Suppose that two objects attract each other with a gravitational force of 18 units. If the mass of one of the objects was tripled, and if the distance between the objects tripled, then what would be the new gravitational force of attraction between the two objects?

The magnitude of the electrostatic force that charge A exerts on charge B is [tex]2.7 x 10^24 N.[/tex]

The electrostatic force between two point charges is given by Coulomb's law:

[tex]F = (k * q1 * q2) / r^2[/tex]

where F is the electrostatic force, q1 and q2 are the charges, r is the distance between them, and k is Coulomb's constant, which is approximately equal to [tex]9 x 10^9 N·m^2/C^2.[/tex]

Substituting the given values, we get:

[tex]F = (9 x 10^9 N·m^2/C^2) * (13.0 x 10^27 C) * (14.0 x 10^27 C) / (2.0 x 10^22 m)^2[/tex]

Simplifying the expression, we get:

[tex]F = 2.7 x 10^24 N[/tex]

Therefore, the magnitude of the electrostatic force that charge A exerts on charge B is [tex]2.7 x 10^24 N.[/tex]

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Answer:

 The state when the two objects have reached the same temperature is known as thermal equilibrium.

The speed of this surface water wave is 3.33 meters per second.

The speed of a surface water wave depends on the wavelength and the frequency of the wave.

The speed of a surface water wave can be determined by the equation:

speed = wavelength × frequency

Here, the wavelength is given as 20 meters (the distance between two successive crests), and the frequency can be calculated by dividing the number of crests passing by in one minute (60 seconds) by the time taken for them to pass:

frequency = 10 crests / 1 minute = 10/60 Hz = 1/6.0 Hz

Put values:

speed = 20 meters × (1/6.0 Hz) = 3.33 meters/second

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The speed of the ball just before its land on the 30 tall Tower is 39.08m/s.

The ball is thrown vertically upward with an initial vertical speed of 46 m/s the ball rises and falls to land on a 30 m tall Tower.

First letters find out the maximum height of the ball by using the formula,

H = u²/2g

Where, H is height, u is initial speed, g is acceleration due to gravity.

Putting values,

H = 46×46/(2×9.8)

H = 107.95 m.

Now when the ball reaches the maximum height and lands on the 30 metre tall Tower it covers a distance d of 77.95 m.

Now, using this distance we can find the speed of the ball just before it lands on the tower by using the formula,

V = √(2gd)

V = √(2×9.8×77.95)

V = √(1527.82)

V = 39.08m/s.

So, the speed of the ball just before it lands on the tower is 39.08m/s.

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The figure indicates the strength of an electric field and the size of the charge by showing the distribution of electric field lines.

Electric field lines represent the strength of the electric field and are drawn in a way that conveys the direction and magnitude of the electric field. The more field lines that are present, the stronger the electric field. The arrows on the field lines indicate the direction of the electric field, and the size of the arrows indicate the strength of the electric field. The size of the charge is indicated by the number of field lines that originate at the charge. The more field lines that originate at the charge, the greater the size of the charge. The arrows represent the direction of the electric field and the length of the arrows represent the strength of the electric field. The larger the arrows, the stronger the electric field. The size of the charge is represented by the number of arrows pointing away from the charge. The more arrows, the larger the charge.

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Given voltage drop across

EDLED is 1.8V in forward bias.

1.8 1.8 1.8

100

if

3.1kn

Applying Kirchhoff's voltage law to the circuit,

we get 10-1.8-1.8-1.8 - EXLOUD

<= 0=)46= 8×1000 [= 4.6 MA.

It is safe current level for a LED-for typical Current is arand power LED maximum forward 20 mA.

Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light. In brief, voltage = pressure, and it is measured in volts (V).

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Because the string of a violin A vibrates 12 times in 4 seconds and the string of a violin B vibrates 18 times in 6 seconds, their frequencies are equal; that is, the string of a violin A and the string of a violin B have the same frequency of 3 Hz.

