. Sulphuric acid (H2SO4) is extremely corrosive to skin. *
O Analytical Chemistry
Physical Chemistry
Biochemistry
O Inorganic Chemistry

The 132 L  volume would it be under these conditions.

What is volume ?

Space is occupied by every three-dimensional object. Its volume serves as a gauge for this area. The area contained by an object's limits in three-dimensional space is referred to as its volume. Another name for it is an object's capacity.

What is mole ?

A mole is the atom's elementary particle, an ion. The mole of the substance is always related to the Avogadro number. The mole is always associated with the weight or mass of the element or substance. The standard unit of a mole is mol. The mole is a significant factor of the reactant and products to form an equation. A mole calculates the atom, ion, and substance weighs.

Therefore, 132 L  volume would it be under these conditions.

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Answer:

8

Explanation:

because you only have 8 hamburger patties

Answer:

2H²+O²--> 2H²O (sry subscripts can't be written on moblie)

Explanation:

the first part of the reaction shows 4 hydrogen atoms and 2 oxygen atoms, and the second formula shows the same

According to law of conservation of mass, if mass of product is 58.3 g the mass of nitrogen is 28 g and that of cesium nitride is 30.3 g which sums up to 58.3 g.

According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Mass of cesium nitride= mass of cesium + mass of nitrogen, thus, mass of nitrogen = 14×2=28 g and that of cesium is 58.3-28=30.3 g.

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According to the stoichiometry of the given chemical equation, 0.2 moles of potassium oxide would be produced assuming you had unlimited oxygen.

Stoichiometry is defined as   the determination of proportions of elements or compounds in a chemical reaction. The  relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given equation,156 g potassium gives 188.4 g potassium oxide, thus, 15.6 g will give 15.6×188.4/156=18.84 g potassium oxide which is 18.84/94.2= 0.2 moles.

Thus, 0.2 moles of potassium oxide would be produced assuming you had unlimited oxygen.

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A brass rod, a copper rod, an iron rod and a lead rod went into water with wax on top, an iron rod will rust first if lead stayed on the longest and copper for the least.

Rust is an iron oxide, which is a typically reddish-brown oxide created by the catalytic interaction of iron with oxygen in the absence of water or air moisture. Rust is often connected with the corrosion of refined iron and is composed of hydrous iron(III) oxides (Fe2O3nH2O) with iron(III) oxide-hydroxide (FeO(OH), Fe(OH)3).

Given enough time and the presence of oxygen and water, any iron mass may ultimately rust completely. A brass rod, a copper rod, an iron rod and a lead rod went into water with wax on top, an iron rod will rust first if lead stayed on the longest and copper for the least.

Therefore, an iron rod will rust first if lead stayed on the longest and copper for the least.

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Answer: The sum of all chemical reactions in the body.

Catabolism (breaking down)- releases energy ATP

Anabolism (building up)- Uses energy to synthesize what body needs.

Explanation:

Answer:

84.066 amu

Explanation:

The average atomic mass of iron can be calculated using the following formula:

Average atomic mass = (54Fe * 0.058 + 56Fe * 0.917 + 57Fe * 0.022 + 58Fe * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)

Plugging in the numbers, we get:Average atomic mass = (54 * 0.058 + 56 * 0.917 + 57 * 0.022 + 58 * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)

Average atomic mass = (31.12 + 51.592 + 1.254 + 0.174) / (0.058 + 0.917 + 0.022 + 0.003)

Average atomic mass = 84.066 / (0.058 + 0.917 + 0.022 + 0.003)Average atomic mass = 84.066 / 1

Average atomic mass = 84.066So, the average atomic mass of Iron is 84.066 atomic mass units (amu).

Yes, Jose reached his goal.

In chemistry, the mole is a unit used to measure the amount of a substance. It is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are atoms in 12 grams of pure carbon-12. This number is known as Avogadro's number and is approximately equal to 6.022 × 10^23.

The concept of the mole is fundamental to many areas of chemistry, including stoichiometry, the study of chemical reactions and their quantitative relationships. It allows chemists to make precise measurements and calculations, and to compare and relate the properties of different substances.

