state and explain five practical applications or uses of eddy current in everyday activities​

Answers

Answer 1

Answer:

They are applied in electromagnetic braking.Used in separation of metals such as Aluminum from other metals.Used in identifying metals in vending machines.Testing of structure of aircrafts apply eddy currents through procedures of Non destructive examination.They are used in defect detecting and safety hazards application.

Explanation:

Eddy current are loops of electric currents which are induced within conductors when there is a change in magnetic field in the conductor through Faraday's Law of induction.

They are applied in electromagnetic braking. This is where the eddy current acts as brakes to stop moving objects. However, they are used along side mechanical braking systems.

Used in separation of metals such as Aluminum from other metals. Using the eddy current separator, ferrous elements are attracted to the magnet while aluminum being non-ferrous ,is left  separated.

Used in identifying metals in vending machines. These machines use eddy currents to detect fake coins where the fake coins will slow at a certain speed to be identified.

Testing of structure of aircrafts apply eddy currents through procedures of Non destructive examination.

They are used in defect detecting and safety hazards application. Defects in heat exchanger tubes can be detected by eddy currents.


Related Questions

What allows a star to remain in stellar equilibrium?

Answers

Explanation:

A star is in equilibrium when the pressures inside the star balance out the force of gravity. The pressure is thermal pressure resulting from the fusion reactions taking place in the star's core. A star stays in equilibrium until the supply of hydrogen in the core is depleted.

In a stable star, the gas pressure pushing out from the center is equal with the gravity pulling atoms inward to the center – when these forces are equal, the star is at equilibrium. Once a star reaches equilibrium for the first time, it will start burning (fusing) hydrogen into helium.

Answer: It has enough mass to resist expansion.

A woman, driving a golf ball off of the tree, gives the ball a speed of 20.0m/s. The mass of the ball is 45g and the duration of the impact with the golf club is 6.0x10^3
a) What is the change in the momentum of the ball?
b) Determine the average force applied by the club.

Answers

Answer:

See the answers below.

Explanation:

a)

The change in momentum can be calculated by means of the following equation.

[tex]P=m*v[/tex]

where:

P = momentum [kg*m/s]

m = mass = 45 [g] = 0.045 [kg]

v = velocity = 20 [m/s]

[tex]P=20*0.045\\P=0.9[kg*m/s][/tex]

b)

The change in momentum can also be calculated by means of the product of force by the duration time of the impact.

[tex]F*t=P\\F*0.006=0.9\\F=0.9/0.006\\F =150 [N][/tex]

What is actually responsible for the "sensation of force" that causes concussions for many professional football

players?

Answers

Answer:

Acceleration.

Explanation:

American football is one of the sports with the highest physical contact, along with boxing, mixed martial arts and rugby. Therefore, the risk of injury for players who play the sport is higher. However, many injuries in this sport have to do with blows to the head, where concussions occur that generate small neuronal short circuits due to the impact, which can cause fainting, amnesia and even vomiting.

This type of injury occurs due to the acceleration of the players when impacting their rival, which increases their strength (since it is known that the greater the acceleration the weight acquires a greater impact force).

Answer:

Acceleration causes the force of concussions for many professional football players.

sum it up a cornell doodle notes

Answers

I do not understand?

Consider a neutron star with a mass equal to the sun, a radius of 10 kmkm, and a rotation period of 1.0 ss. What is the speed of a point on the equator of the star

Answers

Answer:

6.28 * 10⁴ m/s

Explanation:

Using the relation :

Given :

Radius, R = 10km

Period, T = 1.0 s

v = (2πR) / T

Where v = velocity of a point

R in meters ;

1km = 1000m = 10³m

10km = 10 * 10³m = 1 * 10^4 m

v = (2π*10^4m) / 1 s

v = 6.2831853 * 10⁴ m/s

v = 6.28 * 10⁴ m/s

g While driving down a highway, the air flow over an automobile establishes an overall heat transfer coefficient of 18 W/m2K. The passenger cabin of this automobile exposes 9 m2 of surface to the moving ambient air. One day when the ambient temperature is 33oC, how much cooling must the air conditioning system supply to maintain a temperature of 20oC in the passenger cabin

Answers

Answer:

2106 W

Explanation:

Given that

The coefficient of heat transfer, h = W/m².K

Area of cabin exposed to air, A = 9 m²

Initial ambient temperature, T1 = 33 °C

Final system temperature, T2 = 20 °C

To find the cooling rate needed, we use the formula

Q = h * A * ΔT

where, ΔT = T1 - T2

ΔT = 33 - 20

ΔT = 13 °C

Cooling rate, Q = 18 * 9 * 13

Cooling rate, Q = 2106 W

This means that the cooling rate needed is 2106 W

PLEASE HELP!! URGENT!!