The frequency of a string = number of complete cycles of vibration per unit time, and the calculation is given below,

For string A, the frequency is,

frequency = number of vibrations / time frequency

frequency = 12 vibrations / 4 sec= 3 Hz

For string B, the frequency is,

frequency = number of vibrations / time frequency

frequency = 18 vibrations / 6 sec = 3 Hz

Hence, because the string of a violin A vibrates 12 times in 4 seconds and the string of a violin B vibrates 18 times in 6 seconds, their frequencies are equal; that is, the string of a violin A and the string of a violin B have the same frequency of 3 Hz.

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Answer: An element with 5 electrons is more likely to either gain 3  electrons in its’ outer-most valence electron shell

Explanation: To determine whether an element with 5 electrons is more likely to gain 3 or lose 5 electrons in its outermost valence electron shell, we can use the Lewis Dot Structure.

1. Draw the symbol of the element. For example, let's consider the element with 5 electrons as X.

2. Determine the number of valence electrons for the element. Since the element has 5 electrons, it will have 5 valence electrons.

3. Represent the valence electrons as dots around the symbol of the element. In this case, we would draw 5 dots around the symbol X.

4. Analyze the electron configuration to determine the stability of the element.

- If the element gains 3 electrons, it will have a total of 8 valence electrons. This would result in a stable electron configuration, similar to the nearest noble gas. For example, if the element is in Group 15, gaining 3 electrons would give it the electron configuration of the noble gas, Neon (2, 8).

The resistance of another wire of same material that has the same length but double the diameter will have a resistance one fourth of R.

There is a wire that has a resistance R.

Now there is another wire that has the same material and the same length also but the diameter of that wire is double of the first wire.

We know that the resistance of a material is given by the formula,

R = 4pL/πD²

Where R is the resistance of the material, p is the resistivity, L is the length and D is the diameter of the wire.

If the above mentioned resistance is the resistance of the first wire then the resistance of the second wire of double diameter will be given by,

R' = 4pL/π(2D)²

Now, putting R = 4pL/πD²

R' = R/4.

So, the resistance of the another wire will be one fourth of R.

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Double double toil and trouble;

Fire burn and couldron bubble. is by the struggle a lot

option A  

The phrases that the three witches in Macbeth used to inform the audience of Macbeth's actions show that Macbeth would suffer greatly. The three witches foretold Macbeth's ascension to the throne. Additionally, they told him that his reign could not be passed on to his descendants. Instead, the realm would pass to Banquo's sons. The predictions a encouraged Macbeth to kill his t friends, including Duncan, in order to fulfill have excessive desires, which Lady Macbeth pushed him to do. As a result, it to clear from the phrases that the three witches in Macbeth used to the  inform the audience about Macbeth's activities that Macbeth would face many difficulties.

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The complete question follows

Read the following lines that a group of witches say in Macbeth .What do these lines let the audience know that Macbeth is going to do?

Double double toil and trouble;

Fire burn and couldron bubble.

A) struggle a lot

B) catch fire

C) meet someone who looks like him

D) buy a cauldron

The way that an electromagnetic-wave in space never dials back is predictable with the law of preservation of energy, as it keeps a steady energy as it goes through space.

The explanation that makes sense of how the way that an electromagnetic wave in space never dials back is steady with the law of protection of energy is: "Assuming light dialed back, its energy would diminish, subsequently abusing the law of preservation of energy."

The speed of light, or any electromagnetic, still up in the air by the properties of the medium through which it is voyaging. In a vacuum, the speed of light is consistent and doesn't dial back.

This is reliable with the law of preservation of energy, which expresses that energy can't be made or annihilated, just changed starting with one structure then onto the next.

If an electromagnetic wave were to slow down, its energy would have to go somewhere. It would either be converted to another form of energy or lost entirely. This would violate the law of conservation of energy.