Number of moles in 40 g of iron = 40g/56 g/mol

= 0.7 moles

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Answer:

0.09536 g of SO2 in the sample of air

Explanation:

The first step is to convert the volume of KMnO4 solution to moles. This can be done using the formula:

moles = Molarity x volume (in liters)

So,

moles = 0.008 M x (7.37 mL) x (1 L/1000 mL)

= 0.0000596 moles

Next, we need to find the ratio of moles of SO2 to moles of KMnO4 in the balanced equation:

5SO2 + 2MnO4- + 2H205SO42- + 2Mn2+ + 4H+

From the equation, it can be seen that 2 moles of KMnO4- react with 5 moles of SO2. So,

moles of SO2 = (moles of KMnO4) x (5 moles of SO2 / 2 moles of KMnO4)

= 0.0000596 x (5/2)

= 0.0001495 moles

Finally, to convert moles of SO2 to grams, we can use the formula:

grams = moles x molar mass

Since the molar mass of SO2 is 64 g/mol,

grams = 0.0001495 x 64

= 0.09536 g

So, there are 0.09536 g of SO2 in the sample of air.

The temperature at which the diameter of the hole is 1.164 cm is approximately 23.00 + 13.63 = 36.63 ∘C.

The diameter of a hole in a steel plate changes with temperature due to thermal expansion. The amount of expansion is determined by the coefficient of linear expansion of steel, which is around 12x10^-6 per kelvin.

To find the temperature at which the diameter of the hole is 1.164 cm, we can use the formula:

ΔL = L0 * α * ΔT

where ΔL is the change in length, L0 is the initial length, α is the coefficient of linear expansion, and ΔT is the change in temperature.

We can rearrange the formula to solve for ΔT:

ΔT = ΔL / (L0 * α)

Substituting the values:

ΔL = 1.166 - 1.164 = 0.002 cm

L0 = 1.166 cm

α = 12x10^-6 per kelvin

ΔT = 0.002 / (1.166 * 12x10^-6) = approximately 13.63 kelvins

So, the temperature at which the diameter of the hole is 1.164 cm is approximately 23.00 + 13.63 = 36.63 ∘C.

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(a) The hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M. (b) 0.57%. (c) The ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.

(a) The balanced equation for the ionization of propanoic acid is:

C2H5COOH + H2O ⇌ C2H5COO- + H3O+

The equilibrium expression for this reaction is:

Ka = [C2H5COO-][H3O+] / [C2H5COOH]

At equilibrium, the concentration of propanoic acid that has ionized to form propanoate ion and hydronium ion is equal to the concentration of propanoic acid that has not ionized, so we can assume that [C2H5COO-] ≈ [H3O+]. Let x be the concentration of hydronium ion in the solution. Then the equilibrium expression becomes:

Ka = x^2 / (0.20 - x)

Solving for x, we get:

x = sqrt(Ka * (0.20 - x)) = sqrt(1.3x10^-5 * 0.20) = 1.14x10^-3 M

Therefore, the hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M.

(b) The percentage of propanoic acid molecules that are ionized in the solution is given by:

% ionization = [H3O+] / [C2H5COOH] x 100%

% ionization = (1.14x10^-3 / 0.20) x 100% = 0.57%

(c) The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([C2H5COO-] / [C2H5COOH])

At pH 5.20, the hydronium ion concentration is 10^-5.20

= 6.31x10^-6 M.

Using the equilibrium expression for propanoic acid and the fact that [C2H5COO-] + [C2H5COOH] = total buffer concentration,

we can solve for the ratio of the concentrations of propanoate ion to propanoic acid:

Ka = [C2H5COO-][H3O+] / [C2H5COOH]

[C2H5COO-] = Ka[C2H5COOH] / [H3O+]

[C2H5COO-] = (1.3x10^-5)([C2H5COOH]) / (6.31x10^-6)

[C2H5COO-] / [C2H5COOH]

= 2.68

Therefore, the ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.

