Students in Mrs. Anderson’s health class are learning about how exercise affects your heart rate. Twelve students ran around the school track for different lengths of time. Then they measured their heart rates in beats per minute. Heart Rate Record Minutes Heart Rate (bpm) 7 121 8 136 7 122 4 96 3 90 6 120 7 118 4 98 2 84 5 110 7 118 8 128 Find the correlation coefficient of the data. Round to the nearest hundredth

Answer:

Step-by-step explanation:

(1 , -2)   x₁ =1 & y₁ = -2

(-3,10)  x₂= -3 & y₂ = 10

First we need to find the slope.

[tex]\boxed{Slope = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$}[/tex][tex]\boxed{Slope=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}[/tex]

          [tex]=\dfrac{10-[-2]}{-3-1}\\\\\\=\dfrac{10+2}{-4}\\\\\\=\dfrac{12}{-4}\\\\\\= - 3[/tex]

m = -3

Equation of the line: y = mx + b

y = -3x + b

To find the value of b, take one of the point and substitue in the above equaiton.

(1 , -2)

-2 = -3*1 + b

-2 = -3 + b

-2 + 3 = b

b = 1

Equation of the line:

y = -3x + 1

Part A

Part B

Answer:

See below ↓↓

Step-by-step explanation:

Part A

Part B

Answer:

24

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

x=24

Answer:

The smaller number is 24

The larger number is 45

Step-by-step explanation:

smaller number  = x

Larger: 2x - 3

Smaller + larger = 69

x + 2x - 3 = 69                        Combine left

3x - 3 = 69                              add 3 to both sides

3x - 3+3 = 69+ 3                     Combine

3x = 72                                    Divide by 3

3x/3 = 72/3                        

x = 24

Larger number = 2*24 - 3

Larger number = 45

Correlation measures the relationship between variables

The true statements are:

For a correlation coefficient to be valid, the following, must be true:

Using the above highlights, the true statements are: (b) (c) and (e)

Read more about correlation coefficients at:

https://brainly.com/question/18054482

Answer:

2/7

Step-by-step explanation:

Total no. of chocolates in the box =14

No. of dark Chocolates=4

No. of white chocolates=5

No. of milk chocolates=5

Probability of getting a white chocolate

= No. of possible outcomes /Total No. of outcomes

=5/14

Probability of getting a dark chocolate =4/14=2/7

20 separate tickets in total costs £314.

Now we should find out what percentage 262 is of 314.

262÷314×100=83.4%

if 262 is 83.4% of 314, then Sandro saves (100%-83.4%) 16.6%.

ANSWER 16.6%

qartveli xar mgoni dd

Answer: 90 dergrees

Step-by-step explanation: 90 dergrees

Answer:

(x-2)^2+(y-1)^2 = 10^2

(x-2)^2+(y-1)^2 = 100

Step-by-step explanation:

distance between points is diameter

x^2=  (8--4)^2+(-7-9)^2

x^2=12^2+16^2

x^2=144+256

x^2=400

diameter x=20 so radius =10

center point =midpoint (-4+8)/2 and (-7+9)/2

center point =(2,1)

(x-2)^2+(y-1)^2 = 10^2

(x-2)^2+(y-1)^2 = 100

Answer:

9

Step-by-step explanation:

10

Answer:

6/7

Step-by-step explanation:

3x2/7 in the same as 3/1x2/7, which is 6/7

(simply multiply the denominator and numerator of the fraction)

Answer: hii <3

Exact Form:

6/7

Decimal Form:

0.857142

Step-by-step explanation:

Simplify the expression.

Hopefully this helps you

- Matthew

Answer:

The answer is B. 1/4^8

Step-by-step explanation:

Every time the power it to the negative it inverse it.

An example, 2^-2 = 1 / 2^2

So, 4^-8 = 1 / 4^8

24

[tex]Convert\ the\ unit\ for\ \frac{12in}{1ft}:\\ \downarrow\\ 24[/tex]

I hope this helps you

:)

Answer:

54861/1000 convert to a decimal = 54.861

Answer:

a) 1,2; 3.4

b) <1=<6, <6+<6+72=180, 2<6=108, <6=54.

<1=54

You can tell this by "these are parallel lines"

If Carly's bedroom is 15.3ft long and 8.7 ft long then it is necessary to multiply them because you need to find the area of the room so 15.3*8.7= 133.11. We have to do the same for Carter's room so we multiply 14.4 and 9.6 to find the area of the room which is 138.24.

Now that we have both the areas we can compare which room is bigger. Carly's room is 133.11 ft in total and Carter's room is 138.24 ft in total. So it is clear that Carter's room is going to be more expensive to cover with carpet since Carter's room is bigger than Carly's.

Carly:-

Area:-

#Carter

Area:-

Carter's room is expensive

Answer:

through lengthy mafs, your answer should be 307 mi (wrong somehow)

Step-by-step explanation:

if you want an explanation, please, dont be afraid to comment ;)

(to other people who look this up the answer is actually 318 i dont know, but i got it wrong

Answer:

21

Explanation:

To solve this problem, you substitute in the 5 for the x creating this equation: f(5)=6+3(5).

f(5)=15+6

f(5)=21

Using it's concept, it is found that the probability that the coin shows tails and he rolls a 5 is of [tex]\frac{1}{12}[/tex].