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Answer:

the second option

Explanation:

an object vibrating at a second objects natural frequency forces the second object to vibrate

a) The bolt 1.38 seconds to fall through the last 20% of its fall.

b) The bolt begins the last 20% of its fall 3.06 seconds after it is dropped.

c) The speed of the bolt just before it hits the ground is 42.43 m/s.

(a) The time it takes for the bolt to fall through the last 20% of its fall can be calculated using the kinematic equation:

[tex]y = vi*t + (1/2)at^2[/tex]

where y is the distance fallen, vi is the initial velocity (which is 0), a is the acceleration due to gravity ([tex]-9.8 m/s^2[/tex]), and t is the time taken.

Let's call the total distance fallen by the bolt "d". Then, the distance fallen in the last 20% of the fall is 0.2d, and the distance fallen before that is [tex]0.8d[/tex]. So we can write:

[tex]0.2d = (1/2)at^2[/tex]

Solving for t, we get:

[tex]t = sqrt((0.2d)/(0.5*a))[/tex]

Plugging in the values, we get:

[tex]t = sqrt((0.290)/(0.5(-9.8))) = 1.38 seconds[/tex]

To find the speed of the bolt at the end of this 20% fall, we can use the kinematic equation:

[tex]v = vi + a*t[/tex]

where v is the final velocity, vi is the initial velocity (which is 0), a is the acceleration due to gravity ([tex]-9.8 m/s^2[/tex]), and t is the time taken.

Plugging in the values, we get:

[tex]v = 0 + (-9.8)*1.38 = -13.524 m/s[/tex]

The negative sign indicates that the velocity is downward.

(b) The time at which the bolt begins the last 20% of its fall can be found by multiplying the total time taken to fall by 0.8 (since the first 80% of the fall takes 80% of the total time):

[tex]t_start = 0.8sqrt((2d)/g) = 0.8sqrt((2*90)/9.8) = 3.06 seconds[/tex]

(c) The speed of the bolt just before it hits the ground can be found using the kinematic equation:

[tex]v^2 = vi^2 + 2ay[/tex]

where v is the final velocity, vi is the initial velocity (which is 0), a is the acceleration due to gravity [tex](-9.8 m/s^2)[/tex], and y is the distance fallen.

Plugging in the values, we get:

[tex]v = sqrt(0 + 2*(-9.8)*90) = 42.43 m/s[/tex]

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The brightness of the Moon can make it difficult to see fainter stars in its vicinity, further decreasing the likelihood of seeing it near Polaris in the night sky.

The Earth revolves on its axis as the Moon travels around it. The location of celestial objects in the sky seems to vary over time because to the Earth's rotation. Since it sits practically immediately above the North Pole of the Earth, Polaris, also known as the North Star, seems to remain motionless in the sky while all other stars appear to revolve around it.

The Moon, on the other hand, does one full circuit of the Earth every 27.3 days, traveling a distance of around 384,400 kilometers (238,855 miles) on average. Its location in relation to the stars, including Polaris, shifts as it circles.

The Moon will occasionally seem near to Polaris in the night sky, while other times it will look far away due to the Earth's rotation and the Moon's orbit. It is quite uncommon to observe the Moon and Polaris in close proximity to one another since their positions in relation to one another are continually shifting. Further reducing the chances of spotting the Moon close to Polaris in the night sky is the brightness of the Moon, which can make it challenging to discern nearby fainter stars.

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the x-coordinate of the center of the circular path is 0 (since it lies on the y-axis), and the y-coordinate is 2.55 m.

define motion ?

Motion refers to a change in position or location of an object over time relative to a reference point or frame of reference. It can be described in terms of its displacement, velocity, acceleration, and time.

The x-coordinate of the center of the circle can be found by finding the distance from the point (4.20 m, 4.70 m) to the y-axis. This distance is equal to the radius of the circle, which is given by the centripetal acceleration, a = v^2/r, where v is the speed of the particle in its circular path.

