Suppose that you and a friend are playing cards and you decide to make a friendly wager. The bet is that you will draw two cards without replacement from a standard deck. If both cards are spades, your friend will pay you $39 $ ⁢ 39 . Otherwise, you have to pay your friend $5 $ ⁢ 5 . Step 2 of 2 : If this same bet is made 623 623 times, how much would you expect to win or lose? Round your answer to two decimal places. Losses must be expressed as negative values.

The probability that both are red marbles is 0.2391

The given parameters are:

Red =12

Blue = 12

Total = 24

The probability of selecting the first red marble :

P(Red) = 12/24

Now, there are 11 red marbles and 23 marbles in all

The probability of selecting the second red marble :

P(Red) = 11/23

The required probability is:

P =  12/24 * 11/23

Evaluate

P = 0.2391

Hence, the probability that both are red marbles is 0.2391

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Answer:

A

Step-by-step explanation:

In this case you have to show that 1 + 2 = 180

This way when you show that 2 + 3 = 180, that proves 1 & 3 are congruent.

Answer:

A. 2. ∡1 is supplementary to ∡2 (linear pair theorem)

Step-by-step explanation:

Given the following proof so far, we have:
1. Line a and line b intersect => given

2. ? => ?

3.  ∡3 is supplementary to  ∡2 => linear pair theorem

4.  ∡1 ≅ ∡3 => congruent supplements theorem

Now let's take a look at the reasoning for statement 4, which says that angle 1 and 3 are congruent due to congruent supplements theorem.

In this theorem, if 2 angles are supplementary (add up to 180 degrees) to the same angle, it means those 2 angles are congruent.

Why does this work?
________________________________________________________
Let's say x + y = 180, and z + y = 180

By transitivity (if a = b and b =c, then a=c), x + y is equal to z + y

x + y = z + y

Subtract y from both sides

x = z

________________________________________________________

Statement 3 says  ∡3 is supplementary to  ∡2, and because of congruent supplements theorem being our last reason (where  ∡1 and  ∡3 are congruent), we need to make statement 2 also have ∡1 being supplementary to ∡2, (∡2 is like y in the example above - it's the angle that  ∡1 and  ∡3 are both supplementary to).

This will eliminate choices B (which has  ∡1, but also  ∡4 which isn't necessary), C ( ∡which mentions nothing about  ∡1), and D (which also doesn't mention anything about  ∡1, and which also isn't necessary as we have statement 3 essentially saying the same thing), leaving A as the correct answer.

Answer:

  $188.06

Step-by-step explanation:

The total cost for the film will be the sum of film cost, applicable sales tax, and applicable shipping charges. The film cost will be the product of the number of rolls and the cost per roll.

__

  film cost = (18 rolls) × ($9.95 /roll) = $179.10

  sales tax = 0.05 × $179.10 = $8.96

There is no shipping charge associated with the camera shop purchase, so the total cost is ...

  camera shop cost = film cost + sales tax = $179.10 +8.96 = $188.06

__

  film cost = (18 rolls) × ($9.76 /roll) = $175.50

  shipping charge = $15.00

There is no sales tax associated with the mail order, so the total cost is ...

  mail order cost = film cost + shipping charge = $175.50 +$15.00 = $190.50

__

The price from the camera shop is the better of the two prices. The purchase there would cost you $188.06 for 18 rolls of film.

_____

Additional comment

The after-tax charge per roll of film at the camera shop is 9.95×1.05 = 10.4475. This is $0.6975 more than the basic charge per roll from the mail order company. In order to get the shipping charge of $15 to be less than $0.6975 per roll, the number of rolls ordered must be more than 15/0.6975 = 21.5.

An order of 22 rolls of film from the mail order company would cost less than from the camera shop. ($229.50 vs. $229.85)

Answer:

√2/4, √3/4, and √5/4.

Step-by-step explanation:

A rational number is any integer, fraction, terminating decimal, or repeating decimal.

Part 1

[tex](g\circ h)(x)=g(x-4)=(x-4)^2 + 1=x^2 - 8x+16+1=\boxed{x^2 - 8x+17}[/tex]

Part 2

[tex](-\infty, \infty)[/tex]

The answers in the box are:

Given that the functions are

[tex]g(x)=x^2+1[/tex]

[tex]h(x)=x-4[/tex]

Since clearly g(x) and h(x) exist for all real values of x so the domain of g(x) and h(x) both are all real numbers.