(d) When solid NaOH is added to the buffer solution, it reacts with the propanoic acid to form propanoate ion and water:

C2H5COOH + NaOH → C2H5COO- + H2O + Na+

The number of moles of propanoic acid that react with NaOH is equal to the number of moles of NaOH that were added. The new concentration of propanoic acid is:

0.35 M - (0.0040 mol / 0.100 L) = 0.346 M

The new concentration of propanoate ion is:

0.50 M + (0.0040 mol / 0.100 L) = 0.54 M

The new concentration of hydronium ion can be calculated using the equilibrium expression.

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Answer:

Red #3 is the most polar, and Blue #1 is the least polar.

Explanation:

To order the dyes from most polar to least polar, we need to look at the retention factor values. The lower the retention factor value, the more polar the molecule. So, based on the given values, the order from most polar to least polar would be:

Red #3 - 0.000

Yellow #5 - 0.286

Blue #2 - 0.095

Red #40 - 0.046

Blue #1 - 0.58

The molecular formula of the compound is CI4H12S4.

Let's assume that we have 6 grams of the compound, which means that 1 gram of the compound contains 1/6th of the total amount of the compound.

We are given that the compound contains C, H, I, S, and has a molar mass of 229 g/mol. Let's use x, y, z, and w to represent the number of moles of C, H, I, and S in one mole of the compound, respectively.

From the information given in the problem, we can set up the following system of equations:

x + y + z + w = 1 (since the sum of the mole fractions must equal 1)

12x = y (since the compound has six times as much C as H by mass)

To find the molecular formula of the compound, we need to determine the values of x, y, z, and w that satisfy these equations and give a molar mass of 229 g/mol.

The molar mass of the compound can be calculated as:

M = 12x + y + 127z + 32w

Substituting y = 12x from the second equation, we get:

M = 13x + 127z + 32w

We know that the molar mass of the compound is 229 g/mol, so we can set up the equation:

229 = 13x + 127z + 32w

We also know that x + y + z + w = 1, so we can substitute y = 12x, giving:

x + 12x + z + w = 1

13x + z + w = 1

We can solve these equations simultaneously to get:

x = 0.061

z = 0.504

w = 0.069

Substituting these values into the equation for the molar mass, we get:

M = 13(0.061) + 127(0.504) + 32(0.069) = 229

Therefore, the molecular formula of the compound is CI4H12S4.

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Answer:

divide it by

its molar mass

Explanation:

The dosage of an asthma drug is 7 mg/kg of body mass. The required dosage for the 43 lb child is 32.2 mg.

What do you mean by drugs?

Drugs are substances intended for use in the diagnosis, cure, mitigation, treatment, or prevention of disease or to otherwise enhance physical or mental well-being.

An asthma drug is a medication used to treat asthma symptoms. Common types of asthma drugs include bronchodilators, corticosteroids, and anti-inflammatory drugs.

So,

43 lbs = 19.5 kg

7 mg/kg x 19.5 kg = 136.5 mg

136.5 mg = 32.2 mg (rounded to the nearest tenth)

Hence, the required dosage for the 43 lb child is 32.2 mg.

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Answer : Slope = -3, intersection = 11

We need to isolate for y here.

From 9x+3y=33, we need to derive a y=mx+b equation.

First, we take away 9x as follows:

9x+3y-9x=33-9x

The positive and negative values of 9x cancel our on the y side, so we are left with 3y=-9x+33

Now we need to get rid of the y coefficient:

(3y)÷3=(-9x+33)÷3

We need to effectuate the division on both sides to cancel out the coefficient, so we are left with y=-3x+11

Answer: y-intercept = y = 11 - 3x

Slope is m = -3

Answer:  i answerd 34cu i got coreect hopefully you get it corecct!!!!!!!

Explanation:

For the following reasons, brine is a more potent de-icing solution than solid ice melt products: Because brine freezes at a lower temperature than water, it can remain liquid at lower temperatures.