Answers

Answer:

1. Gravity

2. Increases

Explanation:

Gravity is the force that attracts all objects toward each other. This is the force that keeps us grounded on Earth instead of floating in the air.

Although people have gravitational forces, the attraction force is a negligible amount. However, as the mass of the objects are increased, they will exert  far greater gravitational powers to other objects or individuals such as humans.  

For this question you will be designing an investigation Carefully read the information below and respond to the prompt
Does the temperature of a liquid affect the amount of sugar it will dissolve? In other words, if you change the temperature of a liquid, is there a
relationship between the temperature and how much sugar can dissolve at that specific temperature?
Tell how you would test this question, being as scientific as possible (including the different variables, constants, hypothesis, safety considerations, data
tables, etc.) when you write about your test. Write down the steps you would take to find out if the temperature of a liquid affects the amount of sugar it
can dissolve

Answers

Answer:

See Explanation

Explanation:

Temperature affects the amount of sugar that will be dissolved in a liquid. It is general knowledge in chemistry that solutes tend to dissolve in hot solvents compared to cold solvents.

Hence, there is a positive relationship between dissolution of sugar in a liquid and increase in temperature.

To test this hypothesis, the variables are temperature and amount of solute. The volume of solvent and type of solvent must be held constant.

Different amounts of solute are dissolved in the same volume of solvent and heated to a constant temperature and the extent of dissolution of the sugar is observed for each experimental unit.

A control experiment is also set up in which different amount of sugar is dissolved in the same volume of solvent as above without heating and the results are compared.

If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle

Answers

This question is incomplete, the complete question is;

The electric force due to a uniform external electric field causes a torque of magnitude 20.0 × 10⁻⁹ N⋅m on an electric dipole oriented at 30° from the direction of the external field. The dipole moment of the dipole is 7.5 × 10⁻¹² C⋅m.

What is the magnitude of the external electric field?

If the two particles that make up the dipole are 2.5 mm apart, what is the magnitude of the charge on each particle?

Answer:

- the magnitude of the external electric field is 5333.3 N/C

- the magnitude of the charge on each particle is 3.0 × 10⁻¹² C  ≈ 3 nC

Explanation:

Given that;

Torque = 20.0 × 10⁻⁹ N⋅m

dipole moment = 7.5 × 10⁻¹²

∅ = 30°

The moment T of restoring couple is;

T = PEsin∅

E = T/Psin∅

we substitute

E = 20.0 × 10⁻⁹ N⋅m / (7.5 × 10⁻¹²) sin(30°)

E = 20.0 × 10⁻⁹ / 3.75 × 10⁻¹²

E =  5333.3 N/C

Therefore, the magnitude of the external electric field is 5333.3 N/C

The dipole moment is given by the expression;

p = ql

q = p / l

given that l = 2.5 mm = 0.0025 m

we substitute

q = 7.5 × 10⁻¹² / 0.0025

q = 3.0 × 10⁻¹² C ≈ 3 nC

Therefore, the magnitude of the charge on each particle is 3.0 × 10⁻¹² C ≈ 3 nC

If a man weighs 720 N on the Earth, what would he weigh on Jupiter, where the free-fall acceleration is 25.9 m/s2

Answers

Answer:

On Jupiter, the man would weigh  1.903 kN

Explanation:

Given that;

a mans weight is 720 N

on earth, g = 9.8 m/s²

so mass on earth will be;

m = F/g = 720 / 9.8 = 73.4693 kg

In Jupiter, g = 25.9 m/s²

so the man's weight in Jupiter will be;

F = mg

F = 73.4693 × 25.9

F = 1902.8549

F = 1.903 kN

Therefore, on Jupiter, the man would weigh  1.903 kN

Now that you have one of the two variables in Part D, use substitution to solve for the two variables. You may want to review the

Answers

Answer: in cases neither of two equations in the system will contain a variable.

Explanation:

A drone is flying horizontally when it runs out of power and begins to free fall from 16 m. No drag. If it lands 40 m away (in the x-direction) from where it began to fall, what was its horizontal velocity while it was falling

Answers

Answer:

the horizontal velocity while it was falling is 22.1 m/s.

