State the postulate or theorem you would use to prove each pair of triangles congruent.
a) SSS
b) SAS
c) ASA
d) AAS
e) HL
f) Not possible

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Answer:

  see attached

Step-by-step explanation:

The imaginary value is plotted on the vertical axis in the same way that the y-coordinate would be for an ordered pair (x, y). Similarly, the real value is plotted on the horizontal axis.

__

I find it helpful to think of the complex number a+bi as equivalent to the ordered pair (x, y) = (a, b) when it comes to graphing.

Answer:

Hi there! The answers will be in the explanation :D

Step-by-step explanation:

a) I'll attach a doc for the table so it'll basically answer a and b.

c) I'll also attach the graph.

d) I'm not entirely sure for this question, but I'll do my best to answer it correctly for you. I would say no, because we can see that the residuals are all positive, but the graph we're looking is going down which means it's negative. We can also see the table is increasing a bit so it doesn't really make any sense...

Hope this helped you!

9514 1404 393

Answer:

  4√2

Step-by-step explanation:

In a 30°-60°-90° triangle, the ratio of side lengths is ...

  1 : √3 : 2

That is, the hypotenuse (c) is double the short side (2√2).

  c = 4√2

Answer:

f(7)=109

Step-by-step explanation:

Since f(a)=7 then you just imput 7 on each x like this f(7)=8+13(7)+10= 109

Answer:

-3/5

Step-by-step explanation:

3/ -5 is also equal to -3/5  or - (3/5)

Answer:

X = 64

Step-by-step explanation:

All of the angles are right angles (because of the square at one of the angles shown above). This means each angle equals 90 degrees. If X + 26 = 90, then X = 64 because 90 - 26 = 64. I hope this helps!

Answer: X = 64

Step-by-step explanation:

Answer:

a) 0.0081 = 0.81% probability that he receives no job offer

b) He expects to get 2.8 job offers.

c) 0.0837 = 8.37% probability that more than half of the firms he applied do not make him any offer.

d) Each job must be independent of other jobs. Additionaly, if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal approximation to the binomial distribution can be used.

e) 0.2401 = 24.01% probability of him securing more than 3 offers.

Step-by-step explanation:

For each application, there are only two possible outcomes. Either he gets an offer, or he does not. The probability of getting an offer for a job is independent of any other job, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

He can expect to receive a job offer from 70% of the firms to which he applies.

This means that [tex]p = 0.7[/tex]

The student decides to apply to only four firms.

This means that [tex]n = 4[/tex]

(a) What is the probability that he receives no job offer?

This is [tex]P(X = 0)[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{4,0}.(0.7)^{0}.(0.3)^{4} = 0.0081[/tex]

0.0081 = 0.81% probability that he receives no job offer.

(b) How many job offers he expects to get?

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

In this question:

[tex]E(X) = 4(0.7) = 2.8[/tex]

He expects to get 2.8 job offers.

(c) What is the probability that more than half of the firms he applied do not make him any offer?

Less than 2 offers, which is:

[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{4,0}.(0.7)^{0}.(0.3)^{4} = 0.0081[/tex]

[tex]P(X = 1) = C_{4,1}.(0.7)^{1}.(0.3)^{3} = 0.0756[/tex]

Then

[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.0081 + 0.0756 = 0.0837[/tex]

0.0837 = 8.37% probability that more than half of the firms he applied do not make him any offer.

(d) What assumptions do you need to make to find the probabilities? To increase the chance of securing more job offers, the student decides to apply to as many companies as possible, he sent out 60 applications to all different accounting firms.

Each job must be independent of other jobs. Additionaly, if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal approximation to the binomial distribution can be used.

(e) What is the probability of him securing more than 3 offers?

Between 4 and n, since n is 4, 4 offers, so:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{4,4}.(0.7)^{4}.(0.3)^{0} = 0.2401[/tex]

0.2401 = 24.01% probability of him securing more than 3 offers.

First integrate the indefinite integral,

[tex]\int(1-x^2)^{3/2}dx[/tex]

Let [tex]x=\sin(u)[/tex] which will make [tex]dx=\cos(u)du[/tex].