The typical use of brine, a salt-water solution, includes uses as a de-icing agent, a food preservative, and a source of minerals for industrial processes. Brine is a substance that is used in de-icing to either stop the growth of ice or to melt already-existing ice on sidewalks, highways, and other surfaces. It functions by bringing down water's freezing point, which causes ice to melt at lower temperatures. Compared to solid ice melt products, which may contain chemicals damaging to the environment, brine is typically seen as a more cost- and environmentally-friendly de-icing method. Brine is a common choice for de-icing applications since it is simple to prepare and use.

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An aqueous solution containing 35.5 g of an unknown molecular (non-electrolyte) compound in 158.6 g of water was found to have a freezing point of -1.4 ∘C. Therefore, 3.3 × 10² g/mol is the molecular mass.

The quantity of fill with a molecule is referred to as its molecular mass. It is also known as molecular weight.

It is computed by multiplying the mass for every atom by the amount of atoms belonging to the element that the molecule contains. Water, for example, is composed of two hydrogen atoms and one oxygen atom.

ΔT = i × Kf × m

m = ΔT / i × Kf

m = (1.4°C) / 1 × (1.86 °C/m) = 0.70 m

moles of solute = m × kg of solvent = 0.70 mol/kg × 0.1500 kg = 0.11 mol

M = 35.9 g/0.11 mol = 3.3 × 10² g/mol

Therefore,  3.3 × 10² g/mol is the molecular mass.

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Answer:

Creep feeding can help them make the transition without such a setback, and it can also help them begin to produce the enzymes needed to digest nonmilk proteins.

Explanation:

In the years after the civil war   texas farmers produced cotton the most  among all crops,

In the years following the Civil War, cotton was the most important cash crop in Texas and the primary source of income for many farmers. Texas had favorable climatic conditions and fertile soils that were well-suited for cotton cultivation. Additionally, the demand for cotton was high both domestically and internationally, which made it a lucrative crop for farmers. As a result, cotton production in Texas increased significantly in the years after the Civil War, with the state becoming one of the largest cotton producers in the country. However, this dependence on a single crop also left farmers vulnerable to market fluctuations and crop failures, which led to economic hardship and debt for many.

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Answer:

Asexual reproduction is a mode of reproduction that occurs without the involvement of sex cells or meiosis. In this type of reproduction, a single organism produces offspring that are genetically identical to the parent. This can happen through methods such as budding, fragmentation, and self-fertilization.

Sexual reproduction, on the other hand, involves the fusion of gametes or sex cells from two different organisms to produce offspring that have genetic material from both parents. This results in offspring with a unique combination of traits and genetic diversity. Some common examples of sexual reproduction include the exchange of sperm and eggs in animals, and the fusion of male and female gametes in plants.

Explanation:

Yes, it is possible to identify the liquid, and the density of the liquid is closest to 0.889 g/cm³ so the liquid is most likely tetrahydrofuran.

To calculate the density of the unknown liquid, we use the formula:

Density = Mass / Volume

Substituting the given values, we get:

Density = 682. g / 0.767 L

Density = 888.5 g/L

Rounding to three significant digits, the density of the unknown liquid is 889 g/L.

Using the information provided in the question, we can compare the density of the unknown liquid to the known densities of the listed chemicals. The densities (in g/cm³) of the chemicals are:

Dimethyl sulfoxide: 1.092

Acetone: 0.790

Diethylamine: 0.707

Tetrahydrofuran: 0.889

Carbon tetrachloride: 1.594

Comparing the density of the unknown liquid to the known densities, we see that it is closest to the density of tetrahydrofuran, which is 0.889 g/cm³. Therefore, it is likely that the unknown liquid is tetrahydrofuran.

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Answer:

the fromu;la is 50

Explanation:

becuase it is soooopo understand

Answer:

The molar mass of a compound is similar to its formula mass in that both represent the sum of the atomic masses of all the elements in the compound. The formula mass is the total atomic mass of the elements in the chemical formula of a compound, while the molar mass is the mass of one mole of the compound.