To find the speed of the particle, we can use the fact that the velocity is tangential to the circle. Since the particle is moving in uniform circular motion, the magnitude of its velocity is constant. Thus, we have:

|v| = sqrt[(vx)^2 + (vy)^2] = 7.20 m/s

where vx and vy are the x and y components of the velocity vector, respectively.

To find the x-coordinate of the center of the circle, we can use the Pythagorean theorem:

r^2 = (4.20 m)^2 + (4.70 m - y_c)^2

where y_c is the y-coordinate of the center of the circle.

Solving for y_c, we get:

y_c = 4.70 m ± sqrt[r^2 - (4.20 m)^2]

Since the particle is moving to the left (i.e., in the negative x-direction), the center of the circle must be to the left of the point (4.20 m, 4.70 m). Thus, we take the minus sign:

y_c = 4.70 m - sqrt[r^2 - (4.20 m)^2]

Now, we can use the fact that the acceleration is directed in the positive y-direction:

a_y = 14.1 m/s^2 = v^2/r

Solving for the radius, we get:

r = v^2/a_y = (7.20 m/s)^2/14.1 m/s^2 = 3.67 m

Finally, substituting this value into the expression for y_c, we get:

y_c = 4.70 m - sqrt[(3.67 m)^2 - (4.20 m)^2] = 2.55 m

So the x-coordinate of the center of the circular path is 0 (since it lies on the y-axis), and the y-coordinate is 2.55 m.

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Osmosis is the movement of water across a selectively permeable membrane from an area of high water concentration to an area of low water concentration. This process is related to the predictions made in question 2 because it helps to explain why certain substances move across the membrane and others do not.
If the substance in question is able to pass through the membrane, it will move from an area of high concentration to an area of low concentration, just like water does during osmosis. This movement is driven by the difference in concentration on either side of the membrane, and it helps to equalize the concentration on both sides.
Therefore, the predictions made in question 2 about the movement of substances across the membrane are directly related to the process of osmosis. Understanding how osmosis works help to predict how different substances will move across the membrane and what factors will influence this movement.

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The temperature of the filament in an incandescent bulb that produces light with a peak wavelength of 950 nm is approximately 3042 Kelvin. This is calculated using Wien's Law, which states that the peak wavelength of light emitted is inversely proportional to its temperature. Although the bulb's peak output is in the infrared spectrum, it still emits light in the visible spectrum, giving it a warm white glow.

To calculate the temperature of the filament in an incandescent bulb, we use Wien's Law which states that the peak wavelength of light emitted by a black body (here, the filament) is inversely proportional to its temperature. Mathematically it stands as λ_max = b/T, where λ_max is the peak wavelength, b is Wien's displacement constant (approximately 2.9*10^-3 m.K), and T the temperature in Kelvin.

Remember that the wavelength must be in meters, so convert 950 nm to meters, (which gives 950*10^-9 m).

Upon substituting these values: T = b / λ_max, you get T approximately equal to 3042 Kelvin. So, the filament's temperature would be around 3042 Kelvin.

The reason you see an incandescent bulb glowing despite its peak output being in the infrared spectrum (700nm - 1mm) is that it still emits light in the visible spectrum, but just not at its peak energy output. When viewed as a whole, the combined visible light appears as a warm white glow.

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The work done by the spring on the object can be calculated by finding the area under the graph of the spring force versus the position of the object.

Graph is a type of data structure that consists of a set of nodes and edges connecting them. Each node represents an entity, such as a person or place, and each edge represents a relationship between two entities. Graphs are used to represent relationships between different types of data and can be used for tasks such as finding the shortest path between two points or determining if a set of objects is connected. Graphs are also used in machine learning algorithms and artificial intelligence applications, allowing them to process data more efficiently.

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The difference in weight of the ball between the surface of the Earth and the top of Mount Everest is approximately 0.02 pounds.

