(n2−9) Give your answer as a list, separated by commas. For example, if tn=n, you would give your answer as 1,2,3,4,5.

Answers

Answer:

-8, 5 , 0 , -7 , 16

Step-by-step explanation:

Given

[tex]t_n = (-1)^{n+1}(n^2 - 9)[/tex]

Required

The first five terms

When [tex]n = 1[/tex]

[tex]t_1 = (-1)^{1+1}(1^2 - 9)[/tex]

[tex]t_1 = (-1)^{2}(1 - 9)[/tex]

[tex]t_1 = -8[/tex]

When [tex]n =2[/tex]

[tex]t_2 = (-1)^{2+1}(2^2 - 9)[/tex]

[tex]t_2 = (-1)^3 * (4 - 9)[/tex]

[tex]t_2 = 5[/tex]

[tex]t_3 = (-1)^{3+1}(3^2 - 9)[/tex]

[tex]t_3 = (-1)^{4}(9 - 9)[/tex]

[tex]t_3 = 0[/tex]

[tex]t_4 = (-1)^{4+1}(4^2 - 9)[/tex]

[tex]t_4 = (-1)^5(16 - 9)[/tex]

[tex]t_4 = -7[/tex]

[tex]t_5 = (-1)^{5+1}(5^2 - 9)[/tex]

[tex]t_5 = (-1)^{6}(25 - 9)[/tex]

[tex]t_5 = 16[/tex]

So, the first five terms are: -8, 5 , 0 , -7 , 16

The least-squares regression equation
y = 968 – 3.34x can be used to predict the amount of monthly interest paid on a loan after x months. Suppose the amount of monthly interest after 30 months was $865.93.

What is the residual for the amount of monthly interest paid on a loan after 30 months?

–202.27
–1.87
1.87
202.27

Answers

Answer:

-1.87 (B)

865.93 - [968-3.34(30)] = -1.87

ED2021

What is the smallest three-digit odd numb
that can be made from 2, 8,5, 1, 3?

Answers

Answer: 101

Step-by-step explanation:

.

Which of the following rational functions is graphed below?
10
- 10
10
tho
A. F(x) =
3
X-7
B. F(x) = x + 3
X-7
C. F(x) =
(x+3)(x-7)
(x+3)(x-7)
D. F(X)
1
(x + 7(x-3)
7\x-
Check the picture out and please help me lol

Answers

Vertical asymptote:

A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;

In a graphic, these vertical asymptotes are given by dashed vertical lines.

An example is a value of x for which the denominator of the function is 0.

In this graphic:

Dashed vertical lines at: [tex]x = -3, x = 7[/tex], thus, for [tex]x - (-3) = x+3[/tex] and [tex]x - 7[/tex] the denominator is zero.

Thus, the function graphed is:

[tex]F(x) = \frac{1}{(x+3)(x-7)}[/tex]

And the correct answer is given by option C.

To take a look at a problem with asymptote, you can check this item https://brainly.com/question/4084552.

The graph is for the rational function f(x) = 1/(x + 3)(x - 7).

Option C is the correct answer.

We have,

To understand the graph of the function f(x) = 1/((x + 3)(x - 7)).

Vertical Asymptotes:

The function has vertical asymptotes at the values of x for which the denominator becomes zero.

The denominator is (x + 3)(x - 7), so the vertical asymptotes occur at

x = -3 and x = 7.

Horizontal Asymptote:

The highest power of x in the denominator is x², and there is no x² term in the numerator, the function approaches 0 as x goes to positive or negative infinity.

The horizontal asymptote is y = 0.

x-Intercept:

To find the x-intercept, we set y = 0 and solve for x:

0 = 1/((x + 3)(x - 7))

Since the numerator can never be zero, the only way the fraction can be zero is if the denominator is zero:

(x + 3)(x - 7) = 0

Solving for x:

x + 3 = 0

x = -3

x - 7 = 0

x = 7

So, the x-intercepts are (-3, 0) and (7, 0).

y-Intercept:

To find the y-intercept, we set x = 0:

f(0) = 1/((0 + 3)(0 - 7)) = 1/(-3 * -7) = 1/21

The y-intercept is (0, 1/21).

Thus,

The graph is for the rational function f(x) = 1/(x + 3)(x - 7).

Learn more about functions here:

https://brainly.com/question/28533782

#SPJ6

2/5 + 1/10= In simplest form
A. 3/15
B. 5/10
C. 1/4
D. 1/2

Answers

Answer:

1/2

Step-by-step explanation:

2/5 + 1/10

Get a common denominator of 10

2/5 * 2/2 + 1/10

4/10 + 1/10

5/10

simplify

Divide the top and bottom by 5

1/2

Answer:

[tex] \frac{1}{2} [/tex]

Answer D is correct

Step-by-step explanation:

[tex] \frac{2}{5} + \frac{1}{10} \\ \frac{2 \times 2}{5 \times 2} + \frac{1}{10} \\ \frac{4}{10} + \frac{1}{10} \\ \frac{5}{10} \\ \frac{5 \div 5}{10 \div 5} \\ = \frac{1}{2} [/tex]

Other Questions
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