Now the composition of function is given by,

[tex](g\circ h)(x)=g(h(x))[/tex]

               [tex]=g(x-4)[/tex]

               [tex]=(x-4)^2+1[/tex]

               [tex]=x^2-8x+16+1[/tex], since we know that [tex](a-b)^2=a^2-2ab+b^2[/tex]

               [tex]=x^2-8x+17[/tex]

So, [tex](g\circ h)(x)=x^2-8x+17[/tex]

It is a polynomial function so it is defined for all real values of x.

Hence the domain of composition is all real numbers, that is [tex](-\infty,\infty)[/tex]

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Probability that the salesperson has “Fair” potential or has Above Average Sales ability is; 90.8%

A) Probability that the salesperson has “Fair” potential for advancement = (16 + 45 + 93)/500 = 154/500 = 30.8%

B)  Probability that the salesperson has “Fair” potential or has Above Average Sales ability = 30.8% + (300/500)% = 90.8%

C) Probability that the salesperson has “Fair” potential given they have Above Average Sales ability = P(A|B) = P(A ∩ B)/P(B) = (93/500)/0.6 = 0.31 = 31%

D) P(selecting 2 salespersons and finding they both have Fair potential for advancement) = (154/500) * (153/499) = 9.44%

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Answer:

D.

Step-by-step explanation:

He has to walk down 3 blocks and right 10

The multiplicity of the function is 1 for each term after factorization.

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

[tex]\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n[/tex]

We have a polynomial function:

[tex]\rm F(x)= 4x^3+19x^2-41x+9[/tex]

After factorization:

[tex]\rm F(x) = \left(4x-1\right)\left(x^2+5x-9\right)=0[/tex]

[tex]\rm F(x) =(4x-1)^1(\:x-\frac{-5+\sqrt{61}}{2})^1(\:x+\frac{-5-\sqrt{61}}{2})^1[/tex]

The multiplicity of the function is 1 for each term.

Thus, the multiplicity of the function is 1 for each term after factorization.

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Answer:

[tex]\boxed{\sf x= -29.5}[/tex]

Step-by-step explanation:

[tex]\sf \sqrt{-2x+5}-3=5[/tex]

[tex]\sf \sqrt{-2x+5}=8[/tex]

[tex]\sf -2x+5=64[/tex]

[tex]\sf -2x=59[/tex]

[tex]\sf \cfrac{-2x}{-2}=\cfrac{59}{-2}[/tex]

Therefore, x = -29.5.

Answer:

x greater than equal to (-1)

x less than 2

all no. greater than -1 = -1,1, 0 , 1 ,2 ......

no. less than2 = 1, 0, -1,.......

-1,0, 1

Answer:

x=80.8

Step-by-step explanation:

follow BODMAS

2015-(2015÷5(x-5)÷5)=2014

2015-(2015÷5x-25÷5)=2014

2015-(405/x-5)=2014

2015-(405-5x)=2014

2015-405+5x=2014

1610+5x=2014

5x=2014-1610

(5x=404)1/5

x=80.8

Answer: 1

Step-by-step explanation:

[tex]f(8+h)=8+h+10=18+h\\\\f(8)=8+10=18[/tex]

So, the average rate of change is:

[tex]\frac{(18+h)-18}{(8+h)-8}=\frac{h}{h}=\boxed{1}[/tex]

The question is wrong, the expression will not be in terms of h since it is a linear function.

Answer:

Step-by-step explanation:

plug in x try numbers

x = 14.2

Answer:

600

Step-by-step explanation:

Let's consider this question using algebra.

Imagine the number of bricks in the original pile is [tex]x[/tex].

We are told that [tex]\frac{3}{4}[/tex] of the bricks are used for a project, meaning that [tex]\frac{3}{4} x[/tex] has been used, leaving us with [tex]\frac{1}{4}x[/tex] as our remainder.

Then, we are told that [tex]\frac{2}{3}[/tex] of the remainder are used to leave us with 50 bricks. This means that [tex]\frac{1}{3}[/tex] of the remainder is left, and this is equal to 50 bricks. This means that the remainder's original amount is equal to 150, because we are told that [tex]\frac{1}{3}[/tex] of the remainder is equal to 50.