The weight of an object is given by the product of its mass and the acceleration due to gravity at its location. The acceleration due to gravity depends on the distance from the center of the Earth, and it decreases as the distance from the center of the Earth increases.

At the surface of the Earth, the acceleration due to gravity is approximately 9.81 m/s². The radius of the Earth is approximately 6,371 km. Therefore, the weight of the ball at the surface of the Earth is:

Weight = mass x acceleration due to gravity

= 3 kg x 9.81 m/s²

= 29.43 N

To find the weight of the ball at the top of Mount Everest, we need to calculate the acceleration due to gravity at that altitude. We can use the fact that the acceleration due to gravity decreases with the square of the distance from the center of the Earth. The distance from the center of the Earth at the top of Mount Everest is:

Distance = radius of the Earth + height of Mount Everest

= 6,371 km + 8.85 km

= 6,379.85 km

The acceleration due to gravity at this distance is:

acceleration due to gravity = (acceleration due to gravity at the surface of the Earth) x (radius of the Earth / distance)²

= 9.81 m/s² x (6,371 km / 6,379.85 km)²

= 9.78 m/s²

Therefore, the weight of the ball at the top of Mount Everest is:

Weight = mass x acceleration due to gravity

= 3 kg x 9.78 m/s²

= 29.34 N

The difference in weight is the weight at the surface of the Earth minus the weight at the top of Mount Everest:

Difference in weight = Weight at surface - Weight at Everest

= 29.43 N - 29.34 N

= 0.09 N

To convert to pounds, we can divide the weight in newtons by the conversion factor 4.448 N/lb:

Difference in weight = 0.09 N / 4.448 N/lb

= 0.02 lb (rounded to two decimal places)

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(a)  The velocity of the neutron after the collision [tex]3.00(10^3)[/tex] km/s.

(b) Different materials may have different properties that make them more or less suitable as coolants in a fast breeder reactor.

(a) In an elastic collision, momentum and kinetic energy are conserved. Let m be the mass of the neutron and M be the mass of the sodium atom. Before the collision, the momentum of the neutron is

p = mv,

where v is the velocity of the neutron.

The momentum of the sodium atom is zero because it is motionless. Therefore, the total momentum before the collision is

[tex]p_{total} = mv[/tex].

After the collision, the neutron recoils backward along exactly the same path it traveled, so its final momentum is

[tex]p_f = -mv[/tex].

By conservation of momentum, the total momentum after the collision is also

[tex]p_{total} = p_f + 0 = -mv[/tex].

Equating the total momentum before and after the collision gives:

[tex]p_{total} = mv = -mv[/tex]

Solving for the final velocity [tex]v_f[/tex] of the neutron, we get:

[tex]v_f = -v = -3.00(10^3)[/tex] km/s

Therefore, the velocity of the neutron after the collision is [tex]3.00(10^3)[/tex] km/s in the opposite direction.

(b) We follow the same procedure as in part (a), but with a lithium atom instead of a sodium atom.

Let M be the mass of the lithium atom.

Before the collision, the momentum of the neutron is

p = mv,

where v is the velocity of the neutron.

The momentum of the lithium atom is zero because it is motionless. Therefore, the total momentum before the collision is

[tex]p_{total} = mv[/tex]

After the collision, the neutron recoils backward along exactly the same path it traveled, so its final momentum is

[tex]p_f = -mv[/tex].

By conservation of momentum, the total momentum after the collision is also [tex]p_{total} = p_f + 0 = -mv[/tex].

Equating the total momentum before and after the collision gives:

[tex]p_{total} = mv = -mv[/tex]

Solving for the final velocity [tex]v_f[/tex] of the neutron, we get:

[tex]v_f = -v = -3.00(10^3)[/tex] km/s

Therefore, the velocity of the neutron after the collision is [tex]3.00(10^3)[/tex] km/s in the opposite direction.

Comparing the results of parts (a) and (b), we see that the type of metal does not affect the velocity of the neutron after an elastic collision. However, different materials may have different properties that make them more or less suitable as coolants in a fast breeder reactor.