Explanation:

Given;

height of fall, h = 16 m

horizontal distance, x = 40 m

The time to travel 16 m is calculated as;

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 16}{9.8} } \\\\t = 1.81 \ s[/tex]

The horizontal velocity is calculated as;

[tex]v_x = \frac{X}{t} \\\\v_x = \frac{40}{1.81} \\\\v_x = 22.1 \ m/s[/tex]

Therefore, the horizontal velocity while it was falling is 22.1 m/s.

The horizontal velocity while it was falling is

[tex]22.1m/s[/tex]

What is horizontal velocity?

Horizontal velocity becomes important for objects moving in a horizontal direction. Generally, horizontal velocity is horizontal displacement divided by time, such as mph or m/s.

Therefore, from equation of motion

[tex]Time, t = \sqrt\frac{2h}{g}\\\\t = \sqrt\frac{2*16}{9.8}\\\\t = 1.81sec[/tex]

Therefore, the horizontal velocity, [tex]V_h[/tex]

[tex]V_h = \frac{x}{t}\\\\V_h = \frac{40}{1.81}\\\\V_h = 22.09 or 22.1m/s[/tex]

For more information on horizontal velocity, visit

https://brainly.com/question/24681896

Fern life begins as _____.

a spore
a sperm
an egg

Answers

Fern life begins as a sperm

What happens to the resistance of a wire as it gets wider

Answers

Answer:

it snaps

Explanation:

the more force you put on it, the wired out it gets than it snaps. I think

PLEASE HELP!! what is newton’s second law?

Answers

Newton's second law - the law of acceleration (acceleration = force/mass). Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.

A car, travelling at constant speed on a straight, level road, accelerates so that its speed is now doubled. By what factor will the car's kinetic energy change? Explain by using physics

principles

Answers

Answer:

We know that, the kinetic energy

ke=  \frac{1 }{2} m{v}^{2}  

and we also know that the acceleration causes the speed's value to be doubled

Hence, v becomes 2v

When 2v is squared, it becomes 4v^2. After substituting this value in the equation above and comparing it,

We can conclude that the Kinetic Energy has increased

by a factor of 4

Daisy walks across a force platform and the forces exerted by her foot during a step are recorded. The peak vertical reaction force is 1200 N (this force acts upward on Daisy). At the same instant, the braking frictional force is 200 N (this force acts backward on Daisy). How large is the resultant of these two forces? What is the direction of the resultant force?

Answers

Answer:

The direction of the resultant force is approximately 189.462º.

The magnitude of the resultant force is approximately 1216.553 newtons.

Explanation:

Let consider postive the direction of motion of Daisy's foot and the upward direction (perpendicular to direction of motion). Friction ([tex]f[/tex]), measured in newtons, is directed against motion, whereas normal force from ground to the foot ([tex]N[/tex]), measured in newtons, is in the upward direction. Then, resulting direction must be greater than 180º but less than 270º with respect to the axis of the direction of motion, which is found by the following formula:

[tex]\theta = 270^{\circ}-\tan^{-1} \frac{N}{f}[/tex] (1)

Where [tex]\theta[/tex] is the direction of the resultant force, measured in sexagesimal degrees.

If we know that [tex]N = 1200\,N[/tex] and [tex]f = 200\,N[/tex], then the direction of the resultant force is:

[tex]\theta = 270^{\circ}-\tan^{-1} \frac{1200\,N}{200\,N}[/tex]

[tex]\theta \approx 189.462^{\circ}[/tex]

The direction of the resultant force is approximately 189.462º.

The magnitude of the resultant force ([tex]F[/tex]), measured in newtons, is determined by Pythagorean Theorem:

[tex]F = \sqrt{f^{2}+N^{2}}[/tex]

[tex]F =\sqrt{(200\,N)^{2}+(1200\,N)^{2}}[/tex]

[tex]F \approx 1216.553\,N[/tex]

The magnitude of the resultant force is approximately 1216.553 newtons.

A gorilla drags a log across the jungle floor. The log begins at rest and accelerates at until the gorilla is moving at a fast lope. The coefficient of kinetic friction between the log and the mud and plants of the jungle is . Assume that friction and the gorillas pulling force remain constant the whole time. What frictional force acts on the log

Answers

Answer:

  fr = 245 N,  T = fr

Explanation:

We can solve this exercise using the equilibrium conditions, let's start by creating a reference system

where we call T the drag force of the gorilla, m the mass of the trunk and μ the coefficient of kinetic friction

Y axis  

           N- W =

           N = W = mg

X axis

          T - fr = 0

          T = fr

the expression for the friction force is

          fr = μ N

          fr = μ mg

we substitute

           T = μ m g

When analyzing these expressions we see that when the trunk reaches the maximum speed that the gorilla carries, the friction force is equal to the gorilla's tension

            fr = T

for a specific calculation we must assign values ​​to:

      μ = 0.25

      m = 100 kg

let's calculate

         T = 0.25 100 9.8

         T = 245 N

therefore for this case

         fr = 245 N

What three statements are true about the wave shown?