Then

[tex](1-x^2)^{3/2}=(1-\sin^2(u))^{3/2}=\cos^3(u)[/tex] which makes [tex]u=\arcsin(x)[/tex] and our integral is reshaped,

[tex]\int\cos^4(u)du[/tex]

Use reduction formula,

[tex]\int\cos^m(u)du=\frac{1}{m}\sin(u)\cos^{m-1}(u)+\frac{m-1}{m}\int\cos^{m-2}(u)du[/tex]

to get,

[tex]\int\cos^4(u)du=\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{4}\int\cos^2(u)du[/tex]

Notice that,

[tex]\cos^2(u)=\frac{1}{2}(\cos(2u)+1)[/tex]

Then integrate the obtained sum,

[tex]\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int\cos(2u)du+\frac{3}{8}\int1du[/tex]

Now introduce [tex]s=2u\implies ds=2du[/tex] and substitute and integrate to get,

[tex]\frac{3\sin(s)}{16}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int1du[/tex]

[tex]\frac{3\sin(s)}{16}+\frac{3u}{4}+\frac{1}{4}\sin(u)\cos^3(u)+C[/tex]

Substitute 2u back for s,

[tex]\frac{3u}{8}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\sin(u)\cos(u)+C[/tex]

Substitute [tex]\sin^{-1}[/tex] for u and simplify with [tex]\cos(\arcsin(x))=\sqrt{1-x^2}[/tex] to get the result,

[tex]\boxed{\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C}[/tex]

Let [tex]F(x)=\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C[/tex]

Apply definite integral evaluation from b to a, [tex]F(x)\Big|_b^a[/tex],

[tex]F(x)\Big|_b^a=F(a)-F(b)=\boxed{\frac{1}{8}(a\sqrt{1-a^2}(5-2a^2)+3\arcsin(a))-\frac{1}{8}(b\sqrt{1-b^2}(5-2b^2)+3\arcsin(b))}[/tex]

Hope this helps :)

Answer:[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]General Formulas and Concepts:

Pre-Calculus

Calculus

Differentiation

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                    [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

U-Substitution

Reduction Formula:                                                                                               [tex]\displaystyle \int {cos^n(x)} \, dx = \frac{n - 1}{n}\int {cos^{n - 2}(x)} \, dx + \frac{cos^{n - 1}(x)sin(x)}{n}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx[/tex]

Step 2: Integrate Pt. 1

Identify variables for u-substitution (trigonometric substitution).

Step 3: Integrate Pt. 2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Answer:

Exact Form: -4⊥√15

Decimal Form:

0.12701665

7.87298334

…

Answer:

a. x = 3/a

Step-by-step explanation:

Add all like terms on left hand side of the equation:

5 ax + 3 ax => 8 ax

Bring like term 4ax on left hand side

8ax - 4ax

=> 4ax

Therefore we get 4ax = 12

ax = 12/4

ax = 3

x = 3/a

Answer:

$3.90

Step-by-step explanation:

136.44/35= (rounded tot the nearest hundredth) $3.90

Answer:

136.44÷36 =3.79

3.79×36=136.44

Step-by-step explanation:

So one ball cost 3. 79

Answer: [tex]-\frac{9}{2}, -4, -3, -\frac{11}{4}, -2[/tex]

Step-by-step explanation:

slope = m

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-7-9}{-1-(-5)}=-4[/tex]

y = mx + b, (-5,9), (-1,-7), m = -4; (does not matter which point you plug in)

[tex]y=mx+b\\9=-4(-5)+b\\9=20+b\\b=-11\\y=-4x-11[/tex]

(now plug in each y value into the equation above)

[tex]7=-4x-11\\18=-4x\\x=-\frac{9}{2}\\\\5=-4x-11\\16=-4x\\x=-4\\\\1=-4x-11\\12=-4x\\x=-3\\\\0=-4x-11\\11=-4x\\x=-\frac{11}{4} \\\\-3=-4x-11\\8=-4x\\x=-2[/tex]

Answer:

With an ageing population, dietary approaches to promote health and independence later in life are needed. In part, this can be achieved by maintaining muscle mass and strength as people age. New evidence suggests that current dietary recommendations for protein intake may be insufficient to achieve this goal and that individuals might benefit by increasing their intake and frequency of consumption of high-quality protein. However, the environmental effects of increasing animal-protein production are a concern, and alternative, more sustainable protein sources should be considered. Protein is known to be more satiating than other macronutrients, and it is unclear whether diets high in plant proteins affect the appetite of older adults as they should be recommended for individuals at risk of malnutrition. The review considers the protein needs of an ageing population (>40 years old), sustainable protein sources, appetite-related implications of diets high in plant proteins, and related areas for future research.