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Gionny can apply a torque of approximately 127.63 N·m to the lug nut.

To calculate the torque that Gionny can apply to the lug nut, we need to use the formula:

Torque = Force x Distance x sin(θ)

where θ is the angle between the force vector and the lever arm (the distance from the axis of rotation to the point where the force is applied), and sin(θ) is the sine of that angle.

Assuming that Gionny's weight is the force he applies on the tire-iron, and that he can exert a force equal to his weight, we can calculate the force as:

Force = mass x gravity

where mass is Gionny's mass and gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2. Therefore, the force Gionny can apply is:

Force = 42 kg x 9.81 m/s^2 = 411.42 N

The distance from the lug nut to the point where Gionny applies the force is given as 0.31 m. So the torque he can apply is:

Torque = Force x Distance x sin(θ) = 411.42 N x 0.31 m x sin(90°) = 127.63 N·m

Therefore, Gionny can apply a torque of approximately 127.63 N·m to the lug nut.

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The values of theta is the vertical component ay of the acceleration vector greatest in magnitude at  90° and 270°.

Multidimensional stir with constant acceleration can be treated the same way as shown in the former chapter for one- dimensional stir. before we showed that three- dimensional stir is original to three one- dimensional movements, each along an axis vertical to the others.

To develop the applicable equations in each direction, let’s consider the two- dimensional problem of a flyspeck moving in the xy aeroplane with constant acceleration, ignoring the z- element for the moment.

Thinking of circles as parametric equations:

ry=sinθ

rx=cosθ

Note that I have limited θ:     0° <=θ < 360°

Also note that the greatest magnitude of sine and cosine functions is1.

This problem is based only on the y-component, so just consider ry=sinθ.

It hast he greatest magnitude (vertical distance from the center) at90° (and 270°).

Takethe derivative for velocity.

vy=cosθ

It has the greatest magnitudes at 0° and 180°.

Take the derivative for acceleration

ay=-sinθ

It has the greatest magnitudes at 90° and 270°

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Complete question:

At what value(s) of is the vertical component ay of the acceleration vector greatest in magnitude? (Several choices may be correct.) 0° 90° 180° 270°

The child closer to the book must apply a force of 49.05 N to support the board.

To solve this problem, we will use the principle of torque balance. The torque is the product of the force and the perpendicular distance from the force to the point of rotation. In this case, the point of rotation is the midpoint of the board.

First, we need to find the weight of the board. The weight is the force of gravity acting on the board, which is given by:

weight = mass x gravitational acceleration

weight = 5.00 kg x 9.81 m/[tex]s^2[/tex]

weight = 49.05 N

Next, we need to find the weight of the book.

The weight of the book is:

weight book = mass book x gravitational acceleration

weight book = 1.00 kg x 9.81 m/[tex]s^2[/tex]

weight book = 9.81 N

We can now find the torque due to the weight of the board and the book. The torque is the weight multiplied by the distance from the midpoint of the board:

torque weight = (weight board + weight book) x 1.00 m

torque weight = (49.05 N + 9.81 N) x 1.00 m

torque weight = 58.86 N*m

To balance this torque, the child closer to the book must apply a force perpendicular to the board at a distance from the midpoint of the board. We can call this distance x. The force applied by the child is the unknown we want to find, so let's call it F.

The torque due to the child's force is:

torque child = F x x

The torque balance equation is:

torque weight = torque child

Substituting the values we have found, we get:

58.86 N*m = F x x

We know that x = 1.20 m, so we can solve for F:

F = 58.86 N*m / 1.20 m

F = 49.05 N

Therefore, the child closer to the book must apply a force of 49.05 N to support the board.

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Since there is no friction, the normal force must be equal in magnitude and opposite in direction to the weight. Therefore, the magnitude of the normal force is also 46.06 N or 46.1 N.