Answers

The answer would be A

Describe the way the light travels when you see a car behind you in the rear view mirror

Answers

Answer:

Described below

Explanation:

When you see a car behind you in the rear view mirror, it means that light rays travelling from the right hand side of the car driver behind are being reflected by the mirror to get to your eyes on the right side of the light rays from the drivers left hand side.

One limitation about science is that he cannot answer questions about

A. Ancient geography
B. Planets outside the solar system
C. Value
D. Black holes

Answers

Answer:

C. Value

Explanation:

Science is the study of natural and observable measurable phenomenon based on evidence.

Science is not able to answer questions related to value because they are not based on on evidence or facts. Questions related to value can not be answered through scientific investigation.

Hence, the correct answer is "C. Value".

(1) Assume that the lights in your kitchen use 300 watts. How much energy (in kWh) does it use and how much does it cost to leave the lights on 24 hours a day for one year if electricity is 12cents/kilowatt hour

Answers

Answer:

the cost to leave the lights on 24 hours a day for one year is 31,536 cents or 315.36 dollars

Explanation:

Given that;

P = 300 watts = 300/1000 = 0.3

t = 24hrs a day

In a calendar year, we have 365 days

so;

E = 0.3 × 365 × 24

E = 2628 KWh

given that;  1 KWh = 12 cent

then 2628  KWh is x

x = 2628 × 12

x = 31,536 cents or 315.36 dollars

Therefore, the cost to leave the lights on 24 hours a day for one year is 31,536 cents or 315.36 dollars

Which two mixtures are homogeneous?

D A. Gasoline

B. Apple juice

C. Pie crust

D. Cereal in milk

Answers

Answer:

A. Gasoline

B. Apple juice

Explanation:

A homogeneous mixture can be defined as any liquid, solid or gaseous mixture which has an identical or uniform composition and properties throughout any given sample of the mixture. In Chemistry, all solutions are considered to be a homogeneous mixture.

For instance, aqueous hydrogen chloride, HCl(aq) is a homogeneous mixture. The aqueous hydrogen chloride is a homogeneous mixture of water and hydrogen chloride. This ultimately implies that, aqueous hydrogen chloride HCl(aq) is a solution of hydrogen chloride in water and it is commonly referred to as Hydrochloric acid.

Hence, the two mixtures that are homogeneous are gasoline and apple juice.

Answer:

A. Gasoline

B. Apple juice

A homogeneous mixture is a mixture in which the composition is uniform throughout the mixture. The salt water described above is homogeneous because the dissolved salt is evenly distributed throughout the entire salt water sample. Often it is easy to confuse a homogeneous mixture with a pure substance because they are both uniform.  The difference is that the composition of the substance is always the same. The amount of salt in the salt water can vary from one sample to another. All solutions would be considered homogeneous because the dissolved material is present in the same amount throughout the solution.

One characteristic of mixtures is that they can be separated into their components. Since each part of the mixture has not reacted with another part of the mixture, the identities of the different materials is unchanged.

Hence, the two mixtures that are homogeneous are gasoline and apple juice

Explanation:

A soccer player is running to the right at 3.2m/s when a 0.50kg ball travelling at 5.0 m/s to the left collides their 5.0kg head. If the player's head velocity after the collision is 2.5 m/s to the right, what is the new velocity of the ball?

Answers

Answer:

300 m/s

Explanation:

Step one:

Given data

Mass of players head m1= 5kg

The initial velocity of players head u1= 3.2m/s

mass of ball m2= 0.5kg

Initial velocity of ball= 5 m/s

Final velocity of player= 2.5 m/s

Required

The velocity of the ball after collision

Step two:

Applying the conservation of momentum formula for elastic collision

m1u1+m2u2= m1v1+m2v2

substitute

5*32+0.5*5= 5*2.5+0.5*v2

160+2.5= 12.5+0.5v2

collect like terms

162.5-12.5= 0.5v2

150= 0.5v2

divide both sides by 0.5

v2= 150/0.5

v2=300 m/s

The new velocity of the ball is 300 m/s

15 POINTS PLZ HELP IM ON A TIMER! IM ON EDGE EXAM

Which describes pressure during a volcanic eruption?
Pressure increases as magma rises.
Pressure traps dissolved gases in magma.
Pressure increases until the volcano explodes.
Pressure from rocks above causes new rocks to form.