The molar mass of a compound is different from its formula mass in that the molar mass is a unit of measurement for the amount of substance, whereas the formula mass is simply a numerical value representing the total atomic mass of the elements in the compound. The molar mass is expressed in units of grams per mole (g/mol), whereas the formula mass is expressed in atomic mass units (amu). Additionally, the molar mass takes into account the Avogadro's constant, which is the number of entities in one mole of a substance, whereas the formula mass does not.

Explanation:

ALLEN

Answer:

43.63 g of water.

Explanation:

We can use the equation for heat transfer to solve for the mass of water:

q = cmΔT

where

q = heat transfer

c = specific heat

m = mass

ΔT = change in temperature

The heat transfer from the copper to the water can be expressed as:

q = cmΔT

q = (33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C)

And the heat transfer caused a change in temperature in the water, which can be expressed as:

q = mLΔT

q = (m)(4.18 J/g°C)(ΔT)

Equating the two expressions for heat transfer, we can solve for the mass of water:

(33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C) = (m)(4.18 J/g°C)(22.87°C - 21.65°C)

m = (33.41 g)(0.385 J/g°C)(95.6°C - 21.65°C) / (4.18 J/g°C)(22.87°C - 21.65°C)

m = 43.63 g

So the copper was added to 43.63 g of water.

46.2648

Atomic mass describes the number of protons and neutrons in an atom.

Percent Abundance

Percent abundance is the percentage of atoms within a sample that have a specific mass number. The reason that different atoms within a sample would have different mass numbers is that they are different isotopes. For example, if the isotope Cl-35 has a percent abundance of 75%, then 75% of all Chlorine atoms within a sample will have a mass number of 35. Percent abundance refers to the likelihood of an isotope occurring in a natural sample. Percent abundance does not take into account artificial samples of elements.

Finding Atomic Mass

The atomic mass of an element is found through the mass of isotopes and their percent abundances. The formula for atomic mass is:

In this formula, the m is the mass of the isotope and p is the percent abundance. The percent abundance should be expressed as a decimal for all calculations. Now, plug in the values and solve.

Rounded to 4 decimal places, this equals 46.2648. This means that the atomic mass of element "X" is 46.2648 amu.

Information 1: There are 2.0 moles of HCl. It contains 2.5 moles of NaOH.

Data 2 reveals a 2.5 mole concentration of zinc.

HCl has a molecular weight of six.

Fe(OH)3 makes up 4.0 moles, according to Data 3.

It contains 6.5 moles of H2SO4.

Answer (A) (A)

Below is a display of the suggested response.

HCl+NaOH→NaCl+H2O

1 mole of HCl and 1 mole of NaOH combine in the procedure described above.

To calculate how many moles of NaOH are needed to react with 2 mol of HCl, see the formula below.

NaOH=1mol1mol×2mol=2mol

NaOH is, however, just 2.5 moles accessible.

NaOH therefore acts as the excess reactant and HCl as the limiting reactant.

In light of this, HCl is the reaction's limiting reactant.

In response (B),

Below is a display of the suggested response.

Zn+2HCl→ZnCl2+H2

One mole of zinc reacts with two moles of HCl in the mechanism described above.

Thus, it can be determined from the calculations below how many moles of HCl are needed to react 2.5 mol of zinc.

HCl=2mol1mol×2.5mol=5mol

In contrast, there are 6 moles of HCl available.

The excess reactant in the reaction is therefore HCl, whereas the limiting reactant is Zn.

Consequently, Zn serves as the reaction's limiting reactant.

Answer (C) (C)

Below is a display of the suggested response.

2Fe(OH)3+3H2SO4→Fe2(SO4)3+6H2O

In the reaction mentioned above, 3 moles of H2SO4 and 2 moles of Fe(OH)3 react.

Thus, the calculation below determines how many moles of H2SO4 are necessary for four moles of Fe(OH)3 to react entirely.

H2SO4=3mol2mol×4mol=122mol=6mol

However, there is a limited supply of H2SO4 is 6.5 mol.

The limiting reactant in the reaction is therefore Fe(OH)3, while the excess reactant is H2SO4.

In light of this, Fe(OH)3 is the reaction's limiting reactant.

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