The normal force is the force exerted by a surface perpendicular to the object in contact with the surface. In this case, the cart is rolling down the ramp, and the normal force is exerted by the ramp on the cart. Since the ramp is inclined, the normal force will be less than the weight of the cart, which is given by:

[tex]W = m*g[/tex]

where m is the mass of the cart and g is the acceleration due to gravity.

In this problem, the mass of the cart is given as 4.7 kg, and the acceleration due to gravity is approximately [tex]9.8 m/s^2.[/tex]

Therefore, the weight of the cart is:

[tex]W = 4.7 kg * 9.8 m/s^2 = 46.06 N[/tex]

Since there is no friction, the normal force must be equal in magnitude and opposite in direction to the weight. Therefore, the magnitude of the normal force is also 46.06 N.

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The calisthenic move where only your hands are on the ground and your body is perpendicular to floor is Planche.

The Planche is a challenging calisthenics exercise that requires a significant amount of strength and control. In this exercise, the body is held horizontally with only the hands and arms touching the ground. The hips are held high and the legs are straight, parallel to the ground. The Planche requires a strong core, chest, shoulders, and triceps, as well as exceptional balance and stability.

To achieve a Planche, one must train consistently and progressively to build the necessary strength and control. It is a popular exercise in the calisthenics community, and is often used as a benchmark for overall strength and fitness. Variations of the Planche, such as the Straddle Planche and Full Planche, are even more challenging and require even greater strength and control.

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The period of the signal is 9 ms and the frequency is approximately 111.1 Hz, calculated using f = 1/T.

To decide the period and recurrence of the sign displayed on the oscilloscope follow, we want to quantify the time span between two nearby pinnacles.

From the oscilloscope follow, we can see that the time stretch between two nearby pinnacles is around 4.5 squares on the even hub, which relates to 4.5 x 2 ms = 9 ms.

Hence, the time of the sign is 9 ms.

To ascertain the recurrence of the sign, we can utilize the equation:

recurrence = 1/period

Subbing the worth of the period, we get:

recurrence = 1/9 ms = 111.1 Hz

Consequently, the recurrence of the sign is around 111.1 Hz.

To decide the period, we really want to gauge the time it takes for the sign to finish one full cycle. For this situation, we can see that the sign finishes one full cycle in around 9 ms. The recurrence, which is the quantity of cycles each second, can then be determined utilizing the equation recurrence = 1/period, which gives a recurrence of roughly 111.1 Hz.

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The term that best completes the given sentence is "competitive inhibition."

define competitive inhibition ?

Competitive inhibition is a type of enzyme inhibition where a molecule, called a competitive inhibitor, binds to the active site of an enzyme and blocks the binding of the substrate, preventing or reducing the enzyme's activity. The competitive inhibitor has a similar shape to the substrate, and thus competes with the substrate for binding to the active site. This type of inhibition can be reversed by adding more substrate, which outcompetes the inhibitor for binding to the active site.

Competitive inhibition is often used in drug design, as molecules that act as competitive inhibitors can be used to selectively target specific enzymes and prevent their activity.

The term that best completes the given sentence is "competitive inhibition."

Competitive inhibition refers to a situation in which one company or individual attempts to gain an advantage over another by developing or promoting a similar product or idea that reduces the demand for the other's product or idea. In this case, Nela believes that Logan's electric yacht idea is directly competing with Dunamis Motors, and is therefore a form of competitive inhibition.

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Answer:

86400 seconds is equal to 1 day.

Explanation:

The graph of an accelerating object shows the increase in velocity with time. The object which is not accelerating is having a constant velocity with out any change in direction or magnitude.

Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.

The change in direction or magnitude or in both of velocity leads to an acceleration on the object. The object moving through a circular curvature is having a change in its direction of velocity. Hence, the object  is accelerating.

For an object moving without a change in velocity and no change in direction, the object is not accelerating at all as seen in the graph 2.

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