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, the coin has two outcomes, one of which is tails, while the number cube has six outcomes, one of which is five. Since the coin and the number cube are independent, we just multiply the probabilities, hence:

[tex]p = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}[/tex]

The probability that the coin shows tails and he rolls a 5 is of [tex]\frac{1}{12}[/tex].

More can be learned about probabilities at https://brainly.com/question/14398287

Answer:

can you clear more I don't understand

Answer:

The graph shows a steady declining plot as the aveage traffic volume increases. Since y axis is speed the correct answer is that as traffic volume increases the average vehicle speed decreases.

Step-by-step explanation:

Answer:

62

Step-by-step explanation:

(x+8)=(2x-15)
8=x-15
+15   +15
23=x

so


23 +8 = 31
23x2-15 = 46-15 =31
Both are the same always since one side is equal to the other
Therefore
62 is the answer!

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's expand the given expression ~

[tex]\qquad \sf  \dashrightarrow \: - 3y( {y}^{4} + 2 {y}^{3} - 5 {y}^{2} - y + 4)[/tex]

[tex]\qquad \sf  \dashrightarrow \: ( - 3y \cdot {y}^{4} ) + ( - 3y \cdot2 {y}^{3} ) + ( - 3y \cdot - 5 {y}^{2} ) + ( - 3y \cdot - y) + ( - 3y \cdot4)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 3{y}^{5} - 6{y}^{4} + 1 5 {y}^{3} + 3{y}^{2} - 12y[/tex]

The area of the composite figure from the image attached is 112.5 units²

The area of a composite figure refers to the sum total of all the areas of the shapes in that composite figure. This can be done by first identifying the shapes in that composite figure, then finding each area, followed by the addition of all the areas to determine the area of the composite figure.

From the given figure; we can break it down into:

The area of a parallelogram = b × h

where;

The area of a parallelogram =  9 × 6

The area of a parallelogram = 54 units²

The area of a rectangle = Length × breadth

The area of a rectangle = (9 × 3) units²

The area of a rectangle = 27 units²

The area of the triangle [tex]\mathbf{=\dfrac{1}{2}\times b \times h}[/tex]

where;

The area of the triangle [tex]\mathbf{=\dfrac{1}{2}\times b \times h}[/tex]

The area of the triangle [tex]\mathbf{=\dfrac{1}{2}\times 9 \times 7}[/tex]

The area of the triangle [tex]\mathbf{= 31.5 units^2}[/tex]

Therefore, the area of the composite figure is:

= 54 + 27 + 31.5

= 112.5 units²

Learn more about composite figures here:

https://brainly.com/question/15981553

Answer: 56 yd

Step-by-step explanation: if you continue the 8 yd line across, it would show that the missing side is 4yd less than the 13 yd side, meaning the missing side is 9 yd long. So after adding 7 + 13+ 15+ 4 + 8 + 9= 56 yd

Answer:

0.216 cubic feet

Step-by-step explanation:

v = lwh (volume = length times width times height)

v = 0.6 x 0.6 x 0.6  OR 0.6^3

v = 0.216

Answer:

Step-by-step explanation:

Find the zero's of f(x)

Answer:

[tex]x=4, \quad x=1+i,\quad x=1-i[/tex]

(one real zero and 2 complex zeros)

Step-by-step explanation:

Given polynomial:

[tex]f(x)= 2x^3-12x^2+20x-16[/tex]

According to the Factor Theorem, if f(4) = 0 then (x - 4) is a factor of the given polynomial.

[tex]\implies f(x)=(x-4)(ax^2+bx+c)[/tex]

Expand the brackets:

[tex]\implies f(x)=ax^3+bx^2+cx-4ax^2-4bx-4c[/tex]

[tex]\implies f(x)=ax^3+(b-4a)x^2+(c-4b)x-4c[/tex]

Compare coefficients with the given polynomial:

[tex]\implies a=2[/tex]

[tex]\implies -4c=-16 \implies c=4[/tex]

[tex]\implies (b-4a)=-12 \implies b-8=-12 \implies b=-4[/tex]

Substitute the found values of a, b and c:

[tex]\implies f(x)=(x-4)(2x^2-4x+4)[/tex]

To find the zeros of f(x), set the function to zero and solve for x:

[tex]\implies (x-4)(2x^2-4x+4)=0[/tex]

[tex]\textsf{Therefore},\: (x - 4) = 0\: \textsf{ and }\: (2x^2-4x+4)=0[/tex]

[tex]\textsf{To solve}\: (2x^2-4x+4)=0\: \textsf{ use the quadratic formula}[/tex]

Quadratic Formula

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

Therefore:

[tex]\implies x=\dfrac{-(-4) \pm \sqrt{(-4)^2-4(2)(4)} }{2(2)}[/tex]

[tex]\implies x=\dfrac{4 \pm \sqrt{-16}}{4}[/tex]

[tex]\implies x=\dfrac{4 \pm \sqrt{16 \cdot -1}}{4}[/tex]

[tex]\implies x=\dfrac{4 \pm \sqrt{16}\sqrt{-1}}{4}[/tex]

[tex]\implies x=\dfrac{4 \pm 4i}{4}[/tex]

[tex]\implies x=1 \pm i[/tex]

Therefore, the zeros of the function are:

[tex]x=4, \quad x=1+i,\quad x=1-i[/tex]

(one real zero and 2 complex zeros)

Answer:

Undefined.