Answer:

(-2,0)

Step-by-step explanation:

The x intercept is the value when it crosses the x axis ( the y value is zero)

x = -2 and y =0

(-2,0)

Answer:

Step-by-step explanation:

x = 0, 1/5

Answer:

Ask in English then I can help u

Answer:

A

Step-by-step explanation:

v=πr2h

r=(3)²* 5

45π unit³

Let the numbers are x and y

According to the question

⇒x+y=1000.....eq1⇒x 2 −y 2

=256000∵x 2 −y 2

=(x+y)(x−y)

⇒1000∗(x−y)=256000

⇒x−y=256.....eq2

Adding eq1 and eq2

⇒2x=1256⇒x=628

Put the value of x in eq1

⇒628+y=1000⇒y=372

The numbers are 628 and 372

Hi I'm From PHILIPPINES

I'm here to help USA users like you

Answer:

x = 2[tex]\sqrt{5}[/tex]

Step-by-step explanation:

Pytago:

[tex]2^2 + 4^2 = x^2\\x = \sqrt{2^2 + 4^2} \\x = 2\sqrt{5}[/tex]

Answer:

4.47

Step-by-step explanation:

x²= 2² + 4²

x² = 4 + 16

x²= 20

x = √20

x= 4.47

Answer:

y = -1/2x -7

Step-by-step explanation:

3x + 6y = -42

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

Subtract 3x from each side

3x-3x+6y = -3x-42

6y = -3x-42

Divide each side by 6

6y/6 = -3x/6 - 42/6

y = -1/2x -7

Answer:

Part A:

the first step is to work out the brackets by multiplying the coefficients outside the brackets by everything in the brackets.

Part B:

5(3x-4)=-2(6x-9)

15x-20=-12x+18

Part C:

15x-20=-12x+18

15x+12x=18+20

27x/27=38/27

x=1.407

I hope this helps

Answer:

17x^2-9x-9 -->B

Step-by-step explanation:

7x^2 -12x +3 +10x^2+3x-12

Answer:

A. 22

B. 8

C. 23 + 24

D. 22 + 23 + 24

E. 8 + 8 + 10

F. 104 - (sum of all the given numbers) = 3

9514 1404 393

Answer:

  undefined

Step-by-step explanation:

A rational expression is undefined when its denominator is zero.

Answer:

C. The volume of the square prism is equal to the volume of the cylinder.

Step-by-step explanation:

I took the test and it was right

Answer:

-19/50

Step-by-step explanation:

Answer:

-19/50

Step-by-step explanation:

Answer:

10.97%

Step-by-step explanation:

There are 52 cards.

13 of them, are hearts.

Then

52 - 13 = 39 cards are not hearts.

4 cards are drawn, we want to find the percent chance that the fourth card is a heart card, but no before.

So the first card can't be a heart card.

because the deck is well-shuffled, all the cards have the same probability of being drawn.

Then the probability of not getting a heart card, is equal to the quotient between the number of non-heart cards (39) and the total number of cards (52), then the probability is:

p₁ = 39/52

The second card also can't be a heart card, the probability is calculated in the same way than above, but now there are 38 non-heart cards and a total of 51 cards (because one card was already drawn) then the probability here is:

p₂ = 38/51

For the third card the reasoning is similar to the two above cases, here the probability is:

p₃ = 37/50

The fourth card should be a hearts card, the probability is computed in the same way than above, as the quotient between the number of heart cards in the deck (13) and the total number of cards in the deck (now there are 49 cards)

then the probability is:

p₄ = 13/49

The joint probability (the probability of these 4 events happening together) is equal to the product between the individual probabilities:

P = p₁*p₂*p₃*p₄

P = (39/52)*(38/51)*(37/50)*(13/49) = 0.1097

The percent chance is the above number times 100%

Percent =  0.1097*100% = 10.97%

Answer: oranges 1.2 Kg and apples 0.75 Kg.

Step-by-step explanation:

Oranges (4)(1.5)/5

Apples (3)(2)/8