So, we know that the remainder is 150, and we also know that the remainder is [tex]\frac{1}{4} x[/tex]. Let's now use these to form an equation.

[tex]\frac{1}{4} x = 150[/tex]

Because we know that a quarter of the original amount of bricks is equal to 150, we can multiply both sides of the equation by 4 to get the original amount of bricks in the pile.

[tex]x = 150 * 4 = 600[/tex]

So, there were 600 bricks in the original pile.

Inequalities help us to compare two unequal expressions. There exists no solution to the given set of inequalities.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The given Inequalities can be solved as,

5 - x > 7

-x > 7 - 5

-x > 2

x < -2

2x + 3 ≥ 13

2x ≥ 10

x ≥ 5

As per the solution of the two inequalities, the value of x should be less than -2 but at the same time, it should be more than or equal to 5, which is impossible. Thus, there is no solution for the given inequalities.

This can be confirmed by graphing the two inequalities, as shown below. Since there is no area in common between the two inequalities, there exists no solution to the given set of inequalities.

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Answer:

yes

Step-by-step explanation:

because bank

The total amount Maria ended up paying for the equipment will be $14,861.76. And The interest of Maria on the loan will be 8.48%.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

To purchase 13700 worth of restaurant equipment for her business.

Maria made a down payment of 1500 and took out a business loan for the rest, after 3 years of paying monthly payments of 371.16 she finally paid off the loan.

The total amount Maria ended up paying for the equipment will be

Total amount = 371.16 × 3 × 12 + 1500

Total amount = $14,861.76

The interest of Maria on the loan will be

Interset = [(14861.76 – 13700) / 13700] x 100

Interset = 8.48%

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Answer:

K=-3/5

Step-by-step explanation:

y= -3x/5 - 11/5

Answer:

Damien is 74 years old now

Step-by-step explanation:

Define the variables:

Given information:

From the given information, create 2 equations:

Equation 1:  d + k = 100

Equation 2:  d - 10 = 4(k - 10)

Rewrite Equation 1 to make k the subject:

⇒ k = 100 - d

Substitute this into Equation 2 and solve for d:

⇒ d - 10 = 4(100 - d - 10)

⇒ d - 10 = 400 - 4d - 40

⇒ d - 10 = 360 - 4d

⇒ d - 10 + 10 = 360 - 4d + 10

⇒ d = 370 - 4d

⇒ d + 4d = 370 - 4d + 4d

⇒ 5d = 370

⇒ 5d ÷ 5 = 370 ÷ 5

⇒ d = 74

Therefore, Damien is 74 years old now.

Answer:

ab+bc+ac = 7+21 + 28 =56

so the answer is 56

Observe that

[tex]a^2 + b^2 + ab = 7 \iff a^2 + b^2 - 2\cos(120^\circ) = \left(\sqrt 7\right)^2[/tex]

[tex]b^2 + c^2 + bc = 21 \iff b^2 + c^2 - 2\cos(120^\circ) = \left(\sqrt{21}\right)^2[/tex]

[tex]a^2 + c^2 + ac = 28 \iff a^2 + c^2 - 2\cos(120^\circ) = \left(\sqrt{28}\right)^2[/tex]

Drawing a comparison to the law of cosines, we see the first equation defines a triangle with sides [tex]a[/tex], [tex]b[/tex], and [tex]\sqrt 7[/tex]; the second equation defines one with sides [tex]b[/tex], [tex]c[/tex], and [tex]\sqrt{21}[/tex]; and the third equation defines another one with sides [tex]a[/tex], [tex]c[/tex], and [tex]\sqrt{28}[/tex]. We can then join these triangles at a point D to form a new triangle ABC with sides [tex]\sqrt7,\sqrt{21},\sqrt{28}[/tex]. (See attached sketch)

Now, the area of ABC is the sum of the areas of ABD, BCD, and ACD. The area of any of these triangles is equal to half the area of a parallelogram spanned by the sides involving the vertex D. The area of a parallelogram with adjacent sides [tex]x[/tex] and [tex]y[/tex] and with angle [tex]\theta[/tex] between them is [tex]ab\sin(\theta)[/tex].