Formula's used:

[tex]\longrightarrow \bold{sec(x) = \dfrac{1}{cos(x)} }[/tex]

[tex]\longrightarrow \bold{cosec(x) = \dfrac{1}{sin(x)} }[/tex]

[tex]\longrightarrow \bold{cot(x) = \dfrac{1}{tan(x)} }[/tex]

[tex]\longrightarrow \bold{tan(x) = \dfrac{sinx}{cos(x)} }[/tex]

[tex]\longrightarrow \bold{sin^2x + cos^2 x = 1 }[/tex]

[tex]\longrightarrow \sf \bold{Sum \ Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx}[/tex]

[tex]\longrightarrow \bold{ \int \:{sec^2(ax+b) = \dfrac{1}{a}tan(ax+b)+c }}[/tex]

[tex]\longrightarrow \bold{\int \:\dfrac{1}{ax+b} =\dfrac{1}{a} ln|ax+b|+c}[/tex]

Explanation:

[tex]\sf \Longrightarrow \int _{\pi }^{2\pi }\:\dfrac{sin^6(x)+cos^6(x)}{sin^3(x) \ * \ cos^3\left(x)}[/tex]

[tex]\sf \Longrightarrow \sf \int _{\pi }^{2\pi }\:\dfrac{sin^6\left(x\right)}{sin^3\left(x\right)\cdot \:cos^3\left(x\right)} +\dfrac{cos^6\left(x\right)}{sin^3\left(x\right)\cdot \:cos^3\left(x\right)}[/tex]

[tex]\Longrightarrow \sf \int _{\pi }^{2\pi }\:\dfrac{sin^3\left(x\right)}{\:cos^3\left(x\right)} +\dfrac{cos^3\left(x\right)}{sin^3\left(x\right)}[/tex]

[tex]\Longrightarrow \sf \int _{\pi }^{2\pi }\ tan^3(x)+ cot^3(x)[/tex]

[tex]\sf \Longrightarrow \sf \int _{\pi }^{2\pi } \tan ^3(x)dx+\int _{\pi }^{2\pi } \cot ^3 (x)dx[/tex]

[tex]\Longrightarrow \sf \bold{ [ }-\ln |\sec \left(x\right) |+\dfrac{\sec ^2(x)}{2}-\dfrac{\cot ^2 (x)}{2}-\ln |\sin(x)| \bold{ ] }^{2\pi }_\pi[/tex]

apply limits

[tex]\sf \Longrightarrow \sf -\ln \left|\sec \left(2\pi \right)\right|+\dfrac{\sec ^2\left(2\pi\right)}{2}-\dfrac{\cot ^2\left(2\pi\right)}{2}-\ln \left|\sin \left(2\pi\right)\right|-(-\ln \left|\sec \left(\pi \right)\right|+\dfrac{\sec ^2\left(\pi\right)}{2}-\dfrac{\cot ^2\left(\pi\right)}{2}-\ln \left|\sin \left(\pi\right)\right|)[/tex]

simplify using trigonometric basic functions

[tex]\Longrightarrow \sf -\ln \left|\dfrac{1}{\cos \left(2\pi \right)}\right|+\dfrac{\left(\dfrac{1}{\cos \left(2\pi \right)}\right)^2}{2}-\dfrac{\cot ^2\left(2\pi \right)}{2}-\ln \left|\sin \left(2\pi \right)\right|- ( -\ln \left|\dfrac{1}{\cos \left(\pi \right)}\right|+\dfrac{\left(\frac{1}{\cos \left(\pi \right)}\right)^2}{2}-\dfrac{\cot ^2\left(\pi \right)}{2}-\ln \left|\sin \left(\pi \right)\right|)[/tex]

⇒  Undefined

Answer:

[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \boxed{\text{un} \text{de} \text{f}}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

Integration

Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Methods: U-Substitution + U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx[/tex]

Step 2: Integrate Pt. 1

Step 3: Integrate Pt. 2

Step 4: Integrate Pt. 3

Identify variables for u-solve.

1st Integral

2nd Integral

Step 5: Integrate Pt. 4

∴ we have found the value of the given integral.

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Learn more about integration: https://brainly.com/question/14413972

Learn more about calculus: https://brainly.com/question/20197752

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Find the circumference:

8km x 2 x 3.14 = 50.24 km

Arc length = 50.24 x 225/360 = 31.4 km

answer: C. 10 pi or 31.4 km