Answers

Answer:

B.) Pressure traps dissolved gases in magma

Explanation:

I hope this answer is correct

Answer:

B

Explanation:

Maria began riding her bike, from rest, at 6 m/s. If she traveled 500 m, how
long was she riding?

Answers

Answer:

she rode for 166.66 seconds , which is about 2 minutes and 47 seconds

Explanation:

We use the kinematic equation that relates initial and final velocities with time and distance travelled that is shown below:

[tex]distance=\frac{(v_i+v_f)*t}{2}[/tex]

which in our case gives:

[tex]distance=\frac{(v_i+v_f)*t}{2}\\500=\frac{(0+6)*t}{2}\\500=3*t\\t=\frac{500}{3} \,s\\t\approx 166.66\,sec[/tex]

which reduced to minutes gives 2 minutes and approximately 47 seconds

a wye-connected load has a voltage of 480v applied to it. What is the voltage drop across each phase

Answers

Answer:

[tex]Y_A=277.128 \angle 30v[/tex]

[tex]Y_B=277.128 \angle (-150)v[/tex]

[tex]Y_C=277.128 \angle (90)v[/tex]

Explanation:

From the question we are told that

Voltage [tex]V_L_L =480v[/tex]

Generally in a case of Y_connection [tex]V_p_ h[/tex] is mathematical represented as

[tex]V_p_h=\frac{V_l_l}{\sqrt{3}} \angle (\phi-30)v[/tex]

Generally voltage drop across phase A

[tex]Y_A=\frac{408}{\sqrt{3}} \angle -(0-30)[/tex]

[tex]Y_A=277.128 \angle 30v[/tex]

Generally voltage drop across phase B

[tex]Y_B=277.128 \angle (-30-120)[/tex]

[tex]Y_B=277.128 \angle (-150)v[/tex]

Generally voltage drop across phase C

[tex]Y_C=277.128 \angle (-30+120)[/tex]

[tex]Y_C=277.128 \angle (90)v[/tex]

A person on a bridge 25m above the water throws a rock straight downwards at 20m/s.
a. How long does it take to hit the water?
B how fast is it going when it hits?

Answers

Answer:

a) Δd=v₂Δt+[tex]\frac {1}{2}[/tex]aΔt²

v₂=0 (hits ground)

Δd=[tex]\frac {1}{2}[/tex]aΔt²

Δt²=Δd÷[tex]\frac {1}{2}[/tex]a

t=√25÷[tex]\frac {1}{2}[/tex](9.8)  9.8m/s²=gravity

t=5÷4.8

t=1.04s

b) a=[tex]\frac{v_2-v_{1} }{t}[/tex]

a×t=v₂-v₁

v₂=(a×t)+v₁

v₂=(9.8×1.04)+20

v₂=10.192 + 20

v₂=30.192

v₂=30.2m/s rounded

A 0.049 kg bullet moving at 421 m/s strikes a stationary 4.7 kg wooden block. The bullet passes through the block and leaves with a velocity of 301 m/s. If the block was originally at rest, how fast does it move after being hit by the bullet? ANSWER ASAP

Answers

Answer:

The block moves at 1.25 m/s

Explanation:

Law Of Conservation Of Linear Momentum

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of two bodies, then the total momentum is the sum of the individual momentums:

[tex]P=m_1v_1+m_2v_2[/tex]

If a collision occurs and the velocities change to v', the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2[/tex]

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

The bullet of m1=0.049 kg moves at v1=421 m/s. Then it strikes a wooden block of m2=4.7 kg originally at rest (v2=0).

After the collision, the bullet continues at v1'=301 m/s. The speed of the block can be calculated by solving for v2':

[tex]\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}[/tex]

[tex]\displaystyle v'_2=\frac{0.049*421+0-0.049*301}{4.7}[/tex]

Calculating:

[tex]\displaystyle v'_2=\frac{5.88}{4.7}=1.25\ m/s[/tex]

The block moves at 1.25 m/s

explain the process of
anomalous expansion of water​

Answers

The anomalous expansion of water refers to the fact that water, unlike most substances, expands when it freezes. The density of water increases as temperature decreases but reaches a maximum at 4° C then begins to expand.

When liquid water is cooled, it contracts like one would expect until a temperature of approximately 4 degrees Celsius is reached. After that, it expands slightly until it reaches the freezing point, and then when it freezes it expands by approximately 9%.

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