For example, triangle ABD has area

[tex]\mathrm{area}_{\Delta ABD} = \dfrac12 \times ab \sin(120^\circ)[/tex]

Then the total area of triangle ABC is

[tex]\mathrm{area}_{\Delta ABC} = \dfrac12 \sin(120^\circ) (ab + ac + bc)[/tex]

We use Heron's formula to find the area of ABC. If [tex]s[/tex] is its semiperimeter, i.e.

[tex]s = \dfrac{\sqrt7 +\sqrt{21} + \sqrt{28}}2[/tex]

then, with a lot of algebraic simplification,

[tex]\mathrm{area}_{\Delta ABC} = \sqrt{s (s-\sqrt7) (s - \sqrt{21}) (s - \sqrt{28})} = \dfrac{7\sqrt3}2[/tex]

Finally, we find

[tex]\dfrac{7\sqrt3}2 = \dfrac12 \sin(120^\circ) (ab + ac + bc) \implies ab + ac + bc = \dfrac{\frac{7\sqrt3}2}{\frac12\times\frac{\sqrt3}2} = \boxed{14}[/tex]

Answer:

D

Step-by-step explanation:

the cordinate is at (-3,2)

Answer:

Using the rational root theorem, we know to divide the function by (x - 1).

(7x³ + 9x² - 12x - 4) / (x - 1) = 7x^2 + 16x + 4

Now we can further factorize 7x^2 + 16x + 4 into (7x + 2) and (x + 2).

Therefore, the original function can be rewritten as (x - 1) (7x + 2) (x + 2).

Using the factorized form above, the zeros of the function are 1, -2/7, and -2.

Answer: 0 ≤ y < ∞

Step-by-step explanation:

   First, let us graph the function. See attached.

-> If I graphed the formatting of the square root sign incorrectly, please let me know so I can fix the answer.

  The range of the function is all of the function's output values. In this case, all of the y values.

        0 ≤ y < ∞

Jessica sells = 240 books,

Josh sells = 16 books.

The price of one book is = $15

Jessica sold 15 times more books than Josh.

In total, they have sold 256 books.

We can easily find the answer using variables.

Let,

Josh sold a total of x books whereas Jessica sold a total number of 15x books.

together they sold 16x books.

So we can form the equation

16x= 256

by solving this equation we will get x=16

So, Josh sold 16 books and Jessica sold 16×15=240 books in total.

Answer:

Jessica=240

Josh=15

Step-by-step explanation:

Answer:

y=2x+20

Step-by-step explanation:

x is any real number greater than or equal to 0, and y is any real number greater than or equal to 20

Hope this helps :)

Answer: The function is odd and symmetric with respect to the origin.

Step-by-step explanation:

A function is even if f(x)=f(-x), and odd if f(x)=-f(-x). If a function satisfies neither of these, it is neither even nor odd.

[tex]f(x)=x^{3}-2x\\\\f(-x)=(-x)^{3}-2(-x)=-x^{3}+2x=-f(x)[/tex]

Therefore, the function is odd, and thus the function is symmetric about the origin

The median of the distribution is 4.

A histogram is used to represent data graphically. The histogram is made up of rectangles whose area is equal to the frequency of the data and whose width is equal to the class interval.

The median is the number at the center of the data set.

Arranging the numbers in the histogram in ascending order is: 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 6, 6, 7, 8, 9, 10

1/2 x 22 = 11th number  4

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The next three terms will be -1/16, 1/32, and -1/64. Then the correct option is B.

Let a be term and r be the common ratio. Then the geometric sequences will be

[tex]\rm a_n = a_{n -1} \cdot r[/tex]

The sequence is given below.

-1, 1/2, -1/4, 1/8,....

The common ratio will be -1/2.

Then the next three terms will be

a₅ = a₄ x (-1/2)

a₅ = (1/8) x (-1/2)

a₅ = -1/16

a₆ = a₅ x (-1/2)

a₆ = (-1/16) x (-1/2)

a₆ = 1/32

a₇ = a₆ x (-1/2)

a₇ = (1/32) x (-1/2)

a₇ = -1/64

Then the next three terms will be -1/16, 1/32, and -1/64.

Then the correct option is B.

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Answer:

C

Step-by-step explanation: